What is the momentum of a 1kg ball moving at 5m/s?

Taking into account the reaction stoichiometry, 128.4 grams of C are required to produce 10.7 moles of methane.

In first place, the balanced reaction is:

C + 2 H₂ → CH₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of CH₄ is produced by 12 grams of C, 10.7 moles of CH₄ are produced by how much mass of C?

mass of C= (10.7 moles of CH₄×12 grams of C)÷1 mole of CH₄

mass of C= 128.4 grams

Finally, 128.4 grams of C are required.

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Answer:  343 Celsius

Explanation:

Gay lussac law

T2=T1V2/V1  Temp must be in Kelvin

T2= 308.15 X 9.00 / 4.50 =616.30 K - 273.15 to get back in celsius

=343.15 C

Use reagent f. H2CrO4. Chromic acid is a strong acid used to oxidize alcohols into ketones and carboxylic acids. Chromium trioxide combines with water to produce chromic acid, which is deliquescent, light red or brown in color, and soluble in water.

Lindlar catalyst is a type of heterogeneous catalyst used in organic chemistry for hydrogenation reactions. It is composed of palladium metal supported on calcium carbonate, barium sulfate, or similar materials, and is commonly used in the partial hydrogenation of alkynes to alkenes. The catalyst is named after its inventor, Herbert Lindlar, who developed it in the 1950s.

Lindlar catalyst is a selective catalyst, which means that it allows for the hydrogenation of alkyne functional groups to alkenes while inhibiting further hydrogenation to alkanes. This is achieved by using poisoned or deactivated palladium that restricts the catalyst's activity and allows for partial hydrogenation to occur. This controlled hydrogenation is useful in organic synthesis because it provides a way to selectively reduce alkynes to alkenes without the formation of unwanted byproducts.

Reagent (f) can directly convert given alcohol to its carboxylic acid.

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According to the solubility of  of sparingly soluble electrolytes by conductometer and potentiometer.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.

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Answer:

H2O(g) (negative)

Explanation:

Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Answer: Boiling because it makes the molecules in water bounce around.

Hope it helps.

Answer:

A saturated solution is a mixture in which the maximum amount of a given solute has been dissolved into the solvent. ... At this point adding more solute will not change the concentration of the solution; adding more solute will simply result in more solid at the bottom of the solution.

Answer:

will not change

Explanation:

A saturated solution is a mixture in which the maximum amount of a given solute has been dissolved into the solvent. ... At this point adding more solute will not change the concentration of the solution; adding more solute will simply result in more solid at the bottom of the solution.

The first step we have to follow to answer this question is to convert the given mass to moles using CaCO3 molar mass:

Now, use the following formula to find the volume of water needed to prepare the solution:

It means that 0.29L are needed.

The chemical formula for x and y is Cu₂O and CuO. The mass cooper which can react with 0.5g of oxygen to yield x and y is 2.745 g.

A chemical formula is a phrase that lists the constituent parts of a compound together with their relative quantities. No subscript is used if there is just one atom of a certain kind. A subscript is added to the symbol of an atom if it contains two or more of a certain type of atom.

1. 1.535 g of X → 1.365 g of Copper

1.535 – 1.365 = 0.170g of Oxygen

Atomic weight of Cu = 63.5,

Atomic weight of Oxygen = 16

For Cu 1.365 g / 63.5 = 0.02 mol

For Oxygen 0.170 g / 16 = 0.01 mol

X = Cu₂O

1.450 g of Y → 1.160 g of Cu

1.450 – 1.160 = 0.290 g of Oxygen

For Cu = 1.160 g / 63.5 = 0.018 mol

For Oxygen = 0.290 g / 16 = 0.018 mol

Y = CuO

2. The total mass of Oxygen = 0,170 g + 0,290 g

= 0.460 g

Total mass of Cu = 1.160 g + 1. 365 g

= 2.525 g

0.460 g of Oxygen → 2.525 g of Cu

0.500 g of Oxygen → (2.525 x 0.5) / 0.460

= 2.745 g of Cu

Thus, The law of multiple proportions was formulated by John Dalton in 1804.

