The average horizontal component of the force exerted on the sprinter's feet during acceleration is 341.59 N. The speed of the sprinter over the last 50 m of the race is 0 m/s.
A). average force = (mass x change in velocity) / time
acceleration = change in velocity/time
time = √(2 x distance / acceleration)
time = √(2 x 47 / 9.8) = 3.03 s
Using the equation for acceleration, we can find the acceleration of the sprinter:
acceleration = distance / time²
acceleration = 47 / (3.03)² = 5.68 m/s²
Now, we can find the change in velocity during acceleration:
change in velocity = acceleration x time
change in velocity = 5.68 x 3.03 = 17.2 m/s
Finally, we can find the average horizontal component of the force:
average force = (mass x change in velocity) / time
average force = (60 x 17.2) / 3.03 = 341.59 N
B). time = distance / speed
time = 53 / 10 = 5.3 s
Using the same equation as before, we can find the acceleration of the sprinter:
acceleration = change in velocity/time
acceleration = 0 / 5.3 = 0 m/s²
Now, we can rearrange the equation for motion with constant acceleration to solve for the final velocity:
final velocity = (2 x distance x acceleration)^0.5
final velocity = (2 x 50 x 0\()^{0.5\) = 0 m/s
Acceleration is a fundamental concept in physics that refers to the rate at which an object's velocity changes over time. When an object undergoes acceleration, it experiences a change in its speed, direction, or both.
Acceleration is often represented by the symbol "a" and is measured in meters per second squared (m/s²). Acceleration can be positive or negative, depending on whether the object is speeding up or slowing down, respectively. An object at rest has zero acceleration, while an object moving at a constant velocity also has zero acceleration.
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If It took 40 sec for a
vehicle or weight 40,000
newton to move round 7meltes
What time will it achieve same
reat for anothercircular path
or radius 21 metres given
that
the condition
Condition of the
vehicle remains the same
I can’t understand your question
a personal computer with a monitor and keyboard requires 45 w at 115 v (rms). calculate the rms value of the current carried by its power cord.
The RMS value of the current carried by power cord is 0.35 A
What is RMS value voltage and current?The RMS or root mean square current/voltage of an AC current/voltage represents a DC current, a current/voltage that outputs the same average power as an AC current/voltage outputs. For a sine wave, the RMS value is equal to the peak value divided by the square root of 2. Helps find the RMS value of AC (voltage or current). This RMS value is a mathematical quantity (used in many areas of mathematics) used to compare AC and DC currents (or voltages).
To determine the effective current through the power cord:
Iₙ = P/Vₙ
Where, Iₙ = effective current
P = power (45 W)
Vₙ = effective voltage (115 V)
Iₙ = 45/115
Iₙ = 0.35 A
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3 Below, someone is trying to balance a plank with
stones. The plank has negligible weight.
a Calculate the moment of the 4 N force about O.
b Calculate the moment of the 6 N force about O.
- 2 m *
2 m-*
4 m
Р
1
4N
6N
Answer:
a. The moment of the 4 N force is 16 N·m clockwise
b. The moment of the 6 N force is 12 N·m anticlockwise
Explanation:
In the figure, we have;
The distance from the point 'O', to the 6 N force = 2 m
The position of the 6 N force relative to the point 'O' = To the left of 'O'
The distance from the point 'O', to the 4 N force = 4 m
The position of the 4 N force relative to the point 'O' = To the right of 'O'
a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point
a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise
b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.
A blue train of mass 50km moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final speed of the blue train?
The final speed of the blue train after colliding with the green train is 2.79 m/s, while the green train moves with a speed of 3 m/s.
To solve this problem, we need to apply the principle of conservation of momentum, which states that the total momentum of a closed system is conserved, provided that no external forces act on the system. In this case, the system consists of the blue train and the green train, and there are no external forces acting on the system.
