PLLLLLLLLLLEEEEEEEEAAAAAAAASSSSSSSSSSEEEEEEE HELP ME Tracy has forgotten how to complete the square. (A) Give her a detailed description of the process so she can understand how to do it. (B) and provide an example of each.

Answer: C.

Step-by-step explanation:

The answer is C. i believe

You have to subtract 2 by 7x = 33    

I hope this helps!

Answer: \(y=10\)

Step-by-step explanation:

Note that \(\angle ACB \cong \angle ACD\) because diagonals of a rhombus bisect the angles from which they are drawn.

Now, because \(m\angle DEC=90^{\circ}\) since diagonals of a rhombus are perpendicular, it follows that \(m\angle CDB+m\angle ABC=90^{\circ}\).

\(6y+2y+10=90\\\\8y+10=90\\\\8y=80\\\\y=10\)

Answer: 10.50

Step-by-step explanation:

Answer:

The answer is (1,-1)

Based on the information provided, none of the given options (a, b, c, or d) accurately represents the percentage for both the United States and Canada.

In the United States, the percentage of 5-year-old children enrolled in group child care or preschool is not 100% (option d).

The actual percentage is lower, and it varies depending on factors such as location, socioeconomic status, and individual choices made by families.

The most recent available data from the National Center for Education Statistics (NCES) shows that for the 2019-2020 school year, around 55% of 5-year-olds in the United States were enrolled in preprimary programs, which includes preschool.

In Canada, the percentage of 5-year-old children enrolled in group child care or preschool is also not 100%.

The actual percentage is higher than in the United States, but it is not 100% (option d).

According to the most recent data available from Statistics Canada for the year 2019, approximately 76% of 5-year-olds were enrolled in some form of early childhood education, which includes child care and preschool programs.

Based on the information provided, none of the given options (a, b, c, or d) accurately represents the percentage for both the United States and Canada.

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The distance between two speakers is important in understanding the phenomenon of interference. In this scenario, we have two loudspeakers, A and B, emitting sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 600 Hz. To move to a point of destructive interference, you need to walk a distance equal to an odd multiple of half the wavelength towards speaker B.

You are standing between the speakers along the line connecting them, and you are at a point of constructive interference.

Constructive interference occurs when the crests of the waves from both speakers align, resulting in a reinforcement of the sound waves. In this case, you are experiencing maximum sound intensity at your position. To move to a point of destructive interference, where the crests of one wave align with the troughs of the other wave, you need to walk towards speaker B.

To determine the distance you need to walk, we can use the concept of the path difference. The path difference is the difference in the distance traveled by the waves from each speaker to reach a given point. In the case of destructive interference, the path difference between the waves from speakers A and B must be equal to an odd multiple of half the wavelength.

Since the frequency is 600 Hz, the wavelength can be calculated using the formula λ = c/f, where c is the speed of sound (approximately 343 m/s) and f is the frequency. Thus, the wavelength is approximately 0.572 m.

For destructive interference, the path difference should be an odd multiple of half the wavelength. Therefore, you need to walk a distance equal to (2n + 1) * λ/2 towards speaker B, where n is an integer.

Let's consider a few examples:

1. If you walk 0.286 m (half the wavelength) towards speaker B, you will reach a point of destructive interference.
2. If you walk 0.572 m (one full wavelength) towards speaker B, you will also reach a point of destructive interference.
3. Similarly, if you walk 1.146 m (two full wavelengths) towards speaker B, you will reach a point of destructive interference.

In conclusion, to move to a point of destructive interference, you need to walk a distance equal to an odd multiple of half the wavelength towards speaker B.

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The cost of the jalapeno poppers is $8.87. Let's denote the cost of the jalapeno poppers as "x".

The total cost of the order, including nachos and jalapeno poppers, is $17.95 + x.

The friends each paid $8.94, which is one-third of the total cost. So, we can write the equation:

8.94 = (1/3) * (17.95 + x)

To find the cost of the jalapeno poppers, we can solve this equation for "x".

Multiplying both sides by 3 gives us:

26.82 = 17.95 + x

Subtracting 17.95 from both sides:

x = 26.82 - 17.95

x = 8.87

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Answer:

-1y² the rest is right

Step-by-step explanation:

Answer:

You can't synthetic divide since there's no dividend. As you can't factor it so I figure you must've forgot to include something or there's no solution.

