Answer:
Explanation:
Think about the equation for velocity. Its the change in position over the change in time. And now think about the formula for slope, its the change in y over the change in x. Now, if you have a position vs time graph, the slope is position over time, the direct formula for velocity. Therefore, the slope of a position vs time graph gives the velocity in that interval. You could take the derivative at that point and get the instantaneous velocity.
In the first argument, the only way to get a negative slope is if youre moving to the left of your initial position as you pass through time. So the claim isnt necessarily true. When you move away from the origin, that simply means youre moving through time.
In the second argument, a horizontal slope means the value is 0. That means there is a value of 0 for your velocity, aka standing still.
In the third argument, a positive slope means youre moving to the right of your initial position as you go through time.
The fourth one is incorrect. Speed is the magnitude of velocity, and the slope can be determined an any point besides vertical slopes, which would require time to literally stop.
I dont understand the very last part of what you posted, so try to make a decision based on what I just explained to you
Answer:
The answer should be
"A positive slope results when an individual is moving away from the origin."
Also known as C on ed 2020
Explanation:
I hope you get this right even tho I may be late, but to all the others who have this question. Stay safe!!!!
Why is there more pressure the deeper you go in water?
I think because water gives pressure and if u go even deeper theres more pressure
Sound cannot travel without medium write on the basis of the following points (materials required) (procedure) (conclusion
Explanation:
Because it is a mechanical wave and it need material medium to travel through it.
Since the investigative question has two variables, you need to focus on each one separately. Thinking only about the first part of the question, mass, what might be a hypothesis that would illustrate the relationship between mass and kinetic energy? Use the format of "if…then…because…” when writing your hypothesis.
In order to form a hypothesis that would illustrate the relationship between mass and kinetic energy, we first need to understand what kinetic energy and mass are and how they are related. Kinetic energy is the energy that an object possesses due to its motion, and is given by the formula KE = 0.5mv², where m is the mass of the object and v is its velocity. Mass, on the other hand, is a measure of the amount of matter in an object.
The relationship between mass and kinetic energy is direct, meaning that as mass increases, so does kinetic energy, provided that velocity remains constant. Similarly, if velocity increases, then kinetic energy will increase as well, provided that mass remains constant.
The hypothesis that illustrates this relationship can be stated as follows:If the mass of an object is increased, then the kinetic energy of the object will also increase, because kinetic energy is directly proportional to mass, assuming velocity remains constant.In other words, if the mass of an object is doubled, then its kinetic energy will also double, assuming that its velocity remains constant. This hypothesis can be tested through experiments that involve measuring the kinetic energy of objects with different masses, but with the same velocity.
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If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.
Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct terms.
The correct terms that fills the box are;
(i) The incident ray
(ii) The normal
(iii) The reflected ray
(iv) The angle of incident
(v) The reflected angle
What is the terms of the ray diagram?The terms of the ray diagram is illustrated as follows;
(i) This arrow indicates the incident ray, which is known as the incoming ray.
(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.
(iii) This arrow indicates the reflected ray; the out going arrow.
(iv) This the angle of incident or incident angle.
(v) This is the reflected angle or angle of reflection.
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Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan
SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-
They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.
Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.
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A dishwasher has a power rating of 1200 W. Work out how long it would take to transfer 480 kJ of energy.
The dishwasher would need to transfer 480 kJ of energy for 400 seconds, or 6 minutes and 40 seconds.
How are power and force related?Power is determined by the product of force, velocity, and distance traveled (in the force's direction). For those looking to enter the teaching profession in the state of Uttar Pradesh, this is a fantastic opportunity. Voltage and current together produce electrical power P=VXI.
time = energy / power
480 kJ = 480,000 J
time = energy / power
time = 480,000 J / 1200 W
time = 400 seconds
Hence, for the dishwasher to transfer 480 kJ of energy, it would take 400 seconds, or 6 minutes, 40 seconds.
