If a sodium hydroxide solution has a molarity of 2. 6 m, how many moles of naoh will be contained in 2. 00 l of solution?.

one mole of P weights about 31 grams

in one mole there are 6.022*10^23 atoms

we use the rule of threes

6.022*10^23atoms......weight..........31 grams

3.45*10^23 atoms.........weight...........x grams

x=(3.45*10^23*31)/6.022*10^23

x=106.95/6.022=17.76 grams

Answer:

Chemical compounds all have different melting points.

Explanation:

chemical compounds all have different freezing and boiling points. Different chemical compounds means they will have different chemical structures.

The repulsion of the electron pair surrounding the core atom has a significant impact on the geometry or shape of the electron.

The tendency of the electron pairs in an atom to repel one another when they are present is known as electron pair repulsion.

The more repulsion there is between the electron pairs, the more the electrons want to organize themselves to lessen it.

Here, the issue of how electron pair repulsion affects molecule geometry is raised.

The fundamental explanation is that the molecule will change its structure to keep the repelling electron pair apart.

The electron pair repulsion also plays a significant role in determining molecular geometry, since molecules prefer to modify their form and geometry in response to the electron pair.

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Answer:

1.3175675675675604

Explanation:

does this need to be rounded?

Determining the nonprotein respiratory quotient (RQ) and measuring protein oxidation involve considering various factors and employing specific methods. The nonprotein RQ reflects substrate utilization during metabolism and can be calculated through indirect calorimetry by measuring oxygen consumption and carbon dioxide production.

Measuring the amount of protein oxidized requires considering nitrogen balance, which accounts for nitrogen intake and excretion.

Methods include nitrogen balance studies, stable isotope tracers, and marker compounds.

Nitrogen balance studies involve measuring nitrogen intake and excretion to determine the difference, indicating protein oxidation.

Stable isotope tracers track labeled nitrogen from ingested protein. Marker compounds like urea or ammonia serve as indicators.

These techniques require specialized equipment and are used in research to understand metabolic processes and nutrient utilization.

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For naturally occurring substances with unique chemical and atomic configurations, the proper name is "mineral." Compounds found only in living things are typically not considered minerals.

But other minerals, like calcite, are frequently biogenic or schematically classified as organic molecules (such as mellite ). In addition, living things frequently create inorganic minerals that are also found in rocks.

The arrangement of electrons in atomic or molecular orbitals of an atom, molecule, or other physical structure is referred to as the atomic configurations in atomic physics and quantum chemistry.

Atomic configurations electrons. The electron configuration is a list of all the atomic orbitals that have electrons in them, together with the number of electrons in each type of orbital.

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Free energy change for transporting Ca2+ ions is calculated as follows:∆G = RT ln ([Ca2+]outside/[Ca2+]inside)∆G = 8.315 J/mol.K x 310 K x ln (25 mM/145 mM) = -15,400 J/mol.

Here, ∆G is negative, which implies that Ca2+ ions transport spontaneously from the cell to blood. This is because the free energy of the system decreases when Ca2+ ions move from high concentration to low concentration. Therefore, transporting Ca2+ ions is energetically favorable.

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Answer:

Calculate the volume (in L) occupied by 3.40 g of NH3 at STP. (STP: 0 degree Celsius and 1 atmosphere of pressure).

Explanation:

To get the volume of ammonia gas at STP, calculate the number of moles of \(NH_3\) in the given amount.

Number of moles of \(NH_3\) gas is:

\(number of moles of NH_3 gas&=\frac{given mass of the gas}{its molecular mass} \\ &=\frac{3.40g}{17.0g/mol} \\&=0.2 mol.\)

Since,

1 mol of any gas at STP occupies ------- 22.4 L of volume.

then,

0.2 mol of \(NH_3\) occupies how much volume?

\(=>0.2 mol x \frac{22.4 L}{ 1.0 mol} \\=4.48 L\)

Hence, the volume occupied by 3.40 g of ammonia at STP is --- 4.48 L.

The percent composition of fluorine in the 15.8 g sample is approximately: 23%.

To determine the percent composition of fluorine in a 15.8 g sample, we need to first determine the mass of fluorine in the sample. This can be done by using the given percent composition of fluorine in the compound. If the compound contains 22.8% fluorine by mass, then the mass of fluorine in the sample can be calculated as follows:

Mass of fluorine = Percent composition of fluorine x Total mass of sample

Mass of fluorine = 22.8% x 15.8 g

Mass of fluorine = 3.6 g

So, the 15.8 g sample contains 3.6 g of fluorine.

