What is the frequency of a wave that has a wavelength of 10.5x10-10
O
-18
O
O
O
3.5 × 10
2.85714286 × 10¹7
-43
6.9573 × 10
0.105
AS

Answer:   4.15234 m

512 g H2O * \(\frac{1 kg}{1000 g}\) = 0.512 kg H2O

Nitric Acid:  HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol

H = 1.008 g/mol

N = 14.007 g/mol

O3 = 3*15.999

134 g HNO₃ * \(\frac{mol}{63.012 g}\) = 2.126 mol

m = \(\frac{2.126 mol}{0.512 kg}\) = 4.15234 m

Answer:

0.004 m

Explanation:

Given data:

Mass of nitric acid = 132 g

Mass of water = 512 g

Molality of nitric acid = ?

Solution:

Formula:

Molality = number of moles of solute / mass of solvent in Kg

Number of moles of nitric acid:

Number of moles = mass/molar mass

Number of moles = 132 g/ 63.01 g/mol

Number of moles = 2.09 mol

Molality:

m = 2.09 mol / 512 Kg

m = 0.004 m

False.

There is more thermal energy (faster moving particles) in a warmer region, so they spread out over time, warming up the other regions and losing energy.

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Answer:

d

Explanation:

it's called the hydrocarbon

Answer:

A hydrocarbon

Explanation:

When one element in the compound has been swapped out for another, the single replacement reaction can be recognized. Option C is right as a result.

The replacement reaction is the process in which a compound is formed after a highly reactive element has replaced a low reactive element.

The reaction is listed as follows:

AX + Y X + AY

The highly reactive X causes Y to replace Y in the complex, creating the compound AX.

One element in a compound is replaced by another in a chemical reaction known as a single-displacement reaction, sometimes referred to as a single replacement reaction or exchange reaction.

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Answer:

The average mass of one atom of arsenic is 74.92 amu, and the mass of one mole of arsenic atoms is 74.92 grams.

The mass of one mole of arsenic atoms is 74.92 grams.

Calculation,

Mass of one mole of arsenic = Mass of 1 arsenic atom × \(N_{A}\)

Where, \(N_{A}\) = Avogadro's number = 6.022 × \(10^{23}\)

Mass of one arsenic atom = 74.921 u

One u =  1.66 × \(10^{-27}\) kg

And,

Mass of one mole of arsenic atom = 6.022 ×\(10^{23}\) × 74.921 × 1.66 × \(10^{-27}\)×\(10^{3}\) kg

Mass of one mole of arsenic atom = 74.92 \(gmol^{-1}\)

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Answer:

One of the organelles in eukaryotic cells that carry out digestion and waste removal.

Answer:

It's X

Explanation:

kinetic energy

Explanation:

energy associated with motion is kinetic energy

Answer: Kinetic Energy

Explanation: Kinetic energy is the energy of mass in motion. The kinetic energy of an object is the energy it has because of its motion. ... Note that energy is a scalar quantity, i.e., it does not depend on direction, and it is always positive.

The limiting reactant in this reaction is chlorine gas. 0.53 g of chlorine gas will produce about 0.94 g of ferrous chloride.

A limiting reactant in a reaction is the reactant which is fewer in amount or consume early without complete reaction with other reactants. Hence, as soon as this reactant is consume, the reaction stops.

In the given reaction, one mole of Fe reacts with one mole of Cl₂ gas.

Atomic mass of Fe = 55.8 g/mol

molecular mass of Cl₂ = 71 g/mol

no.of moles in 0.60 g of Fe = 0.60 / 55.8 = 0.010 moles.

no.of moles of 0.53 g of Cl2 = 0.53 /71 = 0.007 moles.

Here, both are needed in equal number of moles, but the number of moles of chlorine gas is fewer hence, it is the limiting reactant.

molar mass of FeCl₂ = 126.8 g/mol

71 g of chlorine gas produce 126.8 g of FeCl₂. Then mass of FeCl₂ produced by 0.53 g of Cl₂.

(0.53g × 126.8 g) /71 g = 0.94 g

Therefore, 0.94 g of FeCl₂ is produced.

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Answer:

A

Explanation:

Sana makatulong tong answer ko

The total number of molecules in 34.0 g of ammonia is equal to 12.044×10\(^23\) molecules according to the concept of Avogadro's number.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number.

In the given example,number of molecules is determined as follows,

17 g ammonia has 6.022×10²³ molecules

So,34 g ammonia has, 34×6.022×10²³/17=12.044×10²³ molecules.

