Contains a variety of enzymes that can degrade proteins, amino acids, nucleic acids and carbohydrates.

Answer:

A. 4 only

Explanation:

One of the tests for purity is by determining the melting point of a substance. A pure substance has a sharp meting point.

If the solid in question is a pure solid, when it is heated, it will exhibit a sharp melting point. Mixtures however melt over a range of temperatures due to the presence of impurities in the solid.

Answer:

C1 * V1 = C2 * V2

Explanation:

Where ‘C’ and ‘V’ refer to concentration and volume, ‘1’ and ‘2’ to solution 1 and 2 respectively. So, if ‘1’ refers to the HCl solution, we want to solve this equation for C1.

V1 = (C2*V2)/C1 = (0.4 * 50)/40 = 0.5 M

Answer

C. The equilibrium position would shift to produce more O₂

Explanation

If the concentration of a substance is changed, the equilibrium will shift to minimize the effect of that change. If the concentration of a reactant has increased the equilibrium will shift in the direction of the reaction that uses the reactants, so that the reactant concentration decreases.

Therefore, considering the reaction above at equilibrium, what would happen if more Na₂O2 were added is:

C. The equilibrium position would shift to produce more O₂

Answer:

higher temperature → more kinetic energy → more space between particles higher volume

Explanation:

Kinetic Molecular Theory states that gas particles exhibit perfectly elastic collisions and remain in constant motion. Absolute temperature  is directly proportional to the average kinetic energy of gas particles.

The following sequence represents the relationship between temperature and volume as explained by the kinetic-molecular theory:

higher temperature → more kinetic energy → more space between particles higher volume

The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This was large because the document protected slavery and allowed the state government to decide whether slavery should be allowed in the new state.

The people of the state saw this as an affront to their values and democratic rights and worked to defeat the constitution in a state referendum.

After much debate and campaigning, the Lecompton Constitution was defeated by over 10,000 votes. This was a major victory for antislavery advocates, who had worked hard to make sure the constitution was rejected in Kansas.

The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This document was drafted by pro-slavery advocates and would have made slavery a permanent institution in the state.

The citizens of Kansas were furious, and it sparked a great deal of debate and conflict. Many residents were so opposed to the document that they decided to form an independent government and reject the Lecompton Constitution in a referendum.

The referendum passed in an overwhelming majority, and the Lecompton Constitution was rejected. This event was a major milestone in the struggle for free-state rights in the Midwest and demonstrated the power of the people to resist oppressive legislation.

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The concentration of the Nitric acid solution : 0.114 M

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O​

Concentration a standard solution  of sodium hydroxide :  0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

\(\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles\)

From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=2.495 mlmoles

The volume of HNO₃ = 21.8 cm³, so the concentration :

\(\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114\)

The concentration of the nitric acid solution is 0.11445 mol/dm³

From the question,

We are to calculate the concentration of the nitric acid solution

The given balanced chemical equation for the reaction is

HNO₃ + NaOH → NaNO₃ + H₂O​

This means 1 mole of HNO₃ is needed to completely neutralize 1 mole of NaOH

Using the formula

\(\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}\)

Where \(C_{A}\) is the concentration of acid

\(C_{B}\) is the concentration of base

\(V_{A}\) is the volume of acid

\(V_{B}\) is the volume of base

\(n_{A}\) is the mole ratio of acid

\(n_{B}\) is the mole ratio of base

From the given information

\(C_{B}= 0.0998\ mol/dm^{3}\)

\(V_{A} = 21.80 \ cm^{3}\)

\(V_{B} = 25.0 \ cm^{3}\)

From the balanced chemical equation

\(n_{A} = 1\)

\(n_{B} =1\)

Putting the parameters into the formula, we get

\(\frac{C_{A} \times 21.80 }{0.0998 \times 25.0} = \frac{1}{1}\)

Then,

\(C_{A} \times 21.80=0.0998 \times 25.0\)

∴ \(C_{A}=\frac{0.0998 \times 25.0}{21.80}\)

\(C_{A} =\frac{2.495}{21.80}\)

\(C_{A} = 0.11445 \ mol/dm^{3}\)

Hence, the concentration of the nitric acid solution is 0.11445 mol/dm³

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Answer:

165.3 cm^3

Explanation: hope this is correct!!

