The angle between the airflow (relative wind) and the chord line of an aerofoil is:A) glide path angle.B) same as the angle between chord line and fuselage axis.C) climb path angle.D) angle of attack.

Answer:

To become ASE certified, you must pass an ASE test and have relevant hands-on work experience. The amount of work experience required can vary by test, and is specified in detail here. ASE recommends submitting the form after you've registered to take an ASE certification test.

Good luck!

Explanation:

Answer:  One theme in White Fang is adapting in order to survive. White Fang finally submits to Gray Beaver. He also copes with fighting other dogs. White Fang changes his behaviors so that he can live.

Explanation: its the sample response

Answer: Can't help

Explanation:

Answer:

Bcause if not the house would not have any thing to plugin or like have any internet

Explanation:

Type THHN/THWN conductors have a temperature rating of 90 degrees Celsius and generally meet the temperature requirement for connecting luminaires.

Type THHN/THWN conductors are commonly used in electrical wiring applications. THHN stands for Thermoplastic High Heat-Resistant Nylon, while THWN stands for Thermoplastic Heat and Water-resistant Nylon. These types of conductors are designed to withstand high temperatures and provide reliable electrical connections.

The temperature rating of 90 degrees Celsius indicates that these conductors can safely operate at temperatures up to 90 degrees Celsius without compromising their performance or safety. This temperature rating meets the requirement for connecting luminaires, which are fixtures used for lighting purposes.

THHN/THWN conductors are made of thermoplastic insulation materials with nylon coating, which enhances their heat resistance and electrical insulation properties. They are typically used for wiring installations in buildings, including residential, commercial, and industrial applications.

When connecting luminaires, which can generate heat during operation, it is important to use conductors with a suitable temperature rating to ensure safe and efficient electrical connections. The 90 degrees Celsius temperature rating of THHN/THWN conductors allows them to withstand the heat generated by luminaires and maintain reliable electrical conductivity.

Type THHN/THWN conductors with a temperature rating of 90 degrees Celsius are commonly used for connecting luminaires. These conductors provide a reliable and safe electrical connection, meeting the temperature requirements for luminaires and ensuring efficient operation without compromising their performance. When installing electrical wiring for lighting fixtures, it is crucial to choose appropriate conductors that can withstand the heat generated by the luminaires to ensure the safety and reliability of the electrical system.

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Answer:

there is someone inside the car

The exhaust section of a turbine engine is designed to efficiently discharge the hot gases produced during the combustion process.

The exhaust section of a turbine engine plays a crucial role in the overall engine performance and operation. Its primary purpose is to effectively and safely remove the high-temperature and high-pressure combustion gases from the engine after they have performed work on the turbine blades.

The design of the exhaust section aims to achieve several objectives. Firstly, it must ensure the smooth and efficient flow of exhaust gases to minimize backpressure, which can impede engine performance. This involves optimizing the geometry and shape of the exhaust ducts and nozzles to facilitate the smooth expansion and acceleration of the exhaust gases.

Secondly, the exhaust section is responsible for directing the hot gases away from the aircraft or vehicle, ensuring they are safely discharged into the atmosphere without causing damage or posing a risk to surrounding structures or components.

Additionally, the exhaust section may incorporate features such as noise-reducing components or afterburners, depending on the specific engine design and requirements.

Overall, the design of the exhaust section of a turbine engine aims to balance performance, safety, and efficiency by effectively handling and discharging the high-temperature exhaust gases generated during the combustion process.

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Answer:

15 000 000 Ohms

Explanation:

1 Mega Ohm = 1 000 000 Ohms

So,

15 Mega ohms =15 000 000 Ohms

The weight of the bike and the cyclist is an upward and downward force that the Earth applies to both of them.

When we step on the pedals, the back wheel receives the force and transmits it to the ground. Strength of the effect. The pavement reacts by applying force to the back wheel in the same direction but in the opposite direction. Therefore, always take action. As a result, reduced friction makes riding and walking possible. The pressure exerted by the tire on the ground causes friction, which keeps the lowest portion of the wheel firmly planted on the ground and prevents the tire from turning. This force is transmitted to the wheel axle and used to drive the wheel. The transmission forces transfer the pedal-pushing force from the crank arm to the chainring axis.

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Answer:

Made of Silicon.

Explanation:

A diode is a semiconductor device use in mostly electronic appliances. It is two terminals device consisting of a P-N junction formed either in Germanium or silicon crystal.

Diode can be forward biased or reverse biased.

When a diode is forward biased and the applied voltage is increased from zero, hardly any current flows through the device in the beginning.

It is so because the external voltage is being opposed by the internal barrier voltage whose value is 0.7v for silicon and 0.3v for germanium.