Answer:

\(P(W') = \frac{6}{n+6}\)

Step-by-step explanation:

Let P(W) represents the probability that Paul wins

Let P(W') represents the probability that Paul does not win

Given

\(P(W) = \frac{n}{n+6}\)

Required

\(P(W')\)

In probability, the sum of opposite probability equals 1;

This implies that

\(P(W) + P(W') = 1\)

Substitute \(P(W) = \frac{n}{n+6}\) in the above equation

\(P(W) + P(W') = 1\) becomes

\(\frac{n}{n+6}+ P(W') = 1\)

Subtract \(\frac{n}{n+6}\) from both sides

\(\frac{n}{n+6} - \frac{n}{n+6} + P(W') = 1 - \frac{n}{n+6}\)

\(P(W') = 1 - \frac{n}{n+6}\)

Solve fraction (start by taking the LCM)

\(P(W') = \frac{n + 6 - n}{n+6}\)

\(P(W') = \frac{n - n + 6}{n+6}\)

\(P(W') = \frac{6}{n+6}\)

Hence, the probability that Paul doesn't win is \(P(W') = \frac{6}{n+6}\)

The months in which the depths decreased are:

Between April and May

Between June and July

The change in depth between April and May is calculated as:

Change in depth = -0.28 - (-0.15) = -0.13 m

Thus, there was a decrease in depth between april and may

The change in depth between May and June is calculated as:

Change in depth = -0.08 - (-0.28) = 0.20 m

Thus, there was an increase in depth between May and June

The change in depth between June and July is calculated as:

Change in depth = -0.01 - (-0.05) = 0.07 m

Thus, there was a decrease in depth between June and July.

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The complete question is:

A scientist measures the depth of the water in a pond each month. The pond is considered full at 0 m. She compares her measures to the height of the water when the pond is considered full and records the change in depth in a table

Between which months did the depth of water decrease?

By cutting and adding a piece of string measuring 8.5 feet, Ed extended the length of his kite string. The new length of the string is the sum of the original length and the additional piece.

Initially, Ed had a kite string with a certain length. Let's assume the original length of the string was x feet. Ed then cut a piece of string measuring 8.5 feet and added it to the existing string. To find the new length of the string, we need to add the original length and the length of the additional piece.

Therefore, the new length of the string can be calculated by adding x feet (the original length) and 8.5 feet (the length of the additional piece). Mathematically, it can be represented as:

New Length = Original Length + Additional Length

New Length = x + 8.5 feet

Thus, the new length of the string is x + 8.5 feet.

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Answer:

D

Step-by-step explanation:

w = 6 m

L = 1/2 m

Area = 1/2 * 6

Area = 3 m^2

Are you sure you have the givens correct?  If you are hesitant about this answer, ask your instructor how it is done.

Edit

In that case (L = 12) then the area is

Area = 12 * 6

Area = 72

So the answer is D

Answer:

12 x 6 = 72

Step-by-step explanation:

There are 15 different positive divisors (greater than 1) for the number m³pt. Here m, p, and t are distinct prime numbers. This is obtained by the prime factorization method.

The following are the steps to find the number of positive factors of a number:

Step 1: Find the L.C.M of the number by using the prime factorization method. For example: consider the number 24. Then, its prime factorization is as follows:

24 = 2 × 2 × 2 × 3

Step 2: Same bases should be added in powers. So, the factors we can write as

24 = 2³ × 3¹

Step 3: To find the number of positive factors of the number, the exponents of the prime factors is multiplied by adding 1.

I,e., N = (3 + 1)(1 + 1) = 4 × 2 = 8.

So, there are 8 factors for the number 32. They are 1, 2, 3, 4, 6, 8, 12, and 24.

It is given that, m, p, and t are distinct positive prime numbers.

Then, the number of positive divisors greater than 1 for the number m³pt are

m³× p × t

Since m, p, and t are prime factors, we can multiply their power by adding 1 to them. I.e.,

N = (3 + 1) (1 + 1) (1 + 1) = 4 × 2 × 2 = 16

So, there are a total of 16 factors for the given number (including 1). So, the number of factors greater than 1 is 16 - 1 = 15.

Therefore, there are 15 different positive divisors greater than 1 for the number having prime factors as m³pt.

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Two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.

Given measure: 3, 5, 4, 6, 10, 5, 6, 9, 2, 13.(D) To calculate \(x_2\), first we need to sort the data in ascending order: 2, 3, 4, 5, 5, 6, 6, 9, 10, 13

Now, we need to find the median, which is the middle value of the data. Since the data has even number of values, we will calculate the mean of middle two values, that is:(5+6)/2 = 5.5 Therefore, \(x_2 = 5.5\).\( \frac{2}{x}= \) To find the value of x, we will first cross-multiply and then take the reciprocal of both sides:\[\frac{2}{x} = y \Rightarrow 2 = xy \Rightarrow x = \frac{2}{y}\] Therefore, \( \frac{2}{x}= \frac{2}{y}\).

