Which of the following compounds has a number of electron rich regions that is different from the other compounds? BCI 03 NH3 NO3

Answer: The oxidation state of chlorine (Cl) in ClO– is +1.

Explanation:

To determine the oxidation state of iodine (I) in IO3– and chlorine (Cl) in ClO–, we can use the oxidation state rules.

For IO3– (iodate ion):

The sum of the oxidation states for all atoms in a polyatomic ion equals the charge of the ion. In this case, the charge is -1.

Oxygen typically has an oxidation state of -2.

There are three oxygen atoms in the iodate ion.

Let x be the oxidation state of iodine (I). Then, we can write the equation:

x + 3(-2) = -1

x - 6 = -1

x = +5

The oxidation state of iodine (I) in IO3– is +5.

For ClO– (hypochlorite ion):

The sum of the oxidation states for all atoms in a polyatomic ion equals the charge of the ion. In this case, the charge is -1.

Oxygen typically has an oxidation state of -2.

Let y be the oxidation state of chlorine (Cl). Then, we can write the equation:

y + (-2) = -1

y - 2 = -1

y = +1

The oxidation state of chlorine (Cl) in ClO– is +1.

The expression 7.0x\(10^7\) ÷ 2.0x\(10^4\) can be expressed in proper scientific notation as 3.5x10^3.

To express the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) in proper scientific notation, we need to perform the division and adjust the result to the appropriate format.

Dividing the numbers, we get:

7.0x\(10^7\) ÷ 2.0x\(10^4\)= 3.5x\(10^{(7-4)\)= 3.5x\(10^3\)

The result of the division is 3.5, and we adjust the exponent by subtracting the exponent of the divisor from the exponent of the dividend (7 - 4 = 3).

Therefore, the proper scientific notation representation of the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) is 3.5x\(10^3\).

Scientific notation is a way to express numbers using a coefficient (in this case, 3.5) multiplied by a power of 10 (in this case, 10^3). It allows for more concise representation of very large or very small numbers.

In this case, the division resulted in a number that is smaller than the dividend and has a positive exponent, indicating a smaller magnitude compared to the original numbers. The coefficient represents the significant digits of the result, while the power of 10 represents the scale or magnitude of the number.

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The volume of the gold sample, given the theoretical density and the mass, is 1.23 ml

When given the theoretical density of a gold sample and the mass, you can use the formula for density to find the volume of the gold sample.

The volume for density is:

Density = Mass / Volume

Mass = 23. 82 g

Density = 19. 30 g / ml

The volume is:

19.30 = 23 .82 / Volume

Volume x 19. 30 = 23. 82

Volume = 23. 82 / 19. 30

= 1.23 ml

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The full question is:

A sample of gold has a mass of 23.82 g, given that the theoretical density is 19.30 g/ml, what is the volume of the gold sample?

Answer:

To solve this problem, we can use the definition of percent concentration by mass:

percent concentration = (mass of solute ÷ mass of solution) x 100%

We know that the percent concentration of NaCl in the solution is 15% by mass, and we have a 500 gram sample of the solution. Let's assume that the mass of NaCl in the sample is x grams.

Using the percent concentration formula, we can write:

15% = (x ÷ 500) x 100%

Simplifying this equation, we get:

x = (15 ÷ 100) x 500 = 75 grams

Therefore, there are 75 grams of NaCl in a 500 gram sample of the solution.

The correct answer is c. 75 grams.

Complete Question

The complete question is shown on the first uploaded image

Answer:

Part A

    activation barrier for the reaction \(E_a = 84 .0 \ KJ/mol\)

Part B

    The frequency plot is  \(A = 2.4*10^{13} s^{-1}\)    

Explanation:

From the question we are told that

     at  \(T_1 = 300 \ K\)   \(k_1 = 5.70 *10^{-2}\)

and  at  \(T_2 = 310 \ K\)   \(k_2 = 0.169\)

The  Arrhenius plot is mathematically represented as

      \(ln [\frac{k_2}{k_1} ] = \frac{E_a}{R} [\frac{1}{T_1} - \frac{1}{T_2} ]\)

Where \(E_a\) is the activation barrier for the reaction

         R is the gas constant with a value of  \(R = 8.314*10^{-3} KJ/mol \cdot K\)