If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.

The present cost of maintenance for the new equipment across 4 years is $12,266.01.

The formula for calculating a growing annuity is as follows:

where M = the first payment, g = the growth rate, r = the discount rate, and N = the number of payments.

According to the question,

The first payment is = 275

The growth rate is = 0.5%.

The discount rate is = 0.75%.

The number of payments in 4 years = 4*12 = 48.

Now, put all values in the above equation:

\(\frac{275}{0.75 - 0.5}\)  \((1- (\frac{1+0.5}{1+0.75} )^4^8)\) = 12.366.01.

Therefore, the present cost of maintenance for the new equipment across 4 years is $12,266.01.

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Answer:

1) Make a hypothesis, about what u think will happen if you do something

2) conduct the experiment

3) analyze and see what happens

4) do it several more times and  compare ur answers

5) make a conclusion from ur answers

6) celebrate bc u done

The zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.

You would definitely identify zero-force members in a truss by the fact that a joint has only two non-collinear members and there is no external load or support reaction at that joint, then those two members are zero-force members.

Zero-force members in a truss are the structural members that significantly support no loading but aid in the stability of the truss.

Therefore, the zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.  

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Answer:

Air-cooled direct expansion coils operating below the dewpoint may produce condensate or water along with cool air.

Explanation:

The <111> family of directions includes four directions: <111>, <1-1-1>, <11-2>, and <1-12>.

To find the planes parallel to the (110) plane, we need to use the Miller Indices of the (110) plane, which are (1 1 0).

Using the algorithm for determining Miller Indices of a plane:

We can choose any point on the plane, but for simplicity, let's choose the origin.

The plane intercepts the x, y, and z axes at (1,0,0), (0,1,0), and (0,0,1), respectively, since it passes through the points (0,0,0) and (1,1,0).

Taking the reciprocals of these intercepts, we get (1/1, 1/1, 1/0) = (1, 1, ∞).

Normalizing by multiplying by the lattice parameters a, b, and c, we get (a, b, ∞). Since we do not know the value of c, we cannot normalize the third index.

To reduce to smallest integer values, we take the reciprocals of the indices and multiply by a common factor to get integers. Since the third index is infinity, we can ignore it. Taking the reciprocals of the first two indices, we get (1/1, 1/1, 1/1/2) = (1, 1, 2).

Enclosing the indices in parentheses, we get the Miller Indices of the (110) plane: (1 1 0).

Now, to find the planes parallel to the (110) plane, we need to find the directions that are perpendicular to the (110) plane. We know that the normal vector to the (110) plane is <1 1 0>, so any direction that is perpendicular to this vector will lie in a plane parallel to the (110) plane.

The four <111> family directions that are perpendicular to <1 1 0> are <11-2>, <1-12>, <-112>, and <-1-1-2>. These four directions lie in a plane that is parallel to the (110) plane.

Note that <111> and <1-1-1> do not lie in a plane parallel to the (110) plane.

Explanation:

The <111> family of directions includes four directions: <111>, <1-1-1>, <11-2>, and <1-12>.

To find the planes parallel to the (110) plane, we need to use the Miller Indices of the (110) plane, which are (1 1 0).

Using the algorithm for determining Miller Indices of a plane:

We can choose any point on the plane, but for simplicity, let's choose the origin.

The plane intercepts the x, y, and z axes at (1,0,0), (0,1,0), and (0,0,1), respectively, since it passes through the points (0,0,0) and (1,1,0).

Taking the reciprocals of these intercepts, we get (1/1, 1/1, 1/0) = (1, 1, ∞).

Normalizing by multiplying by the lattice parameters a, b, and c, we get (a, b, ∞). Since we do not know the value of c, we cannot normalize the third index.

To reduce to smallest integer values, we take the reciprocals of the indices and multiply by a common factor to get integers. Since the third index is infinity, we can ignore it. Taking the reciprocals of the first two indices, we get (1/1, 1/1, 1/1/2) = (1, 1, 2).

Enclosing the indices in parentheses, we get the Miller Indices of the (110) plane: (1 1 0).

Now, to find the planes parallel to the (110) plane, we need to find the directions that are perpendicular to the (110) plane. We know that the normal vector to the (110) plane is <1 1 0>, so any direction that is perpendicular to this vector will lie in a plane parallel to the (110) plane.

The four <111> family directions that are perpendicular to <1 1 0> are <11-2>, <1-12>, <-112>, and <-1-1-2>. These four directions lie in a plane that is parallel to the (110) plane.

Note that <111> and <1-1-1> do not lie in a plane parallel to the (110) plane.

Yes, I have prototyped an idea.

