please click on the source of the point source light. position the cursor where the light emanates and click. do not worry if the target shows up elsewhere on the screen. just be sure to click from where the light source emanates.

Answer:

\(\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k\)

Explanation:

for the unit vector, we need to divide the given vector by its norm, because it should be in the SAME direction as the original vector, but of magnitude "1".

We notice that the norm of the given vector is:

\(\sqrt{4^2+2^2+(-5)^2} =\sqrt{45}\)

Then, the unit vector becomes:

\(\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k\)

Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.

Answer:

\(93\:\mathrm{kg}\)

Explanation:

We can use Newton's Universal Law of Gravitation to solve this:

\(F=G\frac{m_1m_2}{r^2}\), where \(F\) is force, \(G\) is gravitational constant \(6.67\cdot 10^{-11}\), \(m_1\)and \(m_2\) represent the masses of both objects, and \(r\) represents the distance between their center of masses.

Plugging in our given values, we have:

\(5.2\cdot 10^{-8}=6.67\cdot 10^{-11}\cdot \frac{97\cdot m_2}{3.4^2},\\m_2=92.9=\fbox{$93\:\mathrm{kg}$}\)(two significant figures).

Answer:

the answer is 93kg

Explanation:

the answer is 93kg

Answer:

Answer is attached

The average velocity for the race is 70 m/s if the dragster crosses the finish line with a velocity of 140 m/s.

It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.

It is given that:

A dragster crosses the finish line with a velocity of 140m/s.

The vehicle maintained a constant acceleration from start to finish.

As we know,

The average velocity can be given as:

V(avrg) = (v1 + v2)/2

v1 = 140 m/s

v2 = 0 m/s

v(avrg) is the average of the velocity.

V(avrg) = (140 + 0)/2

V(avrg) = 140/2

V(avrg) = 70 m/s

Thus, the average velocity for the race is 70 m/s if the dragster crosses the finish line with a velocity of 140 m/s.

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Answer:

False

Explanation:

17%

the answer to your question is false

Gerard's average velocity for the ride is 6 meters per second.

To find Gerard's average velocity for the ride, we can use the formula:

Average velocity = Total displacement / Total time

First, we need to convert the distance traveled from kilometers to meters:

7.20 kilometers * 1000 = 7200 meters

Next, we convert the time from minutes to seconds:

20.0 minutes * 60 = 1200 seconds

Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:

Total displacement = 7200 meters

Finally, we substitute the values into the average velocity formula:

Average velocity = 7200 meters / 1200 seconds

Average velocity = 6 meters per second

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The acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.

The  acceleration of the crate is calculated from the net force acting on the crate as shown below;

F(net) = applied force - frictional force

F(net) = 10 N - 5N

F(net) = 5 N

Apply Newton's second law of motion to calculate the acceleration of the crate.

F(net) = ma

where;

a = F(net) / m

a = 5/5

a = 1 m/s²

Thus, the acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

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Jack is right.  If the ball continues to fall for three times as long, the average speed of the ball will be smaller than 9 m/s, because if the time of motion of an object increases, the speed at which it falls decreases.

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

where;

The initial vertical velocity of the ball = 0

h = 0 +  ¹/₂gt²

h =  ¹/₂gt²

t = √(2h / g)

t = √(2 x 2 / 9.8)

t = 0.64 m/s

The given time of motion of the ball = 0.67 second

If the ball continues to fall for 3 times as long, new time of motion of the ball = 3 x 0.67 s = 2.01 s

The average speed of the ball at this speed is calculated as;

s = [(u + v)/2 ]t

s = [(0 + v) / 2]t

s = (vt) / 2

vt = 2s

v = 2s / t

v = (2 x 2 m) / (2.01 s)

v = 1.99 m/s

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the answer for this question is c

If you need to shade the part of a circle indicative of parent material, these are the guidelines:

It should be noted that to complete the shading process, employ techniques such as utilizing solid colors with pencils, markers, cross-hatching, or diagonal lines.

Ensure that you correctly portray the shaded fraction of the circle and provide clear contrasts between the unshaded segment.

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Answer:

a = 5 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f}=v_{o}+a*t\)

where:

Vf = final velocity = 20 [m/s]

Vo = initial velocity = 10 [m/s]

t = time = 2 [s]

a = acceleration [m/s²]

Now replacing:

\(20 =10 +a*2\\10=2*a\\a=5[m/s^{2} ]\)

Answer:

37.5 J

Explanation:

With work done equation: W=Fs

W=75*0.50=37.5 J

or use mgh=(75)(0.5) which is the same

Answer:

14m/s

Explanation:

The total frequency is 120 1.

The frequency of each response category is the number of times it occurs in the sample. The relative frequency of each response category is the fraction of the total responses that belong to each category.

Class Frequency Relative Frequency

a 60 60/120 = 1/2

b 12 12/120 = 1/10

c 48 48/120 = 2/5

Total 120 1

Therefore, the frequency and relative frequency distributions of the responses are:

Class Frequency Relative Frequency

a 60 1/2

b 12 1/10

c 48 2/5

Total 120 1

Frequency refers to the number of times a particular event or item occurs in a set of data. It is a measure of how often an event or item appears in a data set. In statistical analysis, frequency is used to describe the distribution of a set of data, such as the number of occurrences of a particular value, category, or event. Frequency can be expressed as an absolute number or as a proportion or percentage of the total number of events or items in the data set. Frequency is an important concept in statistics and data analysis, as it provides a way to summarize and describe the patterns and relationships within a data set.

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Answer:

a the distance between the

The velocity of the third piece is v₃ = -12500 kg·m/s / m₃

The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.

velocity of the third piece =  v₃.

The total initial momentum before the explosion = 0

The total final momentum after the explosion= 0

Initial momentum = 0 kg·m/s (since the bomb is at rest)

Final momentum = m₁v₁ + m₂v₂ + m₃v₃

m₁ = mass of the first piece = 150 kg

v₁ = velocity of the first piece = 150 m/s (to the east)

m₂ = mass of the second piece = 100 kg

v₂ = velocity of the second piece = 200 m/s (south 60° west)

m₃ = mass of the third piece = unknown

v₃ = velocity of the third piece = unknown

0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)

final momentum = 0 and hence  v₃ is found as :

0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)

-12500 kg·m/s = (m₃)(v₃)

v₃ = -12500 kg·m/s / m₃

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Answer:

C. 2.5

Explanation:

It said it was right, so that's cool.

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

Answer:

d d d d d d s d. d d d d d df ff f f. f f f r r ff f f ff d f f f f f f f f f r. ff r f. r

The special and general theories of relativity and Albert Einstein's audacious theory that light is a particle are his most famous works as a physicist and Nobel winner. The most well-known scientist of the 20th century is perhaps him.

In March 1879, he was born in Ulm, Württemberg. He had a great interest in nature and the capacity to comprehend challenging mathematical ideas even as a young man in Munich. He had an unremarkable high school experience, doing exceptionally well in arithmetic but completely failing the classics, which were then thought to be crucial for anybody planning to attend college. He detested school's dreary regimentation and uncreative atmosphere.

The second study established a lot of information regarding the nature of molecules and explained Brownian motion, which is the random jostling of molecules floating in a fluid. 16 years later, this study helped him win the physics Nobel Prize.

However, his third work, "On the Electrodynamics of Moving Bodies," was left out of the award's wording. The third article was the one that would have the biggest impact on contemporary physics. It included Einstein's Special Theory of Relativity, which greatly simplified how we think about how radiation, like light, interacts with matter. Speaking about one body moving and another being motionless has no real significance, according to Einstein. Only in connection to one other can bodies be conceived of as moving;

This specifically implies that, regardless of the frame of reference, electromagnetic radiation's (such as light's) speed remains constant. Even well-known scientists struggled to comprehend this theory because of Einstein's insightful and audacious viewpoint. But over time, when the predictions made by his theory were repeatedly verified, the Special Theory of Relativity finally transformed how scientists thought about matter, space, time, and everything that interacts with them.

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Answer:

c) 2Q

Explanation:

From the given information:

The pressure inside a pipe can be expressed by using the formula:

\(\Delta P = \dfrac{128 \mu L Q}{\pi D^4}\)

Since the diameter in both pipes is the same, we can say:

\(D = D_A = D_B\)

where;

length of the first pipe A \(L_A = L\) and the length of the second pipe B \(L_B = 2L\)

Since the difference in pressure is equivalent in both pipes:

Then:

\(\dfrac{128 \mu L_1Q_1}{\pi D_1^4} = \dfrac{128 \mu L_2Q_2}{\pi D_2^4}\)

\(\dfrac{ L_1Q_1}{D_1^4} = \dfrac{ L_2Q_2}{D_2^4}\)

\(\dfrac{ LQ_1}{D^4} = \dfrac{ 2LQ}{D^4}\)

\(\mathbf{Q_1 = 2Q}\)

The flow rate in pipe B is 2Q of the flow rate of the pipe A

The flow rate is defined as the flow of the fluid across the cross section in per unit time.

From the given information:

The pressure inside a pipe can be expressed by using the formula:

\(\Delta p=\dfrac{128\mu LQ}{\pi D^4}\)

Since the diameter in both pipes is the same, we can say:

\(D=D_A=D_B\)

where;

length of the first pipe A  \(L_A=L\) and the length of the second pipe B  

\(L_B=2L\)

Since the difference in pressure is equivalent in both pipes:

Then:

\(\dfrac{128\mu L_1Q_1}{\pi D_1^4}=\dfrac{128\mu L_2Q_2}{\pi D_2^4}\)

\(\dfrac{L_1Q_1}{D_1^4}=\dfrac{L_2Q_2}{D_2^4}\)

\(\dfrac{LQ_1}{D_1^4}=\dfrac{2LQ}{D_2^4}\)

\(Q_1=2Q\)

Hence the flow rate in pipe B is 2Q of the flow rate of the pipe A

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The distance that is covered is 150 m

The displacement is 50 m.

We have to know that the displacement has to do with the distance that is covered in a  specific direction. We have to take note of the direction that we have there as that is what does make the difference between the distance and the displacement.

The distance does not involve the direction. It can then be safe to say that displacement is a vector and that distance is a scalar. Once again let us recall that these are so because the distance does not take cognizance of the direction while the displacement would always take cognizance of the direction of the motion.

Then we have;

Distance = 50 m + 50 m + 50 m = 150 m

For displacement calculation;

Moving towards the opposite side and back = 50 m - 50 m = 0 m

Moving again to the opposite side;

Displacement = + 50 m

Note that the backward motion of the swimmer would be taken as negative.

Therefore total displacement = 50 m

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\( \large \mathfrak{Solution : }\)

let's use first equation of motion to solve this ;

Velocity after 30 seconds = 170 m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The awnser is sulfur dioxide.

The gas that is responsible for lowering the temperature is sulfur dioxide gas.

A volcanic eruption refers to the sudden escape of lava and gases from the earth's core. It usually occurs at a very high temperature. The solidification of the volcano leads to rock formation.

During a volcanic eruption, the gas that is responsible for lowering the temperature is sulfur dioxide gas.

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