a toy cannon is fixed to a small cart and both move to the right with speed v along a straight track, as shown above. the cannon points in the direction of motion. when the cannon fires a projectile the cart and cannon are brought to rest. if m is the mass of the cart and cannon combined without the projectile, and m is the mass of the projectile, what is the speed of the projectile relative to the ground immediately after it is fired?
Answers
The speed of the projectile relative to the ground immediately after it is fired is determined as v.
What is the final speed of the projectile?The final speed of the projectile is obtained by applying the principle of conservation of linear momentum.
The law of conservation of linear momentum states that in an isolated system, the sum of the initial momentum is equal to the sum of the final momentum.
Pi = Pf
where;
Pi is initial momentum of the cannon and small cartPf is the final momentum of the projectilePi = mv
where;
m is the mass of the toy cannon and small cart combined v is the speed of the toy cannon and small cart combinedPf = Pi = mv
since mass of the projectile = m
The final speed is calculated as;
Pf = mv
v = Pf / m
v = mv / m
v = v
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Related Questions
a bulldozer pushed a large rock with a force of 5000 N at 2.0 m/s for 20s. how much work was done by the bulldozer
Answers
Answer:
It is 10KJoules
Explanation:
hope it helps
Do heavier bowling balls go faster than lighter ones?
Answers
Answer:
lighter ones will go faster
Explanation:
assuming you throw both bolwing ball with 10N of force. one is 3kg and the other is 5kg.
by using the equation: F = ma
a = F/m
a = 10/5 = 2m/s^2
a = 10/3 = 3.33333 m/s^2
HIII DROPPING COINS YALL
Answers
Answer:
tysm
Explanation:
Answer:
OMG THANK U SO MUCH I NEEDED THEMMMMM
A series RLC circuit has a resistance of 20 , a capacitance of 10-2 F, an inductance of 10 H and an applied voltage E(t) = 200 cos 5t Volts. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system.
Answers
The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.
To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.
First, let's calculate the resonant frequency (ω) of the circuit:
ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.
The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.
Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.
Now, let's find the impedance (Z) of the circuit:
Z = √(R^2 + (Xl - Xc)^2),
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
R = 20 Ω
Xl = ωL = 1 * 10 = 10 Ω
Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω
Plugging in these values, we get:
Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.
The amplitude of the current (I) can be calculated using Ohm's Law:
I = E / Z = 200 / 22.36 ≈ 8.94 A.
The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:
tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.
Therefore, Φ ≈ -0.464 rad.
The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.
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The diameter of a bullet and/or the barrel of a handgun are the:
jacket
gauge
caliber
profile
Answers
The diameter of a bullet and/or the barrel of a handgun are the C. caliber
Caliber is usually defined as the internal diameter of the gun barrel and the diameter of the projectile that travels through it. Therefore, caliber is a crucial factor in determining the suitability of a firearm for a particular application. Moreover, caliber is often used to describe the type of ammunition that a gun can use.In general, larger caliber firearms are more powerful, produce a louder sound when fired, and have a greater recoil than smaller caliber firearms.
Caliber is commonly expressed in inches or millimeters, depending on the system of measurement in use. For instance, 9mm Luger is a common caliber for handguns, while the 308 Winchester is a popular caliber for rifles. Hence, the diameter of a bullet and/or the barrel of a handgun are referred to as caliber. So therefore the correct answer is C. Caliber is the correct term for the diameter of a bullet and/or the barrel of a handgun.
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the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?
- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a
Answers
\(\\ \sf\Rrightarrow F=ma\)
Take a to leftAs it's multiplied on right side it will be divided on right side.\(\\ \sf\Rrightarrow \dfrac{F}{a}=m\)
Or
\(\\ \sf\Rrightarrow m=\dfrac{F}{a}\)
A +5.0−μC charge experiences a 0.41-N force in the positive y direction. If this charge is replaced with a −2.7−μC charge, find the magnitude of the force in this case.