Let's begin by calculating the initial momentum of the system:
Initial momentum = (mass of blue train x velocity of blue train) + (mass of green train x velocity of green train)
Initial momentum = (50,000 kg x 4 m/s) + (30 kg x 0 m/s)
Initial momentum = 200,000 kg·m/s
Next, we need to calculate the final momentum of the system. We know that the green train moves with a speed of 3 m/s after the collision, but we don't know the final speed of the blue train. However, we can use the principle of conservation of momentum to calculate the final momentum of the system:
Final momentum = (mass of blue train x final velocity of blue train) + (mass of green train x final velocity of green train)
We can simplify this equation by assuming that the collision is perfectly elastic, which means that kinetic energy is conserved as well as momentum. In an elastic collision, the total kinetic energy before the collision is equal to the total kinetic energy after the collision. We can use this fact to solve for the final velocity of the blue train:
Total kinetic energy before collision = (1/2 x mass of blue train x (velocity of blue train)²) + (1/2 x mass of green train x (velocity of green train)²)
Total kinetic energy before collision = (1/2 x 50,000 kg x (4 m/s)²) + (1/2 x 30 kg x (0 m/s)²)
Total kinetic energy before collision = 400,000 J
Total kinetic energy after collision = (1/2 x mass of blue train x (final velocity of blue train)²) + (1/2 x mass of green train x (final velocity of green train)²)
Total kinetic energy after collision = (1/2 x 50,000 kg x (final velocity of blue train)²) + (1/2 x 30 kg x (3 m/s)²)
Total kinetic energy after collision = 225,450 J
Since kinetic energy is conserved in an elastic collision, we can set the total kinetic energy before the collision equal to the total kinetic energy after the collision:
400,000 J = 225,450 J + (1/2 x 50,000 kg x (final velocity of blue train)²)
Solving for the final velocity of the blue train:
(1/2 x 50,000 kg x (final velocity of blue train)²) = 174,550 J
(final velocity of blue train)² = 7.78 m²/s²
final velocity of blue train = 2.79 m/s
Therefore, the final speed of the blue train after the collision is 2.79 m/s.
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The gravitational force on the moon is only 1/6 that on earth. What is the weight of a 10 kg object on the earth and on the moon? what is the mass of the object on the earth and the moon?.
Answer:
10 kg
Explanation:
The mass of the object is always constant and does not depend on the gravitational force of the Earth or the Moon.
A 10 g thread of wool was produced by Julitha Barber of Australia in 1989. Its length was 553 m. Suppose Barber is standing a distance equal to the thread's length from a conver mirror. If the mirror's radius of curvature is 1.20 × 102 'm, what will the magnification of the image be?
The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979
To find the magnification of the image, we need to use the formula:
magnification = -v/u,
where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979 (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.
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Horizontal and vertical motions of a projectile are independent of each other. What is meant by this?.
It means that horizontal and vertical motions are independent to each other, which means they don't influence one another.
Definition of motion in physicsMotion in physics is defined to be a change in position of an object over time. We can describe motion in terms of displacement/distance, time, velocity/speed, acceleration and the like.
There is one-dimensional motion and there is also two-dimensional motion. In two-dimensional motion, there are horizontal motion and vertical motion. Horizontal motion is a projectile motion in a horizontal plane. Meanwhile, vertical motion is a projectile motion in a vertical plane. Both motions are independent, meaning that they don't actually influence each other.
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Pluto has a gravitational field strength (g) of 0.61. If you have a weight of 1000 N on the Earth (g = 10), what will your weight be on Pluto?
A. 0.61 N
B. 6.1 N
C. 61 N
D. 610 N
Reset Selection
Answer: Alternative D.
------------------------------------------------
To calculate the gravitational weight of other planets, the formula is used:
\(\large\boxed{{\mathbf{P = m \cdot g}}}\)
Data:
Mass(m): 1000 N
Gravity(g): 0.61
Weight(p): ?
We replace data:
P = m × g
P = 1000 N × 0.61
P = 610 N
Result: Its weight on Pluto will be 610 Newtons (Alternative D).
A ball with an initial velocity of 2 m/s rolls for a period of 3 seconds. If the ball is uniformly accelerating at a rate of 3 m/s2, what will be the ball’s final velocity?
Answer: 11 m/s
vinitial=2 m/s
time=3 s
acceleration = 3 m/s^2
vfinal = ?
The key here is that it is a constant acceleration, so we can use the constant acceleration equations. The easiest one to use would be:
vfinal=vinitial + a*t
We need vfinal, so algebraically we are ready to put in numbers into the equation:
vfinal=vinitial + a*t = 2 m/s + (3 m/s^2)*(3 s ) = 11 m/s is the final velocity
The ball's final velocity is 11 m/s
From one of equations of kinematics for linear motion
We have that
v = u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time
From the given information in the question
u = 2 m/s
t = 3 secs
a = 3 m/s²
Putting these parameters into the above formula
v = u + at
We get
v = 2 + (3×3)
v = 2 + 9
v = 11 m/s
Hence, the ball's final velocity is 11 m/s
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A low energy photon hits
the electron in the image.