Substituting values

          \(ln [\frac{0.169}{6*10^-2{}} ] = \frac{E_a}{8.314*10^{-3}} [\frac{1}{300} - \frac{1}{310} ]\)

=>       \(E_a = 84 .0 \ KJ/mol\)

The  Arrhenius plot can also be  mathematically represented as

      \(k = A * e^{-\frac{E_a}{RT} }\)

Here we can use any value of k from the data table with there corresponding temperature let take  \(k_2 \ and \ T_2\)

So substituting values

        \(0.169 = A e ^{- \frac{84.0}{8.314*10^{-3} * 310} }\)

=>       \(A = 2.4*10^{13} s^{-1}\)    

Answer:

32,8mL

Explanation:

1lb=2.2kg

18lb= 8.2 kg  

100mg/5mL=20mg/1mL

164mg=32.8mL

Answer:

The EMF and free enthalpy (or Gibbs Free Energy) of a reaction are directly related.

If the free enthalpy of a redox reaction is negative, then the EMF will be negative, indicating that the reaction is spontaneous and will occur without the need for an external source of energy.

If the free enthalpy of the reaction is positive, then the EMF will be positive, indicating that the reaction is not spontaneous and will not occur without the input of energy.

The relationship between free enthalpy and EMF is shown in the following equation:

∆G = -nFE°(cell), where n is the number of electrons transferred, F is the Faraday constant, and E° is the EMF of a cell under standard conditions.

Answer:

D. Valance Electrons

Explanation:

The power for the first tank is 2kW  and the second tank is 150 kw for the theoretical pumping power lifts a solution with a density of 1200 kg/m³ from a tank to a reservoir.

Power is the amount of energy in kilowatt which is required to do some work that needs energy known as power it is the multiplication of pressure and the flow of liquid.

Power for the tank = pressure of water × flow of water

Substituting the value,

power = 1 × 2 = 2 kW = P1

power = 10 × 15 = 150 kW = P2

Therefore,  a solution with a density of 1200 kg/m³ from a tank to a reservoir power for the first tank is 2kW  and for the second tank is 150 kW for the theoretical pumping power lifts.

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Answer:

ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.

Explanation:

Yes, that statement is generally correct. A scientific law is a statement that describes a phenomenon or pattern in nature, often expressed mathematically, without attempting to explain why it occurs. A scientific theory, on the other hand, is a well-substantiated explanation for a set of phenomena, based on empirical evidence and scientific reasoning.

A scientific law summarizes what happens in a particular situation, often in the form of an equation or formula, whereas a scientific theory attempts to explain why it happens.

For example, the law of gravity describes the attraction between masses, but it does not explain why this attraction occurs. In contrast, the theory of general relativity attempts to explain the underlying principles of gravity, including its effects on the curvature of space-time.

It's worth noting that both scientific laws and scientific theories are based on empirical evidence, but they serve different purposes in scientific inquiry. Laws describe what happens in a particular situation, while theories attempt to explain why it happens.

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The value of Kc for the given reaction is 0.0579 (rounded to four decimal places).

The formula for the equilibrium constant, Kc, of a reaction is given by the ratio of the product of the concentrations of the products raised to their respective stoichiometric coefficients to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

The stoichiometric coefficients are the coefficients in the balanced chemical equation.

To determine the value of Kc for the reaction given by the following chemical equation:N2(g) + 3 H2(g) ⇌ 2 NH3(g)

we first need to write the expression for Kc.

The expression for Kc is given by the following formula:Kc = [NH3]² / [N2][H2]³.

We are given the equilibrium concentrations as follows:[N2]eq = 2.66 M[H2]eq = 0.64 M[NH3]eq = 3.34 M

We can substitute these values into the expression for Kc and obtain the following:Kc = (3.34)² / (2.66)(0.64)³ = 0.0579 (rounded to four decimal places).

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The enthalpy of this reaction is 1.48 kJ/mol.

