Answer:
C. not enough mass
Explanation:
Trust me bro
8. What is the frequency of green light waves that have a wavelength of 5.2 x 10-7 m.? The speed of light is 3.0 x 108 m/s
Answer:
\(f=5.76\times 10^{14}\ Hz\)
Explanation:
We need to find the frequency of green light having wavelength o\(5.2\times 10^{-7}\ m\). It can be calculated as follows :
\(c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz\)
So, the required frequency of green light is equal to \(5.76\times 10^{14}\ Hz\).
According to our theory of solar system formation, why do all the planets orbit the Sun in the same direction and in nearly the same plane?
A. The original solar nebula happened to be disk-shaped by chance.
B. Any planets that once orbited in the opposite direction or a different plane were ejected from the solar system.
C. The laws of conservation of energy and conservation of angular momentum ensure that any rotating, collapsing cloud will end up as a spinning disk.
D. The Sun formed first, and as it grew in size it spread into a disk, rather like the way a ball of dough can be flattened into a pizza by spinning it.
E. Luck explains it, as we would expect that most other solar systems would not have all their planets orbiting in such a pattern.
The laws of conservation of energy and conservation of angular momentum ensure that any rotating, collapsing cloud will end up as a spinning disk is the reason.
What is an Orbit?This is defined as a curved path in space which is characterized by an object going round and round a planet, moon, or star.
In this scenario, all the planets orbit the Sun in the same direction and in nearly the same plane to ensure any rotating, collapsing cloud will end up as a spinning disk.
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A 2 kg billiard green ball is moving toward the 2 kg white billiard ball on a pool table. The green ball is moving with an initial speed of 4 m/s and the white ball is at rest. The two balls collide and move apart. The white ball moves away from the green ball with a speed of -6 m/s. With what speed does the green ball move away?
Answer:
10m/s
Explanation:
collisions results in objects sticking together or not sticking together after collision and so they do move with a common velocity or uncommon velocity respectively.
Parameters from the question:
Mass of green billiard balls, m1=2kg
Mass of white billiard balls, m2=2kg
Initial velocity for green billiard balls ,u1=4m/s
Initial velocity for white billiard balls ,u2 = 0m/s( since the body is at rest meaning it wasn't moving)
Final velocity of green billiard ball after collision is,v1= unknown
Final velocity of white green billiard ball after collision is, V2 = -6m/s.
Now from Newton's third law of motion that action and reaction must be equal and opposite;hence change in momentum before collision would be the same after collision since energy is conserved.
Hence,
m1U1 + m2U2 = m1V1 +m2V2
2×4 + 2×0 = 2×V1 + 2× (-6)
8 = 2V1 -12
8+12=2V1
20=2V1
10=V1
V1=10m/s
when an automobile moves with constant velocity, the power developed in a certain engine is 72.9 hp. what total frictional force acts on the car at 39.2 mi/h ? 1 hp
The total friction force acting on the car is 3.1 KN
How do you find friction force?The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.power = force × distance (in direction of the force)time taken, so power = force × velocity.Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.Given, power developed by the engine,
P = 72.9 hp = ( 72.9 x 746 ) W (One horsepower equals 746)
Speed of the car, v = 39.2 mi / hr
(convert mi / hr to m / s)
v = 17.52 m/s
Total friction force acting on the car, f = P / v
f = \(\frac{72.9 * 746}{17.52}\) = 3104 N
= 3.1 KN
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Choose the correct meaning of the underlined word: his eyes had that mischievious glint they sometimes got when he pulled a pop quiz and made all the multiple choice answers b. a enough; an adequate amount b a small flash, sparkle c in a shy way d in a sneaky way
Based on the context provided, the correct meaning of the underlined word "mischievous" is d) in a sneaky way. Hence, option d) is the correct answer.
This is because the sentence describes the person's eyes having a "glint" when he pulls a pop quiz and makes all the multiple choice answers, which suggests that he may be doing it in a playful or mischievous manner. The word "mischievous" is often used to describe behavior that is playful or teasing, but can also be seen as sneaky or sly.
The correct meaning of the underlined word "mischievous" in the given sentence is: d. in a sneaky way.
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Two identical converging lenses of focal length 100 mm are placed 400 mm apart, and an object 40 mm tall is placed 230 mm to the left of the left lens. (a) Draw a scale diagram showing the three principal rays for the left lens, and use them to locate the image formed by this lens. (b) Draw the principal rays for the right lens, and use them to locate the image formed by this lens. Is the image formed by the right lens (c) real or virtual, (d) inverted or upright, (e) larger or smaller than the object?
(a) Image formed by the left lens is 133.33 mm to the right of the lens. (b) image formed by both lenses is 200 mm to the left of the right lens. (c) real (d) inverted (e) larger.
(a) To find the image formed by the left lens, we can use the three principal rays. The first principal ray passes through the center of the lens and goes straight through, unaffected by the lens. The second principal ray passes through the lens and goes through the focal point on the right side of the lens. The third principal ray passes through the top of the object and also goes through the focal point on the right side of the lens.
After passing through the lens, the two latter rays will converge at a point on the right side of the lens. This point is the image formed by the left lens. To find the location and size of the image, we can use the lens equation:
1/f = 1/do + 1/di,
here,
f is focal length,
do is object distance,
di is image distance.
In this case, f = 100 mm, do = 230 mm, and we are trying to find di.
Reserving values into equation:-
1/100 = 1/230 + 1/di
1/di = 1/100 - 1/230
di = 230 * 100 / (230 + 100)
= 133.33 mm
Hence, the image formed by the left lens is 133.33 mm to the right of the lens and is virtual, erect, and smaller than the object.
(b) To find the image formed by the right lens, we can use the three principal rays that are formed after passing through the image formed by the left lens. The first principal ray passes straight through the center of the right lens, unaffected by the lens. The second principal ray passes through the top of the image and goes through the focal point on the left side of the right lens. The third principal ray passes through the bottom of the image and also goes through the focal point on the left side of the right lens. After passing through the right lens, the two latter rays will converge at a point on the left side of the right lens. This point is the final image formed by both lenses. To find the location and size of the final image, we can use the lens equation again:
1/f = 1/do + 1/di,
here,
f is focal length,
do is object distance,
di is image distance.
In this case, f = 100 mm, do = 133.33 mm (the distance to the image formed by the left lens), and we are trying to find di.
Reserving values into equ.:-
1/100 = 1/133.33 + 1/di
1/di = 1/100 - 1/133.33
di = 133.33 * 100 / (133.33 + 100) = 200 mm
So, the final image formed by both lenses is 200 mm to the left of the right lens and is real, inverted, and larger than the object.
(c) Image will be real.
(d) Image will be inverted.
(e) Image will be larger than the object.
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write the reason behind the atmosphere does not escape away from the earth
Answer:
i knew it but now i dont
Explanation:
Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.
Thanks to Earth's gravity, the atmosphere doesn't escape into space. Gravity pushes down on Earth's atmosphere, keeping its air from drifting away, according to the National Oceanic and Atmospheric Administration's SciJinks online earth science education website.
I need help please please please please
The number of parking spaces that the parking lot has, given the length of the parking lot, is 32 parking spaces.
How to find the number of parking spaces ?To find out how many parking spaces the parking lot has, first we need to determine the total length of the row where parking spaces will be created.
Length of the row for parking spaces = Total length of the parking lot - Length not painted for cars to turn
= 316 feet - 28 feet = 288 feet
Now that we know the length of the row for parking spaces, we can calculate how many 9-foot-wide spaces will fit in this row.
Number of parking spaces = Length of the row for parking spaces / Width of each parking space
= 288 feet / 9 feet = 32 parking spaces
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What is a dielectric material?
A dielectric material is a type of insulating material that does not conduct electricity easily.
When an electric field is applied to a dielectric material, the electrons within the material do not move freely like they would in a conductor.
Instead, the electrons remain bound to their respective atoms or molecules, resulting in a polarization of the material.
This polarization creates an opposing electric field that reduces the strength of the applied electric field.
Dielectric materials are commonly used in electrical and electronic applications where insulation is necessary, such as in capacitors, transformers, and printed circuit boards.
Some examples of dielectric materials include air, paper, glass, ceramic, and plastic.
The dielectric constant of a material refers to its ability to store electrical energy in an electric field and is an important parameter in the design of electrical devices.
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what is the principle of charge quantisation?
Answer:
Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge.
Explanation:
If it is known that a motor battery has an input voltage of 12V and a capacity of 6 Ah, how much power and resistor value is required to turn on 8 lamps with a parallel circuit, with the specifications of each lamp having a maximum voltage of 3V and an electric current of 140 mA? How long did all the lights go on until they off?
