Answers
The radius of strut so that the round and struts have same cross-sectional area = 2.764 mm and the critical load of a strut = 3.95*\(10^{-3}\).
Let Radius for a round strut = 'r'
Now, Square Strut:
As, method Cross Section is 24 X 1 (\(mm^{2}\))
So, Area, A' of cross-section = 24*1 = 24 \(m^{2}\)
>> As, Area of round cross-section, A = pi*\(r^{2}\)
Now, Given that, Both have same cross-section area
=> pi*\(r^{2}\) = 24
Solving,
=> r = radius of round cross-section = 2.764 mm
>> Now, According to Buckling Criteria,
Critical Load for a Stru, Pcr = (pi*\(r^{2}\)*E*I)/Le\(q^{2}\)
>> Now, as both Struts or columns are simple supported at both ends
So, Leq = L = 1 m
Also, E = 200 GPa = 200*\(10^{9}\) N/m2
Now, I = Moment of Inertia
As, For Round Strut,
I = pi*\(r^{4}\)/4 = pi*2.7644/4 = 45.837 = 45.837*\(10^{-12}\)
=> Pcr = pi*\(r^{2}\)*200*109*45.837*10-12/12
Solving,
=> Pcr = 0.0905 kN (CRITICAL LOAD FOR ROUND)
>> Now, For Strut,
As, Buckling places about axis with minimum Moment of Inertia
So, Imin = a*\(b^{3}\)/12 = 24*1*1*1/12 = 2 = 2* \(10^{-12}\)
So, Putting every values in Critical Equation:
Pcr = p\(i^{2}\)*200*\(10^{-9}\)*2*\(10^{-12}\)/12
=> Pcr = 3.95*\(10^{-3}\) kN (REQUIRED CRITICAL LOAD STRUT)
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Related Questions
The geothermal gradient is defined as the increase in temperature with depth in the Earth. In normal continental crust a typical geothermal gradient within the first 3 to 5 kilometers (2 or 3 miles) of Earth’s surface is about 25°C/km. This gradient, however, is not sustained but decreases to no more than about 16°C/km at a depth of 40 km.
Answers
The geothermal gradient is a gradient of the increase in temperature of the earth with depth.
What is the geothermal gradient?The geothermal gradient is defined as the increase in temperature with depth in the Earth.
It describes how the increase in the depth of the earth results in a proportional increase in temperature.
The steepness of the geothermal gradient increases as one goes from the lithosphere to the core of the earth.
This gradient, however, is not sustained but decreases to no more than about 16°C/km at a depth of 40 km.
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In this lab, we will determine the capacitance, C1, of an unknown capacitor by which of the following methods? A) Observe the potential difference between the plates of unknown capacitor, C1, when it is charged by the source (battery, dry cell or power supply) and when it is fully discharged. B) Charge a known capacitance, Cz to a known voltage, then add C1 to the circuit and measure the charge on C1 C) Charge C1 to a known voltage, disconnect it from the charge source, then measure the voltage change when C1 is connected to a known capacitor. D) Charge C1 to a known voltage then measure its capacitance with a capacitance meter.
Answers
The method used in this lab to determine the capacitance, C1, of an unknown capacitor involves charging a known capacitance, Cz, to a known voltage, and then adding C1 to the circuit and measuring the resulting charge on C1. Option B is the correct choice.
This method is based on the fact that the total charge in a series circuit must be the same on all capacitors, and that the charge on each capacitor is proportional to its capacitance. By measuring the voltage across Cz and the charge on Cz and C1,
C1 = (Q - Qz) / V
where Q is the charge on both capacitors, Qz is the charge on Cz, and V is the voltage across C1. Option B is the correct choice.
Option A is not a suitable method as it only provides information about the potential difference between the plates of the unknown capacitor, but does not give any information about the capacitance itself.
Option C is not a suitable method as it involves measuring the voltage change when C1 is connected to a known capacitor, but this does not give any information about the capacitance of C1.
Option D is not a suitable method as it involves measuring the capacitance of C1 directly with a capacitance meter, but this would require knowing the capacitance of the meter's own internal components and may not be accurate or feasible in all cases.
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If you answer it I’ll love you forever!!!
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
questions
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Discuss the value of doing "Performance Evaluation Tests" on athletes.
Answers
Answer:
ok my answer was They measure an athlete's performance in that area being tested. This is done to compare to past performance evaluation tests and to measure if the athlete is getting better or worse. It also determines if the athlete should stop or keep doing his/her sport.
Explanation:
is that good :)
Answer:
They gauge how well an athlete performs in the area that is being evaluated. This is done to assess if the athlete is improving or degrading in comparison to previous performance evaluation exams. It also determines whether the athlete should give up or continue practicing their sport.
Explanation: 100% on Edge 2022
how does mass relates to latent heat?
Answers
The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.
What is latent heat?Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.
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Analysis and Conclusion.
1. Which compound dissolved more easily?
2. Which compound had the lower boiling point?
3. Are the answers to 1 and 2 the same compound? What does this tell you about the strength
of the bonds in this compound?
4. Which compound is the sugar?
5. Which compound is the salt?
Answers
The compound identified as sugar would be the organic compound, such as sucrose (C12H22O11).The compound identified as salt would be the ionic compound, such as sodium chloride (NaCl).
To determine which compound dissolved more easily and had the lower boiling point, we need more specific information about the compounds being compared. However, assuming we are comparing a typical organic sugar compound, such as sucrose (C12H22O11), with a common ionic salt compound, such as sodium chloride (NaCl), we can draw some conclusions.
The salt compound (NaCl) would generally dissolve more easily than the sugar compound (C12H22O11). This is because salt is composed of ions, which readily dissociate in water due to the polar nature of water molecules. Sugar, on the other hand, is a covalent compound and requires breaking of covalent bonds for dissolution, which is typically a slower process.
The sugar compound (C12H22O11) would generally have a higher boiling point compared to the salt compound (NaCl). Covalent compounds tend to have higher boiling points than ionic compounds due to the stronger intermolecular forces between covalent molecules.
No, the answers to 1 and 2 do not refer to the same compound. The strength of the bonds in the sugar compound (covalent) is different from the strength of the bonds in the salt compound (ionic).
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Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
Answers
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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Plot a graph of the pendulum period, T, vs. mass, m, using LabQuest App or graph paper. Scale each axis from the origin (0,0). Does the period appear to depend on mass? Do you have enough data to answer this conclusively?
Answers
Given a graph of the period versus the mass.
From the graph, the plot of the period versus mass is almost a horizontal line. That is as the mass of the pendulum increases, its period remains constant. The period of the pendulum is unaffected by the change in the mass. Thus the period of the pendulum does not depend on its mass.
This is also consistent with the formula of the period which is,
\(T=2\pi\sqrt[]{\frac{L}{g}}\)Where L is the length of the pendulum and g is the acceleration due to gravity.
As seen from the formula the period of the pendulum does not depend on the mass of the pendulum.
Therefore the period of the pendulum does not depend on its mass, this is conclusive from the given data.
m
An ostrich accelerates from rest until reaching a speed of 6.0 A graph of the ostrich's velocity over time
is shown below.
S
Velocity
()
6+
3+
Time (s)
3 6 9 12 15 18
What is the ostrich's average acceleration from 9.0 to 18 seconds?
O
Answers
Answer:
0 m/s2
Explanation:
khan
A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
Answers
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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suppose future astronauts are living on a martian base when a major solar flare occurs. how long will it be before the charged particles ejected from the sun during the flare reach them? (hint: use the data in the text to calculate this.)
Answers
In 755.7 seconds, they were able to see the sun during the flare.
Briefly:-the distance between the Sun and Mars is 226.71 * 109 meters.
Speed of light is equal to 3 * 108 m/s.
Speed equals time/distance
Time = Speed/Distance
Time = (226.71 * 10^9)/(3 * 10^8)
Time = 755.7 s
How long does a solar flare take to occur?The bursts of energetic particles known as solar flares usually originate from sunspots on the surface of the sun. These intense bursts of radiation arrive at Earth in less than 10 minutes at the speed of light, yet the magnetosphere of our planet prevents the majority of them from reaching the surface.
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John runs 1.0 m/s at first, and then accelerates to 1.6 m/s during
the course of 4.5 seconds. What is his average acceleration (in
m/s2
Answers
Answer: \(0.13m/s^2\)
Explanation:
\(Formula: a=\frac{V_2-V_1}{t}\)
Where;
a = acceleration
V2 = final velocity
V1 = initial velocity
t = time
If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.
\(a=\frac{1.6m/s-1.0m/s}{4.5s}\)
\(a=\frac{0.6m/s}{4.5s}\)
\(a=0.13m/s^2\)
Answer:.13
Explanation:
If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'
Answers
Answer: Distance traveled in time t is s
Explanation: Self Explanatory
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
Answers
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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A body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest. Calculate their common velocity of the two bodies coalesce after collision
Answers
When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.
When two objects of different masses collide, they can exchange momentum. An object's mass and velocity together make up its momentum. When two objects collide, their momentum is conserved, meaning that the total momentum of the two objects before the collision equals the total momentum of the two objects after the collision. This principle can be used to calculate the velocity of the two objects after a collision.A body of mass 12 kg is travelling at a velocity of 4.2 m/s and collides with a second body of mass 18 kg at rest. The total mass of the system is 12 kg + 18 kg = 30 kg. To determine the velocity of the two objects after the collision, we need to use the conservation of momentum principle. Before the impact, the system's entire momentum is:momentum before = \((mass_1 x velocity_1) + (mass_2 x velocity_2)\)where mass1 is the mass of the first object, velocity1 is the velocity of the first object, \(mass_2\) is the mass of the second object, and \(velocity_2\) is the velocity of the second object. In this case,\(mass_1 = 12 kg, velocity_1 = 4.2 m/s, mass_2 = 18 kg\), and \(velocity_2 = 0\) (because the second object is at rest). Substituting these values into the equation above, we get: momentum before = (12 kg x 4.2 m/s) + (18 kg x 0)momentum before = 50.4 kg m/sFollowing the collision, the system's overall momentum is:momentum after =\((mass_1 + mass_2) * velocity\)where mass1 + mass2 is the total mass of the system, and velocity is the velocity of the two objects after the collision. Let's call this velocity "v". Substituting the values we know into the equation above, we get: momentum after = (12 kg + 18 kg) x vmomentum after = 30 kg x vUsing the conservation of momentum principle, we know that momentum before = momentum after. Therefore, we can set these two equations equal to each other and solve for v.50.4 kg m/s = 30 kg x vv = 50.4 kg m/s ÷ 30 kgv = 1.68 m/sFollowing the impact, the two bodies' common velocity is 1.68 m/s. Hence, the answer to this problem is that when a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.For more questions on collision
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Question 3 of 15
Which of the following statements are not true about gravity? Check all that
apply.
A. Gravity exists in the whole universe.
B. Gravity exists only on Earth.
C. Gravity is a force that pulls two objects together.
D. Gravity exists between two objects that have mass.
E. Gravity doesn't exist between Earth and the sun.
Answers
The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun" is not true about gravity.
Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.
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2. A truck goes from Mombasa to Busia with an average speed of 60 km/hr. The journey takes 30 hours. It returns from Busia to Mombasa on the same road with an average speed of 40 km/hr. What was the average speed of the truck during the roundtrip?
Answers
Answer:
hi what’s going on
Explanation:
The required average speed of the truck during the roundtrip is 48 km/hr.
What is velocity?Velocity is defined as the rate of change in the position of an object with respect to time.
Here,
To find the average speed of the truck during the roundtrip, we need to calculate the total distance traveled and the total time is taken.
Let d be the one-way distance between Mombasa and Busia. Then the roundtrip distance is 2d.
The time taken for the journey from Mombasa to Busia is,
t₁ = d / 60
The time taken for the return journey from Busia to Mombasa is,
t₂ = d / 40
The total time taken for the roundtrip is,
t = t₁ + t₂ = d/60 + d/40
= (2d/120) + (3d/120)
= 5d/120 = d/24
The average speed of the truck during the roundtrip is,
average speed = total distance / total time = 2d / (d/24) = 48 km/hr
Therefore, the average speed of the truck during the roundtrip is 48 km/hr.
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Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answers
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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HELP! How much power is indicated by each example
Answers
Power is indicated by example 1 is 5 ft-lbs/s.
Power is indicated by example 2 is 600 ft-lbs/s.
Power is the rate of doing work. Power is also defined as work divided by time. i.e. Power = Work ÷ Time. Its SI unit is Watt denoted by letter W. Watt(W) means J/s or J.s-1. Something makes work in less time, it means it has more power. Work is Force times Displacement. Dimension of Power is [M¹ L² T⁻³]. Example of the power is when you take 1 J of energy in 1 second then the power is 1 W.
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plz help me
what do you meant by significant figure?give different rules to clarify significant figure.
Answers
Which of the following is not true about Triton, the large moon of Neptune? It is more reflective than Earth's Moon. It is larger than Earth's Moon. It is in a retrograde orbit. It has a thin atmosphere. It has nitrogen geysers.
Answers
Answer:
Triton is the largest of Neptune's 13 moons. It is unusual because it is the only large moon in our solar system that orbits in the opposite direction of its planet's rotation―a retrograde orbit. ... Like our own moon, Triton is locked in synchronous rotation with Neptune―one side faces the planet at all times.
A tennis ball moving at a speed of 4 m/s, collides with a bowling ball at rest. The tennis ball bounces back in the direction opposite to the initial velocity, and the bowling ball moves very slowly too. Which object experiences the greater magnitude impulse during the collision? The bowling ball Neither, both experienced the same magnitude impulse It's impossible to tell none of these The tennis ball
Answers
Answer:
Both experienced the same magnitude impulse
Explanation:
This is because, the impulse force is internal to the system of both the tennis ball and the bowling ball. It is an action-reaction pair. So, the force exerted on the tennis ball by the bowling ball equals in magnitude to the force exerted by the tennis ball on the bowling ball although, they are in opposite directions. This, both experienced the same magnitude impulse.
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
Answers
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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How can you change velocity without changing speed?
Answers
Answer:
Velocity is a vector quantity: thus an object can change direction without changing speed which is a change in vector representing V.
Example: An object moving with constant speed in a circle (on a string, etc)
is constantly changing velocity although its speed is constant.
what is the value of pi(8.104)^2 written with correct significant numbers
Answers
Answer:206.3
Explanation:
A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
of 20 m along level ground (Figure 3). The total weight of sled and load is 14,700
2
N. The tractor exerts a constant 5000 N force at an of 36.9
◦ angle of above the
horizontal. A 3500 N friction force opposes the sled’s motion. Find the work
done by each force acting on the sled and the total work done by all the forces.
Answers
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
Work done by the applied forceThe work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
Work done by frictional forceW = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
Net work done by all the forces on the tractorW(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
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How can you determine the number of protons or electrons in an atom?
Answers
Answer:
number of protons = atomic number
number of electrons = atomic number
Number of electrons = atomic matter
What is the difference between chronic and acute stress?
Acute stress is long-term, while chronic stress is short in duration.
Acute stress is short-term, while chronic stress endures over time.
Chronic stress varies by geographic location, while acute stress is universal.
Chronic stress is not harmful, while acute stress has negative consequences.
Answers
Answer:
The correct difference between chronic and acute stress is:
Acute stress is short-term, while chronic stress endures over time.
Explanation:
Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.
On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.
Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.
What is curved space?
Answers
Which of the images below represents diffraction of a wave?
A
OA. C
OB. D
OC. A
OD. E
B
с
to
D
Answers
The images below represents diffraction of a wave is C. Thus, option A is correct.
A wave is a disturbance or variation that propagates through a medium or space, transferring energy without permanently displacing the medium itself. Waves can take various forms, such as mechanical waves (requiring a medium to propagate, like water waves or sound waves) or electromagnetic waves (which can propagate through a vacuum, such as light or radio waves).
Waves are characterized by several important properties:
Amplitude: The magnitude or maximum displacement of the wave from its equilibrium position.
Wavelength: The distance between two corresponding points on a wave (e.g., crest to crest or trough to trough).
Frequency: The number of complete cycles or oscillations of a wave that occur in a given time period.
Period: The time taken for one complete cycle of a wave.
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FO
1.0 A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The
oscillation amplitude is A = 0.125 m and the block moves at 3.00 m/s as it passes through
equilibrium at x =
<= 0.
(a) Find the spring constant
Answers
The spring constant, k, will be equal to 18 N/m. The spring constant is defined as the force-to-displaced-length ratio.
What is the spring constant?Spring constant is defined as the ratio of force per unit displaced length.
Given data;
Mass of block,m=0.250 k
Amplitude,A = 0.125 m
Velocity,V=3.00 m/
Spring constant, K=?
The spring constant formula when the spring oscillates at the specified amplitude A:
\(\rm k= \frac{v_{max}^2 m}{A} \\\\ k =\frac{3.0 m/s^2 \times 0.250 \ kg}{0.125 \ m} \\\\ k=18 \ N/m\)
Hence, the spring constant, k will be 18 N/m
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