Should the battery still be able to produce energy, it would last for 1000 hours.
How does a battery keep its power?Batteries employ chemistry to store energy in the form of chemical potential, much like many other widely used energy sources. Until they burn, for instance, oxygen and logs both contain energy in their chemical bonds, some of which is later transformed into heat.
In its electrolytes and plates, batteries store chemical energy in the form of power. Chemicals' nature is altered during storage by the influence of an electric current.
Current demand on battery is now = 12/600 = 0.02 Amps
A factor 50 times smaller than the 1 amp/20 hour rating
the battery retain an energy producing capability = 50 × 2 = 1000hrs.
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Which type of stress causes fault-block mountains?
Answer:
tension
Explanation:
correct on edge
Consider a planet with an average surface temperature of 735 K. Will it lose water molecules (molecular weight = 34) in its atmosphere to space if the planet's escape speed is 10.4 km/s?
Yes or no
No, a planet with an average surface temperature of 735 K will not lose water molecules to space if its escape speed is 10.4 km/s.
The ability of a planet to retain its atmospheric molecules depends on various factors, including the average kinetic energy of the molecules and the escape speed of the planet. In this case, the average surface temperature of the planet is 735 K, which corresponds to high thermal energy for the water molecules in the atmosphere.
However, the escape speed of the planet is given as 10.4 km/s.
To determine whether the water molecules will escape to space, we compare the average thermal velocity of the water molecules to the escape speed. The average thermal velocity of a gas molecule can be calculated using the root mean square velocity formula, which depends on the temperature and the molecular weight. Considering the molecular weight of water as 34 g/mol, the average thermal velocity can be determined.
Given the high temperature of the planet, the average thermal velocity of water molecules would be relatively high. However, since the escape speed of the planet is significantly higher than the average thermal velocity of the water molecules, they would not have enough kinetic energy to overcome the planet's gravitational pull and escape into space.
Therefore, the planet will not lose water molecules from its atmosphere despite the high temperature.
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which type of mater conduct heat?
Answer:
Copper is the best conductor
On april 15, 1912, the luxury cruise liner titanic sank after running into an iceberg, what was the cruise liners speed when it collided with the iceberg if it had a mass of 4.23*10^8 kg ship and a momentum of 4.9* 10^9 kg*m/s?
REPLY FAST
On april 15, 1912, the luxury cruise liner titanic sank after running into an iceberg the Titanic's collision speed with the iceberg was 11.6 m/s.
Evaluating :An object's momentum is calculated by multiplying its mass by its velocity. The Titanic's momentum in this instance is :
4.9 x 10⁹ kg ×m/s.
The Titanic has a mass of 4.23 x 10⁸ kilograms. As a result, we can divide the momentum by the mass to determine the Titanic's velocity before it hit the iceberg :
momentum = mass x velocity
4.9 x 10⁹ kg×m/s
= (4.23 x 10⁸ kg) x velocity
velocity = 4.9 x 10⁹ kg ×m/s / (4.23 x 10⁸ kg)
= 11.6 m/s
So the speed of the Titanic when it collided with the iceberg was 11.6 m/s.
Momentum :
Momentum is the sum of a particle's velocity and mass. The quantity momentum is a vector; that is, it has magnitude as well as direction. According to Isaac Newton's second law of motion, the particle's force equals the time rate of momentum change.
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How does the Coriolis effect impact the Gulf Stream and the Brazil Current?
Answer: The Coriolis effect results in bending the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere. The Coriolis effect causes winds and currents to form the circular patterns. The direction in which they spin depends upon the hemisphere in which they are present.Coriolis Effect is named after the French mathematician and physicist Gaspard-Gustave de Coriolis. It affects the weather patterns of an area, it affects the ocean currents, and it also affects air quality.
Hip hop dance translate feelings and emotions of human conditions, situations, or fantasies into movement and dramatic expressions? True or false?
Answer:
false .....................