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Infrared telescopes are usually placed on high-flying airplanes or on satellites in space __________
Answer:
In order to improve visibility
Explanation:
Infrared telescopes are made using infrared cameras that contain infrared detectors which are solid-state and are maintained at very cold (cryogenic) temperatures
Infrared radiation is absorbed by water vapor which is present in the Earth's atmosphere, leading to the limitation of the use of infra red telescopes at high altitudes such as mountains, high flying planes or satellites
If an asteroid that is 50 meters in diameter strikes the earth, the result is likely to be.
Answer:
Not as big as the previous asteroid that whipped out the dinosaurs
Suppose a car travels at a constant speed of 12.0 m/s. How far would it move in 3600.0 s?
Answer:
43200 m
Explanation:
speed = 12.0 m/s
time = 3600.0 s
distance = speed * time
distance = 12.0 m/s * 3600.0 s
distance = 43200 m
Q3. A space probe is traveling in outer space with a momentum that has a magnitude
of . A retrorocket is fired to slow down the probe. It applies a force to
the probe that has a magnitude of and a direction opposite to the probe’s
motion. It fires for a period of 12 s. Determine the momentum of the probe after the
retrorocket ceases to fire
The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s
What is the momentum?We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.
According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.
We know that;
\(F_{t}\) = \(p_{f}\) -\(p_{i}\)
F = force
t = time taken
\(p_{f}\)= final velocity
\(p_{i}\) = initial velocity
\(p_{f}\) = \(F_{t}\) + -\(p_{i}\)
\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7
\(p_{f}\) = 2.4 * 10^7 + 7.5 * 10^7
\(p_{f}\) = 9.9 * 10^7 Kg m/s
Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.
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Missing parts;
A space probe is traveling in outer space with a momentum that has a magnitude of 7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0 * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.
How much heat does it take to raise the temperature of 5.0 kg of plastic from 15°C to 75°C? The specific heat of plastic is 2.60 kJ/(kg × °C).
where
m is the mass
c is the specific heat capacity
ΔT is the change in temperature
In your problem,
m=2.5 kg
c=2.60 kJ⋅°C-1kg-1
Δ
∴ q=2.5kg×2.60 kJ⋅°C-1⋅kg-1×60°C=390 kJ
At what point between earth and the moon will a 50,000kg space probe experience no net force
A space probe weighing 50,000kg will experience no net force between the Earth and the Moon when it is at a point in space called Lagrange point L1.What is Lagrange point L1?The first Lagrange point (L1) is a location in space where the gravitational forces of the Earth and the Moon balance out.
At this point, an object such as a satellite can remain relatively stationary with respect to both bodies.The L1 point is approximately 1.5 million km from the Earth, in the direction of the Moon, and it orbits the Sun along with the Earth and the Moon. It is a popular location for observing the Sun, as a satellite placed at this point can maintain a constant position relative to the Sun without being obscured by the Earth or the Moon.How can you find Lagrange point L1?To find the L1 point, you need to solve for the point in the Earth-Moon system where the gravitational forces of the two bodies cancel out. This point can be found by solving for the gravitational forces of the Earth and the Moon using Newton's Law of Universal Gravitation and setting them equal to each other.There are no net forces at the Lagrange points because the gravitational forces of the Earth and Moon are balanced out by the centrifugal force of the object orbiting the Earth-Moon system. This means that a space probe weighing 50,000kg will experience no net force when it is at the L1 point between the Earth and the Moon.
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HELP PLEASE I'M GONNA FAIL!!! pls help
In a short-answer response, thoroughly describe what free-body diagrams are used for and what the free-body diagram is telling us about the directions of the forces.
Make sure to include which direction the object will move and give an example of what that object could be. (examples: box, soccer ball, rope in a tug-of-war, etc.)
Free body diagrams are used in mechanics problems to illustrate forces and moments applied to a body and to compute reactions.
What is a Free Body diagram?The relative strength and direction of all forces operating on an object in a specific circumstance can be depicted using free body diagrams (FBDs), which are helpful tools. The careful creation of a free-body diagram is a prerequisite for the analysis and description of the majority of physical processes. In a free body diagram, the size of the arrow represents the force's magnitude, while the direction of the arrow represents the way it acts.
These diagrams are widely used to compute internal forces within a structure, as well as to determine the loading of certain structural components.
