Answer:
what are the statements?
Explanation:
Which statement best describes the Sun Earth-Moon system?
Answer:
A
Explanation:
A. The Moon orbits the Earth, and the Earth-Moon system orbits the Sun
B. The Earth and Moon both orbit the Sun separately
C. The Sun orbits the Earth-Moon system
D. The Moon revolves around Earth but not the Sun
A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.
The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.
According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.
Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.
Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.
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what is the magnetic force exerted on a 2.35m length of wire carrying a current of 0.819a perpendicular to the magnetic field of 0.920 t?
The magnetic force exerted on a 2.35m length of wire carrying a current of 0.819A perpendicular to the magnetic field of 0.920 T is 1.807 N.
What is magnetic force?The magnetic force is the force that acts between two magnets or between a magnet and a magnetic material. When a moving charge is exposed to a magnetic field, it experiences a magnetic force. The direction of the magnetic force is perpendicular to both the magnetic field and the direction of the motion of the charged particle.
The magnetic force is given by:
F = BILsin(θ)
where,
F is the magnetic force
B is the magnetic field
I is the current
L is the length of the wire
θ is the angle between the current and the magnetic field.
The length of the wire (L) is 2.35 m
The current (I) is 0.819 A
The magnetic field (B) is 0.920 T
As the wire is carrying the current perpendicular to the magnetic field, the angle between the current and the magnetic field is 90°.
Hence, the magnetic force (F) is given by:
F = BILsin(θ)
F = 0.920 T × 2.35 m × 0.819 A × sin 90°F = 1.807 N
Therefore, the magnetic force exerted on a 2.35 m length of wire carrying a current of 0.819 A perpendicular to the magnetic field of 0.920 T is 1.807 N.
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How earth's magnetic field is taken as uniform magnetic field ?
Answer:
It is in contact with two vertical rails which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and the rails.
Explanation:
Not sure if this is correct but pls give thanks anyway!
A kid drives 4 miles to the mall. If the speed limit is 45 miles/hr and the kid makes the trip in .03 hours. Is the kid breaking the speed limit? a. No, he is going 1 mile/hr. b. Yes, he is going 133 miles/hr, C. No, he is going 40 miles/hr. d. Yes, he is going 150 miles/hr.
Answer:B
Explanation:
.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph
The kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Since the distance to the mall is 4 miles, the time taken is 0.03 hours, hence the speed is:
Speed = distance / time
Speed = 4 miles / 0.03 hours
Speed = 133.3 miles/hr
Hence the kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
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What is the normal force on an object weighing 437N at rest on an inclined plane with an angle of 29 degrees?
Answer:408
Explanation:
Answer:
382.2 N
Explanation:
You want the normal force on an object weighing 437 N situated on an inclined plane 29° from the horizontal.
Force vectorThe vector 437 N straight down can be decomposed to vectors parallel to the plane and perpendicular to the plane. That decomposition looks like ...
(perpendicular, parallel) = 437 N · (cos(29°), sin(29°)) ≈ (382.2, 211.9) N
The normal force on the object is about 382.2 N.
I need answers to these physics problems. (See picture). Also, i'm not sure if the one's I circled are correct
The length of the vector is proportional to the size of the force.
The wheelchair is not accelerating, so the forces on it are balanced.
In a free-body diagram of the wheelchair, force due to gravity points down, normal force points up, force pushing the wheelchair points forward, friction resisting the motion points backward.
For the force diagram:
In picture 1: F gravity points down; F normal points upIn picture 2: F gravity points down; F tension points upIn picture 3: F gravity points down; F spring points up.What are forces?Forces are a push or pull agents that causes a change in the state of a body when they are applied to the body.
Unbalanced forces cause acceleration of a body.
In a free-body diagram, the mass (force) on an object is represented by a vector.
The length of the vector is proportional to the size of the force. Suppose you push a wheelchair forward at constant velocity. The wheelchair is not accelerating, so the forces on it are balanced. In a free-body diagram of the wheelchair, the vector for the force due to gravity points down, the vector for the normal force points up, the vector for your force pushing the wheelchair points forward, and the vector for the force of friction resisting the motion points backward.
