Answer: 6
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Please explain your answer to the question in the picture with steps.
!! This one too!! anybody
Answer:
-2/5
Step-by-step explanation:
You can solve this by doing that rise/run
rise/run = -2/5
Slope = -2/5
I WILL GIVE BRAINILESTTTTT
Answer: C
Step-by-step explanation:
For the polynomial below, what is the coefficient of the term with the power of 3? x + x4 +6X +5
In the algebraic term, there are a number and a variable, the number is called the coefficient of the variable
EX: 2x is an algebraic term, where 2 is the coefficient of x
In the given polynomial
\(x^3+\frac{1}{3}x^4+6x+5\)There are 4 algebraic terms
\(\begin{gathered} x^3 \\ \frac{1}{3}x^4 \\ 6x \\ 5 \end{gathered}\)The coefficient of each term in the number before the variable
If there is no number that means the coefficient is 1
Since there is no number before x^3, then
Its coefficient is 1
The answer is D
is the ordered pair a solution to the equation. y=-7; (-5,6)
Answer: No
To check if (-5,6) is a solution to the equation y=-7, we need to substitute -5 for x and 6 for y in the equation.
If the equation is true, then the ordered pair is a solution to the equation.
If we put (-5,6) into y=-7, we get 6=-7, which is not true.
So, (-5,6) is not a solution to the equation y=-7.
For exponential functions of the form
f(x) = a^x, which of the following
expressions is equal to [f(1)]^2??
Click on the correct answer.
f(1^2)
f(1•2)
f(1 + 2)
Answer:
f(1·2)
Step-by-step explanation:
Subbing x=1 (f(1)) into the original function f(x)=a^x will give f(1)=a^1 which is simply equal to a. Therefore, if we were to do [f(1)]^2, we would just get a^2 because f(1) is equivalent to a. Out of the choice.s present, only f(1·2) is equal to a^2, because a^(1·2)=a^2
HELP PLEASE!!
Quadrilateral CDEF is a rhombus. What is m
Answer:
∠ BDC = 29°
Step-by-step explanation:
the sides of a rhombus are congruent, so CD = ED and Δ EDC is therefore isosceles with base angles congruent , then
∠ BCD = ∠ BED = 61°
• the diagonals are perpendicular bisectors of each other , then
∠ CBD = 90°
the sum of the 3 angles in Δ BCD = 180°
∠ BDC + ∠ CBD + ∠ BCD = 180°
∠ BDC + 90° + 61° = 180°
∠ BDC + 151° = 180° ( subtract 151° from both sides )
∠ BDC = 29°
Name the subset(s) of real numbers to which each number belongs. Then order the numbers from least to greatest.
45−−√ , 16/5 , −1
Answer:
I'm assuming 45−−√ is \(\sqrt{45}\), and that it belongs to the subset of irrational numbers.
16/5 is a rational number, and -1 is an integer.
All numbers belong to the subset of real numbers.
Step-by-step explanation:
Hope this helped!
In a fruit punch drink, the 3 ingredients are apple juice, orange juice and cranberry juice. If 2/7 of
the drink is apple juice and 1/2 is orange juice then write the ratio of cranberry juice to apple
juice to orange juice in its simplest form,
Answer:
3 : 4 : 7
Step-by-step explanation:
apple juice - 2/7 = 4/14
orange juice - 1/2 = 7/14
AJ + OJ = 11/14
this means that 3/14 of the punch is cranberry juice.
cranberry : apple : orange
3 : 4 : 7
A pot contains 25 ounces of soil. You use 4 1/4 ounces of soil to plant 1 herb. Is there enough soil in the pot to plant 5 herbs?
Answer: yes
Step-by-step explanation:
25 divided by 4 1/4 = 5 15/17
hope this helps :)
!
A washer and dryer cost a total of 928$. The cost of the washer is three times the cost of the dryer. Find the cost of each item.
Answer:
Cost of Washer = $696
Cost of Dryer = $232
Step-by-step explanation:
Start by making and equation, put a variable for the missing prices, let's say the cost of the dryer is 'x' and since the cost of the washer is three times, it will be '3x'.
Put the equation together, so we can add the x variables together.
3x + x = 4x
The total cost will be what the '4x' is equal to.
4x = 928
Going back to algebra, we solve the equation by dividing both sides by 4.
x = 232
Remember x is the variable we gave to the dryer, so now we must find the cost of the washer. In order to do this, we will have to multiply it by 3.
3x
3(232) = 696.
To check the answer, we can add them together to make sure we get the total cost.