P1 * V1 / T1 = P2 * V2 / T2

P1 = 84.6 kPa

V1 = 215 cm³

T1 = 23.5°C = 23.5 + 273 K = 296.5 K

At STP:

P2 = 101.3 kPa

V2 = ?

T2 = 273 K

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

The number of atoms in 3 moles K of the particle is 1.806 x 10²⁴ atoms.

The value of one mole of an atom is equal to exactly 12 grams of pure carbon-12.

12.00 g (C-12 ) = 1 mol C-12 atoms = 6.02 × 10²³ atoms .

The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 10²³).

The number of atoms in 3 moles K of the particle is calculated as follows;

= 3 moles  x   6.02 × 10²³ atoms / mol

= 1.806 x 10²⁴ atoms

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we find the energy to be approximately \(3.41 * 10^-19\) Joules is the answer.

To calculate the wavelength of a photon with a frequency of 61.7 MHz, we can use the formula: wavelength = speed of light / frequency. The speed of light is approximately\(3 * 10^8\) meters per second.

Converting the frequency to Hz (\(1 MHz = 10^6 Hz\)), we have \(61.7 * 10^6\)Hz.

Plugging these values into the formula, we get: wavelength =\((3 * 10^8 m/s) / (61.7 * 10^6 Hz).\)

Simplifying, we find the wavelength to be approximately 4.862 meters.

Now, to calculate the energy of a photon with a wavelength of 582.8 nm, we can use the equation: energy = Planck's constant × speed of light / wavelength.

Planck's constant is approximately \(6.63 * 10^-34\) Joule-seconds.

Converting the wavelength to meters (\(1 nm = 10^-9 m\)), we have \(582.8 * 10^-9 m.\)

Plugging these values into the equation, we get: energy =\((6.63 * 10^-34J·s) * (3 * 10^8 m/s) / (582.8 * 10^-9 m).\)

Simplifying, we find the energy to be approximately \(3.41 * 10^-19\) Joules.

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The grams of lactose needed when to make 3.4 l of an isotonic solution of lactose (c12h22o11) is 325.869 g

Isotonic solution: solute (lactose) concentration is equal to the solute concentration in blood cells and is 0.28 mol/L

Therefore the concentration of Lactose solution should be 0.28mol/L.

Mole = Volume × molarity

Mole of Lactose = 3.4L × 0.28mol/L = 0.952 moles.

Mass of Lactose = mole × molar mass = 0.952mol × 342.3g/mol = 325.869g = 325.869 g .

So, 325.869 g of Lactose is required.

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Answer:

the sunflower grow four

The correct answer is (b), the solvent that should be deposited into halogenated waste is dichloromethane.

Dichloromethane, also known as methylene chloride, is the appropriate solvent disposal into halogenated waste. This is because dichloromethane itself is a halogenated compound, containing chlorine atoms.

When disposing of waste solvents, it is crucial to segregate different types of solvents based on their chemical nature and potential hazards. Halogenated waste refers to waste materials that contain halogen atoms, such as chlorine, bromine, or iodine. Proper disposal of halogenated solvents ensures the safe handling and management of hazardous substances.

Dichloromethane is commonly used as a solvent in various laboratory and industrial processes, but its disposal requires special consideration due to its potential environmental impact. By depositing it into halogenated waste, it can undergo appropriate treatment and disposal methods designed to handle halogenated compounds, minimizing the risk of environmental contamination.

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The statement that methyl halides (CH₃–X; X= F, Cl, Br, or I) never undergo E1 reactions is true. This is because E1 reactions require a carbocation intermediate to form, which is not stable in the case of methyl halides.

In E1 reactions, the leaving group departs first, leaving a carbocation intermediate behind. The carbocation intermediate is a positively charged carbon atom with only three bonds, which makes it highly unstable. In the case of methyl halides, the carbon atom is bonded to three hydrogen atoms, which cannot stabilize the carbocation intermediate. This makes the reaction energetically unfavorable, and the reaction does not proceed via the E1 mechanism.

Instead, methyl halides undergo a different type of reaction called the SN2 mechanism. In this reaction, the nucleophile attacks the carbon atom at the same time that the leaving group departs. This results in a single concerted step that avoids the formation of an unstable carbocation intermediate.

