BMW has introduced a program of covered scheduled maintenance for its cars. That is, when you bring in your vehicle for maintenance at a BMW dealership, BMW will cover the costs of everything (except for worn-out tires). This practice specifically targets which stage of the product life cycle?
Answers
Answer:
Usage
Explanation:
A product life cycle refers to the duration from the introduction of the product into the market until it's taken off the shelves.
A program of covered scheduled maintenance for the cars refers to the practice in which the dealership will cover the costs of everything when you bring in your vehicle for maintenance.
In this question, the mentioned practice specifically targets the stage - Usage of the product life cycle
Related Questions
planet a exerts a force on planet b. what can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?
Answers
Planet A exerts a force on planet B, the magnitude and direction of the gravitational force planet B exerts on planet A the gravitational force exerted by planet B on planet A is the same as the magnitude of the gravitational force exerted by planet A on planet B
Newton's third law states that if object A exerts a force on object B, then object B exerts an equal and opposite force on object A. Hence, if planet A exerts a gravitational force on planet B, then planet B exerts an equal and opposite gravitational force on planet A.The magnitude of the gravitational force exerted by planet B on planet A is the same as the magnitude of the gravitational force exerted by planet A on planet B, this is according to the law of universal gravitation,
This law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The direction of the gravitational force exerted by planet B on planet A is towards planet B's center, just as the direction of the gravitational force exerted by planet A on planet B is towards planet A's center. Therefore, we can say that the magnitude and direction of the gravitational force planet B exerts on planet A is equal and opposite to the gravitational force planet A exerts on planet B
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Who would benefit from using a topographic map? Check all that apply
Military
Hikers
Geologists
Submarine divers
Cross Country runners
Airplane Pilots
Answers
Explain the following (using the concepts of moment, center of gravity and stability.) a) Racing cars are low, with wide wheels. b) It is difficult to steer a bicycle by gripping the center of the handlebars
Answers
Answer:
b
Explanation:
Suppose a computer technical support representative can answer calls from 6 customers in an hour. what is the probability that a customer will be on hold less than 30 minutes?
Answers
The prοbability that a custοmer will be οn hοld fοr less than 30 minutes is 1/3 οr apprοximately 0.3333.
How tο calculate the prοbability that a custοmer will be οn hοld fοr less than 30 minutes?Tο calculate the prοbability that a custοmer will be οn hοld fοr less than 30 minutes, we need tο knοw the average time it takes tο handle a custοmer call. Let's assume the average handling time is 10 minutes.
In οne hοur, the suppοrt representative can handle 6 calls. Therefοre, the tοtal time spent handling calls in an hοur is 6 calls * 10 minutes per call = 60 minutes.
Nοw, let's cοnsider the prοbability that a custοmer will be οn hοld fοr less than 30 minutes. Since each call takes an average οf 10 minutes tο handle, if a custοmer is οn hοld fοr less than 30 minutes, it means their call is answered within the first 20 minutes (30 minutes - 10 minutes).
The tοtal time spent handling calls in an hοur is 60 minutes, and the time interval in which a custοmer can be answered within the first 20 minutes is 20 minutes.
Prοbability = Time interval fοr answering within 20 minutes / Tοtal time spent handling calls
Prοbability = 20 minutes / 60 minutes
Prοbability = 1/3
Sο, the prοbability that a custοmer will be οn hοld fοr less than 30 minutes is 1/3 οr apprοximately 0.3333.
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Take 2 glass tube of diameter 4cm each close one end of each tube by tying a piece of cotton cloth to it
Answers
To set up two glass tubes with closed ends, we can follow the given instructions by using a cotton cloth. Firstly, acquire two glass tubes with a diameter of 4 cm each. These tubes should be open at one end.
Next, take a piece of cotton cloth and securely tie it around the open end of each tube. Ensure that the cloth tightly covers the opening, creating a closed end.
The purpose of closing one end of the tube is to create a container or chamber that can be used for various experiments or demonstrations. By closing one end, we restrict the flow of any substances placed inside the tube, allowing for controlled observations or reactions within the confined space.
It's important to note that the cotton cloth should be tied tightly enough to prevent any air or substance from escaping or entering the tube. This ensures that the closed end remains sealed during experiments.
Therefore, With these prepared glass tubes, you can now explore different experiments involving gases, pressure, or other reactions that require a closed chamber. The closed-end design allows for the containment and manipulation of substances within the tubes, enabling a range of scientific investigations.
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Symptoms of excessive stress include all of the following EXCEPT:
Answers
Answer:
Symptoms of excessive stress include all of the following EXCEPT: increased energy level.
A green ball has a mass of 0.525 kg and a blue ball has a mass of 0.482 kg. A croquet player strikes the green ball and it gains an initial velocity of 2.26 m/s. It then strikes the blue ball, which is initially at rest. After the collision, the green ball has a velocity of 1.14 m/s in the same direction. If the balls roll on a frictionless surface and the collision is head-on, what is the final velocity of the blue ball? (Round your answer to the nearest hundredths place.)
Answers
Answer:
v' = 1.21 m/s
Explanation:
Mass of a green ball, m = 0.525 kg
Mass of a blue ball, m' = 0.482 kg
Initial velocity of green ball, u = 2.26 m/s
Initial velocity of blue ball, u' = 0 (at rest)
After the collision,
The final velocity of the green ball, v = 1.14 m/s
We need to find the final velocity of the blue ball after the collision if the collision is head on. Let v' is the final velcity of the blue ball. Using the conservation of momentum to find it :
\(mu+m'u'=mv+m'v'\\\\0.525 (2.26)+0=0.525 (1.14)+0.482v'\\\\0.588=0.482v'\\\\v'=\dfrac{0.588}{0.482}\\\\v'=1.21\ m/s\)
So, the final velocity of the blue ball is 1.21 m/s.
if a solution contains 30 g of
potassium chloride (KCI) per 100 mL of water at 60°C, the
solution would be considered saturated.
true
false
Answers
Answer Questions below
Answers
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
A 1 kg puck sliding on a horizontal shuffleboard court is slowed to rest by 1 point
a frictional force of 3 N. What is the coefficient of kinetic friction between
the puck and the surface of the shuffleboard court? *
O A. 0.25
O B.0.5
O c.0.15
D. .31
Answers
Answer:
miu = 0.31
Explanation:
The friction force is defined as the product of the normal force by the coefficient of friction.
\(f=miu*N\)
where:
f = friction force = 3 [N]
miu = friction coefficient
N = normal force [N]
The normal force on a horizontal surface can be calculated by means of the product of mass by gravity.
where:
m = mass = 1 [kg]
g = gravity acceleration = 9.81 [m/s²]
\(N=m*g\\N=1*9.81\)
\(N= 9,81 [N]\)
Now replacing in the equation above, we can find the friction coefficient.
\(miu=3/9.81\\miu = 0.31\)
an astronaut has a weight of 800.0 n on the international space station (iss). when she returns to earth, her weight is
Answers
The astronaut when she returns to Earth will have a weight of around 6400.0 N.
Weight is a measure of the force of gravity acting on an object. On Earth, the weight of an object is directly proportional to its mass, which is a measure of the amount of matter in the object. However, weight can vary depending on the gravitational force acting on an object. The weight of an object on the ISS would be around 10% of its weight on Earth, due to the lower gravitational force.
So, if the astronaut has a weight of 800.0 N on the ISS, what would her weight be when she returns to Earth? Well, since Earth has a stronger gravitational force than the ISS, the weight of the astronaut on Earth would be greater than her weight on the ISS. In fact, her weight on Earth would be approximately 8 times greater than her weight on the ISS, assuming no changes in her mass. Therefore, when the astronaut returns to Earth, her weight would be around 6400 N (800 N x 8).
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a point sourxe emits sound waves isotropically. The intensity of the waves 2.50 m from the source is 1.91
Answers
The intensity of the sound waves at a distance of 2.50 m from the point source is 11.94.The intensity at a distance of 2.50 m from the point source, we can use the inverse square law for sound intensity. The inverse square law states that the intensity of a sound wave decreases as the square of the distance from the source increases.
First, let's calculate the intensity at the source. Since the source emits sound waves isotropically, the intensity at the source will be the same in all directions. Therefore, the intensity at the source is also 1.91.
Next, we can use the inverse square law to find the intensity at 2.50 m from the source. The formula for the inverse square law is:
I2 = I1 * (d1 / d2)^2
where I2 is the intensity at the second distance, I1 is the intensity at the first distance, d1 is the first distance, and d2 is the second distance.