How to prototype an idea?

STEP-1 Create Your Ideas Now: Here are some initial steps you may take to speed up the idea-generation process. Conduct in-depth research Know the market value, potential rivals, manufacturing method, and overall cost of your goods.

STEP-2 Make a Simplified Version of Your Idea: Making a straightforward representation of your idea would be the next step after conducting considerable research and settling on an idea.

STEP-3 Make a Realistic Prototype: You actually start working on your prototype at this point.

STEP-4 Develop Your Prototype Until It Is Perfect: The hardest and longest phase of them all is this one.

Hence, the prototype of an idea is given.

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From the information, let us list the parameters given to solve for the diameter of the pipe.

Given that:

= 2600 kg/m³

Using the standard conversion rates:

Since 1 lbf/in² = 6894.76 N/m²

∴

From the given information, let's start by determining the volumetric flow rate of the liquid in the pipe:

\(\mathbf{The \ volumetric \ flow \ rate \ ( Q) = \dfrac{mass \ flow \ rate}{density \ of \ the \ liquid}}\)

\(\mathbf{Q = \dfrac{0.882 \ kg/s}{2600 \ kg/m^3}}\)

Q = 0.00034 m³/s

In a cylindrical flow pipe, using the formula for the pressure drop to estimated the pipe diameter, we have:

\(\mathsf{\dfrac{\Delta P}{\rho g}= \dfrac{8fLQ^2}{\pi^2gd^5}} --- (1)\)

where (f) can be computed as;

\(f = \dfrac{64}{\dfrac{\rho vd}{\mu}}\)

\(f = \dfrac{64}{\dfrac{\rho Qd}{A\mu}}\)

replacing the values from the above-listed parameters, we have:

\(f = \dfrac{64}{\dfrac{2600 \times 0.00034 \times d}{\dfrac{\pi}{4}(d)^2 \times 0.002}}\)

\(f = \dfrac{64}{2600 \times 0.00034 \times d} \times \dfrac{\dfrac{\pi}{4}(d)^2 \times 0.002}{1}\)

f = 0.1137d

From equation (1), Recall that:

\(\mathsf{\dfrac{\Delta P}{\rho g}= \dfrac{8fLQ^2}{\pi^2gd^5}}\)

\(\mathsf{\dfrac{\Delta P}{\rho }= \dfrac{8fLQ^2}{\pi^2d^5}}\)

Replacing the values, we have;

\(\mathsf{\dfrac{1261.74}{2600}= \dfrac{8\times 0.1173(d) \times (2784) \times (0.00034)^2}{\pi^2(d)^5}}\)

\(\mathsf{0.48528= \dfrac{2.966\times 10^{-5}}{(d)^4}}\)

\(\mathsf{d^4= \dfrac{2.966\times 10^{-5}}{0.48528}}\)

\(\mathsf{d^4= 6.11193538 \times 10^{-5}}\)

\(\mathbf{d = \sqrt[4]{ 6.11193538 \times 10^{-5}}}\)

d = 0.0884 m

d = 88.4 mm

since 1 mm = 0.0393701 inch

∴

88.4 mm will be = 3.48 inches

Therefore, we can conclude that the diameter of the pipe = 3.48 inches

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Machine building is one part of a larger production group that also includes the production of metal goods and machine building and metalworking.

The process of designing and manufacturing machines for a specific purpose—usually the production of a product or an upgrade to an existing device—is known as machine building.

Tools and fabrication equipment, such as metalworking machines, polishing machines, presses, boilers, industrial ovens, and industrial scales; industrial machinery and equipment; hardware and parts like valves, pneumatic hoses, nuts and bolts, springs, and screws and.

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Answer:

Question 1 A 1020 Cold-Drawn steel shaft is to transmit 20 hp while rotating at 1750 rpm. Calculate the transmitted torque in lbs. in. Ignore the effect of friction. Answer with three decimal points. 60.024 Question 2 Based on the maximum-shear-stress theory, determine the minimum diameter in inches for the shaft in Q1 to provide a safety factor of 3. Assume Sy = 57 Kpsi. Answer with three decimal points. 0.728 Question 3 If the shaft in Q2 was made of ASTM 30 cast iron, what would be the factor of safety? Assume Sut = 31 Kpsi, Suc = 109 Kpsi 0 2.1 O 2.0 O 2.5 0 2.4 2.3 O 2.2

Explanation:

hope it helps

When troubleshooting an engine for too rich mixture to allow the engine to idle, the possible cause could be that there is a misadjusted carburetor.