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Convert the following as instructed:
i.340 cm into m
ii.67 kg into g
iii.2 days into second
iv.86400 second into day
newtons law of gravitation is called a universal law why
Answer:
it is applicable on all bodies having mass and the bodies Will be governed by the same law
The speed of a transverse wave on a string is 130 m/s when the string tension is 116 N. To what value must the tension be changed to raise the wave speed to 180 m/s
The tension in the string must be changed to 508 N to raise the wave speed to 180 m/s.
The wave speed on a string is given by the equation:
v = sqrt(T/μ)
where v is the wave speed, T is the tension in the string, and μ is the linear density of the string.
To find the new tension required to achieve a wave speed of 180 m/s, we can rearrange the equation as:
T = μv^2
We can use the given information to find the initial value of μ:
130 m/s = sqrt(116 N / μ)
Solving for μ, we get:
μ = 0.002938 kg/m
Now we can use this value of μ to calculate the new tension required to achieve a wave speed of 180 m/s:
T = (0.002938 kg/m) x (180 m/s)^2
T = 508 N
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a) Megan was doing time-trials on her bike around a 400 metre horizontal track.
She took seconds to travel 400m.
1.What was her average speed? Give the unit.
2.Compare the forward force on the bike with the backwards force on the bike when Megan was travelling at a constant speed
B) Megan then crouched down over on the bike with the backward force on the bike when Megan was travelling at a constant speed.
1.Compare the forward and backward forces on Megan and her bike now.
2.Explain your answer.
A
1. Megan's average speed is (400/seconds) m/s
The unit for average speed is meters per second (m/s).
2.
When Megan is traveling at a constant speed, the forward force on the bike is equal in magnitude and opposite in direction to the backward force on the bike according to Newton's Third Law of Motion.
B)
1.When Megan crouches down over the bike while traveling at a constant speed, the forward force on the bike remains the same, but the backward force on the bike decreases.
2. The explanation can be seen as the forward force on Megan and her bike remains the same, as Megan's pedaling action is the same as before.
The backward force on Megan and her bike decreases because of the reduction in surface area facing the direction of motion resulting in a net forward force on Megan and her bike, which increases their acceleration and speed.
What is to Newton's Third Law of Motion?Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction.
In the case of Megan, the forward force on the bike is generated by the pedaling action of Megan, while the backward force on the bike is due to air resistance and frictional forces acting against the motion of the bike.
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The last frame before the shuttle begins tomove is 140. The shuttle travels 56meters in 243 frames.(a) If each frame is 24 seconds what is thetime elapsed?(b) Assuming constant acceleration, at whatrate is the shuttle accelerating?(c) If the shuttle continued to move with thisacceleration, what speed would it reach 76s after launch?(d) If the shuttle traveled directly upwards, what would its altitude be at 76 s?
A) if each frame is 24 seconds long and there 243 frames, the total time that elapses is 243 times 24, which equals 5832 seconds.
B) For this, we will need to use kinematics
inital velocity = 0 m/s
time = 5832 seconds
distance = 56 meters
acceleration = ?
We can use the formula
Pleasssseeee helpppp i will mark brainlest
Answer:
the second and the third
Explanation:
the maximum daylight hours is the second, and the warmest temperatures for the northem hemisphere.
please helps i need help xC
a bumblebee is flying towards a flower in a straight line at 4.09 m/s when it begins to accelerate at 1.01 m/s^2 how long does it take the bee to reach the flower if its 23.4 meters away
The time taken for the bumblebee to the reach the flower is 3.87 s.
What is the time of motion of the bumblebee?
The time taken for the bumblebee to the reach the flower that is 23.4 m away is calculated by applying the following equation as shown below.
s = vt + ¹/₂at²
where;
t is the time of motion of the bumblebeev is the initial velocity of the bumblebeea is the acceleration of the bumblebees is the distance travelled by the bumblebeeThe time taken for the bumblebee to the reach the flower is calculated as;
23.4 = 4.09t + ¹/₂(1.01)t²
23.4 = 4.09t + 0.505t²
0.505t² + 4.09t - 23.4 = 0
solve for t using formula method,
t = 3.87 seconds
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The American bullfrog (Rana catesbeiana) can jump a distance of
nearly 15 times its length! If a bullfrog starts on a horizontal log and
leaps with a velocity of 4.40 m/s at an angle of 37.0° to the horizontal,
what distance can it cover?