Answer:
Part A
The power to turn on the lamp, ∑P = 3.36 W
Part B
The Resistor required is approximately 8.04 Ohms
Part C
The time for all the lights to go out is approximately 21.43 hours
Explanation:
The input voltage of the motor battery , V = 12 V
The capacity of the battery, Q = 6 Ah
The number of lamps in parallel = 8 lamps
The maximum voltage of each lamp, = 3 V
The electric current in each lamp = 140 mA
The energy available in a battery, E = Q × V
For the battery, we have;
E = 6 Ah × 12 V = 72 Wh
The energy available in a battery, E = 72 Wh
Part A
The power used by the lamps, \(P_i\) = \(I_i\) × \(V_i\)
∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W
The power to turn on the lamp, ∑P = 3.36 W
Part B
The resistance required, is given as follows;
Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)
∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)
The Resistor required = 8.03571429 Ohms
The Resistor required ≈ 8.04 Ohms
Part C
The time for all the lights to go out = The time for the lamps to use all the power available in the battery
The time for all the lights to go out, t = E/∑P
∴ t = 72 Wh/(3.36 W) = 21.4285714 h
∴ The time for all the lights to go out, t ≈ 21.43 h
The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h
∴ The time for all the lights to go out ≈ 21.43 hours.
How it total reaction energy calculated ?
Here, we are required to determine how the total reaction energy is calculated.
Total reaction energy =
Energy of the product - Energy of the reactants.The total reaction energy, otherwise known as the Enthalpy of the reaction is given by the difference between the enthalpy of the product and that of the reactants.
Also, it is important to note that the enthalpy is the sum total of the internal energy and the work energy of the entity in discuss, which may either be the reactants or the products.
Ultimately,
Total reaction energy =
Energy of the product - Energy of the reactants.Read more:
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Answer:
B. reactant bond energy – product bond energy
Explanation:
Determine the speed s(t)| of a particle with a given trajectory at a time t0| (in units of meters and seconds). c(t)=(ln(t2+1),t3),t0=5|
The speed of a particle with trajectory c(t) = (ln(t^2+1), t^3) at time t0=5 is approximately 130.8 meters per second.
To find the speed of the particle at t0=5, we need to find the derivative of the position function with respect to time and then evaluate it at t=5.
The position function c(t) gives us the particle's x-coordinate and y-coordinate at any given time t. To find the velocity vector, we take the derivative of the position function with respect to time. The x-component of the velocity vector is dx/dt, and the y-component is dy/dt.
Taking the derivative of c(t) gives us c'(t) = \((1/(t^2+1), 3t^2).\) At t=5, the velocity vector is c'(5) = (1/26, 75).
To find the speed of the particle, we take the magnitude of the velocity vector: c'(5) =\(sqrt((1/26)^2 + 75^2)\) ≈ 130.8 meters per second. Therefore, the speed of the particle at t0=5 is approximately 130.8 meters per second.
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Suppose Batman throws a 0.2 kg Batarang 20 m/s at Joker's face, which applies a con constant force of 600 N on the Batarang. Q1) How long does it take the Batarang to stop after it hits the target? Q2) How far does the Batarang travel while the force is being applied?
Q1) To find how long it takes the Batarang to stop after it hits the target, we can use the formula F = ma, where F is the force, m is the mass, and a is the acceleration
Rearranging the formula to solve for a, we get a = F/m. Plugging in the given values, we get a = 600 N / 0.2 kg = 3000 m/s^2. Next, we can use the formula v = at, where v is the final velocity, a is the acceleration, and t is the time. Since the Batarang stops after it hits the target, the final velocity is 0. Rearranging the formula to solve for t, we get t = v/a. Plugging in the given values, we get t = 0 / 3000 m/s^2 = 0 seconds. Therefore, it takes the Bata rang 0 seconds to stop after it hits the target.
Q2) To find how far the Bata rang travels while the force is being applied, we can use the formula d = vt, where d is the distance, v is the velocity, and t is the time. Since the Batarang stops after it hits the target, the time is 0 seconds, as we found in Q1. Plugging in the given values, we get d = 20 m/s * 0 seconds = 0 meters.
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Q1) To find how long it takes the Batarang to stop after it hits the target, we need to use the equation of motion: v = u + at
Where v is the final velocity (which is zero in this case), u is the initial velocity (20 m/s), a is the acceleration (-600 N/0.2 kg = -3000 m/s^2, since force = mass x acceleration), and t is the time we are trying to find.
Rearranging the equation, we get: t = (v - u) / a
Substituting the given values, we get: t = (0 - 20) / (-3000) = 0.00667 seconds. Therefore, it takes the Batarang 0.00667 seconds to stop after hitting the target.
Q2) To find how far the Batarang travels while the force is being applied, we need to use the equation of motion: s = ut + (1/2)at^2; where s is the distance traveled, u is the initial velocity (20 m/s), a is the acceleration (-3000 m/s^2, as before), and t is the time it takes for the Batarang to stop (0.00667 seconds).