This means that the air/fuel mixture is not adjusted properly and is allowing too much fuel into the engine, causing it to run rich. Another possible cause is that the fuel system may be clogged or dirty, causing the fuel to not be delivered properly to the engine. This can cause the engine to idle poorly and run rich.There are a few things that can be done to troubleshoot this issue.

The first step is to check the carburetor and make sure that it is adjusted properly. The air/fuel mixture should be adjusted so that the engine is running at the correct RPM and there is no hesitation or misfire. If the carburetor is misadjusted, it will need to be corrected.

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Almost all of the atoms that make up our bodies were once found inside stars.We would not be here if it weren't for galaxies' ability to recycle material from one star generation to the next.

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Answer:

1218.75

Explanation: If he makes a 25% profit, he needs to sell it for 125% of the computer price. 1.25*975 is 1218.75

A marble column with a cross-sectional area that can support 25,000 kg.

The stress inside the column is 208333.33 N/(m^2). The strain is equal to 4.166 * 10^(-6)

Taking g=10,

a) Stress = (25000*10)/1.2 = 208333.33 N/(m^2)

b) Young's Modulus of Marble = 50 * 10^9

Strain = 4.166 * 10^(-6)

Stress is defined as a force per unit area within a material that results from externally applied forces, unequal heating, or persistent deformation and that enables an accurate description and prediction of elastic, plastic, and fluid behavior in physical sciences and engineering. By dividing a force by an area, stress is expressed.

Various forms of stress exist. Shear stress is caused by forces that are parallel to and lay in the plane of a cross-sectional area of the material, as opposed to normal stress, which is caused by forces that are perpendicular to the area. The typical tension inside a bar with a cross-sectional area of 4 square inches (26 square cm) will increase if the bar is pulled lengthwise by 40,000 pounds (180,000 newtons) of force at each end.

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The vertical reinforcing steel requirement for an 8" thick masonry foundation wall that is 7'6" high, supporting 6'6" of unbalanced backfill with a lateral load of 60 psf is #5 at 48" o.c. The correct option is 3.

The minimum vertical reinforcing steel requirement for a foundation wall is determined by the height of the wall, the thickness of the wall, the load on the wall, and the unbalanced backfill. The minimum size and spacing of vertical reinforcing bars in a masonry wall are specified in ACI 530-11/ASCE 5-11/TMS 402-11. The vertical reinforcing steel requirement for a masonry foundation wall is determined by the formula:

A = (0.0025hd) / s where A is the area of vertical reinforcement (\(in^{2} /ft\)), h is the height of the wall (ft), d is the effective thickness of the wall (ft), and s is the spacing of the bars (in).

The minimum area of vertical reinforcement should not be less than 0.0025 times the product of the height and effective thickness of the wall. The minimum spacing of vertical bars is 48 inches or the thickness of the wall, whichever is less.

For an 8" thick wall with a height of 7'6" and a lateral load of 60 psf, the minimum area of vertical reinforcement is:

0.0025 × 7.5 × 0.67 = 0.0126 (\(in^{2} /ft\)).

The minimum size of the vertical bar is #5 (0.162 in2).

Therefore, the minimum number of bars required is:

0.0126 / 0.162 = 0.0777, which is rounded up to 0.08.

Thus, the minimum spacing of vertical bars is 12 / 0.08 = 48 inches. Therefore, the minimum vertical reinforcing steel requirement is #5 at 48 inches o.c., which is option 3.

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Answer:

The risks associated with the handling of liquid hydrogen are fire, explosion, asphyxiation and extremely low temperature exposure.

Answer:

fire, explosion, asphyxiation, extremely low temperature exposure/cold burns

Explanation:

3 ohms hope this helps :D ❤

Answer:

3 ohms

Explanation:

Answer:

Technician be says that diesel engines produce more power because they use excess air to burn feel who is correct

Explanation:

He is correct as many engines are run by diesel. It produces more power as that is how cars produce more power.

Explanation:

D the answer is D and anyone can answer this Question

Based on the provided options, the scientific expression that is the same as 1545.5347 is 154553.4e3. Therefore, the correct option is option D.

A scientific expression, often known as scientific notation, is a method of representing extremely big or extremely small integers. It is often used to simplify the representation of such numbers in scientific and mathematical operations. A number is expressed in scientific notation as a product of two parts: a coefficient and a power of ten.

The coefficient is a value between 1 and 10, and the power of 10 determines how far the decimal point should be moved. The "e3" signifies multiplying the integer by 10 raised to the power of 3, which is similar to moving the decimal point three places to the right in this formula. As a result, 154553.4e3 equals 154553.4103, which simplifies to 154553400.

Therefore, the correct option is option D.

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Answer:

Dust, dirt, or metal chips can pose a potential eye injury risk in a shop.

Explanation: