Your friend is sitting on another train traveling west at 27 m/s. As you walk toward the back of your train at 2.7 m/s, what is your velocity with respect to your friend

A1.0 horsepower motor that runs for 1.0 hour uses approximately 2.7 x 10^6 joules of energy.

To calculate the number of joules of energy used by a 1.0 horsepower motor that runs for 1.0 hour, you can follow these steps:
Convert horsepower to watts.
1 horsepower (hp) is equal to 746 watts. Therefore, a 1.0 hp motor is equivalent to 746 watts.
Convert hours to seconds.
1 hour consists of 3600 seconds (1 hour x 60 minutes/hour x 60 seconds/minute).
Calculate energy usage in joules.
Energy (in joules) can be calculated using the formula: Energy (J) = Power (W) x Time (s). In this case, the power is 746 watts and the time is 3600 seconds.
Energy (J) = 746 W x 3600 s = 2,685,600 J.
The 2.7 x 10^6 J you mentioned is approximately equal to the calculated value of 2,685,600 J.
In summary, a 1.0 horsepower motor that runs for 1.0 hour uses approximately 2.7 x 10^6 joules of energy.

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Answer:

probaby not

Explanation:

you might get thrown in jail tho

The magnitude of the force exerted on particle B by particle A is 23.374 N.

The magnitude of the force exerted on particle B by particle A can be calculated using Coulomb's Law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is:

F = k * (q1 * q2) / r^2

Where F is the force, k is the Coulomb's constant (8.99 × 10^9 N * m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

Plugging in the given values, we get:

F = (8.99 × 10^9 N * m^2/C^2) * (6.50 × 10^-6 C) * (4.00 × 10^-6 C) / (0.10 m)^2

F = (8.99 × 10^9 N * m^2/C^2) * (26.00 × 10^-12 C^2) / (0.01 m^2)

F = (233.74 × 10^-3 N * m^2/C^2) / (0.01 m^2)

F = 23.374 N * m^2/C^2 * 100 C^2/m^2

F = 2337.4 N/C^2 * 10^-2 C^2

F = 23.374 N

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Answer:

B. Atoms are altered in both processes

Explanation:

Answer: B. Atoms are altered in both processes

Explanation:

1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.

1b) The height of the tank is 2 m.

2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.

3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.

3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.

3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

1a) To calculate the amount of energy stored in the three weights, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

For the 4.5 kg weight:

E = 4.5 x 10 x 0.7 = 31.5 J

For each of the 3.5 kg weight:

E = 3.5 x 10 x 0.7 = 24.5 J

Thus, the total energy stored when all three weights are raised by 70 cm is:

31.5 J + 24.5 J + 24.5 J = 80.5 J

1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:

E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)

To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:

Mass = 200 kg

The height of the tank is 2 m.

Therefore, the gravitational potential energy stored in the water in the tank is:

E = mgh = 200 x 10 x 2 = 4000 J

Assumptions made in the answer:

We have assumed that the tank is full.

2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:

PE = KEPE = mghKE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:

PE = mgh = 200 x 10 x 2 = 4000 J

The potential energy is converted into kinetic energy when the water flows out of the taps.

Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)

3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:

Mass = Volume x Density

Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg

3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:

E = mgh

Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J

3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:

PE = KEP

E = mgh

KE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,

PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:

Power = Energy / Time

Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)

The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

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Answer: I think it's 8,900

Explanation:because since you need to estimate it to the nearest thousand so 6,521 would be 7,000 and then 1,063 would be 1,000 and then 901would turn into 900 so then you add them all up and ur answer will be 8,900.

But I'm sorry if this was not the answer u were looking for

When a given circuit has one unknown voltage source, two unknown resistors and three unknown currents while all other values are known, four unique applications of Kirchhoff's rules are necessary to determine all unknown values.

Kirchhoff's rules, also known as Kirchhoff's circuit laws, are two mathematical statements that summarize the rules governing the behavior of electric currents in electrical circuits.

Kirchhoff's current law and Kirchhoff's voltage law are the two rules.

The Kirchhoff's rules are used to determine the unknown values of voltage and current when given the values of other known elements in an electric circuit.

The significance of Kirchhoff's laws:

Kirchhoff's laws help engineers understand and analyze circuits. They are fundamental to the design and analysis of electronic systems. Kirchhoff's laws are used by electrical engineers to determine the voltage and current in every part of an electrical circuit.

The correct statement is:

When a given circuit has one unknown voltage source, two unknown resistors and three unknown currents while all other values are known, four unique applications of Kirchhoff's rules are necessary to determine all unknown values.

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Answer:

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

Explanation:

Answer:

Electrons flow easily between metal nuclei :)

Explanation:

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.

The force of attraction on the beads are due to both gravitational force and electrostatic force

As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.

Net Force = Electrostatic force

Net Force = K q1 q2 / r²

Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)

Net Force = (9 × 2.5 × 10⁻⁶) / 14

Net Force = 1.6 × 10⁻⁶

For bead c

Force = Mc × Ac = 1.6 × 10⁻⁶

(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶

Ac = 1.6 × 10⁻³

Acceleration of bead C is 1.6 × 10⁻³ m/s²

For bead d

Force = Md × Ad = 1.6 × 10⁻⁶

(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶

Ad = 0.94 × 10⁻³

Acceleration of bead D is 0.94 × 10⁻³ m/s²

Let us suppose bead C travels y distance before collision

So bead D should travel 12-y distance before collision

So speed of both the beads before the collision can be find out by using newton third law of motion

For bead C

Vc² - Uc² = 2 Ac s

Vc² = 2 × 1.6 × 10⁻³ × y

Vc² = 3.2 × 10⁻³ × y

Vc = √(3.2 × 10⁻³ × y)

For bead D

Vd² - Ud² = 2 Ad s

Vd² = 2 × 0.94 × 10⁻³ × (12-y)

Vd² = 1.88 × 10⁻³ × (12-y)

Vd = √(1.88 × 10⁻³ × (12-y))

Applying energy conservation

initial = final

0 + 0 = (1/2)McVc² - (1/2)MdVd²

(1/2)McVc² = (1/2)MdVd²

McVc² = MdVd²

1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)

3.2 × y = 3.2 × (12-y)

y = 12-y

2y = 12

y = 6

Putting the value of y in Vc and Vd

Vc = √(3.2 × 10⁻³ × y)

Vc = √(3.2 × 10⁻³ × 6)

Vc = √(19.2 × 10⁻³)

Vc = √0.0192

Vc = 1.38 m/s   (approximately)

Vd = √(1.88 × 10⁻³ × (12-y))

Vd = √(1.88 × 10⁻³ × (12-6))

Vd = √(1.88 × 10⁻³ × 6)

Vd = √(11.28 × 10⁻³)

Vd = √0.01128

Vd = 0.106 m/s   (approximately)

So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.

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Among the given options, blue light transfers the most energy within the visible light spectrum.

Visible light consists of different colors, each corresponding to a specific wavelength and energy. Blue light has a shorter wavelength and higher frequency compared to red, green, and yellow light. According to the electromagnetic spectrum, shorter wavelengths correspond to higher energy levels. Blue light has a higher energy per photon compared to red, green, and yellow light. This higher energy enables blue light to transfer more energy when interacting with matter. This characteristic is also why blue light is more prone to scattering, causing the sky to appear blue during the day. It's important to note that while blue light has higher energy, prolonged exposure to intense blue light, especially from electronic devices, can have potential effects on eye health. Taking regular breaks and using protective measures like blue light filters can help mitigate any potential issues.

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Answer:

x-ray

Explanation:

Answer:

1a) Transverse wave.

1b) Ripples on the surface of water.

1c) See first attachment.

1d)  See below for explanation.

2a) Longitudinal wave.

2b) Sound waves.

2c) See second attachment.

2d)  See below for explanation.

Part 2) 54 m/s

Explanation:

a)  The wave in the picture is a transverse wave.

In transverse waves, the oscillations are at right angles to the direction of wave travel.

b)  A real world example of a transverse wave is ripples on the surface of water.

c)  See first attachment.

d)  The amplitude is the maximum displacement of a point of a wave from its resting position.  It is measured by calculating the difference in height between a crest and the resting position (mid-line).

a)  The wave in the picture is a longitudinal wave.

In longitudinal waves, the oscillations are parallel to the direction of wave travel.

b)  A real world example of a longitudinal wave is sound waves.

c)  See second attachment.

d)  The amplitude is the maximum displacement of a point of a wave from its resting position.  It is measured by calculating the distance between the particles in the areas where it is compressed.

Wave Speed

\(\large\boxed{v=f \lambda}\)

where:

Given values:

Substitute the given values into the formula and solve for speed:

\(\implies v=60.0 \times 0.90\)

\(\implies v=54\;\sf m/s\)

Therefore, the speed of the wave is 54 m/s.

According to the question,

Initial velocity of the car (\( \rm v_i \)) = 0 m/s

Final velocity of the car (\( \rm v_f \)) = 28 m/s

Time of uniform acceleration (t) = 5.6 s

a. By using \( 1^{st} \) kinematic equation and substituting value we get:

\( \rm \implies v_f = v_i + at \\ \\ \rm \implies at = v_f - v_i \\ \\ \rm \implies a = \dfrac{v_f - v_i }{t} \\ \\ \rm \implies a = \dfrac{28 - 0 }{5.6} \\ \\ \rm \implies a = \frac{28}{5.6} \\ \\ \rm \implies a = 5 \: m {s}^{ - 2} \)

\( \therefore \) Average acceleration of the car during the 5.6 s is 5 m/s²

b. By using \( 2^{st} \) kinematic equation and substituting value we get:

\(\rm \implies s = v_it + \dfrac{1}{2}at^2 \\ \\ \rm \implies s =0 \times 5.6 + \frac{1}{2} \times 5 \times {(5.6)}^{2} \\ \\ \rm \implies s = \frac{1}{2} \times 5 \times 31.36 \\ \\ \rm \implies s =5 \times 15.68 \\ \\ \rm \implies s =78.4 \: m\)

\( \therefore \) Distance travelled by car in 5.6 s is 78.4 m

Answer:

I think it's 3

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

Answer:

Originally Answered: What is the unit of measurement of pressure in the atmosphere? The SI derived unit of pressure is the pascal , abbreviated Pa. This is a pressure exerted by a force of 1 newton acting over an area of 1m².