Plugging in the values, we have:
I2 = 1.91 * (2.50 / 0)^2
I2 = 1.91 * (2.50^2)
I2 = 1.91 * 6.25
I2 = 11.94
Therefore, the intensity of the sound waves at a distance of 2.50 m from the point source is 11.94.
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at 55 mph, under good conditions, a passenger vehicle can stop within
Answers
Under good conditions, a passenger vehicle traveling at 55 mph can stop within a certain distance.
The stopping distance of a vehicle depends on various factors such as speed, road conditions, tire traction, and reaction time. In general, it takes time for the driver to perceive a hazard and react by applying the brakes. Once the brakes are applied, the vehicle's momentum needs to be overcome to bring it to a complete stop.
The stopping distance can be divided into two components: the thinking distance and the braking distance. The thinking distance refers to the distance travelled by the vehicle during the driver's reaction time. The braking distance is the distance required for the vehicle to come to a stop after the brakes are applied.
Under good conditions, with an average reaction time and well-maintained brakes, a passenger vehicle travelling at 55 mph may have a thinking distance of around 55 feet. The braking distance can vary depending on factors like tire condition and road surface, but it is estimated to be around 120 feet for a passenger vehicle travelling at 55 mph. Therefore, the total stopping distance for a passenger vehicle at 55 mph under good conditions would be approximately 175 feet. It's important to note that these figures are approximate and can vary based on the specific circumstances and characteristics of the vehicle.
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Under good conditions, a passenger vehicle traveling at 55 mph can stop within a certain distance.
The stopping distance of a vehicle depends on various factors such as speed, road conditions, tire traction, and reaction time. In general, it takes time for the driver to perceive a hazard and react by applying the brakes. Once the brakes are applied, the vehicle's momentum needs to be overcome to bring it to a complete stop.
The stopping distance can be divided into two components: the thinking distance and the braking distance. The thinking distance refers to the distance travelled by the vehicle during the driver's reaction time. The braking distance is the distance required for the vehicle to come to a stop after the brakes are applied.
Under good conditions, with an average reaction time and well-maintained brakes, a passenger vehicle travelling at 55 mph may have a thinking distance of around 55 feet. The braking distance can vary depending on factors like tire condition and road surface, but it is estimated to be around 120 feet for a passenger vehicle travelling at 55 mph. Therefore, the total stopping distance for a passenger vehicle at 55 mph under good conditions would be approximately 175 feet. It's important to note that these figures are approximate and can vary based on the specific circumstances and characteristics of the vehicle.
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Is a stone in the ground example of newtons first law of motion?
Answers
Answer:
yes, a stone in the ground is a example of newtons first law of motion because it does change it position until an external force is applied.
(Newton’s first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. )
Explanation:
Create a chart that
compares and
contrasts electric
and magnetic
fields. Attach your
chart to your lab
worksheet.
Anyone know any differences I could put in a chart?
Answers
A chart that compares and contrasts electric and magnetic fields.
Some differences between electric and magnetic fields that you could include in a chart are
Electric Fields
1. Created by electric charges.
2. Can exist even when charges are at rest.
3. Can attract or repel other charges.
4. Electric field lines begin and end on charges.
5. Units are N/C or V/m.
5. Can do work on charges, converting potential energy to kinetic energy.
6. Can be shielded by conductors.
Magnetic Fields
1. Created by moving charges.
2. Only exist when charges are in motion.
3. Can attract or repel other magnets.
4. Magnetic field lines form closed loops.
5. Units are T (Tesla) or Gauss.
6. Cannot do work on charges, but can induce a voltage.
7. Cannot be shielded by conductors, but can be partially shielded by materials like iron.
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A 3.00-m long pipe is in a room where the temperature is 20°C. What is the fundamental frequency if the pipe is open at both ends?
Answers
The fundamental frequency if the pipe is open at both ends of a 3.00-m long pipe is in a room where the temperature is 20°C is 57Hz.