In summary, the statement that methyl halides never undergo E1 reactions is true due to the instability of the carbocation intermediate that is required for this reaction mechanism.

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Answer: You would place the apple on the person's head.

Explanation:

The lower value of the calculated amount of water is the theoretical yield and the reactant that is used to calculate the theoretical yield is the limiting reactant. By looking at the calculations, we can say that the theoretical yield of the reaction is ≈1.9 g while the limiting reactant is NaOH.

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The crash where the cone experience a stronger force is option D because: Crash 1: the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.

The ball is drawn back to Earth by gravitational force. The ball returns to Earth as a result of friction. The ball is forced back toward Earth by magnetic force.

A puck's velocity changes when a player makes contact with it when it is still. He causes the puck to speed up, in other terms. The hockey stick's force, which causes the acceleration, is responsible. The velocity grows as long as this force is in motion.

Therefore, the force applied to an object must be larger than what is required for a progressive slowing down if the object must be slowed down quickly. For instance, a bicycle's brakes will slow or stop it more quickly the more force is given to it.

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See full question below

After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone.

Use the information from the diagram to answer.

In which crash did the cone experience a stronger force? How do you know?

answer choices

There was no force on the cone. In both crashes, only the hockey puck experienced a force.

The diagram doesn’t tell you anything about the force on the cone. It only gives information about the force on the pucks.

It was the same force in both crashes; the hockey puck changed speed by the same amount in each crash, so the force on the cone was the same each time.

Crash 1; the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.

Carbon-14 has a half-life of 5,730 years. A fossil with 4 g of C initially started with 32 g of C is 17200 years old.

Half life of a substance tells about how much time taken by a sample to reduced to 50%.

The 32g of C is decayed and it remains 4g of it. Since carbon decays follows first order reaction. To find out the age of fossil, we need to use the formula which is given as

ln(N_t/N_0)=-λt(i)

Where, N_t = 4g

N_0 = 32 g

We need to find λ using half life of carbon which is given as

λ=(0.693/t(1/2))

where t(1/2)=5730 years

Plug all values in the formula

λ=(0.693 year⁻¹/5730)

λ=0.0012094 year⁻¹

Plug all the available values in the equation (i)

ln(4 g/32 g)=-0.00012094 year⁻¹×t

ln(0.125)=-0.00012094 year⁻¹×t

-2.07944=-0.00012094 year⁻¹×t

t=(-2.07944 year/-0.00012094)

t = 17193.9805 year

t = 17200 year

Therefore, a fossil with 4 g of C initially started with 32 g of C is 17200 years old.

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Compound is a group of same molecules, Element is a group of same atoms and mixture is combination of two or more pure substances.

What are Molecules ?

Molecules are the combination of two or more different atoms combine in a fixed ratio.

Molecules can be independently founded.

Atoms are always founded in combined state and does not occurs independently except rare earth elements which belongs to 18th group of periodic table.

Chemicals are taken in compound state But they undergo chemical reaction individually in molecular level.

Hence, Compound is a group of same molecules, Element is a group of same atoms and mixture is combination of two or more pure substances.

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The molar mass of HNO3 is approximately 63 g/mol (1 hydrogen atom = 1 g/mol, 1 nitrogen atom = 14 g/mol, and 3 oxygen atoms = 48 g/mol). By dividing 6.3 g by the molar mass of HNO3, we find that it contains approximately 0.1 moles of HNO3. Since there are three oxygen atoms in each molecule of HNO3, there are 0.1 moles x 3 oxygen atoms = 0.3 moles of oxygen atoms in 6.3 g of HNO3.

To find the number of oxygen atoms, we first calculate the number of moles of HNO3 in 6.3 g by dividing the given mass by the molar mass of HNO3. The molar mass of HNO3 is the sum of the atomic masses of its constituent elements: 1 hydrogen atom (1 g/mol), 1 nitrogen atom (14 g/mol), and 3 oxygen atoms (16 g/mol each).

Adding them up gives us a molar mass of 63 g/mol for HNO3. Dividing 6.3 g by 63 g/mol gives us approximately 0.1 moles of HNO3.