696 + 232 = 928
what is AE
AB=10
AE=2a + 10
ED=x + 3
CD=4
Enter you answer In the box
The given values into the equation AE = 2a + 10. Therefore, The value of AE is 3 - x.
To find the value of AE, we can substitute the given values into the equation AE = 2a + 10.
Given:
AB = 10
AE = 2a + 10
ED = x + 3
CD = 4
Since AB is a segment on the line, it can be divided into AE and ED. Therefore, AB = AE + ED.
We know that AB = 10 and CD = 4. So, if we subtract CD from AB, we get AE + ED = 10 - 4.
AE + ED = 6.
Now, we can substitute the value of ED, which is x + 3, into the equation: AE + x + 3 = 6.
To find the value of AE, we need to isolate it on one side of the equation. Let's subtract x and 3 from both sides:
AE = 6 - x - 3.
Simplifying further, we get;
AE = 3 - x.
Therefore, the value of AE is 3 - x.
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(sec(theta) - tan theta)/(sec(theta)) + (tan theta + sec(theta))/(tan theta) = 2 + cos theta * cot theta
PLEAEE HELP!!
Therefore, the equation is satisfied when the point (cos(theta), sin(theta)) lies on the circle with center (1, 0) and radius 1.
What is trigonometry equation?Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. There are many equations in trigonometry that relate these values. Here are a few examples:
The Pythagorean theorem: In a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as \(a^2 + b^2 = c^2\), where a and b are the lengths of the legs (the two sides that meet at the right angle), and c is the length of the hypotenuse.
The sine, cosine, and tangent functions: These functions relate the angles of a right triangle to the ratios of the lengths of its sides. Specifically:
Let's simplify the left-hand side of the equation first:
\((sec(theta) - tan theta) / (sec(theta)) + (tan theta + sec(theta)) / (tan theta)\)
\(= [(1/cos(theta)) - (sin(theta)/cos(theta))] / (1/cos(theta)) + [(sin(theta)/cos(theta)) + (1/cos(theta))] / (sin(theta)/cos(theta))\)
= [(1 - sin(theta)) / cos(theta)] / (1/cos(theta)) + [(sin(theta) + 1) / cos(theta)] / (sin(theta)/cos(theta))
\(= (1 - sin(theta)) + (sin(theta) + 1) / sin(theta)\)
\(= 2 + 1/sin(theta)\)
Now let's simplify the right-hand side:
\(2 + cos(theta) * cot(theta)\)
\(= 2 + cos(theta) * (cos(theta) / sin(theta))\)
\(= 2 + cos^2(theta) / sin(theta)\)
Since we want to show that the left-hand side is equal to the right-hand side, we can simplify the right-hand side to have a common denominator with the left-hand side:
\(2 + cos^2(theta) / sin(theta)\)
\(= (2sin(theta) + cos^2(theta)) / sin(theta)\)
Now we can compare the two sides:
\(2 + 1/sin(theta) = (2sin(theta) + cos^2(theta)) / sin(theta)\)
Multiplying both sides by sin(theta), we get:
\(2sin(theta) + 1 = 2sin^2(theta) + cos^2(theta)\)
Rearranging terms, we get:
\(2sin^2(theta) - 2sin(theta) + cos^2(theta) - 1 = 0\)
We recognize this as the equation of a circle:
\((x - 1)^2 + y^2 = 1\)
where x = cos(theta) and y = sin(theta)
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Pls look at the picture for the question.
Answer:
10
Step-by-step explanation:
each tick mark is worth 5
there is the -10, then one to the right is -5, next is 0, next is 5, next one (the one where the x is) 10, next 15, next 20.
Evaluate 7x9-9.
Aleks
woman bought 1.8 kg of chicken and 1.6 kg of meat. The chicken cost N5.40 and the meat cost #6.40. If she had bought 2.4 kg of chicken and 2 kg of meat, how much would she have had to pay?