Fundamental frequencyWith crests and troughs, a transverse wave is one that moves through a medium. Transverse waves are demonstrated by the wave on a string. When a wave moves across a medium while compressing and rarefying the air, it is said to be longitudinal. Examples of longitudinal waves include sound waves. Standing waves develop when two waves approach one another simultaneously and along the same path. An illustration of how standing waves form is an organ pipe.The frequency that matches the first harmonic of the pipe's frequency is known as the fundamental frequency. To examine the scenario, determine key factors like frequency, and carry out the experiment, one must be aware that sound waves cause standing waves to form inside the tube.For more information on fundamental frequency kindly visit to
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Complete question:
A 3.00-M Long Pipe Is In A Room Where The Temperature Is 20°C. What Is The Fundamental Frequency If The Pipe Is Closed At One End?
A.57 Hz
B. 114 Hz
C. 29 Hz
D. None Of The Above
could sum1 explain this for 17 points please?
Answers
Answer:
If the potential energy change of each cart is the same, then the total mechanical energy change is the same for each cart
Explanation:
Hills look steeper when standing back from the edge so that gaze is nearly parallel to the surface of the hill. When optical slant (the angle between the center of gaze and the surface) is small, surface orientation is pulled toward the direction of gaze
A rock is rolling down a hill, and it’s halfway down. Would it have both Kintectic engery and Potenial engery? PLEASE HELP
Answers
Answer:
Only kinetic.
Explanation:
Potential energy means it has the potential to move. Not something already in motion.
Answer:
yes
Explanation:
it hasn't stopped moving so it still has kinetic energy and it hasn't reached what is considered 0 so yes it has both potential and kinetic energy
if you need more of an explanation let me know and ill fix it
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
OA. The frequency Increases and the wavelength decreases.
OB. The frequency decreases and the wavelength increases.
OC. The frequency stays the same and the wavelength increases.
OD. The frequency stays the same and the wavelength decreases.
ОЕ. Neither the frequency nor the wavelength is affected.
Answers
The frequency stays the same and the wavelength increases.
Explanation;
Sound waves are a type of mechanical wave which requires a material medium for transmission. The transmission of such waves occurs as a result of vibration of particles in the material medium. The faster the vibration of the particles the higher the speed of the sound waves.
When a sound enters a new medium where the sound travels faster, it means the vibration of particles is high, and the wavelength of the waves increases which means the speed of the wave has increased. The frequency on the other hand will remain constant.
Answer:
A. The frequency stays the same and the wavelength decreases
Explanation:(Plato)
A tow rope pulls a skier of mass 75 kg up a hill with a force of 20 N. The skier is moving at constant speed. The hill has an incline of 25 degrees. What is the value of the force of friction on the skier? What is the value of the normal force?
Answers
The magnitude of the frictional force on the skier is 20 N.
The magnitude of the vertical force of skier is 666.14 N.
What is the frictional force on the skier?The value of the frictional force on the skier is determined by applying Newton's second law of motion as follows;
F - Ff = ma
where;
F is the applied force in horizontal directionFf is the frictional force m is the mass of the skier a is the acceleration of the skierAt a constant speed, the acceleration, a = 0
F - Ff = 0
F = Ff
20 N = Ff
The vertical force due to weight of the skier is calculated as follows;
Fₙ = mg cosθ
where;
θ is the angle of inclination of the hillFₙ = (75 x 9.8) cos(25)
Fₙ = 666.14 N
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In the space provided, explain how Earth’s rotation is connected to daytime and nighttime.
Answers
Earth’s rotation is the spinning of the planet on its axis, which takes approximately 24 hours to complete one full rotation. This rotation is the reason why we experience daytime and nighttime.
As Earth rotates, different parts of the planet are exposed to the sun’s rays at different times. When the side of the Earth that faces the sun is in daylight, it is daytime. Conversely, when the side of the Earth that faces away from the sun is in darkness, it is nighttime.The rotation of Earth also creates a phenomenon called the “solar day”. This is the time it takes for the Earth to rotate exactly once on its axis relative to the position of the sun. The solar day is slightly longer than the 24-hour day that we use for our clocks, as Earth also moves in its orbit around the sun. Therefore, the sun appears to move slightly eastward each day, causing the solar day to be about 4 minutes longer than the 24-hour day.
The rotation of Earth also creates different time zones around the world. As the planet rotates, different parts of the world are exposed to the sun’s rays at different times. For example, when it is noon in New York, it is 9 am in Los Angeles and 5 pm in London. This is because the Earth is divided into 24 time zones, each approximately 15 degrees of longitude wide, and each time zone is one hour ahead or behind the next.