Answers
Answer: r = 0.54m
Explanation: F=k(q1*q2)/r^2
Change micro charge by multiplying 10^-6
Manipulate the formula to find r.
r =√k(q1*q2)/F
r = √(8.99*10^9 N*m^2/c^2)(5.0*10^-6C)(2.7^10^-6C)/0.41N
r = 0.54m
True or false: Mass is a scalar quantity. * (10 Points)
Answers
Answer: True
Explanation:
A scalar quantity is those quantities that only have magnitude and no direction. Therefore the value doesn't change with direction.
If an object is thrown straight up and air resistance is negligible, then its speed when it returns to the starting point is the same as when it was released. If air resistance were not negligible, how would its speed upon return compare with its initial speed
Answers
If an object is thrown straight up and air resistance is negligible, then its speed when it returns to the starting point is the same as when it was released. If air resistance were not negligible, then its speed upon return would be less than its initial speed.
Air resistance is the frictional force that opposes the motion of an object as it moves through the air. The resistance of the air has an effect on the speed and direction of the object. This frictional force is the result of the collision of the object with air molecules.The resistance force is proportional to the square of the object's speed as it moves through the air. As the object moves faster, the resistance force becomes greater, which opposes its motion. If the object moves slowly, the resistance force becomes less because there is less kinetic energy to dissipate.
Therefore, if air resistance were not negligible, the speed of the object upon its return would be less than its initial speed. In fact, the object's speed would be reduced continuously during its ascent. When the object reaches its highest point, it would have zero speed momentarily, and then it would begin to accelerate downward. The air resistance would continue to oppose its motion as it fell back to the ground. In conclusion, the main answer to the question is the speed of the object upon its return would be less than its initial speed.
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if becke lines appear outside of the perimeter of glass than the glass has _____ refractive index.
Answers
If becks lines appear outside of the perimeter of glass than the glass has higher than the refractive index of the glass. refractive index.
What is perimeter?
A closed path that covers, encircles, or outlines a one-dimensional length or a two-dimensional shape is called a perimeter. A circle's or an ellipse's circumference is referred to as its perimeter. There are numerous uses in real life for perimeter calculations.
If the Becke line runs along the outside edge of the glass fragment, the surrounding medium's refractive index is greater than that of the glass.
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With what speed would mail pass through the center of the Moon if falling in a tunnel that runs through the center
Answers
Answer:
$v_f = = 7.9 \times10^3 \text{ m/s }$
g A small ferryboat is 3.70 m wide and 5.70 m long. When a loaded truck pulls onto it, the boat sinks an additional 4.80 cm into the river. What is the weight of the truck
Answers
The weight of the truck that pulls onto a small ferryboat that is 3.70 m wide and 5.70 m long and sinks an additional 4.80 cm into the river can be calculated as follows.Step 1: Calculate the volume of water displaced by the ferryboatThe volume of water displaced by the ferryboat is given by:V = Ah.
Where:A = the area of the base of the ferryboat (which is simply the product of its width and length)h = the height to which the ferryboat sinks into the water when the truck is loaded onto it.Therefore, the volume of water displaced by the ferryboat is:V = Ah = (3.70 m × 5.70 m) × (4.80 cm/100 cm) = 1.00 m³.
Step 2: Calculate the weight of the water displaced by the ferry boat Assuming that the density of water is 1000 kg/m³, the weight of water displaced by the ferryboat is:W = Vρwhere:ρ = the density of water = 1000 kg/m³Therefore,W = Vρ = 1.00 m³ × 1000 kg/m³ = 1000 kgStep 3: Calculate the weight of the truck.
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i don’t know the answer to 4395g=________kg
Answers
Answer:
4.395kg
Explanation:
1kg=1000g
Therefore, 4395g/1000g=4.395kg
2. What is the distance to a star, in parsecs, if its measured parallax (p) is 1/30 of an
arc second (use equation below)? What is its distance in light years? Show your
work!
Dist. (in pc) = 1/ Parallax (in arc sec)
Answers
The distance to the star, in parsecs, is 30 pc.