Answer:
Approximately \(1.90\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the bullfrog is negligible.)
Explanation:
It is given that the initial velocity \(u\) is at an angle of \(\theta = 37.0^{\circ}}\) above the horizontal. Therefore:
Initial vertical velocity: \(u_{y} = u\, \sin(\theta) \approx 2.64799\; {\rm m \cdot s^{-1}}\).Initial horizontal velocity: \(u_{x} = u\, \cos(\theta) \approx 3.51400\; {\rm m \cdot s^{-1}}\).
If air resistance on the bullfrog is negligible, final vertical velocity right before landing will be the opposite of the initial vertical velocity:
\(v_{y} = (-u_{y}) = (-2.64799)\; {\rm m\cdot s^{-1}}\).
Change in vertical velocity:
\((v_{y} - u_{y}) = (-2.64799) \; {\rm m\cdot s^{-1}} - 2.64799 \; {\rm m\cdot s^{-1}} \approx (-5.29598)\; {\rm m\cdot s^{-1}}\).
Vertical acceleration of the bullfrog will be \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\) while the frog is in the air. Therefore, time required for the velocity to change will be:
\(\begin{aligned} t &= \frac{v_{y} - u_{y}}{a_{y}} \\ &= \frac{v_{y} - u_{y}}{(-g)} \\ &\approx \frac{(-5.29598)\; {\rm m\cdot s^{-1}}}{(-9.81)\; {\rm m\cdot s^{-2}}} \\ &\approx 0.53985\; {\rm s}\end{aligned}\).
If air resistance on the bullfrog is negligible, horizontal velocity will be constant: \(v_{x} = u_{x} \approx 3.51400\; {\rm m\cdot s^{-2}}\). After \(t \approx 0.53985\; {\rm s}\) in the air, the horizontal displacement of the bullfrog will be:
\(\begin{aligned}x_{x} &= v_{x}\, t \\ &\approx 3.51400\; {\rm m\cdot s^{-1}} \times 0.53985\; {\rm s} \\ &\approx 1.90\; {\rm m} \end{aligned}\).
Therefore, this bullfrog will cover a distance of approximately \(1.90\; {\rm m}\).
what is the value of the fermi-dirac distribution for energies less than the fermi energy, if the temperature is t=0k ? express your answer to two significant figures.
The value of the Fermi-Dirac distribution for energies less than the Fermi energy at absolute zero temperature (T=0K) is 1.00.
The Fermi-Dirac distribution function describes the probability of finding an electron in a specific energy state in a Fermi gas. It is given by the equation:
f(E) = 1 / (1 + exp((E - EF) / (kT)))
Where f(E) is the Fermi-Dirac distribution function, E is the energy, EF is the Fermi energy, k is Boltzmann's constant, and T is the temperature.
At absolute zero temperature (T=0K), the exponential term in the equation becomes infinite for energies less than EF, and the distribution function simplifies to:
f(E) = 1 / (1 + ∞) = 1 / ∞ = 0
Therefore, for energies less than the Fermi energy at absolute zero temperature, the value of the Fermi-Dirac distribution function is 0. However, it's important to note that this result assumes ideal conditions and a non-degenerate Fermi gas.
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A shuttle bus slows to a stop with an average acceleration of -1.8 m/s^2. How long does it take the bus to slow down from 9.0 m/s to 0.0 m/s?
Time taken to slow down the speed will be 5 seconds.
Average acceleration of the bus, a = 1.8 m/s²
Initial velocity of the bus, u = 9.0 m/s
Final velocity of the bus, v = 0 m/s
According to the First Equation of the motion which relates the acceleration, velocity and time we can say that
v = u + at
v - u = at
0 - 9 = (-1.8) * t
9 = 1.8 * t
t = \(\frac{9}{1.8}\)
t = 5 s
Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s
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A lamp is marked 24V, 100W. Describe an experiment to check that the electrical power supplied to the lamp is 100W when the p.d. across it is 24V.
