The figure shows two waves traveling in the positive x direction. The amplitude
of the resultant wave is

a. 2.0 mm
b. 1.8 mm
c.1.4 mm
d. 1.0 mm
e. 0.83 mm

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Explanation:

CFL bulbs were made to take the place of incandescent bulbs, which generate light as a result of heat. ... LED (light-emitting diode) is a type of bulb that produces light using a narrow band of wavelengths. LED lighting is more energy efficient than CFL bulb.

Answer:

1,902 times

Explanation:

The work done to raise the bar is given by

W = mgh

the given mass is 26 kg and the height the bar is raised is .65 m so we get

W = 26 kg * 9.8 m/s^2 * .65 m

= 165.62 J

If we assume that efficiency is 25%, we divide by .25 to get the total energy consumed. If we assume efficiency is 100%, then work done would be equal to the total energy consumed because you would divide work done by a factor of 1 which doesn't change the value

total energy consumed (when efficiency is 25%) = Work/Efficiency

= 165.62 J / .25

= 662.48 J

I will use assume that the energy content of one slice of pizza is 1260 kJ (which converts to 1,260,000 J)

To find the number of times (N) the weightlifter would have to repeat the same exercise to burn off the energy in one slice of pizza -

662.48 J * N = 1,260,000 J

N = 1,260,000 J / 662.48 J = 1,901.94 = 1,902 times

Answer:

Explanation:

because it is godhood

Answer:

b

Explanation:

equal in magnitude but opposite in direction

The nearpoint of an eye is 151 cm. A corrective lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this lens?

Answer:

29.96cm

Explanation:

Using the corrective lens, the image should be formed at the front of the eye and be upright and virtual.

Now using the lens equation as follows;

\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)   -------------(i)

Where;

f = focal length of the lens

v = image distance as seen by the lens

u = object distance from the lens

From the question;

v = -151cm        [-ve since the image formed is virtual]

u = 25cm

Rewrite equation (i) to have;

\(f = \frac{uv}{u+v}\)

Substitute the values of v and u into the equation;

\(f = \frac{25*(-151)}{25-151}\)

\(f = \frac{-3775}{-126}\)

f = 29.96cm

The focal length should be 29.96cm

A stiff wire bent into a semicircle of radius a = 1.4 cm. The frequency is 30 Hertz and the amplitude of the emf induced in the loop is 1.16 x 10⁻³ V

Formula for the angular frequency is:

ω = 2πf

Where:

ω = angular frequency (rad/s)

f = frequency (Hertz)

In the given problem,

ω = 30 rev/sec = 30 x 2π rad/s

a) f = ω / 2π

f = 30 x 2π / 2π = 30 Hertz

b) The induced emf is:

ε = Bπ²a²f sin(ωt)

Where:

B = magnetic field

a = radius

In the given problem,

B = 20 x 10⁻³ T

a = 1.4 x 10⁻² m

Hence, the amplitude or the maximum emf is:

ε_max = Bπ²a²f

           = (20 x 10⁻³) π² (1.4 x 10⁻²)² (30) = 1.16 x 10⁻³ Volt

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Answer:

the answer is B, stability

Explanation:

A traditional economy is a system that is based on honorable customs, history, and beliefs. Tradition guides economic decisions, such as production and distribution. Traditional economies depend on agriculture, fishing, hunting, gathering or some combination above. They use exchange instead of money. Most traditional economies operate in emerging markets and developing countries. They are often in Africa, Asia, Latin America and the Middle East. But you can find scholarships from traditional economies scattered all over the world. Economists and anthropologists believe that all other economies started out as traditional economies. Thus, they expect the remaining traditional economies to evolve into market, command or mixed economies over time.

Answer:

d

Explanation:

Answer:

each parents contributes the dad gives the seed and the mom gives the egg

Explanation:

and then you are born

The weight of the car the large piston can support is 300 N.

