what is the relationship between the specific rotation of (2s,3s)-dibromopentane and (2r, 3s)-dibromopentane? question 4 options: the specific rotation is equal in magnitude and have the same sign the specific rotation is equal in magnitude but opposite in the sign it is not possible to predict the specifi rotation the specific rotation is different in magnitude and opposite in sign the specific rotation is zero

Answer:

m - mass of each liquids (all masses are equal )

C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second  liquid

C_3C 3- specific heat of the third liquid

Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT

1 =7◦C,T 2 =20◦C,T 3=34◦C

Temperature of 1+2 liquids mix: T_{12}=11^oCT

12 =11 oC

Temperature of 2+3 liquids mix: T_{23}=22.6^oCT

23=22.6 oC

Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?

When the first two are mixed:

m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2

​When the second and therd are mixed:

m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3

​When the first and therd are mixed:

m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:

Answer:

The speed of the student just before she lands, v₂ is approximately 8.225 m/s

Explanation:

The given parameters are;

The mass of the physic student, m = 43.0 kg

The height at which the student is standing, h = 12.0 m

The radius of the wheel, r = 0.300 m

The moment of inertia of the wheel, I = 9.60 kg·m²

The initial potential energy of the female student, P.E.₁ = m·g·h₁

Where;

m = 43.0 kg

g = The acceleration due to gravity ≈ 9.81 m/s²

h = 12.0 h

∴ P.E.₁ = 43 kg × 9.81 m/s² × 12.0 m = 5061.96 J

The kinetic rotational energy of the wheel and kinetic energy of the student supporting herself from the rope she grabs and steps off the roof, K₁, is given as follows;

\(K_1 = \dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2\)

The initial kinetic energy, 1/2·m·v₁² and the initial kinetic rotational energy, 1/2·m·ω₁² are 0

∴ K₁ = 0 + 0 = 0

The final potential energy of the student when lands. P.E.₂ = m·g·h₂ = 0

Where;

h₂ = 0 m

The final kinetic energy, K₂, of the wheel and student is give as follows;

\(K_2 = \dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2\)

Where;

v₂ = The speed of the student just before she lands

ω₂ = The angular velocity of the wheel just before she lands

By the conservation of energy, we have;

P.E.₁ + K₁ = P.E.₂ + K₂

∴ m·g·h₁ + \(\dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2\) = m·g·h₂ + \(\dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2\)

Where;

ω₂ = v₂/r

∴ 5061.96 J + 0 = 0 + \(\dfrac{1}{2} \times 43.0 \, kg \times v_{2}^2+\dfrac{1}{2} \times 9.60 \, kg\cdot m^2 \cdot \left (\dfrac{v_2}{0.300 \, m} }\right ) ^2\)

5,061.96 J = 21.5 kg × v₂² + 53.\(\overline 3\) kg × v₂² = 21.5 kg × v₂² + 160/3 kg × v₂²

v₂² = 5,061.96 J/(21.5 kg + 160/3 kg) ≈ 67.643118 m²/s²

v₂ ≈ √(67.643118 m²/s²) ≈ 8.22454363 m/s

The speed of the student just before she lands, v₂ ≈ 8.225 m/s.

a) Two other forces that act on thee sled are the weight of the daughter and the drag force

b) The drag force slows down the sled while the weight presses it down.

We know that motion is the result of the action of unbalanced forces. From the Newton's third law, we know that if the forces that are acting on an object are balanced that the object is not going to move from its state of rest.

In this case, we are told that a  father pushes his daughter and son on a sled down a hill. The fact that the led is moving is due to the fact that there are forces that are acting on the sled.

The forces that are acting on the sled apart  from the force that was applied in pushing the sled is the drag force and the weight of the son.

The drag force would determine how fast that the sled would move because it acts in opposition to the forward force and tries to slow down the sled as it is moving. The weight of the son does press the sled downwards.

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Answer:

velocity = displacement /time

v= d/t

v= 25/ 10

v = 2.5 m/s

Explanation:

hope this help

Answer:

d=9m

Explanation:

Gauge pressure is the pressure measured relative to atmospheric pressure. A commonly used instrument for measuring gauge pressure is the pressure gauge.

A pressure gauge typically consists of a circular dial with a pointer, a pressure sensing element, and a scale. The sensing element, which is usually a diaphragm or a Bourdon tube, is connected to the system or container whose pressure is being measured.

