Put these atoms in order from most positive overall charge to least positive overall charge.swap_vertAtom A: 14 protons, 16 electronsswap_vertAtom B: 24 protons, 19 electronsswap_vertAtom R: 26 protons, 24 electrons

Explanation:

Simply multiply the # of moles of O2 by a molar ratio to give the # of moles of MgO:

#moles O2 × (2 mol MgO/1 mol O2) = # moles of MgO

where the quantity inside the parenthesis is the molar ratio between MgO and O2.

The final concentration of the reactant of a first order reaction can be determined from the rate constant equation. The concentration of ammonium carbonate after 39 s will be 0.003 M.

Rate constant of a reaction is the rate of reaction when one molar concentration of the reactant is involved in the reaction. The expression for the rate constant k for first order reaction is :

k = 1/t ln (C0/Ct)

Where C0 be the initial concentration and Ct be the concentration after t seconds.

Given that C0 of ammonium nitrate = 0.957 M

rate constant = 0.196 /s

t = 39 s.

The concentration after 39 seconds is calculated as follows:

0.196 /s = 1/39s ln (0.957 M / Ct)

Ct = 0.957 / (ln⁻¹ (0.196 × 39))

    = 0.003 M.

Therefore, the concentration of ammonium carbonate after 39 seconds will be 0.003 M.

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Answer:

0.0447 M.

Explanation:

We'll begin by calculating the molarity of the diluted solution of the first calibration standard solution. This can be obtained as follow:

Molarity of stock solution (M1) = 0.185 M

Volume of stock solution (V1) = 30.8 mL

Volume of diluted solution (V2) = 100 mL

Molarity of diluted solution (M2) =?

M1V1 = M2V2

0.185 × 30.8 = M2 × 100

5.698 = M2 × 100

Divide both side by 100

M2 = 5.698 / 100

M2 = 0.05698 M

Therefore, the molarity of the diluted solution of the first calibration standard solution is 0.05698 M

Finally, we shall determine the molarity of the second calibration standard solution as follow:

Molarity of first calibration standard solution (M1) = 0.05698 M

Volume of first calibration standard solution (V1) = 78.5 mL

Volume of second calibration standard solution (V1) = 100 mL

Molarity of second calibration standard solution (M2) =?

M1V1 = M2V2

0.05698 × 78.5 = M2 × 100

4.47293 = M2 × 100

Divide both side by 100

M2 = 4.47293 / 100

M2 = 0.0447 M

Therefore, the molarity of the second calibration standard solution is 0.0447 M.

Answer:

2. +7

Explanation:

The oxidation state of Cl in `HClO_(4)` is +7.Apr 17, 2022

3ans. CrS+2No3 --) 2No+So4+cr^3+

Cr=1 Cr=1

S=1 S=1

N=1=2 N=1=2

O=3=6 o=5=6

now that is how it look and it is not balanced in oxygen so add 2 in the front of No3.

it will look something like this 2NO3. even if u add 2 in the fornt it is not balance so add again 2 in the No in second and it will look like this 2NO.

so now it is blance.

The de Broglie wavelength of the ball bearing is approximately 1.004 x 10^-35 meters.

According to de Broglie's equation, the de Broglie wavelength (λ) of a particle is given by:

λ = h / p

where

h is Planck's constant (6.626 x 10^-34 J s) and

p is the momentum of the particle.

The momentum (p) of the ball bearing can be calculated using the formula:

p = m * v

where

m is the mass of the ball bearing and

v is its velocity.

Substituting the given values, we get:

p = 0.02 kg * 330 m/s = 6.6 kg m/s

Now, we can calculate the de Broglie wavelength (λ) of the ball bearing as follows:

λ = h / p = 6.626 x 10^-34 J s / 6.6 kg m/s = 1.004 x 10^-35 m

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The equation that relates A and W, considering the desired 15% acetic acid concentration, is 3W = 2.55M.

The equation A = (3/17)W represents the relationship between the mass of acetic acid (A) and the mass of water (W) in the mixture. It states that the mass of acetic acid is equal to three seventeenths (3/17) of the mass of water.

Since the company wants the acetic acid to be 15% of the total mass of the mixture, we can set up another equation to represent this requirement. Let M be the total mass of the mixture. The mass of acetic acid (A) is 15% of the total mass, so we have A = 0.15M.

Now we can substitute A in terms of W from the first equation into the second equation: (3/17)W = 0.15M. We can simplify this equation by multiplying both sides by 17 to get 3W = 2.55M.

This equation allows the company to calculate the mass of water (W) required for a given mass of acetic acid (A) to maintain the desired concentration in the mixture.

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O2 is the limiting reagent and yields 20.4g of CO2.

Describe limiting reagent

The limiting reactant, also known as the limiting reagent, is the reactant that is used first during a chemical reaction, hence restricting the amount of product that can be produced.

2C₂H₂ + 5O₂   →  4CO₂ + 2H₂O

Quantity of C2H2 moles:

Moles equal mass divided by molar mass.

13.7 g/26.04 g/mol is the number of moles.

= 0.526 mol.

O2 moles are calculated using the formula: moles = mass / molar mass.

18.5 g/32 g/mol = the number of moles

= 0.578 mol

Produced CO2 mass:

Number of moles times molar mass equals mass.

Mass = 0.4622 mol at 44 g/mol

Mass = 20.328 g

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H2SO4(aq)+NaOH(s)----->NA2SO4 + H20

When acid and base reaction takes place, it will form salt formation takes place. I.e., neutralization reaction. H₂SO₄+2NaOH→ Na₂SO₄+ 2H₂O.

A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products.

H₂SO₄ is an acid and NaOH is a base. Acid react with base to form salt and water. Salt will be neutral charge and net ionic charge is zero.

Neutralization takes place when, complete dissociation takes place. If any partial dissociation, it will form acidic salt or neutral salt.

Thus complete dissociation neutral reaction is

H₂SO₄+2NaOH→ Na₂SO₄+ 2H₂O.

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There are 237. 5 g of Sulfur,S in 475 g of SO2?

From the question, we can say that

Therefore,

The molar mass for SO2 = 32 + (16 × 2) g/mol  = 64 g/mol

Now,

If 1 mole of SO2 contains 1 mole of S

Then 64 g of SO2, will contain 32g of S;

Such that

475 g of SO2 will give { \(\frac{ 32g of S) ( 475 g of SO2)}{64 of SO2}\) }  = 237. 5 g of Sulfur.

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2 moles of ZnO are produced if 1 mole of Zn and 2 moles of \(O_2\) is required.

A mole is defined as 6.02214076 × \(10^{23}\) of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Balanced equation:

\(2 Zn + O_2\) → \(2 ZnO\)

For 2 moles of Zinc, we need 1 mol of Oxygen to produce 2 moles of Zinc oxide

For 1 mole Zn, we need 2 mol \(O_2\) to produce 2 moles ZnO only.

Hence, 2 moles ZnO is produced.

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Answer: d. Arrangement of grains

Explanation:

Edge:)))

Answer:

Explanation:

Bond angles in BH3 are greater than the bond angles for NH3 because BH3 have three electron clouds that bond to one central atom Boron. Each clods have electrons that bond between Boron and Hydrogen atom. The three electrons cloud attach to Central atom B and adopt a position which make them to form triagonal planar geometry making the angles between them to be bigger.

But as for NH3, it has extra lone pairs making it four electron clouds which form tetrahedral geometry. The extra lone pair occupy space making the angles between the bond to be reduced.

Answer:

24.80°C

Explanation:

hope it helps...!!!

The number of the atoms that should be the numerator is 6.02 * 10^23 atoms.

We have to note that the conversion factor is the factor that can be used in the conversion of one unit to the other. We have to note that if we are able to change the unit then we can be able to make the conversion.

We have to note that the Avogadro's number is the number of atoms that we can find in one mole of a substance and it has a value of about 6.02 * 10^23 atoms in the atom of magnesium.

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The magnetic quantum number (ml) represents the orientation of the orbital in three-dimensional space the only possible value of the magnetic quantum number ml for a 1s electron is 0.

Quantum is the smallest possible unit of a physical quantity, such as energy or momentum. It is a fundamental concept in quantum mechanics, which is the branch of physics that deals with the behavior of matter and energy at the atomic and subatomic level.

The idea of quantization was first proposed by Max Planck in 1900, when he discovered that energy is emitted and absorbed in discrete units called "quanta" when studying the behavior of light and blackbody radiation. Later, this idea was extended to other physical quantities, such as the momentum and position of particles.

According to quantum mechanics, the behavior of particles and systems cannot be fully described using classical mechanics, which assumes that particles have definite positions and velocities at all times. Instead, the behavior of particles and systems is described using wave functions, which represent the probability of finding a particle at a given position and time.

The principles of quantum mechanics have important applications in many areas of physics, including atomic and molecular physics, condensed matter physics, and particle physics. They are also the basis.

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The most likely lead to more n2o emissions is fertilization of agricultural fields.

What is greenhouse gas?

A gas that produces the greenhouse effect by both absorbing and emitting radiant energy in the thermal infrared range is referred to be a greenhouse gas. The five main greenhouse gases in the atmosphere of Earth are ozone, carbon dioxide, methane, and water vapor.

In addition to being 300 times more powerful than carbon dioxide, nitrous oxide also thins out the ozone layer. Reducing it could have a quicker and more dramatic effect on global warming since it also has a shorter life cycle.

Agriculture, particularly fertilized soil and animal dung, is the main source of nitrous oxide, making it more difficult to control. "It is possible to consider limiting carbon dioxide, methane, and other substances. But nitrous oxide is mostly a problem with food production.

Therefore, the most likely lead to more n2o emissions is fertilization of agricultural fields.

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Answer:

a

Explanation:

Answer:

≅ 0.240 grams (3 sig. figs.)

Explanation:

Rxn:   CaCO₃  +          2HCl              => CaCl₂ + H₂O + CO₂

Given:    ?g          45.67ml(0.105M)

                            = 0.04567L x 0.105 mole/L

                            =  0.0048 mole HCl

Rxn ratio for CaCO₃ to HCl is 1:2

∴ moles CaCO₃ consumed = 1/2 of moles HCl used

=> 1/2(0.0048)mole CaCO₃ used = 0.0024 mole CaCO₃

mass CaCO₃ = 0.0024 mole CaCO₃  x  100.09 grams CaCO₃/mole CaCO₃

= 0.23998 grams CaCO₃ (calculator answer)

≅ 0.240 grams (3 sig. figs.)

The International Union of Pure and Applied Chemistry is abbreviated as IUPAC. The International Union of Pure and Applied Chemistry (IUPAC) is a worldwide organization that represents researchers in chemistry and associated disciplines and technologies.

IUPAC's overarching aim is to bring together the global community of chemists and provide a forum for advancement, cooperation, and the sharing of scientific study and knowledge.

IUPAC has created a worldwide standardized system of nomenclature to provide labels for compounds in order to improve scholarly collaboration. The IUPAC naming system assigns a distinct and unambiguous term to each organic compound and allows for easy correlation with other compounds designated in the system.

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Answer: The situation was Alexander Fleming made an experiment showing that the fungus produced a chemical that could kill bacteria. The scientific knowledge was based off Fleming's work, scientists produced the first antibitoic drugs.

It should reanalyze the data to determine whether their results contradicted your hypothesis if the experiment's findings did not support it. So shouldn't change the experiments, observations, or both in order to get results that support the theory.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

If the facts continually contradict the hypothesis, it is obvious that the hypothesis is not a viable explanation for the phenomenon you are examining. The proposed explanation is disproved, and we now look for a fresh hypothesis to explain the experimental results.

If the results confirm the prediction, the hypothesis is supported. Results can be used to disprove the hypothesis if the prediction was not confirmed by the data. By monitoring data and creating a new hypothesis using the new facts, you might need to come up with new questions. Make a finding and a forecast.

Thus, It should reanalyze the data to determine whether their results contradicted your hypothesis if the experiment's findings did not support it.

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Perhaps you like the appearance of rocks and boulders but prefer a material that stays cool in the desert heat. In this case, concrete or travertine should be your top picks. These materials have a high thermal mass and absorb the coolness of the earth below rather than the hot sun overhead

Sometimes you like how rocks and boulders look, but you'd rather have something that keeps cool in the hot desert. In this circumstance, limestone or concrete ought to be your top choices.

Deserts are incredibly arid places where well-adapted flora and animals can be found. Deserts may be divided into four basic categories are hot and dry, semi-arid, coastal, and cold.

The majority of specialists concur that a desert is any region of land with annual precipitation totals of less than 25 cm (10 inches). In a desert, evaporation frequently much outweighs yearly precipitation. Water is scarce for plants and other living things in all deserts.

Thus, Due to their large thermal mass, these materials absorb the cooling of the earth below rather than the heat from the sun above. Something that keeps cool in the hot desert.

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Answer:

Option H

Explanation:

We can get the temperature of the gas by applying ideal gas law,

PV = nRT

Here, P = Pressure of the gas

V = Volume of the gas

n = Number of moles

R = Gas constant

T = Temperature

By substituting the values in the given equation,

5.40 × 120 = 4 × 0.0821 × T

648 = 0.3284T

T = \(\frac{648}{0.3284}\)

T = 1973.20

   ≈ 1973 K

Therefore, temperature of the gas is 1973 °K

Option H will be the answer.

The molecular formula for the compound is 3 times the empirical formula NO₂, which gives us N₃O₆.

