calculate the height of the coulomb barrier for the head-on collision of two deuterons. take the effective radius of a deuteron to be 2.1 fm.
Answers
The nuclear force between two charged particles is attractive, but Coulomb repulsion prevents two charged particles from getting close enough to interact. (K= 170 keV.)
How to fix it?We consider the value of the initial kinetic energy K that each deuteron must possess in order for them to come to rest when their surfaces meet to be the height of the Coulomb barrier.
if r is a deuteron's radius, then by the law of conservation of energy, we get,
2K=1/4πϵo. e²/2r
putting values, we get
K= 1/4πϵo. e²/4r=9x10^9x1.6x10^-19/4x2.1x10^-15=2.75x10^-14 J = 170 keV.
How can the height of a potential barrier be determined?J is the potential energy. Divide it by the electron charge, or 1.6 x 1019C, to convert it to eV. Consequently, the 360keV potential barrier height for a head-on collision of two deuterons. In this work,
What is the calculation for height?5 feet, 6 inches, or 66 inches, is the height of a human. 2.54 centimeters make up one inch (cm). Therefore, to convert your height from inches to centimeters, just multiply it by 2.54. The metric equivalent of a person who is 5 feet, 6 inches tall in this instance is 167.64 cm (66 x 2.54).
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Related Questions
Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart 1. How much force is exerted into cart 2? Explain.
Answers
The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
Mass of cart 1 = m1 = 1 kgMass of cart 2 = m2 = 2kgForce applied on cart 1 = 2 NAccording to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
\(F_1 = -F_2\)
\(F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N\)
Thus, the force exerted on the cart 2 during the collision is 2 N.
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why do we daydream during class
Answers
Answer:
Because we wish that a dragon would just destroy school and you can ride your new dragon to starbucks, you'll be famous!!! BUT THEN REALITY SMACKS YOU IN THE FACE WITH A STUPID STACK OF HOMEWORK!!!
Explanation:
Balanced forces acting on an object
O Always change the object's motion.
O Sometimes change the object's motion.
O Never change the object's motion.
O Are not related to motion.
Answers
Answer:
Balanced forces do not change the motion of an object. The motion of an object will not change if the forces pushing or pulling the object are balanced. An object that is sitting still will stay still if the forces acting on it are balanced
Explanation:
When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces . If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: ... a moving object continues to move at the same speed and in the same direction.
a convex spherical mirror with a radius of curvature of 13.5 cm produces a virtual image one half the size of the real object. where is the object?
Answers
The object is located 20.25 cm in front of the convex spherical mirror.
To solve this problem, we can use the mirror equation for spherical mirrors:
1/f = 1/do + 1/di
where f is the focal length of the mirror, do is the object distance, and di is the image distance.
Given:
Radius of curvature (R) = 13.5 cm (positive for a convex mirror)
Object-image relationship: magnification (m) = -1/2 (negative for a virtual image and smaller size)
We know that the magnification (m) is given by:
m = -di/do
Substituting the given values, we have:
-1/2 = -di/do
Simplifying, we find:
di = do/2
Now, we can use the mirror equation and substitute the values:
1/f = 1/do + 1/(do/2)
Simplifying further:
1/f = 2/do + 1/do
1/f = 3/do
From this equation, we can see that the object distance (do) is three times the focal length (f). Since the radius of curvature (R) is twice the focal length (f), we have:
R = 2f
Substituting this relation, we can solve for the object distance:
do = 3f = 3(R/2) = (3/2)R = (3/2)(13.5 cm)
Calculating this value, we find:
do = 20.25 cm
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Audent se when the stone me themelo CD The student semblance theo of the a) 2 shows the rings to them and 52.00 450 Mao Mass of Flo.2.1 Record the mass shown by the balance in Table 21 Table 2.1 object mas volumelom density in g/cm A 131 25 10.1
Answers
Answer:huh
Explanation:
Identify the part of the macroscale simple distillation set-up corresponding to each name. A B D E F
Answers
A: Heating mantle or heat source, B: Distilling flask, D: Thermometer or temperature probe, E: Condenser, F: Receiving flask or collection flask.