A 10-kg box Initially at rest and moves along a frictionless horizontal surface. A Horizontal force to the right as applied to the box. The magnitude of the box change of the function of time as shown
b. What is the velocity of the box at 10 seconds? Show your work.
c. If you want to apply at constant force starting at 10 seconds, that would stop the box at exactly 20 seconds. What would the magnitude and direction of that force be? Show your work
Answer:
b. 1.1 m/s c. -1.1 m/s
Explanation:
b.
m x v=f x t
The mass is 10 kg
10 x v (equation for momentum) = f x t (impulse)
you would find the impulse by finding the area under the graph, and then dividing by the mass
So in this case:
10 x v = 11
then divide by the mass
v = 11/10
v= 1.1 m/s
c.
F x t = impulse
we are trying to find force (magnitude)
impulse/t = F
we said that in order for it to stop the impulse for b would be 11, so if thats the case it would be 11 but it would be negative because when going in a positive direction and suddenly stopping the direction changes.
-11/t = F
to find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.
-11/10 = F
F= -1.1 m/s
Answer B:
The velocity of the box at 10 seconds is :
Formula :m x v=f x t
Given Information :
Mass(m)=10kg
10 x v (equation for momentum) = f x t (impulse)10 x v = 11v = 11/10v= 1.1 m/sTherefore, the velocity of the box at 10 seconds is 1.1m/s.
Answer C:
The magnitude and direction of that force be :
Formula:F x t = impulse
impulse/t = F-11/t = FTo find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.
-11/10 = FF= -1.1 m/sThe magnitude and direction of that force will be -1.1m/s.
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which term describes a lens with a surface that curves outward like the exterior of a sphere?
Answer:
Convex lens
hope that helps you
a force of 45 n is used to slide a 10 kg mass 5 m along an inclined plane. if the ramp has a height of 2 meters, what is the actual mechanical advantage of the ramp?
A force of 45 n used, The actual mechanical advantage of the ramp is 2.18.
Weight = 10g
= 10 × 9.81
= 98.10N
Force used = 45 N
Mechanical advantage = Height / Force used = 98.1/45 = 2.18
The inverse relationship between acceleration and mass is stated by Newton's second law, which also states that force and acceleration are directly proportionate. By using kinematic measurements, accelerations can be identified. The correct definition of mass is still a contentious issue, despite the fact that modern physics' reference frame analysis provides a comprehensive description of kinematics. It is not apparent how or not this link holds true on microscales because general relativity provides an equivalency between space-time and mass in the absence of a cogent theory of quantum gravity. By expressing Newton's second rule as an equality, the relative units of force and mass may be determined and the law can be interpreted as a quantitative description of mass.
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HELP ASAP need it soon
Answer:
The answer to your question is given below.
Explanation:
The energy and frequency of a wave are related by the following equation:
E = hf
Where
E => is the energy.
h => is the Planck's constant.
f => is the frequency
From the formula i.e
E = hf
The energy is directly proportional to the frequency. Thus, an increase in the frequency of the wave will lead to an increase in the energy and a decrease in the frequency of the wave will lead to a decrease in the energy.
Considering the question given above, if the frequency of the wave is decreased, then the energy of the wave will also decrease.
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Formation of the Solar System Lab Report
Instructions: In this virtual lab, you will investigate the law of universal gravitation by manipulating the size of the star and the positions of planets within Solar System X. Record your hypothesis and results in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objectives(s):
In your own words, what is the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.
If the mass of the sun is 1x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome.
Using the summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record your observation statements from Space Academy.
When the mass of the sun is larger, Earth moves around the sun at a ______ (faster, slower) pace.
When the mass of the sun is smaller, Earth moves around the sun at a ______ (faster, slower) pace.
When Earth is closer to the sun, its orbit becomes _____ (faster, slower).
When Earth is farther from the sun, its orbit becomes _____ (faster, slower).
For each trial, record the orbit number of each planet from the sun. Be sure to indicate the number of planets in the habitable zone after each trial. Create a different configuration of planets for each trial. An example has been supplied for you.
