A chemical rocket may launch a satellite into a Hohmann transfer orbit and maintain it there until it reaches the farthest point in the orbit by performing two very powerful burns.
These chemical rockets aren't very effective, though. They would have perished because it would have taken four weeks to return to Earth orbit.One (very powerful) engine burn is all that the Hohmann transfer orbit requires. But the interval between the two engine burns is nearly half an orbit, or 2 weeks in the event of an Earth to Moon transfer, as opposed to 3 days for the Apollo approach.That translates into four times as much food, oxygen, and cramping in the muscles, which results in increased mass and fuel. Apollo 13 remained on its orbit around the Moon after their oxygen tank exploded, depriving them of electrical power and heating, and returned to Earth after nearly 5 days.They would have perished if they had been in a Hohmann transfer orbit, which would have taken around 4 weeks to return to.
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1. The three forces shown below act on a particle.
a. Find the x and y components of the 6 N force b.
b. Calculate the magnitude of the resultant of the three forces.
The x-component of the 6 N force is 4.24 N and the y-component of the 6 N force is 4.24 N.
The magnitude of the resultant of the three forces is 1.27 N.
What is the resultant of the three forces?To find the x and y components of the 6 N force, we can use trigonometry.
The 6 N force makes an angle of 45° with the positive x-axis, so:
x-component of 6 N force = 6 N cos(45)
x-component = 4.24 N
y-component of 6 N force = 6 N sin(45)
y-component = 4.24 N
b. To calculate the magnitude of the resultant of the three forces, we need to find the x and y components of the resultant force and then use the Pythagorean theorem to calculate the magnitude.
The x-component of the resultant force is the sum of the x-components of the three forces:
x-component = 4.24 N - 3 N + 0 N
x-component = 1.24 N
The y-component of the resultant force is the sum of the y-components of the three forces:
y-component = 4.24 N + 0 N - 4 N
y-component = 0.24 N
The magnitude of the resultant force is given by:
resultant force = √(x² + y²)
resultant force = √{(1.24 )² + (0.24)²
resultant force = 1.27 N
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Select the correct answer.
Which physical property causes you to lean to one side when the bus you are traveling in takes a sharp turn?
A.
inertia
B.
mass
C.
speed
D.
velocity
Answer: I believe that the answer to your question is "Inertia", or A
Explanation:
name two different objects you could use to light a room if you have a power cut. for each object describe the energy transfer and changes to energy stores that occur when it lights up the room
Answer:
candle and hand torch
Explanation:
we can find a light energy and heat energy from the candle but only light energy for hand torch
A car moves with uniform velocity of 40m/s for 5 s. It comes to rest in the next 10 s with uniform deceleration
Answer:
-8 m/s²
Explanation:
Initial velocity = 40 m/s
Final velocity = 0 m/s
Time (T1) = 5 s
Time (T2) = 10 s
Acceleration = v - u/t2 - t1
Acceleration = 0 - 40/10 - 5
Acceleration = -40/5
Acceleration = -8 m/s²
Have you donated blood ? If so describe your experience. If not, explain whether you would or would not donate blood and why.
What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its original length
The speed of the chord wave allows finding a new speed when the mass is increased and the chord length is:
The velocity is: v = \(\frac{v_o}{3}\)
A wave is a periodic movement of the particles that carries energy, but not matter, the speed of the waves is related to the properties of the medium by the relationship.
\(v = \sqrt{\frac{T}{\mu } }\)
Where v is the speed of the wave, T the force and μ is the linear density.
Indicates that the applied mass increases by a factor of 18.0 and the length of the head is increased to twice the original.
The linear density of the cable is
\(\mu = \frac{m}{l}\)
Where m is the mass of the cable and l is the length.
Let's use the subscript "o" for the initial conditions.
M = 18.0 m₀
l = 2 l₀
We look for the density.
\(\mu = \frac{18.0 m_o}{2.0 l_o}\)mu = 18.0 mo / 2 lo
\(\mu = 9.0 \mu_o\)
We substitute in the expression for the velocity assuming that the tension is kept constant.