The distance to the star, in light years, can be calculated using the conversion factor of 3.26 light years per parsec. Therefore, the distance to the star in light years is approximately 97.8 light years.
The distance to a star can be determined using its measured parallax angle. Parallax is the apparent shift in the position of an object when viewed from two different points. It is measured in units of arc seconds.
The formula to calculate the distance to a star in parsecs is:
Distance (in pc) = 1 / Parallax (in arc sec)
Given that the measured parallax is 1/30 of an arc second, we can substitute this value into the formula:
Distance (in pc) = 1 / (1/30) = 30 pc
This gives us the distance to the star in parsecs.
To convert the distance to light years, we use the conversion factor of 3.26 light years per parsec. Multiplying the distance in parsecs by this conversion factor gives us the distance in light years:
Distance (in light years) = 30 pc × 3.26 light years/pc = 97.8 light years
Therefore, the distance to the star is approximately 30 parsecs or 97.8 light years.
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0.20 kg block is suspended from a vertically hanging spring it stretches the spring from its original length of 0.050m to 0.060 m. the same block is attached to the same spring and placed on a horizontal frictionless surface. The block is then pulled so that the spring stretches to a total length of 0.10 m. The block is released at time Band undergoes simple harmonic motion. What is the frequency of the motion?
Answers
Frequency of motion is 4.98 Hz.
Given that ;
Mass of bock (m) = 0.2 kg
As, vertically hanging spring it stretches the spring from its original length of 0.050m to 0.060 m
So, Change in length (∆x) = 0.06-0.06 = 0.01 meter
Applying Hooks Law ;
F = K∆x {where F is force} and {K is spring constant}
We know that F = mg {where, m and g are mass and gravitational force respectively}
Thus, mg = K∆x
K = mg/∆x
K = (0.2×9.8) /0.01
K = 196 N/m
Angular velocity, ω = \(\sqrt{\frac{K}{m} }\)
ω = \(\sqrt{\frac{196}{0.2} }\)
ω = 31.305 rad/s
For Frequency, F = ω/2\(\pi\)
F = 31.305/2π
F = 4.98 Hz
Hence ,frequency of motion is 4.98 Hz
What is simple harmonic motion-
repeated movement through a center, or equilibrium, position in physics where the maximum displacement on one side of the position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.
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- A periodic composite signal with a bandwidth of 2000 Hz is composed of two sine waves. The first one has a frequency of 100 Hz with a maximum amplitude of 20 V; the second one has a maximum amplitude of 5 V. Draw the bandwidth. - A TV channel has a bandwidth of 6MHz. If we send a digital signal using one channel, what are the data rates if we use one harmonic, three harmonics, and five harmonics?
Answers
The bandwidth of the periodic composite signal is drawn as a range between 100 Hz and 2100 Hz , The data rates for sending a digital signal using one harmonic, three harmonics, and five harmonics on a TV channel with a 6 MHz bandwidth would be 6 MHz, 18 MHz, and 30 MHz .
For the first question
Draw the bandwidth of a periodic composite signal, we need to consider the highest frequency component present in the signal.
We have two sine waves one with a frequency of 100 Hz and the other unspecified. Since the bandwidth is given as 2000 Hz, we can assume that the second sine wave has a frequency of 2100 Hz (2000 Hz above the first sine wave frequency).
Draw the bandwidth, we can create a graph with frequency on the x-axis and amplitude on the y-axis.
We plot the amplitude values for the two sine waves at their respective frequencies (100 Hz and 2100 Hz). The bandwidth will be the range between these two frequencies on the x-axis.
For the second question
The data rate for a digital signal transmitted using one harmonic, three harmonics, and five harmonics can be calculated by multiplying the channel bandwidth by the number of harmonics used. Since the bandwidth is given as 6 MHz, the data rates would be as follows:
One harmonic: 6 MHz
Three harmonics: 18 MHz
Five harmonics: 30 MHz
The data rate increases with the number of harmonics used because each harmonic contributes additional information to the signal, allowing for a higher data transmission rate.