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Answer:

26,654,082.

Explanation:

Answer:

In the given question, the mass of empty slender is given 25 points 489 Grand. The mass of Slender plus unknown liquid is given 57 points 847 g. The volume of a non liquid is given 45 three ml. We have to find the density of a non liquid. Firstly we will find the mass of unknown liquid. As the mass of unknown liquid is equal to the mass of cylinder plus unknown liquid minus the mask of empty cylinders. So the mass of a non liquid is equal to seven points 847 g -25 points 489 g. The mass of a non liquid will be 32 points 358 g. The formula to calculate the density of a non liquid is equal to the mass of a non liquid divided by the volume of a non liquid. So we will put the values as the mass of a non liquid is 32.358 g, Divided by the volume, which is given 45.3 ML. When we solve this Comes out to be 0.71 g, but I am in. So the Final answer is the density of a non liquid is equal to 0.71 g.

Answer

s: 1 orbital

p: 3 orbitals

d: 5 orbitals

f: 7 orbitals

from

1moles=iatom

Mole=mass÷avogardos

Where

Avogadro's= 6.02×10²³

So moles = 65.0÷6.02×10²³

Atoms of zinc = 391.6 ×10²³

The number of atoms present in the given mass of Zinc that is 65.0gm is \(5.99\times10^{ 23}\).

Atoms are the basic building blocks of matter. They are the smallest units of an element that retain the chemical properties of that element.

Now, to determine the number of atoms in a given number of moles, we can use Avogadro's number, which is approximately  \(6.022 \times10^{23}\)atoms per mole.

First, we calculate the number of moles of zinc in 65.0g by dividing the given mass by the molar mass of zinc. The molar mass of zinc (Zn) is 65.38 g/mol.

Number of moles = Mass / Molar mass

Number of moles = 65.0g / 65.38 g/mol ≈ 0.9942 mol

Next, multiply the number of moles by Avogadro's number to find the number of atoms.

Number of atoms =\(Number of moles \times Avogadro's number\)

Number of atoms = \(0.9942\)mol × \(6.022 \times10^{23}\) atoms/mol

Therefore, approximately \(5.99\times10^{ 23}\) atoms are present in 65.0g of zinc.

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This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Answer:

From the chemical isotopes in leftover shells of foraminifera, scientists can estimate the ocean's temperature and are able to determine the air's carbon dioxide content.

What are isotopes?

Isotopes are the elements which have same atomic number but different mass number. For example - Carbon has three isotopes- C-12, C-13, C-14

In the three isotopes of carbon, all three isotopes have six protons, but carbon-12 has six neutrons, carbon-13 has seven neutrons, and carbon-14 has eight neutrons. Hence, Mass number differs in case of isotopes.

Scientists can learn about the climate at the time the foraminifera lived by analyzing the chemical isotopes in their leftover shells. Estimation of the ocean's temperature based on the ratio of oxygen isotopes in the shells can also be done. The amount of carbon dioxide in the air at the time based on the ratio of carbon isotopes in the shells can also be calculated.

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Your question is incomplete, but most probably your full question was,

What can scientists learn from the chemical isotopes in leftover shells of foraminifera about the climate at the time the foraminifera lived?

a. They can calculate the amount of carbon dioxide in the air.

b. They can estimate the ocean's temperature.

c. They can calculate the amount of rainfall.

d. They can estimate the air temperature.

Answer:

Explanation:

If you have options, could you please tell me so I can further help you. If you just need an example then

Examples of pure substances include iron, steel, and water

Hope this helps (:

Answer

These are the following answers

A) zinc oxide

B) sugar dissolved in water

C) pond water

D) soil

Explanation:

Answer:

Explanation:

0.150mg - one day

Convert 75 Mcg to mg

= 75/100=0.75mg

If 0.150mg is taking for one day

Then 0.75/0.150=5mg

5mg multiple by 7 will be talking for a week 5 mg * 7=35mg

The mass of HF produced from the given amounts of BF₃ and H₂ is 99.5 grams.

To solve this problem, we need to use stoichiometry to determine the amount of HF produced from the given amounts of BF₃ and H₂.

From the balanced equation;

2 BF₃ + 3 H₂ → 2 B + 6 HF

We can see that 2 moles of BF₃ react with 3 moles of H₂ to produce 6 moles of HF. This means that the ratio of BF₃ to HF is 2:6, or 1:3.

First, we need to calculate the number of moles of BF₃ and H₂ from their given masses and molar masses;

n(BF₃) = m(BF₃) / M(BF₃) = 40 g / 67.81 g/mol = 0.59 mol

n(H₂) = m(H₂) / M(H₂) = 5 g / 2.02 g/mol = 2.48 mol

Next, we can determine which reactant is limiting by comparing their mole ratios. The ratio of BF₃ to H₂ is 1:1.67, which means there is not enough H₂ to react with all of the BF₃. This makes H₂ the limiting reactant.

To find the number of moles of HF produced, we use the mole ratio from the balanced equation;

n(HF) = n(H₂) × (6 mol HF / 3 mol H₂) = 2.48 mol × 2

= 4.96 mol

Finally, we calculate the mass of HF produced from its number of moles and molar mass;

m(HF) = n(HF) × M(HF) = 4.96 mol × 20.01 g/mol

= 99.5 g

Therefore, the mass of HF is 99.5 grams.

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Answer:

D

Explanation:

Transfer of electrons from Na to Cl

Na has configuration of 2,8,1 it will lose one electron to Cl with configuration of 2,7 inorder for both to attain an octet configuration

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions, and with everything in its standard state.

According to the balanced chemical equation ;

CH₄(g) + 2O₂(g) ⟶ CO₂(g) + 2H₂O(l)

Now,

ΔH⁰ = ΔH⁰f(products) − ΔH⁰f(reactants)

​

       = [ΔH⁰(CO₂) +ΔH⁰(H₂O)] − [ΔH⁰(CH₄) + 2ΔH⁰(O₂)]

       = [−393.5 + 2 x (−285.8)] − [−62.7 + 2 x 0]

        = − 902.4 kJ

Hence, The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

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The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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The reaction has a first order in Cl 2 and a second order in NO. The general order of reactions is 2+1 = 3.

We must ascertain the values of the exponents n, m, and p as well as the rate constant, k, in order to derive a rate law. The values of the coefficients required to formulate the rate law are available to us if the reaction orders for a reaction are provided.

The reaction's rate law is rate, starting from the slow step

k'[NOCl2][NO] - (1).

Fast step is used to determine the concentration of NOCl 2, which is an intermediate.

[NOCl 2]=K[NO][Cl2] - (2)

Substitute (2) in (1)

rate=k'K[NO][Cl2][NO]

Hence, rate =k[NO]2[Cl]

The reaction has a first order in Cl 2 and a second order in NO. The general order of reactions is 2+1=3

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Answer:

Sublimation is when a solid transitions into a gas, without turning into liquid.

Decantation is when a mixture of liquids is allowed to separate, such that an element of the mixture may be removed.

Explanation:

Andresiaは13.1マイルの長さのレースを走っています。彼はすでに1.1マイル走っています。アンドレスが走るために残っているマイル数を再確認する

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The slope of a distance-time graph for this motion will have a straight line to represent that the object in motion is at a constant speed.

A distance-time graph depicts how far an object has traveled in a specified amount of time. It is a simple line graph that depicts distance versus time findings. The Y-axis represents distance. On the X-axis, time is plotted.

The slope of the distance-time graph should always be constant because the bike is moving at a constant speed. As a result, the graph will be a straight line through the origin.

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To answer the seventh question, we need the specific value of the heat of fusion (Hf) of ice. This information is missing from the given text, so we cannot provide the final answer.

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