The pressure gauge is usually connected to the system or container through an inlet port. When the pressure in the system or container changes, it exerts a force on the sensing element of the pressure gauge. This force causes the sensing element to deform, which in turn moves the pointer on the dial. The position of the pointer on the pressure scale indicates the gauge pressure.

The pressure scale on the dial is calibrated in units such as psi (pounds per square inch), bar, or kPa (kilopascals), depending on the application and region. The scale allows the user to directly read the gauge pressure value.

It's important to note that the pressure gauge measures the difference between the pressure being measured and the atmospheric pressure. If the system or container is under vacuum (pressure lower than atmospheric pressure), the gauge will indicate negative values.

Pressure gauges are widely used in various industries and applications where monitoring and control of pressure is essential, such as in industrial processes, HVAC systems, pneumatic systems, and hydraulic systems.

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Answer:

The ability to fight with disease and some other kinds of infirmities is Known as immunity

Explanation:

the ability of an organism to resist a particular infection or toxin by the action of specific antibodies or sensitized white blood cells

1.Curved space near massive objects causes other objects to orbit them. - Correct

2.General relativity is an extension of Newton's laws of motion. - Correct

Newton's laws of motion are three physical laws that form the basis for classical mechanics. They were first compiled by English physicist and mathematician Sir Isaac Newton in his 1687 book Philosophiæ Naturalis Principial Mathematical, and describe the relationship between a body and the forces acting upon it.

3.Uniform motion through space is detectable without outside objects if approaching the speed of light. - Incorrect

4.Mass and energy are related. - Correct

5.Neither theory of relativity (general or special) has been experimentally tested. - Incorrect

6.The presence of mass curves space. - Correct

7.The speed of light you observe depends on your frame of reference. - Correct

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Answer:

(a) The time taken for the ball to reach the base of the building can be calculated using the kinematic equation:

h = 1/2 gt^2

where h is the height of the building, g is the acceleration due to gravity, and t is the time taken for the ball to reach the base of the building.

Substituting the given values, we get:

50 = 1/2 × 9.81 × t^2

Solving for t, we get:

t = √(50/4.905) = 3.19 seconds

Therefore, the time taken for the ball to reach the base of the building is 3.19 seconds.

(b) The velocity of the ball just before hitting the base of the building can be calculated using the kinematic equation:

v = gt

where v is the final velocity of the ball, g is the acceleration due to gravity, and t is the time taken for the ball to reach the base of the building.

Substituting the given values, we get:

v = 9.81 × 3.19

v = 31.3 m/s

Therefore, the velocity of the ball just before hitting the base of the building is 31.3 m/s.

(c) The vertical distance passed at the third second can be calculated using the kinematic equation:

h = ut + 1/2 at^2

where h is the distance traveled by the ball, u is the initial velocity, a is the acceleration due to gravity, and t is the time elapsed.

At the end of the second second, the ball has fallen a distance of:

h = 1/2 × 9.81 × (2^2) = 19.62 m

At the end of the third second, the ball has fallen a distance of:

h = 1/2 × 9.81 × (3^2) = 44.145 m

Therefore, the vertical distance passed at the third second is 44.145 - 19.62 = 24.525 m.

Answer:

Explanation:

Silver, Bronze, Gold

Question 1

T=2*pi*sqrt(m/k) 

dimension of T=sec

dimension of 2*pi=nil(dimensionless)

dimension of m=kg

equation dimension

sec=sqrt(kg/k)

sec^2=kg/k

k=kg/sec^2

so dimension of k will be 

MT^(-2) 

dimension of N/m=kgms^(-2)/m=kgs^(-2) so it is same 

Question 2

F=Gm1*m2/r^2

Dimension of F=MLT^(-2)

MLT^(-2)=G*M*M/L^2

G=ML^3T^(-2)/M^2=M^(-1)L^(3)T^(-2)

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Given:

Due to the Doppler effect, when moving away from the source of a sound, _______

Required: To fill in the blank

Explanation:

The sound should get more quiet as the sound waves die out with increasing distance.

Final Answer: Due to the Doppler effect, when moving away from the source of a sound, the sound should get more quiet.

Answer:

a=1 m/s^2

Explanation:

\(a = \frac{v - u}{t} \\ = \frac{10 - 0}{10} \\ = 1m {s}^{ - 2} \)

Hey!!

Solution,

Initial velocity(u)=0 m/s

Final velocity(v)=10m/s

Time(t)=10s

Acceleration=?