Substituting the given values, we get: s = 20(0.00667) + (1/2)(-3000)(0.00667)^2 = 0.067 meters
Therefore, the Batarang travels 0.067 meters while the force is being applied.
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A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
3 A, calculate the size of the resistor
Answer:
4 Ohms
Explanation:
Apply the formula:
Voltage = I (current) . Resistance
You can change it the way you want to use for your purpose.
In this case...
R = V/I
R = 12/3
R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)
how to write it in second?
Answer:
like this
Explanation:
Is the substance above an element, compound or mixture?
Answer:
If it is pure, the substance is either an element or a compound. If a substance can be separated into its elements, it is a compound. If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.
Explanation:
Please help me! I'm not just looking for answers, I'm honestly confused.
Answer:
its Phyiscs How hard Can It Really Be
for an ideal monoatomic gas, the internal energy U os due to the kinetic energy and U=3/2RT per mole.show that cv=3/2R per mole and Cp=5/2RPer mole
Answer:
i. Cv =3R/2
ii. Cp = 5R/2
Explanation:
i. Cv = Molar heat capacity at constant volume
Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT
Differentiating U with respect to T, we have
= d(3/2RT)/dT
= 3R/2
ii. Cp - Molar heat capacity at constant pressure
Cp = Cv + R
substituting Cv into the equation, we have
Cp = 3R/2 + R
taking L.C.M
Cp = (3R + 2R)/2
Cp = 5R/2
How are waves reflected and refracted at boundaries between mediums?
The total mass of the reactants before a chemical reaction is the same as the total mass of the products after the chemical reaction.
Answer:
If it is a True or False question then the answer would be TRUE
Explanation:
Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x distance 0 j 15 j 30 j 60 j
Answer:
he is right it’s D
Explanation:
if u could not read his hand writing
which SI unit is most appropriate for measuring weight ?
The SI unit that is most appropriate for measuring weight is N ( Newton )
Weight of an object is the force acting on the object due to gravity. It is denoted using W.
W = m g
W = Weight
m = Mass
g = Acceleration due to gravity
Newton in SI base units is written as kg m \(s^{-2}\). 1 kg of mass equals to 9.8 N. The standard dimension for weight is M L \(T^{-2}\).
Therefore, the SI unit that is most appropriate for measuring weight is N ( Newton )
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A basketball rolls across a floor without slipping, with its centerof mass moving at a certain velocity. A block of ice of the samemass is set sliding across the floor with the same speed along aparallel line.
How do their energies compare?
The ice has more kineticenergy.
They have equal kineticenergies.
The basketball has more kineticenergy.
The basketball and the block of ice have the same kinetic energy since they have the same mass and speed. The energy of an object in motion is determined by its mass and velocity, and since both objects have the same mass and velocity, they possess equal kinetic energy.
The kinetic energy of an object in motion is determined by its mass and velocity. The greater the mass or velocity of an object, the greater its kinetic energy. In this scenario, the basketball and the block of ice have the same mass and are moving with the same speed, so they possess equal kinetic energy. Even though the basketball is rolling and the block of ice is sliding, they both have the same linear speed. The basketball rolls without slipping because its point of contact with the floor is stationary, and this rotational motion does not affect its linear speed.
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An astronaut 1500n on the moon. What will be his weight on Earth?
I'm pretty sure this poor guy could never have been accepted for astronaut training, much less a mission to the Moon.
He weighs something like 335 pounds when he's ON THE MOON !
If he has enough fuel, and survives a trip back to Earth, he'll weigh around 9,080 Newtons here. That's like 2,040 pounds ... durn close to a ton ! !
Answer:
Gravitational field strength:
Moon is 1.6N/kg
Earth is 9.8N/kg or 10N/kg
Moon:
Weight = mass x gravitational field
1500N = m x 1.6N/kg
÷1.6 both sides
937.5 = m
Mass of astronaut is 937.5kg
(Your mass doesn't change, no matter where you go, in space)
Earth:
Weight = mass x gravitational field
= 937.5kg x 9.8 N/kg
= 9187.5N
Or
Weight = mass x gravitational field
= 937.5kg x 10 N/kg
= 9375N
Thus, the astronaut's weight will be 9187.5N or 9375N on Earth.
Hope this helps!
A 7.0 kg cannonball flying rightward at 12 hits a stationary rock. The cannonball keeps moving in the same
S
m
m
direction at 2.0 after the collision but sends the rock flying at 14 towards right
S
S
What is the mass of the rock?