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A traditional intersection is a place where ____ or more roadway users meet and cross a point
Answers
A traditional intersection is a place where two or more roadway users meet and cross a point.
In the given sentence, the phrase "two or more" indicates that a traditional intersection involves a minimum of two roadway users. These users can include vehicles, pedestrians, cyclists, or any other mode of transportation that utilizes the road network.
An intersection is a location where roadways intersect or cross paths. It is a point where different traffic streams converge and where the movement of vehicles, pedestrians, or cyclists may intersect or interact with each other.
By combining the phrase "two or more" with the definition of an intersection, it becomes evident that a traditional intersection is a point on the road network where two or more roadway users meet and cross paths. This definition encompasses the idea that multiple individuals or vehicles converge at a single point, requiring coordination and adherence to traffic rules and regulations.
In summary, a traditional intersection is a location on the road network where two or more roadway users, such as vehicles, pedestrians, and cyclists, meet and cross paths. It serves as a point of convergence where different traffic streams intersect and necessitates coordination among the various users to ensure safe and efficient movement.
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A patient brings in a new prescription for tetracycline 500 mg, what is the best practice at data entry?
Answers
When a patient brings in a new prescription for tetracycline 500 mg
The best practice at data entry would be
Ask for her date of birth and phone numberAsk if she has any allergiesCheck if you have the medication in stockUses of tetracycline
Tetracycline is used to treat a wide variety of infections, including acne. It is an antibiotic that works by stopping the growth of bacteria. This antibiotic treats only bacterial infections. It will not work for viral infections (such as common cold, flu).
Using any antibiotic when it is not needed can cause it to not work for future infections. Tetracycline can also be used in combination with anti-ulcer medications to treat certain types of stomach ulcers.
Tetracycline works best when taken on an empty stomach 1 hour before or 2 hours after meals. If stomach upset occurs, ask your doctor if you can take this medication with food. Take each dose with a full glass of water (8 ounces or 240 millilitres) unless your doctor directs you otherwise. Do not lie down for at least 10 minutes after taking this medication. For this reason, do not take it right before bedtime.
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why should we change worn out tyres
Answers
Answer:
Your vehicle's tires work hard every time you go on the road. As they age, they become more and more worn down, especially if you use the same set of tires year round. As a result, your tires will need to be replaced. ... If you are driving on a dirt road, or one that is worn, chances are you will feel vibrations.
(342-30(B)) When IMC is installed through bored or punched holes in framing members, additional support requirements are not necessary. This applies to both wood and metal framing members.(True/False)
Answers
True. When IMC is installed through bored or punched holes in framing members, additional support requirements are not necessary, whether the framing members are made of wood or metal.
The National Electrical Code (NEC) requires that when metal framing is used, the IMC must be secured within 8 inches of each box, outlet, or junction, and it must be supported at least every 10 feet. When wood framing is used, the IMC must be secured within 8 inches of each box, outlet, or junction, and it must be supported at least every 4 1/2 feet. However, this support is intended to keep the pipe from becoming displaced, and not to provide additional support for the pipe.
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A flashlight equipped with new batteries produces bright, yellow-white light. As the batteries in the flashlight wear out, the bulb will
Answers
As the batteries in the flashlight wear out, the bulb will produce dimmer light or eventually no light at all.
The brightness and color of the light produced by a flashlight depend on the energy supplied by the batteries. When the batteries are new, they provide a sufficient amount of energy to the bulb, resulting in bright, yellow-white light. However, as the batteries wear out, their ability to supply energy decreases.
This reduction in energy supply will cause the bulb to produce dimmer light. Eventually, when the batteries are fully depleted, the bulb may not receive enough energy to emit any light at all. Therefore, as the batteries in the flashlight wear out, the brightness of the light will diminish and may eventually cease.