Weight can be defined as the gravitational pull on an object. Or it can be defined as the product of mass and gravity of an object.

To calculate the weight of the car the large piston can support, we use the formula below.

Formula:

Where:

Make F the subject of the equation.

From the question,

Given:

Substitute these values into equation 2

Hence, the weight of the car the large piston can support is 300 N.

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The buoyant force acting on the cylinder is, \(Fb = \rho Ahg\). Here A is the cross-sectional area of the cylinder, h is the height of the cylinder, ρ is the density of the cylinder, and g is the acceleration due to gravity.

This buoyant force is also equal to the volume of the fluid displaced. \(Fb = \sigma h(A-x)g\). Here σ is the density of the fluid.

Equate the above two equations and solve for x.

\(\rho Ahg = \sigma A(h-x)g\\\rho h = \sigma h - \sigma x\\x = \frac{(\sigma - \rho)h}{\sigma}\)

So, the distance x depends on the density of the fluid, density of the cylinder and the height of the cylinder.

1. The density of the cylinder is same and distance x is independent of the diameter of the cylinder. Therefor, there will be no change in the distance x. Hence, the correct answer is No change.

2. Now the height is changing keeping the density same. As the distance x is directly proportional to the height, the distance x will increase.

3. The density of the added liquid is greater than of the water and it does not mix with the water. So, the liquid will settle down and there will be no change in the distance x.

4. The density of the added liquid is less than that of the water and it does not mix with the water. So, the liquid will not settle down and the distance x will change. The change in distance x can be determined as follow:

\(\rho Agh = \sigma' Axg + \sigma A(h-x)g\\\rho h=\sigma' x + \sigma h - \sigma x\\x=(\frac{\sigma - \rho}{\sigma - \sigma'})h\)

Here, σ' is the density of the added liquid.

From the above relation it is clear, that on adding the liquid of the density less than that of water, the denominator term become small ando so the value of x will increase.  

5. On removing some of the water inside the glass, the height of the water column will decrease, but the value of x does not depend on the height of the water column. So, there will be no change in the distance x.

6. The density of the new cylinder is smaller than that of the earlier one. So, the numerator term will increase. Therefore, the value of x will increase.

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Answer:

the diameter of the wire is 5 mm.

Explanation:

Given;

tensile force of the wire, F = 60 N

stress on the wire, δ = 3,060,000 Pa = 3,060,000 N/m²

Let A be the cross sectional area of the wire

The cross sectional area of the wire is calculated as follows;

\(\sigma = \frac{F}{A} \\\\A = \frac{F}{\sigma} \\\\A = \frac{60}{3,060,000} = 1.961 \times 10^{-5} \ m^2\)

The diameter of the wire is calculated as follows;

\(A = \frac{\pi d^2}{4} \\\\d = \sqrt{\frac{4A}{\pi} } \\\\d = \sqrt{\frac{4\times 1.961 \times 10^{-5}}{\pi} } \\\\d = 5.0 \times 10^{-3} \ m\\\\d = 5 \ mm\)

Therefore, the diameter of the wire is 5 mm.

Answer:

6logs

Explanation:f

First finding the volume of the logs

V= π/4d²l

= 0.098m³

So number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

So

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5 which is approx 6logs

The minimum number of logs that must be used is 6 logs.

Here first determine the volume of the logs i.e.

V= π/4d²l

= 0.098m³

Now

number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5

= 6logs

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Answer:

20

Explanation:

because it wlll go slow

Based on the velocity-time graph, the function x(t) for Gabriele with respect to Xena is: x(t) = 60 -2t.

A velocity-time graph is a the graph of the change in velocity of an object or body with time.

The area under a velocity-time graph gives the displacement of the body within the given time interval.

From the given velocity-time graph:

The position, x, of Xena at time t, = v*t

x = 8t

The position of Gabriele at time t, = v*t

x =60 + 6t

Therefore, the function x(t) for Gabriele with respect to Xena is

x(t) = 60 + 6t - 8t

x(t) = 60 -2t

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(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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Angular velocity of the platform with its load is 0.94 rad/s.

Since, there is no external torque acting on the system, the momentum is conserved.

So, Initial momentum, L₁ = Final momentum, L₂

I₀ω₁ = (I₀ + m₁r₁² + m₂r₂²)ω₂

I₀ω₁ = [1/2 x 80.7 x (1.91)²] (1.57)

I₀ω₁ = 147.2 x 1.57 = 231.1 kgm²/s

So,

231.1 = [147.2 + 9.57(4/5 x 1.91)² + 21.1(1.91)²]ω₂

Therefore, the final angular velocity,

ω₂ = 231.1/246.5

ω₂ = 0.94 rad/s

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\(\\ \sf{:}\!\implies F=ma\)

\(\\ \sf{:}\!\implies Acceleration=\dfrac{F}{m}\)

\(\\ \sf{:}\!\implies Acceleration=\dfrac{8}{0.25}\)

\(\\ \sf{:}\!\implies Acceleration=32m/s^2\)

Complete Question

The diagram illustrating this question is shown on the first uploaded image

Answer:

The value is \(\theta = 27^o\)

Explanation:

Generally the distance covered by the ball thrown at angle 45° that did not bounce is mathematically represented as

\(D = v cos (45) * t\)

Here t is the total time duration which is mathematically represented as

\(t = \frac{v sin (45)}{g}\)

This distance distance is also mathematically represented as

\(D = vcos(\theta)* t_1 + \frac{v}{2} cos(\theta )*t_2\)

Here \(\theta\) the angles made as shown in the diagram

Here \(t_1\) is the time before the first bounce which is mathematically represented as

\(t_1 = \frac{v sin (\theta )}{g}\)

\(t_1\) is the time duration before the final point which is mathematically represented as

\(t_2 = \frac{\frac{v}{2} * sin (\theta )}{g}\)

So

\(v cos (45) * \frac{v sin (45)}{g} = vcos(\theta)* \frac{v sin (\theta )}{g} + \frac{v}{2} cos(\theta ) * \frac{\frac{v}{2} * sin (\theta )}{g}\)

=> \(cos (45) sin(45) = cos(\theta)sin(\theta ) + cos(\theta )sin(\frac{\theta}{4})\)

=> \(0.5 = \frac{5}{8} * sin(2\theta )\)

=> \(\theta = 27^o\)

As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.

Identify the body's starting velocity:

We may use the equation of motion to get the body's initial velocity (u)

\(v^2 = u^2 + 2as\)

\(0 = u^2 + 2(-9.8)m/s^2 * h\)

\(u^2 = 19.6h\)

u = √(19.6h)

The body's initial velocity (u) and initial relative velocity (u_rel) are the same.

The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).

\(e = v_{rel }/ u_{rel}\)

e = 0 / u_rel = 0 / u

Now, one can investigate the forces affecting the body: When a body is on an inclined plane.

There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).

The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).

Determine the conditions for the body to stop:

μ * N = m * g * sin(45°)

μ * (m * g * cos(45°)) = m * g * sin(45°)

μ * cos(45°) = sin(45°)

(1/2) * cos(45°) = sin(45°)

Simplifying further, we have:

√2 / 4 = √2 / 2

Thus, the body will come to rest following the collision if the equation is valid.

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The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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Answer:

Volume measures liquid

Explanation:

Volume can be measured in meters and centimeters

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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The total momentum after the two balls collide remains conserved.

Given is that a cue ball rolls toward a billiard ball with a velocity of 1 m/s east. Both balls have identical masses.

For the elastic collision, the momentum remains conserved. So -

\($m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\)

We can write -

{m} + {m} = m{v₁ + v₂}

{v₁ + v₂} = 2m/m

{v₁ + v₂} = 2

Therefore, the total momentum after the two balls collide remains conserved.

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