What happens to the
electron if the energy is
below the threshold for
absorption?
A low energy photon hits the electron in the image therefore the photon will bounce off the electron if the energy is below the threshold for absorption.
What is a Photon?This is referred to as a particle representing a quantum of light or other electromagnetic radiation and it carries energy proportional to the radiation frequency but has zero rest mass.
When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level and bounces of if the energy is below the threshold for absorption.
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What is the radius of the event horizon of this 10-Solar-mass black hole, in units of kilometers (km)
The radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.
How do you calculate the radius of the event horizon?The radius of the event horizon of a black hole is known as the Schwarzschild radius and it is a function of the mass of the black hole. The Schwarzschild radius is given by the formula:
r = 2GM/c^2
where
r = radius of the event horizon (in meters)
G = gravitational constant (6.674 x 10^-11 N*(m/kg)^2)
M = mass of the black hole (in kg)
c = speed of light in a vacuum (2.998 x 10^8 m/s)
For a 10-Solar-mass black hole, we can use the mass conversion factor 1 Solar mass = 1.989 x 10^30 kg.
M = 10 x 1.989 x 10^30 kg
Now, we can substitute the values into the formula
r = 2 x 6.674 x 10^-11 x M/ (2.998 x 10^8)^2
r = 2GM/c^2 = 2 x 6.674 x 10^-11 x (10 x 1.989 x 10^30) / (2.998 x 10^8)^2
r = 2.95 x 10^3 m = 2950 kilometers
So, the radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.
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F PHY112 Chapter 29 Homework Question 2 of 4 > -/1 View Policies Current Attempt in Progress An incident X-ray photon of wavelength 0. 2019 nm is scattered from an electron that is initially at rest. The photon is scattered at an angle of 0 = 180. 0° in the drawing and has a wavelength of 0. 2068 nm. Use the conservation of linear momentum to find the momentum gained by the electron. E. X e E, Photon scattering from stationary electron Number Units וח
The momentum gained by the electron in this scattering process is approximately \(6.91 * 10^{-24} kg m/s\).
In this scenario, an incident X-ray photon of wavelength 0.2019 nm is scattered from a stationary electron, resulting in the photon being scattered at an angle of 180 degrees with a wavelength of 0.2068 nm. The conservation of linear momentum can be used to find the momentum gained by the electron in this process.
The momentum of the photon can be calculated using the formula p = h/λ, where h is Planck's constant and λ is the wavelength of the photon.
Using this formula, we find that the initial momentum of the photon is approximately \(3.093 * 10^{-22} kg m/s\).
The final momentum of the photon can be calculated in the same way, using its new wavelength of 0.2068 nm.
The final momentum is approximately \(3.024 * 10^{-22} kg m/s\).
Since momentum must be conserved in this process, we can find the momentum gained by the electron by subtracting the final momentum of the photon from its initial momentum.
Doing so, we find that the momentum gained by the electron is approximately \(6.91 * 10^{-24} kg m/s\).
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The diagram shows movement of thermal energy.
W
to fo
X
Z
In which areas of the diagram does conduction occur?
O W and X
O X and Z
O Y and Z
OZ and W
Answer:
The answer to your problem is, B. X and Z
Explanation:
Heat always transfers from hotter object to colder object. Because well heat it like a big territory with a leader that just wants to get hotter and hotter.
Our conduction will occur when there is contact between hotter body and colder body. The molecules vibrate at their position and transfer heat to the neighboring molecules which can be hot or cold. In the diagram conduction takes place at X and Z. The heat transfers from pan to handle at X and then from handle to hand at Z.
We also know that bulk or stable motion of fluid carries energy. Like in area W in the diagram. Radiation does not require medium to transfer energy because it is not needed for it. Like in the area of Y.
Thus the answer to your problem is, B. X and Z
What is the theorem of work energy?
The work-energy theorem is a fundamental principle in physics that relates the work done on an object to its change in kinetic energy.
The theorem states that the net work done on an object is equal to its change in kinetic energy:
Net Work = Change in Kinetic Energy
In other words, the work-energy theorem tells us that the work done on an object is equal to the change in its kinetic energy. If work is done on an object, its kinetic energy will change by an amount equal to the work done. Conversely, if the kinetic energy of an object changes, it must be due to work being done on the object.