Now,

Acceleration=v-u/t

=10-0/10

= 10/10

=1 m/s^2

The acceleration is 1 m/s^2

Hope it helps

Good luck on your assignment

To calculate the photon flux, we need to use the formula:
Photon flux = intensity / (energy per photon x speed of light x wavelength)
The energy per photon can be calculated using the formula:
Energy per photon = Planck's constant x speed of light / wavelength

Substituting the given values, we get:
Energy per photon = (6.626 x 10^-34 J s x 3 x 10^8 m/s) / (500 x 10^-9 m) = 3.98 x 10^-19 J
Substituting this value and the given intensity and wavelength into the photon flux formula, we get:
Photon flux = 2000 W/m^2 / (3.98 x 10^-19 J x 3 x 10^8 m/s x 500 x 10^-9 m) = 2.51 x 10^15 photons/m^2.s
Therefore, the photon flux is approximately 5 x 10^17, which is option A.
The intensity of a uniform light beam with a wavelength of 500 nm is 2000 W/m². To find the photon flux (in number/m²·s), we first need to determine the energy of a single photon. We can do this using the equation: E = (hc)/λ
where E is the energy of a photon, h is Planck's constant (6.63 x 10^-34 Js), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of light (500 nm, or 5 x 10^-7 m).
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / (5 x 10^-7 m)
E ≈ 3.98 x 10^-19 J
Now that we have the energy of a single photon, we can find the photon flux (Φ) using the equation: Φ = I / E
where I is the intensity of the light beam (2000 W/m²) and E is the energy of a single photon. Φ = (2000 W/m²) / (3.98 x 10^-19 J)
Φ ≈ 5 x 10^21 photons/m²·s
Therefore, the photon flux is approximately 5 x 10^21 photons/m²·s, which corresponds to option C.

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Answer:

d

Explanation:

A 0.25 µF capacitor is connected to a 9.0 V battery. The charge on the capacitor is 2.25 µC. A capacitor's ability to store charge is determined by its capacitance, which is measured in farads (F).

A capacitor is an electrical component that stores electrical energy in an electric field between a pair of conductors. Capacitors of different sizes and types are used in various applications, ranging from smoothing and filtering power supply voltages to storing energy in pulsed lasers.

A capacitor's ability to store charge is determined by its capacitance, which is measured in farads (F). The voltage across the capacitor plates and the capacitance are both proportional to the amount of charge stored on the capacitor.

The formula for calculating the charge on the capacitor is given below: Q = CVWhere Q is the charge, C is the capacitance, and V is the voltage across the capacitor. In this case, the capacitance is 0.25 µF, and the voltage is 9.0 V. Thus, the charge on the capacitor is given by: Q = CV= 0.25 µF × 9.0 V= 2.25 µC

Thus, the charge on the capacitor is 2.25 µC.

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In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.

As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.

According to Archimedes' Principle, the weight of the displaced water will be equivalent to the weight of the content loaded anchored in the seabed. Water displacement volume = weight of the content loaded = 10,000 kN.

The content you provided describes a situation where there is an object or structure anchored in the seabed using cables that exert a downward force of 10,000 kilonewtons (kN). This force keeps the object in place.

In this context, the "water displacement volume" refers to the volume of water that is displaced or pushed aside by the presence of the anchored object. When an object is placed in water, it causes the water to move and occupy a different space. The displaced volume of water can be determined by the buoyant force acting on the object, which is equal to the weight of the water displaced.

To calculate the exact water displacement volume caused by the object, we would need additional information such as the shape, size, and density of the object. With this information, we can apply the principles of fluid mechanics and buoyancy to determine the exact volume of water displaced.

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Electromagnetic waves are a form of radiation that occurs when electric fields and magnetic fields are coupled with each other. Thus, option C is correct.

An electromagnetic field is formed with an electric field and a magnetic field that are dependent on each other. The two fields are perpendicular to each other and travel in that direction as well.

Electromagnetic waves are not elastic waves either and can travel in a vacuum. They are different from mechanical waves as electromagnetic waves can travel in the absence of a medium. They travel at the speed of 3x\(10^{8}\)m/s. Thus, only option C is right.

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Complete question:-

Which of the following are the characteristics of electromagnetic waves?

1. They are elastic waves.

2. They can also move in a vacuum.

3, They have electric and magnetic components which are mutually perpendicular.

4, They move with a speed equal to 3 lakh meters per second.

Select the correct answer using the code given below :

A) 1, 2, 3 and 4

B) 1, 2, and 4

C) 2 and 3 only

D) 3 and 4 only

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

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F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

The difference of time between a sound from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall would be 0.036s.

An echo is a reflection of sound that comes to the audience with a delay after the direct sound in audio signal processing and acoustics. The delay is directly proportionate to the separation between the source and the listener of the reflecting surface. One the kind audio effect that involves significantly delaying a signal is an echo effect. In this instance, after some period of time, listeners hear the same signal repeated clearly. When there is a noticeable delay in the sound, listeners can differentiate individual echoes.

The person seated in the middle row:

The distance sound traveled to middle row => 25/2 = 12.5m

The total distance the sound traveled to full length of auditorium and to the middle row => 25+12.5 => 37.5m

t1 => d1/v => 12.5/343 => 0.036s

t2 => d2/v => 25/343 => 0.072s

t2-t1 => 0.036s

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Answer:

False

Explanation:

they just what they spent money on and thats not all of it

Answer:

30watts

Explanation:

P = IV = 5 x 6 = 30watts

As a result, the sound at the specified distance has a 47.16 W/m2 intensity.

The intensities of the a wave is the amount of energy it transports over a surface in a unit of time and size. It is also equal to the power density times the wave speed. Watts per sq m are typically used to measure it.

P =3.59×10⁵  W, the jet engine's power; and r = 40.9 m, the sound's distance

The following formula is used to determine the sound's intensity at the specified distance;

I = P/ A

where;

I is the sound's amplitude, while P is its power.

A is the circumference of the area

I = P / 4πr²

I = 3.59×10⁵  / 4π (40.9m)²

I = 47.16 W /m².

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Answer:

Frictional force will be 150N

The kinetic energy of the electron just as it reaches the positive plate is \(6 * 10^{-15} J\)

1.55 cm, or 0.015 metres, separates the plates=d

E = the size of the electric field between the capacitor's plates=\(2.5 * 10^{6} V/m\)

q is the size of the electron's charge= \(1.6 *10^{-19} C\)

Electric field-induced force on the electron is expressed as

\(F = q EF = (1.6 * 10^{-19}) (2.5 *10^{6})F = 4 * 10^{-13 }N\)

Initial electron kinetic energy at the negative plate is 0 J, or KE₀

Final electron kinetic energy at a positive plate is expressed as KE

Using work-change in kinetic energy

F d = KE - KE₀

\((4 * 10^{-13}) (0.015) = KE - 0\)

\(KE = 6 * 10^{-15} J\)

As a result, the electron's kinetic energy shortly before it encounters the positive plate is \(6 * 10^{-15} J\)

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88.5 m is the length of the pendulum. This an be solved using the concept of oscillation.

The process of any amount or measure repeatedly varying about its equilibrium position in time is referred to as oscillation. Another way to describe oscillation is as a periodic change in a substance's value between two values or around its midpoint.

Because oscillations are defined as a specific amount of movement of a solid body correlated to the distance travelled or the time required for it, oscillations and vibrations are not the same thing. The difference between the two is that vibration is the motion or change that oscillations induce in the body.

When small angles oscillate under the assumption that the supplied pendulum is oscillating, the oscillation time formula for a mathematical pendulum is:

T=2π × √(L/g)

or, L = (T/π)² × g

or, L = (290/π)² × 9.8

or, L = 88.5 meters

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Based on the provided initial velocity; The cliff was approximately 143.1 meters tall., The box fell approximately 54 meters away from the base of the cliff.

To find the height of the cliff, we can use the following kinematic equation for vertical motion:

y = y0 + v0_yt + 0.5a_y*t⁻².

where:

y = final vertical position

y0 = initial vertical position (0, since we start from the top of the cliff)

v0_y = initial vertical velocity (0, since the box is shoved horizontally)

a_y = vertical acceleration (9.81 m/s², due to gravity)

t = time (5.4 seconds)

Plugging in the values, we get:

y = 0 + 05.4 + 0.59.815.4²

y = 0.59.8129.16

y = 4.90529.16

y = 143.1 m

To find how far away the box fell from the base of the cliff, we can use the following equation for horizontal motion:

x = x0 + v0_x*t

where:

x = final horizontal position

x0 = initial horizontal position (0, since we start from the edge of the cliff)

v0_x = initial horizontal velocity (10 m/s)

t = time (5.4 seconds)

Plugging in the values, we get:

x = 0 + 10*5.4

x = 54 m

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