The amount the women would pay for 2.4 kg of chicken and 2 kg of meat in total is $15.2
What is the unit price?The meaning of unit price is a price quoted in terms of so much per agreed or standard unit of product or service
Given that, a woman bought 1.8 kg of chicken and 1.6 kg of meat. The chicken cost $5.40 and the meat cost $6.40,
We need to find, if she had bought 2.4 kg of chicken and 2 kg of meat, how much would she have had to pay,
To find the same, we will first find the unit price of each,
Unit price = total price / total quantity
Since, 1.8 kg of chicken costs $5.40,
Therefore, 1 kg will cost = 5.40 / 1.8 = $3
Similarly,
If 1.6 kg of meat costs $6.40,
Therefore, 1 kg will cost = 6.40 / 1.6 = $4
Now, to find the cost of 2.4 kg of chicken and 2 kg of meat, we will multiply the unit prices to the required quantities,
Therefore,
2.4 kg of chicken will cost = 2.4 x 3 = $7.2
2 kg of meat will cost = 2 x 4 = $8
In total, she had to pay = 8+7.2 = $15.2
Hence, the amount the women would pay for 2.4 kg of chicken and 2 kg of meat in total is $15.2
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gym help
when doing any weighted exercises that involve using all or little of my body weight do i count my body weight and the added weight as my “actual weight lifted”? for example i weigh 150lbs and let’s say i did a single rep of weighted overhand chin ups with a single 20lbs weight wrapped around me and i wanted to track how much “actual weight” i just lifted would i write down and track just the 20lbs or my body weight 150lbs plus the weight 20lbs?
You should write down and track only the 20lbs weight during your weighted exercise while ignoring your body weight.
What is actual weight?Actual weight is also referred to as gross weight and it can be defined as the exact (original) weight of an object, as measured using an appropriate weighing scale.
This ultimately implies that, you would write down and track only the 20lbs weight during your weighted exercise such as a single rep of weighted overhand chin ups.
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Question 1-2
What is the value of a³ + b (6 + c), when a = 2, b = 3, and c = 4?
Answer:
\(\huge\boxed{\sf 38}\)
Step-by-step explanation:
Given expression:= a³ + b (6 + c)
Put a = 2, b = 3 and c = 4
= (2)³ + 3 (6 + 4)
= 8 + 3(10)
= 8 + 30
= 38\(\rule[225]{225}{2}\)
Answer:
Step-by-step explanation:
the requied answer is 38.
according to the question the value of a=2,b=3,c=4.
here,
to find the value of a³ + b (6 + c)we have to do it in steps:
step 1: solve the bracket (6+4) =10.
step 2: solve the value of a³ =8.
now put these values ,
=8+3(10)
=38.
If two angles are complementary then the sum of their measures is _______.
(Answer with a number ONLY)
If the two angles are complementary, then their sum is 90 degrees.
The inclination is the separation seen between planes or vectors that meet. Degrees are another way to indicate the slope. For a full rotation, the angle is 360°.
Complementary angle - Two angles are said to be complementary angles if their sum is 90 degrees.
If the two angles are complementary, then their sum is 90 degrees.
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what is 26.2 divided by 2.345
Find all points on the x-axis that are 16 units from the point (5,-8)
To find all points on the x-axis that are 16 units away from the point (5, -8), we can use the distance formula. The distance between two points (x₁, y₁) and (x₂, y₂) is given by the formula:
d = √((x₂ - x₁)² + (y₂ - y₁)²)
In this case, the y-coordinate of the point (5, -8) is -8, which lies on the x-axis. So, any point on the x-axis will have a y-coordinate of 0. Let's substitute the given values and solve for the x-coordinate.
d = √((x - 5)² + (0 - (-8))²)
Simplifying:
d = √((x - 5)² + 64)
Now, we want the distance d to be equal to 16 units. So, we set up the equation:
16 = √((x - 5)² + 64)
Squaring both sides of the equation to eliminate the square root:
16² = (x - 5)² + 64
256 = (x - 5)² + 64
Subtracting 64 from both sides:
192 = (x - 5)²
Taking the square root of both sides
√192 = x - 5
±√192 = x - 5
x = 5 ± √192
Therefore, the two points on the x-axis that are 16 units away from the point (5, -8) are:
Point 1: (5 + √192, 0)
Point 2: (5 - √192, 0)
In summary, the points on the x-axis that are 16 units away from the point (5, -8) are (5 + √192, 0) and (5 - √192, 0).
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Jenny is dog sitting for 13 dogs. One runs away, and she is not sure which one. There were 3 Labradors (L), 2 Golden Retrievers (G), 3 Dalmatians (D), 4 terriers (T), and 1 bulldog (B) in the original group.
What is the size of the population of dogs that could have run away from Jenny?
1
5
11
13
Answer:
5
Step-by-step explanation:
It is 5 because she originally had 13. There are 5 types of dogs she was dog-sitting. There are 5 possible types of dogs that ran away.