Considering the picture visual representation of the forces between many interacting objects or the force diagram:
In picture 1: F gravity points down; F normal points up
In picture 2: F gravity points down; F tension points up
In picture 3: F gravity points down; F spring points up.
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The work W done by a constant force F in moving an object from a point A in space to a point B in space is defined as W=F⋅AB. Find the work done in moving an object along a vector u=4i+5j+5k if the applied force is F=2i−3j+3k. Use meters for distance and newtons for force.
The work done by a force in displacing an object from its initial position to its final position can be calculated using the formula W= F.AB. The work done in this problem was calculated using formula to be 38 J.
The work done W by a constant force moving an object from point A to B can be calculated as:
W = F.AB
= (2i−3j+3k)(4i+5j+5k)
= (2×4)(i × i) + (3×5)(j × j) + (3×5)(k × k)
= 8i² + 15j² + 15k²
Since i², j² and k² have the values of 1, we get
= 8 + 15+ 15
= 38 J
Therefore, the work done W is calculated to be 38 J.
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Un muelle se alarga 5 cm, cuando de él se cuelga una masa de 1000 gr. Colocamos después este muelle unido a una masa de 500 g sobre una mesa horizontal sin rozamiento. La masa se separa 3 cm de su posición de equilibrio y se deja vibrar sobre el eje horizontal. Calcular:
a) La fase inicial y la amplitud del movimiento.
b) La elongación y la velocidad en el instante t = 0,5 s
c) La velocidad angular
d) El periodo
e) la constante de recuperación del resorte;
f) El valor máximo de la velocidad.
g) la energía potencial en el punto de máxima deformación en horizontal;
h) La energía cinética cuando x = 2 cm;
i) La aceleración de la partícula 0,25 s después de iniciado el movimiento
j) la velocidad cuando el tiempo es de 1 seg
La expresión del movimiento armónico simple permite encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:
a) La fase inicial es cero y la amplitud es 0,05 m
b) La elongación y velocidad para el tiempo dado son:
x = -0,0445 m y v = -0,0229 m/s
c) La velocidad angular es: w = 19,8 rad/s
d) El periodo vale T = 0,317 s
e) La constante de resorte es: k = 196 N/m
f) La velocidad máximas es: v= 0,99 m/s
g) La energia potencial es: Ep = 0,245 J
h) La energía cinética es: K = 0,2058 J
i) La aceleración es: a = -4,61 m/s²
j) La velocidad es: v= -0,806 m/s
El movimiento oscilatorio ocurre cuando hay un fuerza recuperadora en el sistema, si tea fuerza es proporcional al desplazamiento el movimiento se denomina armónico simple y es descrito por la expresión.
x= A cos (wt +Ф)
w² = k/m
Donde x es el desplazamiento, A la amplitud del movimiento, w la velocidad angular, t el tiempo, fi una constante de fase que se determina con los valores iniciales, k la constante del resorte y m la masa.
e) Indican el desplazamiento de x= 5 cm = 0,05 m para una masa de m= 1000 g = 1 kg. Usemos la condición de equilibrio y la ley de Hooke para encontrar la constante del resorte.
W = F
mg = k x
\(k = \frac{mg}{x}\)
Calculemos.
k = \(\frac{1 \ 19.8}{0.05}\)
k = 196 N/m
c) indican la masa aplicada para el movimiento es m= 0,5 kg , podemos buscar la velocidad angular
w= \(\sqrt{ \frac{k}{m}}\)
w = \(\sqrt{ \frac{196}{0.5} }\)
w = 19,8 rad/s
a) La fase y la mplitud.
La amplitud es la elongación máxima del movimiento
A = 0,05 m
para la fase usamos que el bloque se suelta, por lo cual el tiempo es cero t=0 ,desde la posición de máxima elongación v= 0, usemos la relación entre la posición y la velocidad.
v= \(\frac{dx}{dt}\)
v = -A w sin (wt +Ф)
0 = - A w sin Ф
Por lo tanto fi debe ser cero, para que la función seno ea cero.