Answer:
5.0 kg
Explanation:
use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)
The average power of a human body (for living and metabolism) is about 100 watts. Suppose a 90 kg human body could run on fusion power and could convert 0.7% of its mass into energy Part A How much energy would be available through fusion? Express your answer to two significant figures and include the appropriate units. LOL μΑ ? E = Value Units Submit Request Answer Part B For how long could this body then operate on fusion power? Express your answer in years to two significant years.
The energy available through fusion for a 90 kg human body is approximately 5.67 x 10^13 joules. With this energy, the body could operate on fusion power for approximately 18,000 years.
Part A:
To calculate the energy available through fusion, we need to find 0.7% of the mass of the human body and convert it to energy using Einstein's famous equation E=mc^2.
Mass of the human body (m) = 90 kg
Conversion efficiency (η) = 0.7% = 0.007
Energy (E) = η * m * c^2
The speed of light (c) is approximately 3 x 10^8 m/s.
Plugging in the values:
E = 0.007 * 90 kg * (3 x 10^8 m/s)^2
Calculating:
E ≈ 0.007 * 90 kg * (9 x 10^16 m^2/s^2)
E ≈ 5.67 x 10^13 joules
Therefore, the energy available through fusion is approximately 5.67 x 10^13 joules.
Part B:
To find how long the body could operate on fusion power, we need to divide the available energy by the power consumption of the human body.
Given:
Average power of the human body (P) = 100 watts
The time (t) can be calculated as:
t = E / P
Plugging in the values:
t = (5.67 x 10^13 joules) / (100 watts)
Calculating:
t ≈ 5.67 x 10^11 seconds
To convert seconds to years, divide by the number of seconds in a year (approximately 31,536,000 seconds):
t ≈ (5.67 x 10^11 seconds) / (31,536,000 seconds/year)
t ≈ 1.8 x 10^4 years
Therefore, the body could operate on fusion power for approximately 18,000 years
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A body dropped from rest falls half its total distance in the last second before it strikes the ground.From what height was it released
Answer:
it is dropped from a height of 10m
Explanation:
Answer:
57.1 meters
Explanation:
the distance the body has fallen is given by
d = 1/2 a t^2 with a = 9.8m/s^2 this becomes
d = 4.9 t^2
now we want the distance in one more second to equal the distance fallen before that one second
or 4.9 t^2 = 4.9 (t+1 )^2 - 4.9 t^2 re-arrange
2 * 4.9 t^2 = 4.9 (t+1)^2 simplify to
0 = - 4.9 t^2 + 9.8 t + 4.9 use Quadratic Formula to find
t = 2.414
then t +1 = 3.414
this corresponds to distance d = 1/2 at^2 = 1/2 ( 9.8) (3.414)^2 = 57.1 meters
check: in 2.414 seconds distance = 1/2 a t^2 = 28.6
in one second more distance = 1/2 (9.8)(3.414)^2 = 57.1
so in the last one second it has fallen approx another 28.6 m
Check !
The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light from the data provided. Mention the unit as well.
Answer:
The speed of light is 30,060,120.24048 m/s.
Explanation:
15000000 km into m
1 km = 1000m
15000000 km = 15000000 × 1000 m
= 15000000000m
speed = distance travelled / time taken
or, speed = 15000000000/499 m/s
so, speed = 30,060,120.24048m/s
To solve the problem we must know about the relationship between Speed, distance, and Time.
What is the relationship between Speed, distance, and Time?We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
The speed of the light is 30,060.12 km/sec.
Given to us
The distance between the earth and the sun is 15000000km Light takes 499 seconds to reach earth from the sun.We know that speed can be described as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
Therefore,
What is the speed of the light?\(\text{Speed of light} = \dfrac{\text{Distance between the earth and the sun}}{\text{Time taken by the light to travel the distance}}\)
Substitute the value,
\(\text{Speed of light} = \dfrac{15,000,000\ km}{499\ seconds}\)
\(\text{Speed of light} = 30,060.12\ km/sec\)
Hence, the speed of the light is 30,060.12 km/sec.
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A 20.0 N force is applied at an angle of 40.0 degrees above the horizontal to a 4.00 kg box. The box moves a horizontal distance of 4.00 meters. Friction is negligible. The work done by the 20.0 N force is
a. 61.3 J.
b. 46.3 J.
c. 50.1 J.
d. 75.0 J.
Answer:
The work done by the 20 N force is 61.3 J
Explanation:
20 N Force at horizon is: F=20 N*cos 40=15.32 N
The work done by 20 N at horizon is: W=F*S=15.32 N* 4 m=61.3 J
Answer:
The work done by the 20 N force is 61.3 J
Explanation: