Listed in the Item Bank are individual steps that need to be ordered. To find out more information about steps, some have more
details available when you click on them. Drag and drop the steps in the proper order by placing each in its corresponding open
rectangle. Be sure that the earliest step is placed next to the number 1.
Succession happens in predictable ways. Can you put the steps in order?
ITEM BANK: Move to Bottom
Grasses
Larger trees
Shrubs
Flowering plants
Small trees and shrubs
Soil formers
1
drag and drop answer here
N
drag and drop answethere
3
drag and drop ansvar here
4
6

The surface area of the small intestine is dramatically increased due to the presence of "villi and microvilli" on the luminal surface.

Microvilli are the structures that extend from the lining of the small intestine and maximize the area available for nutrient absorption.

Microvilli are most often found in the small intestine, on the surface of egg cells, as well as on white blood cells. Thousands of microvilli form a structure called the brush border that is found on the apical surface of some epithelial cells, such as the small intestines.

Microvilli are covered in the plasma membrane, which encloses cytoplasm and microfilaments. These cellular extensions do not have any cellular organelles present. Each microvillus has a dense bundle of cross-linked actin filaments which form the core of microvilli.

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Cell Biology: Prokaryotic and Eukaryotic Cells

Given their structure, cells can be classified in the following way:

Prokaryotic cells: Those that don't have a nucleus or other organelles delimited by a membrane. The member of the domains Bacteria and Archaea have this type of cell.

Eukaryotic cells: These kinds of cells have their genetic material inside a nucleus, which is membrane-bound, and it also has other organelles such as mitochondria and endoplasmic reticulum. This type of cell can be found in multicellular organisms such as animals and plants.

They are subdivided into animal cells, plant cells, and fungi cells.

Animal cells don't have a cell wall, while plant cells have a cell wall made of cellulose, and fungi cells have a cell wall made of chitin.

Given that the cell observed by the student has a nucleus and organelles but no cell wall, the cell is an animal cell, so A is the correct answer.

Answer:

Animal Cell

Explanation:

answer A is correct

The dna polymerase that is synthesizing the lagging strand stay bound to its template dna strand and coordinate with the dna polymerase on the leading strand is DNA polymerase on the leading strand attaches to DNA polymerase on the trailing strand.

DNA replication is the process of doubling the DNA chain assisted by DNA polymerase before mitosis or meiosis I in the S phase of the cell cycle. The DNA is made of two strands and each strand of the parent cell acts as a template for the production of complementary strands.

The lagging strand is the synthesized DNA strand and is located in the 5'→3' direction at the replication fork. During the replication process, nucleotides will be added to the end of the sugar from the Okazaki fragment with the help of DNA ligase enzymes. In order for the lagging strand to remain attached to the template DNA strand, the DNA polymerase on the leading strand attaches to the DNA polymerase on the trailing strand.

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Structure 1 is the "cell wall"

Cell wall functions are:-

1. Provide support and limited plasticity.

2. Prevent loss of water

3. Protects from insects and pathogens

4. Prevent over expansion caused by too much water

5.Keep the shape of the plant

6. Allow plants to grow to great heights.

Structure 2 is the "vacuole"

vacuole functions are as follows:-

1.The main function of vacuoles is the storage of many important molecules like amino acids, sugars, various organic acids, and some proteins.

2. In plants, the vacuoles are very large in size and filled with cell sap that helps to maintain the trugidity and rigidity of the cell.

Phytoplankton produces __________ of the oxygen we breathe.

Answer: ~50%

If a sperm cell of an organism contains 14 chromosomes, the number of chromosomes in an autosomal cell of this organism is 28.

Mitosis is a kind of cell division that produces two daughter cells with the same number of chromosomes as the parent cell.The two daughter cells will have 14 chromosome each if the mother cell had 14 chromosomes.

Humans typically have two copies of their 46 chromosomes, which are split into 23 pairs.One of the pairings is made up of two copies of chromosomes 14, one from each parent.

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Radiation is one of the methods used for sterilizing surfaces, medical supplies, and food products.

There are different types of radiation used for sterilization, depending on the specific application.The type of radiation is used to sterilize surfaces are Gamma rays and electron beams, they are commonly used for sterilizing surfaces.

Gamma rays are a type of ionizing radiation produced by the radioactive decay of atomic nuclei. They are highly penetrating and can kill bacteria, viruses, and other microorganisms.

Electron beams are streams of high-energy electrons produced by accelerators. They are also highly penetrating and can destroy microorganisms on surfaces.

Gamma radiation is commonly used for sterilizing food and medical supplies. It is highly effective at killing bacteria, viruses, and other microorganisms. Gamma radiation is generated from a radioactive isotope, such as cobalt-60 or cesium-137. The source is placed near the food or medical supplies to be sterilized, and the radiation penetrates the packaging and kills the microorganisms.

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Answer:

Photosynthesis

Explanation:

Photosynthesis is the process in which plants use carbon dioxide and water to make their food(the sugar), and in the process the also make oxygen that they don't need so they release it back into the atmosphere.

The vibrational motions have to change the dipole moment of the molecule. All molecules with 3 or greater atoms meet this criterion and are IR radiation absorbers.

IR radiation now no longer has sufficient strength to set off digital transitions as visible with UV. Absorption of IR is constrained to compounds with small power variations with inside the feasible vibrational and rotational states. For a molecule to take in IR, the vibrations or rotations inside a molecule have to reason an internet extrude with inside the dipole second of the molecule. The alternating electric area of the radiation (keep in mind that electromagnetic radiation includes an oscillating electric area and an oscillating magnetic subject, perpendicular to every other) interacts with fluctuations inside the dipole moment of the molecule. If the frequency of the radiation fits the vibrational frequency of the molecule, then the radiation may be absorbed, inflicting an alternate with inside the amplitude of molecular vibration.

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Answer: Glucose

Explanation:

Glucose is a type of Carbohydrate and it releases quick energy.

Answer:

Glucose

Explanation:

hope this help !!!!!!!!

Answer:

C.peat

Explanation:

When seedles plants die, the waterlogged soil slows the decay process. Over time, these decaying plants are compressed into a substance called peat

Answer:

the answer is part A

Explanation:

Answer:

D

Explanation:

Answer:  C. The hormone erythropoietin increases the production of red blood cells when oxygen levels are low best supports the statement that hormones are involved in the regulation of homeostasis.

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The phenotypic traits of pollen that would likely be selected to promote survival and fitness within an insect-pollinated flowering plant include characteristics that make the pollen more attractive to the insects that will transfer it from one plant to another.

This may include traits such as size, shape, color, scent, and sugar content. For example, larger pollen grains may be easier for insects to collect and transfer, while a particular color or scent may be more attractive to a certain species of insect pollinator.

Additionally, pollen with a higher sugar content may be more attractive to insects as a food source, potentially increasing the likelihood of successful pollination. Overall, the traits that are selected will likely depend on the specific insects that are the primary pollinators for the plant species in question.

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There are several types of alterations that can promote tumorigenesis. The following types of alterations that would NOT promote tumorigenesis are given below:a) Increased activation of PI3KIt is true that the increased activation of PI3K would promote tumorigenesis.

The PI3K/AKT/mTOR pathway is a major signaling pathway that is activated in cancer. This pathway is responsible for regulating cell proliferation, survival, and growth.b) Overexpression of BAX or BAKOverexpression of the BAX or BAK gene promotes apoptosis or programmed cell death, which is the opposite of what is needed to promote tumorigenesis.

Overexpression of BCL2 or BCLXL Overexpression of BCL2 or BCLXL genes prevents apoptosis or programmed cell death. In contrast, promoting apoptosis is one way to prevent cancer. Thus, overexpression of BCL2 or BCLXL would promote tumorigenesis.d) Defective CHK2 kinase (stress kinase) signalingCHK2 kinase plays a crucial role in cell cycle regulation.

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The areas of the earth that contain communities composed of organisms that are the product of convergent evolution are called analogous regions.

Convergent evolution refers to the phenomenon in which two distinct species that have distinct ancestral origins evolve similar characteristics to adapt to similar environments. In other words, animals that have no common ancestry can appear very similar as a result of the natural selection of their environment. For example, sharks, dolphins, and ichthyosaurs all have a streamlined body and fins adapted for swimming. Despite being unrelated, these species have adapted to similar environments through convergent evolution.

The analogous regions Analogous regions are the areas of the earth that contain communities composed of organisms that are the product of convergent evolution. Analogous regions are characterized by the presence of a particular habitat, which results in the evolution of similar characteristics in unrelated species that occupy the region. An example of analogous regions is the African and South American savannas, which have similar habitats that result in the evolution of similar characteristics in unrelated species.

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Among vertebrates, C. a few species of frogs, salamanders, and turtles can survive a long winter in a semi-frozen state.

While it is true that some species of frogs, salamanders, and turtles have the ability to survive winter in a semi-frozen state, not all species within these groups possess this adaptation. The ability to survive freezing temperatures largely depends on the specific adaptations and physiological mechanisms of each species.

For example, certain species of frogs, such as the wood frog (Rana sylvatica), and some species of salamanders, like the Eastern red-backed salamander (Plethodon cinereus), have the ability to tolerate freezing temperatures by utilizing cryoprotectants and entering a state of suspended animation. These adaptations protect their cells and tissues from ice damage.

Similarly, some species of turtles, including the painted turtle (Chrysemys picta), have developed strategies to survive freezing conditions. They can tolerate ice formation in their body cavities and prevent freezing of critical organs by altering their metabolism and utilizing physiological adaptations.

Therefore, while not all species within these groups exhibit the ability to survive in a semi-frozen state, a few species of frogs, salamanders, and turtles have evolved mechanisms to endure and survive winter conditions.

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The complete question is:

Among vertebrates, _______ can survive a long winter in a semi-frozen state.

A. all species of frogs

B. one species of frog

C. a few species of frogs, salamanders, and turtles

D. all species of amphibians and turtles

Answer:

1. Using the graph, describe the events that occur in the body during the first year of

HIV infection.

2. Describe what happens between the first year and the tenth year of infection.

3. Explain why the concentration of antibodies begins to decrease after nine years of

infection.

4. At what point on the graph does an infected person have AIDS?

5. Why does the number of HIV particles begin to level off after nine years?

6. How do you think the high rates of HIV transmission in humans might be related to the length of time it takes for the virus to develop into AIDS?

Answer:

To measure blood pressure, your doctor uses an instrument call a sphygmomanometer, which is more often referred to as a blood pressure cuff. The cuff is wrapped around your upper arm and inflated to stop the flow of blood in your artery.

Explanation:

Hope it helps you

The underwriting costs of a new issue do not represent a tax implication in the bond refunding decision.

The bond refunding decision involves refinancing existing bonds with new ones. When considering tax implications, certain factors need to be taken into account. The call premium, which is the amount paid to redeem the existing bonds before their maturity date, can have tax implications. The cost savings from lower interest rates can also have tax implications, as they can affect the deductibility of interest expenses. However, the underwriting costs of a new issue do not directly relate to tax implications. Underwriting costs are the fees associated with the issuance of new bonds, which are typically paid to investment banks or underwriters. These costs are not directly linked to taxes but rather represent expenses incurred in the process of issuing new bonds. Therefore, the correct answer is C. Underwriting costs of a new issue do not represent a tax implication in the bond refunding decision.

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In the liver, bilirubin is conjugated to glucuronide.

A class of enzymes called uridine-diphosphoglucuronic glucuronosyltransferase converts bilirubin to glucuronic acid inside the hepatocyte (UDPGT).

One of the many important detoxification processes used by the human body is glucuronidation. There are several distinct UDPGT isoforms, but UDPGT1A1 is the one that is physiologically significant for bilirubin glucuronidation.

The bilirubin's propionic acid side chains are modified by the enzyme by adding two glucuronide moieties. Bilirubin diglucuronide is the most common compound created under typical circumstances.

However, the majority of bilirubin may be converted as bilirubin glucuronide if the conjugation machinery is overloaded under circumstances where there is an excessive amount of bilirubin production.

Hydrogen bonds must be broken in order for bilirubin to be converted to its water-soluble form, which is necessary for liver and kidney excretion.

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Answer:

b

Explanation:

i think im right

Measuring the center of mass (COM) of a person in microgravity can be challenging since traditional methods used on Earth may not be applicable.

It's important to note that measuring the COM accurately in microgravity poses unique challenges due to the absence of gravitational forces. Researchers and engineers continuously develop and refine techniques to improve the accuracy of COM estimation in such conditions.

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The organelle's function would be most affected if a cell was not able to carry out exocytosis is D. Secretory vesicle.

Exocytosis is the process of a cell secreting molecules by releasing them from vesicles through the plasma membrane to the exterior of the cell. Cells use exocytosis to release waste products or byproducts, such as proteins or enzymes, that are produced within the cell. The secretory vesicle's function would be most affected if a cell was not able to carry out exocytosis. The secretory vesicle is a small, membrane-bound sac that contains proteins or other substances that a cell needs to release, it fuses with the plasma membrane during exocytosis to release its contents into the extracellular space.

Exocytosis is a critical process for cells because it allows them to release waste and byproducts, as well as secrete proteins or enzymes that are needed for cell function. If a cell cannot carry out exocytosis, it will accumulate waste and byproducts, which could be harmful to the cell. Additionally, the cell would be unable to secrete important proteins or enzymes, which could affect its overall function. Therefore, the secretory vesicle's function would be most affected if a cell was not able to carry out exocytosis, so the correct answer is D. Secretory vesicle.

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Answer:

1-C............. ...............

The correct matchings are: Deforestation: Destroys natural carbon sinks, leading to more CO2 in the air. Burning fossil fuels: Primary cause of human-created carbon emissions. Waste disposal in landfills: Emits methane from decomposing matter

1. Deforestation intensifies the greenhouse effect by contributing to increased levels of carbon dioxide (CO2) in the atmosphere. Trees act as natural carbon sinks, absorbing CO2 through photosynthesis and storing it in their biomass.

2. Burning fossil fuels, such as coal, oil, and natural gas, is the primary cause of human-created carbon emissions. These fuels release carbon that has been stored underground for millions of years into the atmosphere as CO2.

3. Waste disposal in landfills intensifies the greenhouse effect through the production of methane (CH4). When organic waste decomposes in oxygen-deprived conditions, methane is released. Methane is a potent greenhouse gas, with a significantly higher warming potential than CO2.

These activities highlight the human-induced factors that contribute to the intensification of the greenhouse effect and the resulting impacts on the Earth's climate system.

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All activities of living organisms involve changes in energy which is ability to do work.

Energy metabolism is the process of generating energy from the nutrients and this process is indispensable for cell homeostasis maintenance and responses to varying conditions. Cells require energy for the growth and maintenance and have evolved to have multiple pathways to generate energy.

Metabolism is the set of life-sustaining chemical reactions in the organisms. Three main functions of metabolism are as:  conversion of energy in food to energy available to run cellular processes; conversion of food to building blocks for proteins, lipids, nucleic acids and some carbohydrates and elimination of metabolic wastes.

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In this question, the answer to the question is: Box D corresponds to plants with a heterozygous genotype. we are given four boxes with different letters and numbers representing the genotypes of plants.

To determine which boxes correspond to plants with a heterozygous genotype.

We need to understand the concept of heterozygosity and the notation used to represent genotypes.

Heterozygosity refers to the presence of two different alleles at a given gene locus in an organism's genome. In genetic notation, the two alleles are represented by letters, with the dominant allele typically represented by a capital letter and the recessive allele by a lowercase letter.

For example, if the gene for flower color in a plant has two alleles, one for purple flowers (dominant) and one for white flowers (recessive), then a plant with a heterozygous genotype for this gene would have one allele for purple flowers (represented by the letter P) and one allele for white flowers (represented by the letter p).

Now, looking at the six boxes given in the question, we can see that only box D represents a heterozygous genotype. Box D has the letters D and d, which indicates that this plant has one allele for the dominant trait (represented by the capital D) and one allele for the recessive trait (represented by the lowercase d).

Therefore, the answer to the question is: Box D corresponds to plants with a heterozygous genotype.

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The passage does not provide any information to suggest that the Hfe knockout mice have decreased iron levels. According to the experimental results described in the passage, the most likely conclusion that can be drawn is: Increased oxygen consumption and heat production in Hfe-/- mice fed with a high fat diet result from increased fatty acid oxidation.

Option A: Increased oxygen consumption and heat production in Hfe-/- mice fed with a high fat diet result from increased fatty acid oxidation.

Option B: The relative rate of palmitate oxidation in Hfe-/- mice compared to healthy mice is strain-dependent.  

Option C: High-fat diets lead to lower overall palmitate oxidation in Hfe-/- mice when compared to the wild-type.

Option D: The elevated levels of ferritin in Hfe knockout mice indicate overall decreased iron levels in comparison to healthy mice.

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