Orbit Number
Planet One Orbit Number
Planet Two Orbit Number
Planet Three Orbit Number
Planet Four Number of planets in the habitable zone Number of planets left in successful orbit
Example: sun's mass 1x
1
3
5
6
1
2
sun's mass 1x—Trial One
sun's mass 1x—Trial Two
sun's mass 2x—Trial One
sun's mass 2x—Trial Two
sun's mass 3x—Trial One
sun's mass 3x—Trial Two
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
Using two to three sentences, summarize what you investigated and observed in this lab.
You completed three terra forming trials. Describe the how the sun's mass affects planets in a solar system. Use data you recorded to support your conclusions.
In this simulation, the masses of the planets were all the same. Do you think if the masses of the planets were different, it would affect the results? Why or why not?
How does this simulation demonstrate the law of universal gravitation?
It is the year 2085, and the world population has grown at an alarming rate. As a space explorer, you have been sent on a terraforming mission into space. Your mission to search for a habitable planet for humans to colonize in addition to planet Earth. You found a planet you believe would be habitable, and now need to report back your findings. Describe the new planet, and why it would be perfect for maintaining human life.
Name and Title:
[Your Name], [Instructor's Name], [Date], Formation of the Solar System Lab Report
Objective(s):
The purpose of this lab is to investigate the law of universal gravitation by manipulating the size of the star and the positions of planets within Solar System X, and to understand the factors that influence the habitable zone of planets.
Hypothesis:
(Complete this section with your specific predictions based on the lab activity instructions)
Procedure:
(Include any errors or factors that might have affected the outcome of the experiment)
Dependent variable: The planets' positions in the habitable zone
Independent variable: The mass of the sun
Data:
(Complete the observation statements and record your data from the Space Academy)
Conclusion:
In this lab, we investigated the law of universal gravitation by altering the mass of the sun and positions of planets in Solar System X. We observed how these factors affect the habitable zone of planets and their orbits.
The sun's mass has a significant impact on planets in a solar system. As the mass of the sun increases or decreases, the habitable zone and the planets' orbital speeds change accordingly, as evidenced by our recorded data.
If the masses of the planets were different, it might affect the results, as planets with larger masses would experience a stronger gravitational pull from the sun, influencing their orbits and habitable zones.
This simulation demonstrates the law of universal gravitation by showing how the mass of the sun and planets, along with the distances between them, affect their gravitational attraction and orbits.
In 2085, as a space explorer searching for habitable planets, I discovered a planet that appears suitable for human colonization. This new planet is located within the habitable zone of its solar system, has an Earth-like atmosphere and temperature, and contains abundant water resources. These factors make it ideal for sustaining human life and serve as a potential solution to Earth's overpopulation crisis.
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A cable of 10 mm outside is to be laid in an atmosphere of 25 degree Celsius (h = 12.5 W/m2 degree) and its surface temperature is likely to be 75 degree Celsius due to heat generated within it. How would the heat flow from the cable be affected if it is insulated with rubber having thermal conductivity k = 0.15 W/m degree?
a) 43.80 W per meter length
b) 53.80 W per meter length
c) 63.80 W per meter length
d) 73.80 W per meter length
Insulating the cable with rubber having a thermal conductivity of 0.15 W/m degree increases the heat flow from the cable to 63.80 W per meter length compared to a non-insulated cable in an atmosphere with a temperature difference of 50 degrees Celsius. The correct option is C.
To determine how the heat flow from the cable is affected by insulation, we need to calculate the heat transfer rate for both the insulated and non-insulated cases. The heat transfer rate can be determined using the formula:
Q = (T2 - T1) / (R_total)
Where:
Q is the heat transfer rate per unit length (W/m),
T2 is the surface temperature of the cable (75 degrees Celsius),
T1 is the ambient temperature (25 degrees Celsius),
R_total is the total thermal resistance.
