The student's claim is untrue. When the rod is brought closer, sphere A is polarized, and sphere B acquires a net negative charge. When the rod is removed, sphere B remains charged but sphere A does not remain polarized.
An uncharged object has a neutral charge because it has the same number of protons and electrons. An object is said to be positively charged if it lacks electrons and negatively charged if it has an excess of electrons.
The nature of electric charges is that if the charges are the same, they will repel each other, and if the charges are different, they will attract. So a charged object can attract other charged objects that have a different charge or attract one type of charge on an uncharged object.
When the positively charged rods are brought closer but do not touch ball A. Then sphere A, sphere A is polarized, and sphere B is negatively charged. When the rod is removed, sphere B remains charged but sphere A does not remain polarized.
Complete the question, see the picture.
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A magnifier allows one to look at a very near object by forming an image of it farther away. The object appears larger. To create a magnifier, one would use a.
In order to create a magnifier in convex lens, you should choose a short focal length that is lesser than 1 meter.
What is a convex lens?A convex lens is also referred to as converging lens and it can be defined as a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.
In Science, a magnifier refer to an optical instrument that allow us to look at a very near object because its image is generally formed farther away. Thus, the image of the object appears to be much larger.
In this context, you should choose a short focal length that is lesser than 1 meter when you want to create a magnifier in convex lens because the nearer the object is to the lens, the larger would be the image formed.
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In 1924, edwin hubble proved that the andromeda galaxy lay far beyond the bounds of the milky way, thereby putting to rest the idea that it might have been a cloud within our own galaxy. What key observation enabled him to prove this?.
The key observation enabled Edwin Hubble to prove this by observing individual Cepheid variable stars in Andromeda and applying the period-luminosity relation.
American astronomer Edwin Powell Hubble lived from November 20, 1889, through September 28, 1953. He was a significant contributor to the development of observational cosmology and extragalactic astronomy.
Hubble established that many objects formerly believed to be "nebulae" or clouds of gas and dust, were actually galaxies outside the Milky Way. He scaled galactic and extragalactic distances using the strong direct correlation between a classical Cepheid variable's luminosity and pulsation time, which was found in 1908 by Henrietta Swan Leavitt.
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assume all pulleys are massless and frictionless, and the systems are in equilibrium. find the tension t. the acceleration due to gravity is 9.8 m/s 2
The tension in each pulley would be is 74.96 N.
What is pulley system?A pulley system is a type of mechanical device that uses pulleys to lift or move heavy objects. It consists of two or more pulleys, a belt or cable, and a motor or hand-operated force. The pulleys are connected with a belt or cable that passes over them, creating a loop.
The tension in a pulley system can be found using the equation:
T = m * g * (sin θ1 + sin θ2)
where m is the mass of the hanging object, g is the acceleration due to gravity (9.8 m/s2 in this case), and θ1 and θ2 are the angles of the pulleys.
So to find the tension, we need to know the mass of the object and the angles of the pulleys. If the system is in equilibrium, then the tension in the two pulleys must be equal, so we can set the tension to be equal to the same value in each pulley.
Once we know the mass of the object and the angles of the pulleys, we can solve for the tension in each pulley using the equation above.
For example, if the mass of the object is 10 kg, and the angles of the pulleys are 30° and 45°, then the tension in each pulley would be:
T = 10 kg * 9.8 m/s2 * (sin 30° + sin 45°)
T = 74.96 N
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i will give you full point and mark you as brainiest if you help me please i need it sooner.
The energy of the sun Is a response for the life on earth The planet might take a seat down withinside the liveable radius starting from 0. eighty-five AU to two AU.
Why large planets rotates faster?The large the planet quicker will be the rotation speed, and therefore shortest the time to take rotate across the axis. The large planets are exceedingly greater solid whilst as compared to the small planet system.
The hazards are
• With improved size, the quantity of gravitational enchantment posed via way of means of the planet might additionally increase. This might cause attracting outer area asteroids and consequential crater impact.