Ф =0
b) Calculamos para t=0,5 s la elongación y la velocidad.
La ecuación del movimiento queda.
x = A cos wt
Calculamos.
Recuerda que los ángulos están en radianes.
x = 0,05 cos 19,8 0,5
x = -0,0445 m
La velocidad es:
v = 0,05 19,8 sin 19,8 0,05
v = -0,0229 m/s
d) La velocidad angular esta relacionada con el periodo.
W = \(\frac{2\pi}{T}\)
T = \(\frac{2\pi}{w}\)
T = \(\frac{2\pi}{19.8}\)2pi/19,8
T = 0,317 s
f) El valor máximo de la velocidad.
Este valor ocurre cuando la función seno vale 1
v =Aw
v= 0,05 19,8
v= 0,99 m/s
g) La energía mecánica del sistema se mantiene constante porque no hay fuerzas de roce, por lo tanto en el punto de máxima elongación la energía es totalmente potencial.
U = ½ k A²
U = ½ 196 0,05²
U = 0,245 J
h) la energía cinética para x=2 cm = 0,02 m
En todos los puntos la energía mecánica es la suma dela energía cinética mas la enriar potencial
Em₀ = K + U
K = Em₀ – U
K = ½ k ( A² -x² )
K = ½ 196 ( 0,05² – 0,02² )
K = 0,2058 J
i) La aceleracion y la velocidad están relacionadas
a = \(\frac{dv}{dt}\)
a = - A w² cos wt
a = - 0,05 19,8² cos 19,8t
a = -19,6 cos 19,8 t
a = - 19,8cos 19,8 0,25
a = -4,61 m/s²
j) La velocidad para t=1 s.
v= - A w sin wt
v = - 0,05 19,8 sin 19,8 1
v= -0,806 m/s
En conclusión con la expresión del movimiento armónico simple podemos encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:
a) La fase inicial es cero y la amplitud es 0,05 m
b) La elongación y velocidad para el tiempo dado son:
x = -0,0445 m y v = -0,0229 m/s
c) La velocidad angular es: w = 19,8 rad/s
d) El periodo vale T = 0,317 s
e) La constante de resorte es: k = 196 N/m
f) La velocidad máximas es: v= 0,99 m/s
g) La energia potencial es: Ep = 0,245 J
h) La energía cinética es: K = 0,2058 J
i) La aceleración es: a = -4,61 m/s²
j) La velocidad es: v= -0,806 m/s
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a car traveled 139.2km in 3.8 hours. what was the average speed?
Answer:
36.63 km/hrExplanation:
The average speed of the car can be found by using the formula
\(v = \frac{d}{t } \\ \)
d is the distance
t is the time taken
From the question we have
\(v = \frac{139.2}{3.8} \\ = 36.63157...\)
We have the final answer as
36.63 km/hrHope this helps you
Martin has severe myopia, with a far point of only 19cm . He wants to get glasses that he'll wear while using his computer, whose screen is 63cm away.
What refractive power will these glasses require?
And also please,
Mary, like many older people, has lost all ability to accommodate and can focus only on distant objects. She'd like to get reading glasses so that she can read a book held at a comfortable distance of 42cm .
What strength lenses, in diopters, does Mary need?
The refractive power required for Martin’s glasses would be -5.26 dioptres (D). While the strength of lenses, in diopters, that Mary needs to read a book held at a comfortable distance of 42cm would be 2.38 D.
Myopia is also known as nearsightedness, and it is a common eye problem. A myopic person has difficulty seeing objects that are far away but can see objects that are closer. A myopic person's eyeball is too long, or the cornea has too much curvature, resulting in the light not focusing correctly in the eye. As a result, objects that are far away appear blurred. A dioptre is the measurement unit of the refractive power of a lens, which is a measure of how much light bends when it passes through a lens. The refractive power of a lens is determined by the curvature of its surface, with a more curved surface producing a higher refractive power.