What components make up a distillation system?Figure 1 depicts a typical simple distillation setup. A flask holding the distillable liquid, an adapter holding a thermometer and connecting the flask to a water-cooled condenser, and a flask holding the condensed liquid make up the apparatus (the distillate).
What is the basic distillation setup?A flask (the solution) is part of the distillation apparatus, along with a three-way adapter, a water-jacketed condenser, a vacuum adapter, and a round-bottom flask to catch the condensed liquid.
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A bus accelerates forward. If an apple were on the floor of the bus it would move forward.
A: True
B: False
Answers
Answer:
False
Explanation:
Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.
Which two explanations are based on personal beliefs?
I A. Certain mineral crystals have properties that help protect the
body from illness.
IB. A constellation's position in the night sky can be used to predict
events in a person's life.
I C. Medical data gathered over many years show that lack of
adequate sleep causes health problems.
D. Observations using microscopes reveal that all known organisms
are composed of tiny structures called cells.
I E. Data gathered during experiments show that there is an inverse
relationship between the force of gravity and distance.
Answers
Answer:
The correct options are A and B
Explanation:
Personal beliefs can be described as beliefs that have not been scientifically proven. These beliefs are generally as a result of religion, culture or tradition. Scientifically in theory, these beliefs lack clear path of possibility. For example, being in possession of certain mineral crystals in order to help protect the body against illness have a little possibility of being scientifically (in theory) explained. There is also no scientific evidence to support this claim.
There is also no scientific evidence to support the idea of the constellation's position to predict events in a person's life. This also has little possibility of being theoretically explained in science.
It should however be noted that there are exceptions/coincidences that suggest these events happen as it has been listed in the two options.
Answer: A and B!
Explanation: Just took the quiz.
A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?
Answers
To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.
In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.
In this scenario, the force needed to lift the automobile can be calculated using the formula:
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.
Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:
\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
Simplifying the equation and substituting the values, we can solve for \(F_{2}\):
\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)
Plugging in the values, we find:
\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)
Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:
\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)
Solving for \(F_{1}\), we find:
\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)
Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.
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what is the astronomical object of celestialbodies
Answers
Celestial bodies are objects in space such as the sun, moon, planets, and stars. They form part of the vast universe we live in and are usually very distant from us.
Stars, planets, moons, and many other celestial bodies in the sky are called celestial bodies. The sun and the other celestial bodies that revolving around it form the solar system. These celestial bodies include planets, comets, asteroids, and meteors. Celestial bodies are natural objects floating in space. For example, stars, planets, meteorites, moons, and other space objects. Astronomers use special frames of reference. This is known as the celestial coordinate system. This system is similar to the system used to locate objects on the Earth's surface. Use measurements from known reference points or lines.
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an electron starting from rest accelerates through a potential difference of 36 v. what is the final debroglie wavelength
Answers
When an electron accelerates through a potential difference, its kinetic energy increases. To find the final de Broglie wavelength, we can use the de Broglie equation:
λ = h / p, where λ is the wavelength, h is the Planck's constant, and p is the momentum of the electron.
To calculate the momentum of the electron, we can use the formula p = √(2mK), where m is the mass of the electron and K is the kinetic energy. Since the electron starts from rest, the initial kinetic energy is zero.
Given that the potential difference is 36 V, we can calculate the final kinetic energy using the equation K = qV, where q is the charge of the electron (1.6 x 10⁻¹⁹ C) and V is the potential difference.
Now, we can substitute the value of K into the momentum formula to find the momentum of the electron. Then, using the de Broglie equation, we can determine the final de Broglie wavelength.