• The large the size, the farther it'd be from the big name to atone for the hydrostatic balance, hence reducing the possibilities for it being an inhabitable area.
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i GOT DISCONNECTED WITH A TUTOR THAT WAS EXPLAING, NEED HELPIna shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of −0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.
Given that,
The mass of marble A, m₁=0.08 kg
The mass of marble B, m₂=0.05 kg
The initial velocity of marble A, u₁=0.5 m/s
As the marble B was at rest, the initial velocity of marble B is u₂=0 m/s
The final velocity of marble A, v₁=-0.1 m/s
Let the final velocity of marble B be v₂.
According to the law of conservation of momentum, the total momentum before the collision is equal to the total after the collision.
Therefore
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)On rearranging the above equation,
\(v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}\)On substituting the known values in the above equation,
\(\begin{gathered} v_2=\frac{0.08\times0.5+0.05\times0-0.08\times-0.1}{0.05} \\ =\frac{0.048}{0.05} \\ =0.96\text{ m/s} \end{gathered}\)Therefore the
Answer:
See below
Explanation:
Use conservation of momentum (rather than Kinetic Energy ) for collision problems:
Momentum A = mv = .08 * .5 = .04 km m/s
Momentum B = mv = 0
Total Momentum = .04 + 0 = .04 kg m/s
After collision the sum must be the same
A = mv = .08 ( -.1 ) = - .008 kg m/s
B = m vb = .05 vb
.04 = - .008 + .05 vb
vb = + .96 m/s in the same direction as original A direction
what is the wavelength of a 28Hz periodic wave at 10 meters per second?
AnswerAnswerAnswerAnswerAnswer:0.3571m
Explanation:
Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?
a
2. 970E4 N
b
1. 535E4 N
c
1. 934E4 N
d
4. 550E4 N
e
4. 295E4 N
f
3. 400E4 N
g
3. 821E4 N
h
2. 482E4 N
The required magnitude of the force that stopped Melissa's car is 118608.7 N.
What are 1st 2nd and 3rd laws of motion?According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
According to question:An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
Given,
speed=8.133 m/s
final velocity=0 (due to impact)
time=0.3994 seconds
distance=11.01m
Then,
S = ut + (at^2)/2
a = 2(s - ut)t^2
a = 97.3 m/s^2
So,
Force = ma
Force = 1219(97.3)
Force = 118608.7 N
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Figure 1 shows the kinetic energy as a function of time for a 2kg object that is released from rest and falls toward Earth’s surface. Figure 2 shows the kinetic energy as a function of time for a 5kg object that is released from rest and falls toward Earth’s surface. Both objects are released simultaneously from the same height. How much does the gravitational potential energy of the object-object-Earth system change from 0s to 10s ?
a) 400J
b)600 J
c)1000 J
d) 1400J
Answer:
The answer is 1400 J, according to my Physics teacher.
Explanation:
You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)
1. What kind of spectrum (continuous, bright line or dark line) would you expect to see (in visivble light) from each of the following objects? Explain how you reached each conclusion. a. a steel girder, still glowing as it is removed from its mold b. sunlight shining through our atmosphere (as seen from Earth's surface) c. the Orion Nebula (a hot, glowing cloud of thin gases)
2. The planets in our solar system show regularities and trends that suggest they formed in a rotating disk of gases and dust grains called solar nebula. Describe three of these regularities/trends and their significance in the solar nebula concept.
1. a. A steel girder, still glowing as it is removed from its mold, would produce a **bright line spectrum**. This is because the intense heat causes the atoms in the steel to emit light at specific wavelengths. The high temperature excites the electrons in the atoms, and as they return to lower energy levels, they emit photons of specific energies, resulting in distinct bright lines in the spectrum.
b. Sunlight shining through our atmosphere (as seen from Earth's surface) would produce a **continuous spectrum**. The sunlight consists of a broad range of wavelengths, covering the entire visible spectrum. As it passes through Earth's atmosphere, which contains various gases, particles, and molecules, these components do not selectively absorb or emit specific wavelengths, resulting in a continuous distribution of colors in the spectrum.
c. The Orion Nebula, a hot, glowing cloud of thin gases, would exhibit an **emission line spectrum**. The gases in the nebula are energized by nearby stars, causing them to emit light at specific wavelengths characteristic of the elements present. The excited electrons in the gas atoms emit photons at discrete energies, creating bright lines in the spectrum corresponding to specific elements or molecular transitions.