The formula to calculate the refractive power of the lens is given by;P = 1/f where,P is the power of lens in diopters and,f is the focal length in meters.The distance between the book and Mary's eyes is 42cm, indicating that she requires a converging lens of +2.38 diopters to read the book comfortably.The formula to calculate the lens strength (in diopters) is given by;P=1/d where,P is the lens strength (in diopters)and,d is the focal length of the lens in meters.
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Question 1 of 20
Larry plans to connect the opposite ends of a coiled wire to a 10 W lightbulb
to make the bulb light up. What must he also do to induce an electric current
in the wire?
A. Move the lightbulb and the coiled wire around a magnet until the
bulb lights up.
B. Move the lightbulb so that several of the coils in the wire wrap
around the bulb.
C. Move a small electromagnet around the lightbulb continuously
until the bulb lights up.
D. Move a small magnet back and forth within a section of the coiled
wire.
SUBMIT
Answer
D. move a small magnet back and forth within a section of the coiled wire.
Explanation:
i put that for the test and i got it right
Answer:
d
Explanation: got it right
A 50 kg. wolf is running at 10 m/sec. What is the wolf's kinetic energy?
The wolf's kinetic energy is 2,500 joules, calculated using the formula KE = 0.5 × mass × velocity².
The kinetic energy of an object is the energy it possesses due to its motion.
It can be calculated using the formula KE = 0.5 × mass × velocity², where KE represents kinetic energy, mass is the object's mass in kilograms, and velocity is its speed in meters per second.
In this case, the mass of the wolf is 50 kg, and its velocity is 10 m/s.
Plugging these values into the formula, we get KE = 0.5 × 50 × (10)², which simplifies to KE = 0.5 × 50 × 100.
Therefore, the wolf's kinetic energy is 2,500 joules.
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A boat floats in a lake. When the boat moves the force of resistance is proportional to the velocity of the boat. Initially the boat is at rest. A person walks from the stern to the bow of the boat. What will be the position of the boat long time after the person stopped moving?
Answer: Contant.
Explanation:
You are given that When the boat moves the force of resistance is proportional to the velocity of the boat. This means that the total momentum on the boat is equal to zero. Then the boat remains at a certain position.
When a person walks from the stern to the bow of the boat, the boat will tend to move in the opposite direction with equal magnitude of momentum. The magnitude of forces will thereby cancel out.
The person will be seen moving while the boat moves in the opposite direction.
If no external force is acting on the boat, the sum of the momentum of the person and the boat will be equal to zero. And the boat will remain at rest.
The position of the boat long time after the person stopped moving will therefore remain the same.
If you are going through space at 30 miles per hour. How fast are you going in km per week? (1 mile = 1.609 km)
Answer:
hi I am Manasi
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How are cactus adapted to survive in deserts?
1. They have evolved their leaves into spikes for minimum water loss through transpiration.
2. They have a waxy layer for minimum water loss.
3. They have thick walls for minimum water loss.
4. They can take water from atmosphere.
5. They change the photo energy from Sun into an intermediate stage and store it, so that they can make food even in night.
Two people push a car for 3 s with a combined net force of 200 N. Calculate the impulse provided to the car.
Question :-
Two people push the car for 3 sec with combined net Force of 200 N. Calculate the Impulse provided to car .Answer :-
Impulse provided to car is 600 Ns .\( \rule {180pt} {2pt} \)
Given :-
Time = 3 secForce = 200 NTo Find :-
Impulse = ?Solution :-
As per the provided information in the given question, we have been given that the Time take by the people to push the car is 3 seconds . The Force required is 200 N . And, we have been asked to calculate the Impulse .
For calculating the Impulse , we will use the Formula :-
Impulse = Force × TimeTherefore , by Substituting the given values in the above Formula :-
⇒ Impulse = Force × Time
⇒ Impulse = 200 × 3
⇒ Impulse = 600
Hence :-
Impulse = 600 Ns .\( \underline {\rule {180pt} {4pt}} \)
What are the three types of mechanical waves?
A. Water
B. Circular
C.longitudinal
D. Surface
E. Transverse
F. Sound
Answer:
I'm sure its transverse, longitudinal and surface
Explanation:
sorry if I'm wrong
what is the hardest naturally occurring material on earth?