Hence, the total number of molecules in 34 g of ammonia is 12.044×10²³ molecules.

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Your question is incomplete, but the most probable answer is 12.044×10²³ molecules.

Answer:

0 degree C

Explanation:

0 degree C = 32 degree F

0 degree F = -17.7778 degree C

Answer:

0 degrees C would be warmer

Explanation:

Answer:

calcium ions

Explanation:

Water hardness is due to the presence of calcium ions, and to a lesser extent, magnesium, iron, and manganese.

Insects from the genus Cimex known as bed bugs feast on blood, typically at night and skin rashes.

Thus, Their bites can have a variety of negative health repercussions, such as skin rashes, emotional effects, and allergy symptoms.  

The effects of bed bug bites on the skin might range from little redness to obvious blisters.  Itching is typically prevalent, and symptoms might take anywhere from minutes to days to manifest.  

Some people might experience fatigue or a fever. Usually, impacted bodily parts are those that are exposed. There is no known contagious disease that their bites can spread.Vasculitis and regions of dead skin are unusual complications.

Thus, Insects from the genus Cimex known as bed bugs feast on blood, typically at night and skin rashes.

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Answer:

The answer is option C.

Explanation:

A covalent bonded molecule when not dissolved in an aqueous solution does not contain any ions hence does not conduct electricity making it an insulator.

Hope this helps you.

Answer:

option C is the right answer.

Explanation:

Covalents are poor conductors of heat and electricity, so anything moulded or bonded with covalents are poor conductors of heat and electricity( insulators)

Answer:

C The atoms has a tiny, massive nucleus at its center with electrons surrounding it

Explanation:

From the experiment by Rutherford, he suggested a model of the atom where there is a tiny but massive nucleus at the center with electrons surrounding it.

Answer:

Mass of compound c = 6 g

Explanation:

Given:

Mass of compound a = 2.5 g

Mass of compound b = 3.5 g

Find:

Mass of compound c

Computation:

According to Law of conservation of mass

Mass of compound a + Mass of compound b = Mass of compound c

Mass of compound c = 2.5 + 3.5

Mass of compound c = 6 g

Answer:

-1

Explanation:

Proton +1

Neutron 0

Electron −1

To get the number of moles, you need to use this equation:

n = m/M

where n is the number of moles, m is the mass and M is the molar mass of Iron.

Given:

m = 5227 g

M = 55.8 g/mol (from the periodic table)

Therefore

n = 5227 g/55.8 g/mol

n = 93.7

The first option is closer to 93.7 so the answer is the first option.

There are approximately 0.00493 moles of N in 0.217 g of N2O.

To determine the number of moles of N in 0.217 g of N2O, we need to convert the mass of N2O to moles using the molar mass of N2O, which is 44.0128 g/mol. We can use the formula:

moles = mass / molar mass

So, moles of N = 0.217 g / 44.0128 g/mol = 0.00493 mol. Therefore, there are approximately 0.00493 moles of N in 0.217 g of N2O.

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Answer:

D. something's that's produced during a chemical reaction

Answer:

Explanation:

The answer is Option D.

A substance that is produced during a chemical reaction.

for example in a chemical reaction A+B -----> C

here, reactants A and B react together to produce product C.

The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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The median reaction at the second end point in the HCl and NaOH titration is: HCl + NaOH → NaCl + H2O

In a titration between hydrochloric acid (HCl) and sodium hydroxide (NaOH), the reaction involved is the neutralization reaction between an acid and a base. The balanced equation for this reaction is:

HCl + NaOH → NaCl + H2O

In this reaction, one mole of HCl reacts with one mole of NaOH to form one mole of NaCl (sodium chloride) and one mole of water.

During the titration process, the reaction occurs gradually as the base is added to the acid solution.

The first end point of the titration is reached when the moles of HCl and NaOH are stoichiometrically equivalent, meaning they react in a 1:1 ratio. At this point, all the HCl has been neutralized by the NaOH, and no excess of either reagent remains.

However, if the titration is continued beyond the first end point, the reaction between HCl and NaOH can still occur, albeit in a different ratio.

The second end point refers to the point where the moles of NaOH added exceed the stoichiometrically required amount to neutralize the HCl completely. As a result, any excess NaOH added after the second end point reacts with the excess HCl in a 1:1 ratio.