(b) To calculate Fried m, we will use the formula: \[f_m = L + \frac{(n/2 - F)}{f} \times c\]where L is the lower limit of the modal class, F is the cumulative frequency of the class preceding the modal class, f is the frequency of the modal class, c is the class interval, and n is the total number of values.

First, we will calculate the class interval:c = (upper limit of class - lower limit of class) = (7-6) = 1 Next, we will construct a frequency table to find the modal class:| Class Interval | Frequency ||-------------------|------------|| 2-3 | 1 || 3-4 | 1 || 4-5 | 1 || 5-6 | 2 || 6-7 | 2 || 7-8 | 1 || 9-10 | 1 || 10-11 | 1 || 13-14 | 1 |The modal class is the class with highest frequency.

Here, two classes have frequency 2, so both are modes. They are 5-6 and 6-7.

Therefore, L = 5, F = 2, f = 2, n = 10, and c = 1. Substituting the values, we get:\[f_m = L + \frac{(n/2 - F)}{f} \times c = 5 + \frac{(10/2 - 2)}{2} \times 1 = 7\] Therefore, Fried m = 7.

(c) To find the mode, we look for the value(s) with highest frequency. Here, two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.

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Answer:

Step-by-step explanation:

The graph of the piecewise function is attached below.

Function is a type of relation, or rule, that maps one input to specific single output.

The piecewise function is given as:

f(x) =  - 6  for  -6< x < 1

       -2x + 5 for  1< x < 6

The above means that we plot the function on their interval or domain.

i.e. we plot f(x) = - 6  on the interval x < 0 and f(x) = -2x + 5 on the interval x < -6

Next, we plot the graph of the piecewise function.

Thus, The graph of the piecewise function is attached below.

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Answer: 6x

Step-by-step explanation:

so consider x as the number,

twice of x= 2x

2x tripled= 2x*3

               = (2*3)x

               = 6x

Answer:

See  below.

Step-by-step explanation:

Arranging the data in ascending order:

Team one: { 47, 49,  51,  53,  54,  54,  57, 59, 60, 62}

Team two:  {43, 48,  49,  51,   52, 53,  56, 57,  61,  63}

The mean for team one = sum of the scores / 10 =

= 546/10 = 54.6.

The median for team 1 = 54.

The mean for team two = sum of the scores / 10 =

= 533/10 = 53.3.

The median for team 2 = 52.5.

Team 1 has a higher mean than team 2:  54.6 - 53.3  = 1.3 higher.

In both cases, the mean is greater than the median though the difference is < 1 in both cases. So in both cases the distribution of the scores is close to symmetrical, with team 1 being slightly more symmetrical.

Answer:

60°

Step-by-step explanation:

because sum of internal angles of traingle is always 180°

The average time it takes to rent a video tape is 0.141 minutes.

Given data:Customers arrive at a video rental desk at the rate of 12 per minute(Poisson).
Each server can handle 8.15 customers per minute(Poisson). If there are 3 servers, we need to determine the average time it takes to rent a video tape.
Let us assume λ = 12 and μ = 3 × 8.15 = 24.45
Average time it takes to rent a video tape = 1 / (μ - λ/n)
Where, n = number of servers⇒ Average time it takes to rent a video tape = 1 / (24.45 - 12/3)⇒ Average time it takes to rent a video tape = 1 / 8.45⇒ Average time it takes to rent a video tape = 0.1185 minutes = 0.141 rounded to three decimal places.

Thus, the average time it takes to rent a video tape is 0.141 minutes.

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Answer:

convert all into decimals then sort greatest to least

Answer:

Please don't cheat Elina, it isn't worth it, what do you gain?

Explanation:

Rather than eating hot cheetos and facetiming your friends such as hi*za and reb***a you should study! Studying is the key to success rather than gossip and other stuff. The answer is wisdom, nothing less and nothing more. Go on the right path to success not the wrong way. Oh and, I ain't never seen two pretty best friends, it's always one of them that gotta be ugly.

Answer:

can't can't be simplified .

Step-by-step explanation

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. The range is the set of all valid y values.

Step-by-step:ex:pla:nation

Step-by-step explanation:

A represents the number of minutes for television advertising an B represents the square inches of newspaper advertising.

To find the price, you have to multiply the amount of money per minute by the number of minutes for television advertising which is $100 and the amount of money per square inch for newspaper advertising which is $25 and it should be less than or equal to the money he has allocated to advertising as seen in the inequality below.