The formula to calculate heat energy is

Q = m × c × ΔT

ΔT = T₂ - T₁

ΔT = T₂ - T₁ = 24.70 - 21.00 = 3.70 °C

Q = m × c × ΔT

Q = 191 × 4.184 × 3.70

Q = 2,956.83 J

Q = (2,956.83 ÷ 1,000) kJ

Q = 2.96 kJ

The enthalpy ΔH = Q ÷ n

ΔH = Q ÷ n

ΔH = 2.96 ÷ 2.00

ΔH = 1.48 kJ/mol

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The correct identification of the units is given below:

The SI units and the physical quantities they represent are the meter for length, the second for time, the kilogram for mass, the kelvin for temperature, the candela for light intensity, the ampere for current flow, and the mole for substance amount.

US customary units refer to the system of measures used in the US to measure objects. All other measures are conventional, including the gallon for volume, mile for length, pound for mass, and degree Fahrenheit for temperature.

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identify each unit as belonging to si units or us customary units. gallon. mile. meter. pound. kilogram. degrees farenheight. kelvin.

Answer:

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Explanation:

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Approximately 1.167 grams of the 25% (m/m) NaCl solution would contain 0.250 moles of sodium chloride.

To determine the mass of a 25% (m/m) sodium chloride (NaCl) solution containing 0.250 moles of sodium chloride, we need to consider the concentration and molar mass of NaCl.

The percentage (m/m) concentration indicates the mass of solute (NaCl) present per 100 grams of the solution. Therefore, a 25% (m/m) NaCl solution contains 25 grams of NaCl per 100 grams of the solution.

First, we calculate the mass of NaCl in the given solution:

Mass of NaCl = (25% / 100%) x Mass of solution

= (25 / 100) x Mass of solution

Next, we can determine the mass of the solution required to have 0.250 moles of NaCl using the molar mass of NaCl, which is approximately 58.44 g/mol.

Mass of NaCl = Moles x Molar mass

Mass of solution x (25 / 100) = 0.250 moles x 58.44 g/mol

Now, we can solve for the mass of the solution:

Mass of solution = (0.250 moles x 58.44 g/mol) / (25 / 100)

= 1.167 g

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Since she suspects that the substance is cocsine, the thing that she should do next is option 1-Perform a confirmatory test.

The way that Drug evidence is collected is that from any crime scene, evidence is obtained, photographed, packaged, documented as well as been sent for analysis and then the forensic scientist will carry out the Analysis.

Since the evidence has been sent to Roshni, all she has to do is to carry out the confirmatory test to see if the drug is what she suspected.

Therefore, Since she suspects that the substance is cocsine, the thing that she should do next is option 1-Perform a confirmatory test.

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x in  Na₂CO₃.xH₂0  is the number of water molecule that is attached to sodium carbonate called water of crystallization. Therefore the value of x is 10

Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known. To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen

The balanced equation is

Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂

Concentration of H₂SO₄= 0.05 mol/L

Volume of H₂SO₄ = 20 ml = 0.02 L

number of moles of H₂SO₄= 0.05× 0.02 = 0.001mol

number of moles of H₂SO₄ = n(Na2CO3) = 0.001 mol

Molar mass of Na₂CO₃= 106 g/mol

mass of Na₂CO₃ = n× M = 0.001 × 106 = 0.106g

change in mass =∆m = 0.276 – 0.106 = 0.17 g

Molar mass of (H₂O = 18 g/mol

n umber of moles of water = mass÷ Molar mass=0.17 g÷18=0.0094mol

x= number of moles of H₂O÷ number of moles of sodium carbonate

 = 0.0094mol÷0.001

  =10

Therefore the value of x is 10

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Answer:

9.93712g

Explanation:

You have 10mL of water at 33 degrees, so you want to look at the density of water at 33 degrees. Then you multiply that density (.993712) by 10 and the mL cancel out and you are left with 9.93712g.

Hope this helps!

Answer: 1 g/ml

Explanation:

5 g / 5ml= 1 g/ml

(a) Partial pressure of Ne is 470 torr. (b) Partial pressure of of CF₄ is 110 torr. (c) Total pressure is 580 torr. (d) Mole fraction of Ne is 0.621.

(a) The initial pressure of Ne is 470 torr, so the partial pressure of Ne after mixing is also 470 torr.

(b) The initial pressure of CF₄ is 110 torr, so the partial pressure of CF₄ after mixing is also 110 torr.