To find the final de Broglie wavelength, we can follow these steps:
Calculate the final kinetic energy: Since the electron starts from rest, the initial kinetic energy is zero. The kinetic energy is given by the equation K = qV, where q is the charge of the electron (1.6 x 10⁻¹⁹ C) and V is the potential difference. In this case, the potential difference is 36 V.
Thus, K = (1.6 x 10⁻¹⁹C)(36 V)
= 5.76 x 10⁻¹⁸ J.
Calculate the momentum of the electron: The formula for momentum is p = √(2mK), where m is the mass of the electron (9.1 x 10⁻³¹ kg) and K is the kinetic energy.
Plugging in the values, we get p = √(2(9.1 x 10⁻³¹ kg)(5.76 x 10⁻¹⁸ J))
= 1.68 x 10⁻²³ kg∙m/s.
Calculate the final de Broglie wavelength: Using the de Broglie equation, λ = h / p, where λ is the wavelength, h is Planck's constant (6.626 x 10⁻³⁴ J∙s), and p is the momentum of the electron.
Substituting the values,
we have λ = (6.626 x 10⁻³⁴ J∙s) / (1.68 x 10⁻²³kg∙m/s)
= 3.94 x 10⁻¹¹ m.
Therefore, the final de Broglie wavelength of the electron is 3.94 x 10⁻¹¹meters.
The final de Broglie wavelength of an electron that accelerates through a potential difference of 36 V is 3.94 x 10⁻¹¹ meters. This is calculated by finding the final kinetic energy using the formula K = qV, where q is the charge of the electron and V is the potential difference.
Then, the momentum of the electron is calculated using the formula p = √(2mK), where m is the mass of the electron and K is the kinetic energy. Finally, the de Broglie wavelength is determined using the equation λ = h / p, where λ is the wavelength and h is Planck's constant.
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Utility companies measure electrical energy usage in units of kilowatt-hours. A kilowatt-hour is theamount of energy used by a 1 kW device that is in operation for 1 hour.
(a) Determine the number ofjoules equivalent to a kilowatt-hour.
(b) Determine number of coulombs associated with a kilowatt-hour,given a voltage of 120 V.
(c) Find the current used by a 1 kW device.
Answers
(a) The number of joules equivalent to a kilowatt-hour is 3.6 × 10⁶ J.
(b) The number of coulombs associated with a kilowatt-hour, given a voltage of 120 V, is 3.0 × 10⁴ C.
(c) The current used by a 1 kW device is 8.33 A.
(a) To determine the number of joules equivalent to a kilowatt-hour, we need to convert the units.
Given that 1 kilowatt-hour is the energy used by a 1 kW device in operation for 1 hour, we can use the relationship:
1 kilowatt-hour = 1 kW × 1 hour
To convert hours to seconds, we know that 1 hour is equal to 3600 seconds (60 seconds × 60 minutes).
So, 1 kilowatt-hour = 1 kW × 3600 s
Now, to convert kilowatts to watts, we know that 1 kilowatt is equal to 1000 watts.
Therefore, 1 kilowatt-hour = 1000 W × 3600 s
Multiplying these values together, we find:
1 kilowatt-hour = 3.6 × 10⁶ J
(b) To determine the number of coulombs, we can use the relationship between energy, voltage, and charge:
Energy (in joules) = Voltage (in volts) × Charge (in coulombs)
Given that 1 kilowatt-hour is equivalent to 3.6 × 10⁶ joules, and the voltage is 120 V, we can rearrange the equation to solve for charge:
3.6 × 10⁶ J = 120 V × Charge (in coulombs)
Solving for Charge, we find:
Charge (in coulombs) = (3.6 × 10⁶ J) / (120 V) = 3.0 × 10⁴ C
(c) Given that power (P) is equal to 1 kW (1000 W) and the voltage (V) is 120 V, we can use Ohm's law, which states that current (I) is equal to power divided by voltage:
Current (I) = Power (P) / Voltage (V)
Substituting the values, we have:
Current (I) = 1000 W / 120 V ≈ 8.33 A
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Find the equivalent resistance of this circuit.