100a + 25b  ≤  2500

The simplification based on Laurent series of the function (22-9)(2+3) centered at z = −3

[((1/4)(3)⁴ + (2/3)(3)³ + (9/2)(3)² - 27(3))] - [((1/4)(-3)⁴ + (2/3)(-3)³ + (9/2)(-3)² - 27(-3))]

The given problem involves finding the Laurent series of a function centered at z = -3 and evaluating the integral of another function over a specific interval. The Laurent series simplifies to a constant term of 65.

(a) To find the Laurent series of the function (22-9)(2+3) centered at z = −3, we can expand the function in powers of (z + 3):

(22-9)(2+3) = (13)(5) = 65

Since there are no negative powers of (z + 3), the Laurent series of the function is simply the constant term:

f(z) = 65

(b) To evaluate the integral ſc[−3,3] (z²−9)(z+3) dz, we can first simplify the integrand:

(z² - 9)(z + 3) = (z - 3)(z + 3)(z + 3) = (z - 3)(z + 3)²

Now, let's integrate the simplified expression:

∫[(z - 3)(z + 3)²] dz

Expanding the expression:

∫[z³ + 6z² + 9z - 27] dz

Integrating each term:

(1/4)z⁴ + (2/3)z³ + (9/2)z² - 27z

Now, we can evaluate the integral over the given interval [−3, 3]:

∫[−3,3] (z²−9)(z+3) dz = [((1/4)z⁴ + (2/3)z³ + (9/2)z² - 27z)] evaluated from z = -3 to z = 3

Substituting the upper and lower limits into the expression and simplifying, we get:

[((1/4)(3)⁴ + (2/3)(3)³ + (9/2)(3)² - 27(3))] - [((1/4)(-3)⁴ + (2/3)(-3)³ + (9/2)(-3)² - 27(-3))]

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Answer:

The length of the missing leg:

Step-by-step explanation:

Given

To determine:

The length of the leg b = ?

For a right-angled triangle, with sides a and b the hypotenuse c is defined as:

\(c=\sqrt{a^2+b^2}\)

We can find the length of the leg b using the formula

\(b=\sqrt{c^2-a^2}\)

substituting c = 10 and b = 6 in the formula

\(b=\sqrt{10^2-6^2}\)

\(b=\sqrt{100-36}\)

\(b=\sqrt{64}\)

\(b=\sqrt{8^2}\)

\(\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\)

\(b=8\) mi

Therefore, the length of the missing leg:

Answer:

a). AB = 8 in

b). AB = 9.75 in

c). AC = 6.5 in

d). BC = 1.5 in

Step-by-step explanation:

a). Since, AB = AC + CB

   Length of AC = 5 in. and CB = 3 in.

   Therefore, AB = 5 + 3 = 8 in.

b). Given : AC = 6.25 in and CB = 3.5 in

   Therefore, AB = AC + CB = 6.25 + 3.5

   AB = 9.75 in.

c). Given: AB = 10.2 in. and BC = 3.7 in.

    AB = AC + BC

    AC = AB - BC

    AC = 10.2 - 3.7

    AC = 6.5 in

d). Given: AB = 4.75 in and AC = 3.25 in.

   BC = AB - AC

   BC = 4.75 - 3.25 = 1.5 in.

We can see that h is the opposite angle of the angle which measures 47, as they are the angles that are directly opposite to each other where 2 lines/rays cross.

And since 2 opposite angles are equal to each other, h = 47.

Answer:

1. $1400

2 329.4 shares

3. $350

4. 1.25

Step-by-step explanation:

1. if Tim does not buy DEF, how many can he spend on ABC?

From the attached image

100 shares for ABC = $425

100 shares for DEF $600 + $375 commission

Therefore, the amount he can spend on ABC without buying DEF = $600 + $375 + $425 = $1400

2: how many shares of ABC can he buy if he does not buy DEF?

$425 = 100 shares

$1400 =

Cross Multiply

= $1400 × 100 shares/ $425

= 329.41176471 shares

= 329.4 shares

3: if the selling price is $1,750, how much will Tim have earned by investing?

The cost of buying ABC = $1400

The Amount earned from investing = $1750 - $1400

= $350

4: what is the total return divided by the total cost In this example?

Total return = $1750

Total cost = $1400

= $1750/$1400

= 1.25

Answer:

y = 4x + 8

Step-by-step explanation:

1) Find slope:

y2-y1/x2-x1

12-8/1-0 = 4/1 = 4

Slope = 4

2) Plug in a point in point-slope form

y-y1=m(x-x1)

y-8=4(x-0) =

y-8=4x-0 -> add 8 to both sides

y=4x+8

Answer:

21

Step-by-step explanation:

Answer: The correct answer is 21

Step-by-step explanation:

HAVE A GOOD DAY!