2. Three regularities/trends observed in the planets of our solar system that support the solar nebula concept are:
a. **Orbital Plane Alignment**: Most planets orbit the Sun in a nearly flat plane known as the ecliptic. This alignment suggests that the planets formed from a rotating disk of gas and dust, as the rotation of the solar nebula would have caused material to flatten into a disk-shaped structure.
b. **Terrestrial and Jovian Planet Differences**: There is a clear distinction between the inner terrestrial planets (Mercury, Venus, Earth, and Mars) and the outer gas giant planets (Jupiter, Saturn, Uranus, and Neptune). The terrestrial planets are smaller, denser, and composed mainly of rocky material, while the gas giants are larger, less dense, and composed mostly of hydrogen and helium. This supports the idea that the solar nebula had different zones with varying compositions and temperatures, leading to the formation of different types of planets.
c. **Rocky Debris in Inner Solar System**: In the inner solar system, there are numerous rocky asteroids and comets, which are remnants from the early stages of planet formation. These bodies are predominantly found in the asteroid belt between Mars and Jupiter and the Kuiper Belt beyond Neptune. Their presence suggests that rocky material was abundant closer to the Sun, while the outer regions contained more gas and icy material.
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If an object has ____
particles (more mass), but is the same _____
then it will have more thermal energy
Identify the correct information about the kinetic energy (KE) and potential energy (PE) of each point in the path of the pendulum. Assume points A and Care the maximum height of the pendulum. Answer Bank :- Min KE Max PE - Max KE Max PE - MKE Min KE - Min PE Min PE
The correct information about the kinetic energy (KE) and potential energy (PE) at each point in the path of the pendulum: Point A: Min KE, Max PE, -Point B: Max KE, Min PE, - Point C: Min KE, Max PE.
Point A: At the maximum height, the pendulum has no motion, so it has minimum kinetic energy (Min KE). However, its potential energy is at its maximum due to its height (Max PE). So, Point A has Min KE and Max PE.
Point B: At the midpoint of the pendulum's swing, it reaches its maximum speed, giving it maximum kinetic energy (Max KE). The potential energy is at its minimum here because the pendulum is at its lowest point in the swing (Min PE). So, Point B has Max KE and Min PE.
Point C: This point is similar to Point A, as it is also at the maximum height of the pendulum. Therefore, Point C has minimum kinetic energy (Min KE) and maximum potential energy (Max PE).
In summary:
- Point A: Min KE, Max PE
- Point B: Max KE, Min PE
- Point C: Min KE, Max PE
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A bat flies toward a wall, emitting a steady sound of frequency 1. 70 khz. This bat hears its own sound plus the sound reflected by the wall. How fast should the bat fly in order to hear a beat frequency of 8. 00 hz?.
The bat should fly about 0.8065 m/s in order to hear a beat frequency of 8 Hz.
The shift in a wave's frequency caused by an observer moving away from the wave source is known as the Doppler effect or Doppler shift. The equation for this is given by,
\(f=\frac{v \pm v_0}{v\mp v_s}f_s\)
where f is the observed frequency, v is the speed or velocity of the sound waves, v₀ is observer velocity ("+" if it's towards and "-" if it's away from the source), vs is source velocity("-" if it's towards and "+" if it's away from the observer), and fs is the actual frequency of the sound waves.
The velocity of sound waves in the air is 344 m/s, v₀ is zero for the incident, v is the source velocity towards the wall, and fs is 1700 Hz.
Then, the incident frequency is given by,
\(f_{incidence}=\frac{344-0}{344-v}\times f_s\)
The wall is stationary, therefore, f(incidence)=f(reflected). Then, the new frequency the bat hears is,
\(\begin{aligned}f_{new}&=\frac{344+v}{344}\times f_{reflected}\\&=\frac{344+v}{344}\times \frac{344-0}{344-v}\times f_s\\&=\frac{344+v}{344-v} \times f_s\end{aligned}\)
To hear a beat frequency of 8 Hz, the velocity of the bat should be,
\(\begin{aligned}f_{new}-f_s&=8\\\left(\frac{344+v}{344-v} \right)f_s-f_s&=8\\\frac{344+v}{344-v}-1&=\frac{8}{f_s}\\\frac{344+v-344+v}{344-v}&=\frac{8}{1700}\\2v&=0.0047(344-v)\\2v&=1.6168-0.0047v\\2.0047v&=1.6168\\v&=\mathrm{0.8065\;m/s}\end{aligned}\)
The answer is 0.8065 m/s.
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A. PE= Maximum, KE = Minimum
B. PE= Minimum, KE = Maximum
C. PE= Increasing, KE= Decreasing
D. PE=Decreasing, KE = Increasing
Answer:
Explanation:
im confused
Answer:. B
Explanation: how this helps sry if I'm wrong
FILL IN THE BLANK. when cycling forward in a straight line, the knee is rotating about a(n) ____ axis.
When cycling forward in a straight line, the knee is rotating about a(n) horizontal axis.
Cycling, often known as bicycling or biking when done on a two-wheeled bicycle, refers to the use of cycles for transportation, recreation, exercise, or sport. Cycling enthusiasts are known as "cyclists," "bicyclists," or "bikers." In addition to riding a two-wheeled bicycle, "cycling" also refers to using a recumbent bike or other comparable human-powered vehicles (HPVs), such as a unicycle, tricycle, or quadricycle.
Since their invention in the 19th century, bicycles have grown to almost one billion in number globally. In many regions of the world, especially in heavily populated European towns, they are the main form of transportation. For short to medium distances, cycling is widely regarded as an effective and efficient means of transportation.
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A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work is done?
Answer:
\(\boxed {\boxed {\sf 157.5 \ Joules }}\)
Explanation:
Work is equal to the product of force and distance.
\(W=F*d\)
The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.
\(F= 45 \ N \\d= 3.5 \ m\)
Substitute the values into the formula.
\(W= 45 \ N * 3.5 \ m\)
Multiply.
\(W= 157.5 \ N*m\)
1 Newton meter is equal to 1 Joule Our answer of 157.5 N*m equals 157.5 J\(W= 157.5 \ J\)
157.5 Joules of work are done on the crate.
Tanias little sister sits 1.2m from the pivot of a see-saw. Her mass provides a force of 200 N. Tania pushes down on the other end of the see-saw to make it balance. The maximum pushing force she can provide is 100 N. How far from the pivot must tania push to make the see-saw balance?
The distance at which Tania must push to make the see-saw balance is 2.4 m.
For the see-saw to balance, the moment due to Tania's little sister's weight,M must balance the moment due to Tania's push, M'.
Moment of a ForceThe moment of a force, M is the product of the force, F and its perpendicular distance from the point of action, d.
Thus M = Fd
Let
W = Tania's little sister weight = 200 N, d = distance of Tania's little sister from pivot = 1.2 m, F = Tania's push force = 100 N and L = distance of Tania's force from pivot.Since both moments are equal for the see-saw to balance,
M = M'
Wd = FL
So, making L subject of the formula, we have
L = Wd/F
Substituting the values of the variables into the equation, we have
L = 200 N × 1.2 m/100 N
L = 2 × 1.2 m
L = 2.4 m
So, the distance at which Tania must push to make the see-saw balance is 2.4 m.
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What questions do you still have about supermassive black holes after watching this Ted Talk? Do you feel that you have a deeper understanding of what they are and why they are important, like was asked of you in the third question? Explain and discuss.
After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.