Explanation:

Hope this helps you a lot my boo!

Answer:

Below

Explanation:

Fn = Normal force = (5  + 10) ( 9.81 ) = 147.15 N      (Contact force)

Friction force = 147.15 * .2 = 29.43 N

Net force causing boxes to move = 45 - 29.43 = 15.57 N

F = m * a

15.57  = ( 5+10) * a      shows  a = 1.038 m/s^2

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

Answer:

a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars

Explanation:

Answer:

Explanation:

A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.

9.8 J of work done is required to launch the item (Option C).

To determine the work done in launching the object, we can use the formula:

Work = Force x Distance x Cos(theta)

where theta is the angle between the force vector and the direction of motion. In this case,

since the force is applied in the same direction as the motion of the object, theta is 0 degrees, and cos(theta) is 1.

Substituting the given values, we get:

Work = 19.6 N x 0.50 m x 1 = 9.8 J

Therefore, the work done in launching the object is 9.8 J (Option C).

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Complete question:

Question asked: how much work is done in launching the object?

Information in the passage included: 1.00 kg object initially at rest. The student applies a force of 19.6 N through a distance of .50 m to propel the object straight upward.

Answer:

Fn = 50 N

Explanation:

Net Force

The net force is the sum of all the forces acting on an object.

When all the forces act in a single line, the direction of the forces is given by their signs. Positive signs are assumed to be up and left on both axes.

The box being raised by a force has a weight of W=-125 N. The negative sign indicates the weight points down. The accelerating force goes up and its value is F=175 N. The positive sign indicates this force pushes the box up.

The forces acting on the box are:

The weight W=-125 N

The accelerating force F=175 N

The net force is

Fn = W + F = -125N + 175 N

Fn = 50 N

A good relationship must possess the attributes of communication and trust. Without trust, there can be no intimacy, and without communication, there can be no understanding.

This is a true expression of the truth. In order to build a solid and lasting connection between two individuals, communication and trust are essential elements of a good relationship.

Absolutely! Relationships that lack open and honest communication, as well as trust, are likely to be unstable and can lead to misunderstandings, conflicts, and even a breakdown of the relationship over time. Building a strong foundation of trust and communication can help ensure that a relationship can withstand challenges and grow stronger over time.

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Answer:

The water filled balloon does not burst because the rubber obviously does not reach a temperature sufficient for it to melt or burn. The rubber is stretched thin so that heat is quickly transferred into the balloon. With air inside the balloon, this heat is not readily dissipated away from the spot touching the flame.

Height of cliff where a diver jumps  is 36.9m and from base the diver will be out by 3.6m distance.

The distance of a point from the y-pivot is called its x-direction, or abscissa. The distance of a point from the x-hub is called its y-direction, or ordinate. The directions of a point on the x-hub are of the structure (x, 0), and of a point on the y-hub are of the structure (0, y).

For calculating distance in horizontal direction (in positive x-axis),we need to use second equation of motion which is given by the formula

S=ut + (1/2)at²

In x-direction acceleration in x-direction=0m/sec²

So, value of a=0m/sec²

Value of u=1.6m/sec, t=3.0sec

=>S=1.6 ×3=3.8m

Similarly, for calculating distance in vertical direction (in positive x-axis),we need to use second equation of motion which is given by the formula

S=ut+ (1/2)at²

In y-direction,acceleration is 9.8m/sec²

Also,in y-direction initial velocity(u) is 0m/sec.

=>S=0×t + (1/2)×9.8×(3.0)²

=>S=0+4.9×9

=>S=36.9m

Hence,height is 36.9m and distance in horizontal direction is 3.8m

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Answer:

I think its frequency

Explanation:

Answer:

its B or A thank me please

Answer:

1.75 \(m/s^{2}\)

Explanation:

Acceleration = \(\frac{Final velocity-Initial velocity}{Time}\)

= \(\frac{10 - 3}{4}\)

= \(\frac{7}{4}\)

= 1.75 \(m/s^{2}\)

Answer:

Spectrum because it could respond to a specific color based upon how you humans typically perceive Lights of the wavelength

Answer:

spectrum

Explanation:

Answer:

Along with physical elements, the training context should include emotional elements. The most accurate way to assess training effectiveness is to conduct pretests and posttests and then train all the employees.