Help plz:)))I’ll mark u Brainliest
Answer:
scale factor = 1.5
Step-by-step explanation:
15 / 10 = 1.5
10 * 1.5 = 15
Use the limit definition of the derivative to find the slope of the tangent line to the curve f(x) = 7x ^ 2 + 2x + 3 at x = 1
Answer:
16
Step-by-step explanation:
Step 1: Write down the function \(f(x)=7x^2+2x+3.\)
Step 2: Write down the limit definition of the derivative:
\(f'(x)= lim_{h0} \frac{f(x+h)=f(x)}{h} .\)
Step 3: Substitute the function \(f(x)\) into the limit definition:
\(f'(x)=lim_{h0} \frac{(7(x+h)^2+2(x+h)+3)-(7x^2+2x+3)}{h}.\)
Step 4: Simplify the expression inside the limit:
\(f'(x)=lim_{h0}\frac{7x^2+14xh+7h^2+2x+2h+3-7x^2-2x-3}{h} .\)
Step 5: Combine like terms:
\(f'(x)=lim_{h0} \frac{14xh+7h^2+2h}{h} .\)
Step 6: Factor out an \(h\) from the numerator:
\(f'(x)=lim_{h0} \frac{h(14x+7h+2h}{h} .\)
Step 7: Cancel out the \(h\) in the numerator and denominator:
\(f'(x)=lim_{h0}(14x+7h+2).\)
Step 8: Evaluate the limit as \(h\) approaches 0:
\(f'(x)=14x+2.\)
Step 9: Substitute \(x=1\) into the derivative:
\(f'(1)=14(1)+2=14+2=16.\)
The Slope of the tangent line to the curve \(f(x)=7x^2+2x+3\) at \(x=1\) would be \(16.\)
Suppose it costs $52,000 per year to live in City A. It costs $90,000 to live in City B. If you are offered $69,000 to work and live in City A and you are offered $110,000 to work and live in City B, which offer is better in terms of purchasing power?
\( \bf \large City \: A \: = \frac{69000}{52000} => 1.33\)
\( \bf \large City \: B = \frac{110000}{90000} => 1.22\)
\( \large\implies \bf1.33 > 1.22\)
So, City A is better.Based on the information in the table, what
was the approximate value of this item in
1980?
Answer:
B) 4,700
Step-by-step explanation:
6000 - 4000 = 2000
2000 in 15 year, find how much for each year
2000/ 15 = 133.3333333
133.3333333 estimated = 133
133 approximately for each year
1975 to 1980 is five years
133 x 5 = 665
4000 + 665 = 4665
4665 rounded the the nearest hundred
4700
For which conditions is p V q false?
p is true and q is false.
p is true and q is true.
p is false and q is true.
Opis false and q is false.
Answer:
opis is false and q is false
Step-by-step explanation:
Answer:
its d
Step-by-step explanation:
Malcolm trains on his kayak every weekend. He paddles upstream (against current) for 3 ½ hours and then returns downstream (with current) in 2hrs 6 minutes. If the river flows at 3km/ h, find:
* The paddling speed in still water
* The distance he paddles upstream.
The probability she pulls out a purple piece of candy would be 0.22.
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.
Given is Sam's fathers collection.
We can write the equations for upstream and downstream as -
x - y = 7/2
x + y = 21/10
Solving the equations graphically -
{x} = 2.8
{y} = 0.7
In still water, the speed would be -
S = 3 - 0.7
S = 2.3 Km/h
Distance peddled upstream -
D = 2.8 x 3.5 = 9.8 Km
Therefore, the speed in still water would be 2.3 Km/h and the distance peddled upstream would be 9.8 Km.
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Some one please help
I have attached the question
Answer:
a number question's answer is a power 2. and is c power 1
an answer does not exist.
f(x) = (x^4)/4-3x^3-2
a) Determine the intervals on which f is concave up and concave down.
f is concave up on:
f is concave down on:
b) Based on your answer to part (a), determine the inflection points of f. Each point should be entered as an ordered pair
(that is, in the form (x, y)).
c) Find the critical numbers of f and use the Second Derivative Test, when possible, to determine the relative extrema. List
only the x-coordinates.
Relative maxima at:
Relative minima at:
d) Find the x-value(s) where f'(x) has a relative maximum or minimum.
f' has relative maxima at:
f' has relative minima at:
a. F is concave up on (-∞, 0) ∪ (6, ∞) and concave down on (0, 6).
b. The inflection points are (0, -2) and (6, -226).
How to determine the intervals of concavity?a) To determine the intervals of concavity, we need to find the second derivative of f:
f(x) = (x⁴)/4-3x³-2f'(x) = x³ - 9x²f''(x) = 3x² - 18x
The second derivative f''(x) is a polynomial. We need to find the values of x for which f''(x) is zero or undefined.3x² - 18x = 3x(x - 6)f''(x) = 0 when x = 0 or x = 6.