While the speaker did mention that these black holes are responsible for the creation of galaxies, I wanted to know more about how this process works and why it is so important.Despite these questions, I do feel that I have a deeper understanding of supermassive black holes and their importance.From the Ted Talk, I learned that supermassive black holes are some of the largest objects in the universe and are essential for the formation of galaxies. I also learned that these black holes are incredibly powerful and have the ability to affect the trajectory of stars and planets.Overall, I think that the Ted Talk did a great job of explaining supermassive black holes in a way that was easy to understand. While there were still a few questions that I had after watching the video, I feel that I now have a better grasp of what supermassive black holes are and why they are so important.For such more question on supermassive
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28,800 C of charge flow through a lamp every hour. Calculate the current used by this lamp
This lamp's estimated current consumption is 8 amperes.
What is electric current ?Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.
Given information:
amount of charge flowing through the lamp, Q = 28800 C;
The charge flow time was t = 1 hour = 3600 seconds.
Hence, the current passing through the bulb as a result.
I = Q/t
= 28800/3600 ampere,
= 8 ampere
Therefore, this lamp consumes 8 amperes of current.
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a battery made up of two cells joined in series supply current to an external resistance of each cell is 0.6v and 3 ohms respectively. calculate 1 the current flowing in the external resistance 2 the thermal potential difference 3 the lost voltage
Answer:
We have a battery here, composed of two cells joined in series, which is supplying current to an external resistance. The voltage of each cell is given as 0.6 volts and the resistance is 3 Ohms. In order to solve the problem, we need to calculate three things: the current flowing in the external resistance, the thermal potential difference and the lost voltage.
First, let's calculate the current flowing in the external resistance. Using Ohm's Law, we can find the current as I = V/R, where V is the total voltage of the battery (i.e. 2*0.6=1.2V) and R is the external resistance, which is given as 3 Ohms. Therefore, I = 1.2/3 = 0.4 amps.
Next, let's calculate the thermal potential difference. This is the amount of heat generated by the current flowing through the external resistance, and is given by the formula P = I^2*R, where P is the power, I is the current, and R is the resistance. Plugging in the values, we get P = 0.4^2*3 = 0.48 watts. Since we know that power is equal to voltage times current (P = VI), we can rearrange the formula to get V = P/I, which gives us V = 0.48/0.4 = 1.2 volts.
Finally, we need to calculate the lost voltage. This is the voltage drop that occurs across each cell due to internal resistance. We can use the formula V_lost = I*R_int, where R_int is the internal resistance. Since we know the current and the resistance of the external load, we can use the total voltage of the battery to find the internal resistance. Recall that the total voltage of the battery is 1.2V. Therefore, V_lost = I*R_int, or R_int = V_lost/I. We know that the voltage drop across each cell is equal, so we can divide the lost voltage by 2 to get the voltage drop across each cell. Therefore, V_cell = V_lost/2 = (0.4)*(R_int/2). Plugging in the values, we get V_cell = 0.4*(1.2-0.4*3)/2 = 0.06 volts.
In summary, the current flowing in the external resistance is 0.4 amps, the thermal potential difference is 1.2 volts, and the lost voltage across each cell is 0.06 volts.
on a wet road, you would need to adjust your speed to _____ slower than normal.
a. 5-10 mph
b. 20-30 mph
c. 40-50 mph
On a wet road, you would need to adjust your speed to 5-10 mph slower than normal.So option a is correct.
On a wet road, you should adjust your speed to ensure that you can drive safely. This is because water causes tyres to lose traction with the road. If you increase your speed on a wet road, you'll have less control over your vehicle. When the road is wet, your vehicle's tyres may not be able to grip the road as well as they would on a dry road.When driving on wet roads, you should maintain a safe distance between your vehicle and the car in front of you. This provides you with enough space to stop safely if the car in front of you stops suddenly.In addition, when driving on wet roads, it's best to avoid sudden steering or braking movements. This will cause your car to skid. Therefore, you should slow down and move more gently on a wet road, and always adjust your speed to 5-10 mph slower than normal.Therefore option a is correct.