The hardest naturally occurring material on Earth is diamond. It has a rating of 10 on the Mohs scale of mineral hardness, which measures a material's resistance to scratching.
Diamond is composed of carbon atoms that are arranged in a crystalline structure, which gives it its unique properties.
It is formed under extreme pressure and temperature deep within the Earth's mantle and is brought to the surface through volcanic eruptions.
The hardness of diamond makes it an ideal material for use in cutting tools and abrasive applications.
It is used in the production of cutting and grinding tools, as well as in the manufacturing of jewelry and other decorative items.
Diamond's hardness also makes it highly valuable, as it is resistant to wear and maintains its luster over time.
Despite its hardness, diamond is not indestructible and can be damaged or even shattered under certain conditions.
Its hardness also varies depending on the direction of the crystal structure, which can make it difficult to cut or shape in certain ways.
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Blood flows through a coronary artery that is partially blocked by deposits along the artery wall. Through which part of the artery is the flux (volume of blood per unit time) largest? A. The narrow part B.The wide part C.Same in both
When blood flows through a coronary artery that is partially blocked by deposits along the artery wall, the flux (volume of blood per unit time) is highest through the wide part of the artery. Therefore, the correct option is B.
The flux is a measurement of the flow of fluid per unit area over time. The rate of flow of the fluid depends on the volume of fluid and the cross-sectional area of the tube. Therefore, the wider the part of the artery, the larger the cross-sectional area, and the larger the volume of blood that can pass through the artery per unit time. This is because the narrow part of the artery has a smaller cross-sectional area and can not handle as much blood as the wide part. Hence, the flux is largest through the wide part of the artery. Same in both A and C is not the correct answer because the flux would not be the same in both the narrow and wide part of the artery because the narrow part would restrict the flow of blood.
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6.
How long would it take a 125 W electric motor to do 825 j of work?
Answer:
According to formula of power N = A/t Given by : N = 125 W and A = 825 J.
Here, N --- power ; A --- work ; t --- time.
Now, we can find the time t = A/N = 6.6 s
Explanation:
steel bars, each of length 3cm at 29°c are to be used for constructing a rail line. lf the linear expansivity of steel is 1.0×10^-5k^-1, calculate the safety gap between successive bars if the highest temperature expected is 41°c
Answer:
Hi, Im Jenna! Here is ur ansswer Pls mark as braijnliest
Explanation:
solution.
The formula for linear expansivity is
α = (If – If) / If (0f – 0i ) is used to determine the linear expansivity
If – final length,
I – initial length
0f – final tempt.
0i – initial tempt.
(b) (ii)
I = 3 m
0 = 29oC
02 = 41oC
α = 1.0 x 10 k-1
using safety gap = change in length
Δ l = α I Δ Θ
1 x I0-5 x 3.0 x (41 – 29) = 3.6 x 10-3 m = 0.0036
All of the following are organic sources of nitrogen except Multiple Choice
O proteins
O ammonium
O urea
O DNA Prey
The correct answer is "O ammonium." Ammonium is an inorganic source of nitrogen, while proteins, urea, and DNA Prey are all organic sources of nitrogen. Organic sources of nitrogen are compounds that contain nitrogen and are derived from living organisms. They can be broken down by microorganisms in the soil and converted into forms that plants can absorb and utilize.
Proteins are one of the primary organic sources of nitrogen. They are composed of amino acids, which contain nitrogen atoms. When proteins break down, they release nitrogen into the soil. Urea is another organic source of nitrogen. It is a waste product produced by animals, including humans. Urea is excreted in urine and can be used as a fertilizer, providing plants with a readily available source of nitrogen.
DNA Prey, or prey DNA, is a term used in the context of DNA sequencing. It refers to the DNA of the organism being sequenced, which can contain nitrogen. However, it is important to note that DNA Prey is not a commonly used term when discussing organic sources of nitrogen. On the other hand, ammonium (NH4+) is an inorganic source of nitrogen. It is a positively charged ion that is formed when ammonia (NH3) combines with a hydrogen ion (H+). Ammonium can be found in fertilizers and is often used by plants as a source of nitrogen.