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the region of the atmosphere that is so evenly mixed that it behaves as if it were a single gas is the
Answers
The region of the atmosphere that is so evenly mixed that it behaves as if it were a single gas is known as the homosphere.
This region extends from the Earth's surface up to an altitude of approximately 80-100 kilometers. The homosphere is characterized by a relatively constant composition of gases, primarily nitrogen (78%) and oxygen (21%), with trace amounts of other gases such as carbon dioxide and argon.
The gases in the homosphere are well-mixed due to turbulent mixing processes, which help to distribute gases evenly throughout the region. This homogenous mixing also helps to maintain a relatively stable temperature and pressure profile in the atmosphere.
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Express the work done in Kwh if a motor that does 24000 J of work in two minutes
Answers
To express the work done by a motor in kilowatt-hours (kWh), we need to convert the given values of joules (J) and time.
You mentioned that the motor does 24,000 J of work in two minutes. First, we need to convert the work done from joules to kilowatts. We can do this by dividing the work done (24,000 J) by 3,600,000 (1 kWh = 3.6 x 10^6 J):
24,000 J / 3,600,000 = 0.00666667 kW
Next, we need to convert the time from minutes to hours. There are 60 minutes in an hour, so we divide the time (2 minutes) by 60:
2 minutes / 60 = 0.0333333 hours
Now, we can find the work done in kWh by multiplying the work done in kilowatts (0.00666667 kW) by the time in hours (0.0333333 hours):
0.00666667 kW × 0.0333333 hours = 0.000222222 kWh
So, the work done by the motor in kWh is approximately 0.000222 kWh.
Kilowatt-hours (kWh) are a unit of measurement for the total quantity of electrical energy used or generated over a given period of time. This metric is frequently used to gauge how much energy is utilised by home appliances as well as how much energy is generated from renewable resources like solar and wind energy.
A quantity must have both power (kW) and time (hours) units in order to be converted to kilowatt-hours. Energy bills, which are often expressed in kilowatt-hours per month, and solar panels, whose output is expressed in kilowatt-hours per day or year, are typical instances of quantities that can be converted to kWh. Battery capacity is another item that may be converted to kWh.
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Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth's mass $M$, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.
Answers
The mass of the asteroid would have to be approximately 1.67 x 10^22 kg, or about 2.8% of the mass of the Earth, for the day to become 25% longer.
When the asteroid collides with the Earth at the equator and buries itself just below the surface, it will transfer some of its angular momentum to the planet.
This will cause the Earth to rotate more slowly, resulting in a longer day. To calculate the required mass of the asteroid, we need to use the principle of conservation of angular momentum.
Assuming that the Earth is a uniform sphere and that the asteroid is very small compared to the Earth, the initial angular momentum of the Earth is given by:
L = Iω = (2/5)MR²ω
where I is the moment of inertia of the Earth, ω is the initial angular velocity of the Earth, M is the mass of the Earth, and R is the radius of the Earth.
After the collision, the angular momentum of the Earth will be:
L' = (2/5)MR²(ω/1.25)
where ω/1.25 is the final angular velocity of the Earth, assuming that the day becomes 25% longer.
The change in angular momentum of the Earth is therefore:
ΔL = L' - L = (2/5)MR²(ω/1.25) - (2/5)MR²ω = (2/25)MR²ω
The asteroid must therefore have an angular momentum of:
L_asteroid = -ΔL = -(2/25)MR²ω
Assuming that the asteroid is traveling straight toward the center of the Earth, its angular momentum is given by:
L_asteroid = mvR
where m is the mass of the asteroid, v is its velocity, and R is the radius of the Earth.
Equating these two expressions for the angular momentum of the asteroid, we get:
mvR = -(2/25)MR²ω
Solving for m, we get:
m = -(2/25)(Rω/v)M
Substituting the value for the initial angular velocity of the Earth (ω = 7.292 x 10^-5 rad/s), the radius of the Earth (R = 6.371 x 10^6 m), and the velocity of the asteroid (v = escape velocity = 11.2 km/s), we get:
m = 1.67 x 10^22 kg
Therefore, the mass of the asteroid would have to be approximately 1.67 x 10^22 kg, or about 2.8% of the mass of the Earth, for the day to become 25% longer.