In your account you should
* include a circuit diagram,
* state the readings that are taken,
* show how the result is calculated from the readings.
The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
What is electrical power?Electrical power is the rate at which electrical work is done.
The unit of electrical power is Watts.
Power = Current × VoltageThe experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.
The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.
The ammeter reading is taken as well.
When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.
Calculating, the power of the lamp:
Power = 24 × 4.2 = 100 W
Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
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A rock thrown vertically upward from the surface of the moon at a velocify of 12 m/sec reaches a hoight of s =121−0gr^2 meters in t wec: a. Find the rock's velocity and acceleration at time t. b. How long doess it take the rock to reach its highect point? C. How high does the rock go? d. How long does it take the rock to reach half its maximum height? e. How long is the rock alon?
a. The velocity of the rock at time t is given by v = 12 - 9.8t m/s, and the acceleration is constant and equal to -9.8 m/s².
b. The time taken for the rock to reach its highest point can be found by setting the velocity equal to zero and solving for time.
c. The rock reaches a height of 121 meters.
d. To find the time it takes for the rock to reach half its maximum height, we can set s equal to half the maximum height and solve for time.
e. The total time the rock is in the air can be determined by doubling the time taken to reach the maximum height.
The velocity of the rock at any time t can be determined by subtracting the acceleration due to gravity (9.8 m/s²) multiplied by the time t from the initial velocity of 12 m/s. This gives us v = 12 - 9.8t m/s. The acceleration remains constant at -9.8 m/s² throughout the motion.
To find the time taken for the rock to reach its highest point, we set the velocity equal to zero (since the rock momentarily stops at the highest point) and solve for time. By substituting v = 0 into the equation v = 12 - 9.8t, we can find the value of t.
The height reached by the rock is given by the equation s = 121 - 0.5gt², where g is the acceleration due to gravity. Plugging in the values, we find that the rock reaches a height of 121 meters.
To determine the time it takes for the rock to reach half its maximum height, we set s equal to half of the maximum height (60.5 meters) and solve for time using the same equation.
The total time the rock is in the air can be found by doubling the time it takes to reach the maximum height. This is because the motion is symmetrical, and the time to ascend is equal to the time to descend.
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How much potassium nitrate (KNO3) would dissolve in 50 milliliters of water at 45ºC given that 55g of KNO3 is dissolved in 150mL of water at 45°C.
A. 19.7g
B. 15.1g
C. 18.3g
D. 23.3g
If a toy train has a mass of 1.5 KG and accelerates at a rate of 20 M/S 2 calculate force acting on it?
Answer:
F = 30 N
Explanation:
Given that,
Mass of a toy train, m = 1.5 kg
The acceleration of the toy-train, a = 20 m/s²
We need to find the force acting on it. We know that, net force acting on an object is given by :
F = ma
Substitute all the values,
F = 1.5 × 20
F = 30 N
Hence, the net force acting on the toy train is equal to 30 N.
If the same strength force is exerted on two objects why might they be affected differently?
Answer:
Due to their mass
Explanation:
If the same strength force is exerted on two objects they might be affected differently due to their mass.
The way objects reacts to a force impact is largely dependent on their mass.
The mass of an object is the amount of matter it contains.
According to the Newton's second law of motion, the force applied on a body is directly proportional to the product of its mass and acceleration.
Force = mass x acceleration
Therefore, the way a force acts on a body is a function of its mass.
A psychologist working from the cognitive perspective would most likely believe that anxiety is caused by __________.
A.
unconscious and unresolved conflicts
B.
a person’s failure to reach one’s potential
C.
certain hormones in the brain
D.
erroneous perceptions or thoughts
Answer:
D.Erroneous Perceptions or thoughts
Answer:
D. erroneous perceptions or thoughts
Explanation:
why not
Type of mirror used as a side mirror on a vehicle to provide a wide angle view...
Answer:
yes done first thing tomorrow
Answer:
convex mirror is used in vehicle to provide a wide angle view