If it's a summer day and you want to take a picnic are you concerned with weather
or climate? Why?

The density of the He nucleus is approximately 2.8 × 10^17 grams per cubic centimeter (g/cm³).

To calculate the density of the He nucleus, we need to know its mass and volume. Given that the diameter of the nucleus is approximately 2.0 fm, we can calculate its radius as 1.0 fm (since the radius is half the diameter).

The volume of a sphere can be calculated using the formula V = (4/3)πr³, where V is the volume and r is the radius. Substituting the values, we get:

V = (4/3)π(1.0 fm)³

Using the conversion factor that 1 fm = 1 × 10^-13 cm, we can convert the volume from fm³ to cm³:

V = (4/3)π(1.0 × 10^-13 cm)³

Simplifying the equation further, we have:

V = (4/3)π(1.0 × 10^-13)³ cm³

Now, to calculate the density, we need the mass of the He nucleus. The mass of a He nucleus is approximately 4 atomic mass units (4 amu).

Using the conversion factor that 1 amu = 1.66 × 10^-24 g, we can convert the mass from atomic mass units to grams:

Mass = 4 amu × (1.66 × 10^-24 g/amu)

Now we have both the mass and volume. The density (D) of an object is defined as mass divided by volume:

D = Mass/Volume

Substituting the values, we get:

D = (4 amu × 1.66 × 10^-24 g/amu) / [(4/3)π(1.0 × 10^-13)³ cm³]

Simplifying the equation and performing the calculations, the density of the He nucleus is approximately 2.8 × 10^17 g/cm³.

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0.1825 M is the concentration of H2SO4

To do this, let's write equation again:

Na2CO3 + H2SO4 ---------> H2O + CO2 + Na2SO4

As we can see, equation is already balanced and we can also see that mole ratio between the acid and the carbonate is 1:1, this means that moles of the acid, would be the same moles of carbonate, therefore, we can use the following expression:

M₁V₁ = M₂V₂ (1)

1: Is the carbonate

2: is the acid

To get the concentration of acid, we need to calculate the moles of carbonate used. This can be done using the molecular mass of sodium carbonate, which is 105.9888 g/mol, so the moles:

n₁ = 0.512/105.9888 = 0.0048 moles

Now that we have moles, we can use (1) and calculate the concentration of acid.

We know :

n₁ = M₁V₁ (2)

Replacing in (1) we have:

n₁ = M₂V₂

M₂ = n₁ / V₂ (3)

Now all we have to do is replace values and solve for concentration:

M₂ = 0.0048 / (0.02630) = 0.1825 M

This is concentration (molarity) of the H2SO4

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Answer:

Mars and Orbital code saber and the alien

Answer:

1. Molecular equation

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

2. Complete Ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

3. Net ionic equation

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

Explanation:

1. Molecular equation:

BaCl2(aq) + AgNO3(aq) –> AgCl(s) + Ba(NO3)2 (aq)

The above equation can be balance as follow:

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of AgCl as shown below:

BaCl2(aq) + AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balance by putting 2 in front of AgNO3 as shown below:

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

Now, the equation is balanced

2. Complete ionic equation

In solution, BaCl2 and AgNO3 will dissociate as follow:

BaCl2(aq) —> Ba²⁺(aq) + 2Cl¯(aq)

AgNO3(aq) —> Ag⁺(aq) + NO3¯ (aq)

BaCl2(aq) + AgNO3(aq) –>

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯

3. Net ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

Cancel out the spectator ions i.e ions that appears on both side of the equation in order to get the net ionic equation. This is illustrated below:

2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

1. Molecular equation: \(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)

2. Complete Ionic equation:\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)3. Net ionic equation: \(Cl^- (aq) + Ag^+ (aq) \rightarrow AgCl(s)\)

1. Molecular equation:

\(BaCl_2(aq) + AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)

There are two Cl atoms on the left side and one on the right. Balance can be achieved by adding 2 in front of AgCl, as seen below:

\(BaCl_2(aq) + 2AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)

There are two Ag atoms on the right side and one on the left. It is possible to achieve equilibrium by adding 2 in front of \(AgNO_3\), as demonstrated below:

\(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)