To calculate the percent composition of fluorine in the sample, we need to divide the mass of fluorine by the total mass of the sample and multiply by 100. Thus, the percent composition of fluorine in the sample can be calculated as:

Percent composition of fluorine = (Mass of fluorine / Total mass of sample) x 100%

Percent composition of fluorine = (3.6 g / 15.8 g) x 100%

Percent composition of fluorine = 0.2278 x 100%

Percent composition of fluorine = 22.78%

Therefore, the percent composition of fluorine in the 15.8 g sample is approximately 23%.

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Answer:

Physical

Explanation:

You just melted the solid with heat, it has no new properties.

Answer:

1. C = 0.73 M.

2. pH = 0.14

Explanation:

The reaction is the following:

HCl + NH₃ ⇄ NH₄⁺Cl⁻

From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

\( n_{a} = n_{b} \)

Where "a" is for acid and "b" is for base.

The number of moles is:

\( n = C*V \)  

Where "C" is for concentration and "V" for volume.

\( C_{a}V_{a} = C_{b}V_{b} \)

\( C_{a} = \frac{0.1293 M*28.15 mL}{5.00 mL} = 0.73 M \)

Hence the initial concentration of the acid is 0.73 M.

The original pH of the acid is given by:

\( pH = -log([H^{+}]) \)

\( pH = -log(0.73) = 0.14 \)          

Therefore, the original pH of the acid is 0.14.

I hope it helps you!                  

Answer:

Ver explicacion

Explanation:

Cristalización y disolución de cloruro de sodio: equilibrio físico dinámico

Conversión de oxígeno gaseoso en ozono - equilibrio químico

Condensación y evaporación de un líquido - equilibrio físico dinámico

Reacción entre H2 y 12 para producir Hl - equilibrio químico

Una solución saturada de azúcar - equilibrio físico dinámico

El equilibrio alcanzado en los procesos físicos se llama procesos físicos. El equilibrio físico se llama. Ejemplos de tales procesos físicos incluyen; condensación y evaporación, cristalización y disolución, etc.

Un equilibrio dinámico ocurre en un sistema químico cuando la reacción directa y la reacción inversa se desarrollan a la misma velocidad.

Answer:

cells comes from preexisting cells through the process of cell division

Answer:

The spine is also designed to protect your spinal cord. The spinal cord is a column of nerves that connects your brain with the rest of your body, allowing you to control your movements. Without a spinal cord, you could not move any part of your body, and your organs could not function.

The process of dissolution of KBr in water occurs because the final solution has a lower energy state than the two components separately.

What do you mean by endothermic?

Endothermic reactions are chemical reactions that absorb energy from their surroundings in order to proceed. This energy is usually in the form of heat and is absorbed from the surroundings in order to drive the reaction forward.

Even though the dissolution process is endothermic, it occurs because the enthalpy of solution is less than the sum of the enthalpies of the two components separately. The enthalpy of solution is the energy required to break the strong ionic bonds between the KBr molecules, allowing them to dissolve into the solution. The energy released from the formation of new hydrogen bonds between the KBr molecules and the water molecules is greater than the energy needed to break the ionic bonds, resulting in a net release of energy. This release of energy causes the overall process to be exothermic, even though the dissolution of KBr into water is endothermic.

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Answer:

polyatomic ion

Explanation:

Answer and Explanation: A group of covalently bonded atoms that has an overall electrical charge is called a polyatomic ion, which is the choice c.

The diffusion of food coloring molecules in water demonstrates an increase in entropy as the system transitions from a state of lower concentration to a state of higher concentration, aligning with the Second Law of Thermodynamics.