Now we can determine the intervals of concavity by testing the sign of f''(x) in each interval:
Interval (-∞, 0):f''(-1) = 3(-1)² - 18(-1) = 21 > 0, so f is concave up on (-∞, 0).
Interval (0, 6):f''(1) = 3(1)² - 18(1) = -15 < 0, so f is concave down on (0, 6).
Interval (6, ∞):f''(7) = 3(7)² - 18(7) = 63 > 0, so f is concave up on (6, ∞).
Therefore, f is concave up on (-∞, 0) ∪ (6, ∞) and concave down on (0, 6).
B. The inflection points occur where the concavity changes, which are at x = 0 and x = 6.
The ordered pairs for the inflection points are (0, f(0)) and (6, f(6)).
f(0) = -2 and f(6) = -226, so the inflection points are (0, -2) and (6, -226).
c) To find the critical points, we need to find the values of x for which f'(x) = 0 or f'(x) is undefined:
f'(x) = x³ - 9x² = x²(x - 9)
f'(x) = 0
when x = 0 or x = 9.f''(0) = 0,
so we can use the First Derivative Test to determine that f has a relative maximum at x = 0.f''(9) = 36 &
gt; 0 so we can use the Second Derivative Test to determine that f has a relative minimum at x = 9.
Therefore, the relative extrema are:
Relative maximum at x = 0.
Relative minimum at x = 9.
d) To find where f'(x) has relative maxima and minima, we need to find the values of x for which f''(x) = 0 or f''(x) is undefined:
f''(x) = 3x² - 18x = 3x(x - 6)f''(x) = 0 when x = 0 or x = 6.
We can use the First Derivative Test to determine the nature of the relative extrema:
For x &
lt; 0, f'(x) is negative, then f'(x) is increasing from negative to zero as x approaches 0 from the left.
Therefore, f'(x) has a relative minimum at x = 0.
For 0 < x < 6, f'(x) is positive, then f'(x) is increasing from zero to positive as x increases.
Therefore, f'(x) has a relative maximum at x > 0.
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a. F is concave up on (-∞, 0) ∪ (6, ∞) and concave down on (0, 6).
b. The inflection points are (0, -2) and (6, -226).
How to determine the intervals of concavity?
a) To determine the intervals of concavity, we need to find the second derivative of f:
f(x) = (x⁴)/4-3x³-2f'(x) = x³ - 9x²f''(x) = 3x² - 18x
The second derivative f''(x) is a polynomial. We need to find the values of x for which f''(x) is zero or undefined.3x² - 18x = 3x(x - 6)f''(x) = 0 when x = 0 or x = 6.
Now we can determine the intervals of concavity by testing the sign of f''(x) in each interval:
Interval (-∞, 0):f''(-1) = 3(-1)² - 18(-1) = 21 > 0, so f is concave up on (-∞, 0).
Interval (0, 6):f''(1) = 3(1)² - 18(1) = -15 < 0, so f is concave down on (0, 6).
Interval (6, ∞):f''(7) = 3(7)² - 18(7) = 63 > 0, so f is concave up on (6, ∞).
Therefore, f is concave up on (-∞, 0) ∪ (6, ∞) and concave down on (0, 6).
B. The inflection points occur where the concavity changes, which are at x = 0 and x = 6.
The ordered pairs for the inflection points are (0, f(0)) and (6, f(6)).
f(0) = -2 and f(6) = -226, so the inflection points are (0, -2) and (6, -226).
c) To find the critical points, we need to find the values of x for which f'(x) = 0 or f'(x) is undefined:
f'(x) = x³ - 9x² = x²(x - 9)
f'(x) = 0
when x = 0 or x = 9.f''(0) = 0,
so we can use the First Derivative Test to determine that f has a relative maximum at x = 0.f''(9) = 36 &
gt; 0 so we can use the Second Derivative Test to determine that f has a relative minimum at x = 9.
Therefore, the relative extrema are:
Relative maximum at x = 0.
Relative minimum at x = 9.
d) To find where f'(x) has relative maxima and minima, we need to find the values of x for which f''(x) = 0 or f''(x) is undefined:
f''(x) = 3x² - 18x = 3x(x - 6)f''(x) = 0 when x = 0 or x = 6.
We can use the First Derivative Test to determine the nature of the relative extrema:
For x &
lt; 0, f'(x) is negative, then f'(x) is increasing from negative to zero as x approaches 0 from the left.
Therefore, f'(x) has a relative minimum at x = 0.
For 0 < x < 6, f'(x) is positive, then f'(x) is increasing from zero to positive as x increases.
Therefore, f'(x) has a relative maximum at x > 0.
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