The work-energy theorem applies to both conservative and non-conservative forces. For conservative forces, the work done depends only on the initial and final positions of the object, and not on the path taken between them.
For non-conservative forces, such as friction, the work done depends on the path taken and may result in a loss of mechanical energy.
The work-energy theorem is a powerful tool for analyzing and solving problems in physics, and it is widely used in many fields, including mechanics, thermodynamics, and electromagnetism.
It allows us to relate the work done on an object to its resulting motion and energy changes, providing a comprehensive picture of the physical system under consideration.
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Please someone answer this quickly!! I'll give 20 points for it, I just need the answers :)
The potential energy of the person mass 95 Kg sitting on top of a slid 3 m high is 2795.85 J
How do i determine the potential energy of the person?The following data were obtained from the question:
Mass of person (m) = 95 KgHeight of slid (h) = 3 mAcceleration due to gravity (g) = 9.81 m/s² Potential energy of person (PE) = ?The potential energy of the person can be obtained as follow:
PE = mgh
Inputting the given parameters, we have:
= 95 × 9.81 × 3
= 2795.85 J
Thus, the potential energy of the person is 2795.85 J
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Determine la inercia rotacional de una varilla de 4 m de largo y 2 Kg de mesa si su eje de rotación esta situado a la mitad de la varilla.
Answer:
I = 2.667 kg m²
Explanation:
The moment of inertia of a body can be calculated by the expression
I = ∫ L² dm
For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is
I = \(\frac{1}{12}\) m L²
let's calculate
I = \(\frac{1}{12}\) 2 4²
I = 2.667 kg m²
What is the kinetic energy
Answer:
energy which a body possesses by virtue of being in motion
Explanation:
friction and normal force are examples of
Answer:
Friction is a force that tends to oppose the relative motion between two bodies in contact. Frictional force always acts on a moving body from the direction opposite to the direction of motion. It opposes the motion, and therefore, helps to reduce the speed of the moving object. It is a contact force.
True or False
1)All forces cause a change in an object’s speed and direction.
Answer:
True
Explanation:
Answer and Explanation:
True I believe bc if you put a certain amount of force on an object it'll move and depending on where you place the force on the object it'll move in that direction. How much force and how much weight the object has will determine the speed...
A 40 V battery is connected to a 10 Ω resistor. Determine the current in the circuit?
Answer:
I=V/R=40 V/10 ohm = 4 A.
Explanation:
Use Ohm's law , V=I*R to find Current. Unit of current is ampere.
Researchers recorded the forces over a short period of time (0.065 s) for three different airbag designs as well as one crash without airbags. Your task is to analyze the data from the trials listed below. Use this analysis to construct an argument about which airbag design provides the most protection, citing patterns from the data as evidence for your claim. Data Time (seconds) Design 1(kN) Design 2 (kN) 0 0 0 0.005 0 7.38 0.01 0 46.18 0.015 7.63 84.08 0.02 56.03 91.87 0.025 101.84 90 08 0.03 126 81 81 03 0.035 114.13 54.13 0.04 64 84 36.96 0.045 38.15 29.96 0.05 17.78 18.2 0.055 5.04 10.87 0.06 0 4.31 Design 3 (kN) No Airbag (kN) 0 0 0 0 8.65 2.3 33.45 5.72 83.88 232 54 147.5 222 68 111 23 67.44 77.43 16 23 36.55 4.17 22.76 0 9.43 0 0 0 0 0 O 065 0 0 0 0
what is the pattern
Answer:
Design 2
Explanation:
I had this same question
My answer:
"Design 2 is the well-designed one, because the air molecules are the most compact and could protect the individual better than 1,3,and no air bag."
A force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable
A. Stress
B. Tension
C. Strain
D. None of the options
Answer:
B
Explanation:
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.
Answer:
B. Tension
Explanation:
A tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.
A compact car, mass 664 kg, is moving at 19 km/h toward the east. What is the car's momentum in kg x m/s?
Answer:
3504.4 kgm/s
Explanation:
First, convert km/hr to m/s:
19 km/hr x 1000m/1km x 1/60min x 1/60s = 5.28 m/s
p = mv
p = (664 kg)(5.28 m/s) = 3504.4 kgm/s
A monochromatic beam of X-rays produces a first order Bragg maximum when reflected off the face of an NaCl crystal with glancing angle theta = 20 degree. The spacing of the relevant planes is d = 0.28 nm. What is the minimum possible voltage of the tube that produced the X-rays?
In this scenario, we have X-rays incident on an NaCl crystal at a glancing angle of 20 degrees with a spacing of 0.28 nm between crystal planes. The X-ray tube's bare minimum operating voltage is roughly 7.11 x 10¹⁶ volts.
To calculate the minimum possible voltage of the tube that produced the X-rays, we can use Bragg's law, which relates the angle of diffraction, the wavelength of the X-rays, and the spacing between crystal planes.
The equation for Bragg's law is:
nλ = 2d sinФ
Where:
n is the order of the diffraction maximum (in this case, n = 1 for the first order maximum)
λ is the wavelength of the X-rays
d is the spacing of the relevant planes
theta is the glancing angle
We need to rearrange the equation to solve for λ (wavelength):
\(\lambda = \frac{{2d \sin(\theta)}}{n}\\\)
Given:
d = 0.28 nm
theta = 20 degrees
n = 1
We can substitute these values into the equation to find the wavelength of the X-rays.
Now, to calculate the minimum possible voltage of the tube, we can use the equation that relates the wavelength of X-rays to the minimum voltage:
\(V = \frac{{hc}}{{\lambda}}\)
Where:
V is the minimum voltage of the tube
h is Planck's constant (6.626 x 10⁻³⁴ J.s)
c is the speed of light (3.00 x 10⁸ m/s)
λ is the wavelength of the X-rays
Substituting the given values:
\(V = \frac{{(6.626 \times 10^{-34} , \text{J.s})(3.00 \times 10^8 , \text{m/s})}}{{(0.28 \times 10^{-9} , \text{m})}}\)
V ≈ 7.11 x 10¹⁶ V
Therefore, the minimum possible voltage of the tube that produced the X-rays is approximately 7.11 x 10¹⁶ volts.
\(V = \frac{{(6.626 \times 10^{-34} \, \text{J}\cdot\text{s})(3.00 \times 10^8 \, \text{m/s})}}{{(0.28 \times 10^{-9} \, \text{m})(1.602 \times 10^{-19} \, \text{C})}}\)
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Question 5
2 pts
(04.03 MC)
Which types of changes must follow the law of conservation of mass? (2 points)
O Both physical and chemical changes
Neither physical nor chemical changes
O Only physical changes
O Only chemical changes
Answer:
A Both physical and chemical changes.
Explanation:
HEYY! Please help!
Turn this Algebraic expression into a Verbal expression!
2(3j+5+8j)
Thank you! <33
Answer:
22J+10
Explanation:
that is it in verbal expression
can someone please help me A wave’s velocity is 120 m/sec with a frequency of 6 Hz. What is its wavelength?
Answer:
by using formula,
wavelength= velocity/frequency
= 120/6
= 20 meter
Ans: 20 meter
Answer:
wavelength= velocity
= 120/6= 20 meter
Explanation:
jon is in a raft that is 117m from the base of a 56m cliff. what is the angle of depression from the top of the cliff to the raft?
Give me an example of theory
Answer:
theory is an idea to explain something,
Explanation:
Einstein's ideas about relativity are an example of the theory of relativity.
Answer: If skin cancer is related to ultraviolet light, then people with a high exposure to uv light will have a higher frequency of skin cancer.
Explanation:
4) A basketball is launched at a velocity of 25 m/s in a direction making an angle of 50° upward with the
horizontal. What is the maximum height reached by the object?
Answer:
As Per Provided Information
Velocity of projection u is 25m/sAngle made by ball ∅ is 50°We have been asked to determine the maximum height reached by the object .
here we will take acceleration due to gravity g is 9.8 m/s².
For calculating the maximum height attained by the object we will use the following formula .
\( \boxed{\bf \:H_{(max)} \: = \cfrac{u {}^{2} {sin}^{2} \theta }{2g}}\)
Substituting all the value in above equation we obtain
\(\sf \qquad \: \longrightarrow\:H_{(max)} \: = \cfrac{ {25}^{2} {sin}^{2} {50}^{ \circ} }{2 \times 9.8} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{625 \times(0.766) {}^{2} }{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{625 \times 0.586756}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{366.7225}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cancel \cfrac{366.7225}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} =18.71 \: m\)
Therefore,
Maximum height reached by the object is 18.71 meters.