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Melanie is given an unknown substance by her teacher. Melanie’s teacher tells her that the substance has a bitter taste. Melanie also observes that the substance is slippery. These properties indicate that the substance may be which of the following?
Answers
Answer:
base
Explanation:
I hope this helps
Answer:base
Explanation:
The exchange of materials between a cell and its environment takes place across cell?A. MitochondriaB. MembraneC. NucleusD. Nucleolus
Answers
Answer:
I'm not 100% sure but I think its Cell membrane
Explanation:
please, correct me if i'm wrong.
Imagine that a coffee filter is falling through the air after being released from a specific height. The filter accelerates for a time and rotates a bit so that the bottom of the filter is facing down, but then reaches a terminal velocity. Now, it is continuing to fall at a constant speed without tipping or rotating. At this moment, is the coffee cup in equilibrium?
Answers
The moment when the coffee filter fall from the upward, it is in the equilibrium.
A coffee filter is falling through the air after being released from a specific height. The filter accelerates for a time and rotates a bit so that the bottom of the filter is facing down, but then reaches a terminal velocity. Now, it is continuing to fall at a constant speed without tipping or rotating. When it is falling from the height, the gravitational force acting on it and the air resistance acting on it balances out each other. Then there is no net force on the coffee filter that is acting on it either ways. When the filter is going downwards many are the forces they are working on it, but when it is going down all the forces acting on it got cancel out and only the net forces acting on majorly cancel each other effect and it nullifies them and their effect and we got a net zero force on it. Hence, we can conclude that at the moment, when the coffee filter is falling from the height the forces are balance out and there is no net force and the coffee cup is in equilibrium.
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In a laboratory experiment, a student found that a 112-mL aqueous solution containing 2.379 g of a compound had an osmotic pressure of 31.3 mm Hg at 298 K. The compound was also found to be nonvolatile and a nonelectrolyte. What is the molar mass of this compound?
Answers
The molar mass of the compound is approximately 12,720 g/mol.
The van't Hoff equation, which relates the osmotic pressure (π) to the molar concentration (C) of the solution is,
π = iMRT
Where:
π = osmotic pressure
i = van't Hoff factor (for a nonvolatile and nonelectrolyte solute, i = 1)
M = molar concentration (in mol/L)
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin
Convertion of the osmotic pressure from mm Hg to atm,
31.3 mm Hg = 31.3 mm Hg × (1 atm/760 mm Hg) ≈ 0.04118 atm
Rearranging the van't Hoff equation,
M = π / iRT
M = 0.04118 atm / (1 × 0.0821 L·atm/(mol·K) × 298 K) ≈ 0.00167 mol/L
Finding moles,
moles of compound = M × volume in liters
moles of compound = 0.00167 mol/L × 0.112 L ≈ 0.00018704 mol
The molar mass of the compound,
molar mass = mass of compound / moles of compound
molar mass = 2.379 g / 0.00018704 mol ≈ 12720 g/mol
Therefore, the molar mass of the compound is approximately 12,720 g/mol.
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Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.34 kW/m2. How long does it take (in days) for 1.73 ✕ 109 J to arrive on an area of 9.03 m2?
Answers
Given :
Intensity, I = 1.34 kW/m².
Area, A = 3.28 m².
To Find :
Time taken to arrive.
Solution :
Power is given by :
P = I × A
P = 1.34 × 3.28 × 1000 W
P = 4395.2 W
Also, power is given by :
P = E/t
t = E/P
t = 1.73 × 10⁹ J/4395.2 W
t = 393611 s
Converting this time in second to days, we get :
t = 393611/( 24×60×60) days
t = 4.55 days.
Hence, this is the required solution.
which blu-ray standard defines rewritable disks?
Answers
The blu-ray standard that defines rewritable disks is BD-RE which stands for Blu-ray Disc Recordable.
What is BD-RE?
BD-RE stands for Blu-ray Disc Recordable and it refers to two direct to disc optical disc recording technologies that can be recorded on to a Blu-ray-based optical disc with an optical disc recorder.
Thus, the blu-ray standard that defines rewritable disks is BD-RE which stands for Blu-ray Disc Recordable.
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