(c) The total pressure is the sum of the partial pressures of the two gases:

Total pressure = partial pressure of Ne + partial pressure of CF₄

Total pressure = 470 torr + 110 torr

Total pressure = 580 torr

(d) To find the mole fraction of Ne, we need to know the number of moles of Ne and CF₄. We can use the ideal gas law to find the number of moles of each gas:

PV = nRT

n = PV/RT

For Ne:

n = (470 torr x 1.50 L)/(0.0821 L·atm/mol·K x 298 K)

n = 19.25 mol

For CF₄:

n = (110 torr x 2.50 L)/(0.0821 L·atm/mol·K x 298 K)

n = 11.72 mol

The total number of moles is:

nTotal = nNe + nCF₄

nTotal = 19.25 mol + 11.72 mol

nTotal = 30.97 mol

The mole fraction of Ne is:

XNe = nNe/nTotal

XNe = 19.25 mol/30.97 mol

XNe = 0.621

Therefore, the mole fraction of Ne is 0.621.

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The number of the atoms that should be the numerator is 6.02 * 10^23 atoms.

We have to note that the conversion factor is the factor that can be used in the conversion of one unit to the other. We have to note that if we are able to change the unit then we can be able to make the conversion.

We have to note that the Avogadro's number is the number of atoms that we can find in one mole of a substance and it has a value of about 6.02 * 10^23 atoms in the atom of magnesium.

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Answer:

T(final) = 26.2°C (3 sig. figs.)

Explanation:

Q = m·c·ΔT

m = mass of sample of interest = 20.0g

c = specific heat of sample of interest = 0.902j·g⁻¹·C⁻¹

ΔT = Temperature change = T(final) - T(initial) = T(f) - 2.5°C

Q = 427 joules

Q = m·c·ΔT => = ΔT = Q/m·c => T(f) = Q/m·c + T(i) = (427j/20.0g·0.902j·g⁻¹·C⁻¹) + 2.5°C = 26.16962306°C (calc. ans.) ≅ 26.2°C (3 sig. figs.)

Answer:

The answer is combustion.

Answer: Oxygen

Explanation: Its found on the periodic table as an element.

Hello!

Answer:

32.8 °C

Hope this helps :)

Answer:

Explanation:

Combined Gas Law

T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C

To solve this problem, we need to consider the energy required to warm the ice cube from -18.5°C to 0°C, the energy required to melt the ice cube, and the energy required to warm the melted water from 0°C to 55°C. Let's calculate the energy for each step and determine the number of ice cubes needed.

Warming the ice cube to 0°C:

The specific heat capacity of ice is 2.05 J/g°C. The temperature change is from -18.5°C to 0°C. Therefore, the energy required to warm the ice cube can be calculated as:

Energy = mass × specific heat capacity × temperature change

Energy = 24 g × 2.05 J/g°C × (0°C - (-18.5°C))

Energy = 24 g × 2.05 J/g°C × 18.5°C = 899.4 J

Melting the ice cube:

The heat of fusion (specific latent heat of fusion) of water is 334 J/g. We need to determine the energy required to melt the ice cube. The mass of the ice cube is 24 g, so the energy required can be calculated as:

Energy = mass × heat of fusion

Energy = 24 g × 334 J/g = 8016 J

Warming the melted water from 0°C to 55°C:

The specific heat capacity of water is 4.184 J/g°C. We need to determine the energy required to warm the melted water from 0°C to 55°C. The mass of the melted water can be calculated by subtracting the mass of the ice cube that melted from the initial mass of the ice cube (24 g).

Mass of melted water = 24 g - 24 g = 0 g (since all the ice melted)

Therefore, no additional energy is required for this step.

Now, let's add up the energy required for each step to determine the total energy needed to cool the coffee from 85°C to 55°C:

Total energy required = Energy to warm the ice cube to 0°C + Energy to melt the ice cube

Total energy required = 899.4 J + 8016 J = 8915.4 J

Given that each ice cube provides 8915.4 J of energy, we can determine the number of ice cubes needed to cool the coffee.

Energy per ice cube = 8915.4 J

Energy required to cool the coffee = Total energy required = 8915.4 J

The number of ice cubes needed = Energy required to cool the coffee / Energy per ice cube

Number of ice cubes needed = 8915.4 J / 8915.4 J = 1

Therefore, you would need to add 1 ice cube to your 355 mL cup of coffee to bring it to 55°C.

The correct answer is A. 1.