For the non-insulated case:
R_total = R_convection
For the insulated case:
R_total = R_convection + R_insulation
Let's calculate the heat transfer rate for both cases:
Non-insulated case:
R_convection = 1 / (h * A)
A = 2 * π * r * L (surface area of the cable)
Q_non-insulated = (T₂ - T₁) / (R_convection)
Insulated case:
R_insulation = d / (k * A)
Q_insulated = (T₂ - T₁) / (R_convection + R_insulation)
Given the information:
h = 12.5 W/m² degree
k = 0.15 W/m degree
d = 10 mm = 0.01 m
T₂ = 75 degrees Celsius
T₁ = 25 degrees Celsius
By comparing the heat transfer rates for the non-insulated and insulated cases, we can determine the effect of insulation on the heat flow from the cable.
Therefore, by Calculating the values and comparing the heat transfer rates, we find that the correct option is c) 63.80 W per meter length.
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An engineer is designing a runway. She knows that a plane, starting at rest, needs to reach a speed of 180mph at take-off. If the plane can reach this take-off speed in 65.0s, how far will the plane travel before take-off. Assume the plane increases speed steadily.
How far does the plane need to travel during take-off (in given units)?
ft
Could the plane take off on a 10000ft long runway?
Answer:
The plane would need to travel at least \(8,\!580\; {\rm ft}\) (\(8.58 \times 10^{3}\; {\rm ft}\).)
The \(10,\!000\; {\rm ft}\) runway should be sufficient.
Explanation:
Convert unit of the the take-off velocity of this plane to \(\rm ft\cdot s^{-1}\):
\(\begin{aligned}v &= 180\; {\rm mph} \\ &= 180\; {\rm mi \cdot hrs^{-1}} \times \frac{1\; {\rm hrs}}{3600\; {\rm s}} \times \frac{5280\; {\rm ft}}{1\; {\rm mi}} \\ &= 264\; {\rm ft \cdot s^{-1}}\end{aligned}\).
Initial velocity of the plane: \(u = 0\; {\rm ft \cdot s^{-1}}\).
Take-off velocity of the plane \(v =264\; {\rm ft\cdot s^{-1}}\).
Let \(x\) denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation \(x = ((u + v) / 2) \, t\).
Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration \(t\) times average velocity \((u + v) / 2\).
The distance that the plane need to cover would be:
\(\begin{aligned}x &= \left(\frac{u + v}{2}\right)\, t \\ &= \frac{0\; {\rm ft \cdot s^{-1}} + 264\; {\rm ft \cdot s^{-1}}}{2} \times 65.0\; {\rm s} \\ &= 8.58\times 10^{3}\; {\rm ft}\end{aligned}\).
two common sources of electric current are generators and:
The second common source of electric current is batteries.
Electricity is a type of energy that is essential in our daily lives. It's used to power machines, light up homes, charge smartphones, and much more. To make all of this possible, a source of electric current is necessary. Generators and batteries are two common sources of electric current.
Generators are devices that convert mechanical energy into electrical energy. Generators use turbines or engines to create motion, which is then converted into electricity. They are commonly used in power plants to generate electricity on a large scale.
They are also used in portable generators for remote power in areas without electricity. The generators function as backup power for data centers, hospitals, and emergency services.Batteries are another source of electric current. Batteries produce electric current through a chemical reaction.
The reaction generates a flow of electrons from the anode to the cathode. Batteries come in various sizes and types, from small disposable batteries used in flashlights to large batteries used in electric cars, and even large-scale battery systems used to store energy from renewable sources. Batteries are commonly used in portable electronic devices, such as smartphones, laptops, and cameras.
In conclusion, generators and batteries are two common sources of electric current. Generators convert mechanical energy into electrical energy, while batteries produce electric current through a chemical reaction. Both are essential sources of energy in our daily lives, powering everything from our homes to our cars.
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Two astronauts are floating close to each other in space. Can they talk to each other without using any special device? plsss help me i need help
Answer:
no they can't talk to each other bcoz of the lack of atmosphere.
Explanation:
l hope it helps you
four identical planets are arranged in a square as shown. if the mass of each planet is m and the edge length of the square is a, what must be their speed if they are to orbit their common center under the influence of their mutual attraction?
Therefore, the speed required for the four identical planets to orbit their common center is √(2Gm/a).