Answers
\((R_1 +R_2)||R_3\\\\R_{eq} = \left(\dfrac 1{R_1 + R_2} + \dfrac 1{R_3}} \right)^{-1}\\\\\\~~~~~~=\left( \dfrac{1}{100+200} + \dfrac 1{600} \right)^{-1}\\\\\\~~~~~~=\left( \dfrac{1}{300} + \dfrac{1}{600} \right)^{-1}\\\\\\~~~~~~=\left(\dfrac{3}{600} \right)^{-1}\\\\\\~~~~~~=\dfrac{600}3 \\\\\\~~~~~~= 200~ \Omega\)
Newton's 2nd law of Motion
what are some objects that have a little mass but a large amount of acceleration and therefore produce a large Force upon impact with something else.
aka..
what are some objects that have less mass but a larger acceleration
to break cardboard?
Answers
A bullet and a base ball
What objects has a small mass but produce large acceleration?Objects with a small mass can produce a large acceleration if they experience a large force. This is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.
It's important to note that while these objects can produce a large acceleration, they can also cause significant damage or harm if not handled properly. It's important to always take appropriate safety precautions when working with objects that have the potential to produce large forces and accelerations.
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a block is sitting on a small platform supported by a spring and is undergoing simple harmonic oscillation with an amplitude of 7.5 cm. what is the maximum frequency at which the block will stay on the platform?
Answers
Answer:
Explanation:
For a block understanding simple harmonic oscillation,
the maximum amplitude(A) = 7.5cm
A = 0.075m
Let angular frequency be (w)
Then,max acceleration of platform = w²A…… {where, A is amplitude}
and, Fictitious force experienced by platform = mw²A
At mean position, acceleration, a=0
⇒N=mg (N = normal reaction)
Below the mean positon, acceleration is upwards (towards the mean position)
∴N−mg=ma or
N=m(g+a)
Above the mean position, acceleration is downwards (towards the mean position)
∴mg−N=ma or
N=m(g−a)
In this case, N decreases as 'alpha' increases. At the extreme position acceleration is maximum (=ω²A) so N is minimum. When the block leaves contact with the plank N becomes zero.
So,
0= m(g-w²A)
w²A=g
w=√g/A
w=√9.8/0.075
w=11.43 rad/ sec
In Hz,
w= 11.43/2π = 1.82Hz
So, maximum frequency at which the block will stay on the platform is 1.82Hz
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A 1.2-kg hot iron sphere with heat capacity
576 J °C-1 is cooled by immersing it in a tank of
water (Fig g). (See the photo that I uploaded)The mass of the water is 3 kg and
its initial temperature is 12 °C. After 5 minutes,
both the iron sphere and the water reach a final
temperature of 15 °C.
(a) Find the energy gained by the water.
(b) Find the average rate of energy transfer from
the iron sphere to the water.
(c) What is the initial temperature of the iron
sphere?
Answers
Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:
A. The energy gained by the water is 37656 J
B. The average rate of energy transfer from
the iron sphere to the water is 125.52 J/s (Watts)
C. The initial temperature of the iron
sphere is 65.4° C
A. How to determine the heat gained Mass of water (M) = 3 Kg = 3 × 1000 = 3000 gInitial temperature (T₁) = 12 °C Final temperature (T₂) = 15 °Change in temperature (ΔT) = 15 – 12 = 3 °C Specific heat capacity (C) = 4.184 J/gºC Heat (Q) =?Q = MCΔT
Q = 3000 × 4.184 × 3
Q = 37656 J
B. How to determine the rate of energy transfer Heat (Q) = 37656 JTime (t) = 5 min = 5 × 60 = 300 sPower (P) =?Power = energy / time
Power = 37656 / 300
Power = 125.52 J/s (Watts)
C. How to determine the initial temperature of the iron Mass of iron (M) = 1.2 Kg = 1.2 × 1000 = 1200 gHeat capacity (C) = 576 J/ºC Heat (Q) = 37656 JTemperature (T) =?Q = CT
37656 = 576 × T
Divide both side by 576
T = 37656 / 576
T = 65.4° C
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You step off of a ledge and land 0. 5 seconds later. How high was the ledge?
Answers
The height of the ledge can be calculated using the equation h = 0.5 * g * t2, where g is the acceleration due to gravity (9.8 m/s2) and t is the time taken (0.5 s in this case). Thus, the height of the ledge is 4.9 m.
To calculate the height of a ledge, the time taken for the object to reach the ground must be known. This can be determined by measuring the time taken for the object to fall from the ledge and calculating its velocity at the point of release.
Once the velocity is known, the time taken for the object to fall can be calculated by dividing the velocity by the acceleration due to gravity. Using this information, the height of the ledge can then be calculated using the equation above. To illustrate this, if an object is dropped from a ledge 4.9 m high and takes 0.5 s to reach the ground, then the equation can be used to calculate the height of the ledge: h = 0.5 * 9.8 * (0.5)2 = 4.9 m.
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can someone tell me the ans of this question also please wit hthe steps of the solution.
Answers
Answer:
C
Explanation:
speed=distance÷time
total distance=100+20=120km
total time=1+1/2=1.5hrs
speed=120÷1.5
speed=80km/hr
Light of wavelength 540nm is incident on a slit of width 0.150mm and a diffraction pattern is produced on a screen that is 2.00m from the slit. What is the width of the central bright fringe?
Answers
Light of wavelength 540nm is incident on a slit of width 0.150mm and a diffraction pattern is produced on a screen that is 2.00m from the slit. The width of the central bright fringe is approximately 7.2 x \(10^{-3}\) meters.
To determine the width of the central bright fringe in a diffraction pattern, we can use the formula for the single-slit diffraction pattern:
w = (λ * L) / (2 * d)
Where:
w is the width of the central bright fringe,
λ is the wavelength of light (540 nm = 540 x \(10^{-9}\) m),
L is the distance from the slit to the screen (2.00 m),
and d is the width of the slit (0.150 mm = 0.150 x \(10^{-3}\) m).
Substituting the given values into the formula:
w = (540 x \(10^{-9}\) m * 2.00 m) / (2 * 0.150 x \(10^{-3}\) m)
Calculating the expression:
w = 7.2 x \(10^{-3}\) m
The width of the central bright fringe is approximately 7.2 x \(10^{-3}\) meters.
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What did they call the people who designed and built the trebuchet?
Answers
Answer:
engineers? do you have references
A 101 Kg racer moves around a flat circular track with a radius of 55 m with a constant speed. The car makes one revolution around the track every 13 seconds. Find the speed of the car.
Answers
Answer:
26.6 m/s
Explanation:
\(v = r \alpha \\ v = r( \frac{2\pi}{t} ) \\ v = (55)( \frac{2\pi}{13} ) \\ v = 26.6 \: m {s}^{ - 1} \)
Which of the following consists of photovoltaic cells?
