for the logistic function f(x)=100/(1 5(0.8)^-x)

Answer:

The first one is B, because it say time (hours) so it makes it to be the unit rate of the graph in miles per hour. So the answer is B i hope you understand

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Answer:

Yes, it is!!!

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Answer:

210

Note: this answer might be incorrect because of the value of music (212). This doesn't make logical sense.

Step-by-step explanation:

Hello,

This question can easily be solved through the use of a venn diagram.

Total number of students = 55

Number of medals in sport = 40 = A

Number of medals in dance = 25 = B

Number of medals in music = 212 = C

Number of students that got award in the three categories = (AnBnC) = 6

n(AuBuC) = 55

n(AnB) + n(BnC) + n(AnC) - 3n(AnBnC) =

n(AnB) + n(AnB) + n(AnC) -3×6 ......equation (i)

n(AuBuC) = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

Therefore,

n(AnB) + n(BnC) + n(AnC) = n(A) + n(B) + n(C) + n(AnBnC) - n(AuBuC)

n(A) + n(B) + n(C) + n(AnBnC) - n(AuBuC) - 18

40 + 25 + 212 + 6 - 55 - 18 = 210

Note: this answer might be incorrect because of the value of C (music)

In summary, the Fourier coefficients for the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5 are:

c₀ = -3 (DC component)

cₙ = 0 for n ≠ 0 (other coefficients)

To find the Fourier coefficients of the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5, we can use the formula for Fourier series coefficients:

cn = (1/T) ∫[t₀-T/2, t₀+T/2] y(t) \(e^{(-i2\pi nt/T)}\) dt

where T is the period of the function and n is an integer.

In this case, the function y(t) is constant, y(t) = -3, and the period is T = 10 (since the interval -5 ≤ t ≤ 5 spans 10 units).

To find the Fourier coefficient c₀ (corresponding to the DC component or the average value of the function), we use the formula:

c₀ = (1/T) ∫[-T/2, T/2] y(t) dt

Substituting the given values:

c₀ = (1/10) ∫[-5, 5] (-3) dt

  = (-3/10) \([t]_{-5}^{5}\)

  = (-3/10) [5 - (-5)]

  = (-3/10) [10]

  = -3

Therefore, the DC component (c₀) of the Fourier series of y(t) is -3.

For the other coefficients (cₙ where n ≠ 0), we can calculate them using the formula:

cₙ = (1/T) ∫[-T/2, T/2] y(t)\(e^{(-i2\pi nt/T) }\)dt

Since y(t) is constant, the integral becomes:

cₙ = (1/T) ∫[-T/2, T/2] (-3) \(e^{(-i2\pi nt/T)}\) dt

  = (-3/T) ∫[-T/2, T/2] \(e^{(-i2\pi nt/T)}\) dt

The integral of e^(-i2πnt/T) over the interval [-T/2, T/2] evaluates to 0 when n ≠ 0. This is because the exponential function oscillates and integrates to zero over a symmetric interval.

all the coefficients cₙ for n ≠ 0 are zero.

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The volume of the snowball decreasing at the rate of 376.8 cm³/min when the radius is 10 cm and its radius is decreasing at a rate of 0.3 cm/min.

Volume is defined as the space occupied by an item inside the confines of three-dimensional space. It is also known as the object's capacity. Volume is the entire amount of space occupied by an item in three dimensions. The ability of something (such as a solid substance, gas, or liquid) to hold, absorb, or receive by an item is referred to as capacity.

Here,

dr/dt=-0.3 cm/min

v=4πr³/3

dv/dt=4πr².dr/dt

here r=10 cm

=4π*10²*0.3

=4*3.14*100*0.3

dv/dt=376.8 cm³

When the radius is 10 cm, the volume of the snowball decreases at a rate of 376.8 cm³/min, and its radius decreases at a rate of 0.3 cm/min.

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The diameter οr radius οf the circular οbject is 120mm, and the circumference οf the οbject 1 frοm the centre tο the edge οf a DVD is 380mm.

A circle's οr an ellipse's circumference is its perimeter. In οther wοrds, if the circle were tο be straightened οut alοng a line segment, the length οf the arc wοuld be the circumference. The perimeter is mοre frequently used tο refer tο the length οf the curve surrοunding any defined figure.

The given infοrmatiοn is that a DVD's edge is 60 mm lοng.

The diameter, radius, and circumference οf the circular οbject must be determined in οrder tο determine the measurement.

We cοncluded that

Radius = 60mm

Diameter = 120mm

Circumference = 380mm

Hence, Diameter = 120mm

Circumference = 380mm

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Answer:

79

Step-by-step explanation:

The division of 6x⁴ + 11x³ + 13x² - 3x + 27 by 3x + 4 will have a quotient of 2x³ + x² +3x -5 and a remainder of 47 using the remainder theorem.

The remainder theorem states that if a polynomial say f(x) is divided by x - a, then the remainder is f(a).

We shall divide the 6x⁴ + 11x³ + 13x² - 3x + 27 by 3x + 4 as follows;

x⁴ divided by 3x equals 2x³

3x + 4 multiplied by 2x³ equals 6x⁴ + 8x³

subtract 6x⁴ + 8x³ from 6x⁴ + 11x³ + 13x² - 3x + 27 will give us 3x³ + 13x² - 3x + 27

3x³ divided by 3x equals x²

3x + 4 multiplied by x² equals 3x³ + 4x²

subtract 3x³ + 4x² from 3x³ + 13x² - 3x + 27 will give us 9x² - 3x + 27

9x² divided by 3x equals 3x

3x + 4 multiplied by 3x equals 9x² + 12x

subtract 9x² + 12x from 9x² - 3x + 27 will give us -15x + 27

-15x divided by 3x equals -5

3x + 4 multiplied by -5 equals -15x - 20

subtract -15x - 20 from -15x + 27 will result to a remainder of 47

using the remainder theorem, x = -4/3 from the the divisor 3x + 4

thus:

f(-4/3) = 6(-4/3)⁴ + 11(-4/3)³ + 13(-4/3)² - 3(-4/3) + 27 {putting the value -4/3 for x}

f(-4/3) = (1536/81) - (704/27) + (208/9) + (12/3) + 27

f(-4/3) = (1536 - 2112 + 1872 + 324 + 2157)/81 {simplification by taking the LCM of the denominators}

f(-4/3) = (5919 - 2112)/81

f(-4/3) = 3807/81

f(-4/3) = 47

Therefore, the quotient of after the division of 6x⁴ + 11x³ + 13x² - 3x + 27 by 3x + 4 is 2x³ + x² +3x -5 and there is the remainder of 47 using the remainder theorem.

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Answer:

The axis of symmetry is (0,0)

Step-by-step explanation:

This is the picture

the solution for the number of tigers present over time is given by:

P - (P^2)/(2K) - (T/K)P + (T/K)ln(P) = rt + 11.375 + 0.1ln(15)

To solve the given differential equation for the population of Bengal tigers in the conservation park, we'll use the given parameters and initial conditions.

The differential equation for the population (P) is:

P't = rp(1 - P/K)(1 - T/P)

Given:

Carrying capacity (K) = 100

Minimum threshold value for survival (T) = 10

Population growth rate (r) = 1% = 0.01 (per year)

Initial population (P0) = 15

Now, let's solve the differential equation to find the number of tigers present over time.

Separating variables, we have:

(1 - P/K)(1 - T/P) dP = rp dt

Integrating both sides:

∫ (1 - P/K)(1 - T/P) dP = ∫ rp dt

Let's evaluate the integral on the left side:

∫ (1 - P/K)(1 - T/P) dP = ∫ (1 - P/K - T/K + T/(KP)) dP

= ∫ (1 - P/K) - (T/K) + (T/PK) dP

= P - (P^2)/(2K) - (T/K)P + (T/K)ln(P) + C1

On the right side, we have:

∫ rp dt = rt + C2

Combining both sides and simplifying, we have:

P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) + C1 = rt + C2

To solve for the constants C1 and C2, we use the initial condition P(0) = P0:

P0 - (P0²2)/(2K) - (T/K)P0 + (T/K)ln(P0) + C1 = r(0) + C2

P0 - (P0²2)/(2K) - (T/K)P0 + (T/K)ln(P0) + C1 = C2

Substituting the given values:

15 - (15²2)/(2×100) - (10/100)×15 + (10/100)ln(15) + C1 = C2

15 - (225/200) - (150/100) + (10/100)ln(15) + C1 = C2

15 - 1.125 - 1.5 + 0.1ln(15) + C1 = C2

Simplifying further, we have:

12.375 + 0.1ln(15) + C1 = C2

Now we have the general solution:

P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) = rt + C

Using the initial condition P(0) = 15, we can solve for C:

15 - (15²2)/(2×100) - (10/100)×15 + (10/100)ln(15) = r(0) + C

15 - 1.125 - 1.5 + 0.1ln(15) = C

11.375 + 0.1ln(15) = C

Therefore, the solution for the number of tigers present over time is given by:

P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) = rt + 11.375 + 0.1ln(15)

This is the general solution for the population of Bengal tigers in the conservation park.

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To design the table, you could create a "Sports" table and a "Patient-Sport" table with the following fields:

Sports table:                                      Patient-Sport table:

SportID (primary key)                        PatientID (foreign key)

SportName                                        SportID (foreign key)

A database is a collection of organized data stored and retrieved electronically. It is designed to allow efficient storage, retrieval, manipulation, and management of large amounts of data. Databases can be used to store information such as text, numbers, images, and other media. The data in a database is typically organized into tables, which are made up of rows and columns. Each row represents a single record, and each column represents a field of information within that record. There are many different types of databases, including relational databases, NoSQL databases, and in-memory databases, and they are used in a wide range of applications, such as online retail, finance, healthcare, and more.

The Patient-Sport table is used to connect the patient to the sport they are playing. This allows for multiple sports to be assigned to a single patient. In this way, you can track the sports played by each patient, while still maintaining the relationships between the patient and their data in the other tables.

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From the total of 300 workers in the factory :

a. Number of men = 200 and Women = 100

b. Number of workers works in the morning = 225

c. Number of workers unionized are 150.

d. Number of workers trustworthy are 50.

Total number of workers in the factory are 300.

a. Fraction of men in the factory are ( 2/3)

= 2/3 of 300

= 200

Women

= 300 -200

= 100

b. Number of workers in the morning shift are

= 3/4 of 300

= 225

c. Total number of workers unionized

= 1/ 2 of 300

= 150

d. Number of trustworthy workers

= 1/6 of 300

= 50

Therefore, out of 300 workers in the factory answer of the following questions are:

a. Number of men and women work in the factory are 200 and 100 respectively.

b. Number of workers works in the morning is 225.

c. Unionized workers = 150

d. Trustworthy workers = 50.

The above question is incomplete , the complete question is :

The Factory has 300 workers of which 2/3 are men, 3/4 work in the morning, 1/2 are unionized and 1/6 are trusted personnel.

a. How many men work in the factory and how many women?

b. How many workers work in the morning?

c. How many are unionized?

d. How many are trustworthy?

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Answer:

Use a website called Desmos and click on the graphing calculator

Step-by-step explanation:

Type all of those equations in the graphing calculator and the one that is the same as the graph above is the correct one!

Answer:

Since it’s negative it will have a negative slope so it would be down to a, b, c

Then look at the y intercept which is 2 and it’s positive so it would be c

Answer:C

Answer:

688.1 cm

Step-by-step explanation:

Area of circle = (π)r^2

Area= π × 14.8^2

Area = 688.1 cm^2 (to the nearest tenth)

Answer:

a= -8.33

Step-by-step explanation:

it will be deceleration because he was 12 m/s then go to 4.5 m/s

and by applying moving equation

\(v_{2}\)=\(v_{1}\)+at

we have all but not have a  

The a = 0.Substituting the values of a, b, and c in the general equation, we get:y = 0x² + 2x + 3The quadratic function is:y = 2x + 3Answer: The quadratic function is y = 2x + 3.

The given table illustrates the values of a quadratic function. Here is how you can find the quadratic function:Step 1: Write the general form of a quadratic function y = ax² + bx + c, where y is the dependent variable and x is the independent variable. a, b, and c are constants that affect the shape and position of the parabola.Step 2: Substitute the values from the table for x and y to form a system of equations.Step 3: Solve the system of equations to find the values of a, b, and c. Once you have found these values, substitute them into the quadratic equation to get the quadratic function.

The given table is as follows:x   |  0   |  2   |  4  |   6y   |  3   |  1   |  -1  |   -3Step 2:Form a system of equations using the values in the table. Here are the equations:y = a(0)² + b(0) + cy = a(2)² + b(2) + cy = a(4)² + b(4) + cy = a(6)² + b(6) + cStep 3:Solve the system of equations.Using the first equation, y = c. Hence, we have:y = 0²a + 0b + c3 = cThe value of c is 3.Using the second equation, we have:y = 2²a + 2b + 3y = 4a + 2b + 3Subtracting the two equations, we get:- 2a - b = - 2a + b = 2b = 4Therefore, b = 2.Substituting the values of b and c into the first equation, we get:3 = a(0)² + 2(0) + 3

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Answer:

1137

Step-by-step explanation:

5675+453

6128

Now

7265-6128

1137

the total amount of oil that leaks out over the entire time interval [0, 120].

integral ∫₀¹₂₀ r(t) dt represents the total amount of oil that leaks from the tank in 120 minutes.

To see why, consider the definition of an integral. If we divide the interval [0, 120] into small subintervals of width Δt, then the amount of oil that leaks out during each subinterval is approximately r(t)Δt. Summing up all these small amounts over the entire interval gives:

Σᵢ r(tᵢ) Δt

where tᵢ is the midpoint of the i-th subinterval. As we take the limit as the subinterval width goes to zero, this sum becomes the integral:

∫₀¹₂₀ r(t) dt

which represents the total amount of oil that leaks out over the entire time interval [0, 120].

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Answer:

9 hr * 60 min/hr = 540 min. 540 min * 60 sec/min = 32,400 sec. Use the method described by panic mode: round the number down until there is only one non-zero digit left. Here, 32,400 rounds down to 30,000. Now count the number of zeroes; the result is the order of magnitude: 4. (You see this in scientific notation also: 30,000 = 3 × 10^4.)

3) The two triangles that are congruent are:

ΔRST ≅ ΔTMN

4) The two triangles that are congruent are:

ΔDEF ≅ ΔEDC

5) The value of the missing side x is: x = 13.9

6) The value of the missing side x is: x = 8.5

Some of the postulates to determine that two triangles are congruent are:

SAS

SSS

ASA

AAS

HL

3) The two triangles are congruent by SSS Congruency as they have three congruent sides. Thus:

ΔRST ≅ ΔTMN

4) The two triangles are congruent by SSS Congruency as they have three congruent sides. Thus:

ΔDEF ≅ ΔEDC

5) Using trigonometric ratios, we have:

10/x = cos 44

x = 10/cos 44

x = 13.9

6) Using trigonometric ratios, we have:

x/20 = tan 23

x = 20 * 23

x = 8.5

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Answer:

3xy=96  2y2-z2=12

Step-by-step explanation:

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

Answer:

An equivalant faction would be 10/12

Step-by-step explanation:

Answer:

10/12

Step-by-step explanation:

12/6 = 2

5/6 * 2/2 = 10/12

Answer: 10/12

Answer:

I believe it's c.

Step-by-step explanation:

Starts and includes 2, goes until and includes 5.

Answer:

C

Step-by-step explanation:

Domain represents the possible x-values and the line on the graph only runs through x-values between 2 and 5.

The probability of color coming up the same for rolling two 20-sided dice is 129/400.

Probability is defined as how likely something is to happen. For a single dice, getting a maroon, teal, and cyan have a probability of 4/20, 7/20, and 8/20, respectively.

Before solving the probability, we must identify whether the events are considered independent or dependent. Independent events are when the probability of an event happening does not affect the other's event probability of happening. A dependent event is when the probability of an event happening affects the other event. The rolling of dice is considered an independent event.  

For events that should occur together, the multiplication rule is used. To solve for the probability of two sides coming up the same, the formula below is used.

P (A and B) = P (A) * P (B)

P (red and red) = (4/20)*(4/20) = 1/25

P (teal and teal) = (7/20)*(7/20) = 49/400

P (cyan and cyan) = (8/20)*(8/20) = 4/25

Since no specific color was stated in the problem, the sum of the probability of each color coming up the same is determined.

P (color come up the same) = P (red and red) + P (teal and teal) + P (cyan and cyan)

P (color come up the same) = 1/25 + 49/400 + 4/25

P (color come up the same) = 129/400

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In the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

The domain refers to the set of possible inputs or variables in a given context. In this case, the scatterplot is being created based on the relationship between the time students spent studying and their corresponding test grades. Therefore, the domain in this context would be the number of minutes the students studied (option D).

The domain represents the independent variable, which is the variable that is controlled or manipulated in the analysis. In this scenario, the math teacher wants to analyze the relationship between studying time and test grades, so the number of minutes studied would be the independent variable. The teacher surveys the students to collect data on the time spent studying, and this variable becomes the domain of the scatterplot.

The range, on the other hand, represents the dependent variable, which is the variable that is measured or observed as an outcome or response. In this case, the dependent variable would be the students' test grades. The scatterplot will show how the test grades correspond to the amount of time students studied.

To summarize, in the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

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Answer:

Work the problem backward

Step-by-step explanation:

instead of 10-x=25 do 25-10 = x So yeah that should give you the variable X

Answer:

-15

Step-by-step explanation:

10-x=25

take away 10 from both sides of the equation.

-x = 15

divide by - (-1) to get x

x = -15

The length of the base edge of the square pyramid is 6 feet.

The surface area of a square pyramid is 96 square feet. The height is two thirds of the length of the base edge.

The length of the base edge can be found as follows:

Hence,

surface area of square pyramid = a² + 2al

where

Therefore,

using Pythagoras's theorem, let find the slant height of the pyramid.

c² = a² + b²

where

Hence,

height = 2 / 3 a

Therefore,

l² = (2 / 3 a)² + (1 / 2a )²

l² = 4 / 9 a² + 1 / 4 a²

l² = 25 / 36 a²

square root both sides

l = 5 / 6 a

Hence,

surface area of square pyramid = a² + 2a(5 / 6 a)

surface area of square pyramid = a² + 10 / 6 a²

surface area of square pyramid = 16 / 6 a²

96 = 16 / 6 a²

96 = 8 / 3 a²

cross multiply

96 × 3 = 8a²

288 / 8 = a²

a² = 36

a = √36

a = 6 feet

Therefore, the base length is 6 feet.

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