To find the speed required for the four identical planets to orbit their common center, we can use the formula for the gravitational force between two objects:
F = G(m1*m2/r²)
where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
For the four planets, each planet is attracted towards the center of mass, which is located at the center of the square. The distance between each planet and the center of mass is a/2, where a is the edge length of the square. So, the gravitational force between each planet and the center of mass is:
F = G(m*m/(a/2)²)
= 4Gm²/a²
The planets will orbit the center of mass if this force is balanced by the centripetal force required for circular motion:
F = mv²/r
where m is the mass of the planet, v is its velocity, and r is the radius of the orbit. In this case, the radius of the orbit is the distance between the planet and the center of mass, which is a/2.
Equating these two forces, we get:
4Gm²/a² = mv²/(a/2)
Simplifying this expression, we get:
v = √(2Gm/a)
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What is the hydronium ion concentration in a solution of HCl that has a pH of 4. 65? × 10n M n = What is the hydroxide ion concentration in a solution of NH3 with a pOH of 4. 65? × 10n M n =.
The hydronium ion concentration in the HCl solution with a pH of 4.65 is approximately 2.2 x 10⁻⁵ M. On the other hand, the hydroxide ion concentration in the NH₃ solution is approximately ≈ 2.2 x 10⁻⁵ M
How to calculate ion concentrations from pH or pOH?To calculate the hydronium ion (H3O+) concentration in a solution of HCl with a pH of 4.65, you can use the formula: pH = -log [H3O+].
First, you'll need to rearrange the formula to solve for [H3O+]. You can do this by taking the inverse logarithm (antilog) of both sides:
[H3O+] = 10^(-pH)
Now, plug in the given pH value of 4.65:
[H3O+] = 10^(-4.65)
Calculating the value, you get:
[H3O+] ≈ 2.2 x 10⁻⁵ M
So, the hydronium ion concentration in the HCl solution with a pH of 4.65 is approximately 2.2 x 10⁻⁵ M.
The pOH is defined as the negative logarithm (base 10) of the hydroxide ion concentration ([OH-]).
The relationship between pOH and [OH-] is as follows:
pOH = -log[OH-]
To find [OH-], we rearrange the equation:
[OH-] = 10^(-pOH)
Given a pOH of 4.65, we can calculate the hydroxide ion concentration as follows:
[OH-] = 10^(-4.65)
[OH-] ≈ 2.2 x 10⁻⁵ M
The hydroxide ion concentration in the NH₃ solution is approximately ≈ 2.2 x 10⁻⁵ M (moles per liter)
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Acceleration Due to Gravity - Free Fall
V=V;+gt
vir initial velocity (m/s)
=final velocity (m/s)
g=gravity (10 m/s2)
t = time (s)
1. What is the velocity of a dropped object after it has fallen
downward for 3.0s?
V=V;+gt
Vi = 0
8 = 10
t = 3
2. A brick is thrown down off a bridge with a velocity of 5 m/s. What
is its velocity after it has fallen for 2 seconds?
I
3. An arrow is launched straight up from the ground. It reaches its
highest point in 6 s. What velocity was it released at?
a b c d
A V=V+gt
dhehehdhehdhshehehehehehe
a balloon, of negligible mass, is submerged in a container of water and tied to a dynamometer as in Figure 3.53. What is the volume of the balloon if the dynamometer scale is in newtons?
Answer: a balloon, of negligible mass, is submerged in a container of water and tied to a dynamometer as in Figure 3.53. What is the volume of the balloon if the dynamometer scale is in newtons?
Explanation:
Light refracts when it
What sport does not require a high level of fitness
A cube has sides of length 10 cm and weighs 10 N.
Calculate the pressure when it rests on one side ....N/cm2
Answer:
P = r g h where r here is the density m / V and then P is the pressre.
W (weight) = m g
m = 10 N / 9.8 m / s^2 = 1.02 kg
r (density) = m / V = 1.02 kg / 1000 cm^3 = .00102 kg/cm^3
P = .00102 kg / cm3 * 9.8 m/s^2 * 10 cm
P = .1 kg m / (s^2 cm^2)
Since 1 N = kg m / s^2 then P = .1 N / cm^2
More simply P = F / A = 10 N / 100 cm^2 = .1 N / cm^2
callisto, the fourth moon of jupiter's, takes 17 days to orbit jupiter. if i stand on the surface of callisto and see jupiter high in the sky over my head, and then wait 8.5 earth days in the same spot, where will i see jupiter? a. you won't see it; it will only be visible from the other side of callisto b. setting in the west c. overhead, where it was before d. rising in the east e. we need more information to give even a rough estimate of where jupiter will be
Answer:
a) if callisto is directly overhead at noon then in 8.5 days it will be high overhead at midnight - this is assuming callisto does not rotate, that is the same side of callisto always faces Jupiter
Suppose one is on the moon. When the moon is full one on the moon would not see the earth because earth is between moon and sun - 1/2 period later one could see the earth in full view beause the moon is between the earth and the sun
Again, one has to consider the rotation of callisto with respect Jupiter
The moon does not rotate with respect to earth but rotates once with respect to the fixed stars in 28 days
What is the velocity of a person walking to the office from Mrs. Dozler's class if the person travels 50m in 60 seconds?
Answer:
Velocity (v) = 0.83 m/s
Explanation:
We know that
\(Velocity = \frac{Displacement}{Time} \)
So here distance displaced by the person = 50m
Time taken by the person = 60 sec
So velocity of the person =
\( \frac{50}{60} = 0.83 \: m/s \)
Which term is described as a wave that is not confined to the space along the medium?
tsunami
standing wave
traveling wave
breaking wave
(there will be more Q's about this :\ )
Answer: Traveling wave
Explanation:
Balls A and B roll across a table, then collide and bounce off each other. The paths of the two balls are pictured (viewed from above) in the diagram. (Figure 1) Which set of arrows best represents the change in momentum for balls A and B? (Figure 2)
Based on the given information, when balls A and B collide, they exchange momentum. The set of arrows in Figure 2 that best represents this change in momentum would be the arrows pointing in opposite directions. This is because when the balls collide, the momentum of ball A is transferred to ball B, while the momentum of ball B is transferred to ball A, causing them to move in opposite directions.
When two balls (A and B) collide, the change in their momentum can be understood using the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.
1. Calculate the initial momentum of both balls before the collision.
Initial momentum of ball A = mass of A × initial velocity of A
Initial momentum of ball B = mass of B × initial velocity of B
2. Calculate the final momentum of both balls after the collision.
Final momentum of ball A = mass of A × final velocity of A
Final momentum of ball B = mass of B × final velocity of B
3. Apply the conservation of momentum principle:
Initial momentum of ball A + initial momentum of ball B = final momentum of ball A + final momentum of ball B
The change in momentum can be represented by arrows that indicate the direction and magnitude of the change in momentum for each ball. The combination of these arrows for balls A and B should conserve the total momentum, as per the principle mentioned in step 3.
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places a stick in a pond. when she looked down at the stick, it appeared to be broken at the point where the stick entered the water. this was caused by:
This phenomenon is caused by the refraction of light as it passes from one medium (air) to another (water).
Light refraction breaks the stick where it reaches the water. Light refracts when it goes from air to water. Light changes speed and direction when it flows from air to water. Refraction causes this alteration. The angle light enters the water determines refraction.
In this situation, the stick appears to move because light rays from the submerged section bend or refract as they transit from water to air. This optical illusion makes the stick look shattered at the water's surface.
Light refraction at the air-water contact makes the stick seem shattered.
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Calculate the change of entropy a) of a bath containing water, initially at 20C, when it is placed in thermal contact with a very large heat reservoir at 80C, b) of the reservoir, c) of the bath and reservoir if the bath is brought to 80C via Carnot engine operating between them. The bath and its contents have total heat capacity 10^4 J/K.
a) The change of entropy of the bath containing water is 5.8 J/K.
b) The change of entropy of large heat reservoir is 28.3 J/K.
c) The change of entropy of the bath and reservoir, if the bath is brought to 80C via the Carnot engine operating between them, is 0 J/K.