The Second Law of Thermodynamics states that the entropy of an isolated system tends to increase over time. Entropy is a measure of the system's disorder or randomness. A gradient in concentration initially appears when a few drops of food colouring are applied to water. The water molecules are more equally dispersed, whereas the food colouring molecules are concentrated in one place. The food colouring molecules undergo diffusion over time, shifting from one region of high concentration to another region of lower concentration until they are evenly distributed throughout the water. The system switches from a lower entropy (more ordered) to a higher entropy (more disordered) state during this process. The food coloring molecules increase the system's overall disorder or unpredictability as they disperse more randomly within the water. Entropy increases are predicted by the Second Law of Thermodynamics, which states that isolated systems tend to gravitate over time towards states of greater disorder. In conclusion, the diffusion of food colouring molecules in water exhibits an increase in entropy as the system becomes more complex. Transitions from a state of lower concentration to a state of higher concentration, aligning with the Second Law of Thermodynamics.

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Answer: No

Explanation:  The snacks did not work because the result of the snails either stayed the same, or decreased.

The electronic configuration of V5+ is [Ar]3d3. This means that it has three electrons in its 3d orbitals and no electrons in its 4s, 4p, and 4d orbitals.

The electronic configuration of an atom describes the arrangement of electrons in the atomic orbitals of that atom. In the case of V5+, the electronic configuration is [Ar]3d3, which can be understood as follows:

It is important to note that V5+ as an ion has lost 5 electrons. This means that it has lost the electrons from its 4s, 4p, and 4d orbitals, leaving only the electrons in its 3d orbitals. So no electrons are in 4s, 4p, and 4d orbitals.

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The mole ratio can be seen below and the volume of each precipitate is 60 mL.

A mole ratio refers to a conversion factor that compares the quantities of two chemicals in moles in a chemical laboratory experiment.

Mole ratio For 1:

Mole ratio For 2:

Mole ratio For 3:

Mole ratio For 4:

Mole ratio For 5:

Mole ratio For 6:

Mole ratio For 7:

Since the parameters from the left side of the diagram are not shown, we will assume that the volumes for each precipitate are the addition of both volumes in each column.

By doing so, we have:

1.

2.

3.

4.

5.

6.

7.

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Answer:

Chemical change

Explanation:

Because it will be 2 mixtures of each substances making it 1 substance, and 1 change.

220 grams are there in 5 moles of CO₂.

Mole is defined as the mass of a system whose elementary constituents total the number of atoms in 0.012 kilograms of carbon 12. Any material has a molecular weight of 6.023 x 10²³. It can be used to quantify the results of a chemical reaction. The term "Molarity" is derived from the unit of measurement called a mole, which is used to describe chemical substances.

To get an object's mass, divide its weight by the acceleration of gravity.

As we know that mass of CO₂ is 44 gram.

The mass in grams of one mole of any chemical is known as its molar mass.

Number of moles = Mass of substance / Mass of one mole.

1  mole = 44 gram of CO₂

So 5 mole = 44 gram x 5

                 = 220 gram of CO₂

Thus, 220 grams are there in 5 moles of CO₂.

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Answer:

I think the answer is 800J

Explanation:

As the kinetic energy goes down, the potential energy goes up

Answer:

17190 years          

Explanation:

The exponential decay equation is:

\( N_{t} = N_{0}e^{-\lambda t} \)          

\( \frac{N_{t}}{N_{0}} = e^{-\lambda t} \)

Where:

N(t) is the quantity at time t

N₀ is the initial amount

λ is the decay constant = ln(2)/t(1/2)

t(1/2) is the half-life    

Since the ratio of carbon-14 to carbon-12 is 12.5%, we have that:

\( \frac{N_{t}}{N_{0}} = e^{-\lambda t} \)

\( \frac{0.125N_{0}}{N_{0}} = e^{-\lambda t} \)

\( ln(0.125) = -\lambda t \)

By solving the above equation for t:

\( t = \frac{ln(0.125)}{-\lambda} = \frac{ln(0.125)}{-ln(2)/t_{1/2}} = \frac{5730 y* ln(0.125)}{-ln(2)} = 17190 y \)

Therefore, the site is 17190 years old.  

I hope it helps you!

1) Noble gases. Elements in the periodic table are organized in groups. We can find the noble gases in the eighteenth group (column).

2) Zoom in to the right part of the periodic table.

We can see in this image that Krypton (Kr), Neon, and Argon ARE noble gases.

Iron is NOT a noble gas.

.

The mass of the silver sample is approximately 77.9 grams.

To solve this problem, we can utilize the equation for heat transfer:

q = m * c * ΔT

where q represents the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Initially, we calculate the heat transferred from the silver to the water:

q silver = m silver * c silver * ΔT silver

q water = m water * c water * ΔT water

For thermal equilibrium between the silver and water, we equate the two equations as they reach the same temperature:

q silver = q water

m silver * c silver * ΔT silver = m water * c water * ΔT water

Rearranging the equation allows us to solve for the mass of the silver:

m silver = (m water * c water * ΔT water) / (c silver * ΔT silver)

Substituting the given values:

m silver = (250g * 4.184 J/g°C * (23.35°C - 6.5°C)) / (0.235 J/g°C * (98.75°C - 23.35°C))

As a result:

m silver = 77.9 g

Thus, the mass of the silver sample is approximately 77.9 grams.

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Decane react with 31/2 O₂  to yield 10CO₂ and 11H₂O.

Reaction is given below:-

C₁₀H₂₂ + 31/2 O₂ → 10CO₂ + 11H₂O

Hence, Decane react with 31/2 O₂  to yield 10CO₂ and 11H₂O.

Molecular oxygen, O₂ is a diatomic molecule that is composed of two oxygen atoms held together by a covalent bond. Molecular oxygen is essential for life, as it is used for respiration by many organisms.

Diatomic means that an atom cannot exist by itself. There is no such thing as lone O atoms floating around the atmosphere. Oxygen exists as O₂ .

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Answer:

1.37 L

Explanation:

(87.0)(0.492)(643)÷(39.1)(515)

27522.972 ÷ 20136.5

=

1.36682005314

↓

1.37 (Rounded)

Hope this Helps!

Answer:

1.37 L

Explanation:

XD

We have been given the mass percentage of each element in the compound and its molar mass. To find the empirical formula of the compound, we need to follow the given steps:

Calculate the number of moles of each element using its mass percentage.

Calculate the simplest whole number ratio of the atoms using the number of moles. Divide each of the atoms' subscripts by the smallest number obtained in the previous step. Write the empirical formula of the compound. The given compound has 43.64% of Phosphorous (P) and 56.36% of Oxygen (O) by mass. Let's calculate the number of moles of each element.1. For Phosphorous (P):Mass percentage of P = 43.64%Atomic mass of P = 31 g/mol .Molar mass of the compound = 283.39 g/mol.

Number of moles of P in the compound= (43.64/100) * (283.39 g/mol) / (31 g/mol) = 3.996 moles2. For Oxygen (O):Mass percentage of O = 56.36%.

Atomic mass of O = 16 g/molMolar mass of the compound = 283.39 g/molNumber of moles of O in the compound = (56.36/100) * (283.39 g/mol) / (16 g/mol) = 11.994 molesNow, to find the simplest whole number ratio of the atoms, we can divide the above values by the smaller of the two, i.e., 3.996.3.996/3.996 = 1 for P11.994/3.996 = 3 for OTherefore, the empirical formula of the compound with 43.64% P and 56.36% O and a molar mass of 283.39 g/mol is P1O3.

From the given information, we have to calculate the empirical formula of a compound with 43.64% P and 56.36% O and a molar mass of 283.39 g/mol. We can calculate the empirical formula of a compound from its percentage composition or elemental composition, which is given to us.The empirical formula of a compound is the simplest whole number ratio of the atoms present in the compound.

To determine the empirical formula of a compound, we need the mass percentage of each element present in the compound and its molar mass. The molar mass of the compound is the sum of the atomic mass of all atoms present in it.To calculate the empirical formula of the compound, we will first calculate the number of moles of each element. The formula for calculating the number of moles is:

Number of moles = Mass / Molar mass.

Once we know the number of moles of each element, we can find the simplest whole number ratio of atoms present in the compound. To find the simplest whole number ratio, we will divide the number of moles of each element by the smallest number of moles among the elements.The smallest number of moles is 3.996, which is the number of moles of P. We can calculate the number of moles of O by the same formula. By dividing 11.994/3.996, we get 3. Therefore, the empirical formula of the compound is P1O3.The empirical formula of the compound with 43.64% P and 56.36% O and a molar mass of 283.39 g/mol is P1O3.

The empirical formula of the compound with 43.64% P and 56.36% O and a molar mass of 283.39 g/mol is P1O3. We can calculate the empirical formula of a compound by knowing the mass percentage of each element in the compound and its molar mass. The empirical formula of a compound is the simplest whole number ratio of atoms present in the compound.

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