Therefore, the median reaction at the second end point in the HCl and NaOH titration is:

HCl + NaOH → NaCl + H2O

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Due to the inverse relationship between bond length and bond strength, triple bonds, which are the strongest bonds, also have the shortest bond lengths.

Why do single bonds tend to be longer than triple bonds?

The strength of the bond affects how long the bond lasts. The link will be stronger and last longer. Because they are the strongest and shortest, triple bonds. Next are double bonds, which are between single and triple bonds in terms of strength.

The quantity of bound electrons determines how long the bond will be (the bond order). The attraction between the two atoms is stronger and the bond length is shorter the higher the bond order.

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Metal conductivity generally goes down or resistivity goes up with temperature goes up.

The temperature and pressure of the left box is 250c (298 K), and 1 atm pressure.

The right box is at standard temperature and pressure.

Standard temperature and pressure is 00c (273.15 K) and 1 atm.

Hence, the pressure is the same, therefore the position is piston will be the same as the left figure.

At constant pressure, volume is directly proportional to absolute temperature.

\(V \propto T .\)

Now, as the temperature at the right box is less than 250c that of the left box, hence the volume decreases significantly.

The arrangement of molecules in the right box will be closer.

A diagram of the right box is given below.

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The question asks us to calculate how many moles of phosporic acid (H3PO4) can be produced from 180.4 kg of sulfuric acid (H2SO4).

The first step is to determine the molar mass of each compound. To calculate the molar mass, I'll be using the following atomic masses (found in a periodic table):

H: 1.00 u

P: 30.97 u

O: 15.99 u

S: 32,07 u

Then we calculate the molar mass of H3PO4 and H2SO4 considering the atomic masses and the amount of each atom in the compound:

H3PO4: (3 * 1.00) + (1 * 30.97) + (4 * 15.99) = 97.93 g/mol

H2SO4: (2 * 1.00) + (1 * 32.07) + (4 * 15.99) = 98.03 g/mol

Now that we know the molar mass, we can calculate the number of moles contained in 180.4 kg of H2SO4::

98.03 g H2SO4 ------------- 1 mol H2SO4

(180.4 * 1000) g H2SO4 -- x

Solving for x, we have that 180.4 kg of H2SO4 corresponds to 1.840 x 10^3 moles of H2SO4

The last step is to calcuate the amount of H3PO4 produced considering the stoichiometric coefficients from the reaction given:

3 mol H2SO4 -------------------- 2 mol H3PO4

1.840 x 10^3 mol H2SO4 ---- y

Solving for y, we have that 1.227 x 10^3 moles of H3PO4 are produced when using 180.4 kg of H2SO4.

Answer:

Number of moles = 0.002 mol

Explanation:

Given data:

Volume of solution = 13.42 mL

Molarity of solution = 0.1400 M

Number of moles of NaOH = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Volume of solution:

13.42 mL (13.42 mL×1 L /1000mL = 0.013 L)

by putting values,

0.1400 M = number of moles / 0.013 L

Number of moles = 0.1400 M × 0.013 L

            M = mol/L

Number of moles = 0.002 mol

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

\(n_{H_2}^{by\ HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl} =0.0284molH_2\\\\n_{H_2}^{by\ Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2\)

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

\(m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2\)

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

\(m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg} =0.690gMg\)

Thus, the mass of excess magnesium turns out:

\(m_{Mg}^{excess}=2.38g-0.690g=1.69gMg\)

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

\(Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%\)

Best regards!

a) The limiting reactant would be HCl

From the equation of the reaction:

\(Mg (s) + 2 HCl (aq) ---> MgCl_2 (aq) + H_2 (g)\)

The mole ratio of Mg to HCl is 1:2.

Mole = mass/molar mass = molarity x volume

Mole of Mg = 2.38/24.3

                     = 0.098 moles

Mole of HCl = 2.27 x 25/1000        

                     = 0.057 moles

Thus, HCl is limiting while Mg is in excess.

b) Since the mole ratio of HCl to H2 is 2:1:

Mole of H2 produced = 0.057/2

                                    = 0.028 moles

Mass of H2 produced = mole x molar mass

                                    = 0.028 x 2

                                     = 0.057 g

c) Actual mole of Mg that should react = 0.057/2

                                                                    = 0.028 moles

Excess mole of Mg = 0.098 - 0.028

                                   = 0.07

Mass of excess Mg = 0.07 x 24.3

                                 = 1.701 g

d) Percentage yield if 0.044 g of hydrogen is obtained = yield/theoretical x 100

                     = 0.044/0.057 x 100

                       = 77.19%