The change of entropy for a) the bath containing water when placed in contact with a heat reservoir at 80C is calculated as follows: ΔS = Q/T = (10^4 J/K)(1/Tbath - 1/Treservoir) = (10^4 J/K)(1/293 K - 1/353 K) = 5.8 J/K.
For b) the large heat reservoir, the change of entropy is ΔS = Q/T = (Q added to reservoir)/(Treservoir) = (10^4 J)/(353 K) = 28.3 J/K.
For c) the bath and reservoir brought to 80C via a Carnot engine operating between them, the entropy change of the bath is ΔSbath = Qh/Th - Qc/Tc = (10^4 J)(1/353 K - 1/293 K) = -5.8 J/K, where Qh is the heat added to the bath and Qc is the heat removed from the reservoir. The entropy change of the reservoir is ΔSreservoir = -Qh/Th + Qc/Tc = -(10^4 J)(1/353 K) + (10^4 J)(1/293 K) = 5.8 J/K. The total entropy change for the system is ΔStotal = ΔSbath + ΔSreservoir = 0 J/K.
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Explain the difference between the point of origin and the point of convergence. Which is shown in the image below?
The point of origin is the three dimensional location while the point of convergence is the area containing intersections.
Blood pattern analysisBlood pattern analysis is usually used by the forensic specialists to determine the facts surrounding an investigation using physical nature of blood stains.
There are different types of blood analysis but the one that was displayed in the picture is the impact spatter patterns which contains a point of origin and point of convergence.
The point of origin is the three-dimensional location from which blood spatter originated while the point of convergence is the area containing the intersections generated by lines drawn through the long axes of individual stains that indicates in two dimensions the location of the blood source.
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Sunee is training for an upcoming 5.0-km race. She starts out her training run by moving at a constant
pace of 4.3 m/s for 19 min. Then she accelerates at a constant rate until she crosses the finish line, 19.4
s later. What is her acceleration during the last portion of the training run?
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Here, we are required to determine Sunee's acceleration during the last portion of the training run.
Sunee's acceleration during the last portion of the training run is a = 0.0775m/s².
She starts out at a pace of 4.3 m/s for 19mins.
Therefore, after 19 mins = 1140seconds;
Sunee must have travelled a distance,
D = speed × time
D = 4.3 × 1140
D = 4902 m
However, the race is a 5km race, therefore the rest of the race, S = 5000 - 4902 = 98m
By using the equation of motion thus;
S = ut + (1/2)at².
where t = 19.4su = 4.3m/sS = 98ma = ?Therefore;
98 = 4.3(19.4) + (1/2) × a × (19.4)²98 = 83.42 + 188.18a14.58 = 188.18aa = 14.58/188.18a = 0.0775 m/s².
Therefore, Sunee's acceleration during the last portion of the training run is a = 0.0775m/s².
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This question can be solved using the equations of motion.
The acceleration of Sunee during the last portion is "0.077 m/s²".
First, we will find the distance covered by Sunee in the first portion of uniform motion. So, we will use the equation for uniform motion here:
\(d = vt\\\)
where,
d = distance covered = ?
v = uniform speed = 4.3 m/s
t = time interval = 19 min = 1140 s
Therefore,
\(d = (4.3\ m/s)(1140\ s)\\d = 4902\ m\)
Now, the distance covered during the last portion will be:
s = Total Distance - d
s = 5 km - 4902 m = 5000 m - 4902 m
s = 98 m
Now, we use the second equation of motion to find out the acceleration during the last portion:
\(s = v_it+\frac{1}{2}at^2\)
where,
s = 98 m
vi = initial speed = 4.3 m/s
t = time interval = 19.4 s
a = acceleration = ?
Therefore,
\(98\ m = (4.3\ m/s)(19.4\ s)+\frac{1}{2}a(19.4\ s)^2\\\\a = \frac{2(14.58\ m)}{376.36\ s^2}\)
a = 0.077 m/s²
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The attached picture shows the equations of motion.