\(v= \sqrt{\frac{T}{9.0 \mu} }\)
\(v= \frac{v_o}{3}\)
In conclusion, using the speed of the chord wave we can find a new speed when the mass is increased and the chord length is:
The velocity is: v = \(\frac{v_o}{3}\)
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106. Block A, with a mass of 4 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8 kg, is moving in the opposite direction with a speed of 3 m/s. The center of mass of the two block-system is moving with a velocity of:
Answer:
v = 1⅓ m/s in the direction of the 8 kg block.
Explanation:
As momentum is a vector, we need to handle direction as well as magnitude.
If we assume the 4 kg block is moving in the positive direction.
4(2.0) + 8(-3) = (4 + 8)v
v = -1.33333...
explain the term tenscopo
Answer: Here you go, i hope this kinda helps.
Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".
Watson Assistant replies to user's questions based on a confidence score.
Sometimes the customer's question could be interpreted in two or three different ways.
For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:
Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?
Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.
Pulley system is marked wih a Mechanical Advantage of 2.5. A worker applies 450n to the pulley in an attempt to lift a sound system with a 1500n weight. Of this task we could say that:
The worker must apply 600N of force to lift the sound system. The mechanical advantage of 2.5 means that the worker only needs to apply 600N of force to lift the sound system.
What is Pulley system?We can employ pulley systems to provide ourselves a mechanical advantage by multiplying our input effort to apply more force to a load.
They can be used to apply tension within a system, such as in a Tensioned Line or Tyrolean, in addition to their traditional uses of hauling and lifting loads. The basic operating principles of pulley systems are explained on this page; for details on how to use them for hauling, check the topic on hauling systems.
The dynamic unit of Newtons is commonly used to express force, which is an impact that has both magnitude and direction (N). On this page, kilograms have been utilized for the sake of clarity.
Therefore, The worker must apply 600N of force to lift the sound system. The mechanical advantage of 2.5 means that the worker only needs to apply 600N of force to lift the sound system.
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HELPP
When two forces are in opposite directions, and they are the exact same magnitude, the forces will _______.
a. subtract from each other
b. cancel out
c. go on infinitely
d. eventually reach equilibrium
Answer:
i think the correct answer is B. cancel out
Define a surface based temperature inversion
Answer:
temperature inversion, also called thermal inversion, a reversal of the normal behaviour of temperature in the troposphere (the region of the atmosphere nearest Earth's surface), in which a layer of cool air at the surface is overlain by a layer of warmer air. example <freezing rain
Asset questions below fill in the blanks
Acceleration is defined as the change in velocity per unit time. Its unit is m/s².
Distance is the amount of space, or the actual length of the path travelled.
Displacement is the difference between the initial and final positions of the object.
Speed is the rate at which an object covers a certain distance.
Velocity is defined as the speed with a direction.
An object is said to have a positive velocity, if it is moving in the positive direction. And an object moving in negative direction has a negative velocity.
Acceleration is the change in velocity per unit time.
For freely falling objects, gravity is the only thing acting on the object.
The acceleration due to gravity on the earth is 9.8 m/s².
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The speed of a cart is increased uniformly from 0.32 meters per second to 1.43 meters per second in 1.82 seconds. The cart’s acceleration is
Answer:
0.610m/s^2
Explanation:
Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.
If an object is placed 15cm in of front of a concave mirror of radius Curvature 20cm. Determine the position of the image formed
The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
Given that,
Object distance, u = -15 cm
The radius of curvature of the concave mirror, R = 20 cm
Focal length, f = R/2 = -10 cm (negative for concave mirror)
Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :
\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)
\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)
\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)
\($v=-30 \mathrm{~cm}$\)
So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
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20 POINTS
An object released from rest at time t = 0 slides down a frictionless
incline a distance of 2 m during the time interval from t=0 s to t = 1 s.