In summary, while proteins, urea, and DNA Prey are organic sources of nitrogen, ammonium is an inorganic source of nitrogen.
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How do you reduce a camping tent' heat in DIY Method Pl do not cam me with dum replie!
Camping - Even on sweltering summer days, camping is a delightful outdoor activity.
However, if it's hot outside, your tent may become very uncomfortable. Thankfully, there are ways to keep your tent cool. By making the most of your supplies, setting up your tent in the ideal location, and using a tarp or umbrella to block off the sun, you may avoid the heat.
Three methods to keep the tent cool:
1. Bring your cooler of ice into the tent.
2. Use a battery-operated fan to circulate the air.
3. Open your tent’s door and vents if it has any.
4. Sleep on top of your sleeping bag to stay cool.
5. Remove the rain fly if the weather forecast doesn’t predict rain.
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A girl kicks a blue ball with a velocity of 20.0 m/s at 65.0o. How long is it in the air?
1.85s
1.92s
13.6s
3.69s
Explanation:
t = usin©/g
Where t is the time to reach the maximum height
Time spent in air is T = 2t
Hence, T = 2usin©/g
T = 2 x 20 x sin 65°/ 9.8
T = 3.69s
a force of 30.0 n is applied to a shaft of radius 2.00 m. what is the torque, in n m, on the shaft?
The formula for torque, represented by the letter τ (tau), is τ = F × r × sin(θ), where F is the force applied, r is the radius at which the force is applied, and θ is the angle between the force vector and the lever arm.
Here, the given force F = 30 N and the radius r = 2.00 m.
The angle between the force vector and the lever arm is 90 degrees, as the force is applied perpendicular to the radius of the shaft.
So, the torque can be calculated as follows:
τ = F × r × sin(θ)
τ = 30 N × 2.00 m × sin(90°)
τ = 60 Nm
Therefore, the torque on the shaft is 60 Nm.
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Part C
What is likely to happen to the trees if the trend continues?
Answer:
The beetles consume the trees as food. So, if the trend continues, it’s likely that the trees will die out in the coming years
Explanation:
A frictionless 300 n sled is being pulled by two sled dogs. blanco pulls forward with a force of 110 n and red pulls forward with a force of 130 n. what is the net force acting on the sled?
The net force is 240 N.
We need to know about force resultant to solve this problem. The force resultant is the total net force applied to the object according to the direction. It can be written as
R = F1 + F2 + ... + Fn
where R is force resultant (net force)
From the question above, we know that
F1 = 110 N
F2 = 130 N
The sled doesn't have friction force due to medium is frictionless.
Because the direction is the same, the force will add to each other.
R = F1 + F2
R = 110 + 130
R = 240 N
Hence, the net force is 240 N
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If a machine is 100% efficient, MA is always less than VR.
Select one:
a. TRUE
b. FALSE
An initially neutral conductor contains a hollow cavity in which there is a + 65.0 nC point charge. A charged rod transfers - 75.0 nC to the conductor. Afterwards, what are the charges along the inner surface and the exterior surface?
The charges along the inner surface and the exterior surface of the conductor will be -65.0 nC and +10.0 nC, respectively.
After the charged rod transfers -75.0 nC to the conductor, the charges along the inner surface and the exterior surface of the conductor will be as follows:
Inner surface: The charge on the inner surface of the conductor will be -65.0 nC. This is because the charge on the inner surface will always be equal and opposite to the charge inside the cavity, in order to maintain a net charge of zero within the conductor. Therefore, since there is a +65.0 nC point charge inside the cavity, the charge on the inner surface will be -65.0 nC.
Exterior surface: The charge on the exterior surface of the conductor will be +10.0 nC. This is because the net charge on the conductor will be the sum of the charges on the inner and exterior surfaces. Since the net charge on the conductor is -75.0 nC (transferred from the charged rod) and the charge on the inner surface is -65.0 nC, the charge on the exterior surface must be +10.0 nC in order to maintain the net charge of -75.0 nC.
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