2. Complete ionic equation

\(BaCl_2\) and \(AgNO_3\) will dissociate in solution as follows:

\(BaCl_2(aq) \rightarrow Ba^{2+}(aq) + 2Cl^-(aq)\)

\(AgNO_3(aq) \rightarrow Ag^+ (aq) + NO_3^-(aq)\)

\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)

3. Net ionic equation

To obtain the net ionic equation, cancel out the spectator ions, which are ions that appear on both sides of the equation. As an example, consider the following:

\(2Cl^-(aq) + 2Ag^+(aq) \rightarrow 2AgCl(s)\)

\(Cl^-(aq) + Ag^+(aq) \rightarrow AgCl(s)\)

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Answer:

3HCl(aq)+Al(OH)3(s)=AlCl3(aq)+3H2O(l)

Explanation:

This is a double replacement reaction.

Step One: Write down the compound from the name.

Aluminum Hydroxide Al(OH)3

Hydrochloric Acid HCL

Step Two: Perform the double replacement reaction.

AB+CD=AD+CB

Step Three: Balance the equation

Final step: Write in physical states.

The physical state will either be (aq), (s), (l) or (g).

The number of moles of Al2S3 that would be equivalent to 605 g of the compound will be 4.03 moles.

The number of moles in a particular mass of a compound is the ratio of the mass of the compound and the molar mass of the compound.

Mole = mass/molar mass

Molar mass of Al2S3 = 150.17

Mole of 605 g Al2S3 = 605/150.17

                                    = 4.03 moles

In other words, the number of moles of 605 g Al2S3 is 4.03 moles.

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Answer: Hello Luv.......

Find the pH of a 0.0025 M HCl solution. ... The hydronium ion concentration can be found from the pH by the reverse of the ... 8.34 = - log [H3O+].

Explanation:

Calculate the pH of the solutions below. 1. ... a) [H+] = 1.0 x 102 M OH-]= 1 x 10-2M aad ... What is the pH of a 7.98 x 10-2 M solution of HNO3 (nitric acid). ... Find the hydronium ion concentration [H3O+] from the pH of the following solutions.

Hope this helps. Sorry if wrong.

Mark me brainest please.

Anna ♥

Explanation:

Well, the qualitative significance of a chemical equation is that it shows us concisely, and economically how matter interacts chemically in the breaking, and making of chemical bonds to form new substances…

Quantitatively, ALL stoichiometrically balanced equations show us that MASS is CONSERVED, and that “TANSTAAFL” , i.e. “there ain’t no such thing as a free lunch” , operates. And so 5∙g , 5∙kg , 5∙tonne of total REACTANT from all sources, leads to AT MOST to 5∙g , 5∙kg , 5∙tonne of total PRODUCT…. and in practice, we are not even going to get that… Electronic charge is also conserved in every chemical reaction … and we use this conservation principle when we write redox equation…

Chemical equations are the symbolic expression of the compounds and elements. It shows the quality and quantity by the chemical interaction and stoichiometry coefficient.

A chemical equation expresses the chemicals of the reactant and the product side in the form of symbols and mathematical expressions. They are quantitatively significant as they represent the stoichiometry coefficient. It tells about the moles needed by the reactants needed for product formation.

They also are qualitatively important as they depict the phases of the reactants and the products and tell the type of reaction like the decomposition, oxidation, reduction, combustion, etc. undergone by the substances.

Therefore, the chemical equation is significant both qualitatively and quantitatively.

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Answer:

a measure of concentration equal to the gram equivalent weight per liter of solution.

Explanation:

Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's role in the reaction determines the solution's normality. Normality is also known as the equivalent concentration of a solution.

hope it helped

Answer:

3.43 moles

Explanation:

To convert moles into grams you must take the number of grams and divide it by the atomic mass of the compound.

in this case, grams is 151 and N2O has an atomic mass of 44.013

so your equation would look like

151/44.013=3.430804535

your answer would be 3.43 moles

Answer:

b) Glucitol

Explanation:

The glucose loses the carbonyl group and its transformed to CH2OH

Answer:

1/4

Explanation:

From the question given above, the following data were:

Original amount (N₀) = 100 g

Time (t) = 24.8 h

Fraction remaining =?

