A spaceship is traveling at 0.7c when a laser beam is turned on, directed in the direction the ship is traveling.
According to the theory of relativity, the speed of light in a vacuum is always the same for all observers, regardless of their relative velocities.
The speed of the laser light is always c, which is the speed of light in a vacuum, approximately 3.0 x 10^8 meters per second. This is because the speed of light is constant and does not depend on the speed of the source (in this case, the spaceship).
Explanation:
In this scenario, the spaceship is traveling at 0.7c, which means that it is moving at a speed that is 0.7 times the speed of light. When a laser beam is turned on in the direction of the spaceship's motion, the speed of the laser light is still c, as measured by an observer on the spaceship. This is because the speed of light is always the same, regardless of the motion of the source or observer.
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A laser beam is activated and pointed in the direction of a spaceship that is moving at 0.7c.
The speed of light in a vacuum is constant for all observers, regardless of their relative velocities, according to the theory of relativity.
The speed of the laser light is always c, or around 3.0 x 108 metres per second, the speed of light in a vacuum. This is due to the fact that the speed of light is independent of the source's (in this example, the spacecraft's) speed and is always constant.
In this scenario, the spaceship is traveling at 0.7c, which means that it is moving at a speed that is 0.7 times the speed of light. When a laser beam is turned on in the direction of the spaceship's motion, the speed of the laser light is still c, as measured by an observer on the spaceship. This is because the speed of light is always the same, regardless of the motion of the source or observer.
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a certain amount of nobr(g) is sealed in a flask, and the temperature is raised to 350 k. the following equilibrium is established: nobr(g) uv no(g) 1 12 br2(g) the total pressure in the flask when equilibrium is reached at this temperature is 0.675 atm, and the vapor density is
The partial pressures of each species of the equilibrium are
NOBr = 0.39 atmNO = 0.19 atmVapour density = 2.219 g / L
Temperature = 350 K
Total pressure = 0.675 atm
Since volume of flask is constant and the mass is conserved,
Initial mass of NOBr = 2.219 g
1 mol NOBr = 109.92 g
Number of moles of NOBr = 2.219 / 109.92 = 0.02019 mol
Total number of moles at equilibrium is,
\(n_{total}\) = ( 0.02019 - x ) + x + 0.5 x
\(n_{total}\) = 0.02019 + 0.5 x
Acording to ideal gas equation.
\(n_{total}\) = P V / R T
\(n_{total}\) = ( 0.675 * 1 ) / ( 0.08206 * 350 )
\(n_{total}\) = 0.00662
Partial pressure of NOBr,
P = ( 0.02019 - x ) * 0.675 / ( 0.02019 + 0.5 x )
P = 0.39 atm
Partial pressure of NO,
P = x * 0.675 / ( 0.02019 + 0.5 x )
P = 0.19 atm
Partial pressure of Br₂,
P = 0.5 x * 0.675 / ( 0.02019 + 0.5 x )
P = 0.095 atm
Therefore, the partial pressures of
NOBr = 0.39 atmNO = 0.19 atmBr₂ = 0.095 atmThe given question is incomplete. The complete question is:
A certain amount of NOBr(g) is sealed in a flask, and the temperature is raised to 350 K. The following equilibrium is established:
NOBr(g) ↔ NO(g) + ½ Br2(g)
NOBr(g)↔NO(g)+½Br2(g)
The total pressure in the flask when equilibrium is reached at this temperature is 0.675 atm, and the vapor density is 2.219 g L^-1. Calculate the partial pressure of each species.
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An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg
Answer:
b 43 kg
Explanation:
mass doesn't differ from place to place.
but the weight may
Discuss the changes in magnitude of residual stress in a plasma sprayed coating as a function of changes in each of the following process parameters: (i) Size of the starting powder; and Sprayed particle impact velocity
Changes in the starting powder size and sprayed particle impact velocity affect the residual stress magnitude in a plasma-sprayed coating.
Plasma spraying is an established thermal spray technology that allows for the deposition of coatings of various materials on different substrates. Plasma-sprayed coatings are used for many applications, ranging from aerospace and energy production to biomedical and automotive industries. Residual stresses are one of the essential parameters affecting the properties and performance of plasma-sprayed coatings.In this context, this essay will discuss the changes in the magnitude of residual stress in a plasma-sprayed coating as a function of changes in the size of the starting powder and the sprayed particle impact velocity.
The residual stresses in a plasma-sprayed coating originate from thermal and mechanical processes taking place during the deposition process. The thermal cycle experienced by the substrate and coating depends on various parameters such as the spray process and material properties. As a result, residual stresses are induced within the coating during the deposition process.When starting powder size is altered, it can significantly influence the residual stresses in the coating. The size of the powder particles can directly affect the particle velocity, energy, and temperature when they interact with the plasma jet.
The powder size distribution affects the surface roughness and porosity of the coating, which further affects the residual stress. Hence, a larger starting powder size tends to increase the residual stress magnitude. In contrast, a smaller starting powder size tends to decrease the residual stress magnitude. Moreover, the sprayed particle impact velocity is another crucial factor that influences the residual stress magnitude.
When the velocity of the particle increases, the coating's residual stress magnitude increases due to the higher kinetic energy transferred to the substrate. In summary, changes in the starting powder size and sprayed particle impact velocity affect the residual stress magnitude in a plasma-sprayed coating.
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Somewhere you place a 7.5 kg pumpkin on a spring scale. If the scaled reads 12.5 N , what is the acceleration due to gravity at that location?
Answer:
1.667 m/s ^2
Explanation:
we use the formula F=ma
F= 12.5 N
m= 7.5 kg
a=?
F=ma
12.5= 7.5 x a
a= 12.5/7.5
a= 1.667 m/s^2
air expands from 3.5MPa and 100°C to 500kPa in an adiabatic expansion valve. For environmental conditions of 101.3kPa and 25°C, calculate the temperature change across the valve, and specific irre- versibility of the process.
The given information is as follows: Initial pressure and temperature of air, P1 = 3.5 MPa and T1 = 100°C
Pressure after adiabatic expansion, P2 = 500 kPa
Environmental pressure and temperature, P3 = 101.3 kPa and T3 = 25°C
The adiabatic process is a process in which no heat transfer takes place, and no thermal energy enters or leaves the system. For an adiabatic process, PVγ = constant where P is the pressure, V is the volume, γ is the ratio of specific heats and is equal to CP/CV.CP and CV are the specific heats of the gas at constant pressure and constant volume respectively.
Since there is no heat transfer, PVγ = constant can be written as P1V1γ = P2V2γwhere V1 and V2 are the initial and final volumes of the gas respectively.
Now, from the ideal gas equation PV = nRT,
we have V1 = nRT1/P1 and V2 = nRT2/P2
where n is the number of moles of the gas and R is the universal gas constant.
Substituting the values, P1V1γ = P2V2γ gives T2 = T1(P2/P1)^(γ-1)
Using the values of T1, T3, P1, P3, and γ = 1.4, the temperature change across the valve can be calculated as follows:
T2 = T1(P2/P1)^(γ-1)
= 373.15 K (500/3500)^(1.4-1)
= 260.7 K
The specific irreversibility of the process can be calculated using the following formula:
σ = T0/SΔS
where T0 is the environmental temperature, ΔS is the change in entropy of the system, and S is the total entropy generated during the process.
Since the process is adiabatic, there is no heat transfer, and hence, ΔS = 0.So,
σ = T0/SΔS
= T0/S(0)
= undefined (since division by zero is not possible)Therefore, the specific irreversibility of the process is undefined.
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A student pushes a 40 Kg cart with a force of 300 Newtons. What is its
acceleration?
Answer:
7.5 m/s2
Explanation:
F = ma
300 = 40 kg (a)
divide both sides by 40 to single out the variable a (acceleration)
300/40 = 7.5 m/s2
What is the name of the shuttle with 134 successful launches
International space station is the mission of NASA. It has launched 134 successful space missions.
What is International Space Station ?International space station is a huge place in the space but in the close orbit with all possible facilities for astronauts , scientists and others
What is NASA ?The National Aeronautics and Space Administration (NASA) is an acronym for the National Aeronautics as well as Space Administration. NASA was established as a division of the United States government on October 1, 1958. NASA is just in charge of all research and technology related to aviation and space in the United States.
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A student pulled a 100 kg cart up a ramp using a force of 150 N. By the time the cart reached the top of the ramp, it had gained 980 joules of potential energy. What happened to the work the student did by pulling the cart?
Answer:
Some of the work done on the cart became the cart’s potential energy, and some of the work was converted into heat by friction.
Explanation:
Here, some fraction of the work done by the student on the cart is converted to the potential energy of the cart it gained at the height.
What is work done ?Work done is the measure of the effectiveness of the force on making some displacement. It is the dot product of force and displacement. Work done like force is a vector quantity and have magnitude and direction.