The distance traveled by the object during the time interval from t = 2s
to t = 3s is: (A) 15 m (B) 10 m (C) 5 m (D) 2 m (E) 1m
Answer:
10m
Explanation:
let's take the acceleration as a constant throughout the complete motion...
therefore first let's find the acceleration
\(s = ut + \frac{1}{2} a {t}^{2} \\ 2 = \frac{1}{2} a {1}^{2} \\ a = 4m {s}^{ - 2} \)
then we have to find v1
apply V = u + at
v = 4×1
= 4ms^-1
lets find the distance travel by the object DURING THE TIME INTERVAL 1-2
\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 4 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s= 6m \)
then let's find the V2
\( {v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {4 }^{2} + 2 \times 4 \times 6 \\ {v}^{2} = 64 \\ v = \sqrt{64} = 8m {s}^{ - 1} \)
then let's find the distance travel by the object during time interval 2s to 3s\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 8 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s = 10m \)
The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.
What are the three equations of motion?There are three equations of motion given by Newton
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, an object released from rest at time t = 0 slides down a frictionless incline a distance of 2 m during the time interval from t=0 seconds to t = 1 seconds.
2 = ut + 1/2*a*t²
2 = 0 + 0.5×a×1²
a = 2 / 0.5
a = 4 meters / second²
Now to find the velocity after the 2 seconds,
v = u + at
v = 0 + 4×2
v = 8 m/s
Now by using the second equation of motion,
S = ut + 1/2×a×t²
S = 8×1 + 0.5×4×1²
S = 8 + 2
S = 10 meters
Thus, The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.
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Which particles are considered nucleons? O A. Electrons and neutrons O B. Neutrons and protons OC. Protons and electrons D. Only electrons
The particles that are considered nucleons are neutrons and protons. Option B.
What are nucleons?Nucleons are particles found in the nucleus of an atom, specifically protons and neutrons.
Protons have a positive charge, while neutrons have no charge, and together they make up the majority of the mass of an atom.
Electrons, on the other hand, are much smaller than protons and neutrons, and they orbit around the nucleus in shells. Since they are not found in the nucleus, electrons are not considered nucleons.
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When you throw a ball into the air, its kinetic energy _
Answer:
increases
Explanation:
The ball's kinetic energy is the energy it has due to its motion. When you throw the ball into the air, it gains kinetic energy from the force of your throw.
You are standing on a large sheet of frictionless ice and holding a large rock. In order to get off the ice, you throw the rock so it has velocity 12.0 m/s relative to the earth at an angle of 35.0∘ above the horizontal. Your mass is 72.0 kg and the rock’s mass is 3.50 kg . What is your speed after you throw the rock?
Answer:
0.4778 m/s
Explanation:
To solve this question, we will make use of law of conservation of momentum.
We are given that the rock's velocity is 12 m/s at 35°. Thus, the horizontal component of this velocity is;
V_x = (12 m/s)(cos(35°)) = 9.83 m/s.
Thus, the horizontal component of the rock's momentum is;
(3.5 kg)(9.83 m/s) = 34.405 kg·m/s.
Since the person is not pushed up off the ice or down into it, his momentum will have no vertical component and so his momentum will have the same magnitude as the horizontal component of the rock's momentum.
Thus, to get the person's speed, we know that; momentum = mass x velocity
Mass of person = 72 kg and we have momentum as 34.405 kg·m/s
Thus;
34.405 = 72 x velocity
Velocity = 34.405/72
Velocity = 0.4778 m/s
Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.
The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.
What is Force?Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = m(vf - vi)
Δ P = 1300 (0 - 11)
Δ P = -1.43 × 10⁴ kg.m/s
The impulse is equal to the change in momentum of the car
I = -1.43 × 10⁴ kg.m/s
Magnitude of the force experienced by Kara
I = F × t
where, I is impulse acting on the car
t is time
- 1.43 × 10⁴ = F × 0.14
F = -1.021 × 10⁵ N
Negative sign represents the direction of the force.
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Your question is incomplete, most probably the complete question is:
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.
a. Determine the momentum change of Kara's car.
b. Determine the impulse experienced by Kara's car.
c. Determine the magnitude of the force experienced by Kara's car.
re testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A) the car has a speed of 25.0 m/s and at the top of the loop (point B) it has speed of 8.00 m/s . You may want to review (Pages 203 - 212) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A vertical circle with friction. Part A As the car rolls from point A to point B, how much work is done by friction?
Answer:
-4530 J
Explanation:
Given that
Mass of the car, m = 100 kg
Speed of the car at point A, v1 = 25 m/s
Speed at point B, v2 = 8 m/s
Radius of the track, r = 12 m and with respect to the origin of the center of the track, we say that y1 = -12 at point A and y2 = 12 at point B
We also know that
W(total) = W(grav) + W(other) = K₂ - K₁
Work done by the gravitational force, W(grav) = -U(grav) = mgy1 - mgy2
Kinetic Energy, K = ½mv²
Adding all together, we have
½mv₁² + mgy1 + W(other) = ½mv₂² + mgy2
½ * 100 * 25² + 100 * 9.8 * -12 + W = ½ * 100 * 8² + 100 * 9.8 * 12
50 * 625 + 980 * -12 + W = 50 * 64 + 980 * 12
31250 - 11760 + W = 3200 + 11760
19490 + W = 14960
W = 14960 - 19490
W = -4530 J
What is scintillator
Answer:
Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).
https://web.stanford.edu › scintillators
What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory
A horse is dragging a crate behind it. The horse applies a force of 60.0 N to accelerate the crate to the right, and the crate experiences a 10.0-N force in the opposite direction due to a force called friction from the ground. The crate's acceleration is 0.67 m/s?. Determine the crate's mass.
The mass of the crate is approximately 74.63 kg.To determine the crate's mass, we can use Newton's second law of motion.
The Newton's law of motion states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be expressed as:
Net Force = mass × acceleration
In this case, the net force acting on the crate is the force applied by the horse (60.0 N) minus the force of friction (10.0 N), which is given as:
Net Force = 60.0 N - 10.0 N = 50.0 N
The acceleration of the crate is given as 0.67 m/s².
We can now rearrange the equation to solve for mass:
mass = Net Force / acceleration
mass = 50.0 N / 0.67 m/s²
mass ≈ 74.63 kg
Therefore, the mass of the crate is approximately 74.63 kg.
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one of the primary characteristics present in situations in which management science techniques are applied is_____.
One of the primary characteristics present in situations in which management science techniques are applied is that the management problems have only a few variables. Thus, the correct option is A.
What are Management science techniques?Management science is important while doing any research, business, or study because it helps the organizations in identification of the issues which they need to solve, streamline management efforts, use resources more effectively, and also develop roadmaps for achieving the set goals.
Management problems are studied and these are so complicated that managers need help to analyze a large number of variables before doing any research.
Therefore, the correct option is A.
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Your question is incomplete, most probably the complete question is:
One of the primary characteristics present in situations in which management science techniques are applied is ________.
A) that the management problems have only a few variables
B) that the situation deals with quantifiable factors such as sales
C) that the situation deals with the physiological, safety, social, esteem, and self-actualization needs of organization members
D) that the situation deals with assessing qualitative factors of the workplace or environment
E) that social implications are the guidelines for making a particular decision
Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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How does the law of conservation of mass apply to chemical reactions?
Answer: mass is neither created nor destroyed
Explanation: For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.
The discipline, which seeks to understand and compare religious patterns from around the world is known as?
water vapor is what kind of gas?
Answer:
the gaseous phase of water
Explanation:
"It is one state of water within the hydrosphere. Water vapor can be produced from the evaporation or boiling of liquid water or from the sublimation of ice. "
hope this helps!!
Water vapor is a greenhouse gas.
I know this is a simple answer, but I sincerely hope this helped!
Compare sound and earthquake waves
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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Water in a metal pot is heated over a campfire. Primarily, by wat means of energy transfer is thermal energy moved from the fire to the bottom of the pot?
when water in a metal pot is heated over a campfire. Primarily, by means of convection energy transfer is thermal energy moved from the fire to the bottom of the pot
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
Thermal energy can flow by different means such as conduction, convection, and radiation.
As given in the problem when water in a metal pot is heated over a campfire. The energy we receive around the campfire is mostly due to the effect of the radiation of the heat but the Primary means of energy transfer is thermal energy moved from the fire to the bottom of the pot because of the convection.
Thus, when water is heated in a metal pot over a campfire. Thermal energy is primarily transferred from the fire to the bottom of the pot through convection.
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