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Which describes the greenhouse effect? 1. Earth continues to get warmer over time because it is slowly moving closer to the sun. 2. Earth's atmosphere blocks the sun's ultraviolet light. 3. Pollution gets into the air, causing trees to not get enough oxygen. 4. Energy given off by earth is reflected off of earth's atmosphere back down to the surface.
Answer: The green house effect is best described by option 4 (Energy given off by earth is reflected off of earth's atmosphere back down to the surface).
Explanation:
The green house effect can be described as the energy given off by earth is reflected off of earth's atmosphere back down to the surface.
When energy from the sun passes through the atmosphere, some are absorbed which keeps the earth surface warm. While the rest is reflected back largely by cloud.
The energy which is emitted from the earth surface is called the infrared radiation. Some of the infrared radiation passess through the atmosphere but most is absorbed and re- emitted in all directions by the greenhouse gas molecules and clouds. This effect warms the earth surface and the lower atmosphere. Therefore this statement (Energy given off by earth is reflected off of earth's atmosphere back down to the surface) is correct about greenhouse effect.
For the greenhouse effect to occur, greenhouse gas molecules are mostly needed. Examples of these gases include:
--> Carbon dioxide (CO2),
--> Water vapor (H2O), and
--> Methane (CH4)
Over the years, the excessive human activities has lead to increase in the greenhouse gas molecules which has negatively affected the greenhouse effects.
1) An average soccer ball has a mass of .4 kg. If a soccer ball is kicked with a force of 750 Newtons, what is the acceleration of the soccer ball after it has been kicked?
2) If a tiger runs at a speed of about 12.3 m/s, how far will it travel in 25 seconds?
Answer:
Explanation:
#1 uses Newton's 2nd Law: F = ma so filling in:
750 = .4a and
a = 1875 m/s/s
#2 uses d = rt so
d = 12.3(25) and
d = 307.5 m
with what constant velocity would you have to push or pull the rod in order to make the magnetic force zero
Energy and Power Due to Motional Electromotive Force. Emf may be prompted in primary ways: Due to the movement of a conductor withinside the presence of a magnetic field. Due to the extrude withinside the magnetic flux enclosed via way of means of the circuit.
The length of the voltage may be various through 3 factors: The length of the magnetic discipline. The greater flux strains there are, the greater flux strains there are for the conductor to cut.
The lively period of the conductor. The velocity at which the conductor passes thru the discipline. Moving the bar to the proper decreases the vicinity of the loop, reducing the flux.
The caused modern need to generate a discipline out of the page. This calls for a counter-clockwise modern. The flux thru the loop is converting, so the loop attempts to oppose the alternate. The flux is converting due to the fact the bar is moving, converting the place of the loop. To oppose the alternate the loop makes the bar gradual down.
Thus the velocity (and the brought on emf and current) lower exponentially to zero.
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if quasars are at the distances most astronomers believe they are, then (for the most luminous ones) their luminosities must be:
Like the combined luminosity of a hundred trillion (1014) Suns.
What is the luminosity of the most powerful quasars?A new quasar with a 12 billion solar mass central black hole and 430 trillion solar luminosity was found by the Peking University Department of Astronomy at a distance of 12.8 billion light years from the Earth. This quasar, driven by the most massive black hole then known to exist, is the most brilliant one to be found in the early Universe. The finding of this quasar, designated SDSS J0100+2802, represents a significant advancement in our understanding of the evolution of quasars, the most potent cosmic phenomena, from their inception nine hundred million years after the Big Bang. On February 26, 2015, the leading scientific publication Nature reported on this discovery.To learn more about quasars, refer to
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DESPERATE!! WILL GIVE BARINLIST AND THANKS
Many farmers harvest their crops in the fall and then let the leftover plant material stay on the ground over winter. How does this help prevent erosion?
Answer:
it grabs unto soil and keeps it clamped together it prevents this makes the soil harder to wash away
Answer:
When the leftovers are left in the autumn, they have two purposes:
- Preventing erosion; the roots remain in the ground, so they hold it tightly till the next planting of the crops.
- Fertilizing the soil with natural material; the roots will not rot quickly in the colder period of the year, but will start rotting much faster in the spring, thus they will enrich the soil.
Dry steam at 100° is bubbled into 500g of water originally at 20° . what will be the temperature of water after 30g of steam has condensed .(Specific latent heat of steam=2.26×10^6Jkg,specific heat capacity of water =4200Jkgk)
The temperature of the water after 30g of steam has condensed will be approximately 52.14°C.
To solve this problem, we need to consider the energy transfer that occurs when steam condenses into water. The energy released by the condensing steam will be absorbed by the water, resulting in a temperature change.First, let's calculate the energy released when 30g of steam condenses. The specific latent heat of steam is given as 2.26 × 10^6 J/kg, so the energy released by 30g of steam can be calculated as:
Energy released = (30g) × (2.26 × 10^6 J/kg) = 6.78 × 10^7 J
Next, we need to calculate the energy required to raise the temperature of the water from 20°C to the final temperature. The specific heat capacity of water is given as 4200 J/kgK, and the mass of the water is 500g. Therefore, the energy required can be calculated as:
Energy required = (500g) × (4200 J/kgK) × (final temperature - 20°C)
Since the energy released by the steam is equal to the energy required by the water, we can set up the equation:
6.78 × 10^7 J = (500g) × (4200 J/kgK) × (final temperature - 20°C)
Now, we can solve for the final temperature:
(final temperature - 20°C) = (6.78 × 10^7 J) / ((500g) × (4200 J/kgK))
(final temperature - 20°C) = 32.14°C
final temperature = 32.14°C + 20°C
final temperature ≈ 52.14°C
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list the four possible subshells in the quantum-mechanical model.
S, P, D, and f are the four potential subshells in quantum mechanical theories. The angle momentum quantum number, l, is represented by these letters in numerical form.
What is subshells?A subshell is a group of states that make up a shell and are identified by the azimuthal quantum number, l. Subshells s, p, d, and f are represented by the values l = 0, 1, 2, and 3, respectively. The equation 2(2l + 1) states how many electrons can fit into a subshell at once.
The circular routes that electrons take in an atom's shells as they circle its nucleus. (In line with the Bohr Model). The primary quantum number, n, serves as a representation of the shells. Additionally, each shell is divided once more into many subshells.
Four subshells are present: s, p, d, and f.
For instance, the first shell has just one sub-shell, which is s.
There are two sub-shells in the second shell: s and p.There are three sub-shells in the third shell: s, p, and d.The remaining shells are made up of all four subshells: s, p, d, and f.
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Erin said that when you are standing in front of a fire you are warm because you release the coolness of your body to the heat of the fire.
Chris said that when you are standing in front of a freezer with the door open you feel cool because the air from the freezer is being transferred to your body.
Who has made the accurate statement regarding heat transfer?
Both Erin and Chris are correct.
Erin is correct.
Chris is correct.
Neither Erin nor Chris are correct.
third down, chris is correct
A cart at rest starts to move from its initial position by an external force F. Find its acceleration in m/s^2 when it has moved 0.1 m when m=20 kg, F=100 N, k=1000 N/m.
a. 0.1
b. 0.025
c. 0.25
d. None of the above
The Acceleration experienced by cart is Option (a) 0.1m/s².
Consider the fact that the vector of acceleration points in the same general direction as the velocity vector change.
This means that whether you add to or subtract from the velocity depends on the direction of the acceleration.
According to mathematics, a negative acceleration indicates that you will reduce the velocity's current value, and a positive acceleration indicates that you will increase it.
If the velocity was already negative to begin with, subtracting from it could make an object move faster because the magnitude would grow.
\(v^2-u^2=2as\)
To find acceleration rearranging the terms of equation.\(\frac{v^2-u^2}{2s} =a\)
F=ma
a=F/m
=100/20
=5m/s²
Comparing and finally A=1/a=0.1m/s²
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An object is pulled northward at 20 N and southward at 15 N. What is the direction and force of the object?
Answer:
It moves northward at 5N
Explanation: