Kathy is making some smoothies. The recipe uses 10 strawberries, s, for every 15 ounces of peaches, p.
Write an equation that can be used to determine the amount of strawberries needed based on the ounces of peaches.
S =
-P

Answer:

No, but they add up to 180 degrees.

Step-by-step explanation:

Take one of the angles, interior or exterior and subtract it from 180 and you should have your other angle.

Answer:

y=90(0.5)^x

The y-intercept is (0,90), so when x=0, y should be 90.

By replacing x=0 in all equations you get;

1)

y=90(2)^0 =90 accepted

2)

y=2(90)^0 =2 rejected

3)

y=0.5(90)^0 =0.5 rejected

4)

y=90(0.5)^0 =90 accepted

Since this is an exponential decrease,

y=90(2)^x is rejected.

Jenny jumps rope for 15minutes a day.

Month of december has 31 days

So

Total minUtes she jumped

Option B

Answer:

One ticket cost $10.90.

Step-by-step explanation:

The total spent was $98.50--food, drinks, admission--everything.

$44.00 was for food and drinks.

We can take the 44 away from the total.

98.50 - 44.00

= 54.50

They spent 54.50 on 5 tickets to get in. Divide to find the cost of one tickets. This assumes that all 5 tickets were the same price.

54.50 ÷ 5 = 10.90



The price of one ticket was $10.90

To make this look like algebra class...

let x = the price of one ticket

5x = the price of 5 tickets

5x + 44 = 98.50

subtract 44

5x = 54.50

divide by 5

x = 10.90

To find the number of dimes and quarters, you have 17 dimes and 34 quarters in your pocket , when there are 51 coins in your pocket.

To solve this problem, we can set up a system of equations using the given information. Let's use "d" to represent the number of dimes and "q" to represent the number of quarters.

We know that there are 51 coins in total, so we can write the equation: d + q = 51.

We also know that the total value of the coins is $10.20, which can be expressed as 10d + 25q (since dimes are worth 10 cents and quarters are worth 25 cents). So our second equation is: 10d + 25q = 1020.

To solve this system of equations, we can use substitution or elimination. Let's use substitution:

Rearrange the first equation to solve for d: d = 51 - q.

Substitute this expression for d in the second equation: 10(51 - q) + 25q = 1020.

Simplify and solve for q: 510 - 10q + 25q = 1020.

Combine like terms: 15q = 510.

Divide both sides by 15: q = 34.

Now substitute this value back into the first equation to solve for d: d + 34 = 51.

Subtract 34 from both sides: d = 17.

Therefore, you have 17 dimes and 34 quarters.

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Answer:

38 degrees

Step-by-step explanation:

142 and x are supplementary angles due to them being on the same line, so they have to add up to 180

180 - 142 = x

x = 38 degrees

Complete Question

The  complete question is shown on the first uploaded image

Answer:

Step-by-step explanation:

From the question we are told that

  The  relationship is  \(\frac{150 }{d} = \frac{130}{c}\)

   The number of fence post painted by chuck is  \(l = 130\)

    The number of fence post painted by Diana  is \(k = 150\)

    can paint 10 fences more than chuck  so let say the  of fence painted in an hour by chuck is \(g\)

     Then  the number of fence post painted by Diana in one hour is

          \(f = g+ 10\)

 So

       \(\frac{150 }{ g + 10 } = \frac{130}{g}\)

       \(130 g + 1300 = 150g\)

        \(g = 65 \ m\)

Answer:

7a+14

Step-by-step explanation:

You distribute the 7 across the equation (7xa)+(7x2) = 7a=14

The amount that John would spent on rent, clothes, and the automobile are :

The amount that John would spend on his rent is :

= Percentage of pie chart x Monthly pay

= 38 % x 805

= $ 305. 90.

The amount spent on Clothes by John:

= Percentage of pie chart x Monthly pay

= 14 % x 805

= $ 112. 70

Amount spent on the automobile :

= 22 % x 805

= $ 177. 10

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The things you are to calculate spending on are:

Answer:

78.5

Step-by-step explanation:

Siama and Wills used different methods to find the differences between (5x + 6x) and (2x - 1) but they both arrived at the same answer.

I prefer Wills method because it is easier and less complicated.

Wills method:

(5x + 6x) - (2x - 1)

Subtract both 2x and -1

5x + 6x - 2x - - 1

5x + 4x + 1

In conclusion, Wills method is preferred when both methods are compared.

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Step-by-step explanation:

-coefficent=1

-collect like terms /variables

-add numbbers (1+2)=3p

Answer:

1

Step-by-step explanation:

(p+q)(p-q)/(p+q)(p-q)=1

[It is an identity : a²-b²= (a+b)(a-b)]

Hope this will help:)

Answer:

\(\sum_{n = 1} 2*(-5)^{n-1}\)

Step-by-step explanation:

An arithmetic sequence is of the form:

\(A_n = A_{n-1} + d\)

While a geometric sequence is of the form:

\(A_n = A_{n-1}*r\)

notice that first, we have a change of sign in our sequence, so we already can discard the arithmetic sequence.

In fact, the pattern is kinda easy to see.

The first term is:

A₁ = 2

the second term is:

A₂ = -10

notice that:

A₂/A₍ = r = -10/2 = -5

The third term is:

A₃ = 50

the quotient between the third term and the second term is:

A₃/A₂ = 50/-10 = -5

Whit this we can already conclude that the n-th term of our sequence will be:

\(A_n = A_{n-1}*(-5)\)

Then the summation will be something like:

\(\sum_{n = 1} A_n = A_1 + A_2 + A_3 + ... = 2 - 10 + 50 - ...\)

We can write:

\(A_n = A_{n-1}*(-5) = (A_{n-2}*(-5))*(-5)) = A_1*(-5)^{n-1} = 2*(-5)^{n-1}\)

Then the summation is just:

\(\sum_{n = 1} 2*(-5)^{n-1}\)

Answer:

y = x - 8

Step-by-step explanation:

I plugged iin for the values and checks out.

Hope this helps!

Step-by-step explanation:

After you find the sums for each set, make a list, counting the number of ways a sum can occur.

You'll notice that for Set A, sums of 5, 6, 7, 8, and 9 all appear 4 times.  So they have equal probabilities.  In Set B, a sum of 7 appears 6 times.  Sums smaller or larger than 7 are less common.

When we look at the data, we see that were more sums of 7 than any other sum.  So this data was probably from Set B.

Answer:

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions

Step-by-step explanation:

set = {0,1,2,3,4,5,6,7,8,9}

setting up a one-to-one correspondence between the set of real numbers between 0 and 1

The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1

hence The power set of (n) is uncountable and is equivalent to the set of real numbers given

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions

Answer:

I am pretty sure your answer is right

Step-by-step explanation:

Answer:

D is correct trust.

Step-by-step explanation:

I literally took the test 2 minutes ago and got that answer.

The cannonball will land approximately 20.4 seconds after it was fired.

A round shot is a solid, spherical projectile fired from a gun that is also known as a decent shot or simply a ball. Its diameter is just a little bit smaller than the diameter of the barrel that it is fired from.

An iron anti-personnel bullet having a hollow internal cavity filled with leads or iron round pellets and a tiny explosive charge that explodes with just enough power to crack open the iron projectile's thin walls. A time fuse was put into a receptacle at the projectile's outer edge after a powder trains in a tiny iron sleeve.

We can use the equations of motion for projectile motion to solve this problem. Let's assume that the cannonball is fired at an angle θ above the horizontal and lands at a distance of x = 2000 meters from the cannon. We also know that the initial speed of the cannonball is 200 m/s.

The horizontal and vertical components of the velocity can be expressed as:

vₓ = v₀ cos(θ)

vₐ = v₀ sin(θ) - gt

where v₀ is the initial velocity (200 m/s), g is the acceleration due to gravity (9.8 m/s²), and t is the time taken for the cannonball to land.

Using the equation for the horizontal motion, we can find the time taken for the cannonball to travel a distance of 2000 meters:

x = v₀ cos(θ) * t

t = x / (v₀ cos(θ))

Using the equation for the vertical motion, we can find the time taken for the cannonball to reach the ground:

y = v₀ sin(θ) * t - (1/2) * g * t²

0 = v₀ sin(θ) * t - (1/2) * g * t²

Solving for t in the second equation gives:

t = 2 * v₀ sin(θ) / g

Substituting this expression for t into the first equation gives:

x = (v₀² / g) * sin(2θ)

We can now solve for θ:

sin(2θ) = (g * x) / v₀²

θ = 0.5 * arcsin((g * x) / v₀²)

Plugging in the given values for g, x, and v0, we get:

θ = 0.5 * arcsin((9.8 m/s² * 2000 m) / (200 m/s)²) ≈ 20.3 degrees

Therefore, the cannon fired the shot at an angle of approximately 20.3 degrees above the horizontal.

To find the time taken for the cannonball to land, we can use the expression for t derived earlier:

t = 2 * v₀ sin(θ) / g

t = 2 * 200 m/s * sin(20.3°) / 9.8 m/s² ≈ 20.4 seconds

Therefore, the cannonball will land approximately 20.4 seconds after it was fired.

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Answer: The Silo is 44 meters tall

Step-by-step explanation:

To find the height of the silo, first you have to divide the drawing height (33cm) by 1.5 to get the unit rate. Then multiply the 22 by 2 to get 44 meters (The height of the silo)

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

-38

Step-by-step explanation:

10 + 28 = 38 so to check it 10- (-38)=28

Answer: The answer is h ≥ 57.

Step-by-step explanation: This is because the child has to be at least 57 inches. This means that h > 57 will not work because the problem includes 57. We have to write an inequality that does include 57, and includes numbers that are greater than 57. Hence, the answer is h ≥ 57.  

2) The value of rational function represented by the graph is,

⇒ y = 3 - x

3)  Domain of function is, (- ∞, 0)

And, The range of the function is, (- ∞, 1) ∪ (1, ∞)

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

2) Take two points o the graph are,

(0, - 3) and (3, 0)

Hence, The value of rational function represented by the graph is,

⇒ y - (- 3) = (0 + 3) / (3 - 0)  (x - 0)

⇒ y + 3 = 3/3x

⇒ y + 3 = x

⇒ y = 3 - x

Thus, The value of rational function represented by the graph is,

⇒ y = 3 - x

3) The graph is shown in figure.

Hence, By graph the domain is defined by up and down.

Thus, Domain of function is,

(- ∞, 0)

And, The range of the function is defined left to right.

Hence, We get;

Range = (- ∞, 1) ∪ (1, ∞)

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\impliedby y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{5}}x-8\)

so we're really looking for the line of a slope of 3/5 and passing through (0,-3)

\((\stackrel{x_1}{0}~,~\stackrel{y_1}{-3})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{3}{5}}(x-\stackrel{x_1}{0}) \\\\\\ y+3=\cfrac{3}{5}x\implies y=\cfrac{3}{5}x-3\)

Answer:

answer is sister's.

Step-by-step explanation:

sisters mean more than one sister.

sisterses isn't a word.

sisters' also isn't a word.

sister's is a word and it means that she has possession of something or that she owns something.