Since each molecule of HNO3 contains 3 oxygen atoms, we can multiply the number of moles of HNO3 by 3 to find the number of moles of oxygen atoms. Therefore, 0.1 moles of HNO3 x 3 = 0.3 moles of oxygen atoms. This means that in 6.3 g of HNO3, there are approximately 0.3 moles of oxygen atoms.

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Among neutral organic compounds, the group of compounds known as alkanes typically form one covalent bond and have no unshared pairs of electrons.

Alkanes are characterized by having a general formula of CnH2n+2, where n is the number of carbon atoms in the molecule.

The carbon atoms in alkanes are each bonded to four other atoms, typically hydrogen atoms, resulting in a tetrahedral geometry and no unshared pairs of electrons.

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The concentration of the NaOH solution is 10.00 g/dm³.

To calculate the concentration in g/dm³ of a solution of NaOH containing 0.25 moles in 1 dm³, we need to know the molar mass of NaOH.

The molar mass of NaOH is calculated as follows:

Na (Sodium) = 22.99 g/mol

O (Oxygen) = 16.00 g/mol

H (Hydrogen) = 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the concentration (C) using the formula:

C = (moles of solute) / (volume of solution in dm³)

C = 0.25 moles / 1 dm³

C = 0.25 mol/dm³

To convert moles to grams, we can multiply the molar mass by the number of moles:

Concentration in g/dm³ = (0.25 mol/dm³) * (40.00 g/mol)

Concentration in g/dm³ = 10.00 g/dm³

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Answer:

The sun provides more than enough energy to meet the whole world's energy needs, and unlike fossil fuels, it won't run out anytime soon. As a renewable energy source, the only limitation of solar power is our ability to turn it into electricity in an efficient and cost-effective way.

Answer:

For water this amount is one calorie, or 4.184 joules. as a result, it takes water a long time to heat and a long time to cool. In fact, the specific heat capacity of water is about five times more than that of sand

Answer:

2Ca+2O2->2CaO

Explanation:

You have 2 O’s on the left side so you multiply the right side by 2.

Ca + O2 -> 2CaO

Now that you have 2 Ca on the right side and only 1 on the left, you multiply the Ca on the right by 2.

2 Ca + O2 -> 2 CaO

Answer:about 10,000 years b maybe

Explanation:Strontium-90 and cesium-137 have half-lives of about 30 years (half the radioactivity will decay in 30 years). Plutonium-239 has a half-life of 24,000 years. High-level wastes are hazardous because they produce fatal radiation doses during short periods of direct exposure.

The radioactive waste from nuclear plants is radioactive for 10,000 years and the correct option is option B.

The waste produced by a nuclear power plant or lab is referred to as radioactive waste. They include radioactive substances that are dangerous to the environment and the majority of biological forms. The wastes degrade over time.

Radioactive wastes are stored to-

Therefore, the radioactive waste from nuclear plants is radioactive for 10,000 years and the correct option is option B.

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The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.

What is Charles's law?

Charles's law states that, "When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion".

V ∝ T

\(\frac{V}{T}=K\)

Where,

V is the volume of the gas,

T is the temperature of the gas (measured in kelvins), and

K is a non-zero constant.

In two different states, an initial state 1 and a final state 2, the equation is,

\(\frac{V1}{T1}=\frac{V2}{T2}\)

Given data:

V1 = 11.2L

V2 = 13.3L

T2 = 55°C = 328K

By substituting the given data,

\(\frac{11.2}{T1}=\frac{13.3L}{328K}\)

\(T1=\frac{11.2L/328K}{13.3L}\)

∴T1 = 276K = 3°C

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The formula of the compound containing Al³⁺ and S²⁻ ions  is Al₂S₃.

Ionic compounds are formed when ions with opposing negative and positive charges form ionic bonds and form compounds, which are compounds made of ions.

Ionic compounds are named by stating the cation first, followed by the anion. When a neutral atom loses one or more electrons, it acquires a positive charge and is called a cation and when an atom gains one or more electrons, it becomes an anion and acquires a negative charge.

Valency of Al is 3 and that of S is 2. Exchange of valencies takes place during the formation of ionic compound and thus the formula is Al₂S₃.

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