1. Solar panels
2. Rube Goldberg device
3. Solar oven
4. Electric generator
Answers
What is the temperature of an incandescent lamp filament
Answers
Answer:
about 5000 °F
Explanation:
A trebuchet fired a tennis ball with an initial velocity. Determine the following
Answers
ANSWER
\(\begin{gathered} (a)\text{ }12.61\text{ }s \\ (b)\text{ }194.73m \\ (c)\text{ }608.57\text{ }m \\ (d)\text{ }78.4\text{ }m\/s \end{gathered}\)EXPLANATION
Parameters given:
Initial velocity, v0 = 78.4
Angle of projectile, θ = 52 degrees
(a) To find the flight time of the tennis ball, apply the formula:
\(t=\frac{2v_0\sin\theta}{g}\)where g = acceleration due to gravity
Hence, the total flight time of the tennis ball is:
\(\begin{gathered} t=\frac{2*78.4*\sin52}{9.8} \\ t=12.61\text{ }s \end{gathered}\)(b) To find the maximum altitude of the ball during its flight, apply the formula:
\(H=\frac{v_0^2\sin^2\theta}{2g}\)Therefore, the maximum height attained by the tennis ball is:
\(\begin{gathered} H=\frac{78.4^2*\sin^2(52)}{2*9.8} \\ H=194.73\text{ }m \end{gathered}\)(c) To find the horizontal distance the tennis ball travels, apply the formula:
\(R=\frac{v_0^2\sin2\theta}{g}\)Hence, the horizontal distance traveled by the tennis ball is:
\(\begin{gathered} R=\frac{78.4^2*\sin(2*52)}{9.8} \\ R=608.57\text{ }m \end{gathered}\)(d) To find the final velocity of the tennis ball, apply the formula:
\(v=\sqrt{v_0^2+2h(-g)}\)where h = initial height = 0 m
Hence, the final velocity of the tennis ball just before impact is:
\(\begin{gathered} v=\sqrt{78.4^2+2(0)(-9.8)} \\ v=\sqrt{78.4^2+0}=\sqrt{78.4^2} \\ v=78.4\text{ }m\/s \end{gathered}\)Một bóng đèn có hiệu điện thế định mức là 110V. Đặt vào hai đầu bóng đèn các hiệu điện thế sau đây, hỏi trường hợp nào dây tóc của đèn sẽ đứt?
Answers
Answer:
fhaiisjrbekxkrkebxnsiiwj4bnds
5.1 What is the nucleus composed of ?
Answers
Answer:
5.1 The DNA double helix is the most recognizable nucleic acid structure, but these are ribozymes.
In an experiment, a thin sheet of material A,B, or C was used to divide two objects of different temperature in each trial, the conditions were identical except for the material of the thin sheet. The data table shows
the times in which the objects reached thermal equilibrium
Which material, if any, is the best thermal equilibrium
Answers
The best material for achieving thermal equilibrium can be determined by analyzing the data table. The time taken for each object to reach thermal equilibrium is dependent on the material used to divide them.
Material C appears to be the best as it takes the least amount of time for the objects to reach thermal equilibrium.
Based on the given information, the material that results in the shortest time to reach thermal equilibrium would be considered the best thermal conductor. To determine this, compare the times in the data table for materials A, B, and C. The material with the shortest time to reach thermal equilibrium is the best thermal conductor and, therefore, the best material for this experiment.
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a disc starts from rest with an angular acceleration completes 10 revolutions in 2 seconds. the time taken by it to complete 10 more revolution from that instant is
Answers
Starting from rest, the disc completes \(\theta\) revolutions after \(t\) seconds according to
\(\theta=\dfrac\alpha2t^2\)
with angular acceleration \(\alpha\). It completes 10 rev in 2 s, which means
\(10\,\mathrm{rev}=\dfrac\alpha2(2\,\mathrm s)^2\implies\alpha=5\dfrac{\rm rev}{\mathrm s^2}\)
Find the time it takes to complete 20 rev with this acceleration:
\(20\,\mathrm{rev}=\dfrac12\left(5\dfrac{\rm rev}{\mathrm s^2}\right)t^2\implies t=\sqrt8\,\mathrm s\approx2.83\,\mathrm s\)
so it takes approximately 0.83 s to complete 10 more rev.
If you move 3 meters east and 4 meters north what is the distance and what is the displacement?
If you move 6 meters East and 8 meters south what is the distance and what is the displacement?
Answers
Answer:
Distance 14
Displacement 10
Explanation:
Help quickly…
As a person travels due east, the altitude of the North Star
(1) decreases
(2) increases
(3) remains the same
Answers
East or west: it remains the same.
North: it increases.
South: it decreases.
At the North pole: it's straight up over your head.
At the equator: it's on the horizon, north of you.
South of the equator: it's below the horizon and you can't see it at all.