When a force applied on a body results in a displacement, then it is said to be work is done on the body. The work done is numerically equal to the energy needed to displace the object.
Here, the force applied on the cart of 100 Kg results in a work done on the cart by pulling it to height. Where the energy equivalent to the work done is stored in the form its potential energy. The potential energy
p = mgh
Some fraction of work done is stored as this energy while the remaining probably lost into the surroundings.
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A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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mario watches his friends run the relay at a high school track meet on a warm, friday afternoon. jack was at the starting line, ready to take off. the starting gun boomed and jack took off. jack ran his part of the relay and handed his wooden baton off to azrial, who ran and handed the baton to juan. roberto finished the last stretch of the race. which type of energy was least likely to have been a part of the race?
Based on your question, the type of energy least likely to have been a part of the relay race is gravitational potential energy.
Based on the given scenario, it is clear that the race involves physical activity and requires energy to complete. The runners use their muscles to run and pass on the baton. In a relay race, the runners, such as Jack, Azreal, Juan, and Roberto, primarily use kinetic energy as they run and transfer the baton. Their muscles also utilize chemical energy from the food they consume to generate the needed energy for running.
However, gravitational potential energy, which is associated with an object's height and position, plays a minimal role in a flat relay race, as the runners are not significantly changing their height or position relative to the Earth during the run. Overall, the race is a great example of how energy plays a crucial role in physical activities and how different types of energy are used in different situations.
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describe how air resistance would affect a falling object
Answer:
With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down. How much it slows the object down depends on the surface area of the object and its speed
Explanation:
PLZ MARK AS THE BRAINLIEST
HAVE A GOOD DAY
: )
what are the things to consider in planning food for the family?
Answer:
tips to get you started
Make a menu. ...
Plan your meals around foods that are on sale. ...
Plan at least one meatless meal a week. ...
Check your pantry, refrigerator and freezer. ...
Enjoy grains more often. ...
Avoid recipes that need a special ingredient. ...
Look for seasonal recipes. ...
Plan to use leftovers.
Explanation:
sana po makatulong
PLEASE HELP!!
A swimmer starting from rest has a final velocity of 2.0 m/s after 20 seconds. What is her average acceleration?
O A. 18 m/s2
OB. 22 m/s2
OC. 0.10 m/s2
O D. 40 m/s2
Answer:
\(a=0.1\ m/s^2\)
Explanation:
Given that,
Initial velocity, u = 0
Final velocity, v = 2 m/s
Time, t = 20 s
We need to find the acceleration of the swimmer. The acceleration of an object is equal to the change in velocity per unit time. It can be given by :
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{2\ m/s}{20\ s}\\\\a=0.1\ m/s^2\)
So, her average acceleration of the swimmer is \(0.1\ m/s^2\).
How much is the velocity of a body when it travels 600m in 5 minutes?
answer
so unit of velocity is m/s
displacement=600m
5minutes should be converted to seconds
5×60=300 seconds
so,
velocity= displacement÷time
= 600m ÷300s
=2m/s or 2ms^-1
Answer:
2 m/s
Explanation:
we have given
distance traveled by body =600m
time taken = 5*60 =300 sec( si unit of time is second)
velocity =?
we know that
velocity =distance traveled/ time taken
=600/300
= 2 m/s
______ is a chemical reaction between an acid and a base that forms a salt and water. Group of answer choices Neutralization Dissociation Titration Ionization
Answer:
neutralization
Explanation:
this is because
acid + base ---> salt + water
Qsn 2 full question please?
Answer:
the work done by the worker in pulling the crate is 500 J, and the kinetic energy of the crate at the end of the 10 m distance is 292.13 J.
Explanation:
To solve the problem, we need to first resolve the applied force and the frictional force into their horizontal and vertical components. The horizontal component of the applied force is:
F_h = Fcos(30°) = 50cos(30°) = 43.3 N
The vertical component of the applied force is:
F_v = Fsin(30°) = 50sin(30°) = 25 N
The frictional force is acting in the opposite direction to the applied force, so its horizontal component is:
f_h = -F_f = -20 N
Since the crate is initially at rest, the net force on the crate is equal to the applied force minus the frictional force:
F_net = F_h + f_h = 43.3 - 20 = 23.3 N
The acceleration of the crate is given by Newton's second law:
F_net = ma
where a is the acceleration of the crate. Rearranging this equation, we get:
a = F_net/m = 23.3/30 = 0.78 m/s²
The work done by the worker in pulling the crate a distance of 10 m is given by:
W = Fdcos(θ)
where d is the distance pulled, and θ is the angle between the applied force and the displacement. In this case, θ = 0° since the force is applied horizontally. Therefore, the work done is:
W = Fd = 5010 = 500 J
The kinetic energy of the crate at the end of the 10 m distance is:
K = (1/2)mv²
where v is the final velocity of the crate. We can find v using the equation of motion:
v² = u² + 2as
where u is the initial velocity (zero), s is the displacement (10 m), and a is the acceleration (0.78 m/s²). Therefore:
v² = 0 + 20.7810 = 15.6
v = sqrt(15.6) = 3.95 m/s
Substituting this value of v into the equation for kinetic energy, we get:
K = (1/2)mv² = (1/2)30(3.95)² = 292.13 J
Therefore, the work done by the worker in pulling the crate is 500 J, and the kinetic energy of the crate at the end of the 10 m distance is 292.13 J.
Scientist in a lab are working with2 different types of mercury they know the different samples are different isotopes which propeetybof the isotopes must be different
Answer:
The atomic weight
Explanation:
The property of isotopes that must be different is the atomic weight.
Isotopes are generally referred to as atoms of the same element with the same atomic number (proton number) but different neutron numbers.
Since the atomic weight of an atom is the sum of proton and neutron, atomsof the same element with different number of neutrons will definitely have different atomic weight.
_____ is a measure of the force of gravity pulling down on an object. it is measured in newtons (N), the common unit for measuring force
By definition, Weight is a measure of the force of gravity pulling down on an object. it is measured in newtons (N), the common unit for measuring force.
Weight is called the action exerted by the force of gravity on the body.
The mass (amount of matter that a body contains) of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.
The formula that allows you to calculate the weight of any body is:
P = m×g
where:
P = weight measured in N. m = mass measured in kg. g = acceleration of gravity measured in m/s². The acceleration of gravity g is the same for all objects that fall due to gravitational attraction, regardless of their size or composition. For example, as an approximate value on Earth, g = 9.8 m/s².
Then, the weight of an object is the force of gravity on the object, that is, the weight will vary according to the force of gravity that acts on it. So the correct answer is:
Weight is a measure of the force of gravity pulling down on an object. it is measured in newtons (N), the common unit for measuring force.
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brainly.com/question/15566515?referrer=searchResults brainly.com/question/15271930?referrer=searchResults brainly.com/question/4735812?referrer=searchResultsWhich of the following planets or moons has an atmosphere consisting mainly of Hydrogen and Helium with some methane?
A) Venus
B) Saturn
C) Titan
D) Uranus
Saturn is the following planet or moon, and its atmosphere is primarily made of hydrogen with a small amount of methane.
The correct answer is B
What makes Saturn the best planet?The planet Saturn is incredibly large and its rings make it incredibly gorgeous. Amazing moons as Titan reside there as well. The Solar System's Saturn is arguably the most popular and stunning planet. Compared to the rings of other planets, Saturn's are much larger and easier to see.
Where could we possibly live?Then, only a year ago, researchers found a second Earth-like planet around Proxima Centauri, one of our nearest nearby stars. The best option we now have for maintaining human life is this planet.
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Can some one please explain how to read this and what the answer would be?
Answer:
4 to 5
Explanation:
You are boiling water to make pasta. How could you describe the pot, water, and pasta using physical properties?
The pasta and pot can be referred to as a Solid while the water is a liquid
when their physical forms are compared.
The pot is usually a metal because of its high heat conductivity and the
pasta is usually made from organic materials such as wheat, starch etc.
The water on the other hand should be colorless and odorless to avoid
ingesting pathogens.
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Hello!
I need your help
I have a friend who is in 5th grade, she doesn't know what force and motion is I wanna make her like a help page?
Can someone help me put stuff into the sheet?
Answer:
Explanation:
Force = something being pulled or pushed
Motion = what the object is doing, most likely moving
i think thats right
What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
a) 4. 1 atm
b) 5. 0 atm
c) 6. 4 atm
d) 1. 1 atm
The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
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50. A longitudinal wave is a wave in which particles vibrate perpendicular to the
direction of the flow of energy. ____________________
Longitudinal waves are those in which the displacement of the medium moves in the same plane as the wave's direction of travel.
In longitudinal waves, the motion of the individual medium particles is parallel to the direction of energy transit.
That means, the longitudinal waves are waves in which the particles move energy from one location to another by vibrating in the wave's path of propagation.
Waves such as sound waves, ultrasound waves, seismic P-waves, etc. are the examples of longitudinal waves.
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Assuming your skin temperature is 37. 2 C and the temperature of your surroundings is 23. 4C , determine the length of time required for you to radiate away the energy gained by eating a 335- C ice cream cone. Let the emissivity of your skin be 0. 915 and its area be 1. 27 m^2
T=___h
It would take approximately 4.4 hours for the person to radiate away the energy gained by eating the ice cream cone.
To calculate the time required for a person to radiate away the energy gained by eating an ice cream cone, we need to use the Stefan-Boltzmann law, which states that the rate of heat transfer from an object is proportional to the fourth power of its temperature and its surface area.
The formula is given as: Q/t = εσA(\(T^{4}\) - \(T0^{4}\))
where Q is the heat energy gained by eating the ice cream, t is the time taken to radiate it away, ε is the emissivity of the skin, σ is the Stefan-Boltzmann constant, A is the surface area of the skin, T is the skin temperature, and T0 is the temperature of the surroundings.
Plugging in the given values, we get: 335,000 J/t = 0.915 x 5.67 x \(10^{-8}\) x 1.27 x (\(373.2^{4}\) - \(296.4^{4}\))
Solving for t, we get t ≈ 4.4 hours.
Therefore, it would take approximately 4.4 hours for the person to radiate away the energy gained by eating the ice cream cone.
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Determine the Relative Humidity, Dew Point, and Lifting Condensation Level: 1. The temperature is 30∘F and it contains 3.5 g/kg of water vapor. 2. The temperature is 50∘F and it contains 5.70 g/kg of water vapor. 3. The temperature is 70∘F and it contains 3.5 g/kg of water vapor. 4. The temperature is 80∘F and it contains 5.60 g/kg of water vapor. 5. The temperature is 80∘F and it contains 11.56 g/kg of water vapor. 6. The temperature is 30∘F and the mixing ratio is 3.5. 7. The temperature is 70∘F and the mixing ratio is 8.32. 8. The temperature is 70∘F and the mixing ratio is 3.66. 9. The temperature is 80∘F and the mixing ratio is 17.59. 10. The temperature is 50∘F and the mixing ratio is 6.54.
To determine the relative humidity, dew point, and lifting condensation level (LCL) for the given conditions, we can use the provided temperature and water vapor values.
Here are the calculations for each scenario:
1. Temperature: 30°F, Water Vapor: 3.5 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
2. Temperature: 50°F, Water Vapor: 5.70 g/kg
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
3. Temperature: 70°F, Water Vapor: 3.5 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
4. Temperature: 80°F, Water Vapor: 5.60 g/kg
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
5. Temperature: 80°F, Water Vapor: 11.56 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
6. Temperature: 30°F, Mixing Ratio: 3.5
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
7. Temperature: 70°F, Mixing Ratio: 8.32 - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
8. Temperature: 70°F, Mixing Ratio: 3.66
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
9. Temperature: 80°F, Mixing Ratio: 17.59 - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
10. Temperature: 50°F, Mixing Ratio: 6.54
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
To calculate the relative humidity, dew point, and LCL, we require
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Why is an object’s mass, rather than its weight, used to indicate the amount of matter it contains?.
An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.
However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.
Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.
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Compare and contrast an earthquake and a tsunami.
Answer:
An earthquake is a trembling movement of the earth's crust. These tremors are generally caused by shifts of the plates that make up the earth's surface. ... A tsunami (pronounced soo-NAHM-ee) is a series of huge waves that occur as the result of a violent underwater disturbance, such as an earthquake or volcanic eruption.
Explanation:
Two parents, both heterozygous (Tt) and tall, are crossed to produce offspring. What are the possible genotypes and phenotypes of the offspring? What is the percentage chance of being homozygous?
Answer:
Look below
Explanation:
The possible genotypes of the offspring are: TT, Tt, and tt.
The possible phenotypes of the offspring are: tall and short.
The percentage chance of being homozygous can be calculated using a Punnett square. When the heterozygous parents are crossed, the possible genotypes of the offspring are:
| T | t
--|---|---
T | TT| Tt
t | Tt| tt
From the Punnett square, we can see that there is a 25% chance of the offspring being homozygous (TT or tt). This is because there are four possible outcomes and two of them result in a homozygous genotype (TT and tt).
If you take away an electron what about the atom changes.
Answer: cool things
Explanation:
Answer:
Unlike protons, electrons can move from atom to atom. If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.
Explanation: