Iodine-131 is one of the most important isotopes used in the diagnosis of thyroid cancer. One atom has a mass of 130.906114 amu. Calculate the binding energy(c) per mole in kJ.

Answers

Answer 1

Iodine-131 is one of the most important isotopes used in the diagnosis of thyroid cancer. One atom has a mass of 130.906114 amu.\

What is thyroid cancer?

Cancer that originates in the tissues of the thyroid gland is known as thyroid cancer. It is a condition where cells develop improperly and are susceptible to spreading to different bodily regions. A bump in the neck or swelling are examples of symptoms. Thyroid cancer is not always diagnosed because it can move from other parts of the body to the thyroid.

Young age radiation exposure, having an enlarged thyroid, and family history are risk factors. Papillary thyroid cancer, follicular thyroid cancer, medullary thyroid cancer, and anaplastic thyroid cancer are the four primary kinds. Ultrasound and tiny needle aspiration are frequently used in diagnosis. As of right now, it is not advised to screen those who are healthy and at normal risk for the disease.

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Related Questions

How specifically is kinetic energy lost during a car crash?

Answers

Most of the kinetic energy in the collision process is converted into the internal energy of the car, because the metal plastic deformation after the collision increases the internal energy a lot. Other kinetic energy is converted into heat energy, sound energy, etc.

Answer + Explanation:

During a car crash, kinetic energy is lost through various forms of deformation of the vehicle and the generation of heat.

When a car collides with another object, the force of the impact causes the vehicle's body and structure to deform. This deformation absorbs some of the kinetic energy and converts it into other forms of energy, such as heat and sound.

In addition, friction between the moving parts of the car and between the car and the road can also generate heat, which absorbs some of the kinetic energy.

The amount of kinetic energy lost during a car crash depends on the mass of the vehicle, the speed at which it was traveling, and the type and severity of the collision. In general, higher speeds and more severe collisions result in greater kinetic energy loss.

READING CHECK
7. What is the difference between a compound and a mixture?
ker notes

Answers

Compound are substances which can be formed by chemically combining two or more elements. Mixtures are substances that are formed by physically mixing two or more substances. Compounds can be of three types, which are: covalent compounds, metallic compounds and ionic compounds

Hope this helps

Calculate the pH after 0.13 mol NaOH are added to 1.00 L of 0.50M HC2H3O2 and 0.80M NaC2H3O2 buffer solution, Ka= 1.3 x 10^-5. I really need help, I'm struggling with this topic.

Answers

Determine how many mL of solution A (acetic acid-indicator solution) must be added to solution B (sodium acetate-indicator solution) to obtain a buffer solution that is equimolar in acetate and acetic acid. Solution A: 10.0 mL 3.0e-4M bromescol green

hoped I helped

A 55 kg person on Earth has the __________mass on the moon.

Answers

Answer:

89.1 N

Explanation:

W = m gm = 55.0 x 1.62 = 89.1 N

The magnitude of Kw indicated that _____.
A. the auto-ionization of water is exothermic
B. water auto-ionizes only to a very small extent
C. water auto-ionizes very quickly D. Water auto-ionizes very slowly

Answers

The magnitude of Kw indicates that B. water auto-ionizes only to a very small extent.

Kw, also known as the ionization constant of water, is a measure of the extent to which water molecules dissociate into hydronium ions (H3O+) and hydroxide ions (OH-) in aqueous solution. The value of Kw is determined to be 1.0 x 10^-14 at 25 degrees Celsius. This small value indicates that water auto-ionizes only to a very small extent. In other words, the concentration of both hydronium and hydroxide ions in pure water is very low, suggesting that the auto-ionization process occurs minimally.

The auto-ionization of water is a relatively slow process, and the number of water molecules that dissociate into ions at any given time is small compared to the total number of water molecules present.

Option B is answer.

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Describe density in your own words(you may use an example)

Answers

Answer:

density, is the a substance is its mass per unit volume thats what i wrote in my notebook

Explanation:

Calculate the relative formula mass of water, H₂O.
(Relative atomic masses: H = 1.0, 0 = 16)

Answers

The molecular mass of water

H2O = ( 2 * Atomic mass of hydrogen) + ( 1 * atomic mass of oxygen)

= ( 2 * 1 . 0084 ) + ( 1 * 16 )

= 18.0168

= 18.02 g/ mol

a dilute solution is prepared by transferring 20.00 ml of a 0.3965 m stock solution to a 900.0 ml volumetric flask and diluting to mark. what is the molarity of this dilute solution?

Answers

The molarity of the dilute solution prepared by transferring 20.00 mL of a 0.3965 M stock solution to a 900.0 mL volumetric flask and diluting to the mark is approximately 0.00881 M.

To calculate the molarity of the dilute solution, we can use the formula:

M1V1 = M2V2

where M1 is the molarity of the stock solution, V1 is the volume of the stock solution used, M2 is the molarity of the dilute solution, and V2 is the final volume of the dilute solution.

Given:

M1 = 0.3965 M

V1 = 20.00 mL = 20.00/1000 L = 0.0200 L

V2 = 900.0 mL = 900.0/1000 L = 0.900 L

Using the formula:

M1V1 = M2V2

0.3965 M × 0.0200 L = M2 × 0.900 L

M2 = (0.3965 M × 0.0200 L) / 0.900 L ≈ 0.00881 M

Therefore, the molarity of the dilute solution is approximately 0.00881 M.

The molarity of the dilute solution prepared by transferring 20.00 mL of a 0.3965 M stock solution to a 900.0 mL volumetric flask and diluting to the mark is approximately 0.00881 M.

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what is the bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals?

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The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2

Bond order = (8 - 5) / 2

Bond order = 1.5.

This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

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Where basalts are created within the earth?

Answers

Basalts are formed in many areas of the earth such as the colorado, red sea, oceanic crust and others.

How basalts are formed?

Basalts are are formed from the cooling of lava from the Earth's surface. The lava from which these basalts are made from is from magma.

This formed basalt is a form of igneous rock. The outside layer of the earth crust which is the oceanic crust is where the basalts are formed.

However, the importance of basalts cannot be overemphasized as is used in many building materials. It is also used for thermal purposes.

In conclusion, it can be deduced that the basalts are also created or produced in the oceanic crust of the earth.

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Sedimentary
Weathering
erosion, transport
deposition
Heat and/or
pressure
Igneous
Metamorphic
The
Rock
Cycle
Intrusion or
eruption
Burial and
extreme heat
Magma
Look at the diagram above.
Which sentence BEST describes a process in the rock cycle?
Igneous rocks can become metamorphic and sedimentary rocks.
Metamorphic rocks can form by the weathering process,
Volcanoes can deposit sedimentary rock to form mountains.
O Sedimentary rocks can melt to become metamorphic rocks.

SedimentaryWeatheringerosion, transportdepositionHeat and/orpressureIgneousMetamorphicTheRockCycleIntrusion

Answers

Answer:

I am confident that it is the last answer but if you can find a more verified answer I would go for that.

Sea-Floor Spreading1. The arrows on the figure show the ocean floor spreading from the ridge. What are three kinds of evidence scientists have found to support this idea?
A. B. C.
I NEED HELP

Answers

Answer is

-B

Explanation

PLEASE HELP ASAP PLEASE ! balance and a graduated
cylinder are used to
determine the density of a
mineral sample. The
sample has a mass of 14.7
g and a volume of 2.2 cm3.
What is the density of the
mineral sample?
A 0.15 g/cm
B 32 g/cm
C 18 g/cm
D 13 g/cm

Answers

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 14.7 g

volume = 2.2 cm³

The density is

\(density = \frac{14.7}{2.2} \\ = 6.6818181...\)

We have the final answer as

6.68 g/cm³

Hope this helps you

An unknown mass of aluminum requires 6290 joules to raise the tempature from 23.9 degrees c to 80.0 degrees c what is the Mass of aluminum

Answers

Answer: the mass of aluminum is 124.579 g
An unknown mass of aluminum requires 6290 joules to raise the tempature from 23.9 degrees c to 80.0 degrees

Describe and explain the possible effect on your results of the following experimental errors or variations. In each case, specify the component(s) whose percentage(s) would be too high or too low. (a) After adding DCM to Panacetin, you didn't stir or shake the mixture long enough. (b) During the NaOH extraction, you failed to mix the aqueous and organic layers thoroughly. (c) You mistakenly extracted the DCM solution with 5% HCL rather than 5% NaOH. (d) Instead of using pH paper, you neutralized the NaHCO3 solution to pH 7 using litmus paper.

Answers

Experimental errors or variations can significantly impact the results of the experiment. In this case, inadequate stirring, incomplete mixing of layers, incorrect extraction solution, and improper pH measurement can lead to inaccurate component percentages in the final product.

(a) Inadequate stirring or shaking of the mixture after adding DCM to Pan acetin can result in incomplete dissolution or extraction of certain components. This would lead to lower percentages of the components that require proper mixing for their extraction.

(b) Failure to thoroughly mix the aqueous and organic layers during the NaOH extraction can cause incomplete transfer of target components from one layer to another. As a result, the percentages of the desired components may be lower than expected, indicating incomplete extraction.

(c) Mistakenly using 5% HCL instead of 5% NaOH for the DCM extraction can affect the selectivity of the extraction process. Different solvents have varying affinities for specific components, so using the wrong extraction solution can lead to incorrect percentages of the components in the final product.

(d) Instead of using pH paper, if litmus paper is used to neutralize the \(NaHCO_{3}\) solution to pH 7, the accuracy of pH measurement may be compromised. Litmus paper provides a visual color change indication but lacks the precision of pH paper. As a result, the pH adjustment may not be accurate, potentially leading to deviations in the final component percentages.

In summary, these experimental errors or variations can introduce inaccuracies in the component percentages of the final product due to inadequate mixing, incorrect extraction solution, and imprecise pH measurement. It is essential to carefully follow the experimental procedure to minimize such errors and ensure reliable results.

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Now, we would like you to share your plant evaluations with Sandy Waters, President of Save the Shoreline. You will do this by writing Mr. Waters a letter. When writing your letter, be sure to use a traditional letter format.
Must include:
an opening that describes the procedure for ranking plants
all plant rankings
evidence from the data to support plant rankings
a closing that explains how plant rankings could protect the dunes

Answers

The given question is incomplete the complete question is

Now, we would like you to share your plant evaluations with Sandy Waters, President of Save the Shoreline. You will do this by writing Mr. Waters a letter. When writing your letter, be sure to use a traditional letter format. This means that your letter should include a greeting (Dear ________, ) a body, and a closing (Sincerely, _________). The body of your letter must include the following: an opening that describes the procedure for ranking plants all plant rankings evidence from the data to support plant rankings a closing that explains how plant rankings could protect the dunes As always, be sure to use complete sentences and proper punctuation, capitalization, and spelling.

Identification of plant includes scientific name and origin of species

Plant is the living thing that grow in the earth and that has a stem leaves and roots

Dear sandy water, the most common process of plant identification is by comparison and in this process the newly collected sample is compared with another collected and identified sample if all characteristics are same then name of sample can be determined

Your sincerely

With this information, we can conclude that identification of a sample includes providing the scientific name and origin of the species

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Answer:

Nice Profile Pic

Explanation:

Determine the mass of 2330 ml of gasoline. The density of gasoline id 0.008 g/ml

Answers

The density of gasoline id 0.008 g/ml is 18.64 gram.

What is density?

Density is defined as mass per unit volume it means that mass is present in one meter cube.

S.I unit of density is kg/meter^3.

Mathematically

Density = Mass/Volume.

In above question

Volume = 2330 mL

Density = 0.008 g/mL

Density = mass/ volume

So,

Mass = density x volume

Mass = 0.008 x 2330

Mass = 18.64 gram

Therefore, The density of gasoline id 0.008 g/ml is 18.64 gram.

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How is latitude related to temperature?

Answers

Answer:

The closer a place is to the equator the warmer it is

Explanation:

The equator is the part of the earth that is in the sun the longest and the poles are in the sun for a very short period of time each year. Therefore the equator is the warmest compared to the two poles.

What is the∆S° of 0₂​

Answers

Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

While solving a problem, we use a system in which mass (kg), force (N), and length (m) are the base units. What would you recommend for this system from the following: A new system of units will have to be formulated b. The above situation is not feasible Only the unit of time have to be changed from second to something else a No changes are required A Moving to another question will save this response.

Answers

The correct answer for this question is "A new system of units will have to be formulated."

When the mass (kg), force (N), and length (m) are the base units, it forms the SI system.

Therefore, the SI system is not appropriate in this scenario since it has meter, kilogram, and second as its base units. The only option remaining is to form a new system of units that would support these base units in order to resolve the problem.The Metric system is a popular system that is used all around the world. It is quite simple and has three main base units which include mass (gram), length (meter), and time (second). However, it is not acceptable for the aforementioned scenario. Instead, a new system of units will have to be formulated that would support the base units of mass, force, and length.

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Fuel-efficient cars help decrease the global dependency on nonrenewable resources because they use less _______ than other vehicles to travel the same distance.

Answers

Fuel-efficient cars help decrease the global dependency on nonrenewable resources because they use less fuel than other vehicles to travel the same distance.

What are non renewable resources?

Nonrenewable resources are natural resources that cannot be readily replaced or regenerated, such as fossil fuels (coal, oil, and natural gas), minerals, and some metals. These resources are finite and once they are used they cannot be replenished. They are formed over millions of years and are essential for the functioning of modern society, but their extraction and use can have negative impacts on the environment.

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In a solid to liquid mixture and increase in temperature means?

Answers

Answer:

Increase in temperature will not affect a solid - liquid mixture. Example can be taken of salt and water

The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air is in a room that measures 11.0 ft x 12.0 ft and has a(n) 10.0 ft ceiling? 1 in =2.54 cm (exactly); 1 L = 10^3 cm^3?A. 45 x 10^4B. 0.1145C. 3.99D. 44.5E. 0.166

Answers

First, we define density as:

Density = mass/volume;

We focus first on the volume of air in the room.

Volume:

We have the measurements of where the air is.

We calculate the volume with these measurements, but first, we change the units to L:

1 inch = 2.54 cm

1 L = 10^3 cm^3

1 ft = 12 inch

Now,

11.0 ft x (12 in/1 ft) x (2.54 cm/1 in) = 335.28 cm

12.0 ft = 365.76 cm

10.0 ft = 304.8 cm

Therefore, the volume of the room = 335.28 cm x 365.76 cm x 304.8 cm

Volume = 37378237.5 cm^3 x (1 L/10^3cm^3) = 374 x 10^2 L

From the Density equation, we clear the mass:

Density x volume = mass (g)

1.19 g/L x 374x10^2 L = 445x10^2 g x (1 kg/1000 g) = 44.5 kg

Answer: 44.5 kg

How many liters at STP are in 8.0 x 102 grams of sulfur dioxide?

Answers

Answer:

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

In this case, the molar mass of sulfur dioxide, that is, the mass of one mole of the substance, is 64 g/mole.

You can apply the following rule of three: if by definition of molar mass 64 grams of sulfur dioxide are contained in 1 mole, 8.0*10² grams are contained in how many moles?

\(amount of moles=\frac{8*10^{2}grams*1 mole }{64 grams}\)

amount of moles= 12.5 moles

Now you can apply a new rule of three: if by STP conditions 1 mole of any gas occupies a volume of 22.4 liters, 12.5 moles will occupy how much volume?

\(volume=\frac{12.5 moles*22.4 L}{1 mole}\)

volume= 280 L

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

A piece of cork has a volume of 35.5 milliliters, ml. what is the mass of the piece of cork in grams, g?

Answers

The mass of the piece of cork is determined by its density, which can vary depending on the specific type of cork.

To calculate the mass of the piece of cork, we need to know its density. Density is defined as the mass per unit volume of a substance. However, the question only provides the volume of the cork, which is 35.5 milliliters (ml). Without the density, we cannot directly determine the mass.

To find the mass, we need to multiply the volume by the density of the cork. Density is typically expressed in grams per milliliter (g/ml) or grams per cubic centimeter (g/cm³). Once we have the density, we can use the formula:

Mass (g) = Volume (ml) x Density (g/ml)

Without information about the density of the cork, we cannot accurately calculate its mass. Therefore, we need additional data or specifications to proceed with the calculation.

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The formula of a compound is M(OH)2 . Given that the Mr of compound is 98 , calculate Ar of M. (Ar of O = 16 , H = 1 ) WITH WOKING OUT

Answers

Answer:

The atomic weight Ar, of M is 64

Explanation:

The formula of the given compound is M(OH)₂

Mr, is the molecular weight of a compound and for the given compound, Mr is equal to 98.

Ar, is the atomic weight of the elements in the compound

The molecular weight, Mrof a compound is the mass of one mole mole of that compound. It can be obtained by summing the atomic masses of all elements in that compound. For elements that has more than one atom in the compound, the atomic weight of that element is multiplied by the number of atoms of the element present in the compound and then the sum of the weight of each element gives the molecular weight of the compound.

Onnthe compound above,the atomic weight of the unknown element M, is to be obtained.

Ar of the other elements inn he compound is given : Ar of O = 16, Ar of H = 1.

Molecular weight of the compound, Mr = 98

Calculating for the Ar of M:

(M × 1) + (16 × 2) + (1 × 2) = 98

M +32 + 2 = 98

M + 34 = 98

M = 98 -34

M = 64

Therefore, the atomic weight Ar, of M is 64

What is reduction give one example?

Answers

reduction is the gaining of electrons or loss of oxygen for example Al+ + MG becomes AL + MG+

CaC2 + 2H2O → C2H2 + Ca(OH)2If 4.8 moles of CaC2 are consumed in this reaction, how many grams of H2O are needed?

Answers

The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.

So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:

Mol of H2O = Mol of CaC2 x 2

Mol of H2O = 4.8 x 2 = 9.6 mol of H2O

Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.

Mass molar of H2O =18.01 g/mol

\(\begin{gathered} \text{Mass of H2O=Mol of H2O }\times Mass\text{ molar of H2O} \\ \text{Mass of H2O = 9.6 mol }\times18.01\frac{\text{ g}}{mol} \\ \text{Mass of H2O = 172.9 g} \end{gathered}\)

So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed

Zinc and sulphur react to zinc sulphide if 25.0g of zinc and 30.0 g of sulphur are mixed.
A. Which chemical is the limiting reactant?
B. How many grams of ZnS will be formed?
C. How many grams of the excess reactant will remain after the reaction is over? ​

Answers

Answer:

of zinc sulfide:

0.382 moles ZnS * 97.45 g/mol = 37.4 g ZnS

To find the mass of the excess reactant (sulfur) that will remain after the reaction is complete, we need to subtract the mass of the product (zinc sulfide) from the mass of the excess reactant:

30.0 g sulfur - 37.4 g ZnS = -7.4 g excess sulfur

Since the mass of the excess reactant is negative, this means that the reaction will consume all of the sulfur and there will be none left over.

To summarize:

A. Zinc is the limiting reactant.

B. 37.4 g of ZnS will be formed.

C. There will be no excess sulfur left over after the reaction is complete.

Explanation:

what is this can any body answer

what is this can any body answer

Answers

Bc the light was reflecting on to the object
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