NOTE: The half-life of K–42 is 12.4 h

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 24.8 h

Half-life (t½) = 12.4 h

Number of half-lives (n) =?

n = t / t½

n = 24.8 / 12.4

n = 2

Finally, we shall determine the fraction remaining. This can be obtained as follow:

Number of half-lives (n) = 2

Fraction remaining =?

Fraction remaining = 1/2ⁿ

Fraction remaining = 1/2²

Fraction remaining = 1/4

2x = 350- x

3x = 350

x = 350/x

therefore,

x = 116.67cm.

so, (350 - x)cm³ = (350- 166.67)cm³ = 233.33cm³

Hence distance covered by gas A is 116.67cm that by B is 233.33cm

depends on the situation, but scientifically, Einstein's theory of special relativity sets the speed of light, 186,000 miles per second (300 million meters per second). But some scientists are exploring the possibility that this cosmic speed limit changes. The speed of light is constant, or so textbooks say. (google)

The hydrogen ion concentration of the solution having a pH of 1.75 is 0.0178 M

pH is is given by the following equation:

pH = -Log [H⁺]

Where

With the above formula, we can obtain the hydrogen ion concentration of the solution as illustrated below:

pH = -Log [H⁺]

Inputting the various parameters, we have

1.75 = -Log [H⁺]

Multiply through by -1

-1.75 = Log [H⁺]

Take the anti-log of -1.75

[H⁺] = Anti-log -1.75

[H⁺] = 0.0178 M

Thus, we can conclude that the hydrogen ion concentration is 0.0178 M

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Answer:

it is not naturally occuring

Answer:

15

Explanation:

Magnesium Acetate Mg(C2H3O2)2

Number of atoms:

Carbon = 4

Hydrogen = 6

Magnesium = 1

Oxygen = 4

Total = 15

Answer:

108.6 g

Explanation:

First we use the PV=nRT formula to calculate the number of nitrogen moles:

Inputting the data:

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

Answer:

Insulation acts as a conductor to heat flow

Explanation:

Insulation helps increase the energy efficiency of your home by reducing the amount of heat that escapes from it in the winter.

Answer:

Insulation acts as a barrier to heat flow.

Explanation:

i hope it helps

A) The specific humidity of the air with the given parameters is;

w1 = 0.00967

B) The relative humidity of the air with the given parameters is;

Φ1 = 0.459

C) The enthalpy of the air in KJ/kg dry air with the given parameters is;

h1 = 49.75 KJ/Kg

Correct question is;

The dry- and wet-bulb temperatures of atmospheric air at 95 kPa are 25 and 17 °C, respectively. Determine (a) the specific humidity, (b) the relative humidity, and (c) the enthalpy of the air, in kJ/kg dry air.

We are given;

Atmospheric Pressure;P = 95 KPa

Dry temperature;T1 = 25 °C

Wet temperature;T2 = 17°C

A) From table A-4 attached and at temperature of 17°C and by interpolation, we have a saturation pressure of P_g2 = 1.938 kpa

First of all, we will calculate the specific humidity from the given pressure and saturation pressure with the formula;

w2 = (0.622 × P_g2)/(P - P_g2)

w2 = (0.622 × 1.938)/(95 - 1.938)

w2 = 0.013

Now, let's calculate specific humidity with the enthalpies at 17 °C and by interpolation. We have specific enthalpies from table A-4 as;

h_fg2 = 2460 KJ/Kg

h_g1 = 2546.5 KJ/Kg

h_f2 = 71.36 KJ/Kg

The formula for the specific humidity under these conditions is;

w1 = (c_p(T2 - T1) + w2•h_fg2)/(h_g1 - h_f2)

c_p of air has a value of 1.005 KJ/Kg.°C

Thus;

w1 = (1.005(17 - 25) + 0.013*2460)/(2546.5 - 71.36)

w1 = 0.00967

B) The relative humidity is determined from the equation;

Φ1 = (w1*p)/(0.622 + w1)p_g1

From table A-4 attached and at temperature of 25 °C, we have a saturation pressure of P_g1 = 3.1698 KPa

Φ1 = (0.00967*95)/(0.622 + 0.00967)3.1698

Φ1 = 0.459

C) For the enthalpy of air, h1 we will use the formula;

h1 = (c_p × T1) + (w1 × h_g1)

h1 = (1.005 × 25) + (0.00967 × 2546.5)

h1 = 49.75 KJ/Kg

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The Empirical formula of the compound is : CH3O

The empirical formula of a chemical compound is described as the simplest whole number ratio of atoms present in a compound.

We Calculate the moles of C, H, and O.

For C= 0.2322g/12g/mole= 0.01935 mole

For H= 0.05848g /1 g/mole = 0.05848 mole

For O= 0.3091g/16 g/mole = 0.01932 mole

We then calculate the number of atom of each element by dividing each mole by the lowest mole ratio:

C= 0.01935mole/0.01932 mole= 1 atom

H= 0.05848 mole/0.01932 mole = 3 atom

O = 0.01932 mole/0.01932 mole = 1 atom

Therefore the empirical formula of the compound is : CH3O

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The name of the organic compound shown is methylpropenaoate.

It is an alkanoate.

Esters are organic compounds formed when an organic acid reacts with an organic base.

An example of an ester is alkanoates.

Alkanoates are formed when alkanoates, the alkanoic acids react with alkanols.

In hydrogen ion, an alkanoic acid reacts with the hydroxide ion of the alkanol to form water and the alkanoates are formed as well from the remaining moieties of the alkanol and the alkanoic acids.

The molecule whose structure is shown is an alkanoate.

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Answer:

3.00 L

Explanation:

PV = nRT

(82 atm × 101325 Pa/atm) V = (10 mol) (8.314 J/mol/K) (27 + 273) K

V = 0.00300 m³

V = 3.00 L

Answer:

ΔH°r = -1009.8 kJ

Explanation:

Let's consider the following balanced reaction.

2 NH₃(g) + 3 N₂O(g) ⇒ 4 N₂(g) + 3 H₂O(l)

We can calculate the standard enthalpy of the reaction (ΔH°r) using the following expression.

ΔH°r = [4 mol × ΔH°f(N₂(g)) + 3 mol × ΔH°f(H₂O(l))] - [2 mol × ΔH°f(NH₃(g)) + 3 mol × ΔH°f(N₂O(g))]

ΔH°r = [4 mol × 0 kJ/mol + 3 mol × (-285.8 kJ/mol)] - [2 mol × (-46.2 kJ/mol) + 3 mol × 81.6 kJ/mol]

ΔH°r = -1009.8 kJ

The standard enthalpy change (∆H°rxn) for the given reaction is -38.0 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases heat to the surroundings.

The standard enthalpies of formation (∆Hf°) for the reactants and products involved in the reaction are: ∆Hf°[NO2(g)] = +33.2 kJ/mol. ∆Hf°[H2O(l)] = -285.8 kJ/mol. ∆Hf°[HNO3(aq)] = -207.2 kJ/mol. ∆Hf°[NO(g)] = +90.4 kJ/mol. We can use these values to calculate the standard enthalpy change (∆H°) for the reaction using the following equation:

∆H°rxn = Σn∆Hf°(products) - Σm∆Hf°(reactants) where n and m are the stoichiometric coefficients of the products and reactants, respectively. Substituting the values, we get:∆H°rxn = [2 × ∆Hf°(HNO3(aq))] + [∆Hf°(NO(g))] - [3 × ∆Hf°(NO2(g))] - [1 × ∆Hf°(H2O(l))]. ∆H°rxn = [2 × (-207.2 kJ/mol)] + [90.4 kJ/mol] - [3 × (+33.2 kJ/mol)] - [1 × (-285.8 kJ/mol)]. ∆H°rxn = -414.4 kJ/mol + 90.4 kJ/mol - 99.6 kJ/mol + 285.8 kJ/mol. ∆H°rxn = -38.0 kJ/mol

Therefore, the standard enthalpy change (∆H°rxn) for the given reaction is -38.0 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases heat to the surroundings.

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Answer:

a

Explanation: because the sum of the bond enthalpies of the bond in the reactant is greater than the sum.

Answer

the answer is p block