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I WILL MARK BRAINLIEST
Answers
Answer:
well I mean it would depend on where u live for this question that's the only reason I am confused.. I'm pretty sure it's A thi
Consider a weathered rock or soil particle lying on a slope. How will the gravitational force pulling the particle downward along the land surface vary with the inclination of the slope?.
Answers
The gravitational force pulling a weathered rock or soil particle downward along the land surface will decrease as the slope angle is lessened.
The gravitational force acting on a body is due to the mass of the object. If an object is falling straight down, the gravitational force acting on the body is given by,
W = m g
W = Weight / Force of gravity
m = Mass
g = Acceleration due to gravity
If the object falls through a slope, its acceleration will be less than 9.8 m / s² which is the value of g when it falls straight down. the value of acceleration will decrease as the angle of slope is decreased.
Therefore, the gravitational force pulling the particle will decrease with decrease in angle of slope.
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The small piston of a hydraulic lift has an area of 15 cm². A car weighing 45,000 N is placed on the 2500 cm² large piston. How much force is required on the small piston to lift the car?
Answers
Explanation:
I believe the answer is 12 N
What effect does changing plate separation and surface area have on your capacitor?
How does the addition of a dielectric effect the capacitance?
If charge Q is stored on a capacitor, what is the magnitude of positive charges stored on one plate? What is the magnitude of negative charges stored on the opposite plate?
For part 2 step 3, which capacitor stores less charges and why?
steps for this:
Q = c x v
C2: 3V x .05 = .15 C
C3: 3V x .15 =.45 C
Ceq = C2 + C3 = .45 + .15
q = .6 C
V = .6/.2 = 3V
Answers
The effect that changing plate separation and surface area has on your capacitor is that if the distance between the plates is increased then the capacitance of the capacitor will decrease. If the distance between the plates is decreased, then the capacitance of the capacitor will increase.
Similarly, if the surface area of the plates is increased, the capacitance of the capacitor will increase. If the surface area of the plates is decreased, the capacitance of the capacitor will decrease.The addition of a dielectric effect the capacitance by increasing the capacitance of the capacitor by a factor equal to the dielectric constant. The capacitance of the capacitor is given by the formula C = Kε0A/d Therefore, the capacitance of the capacitor increases.Charge Q is stored on a capacitor in such a way that there is an equal and opposite charge on each plate. If the magnitude of the charge on one plate is q, then the magnitude of the charge on the other plate is -q.
The capacitance of a parallel-plate capacitor is given by the formula:C = ε0A/dWhere:C = capacitance of the capacitorε0 = permittivity of free spaceA = area of the platesd = distance between the platesIf the distance between the plates is increased, then the capacitance of the capacitor will decrease. If the distance between the plates is decreased, then the capacitance of the capacitor will increase.If the voltage across the equivalent capacitor is 3V, the charge on the equivalent capacitor is given by:Q = CeqV = (0.2F)(3V) = 0.6CIf the charge on the equivalent capacitor is 0.6C, the charge on capacitor C2 is given by:q2 = C2V = (0.05F)(3V) = 0.15CIf the charge on the equivalent capacitor is 0.6C, the charge on capacitor C3 is given by:q3 = C3V = (0.15F)(3V) = 0.45CTherefore, the capacitor that stores less charge is capacitor C2, because its capacitance is smaller than the capacitance of capacitor C3.
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How to find final velocity and initial velocity and acceleration ? :(
Answers
Explanation:
Final velocity=Initial velocity+(acceleration×time)
4 ways to find initial velocity:
1) Initial velocity=Final velocity-(acceleration×time)
2) Initial velocity=(Distance/Time)-((acceleration×time)/2)
3) Initial velocity=√Final velocity-(2×(acceleration×distance))
4) Initial velocity=2(distance/time)-Final velocity
Total force = Mass×Acceleration
(F=ma)
Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds
Answers
Given that the velocity at any time t is
\(v(t)=t^2-9t+18\)Also, the time interval is from t = 0 to t = 8 seconds
The position at time t = 0 s is s(0) = 1 m towards right of zero.
The initial time is t = 0 s, so the initial velocity will be
\(\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}\)The final time is t = 8 s, so the final velocity will be
\(\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}\)The average velocity will be
\(\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}\)Thus, the average velocity is 14 m/s.
Part II:
The instantaneous velocity at time t =5 s will be
\(\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}\)The instantaneous speed is the magnitude of instantaneous velocity.
Thus, the instantaneous speed will be 2 m/s.
Part III:
The particle will move towards the right when v(t) > 0
The time intervals will be
\(\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}\)Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.
Part IV :
The particle will move faster if the acceleration, a(t) > 0
The particle will slow down if the acceleration, a(t) < 0
So, first, we need to find the acceleration, it can be calculated as
\(\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}\)For the particle moving faster,
\(\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}\)For particle slowing down,
\(\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}\)The total distance can be calculated as
\(\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}\)Here, the negative symbol indicates it is towards the left from zero.
The International Energy Agency defines energy access to include all of the following EXCEPT A first connection to electricity An increasing level of electricity consumption over time Access to clean cooking facilities Access to motorized transportation Question Adoption of a cookstove intervention in rural Bangladesh is extremely low. As a consultant to the UN, you are asked for your opinion on why this occurred. Which of the following is/are a plausible explanation(s)? The technology was not well maintained by users All of these answers are correct The stoves failed to take into account regional cooking preferences The stoves failed to take into account regional cooking preferences The chosen stove was too complicated for less well-educated users
Answers
The correct answer is: All of these answers are correct.
All the provided explanations can be plausible reasons for the low adoption of a cookstove intervention in rural Bangladesh. It is important to consider factors such as technology maintenance, regional cooking preferences, and the suitability of the chosen stove for the user's level of education.
All of these factors can significantly impact the acceptance and adoption of a new cooking technology.It would hinder their ability to effectively use and benefit from the intervention.
Considering these factors collectively provides insight into why the adoption rate remained low. Addressing these issues is crucial to improving the acceptance and success of cookstove interventions in rural communities.
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A current of 0.75 passes through a flashlight bulb that is connected to a 3.0-V battery. Calculate the bulb's resistance.
Answers
Answer:
4 ohms
Explanation:
Use Ohm's Law: V = IR
V = 3.0 V
I = 0.75 A
Plug thise values into the equation:
3.0 V = (0.75 A) R
---> R = 4 ohms
The resistance of the bulb when a current of 0.75 is passed when connected to 3.0 V battery is 4 ohms.
What is resistance?Resistance is the opposition to the flow of current through it.
Given is the current passing through the bulb is 0.75 Amperes and the voltage of the battery is 3.0 V, then according to the ohm's law,
V = IR
where R is the resistance of the bulb
3.0 V= 0.75 A× R
R = 4 Ω
The resistance of the bulb is 4 Ω.
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Use equation 11.27 to calculate the wavelength of the electronic transition in polyenes for n = 6, 8, and 10. comment on the variation of a with l, the length of the molecule.
Answers
Equation 11.27 can be used to calculate the wavelength of electronic transitions in polyenes for different values of n, such as n = 6, 8, and 10. The variation of a with l, the length of the molecule, can be observed and commented upon.
Equation 11.27, which is not provided here, likely relates to the mathematical expression used to calculate the wavelength of electronic transitions in polyenes. By applying this equation for different values of n (such as n = 6, 8, and 10), we can determine the corresponding wavelengths for the electronic transitions in polyenes with varying chain lengths.
By analyzing the results obtained from the calculations, we can comment on the variation of a with l, where a represents the wavelength and l represents the length of the molecule. This analysis will help us understand the relationship between the length of the polyene molecule and the wavelength of its electronic transitions. We may observe a pattern or trend indicating how the wavelength changes as the molecule lengthens.
Further analysis and interpretation of the calculated wavelengths and their relationship to the length of the molecule could provide insights into the behavior of electronic transitions in polyenes. It may help identify any systematic trends or deviations from expected patterns, leading to a better understanding of the structure and properties of polyene systems.
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