6. In the molecular formula for a compound with an empirical formula of NO₂ and a molar mass of 138.015 g/mol,

The empirical formula tells us the simplest whole-number ratio of atoms in the compound, which in this case is NO₂. The molar mass of the empirical formula NO₂ can be calculated by adding the atomic masses of nitrogen (N) and two oxygen (O) atoms:

Molar mass of NO₂ = (1 × atomic mass of N) + (2 × atomic mass of O)

Molar mass of NO₂ = (1 × 14.01 g/mol) + (2 × 16.00 g/mol)

Molar mass of NO₂ = 46.01 g/mol

Molecular formula units = Molar mass of the compound / Molar mass of the empirical formula

Molecular formula units = 138.015 g/mol / 46.01 g/mol

Molecular formula units ≈ 3

7. a. To determine the empirical formula of nicotine given the mass percentages of carbon (C), hydrogen (H), and nitrogen (N), we can assume a 100 g sample of nicotine.

Mass of C in 100 g of nicotine = 74.1 g

Mass of H in 100 g of nicotine = 8.6 g

Mass of N in 100 g of nicotine = 17.3 g

To find the moles of each element, divide the mass by their respective atomic masses:

Moles of C = 74.1 g / atomic mass of C ≈ 74.1 g / 12.01 g/mol ≈ 6.17 mol

Moles of H = 8.6 g / atomic mass of H ≈ 8.6 g / 1.008 g/mol ≈ 8.53 mol

Moles of N = 17.3 g / atomic mass of N ≈ 17.3 g / 14.01 g/mol ≈ 1.23 mol

To obtain the simplest ratio between the elements,  divide the number of moles by the smallest number of moles, which in this case is 1.23 mol:

C ≈ 6.17 mol / 1.23 mol ≈ 5

H ≈ 8.53 mol / 1.23 mol ≈ 7

N ≈ 1.23 mol / 1.23 mol ≈ 1

Therefore, the empirical formula of nicotine is C₅H₇N.

b. To determine the molecular formula of nicotine, its molar mass, which is given as approximately 160 g/mol.

The empirical formula of nicotine is C₅H₇N, with a molar mass of:

(5 × atomic mass of C) + (7 × atomic mass of H) + (1 × atomic mass of N)

(5 × 12.01 g/mol) + (7 × 1.008 g/mol) + (1 × 14.01 g/mol)

60.05 g/mol + 7.056 g/mol + 14.01 g/mol

≈ 81.116 g/mol

To find the molecular formula,  the molar mass of nicotine (160 g/mol) by the

Molecular formula ratio = 160 g/mol / 93.131 g/mol

≈ 1.717

Therefore, the molecular formula of nicotine is 2 times the empirical formula: C₁₀H₁₄N₂.

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Answer:

Commercial salt is manufactured from rock salt, as well as from seawater and other natural and artificial brines.In solution mining, water is pumped into the underground rock salt deposits to create brine that is then pumped back out to the surface. The brine is then evaporated in huge evaporating vessels to make the familiar white salt. This salt can be used in industry, by food manufacturers and, of course, at the table.

Answer:

Explanation:

1.08kg/50.5 cm^3(1000g/kg)=21.386 g/cm^3

Answer:

\(\boxed {\boxed {\sf 21.4 \ g/cm^3}}\)

Explanation:

We are asked to find the density of an object.

The density of a substance is its mass per unit volume. It is calculated by dividing the mass by the volume.

\(\rho= \frac{m}{v}\)

The mass of the object is 1.08 kilograms. The object displaced 50.50 cubic centimeters of water, so this value is its volume.

We are asked to give the density in grams per cubic centimeter, so we must convert the mass. There are 1000 grams in 1 kilogram. Set up a conversion factor.

\(\frac {1000 \ g}{1 \ kg}\)

Multiply by the given mass: 1.08 kg

\(1.08\ kg *\frac{1000 \ g }{ 1\ kg}\)

The units of kilograms cancel.

\(1.08*\frac{1000 \ g }{1}\)

\(1.08*{1000 \ g } = 1080 \ g\)

Now we know the mass in grams and the volume:

Substitute the values into the density formula.

\(\rho= \frac{1080 \ g }{50.50 \ cm^3}\)

Divide.

\(\rho= 21.3861386 \ g/cm^3\)

The original measurements of mass and density have 3 and 4 significant figures. Our answer must have the least number of significant figures, or 3.

For the number we found, that is the tenths place. The 8 in the hundredth place tells us to round the 3 in the tenths place up to a 4.

\(\rho \approx 21.4 \ g/cm^3\)

The density of the object is approximately 21.4 grams per cubic centimeter.