Arrange the following elements in order of increasing ionization energy
Picture of elements included.

The mass of Fe2S3 formed would be 12.0 g

The limiting reactant is iron (Fe)

The percent yield of iron (III) sulfide would be 108.4%

Fe + S -> FeS

From the equation, we see that one mole of Fe reacts with one mole of S to produce one mole of FeS. To determine the mass of FeS that can be formed, we need to determine which reactant is limiting and which is in excess.

Number of moles of Fe = mass / molar mass = 7.62 g / 55.845 g/mol = 0.136 moles

Number of moles of S = mass / molar mass = 8.67 g / 32.06 g/mol = 0.27 moles

We see that Fe is limiting because there are fewer moles of Fe than S. The stoichiometry of the reaction tells us that one mole of Fe produces one mole of FeS.

The mass of FeS that can be formed is:

mass = number of moles × molar mass

mass = 0.136 moles × 87.91 g/mol (molar mass of FeS)

mass = 12.0 g

percent yield = actual yield / theoretical yield × 100%

percent yield = 13.01 g / 12.0 g × 100%

percent yield = 108.4%

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Answer:Copper oxide + Hydrogen → Copper + Water

Copper sulfate + Zinc → Zinc sulfate + copper

Aluminium + Copper chloride → Aluminium chloride + copper

Copper + Oxygen → Copper oxide

Explanation:

Chemical reactions involves chemical combination of compounds or elements as reactants to form other compounds or elements.

In this case, various reactants given will react exhibiting different types of chemical reactions to form products.

First reaction

Aluminium + Copper chloride → Aluminium chloride + Copper

This is a single displacement reaction in which aluminium which is a more reactive element than copper displaces copper from its salt.

Second reaction

Copper oxide + Hydrogen → Copper + water

It is another example of a single replacement reaction. Hydrogen displaces less reactive metals from their oxide to form water and the metal.

Third reaction

Copper sulfate + Zinc → Zinc sulfate + copper

It is another single replacement reaction.

Zinc is more reactive than copper and therefore replaces copper from its salt solution.

Fourth reaction

Copper + Oxygen → Copper oxide

It is a synthesis reaction.

A synthesis reaction is a reaction in which elements or small compounds combine to form single compound.

Answer:In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

Explanation:

Answer:

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Explanation:

e

Answer: A

Explanation:

Answer:

The answer is A

Explanation:

Answer:

Explanation:

1).  Ca(NO₃)₂ + KI → CaI + K(NO₃)₂

    This equation is incorrect.

    When Ca⁺⁺ reacts with I⁻, final product is CaI₂

    And when K⁺ react with NO₃⁻, final product is KNO₃

    Hence the equation will be,

    Ca(NO₃)₂ + KI → CaI₂ + KNO₃

    Now we have to balance this equation.

     Ca(NO₃)₂ + 2KI → CaI₂ + KNO₃

                          ↓

     Ca(NO₃)₂ + 2KI → CaI₂ + 2KNO₃

2). Ca(NO₃)₂ + KOH → CaOH + K(NO₃)₂

    This equation is incorrect,

    Since the reaction of Ca⁺⁺ with OH⁻ gives the final product     Ca(OH)₂

    And final product of K⁺ and NO₃⁻ is KNO₃

    Therefore, the equation will be,

    Ca(NO₃)₂ + KOH → Ca(OH)₂ + KNO₃

    Now we will balance this equation by changing the coefficients of the      molecules until the number of atoms on both the sides become equal.

    Ca(NO₃)₂ + KOH → Ca(OH)₂ + 2KNO₃

                                ↓

     Ca(NO₃)₂ + 2KOH → Ca(OH)₂ + 2KNO₃

3). Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2Na(NO₃)₂

    This equation is incorrect,

    Since the reaction of Na⁺ and NO₃⁻ gives the final product    NaNO₃.

    Therefore, the correct equation will be,

    Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2NaNO₃

     This equation is in the balanced form.

The given reaction involves the compound cn nh2NH2. To perform this reaction, the necessary reagents are:

C) LiAlH4, H20

LiAlH4 (lithium aluminum hydride) is a strong reducing agent that is capable of reducing the carbonyl group (C=O) present in cn nh2NH2 to a primary alcohol (C-OH) by adding a hydride (H^-) ion. The resulting compound is then hydrolyzed (reaction with water) to give the desired product.

Option A) H20, H+ and B) H20, OH are not suitable reagents as they will not reduce the carbonyl group to a primary alcohol.

Option D) DIBAL-H, H20 (diisobutylaluminum hydride) is a milder reducing agent compared to LiAlH4 and is used for selective reduction of carbonyl groups to aldehydes. It may also cause over-reduction to form primary alcohols, which is not desired in this case.

Option E) CH3 MgBr, H20 (methyl magnesium bromide) is a Grignard reagent that is used for nucleophilic addition reactions. It may react with the carbonyl group to form a tertiary alcohol, which is not the desired product in this case.
Hi! To perform the reaction where you convert a nitrile (CN) to a primary amine (NH2), you would need the following reagents:

Your answer: C) LiAlH4, H2O

LiAlH4 (lithium aluminum hydride) is a strong reducing agent that converts nitriles to primary amines, and H2O is used to quench the reaction.

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In the realm of organic chemistry, a cyano group (CN) can be transformed into an amine group (NH2) using a powerful reducing agent named lithium aluminium hydride (LiAlH4), typically in water. Therefore, the correct choice, in this case, is option C, LiAlH4 and H20. This conversion is a two-step process involving an intermediate imine step.

The student appears to be asking about a reagent suitable for a particular chemical reaction: converting a cyano (CN) group to an amino (NH2) group. This is a topic related to organic chemistry.

The correct reagent for this transformation is generally LiAlH4 (lithium aluminium hydride) in water (H20). So, the correct choice is option C). This substance is a powerful reducing agent known for its ability to convert cyano groups into amino groups.

Please note that this reagent is used in a two-step process:

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Answer:

one mole

There is one mole of carbon atoms in a 0.500-mole sample of C2 H6.

The moles of carbon atoms in 0.500 moles of \(C_2H_6\) is 1.00 mol

In the International System of Units, Mole is the base unit of the amount of any substance.

The reaction is

\(2C + 3H_2 = C_2H_6\)

Now, there is 2 mol of carbon, 3 mol of hydrogen, and 1 mol of ethane.

If 2 mole of carbon is present in one mol of ethane.

Then, in 0.500 ethane there will be half of the mole of carbon present that is 1.

Thus, there are 1.00 moles of carbon present.

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H2S, NF3, and OF2 are three structures in which we can anticipate variations from the idealized bond angle, but CF4 will not, as it lacks a lone pair on the central atom.

The structures have a tetrahedral geometry, which produces a bond angle of 109.8 degrees. Any deviation is the result of central ion lone pair repulsions and x lone pair repulsions.

Thus, there was less attraction between the nitrogen structures, which causes the NF3 bond angle to be less. When it comes to NH3, nitrogen has a stronger electronegative charge than hydrogen. The repulsion between the nitrogen bond grew as a result of it drawing in additional electrons. Consequently, it raises NH3's bond angle relative to NF3's.

This is due to the fact that oxygen has a higher electronegative charge than the sulphur atom, which will cause it to draw more electrons to itself and increase bond pair-bond pair repulsion, which leads to a widening of the bond angle in H2O. H2O's bond angle is 104.5 degrees, while H2S's bond angle is 92.1 degrees.

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DE shielded protons experience a net magnetic field strength that is higher than the Shielded protons.

It experiences various magnetic fields because diverse chemical conditions are present. It comes in two varieties according to the net magnetic field that has been observed: - Protons without shields: De shielded protons are protons that are bound to specific electronegative groups that encounter a stronger net magnetic field. The reason for this is a lower electron density. A higher frequency will be resonant for this kind of proton.

Protons that are connected to particular groups and experience a lower net magnetic field are referred to as shielded protons. More electrons are concentrated around the nucleus as a result. This kind of proton will have a lower resonance frequency.

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The rate law for the given reaction is k[A][B]^3.

Given reaction is 2A + 3B → Products which is first order in A and third order overall.

To find the rate law we need to use the equation for the third-order reaction which is given as :

k[A]^m[B]^n

where, k is the rate constant

m is the order of the reaction with respect to A (i.e., first order in A)

n is the order of the reaction with respect to B (i.e., third order in B)

By substituting the given values , k[A]^1[B]^3

The order of the reaction with respect to A is 1, so we include [A] to the power of 1, which we can write as [A]^1 or simply as [A]. The order of the reaction with respect to B is 3, so we include [B] to the power of 3, which we can write as [B]^3.

The overall rate law is : k[A][B]^3

Thus, the rate law for the given reaction is k[A][B]^3.

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The molecular weight of gas X would be 23.36 g/mol.

According to Graham, the rate of effusion of gases is inversely proportional to the square root of their molecular weights.

Graham's law can be mathematically expressed as:

\(r_1/r_2\) = \(\sqrt{\frac{m_2}{m_1} }\)

Where \(r_1\) and \(r_2\) are rates of diffusion or effusion of gases 1 and 2, and \(m_1\) and \(m_2\) are their molecular weights respectively.

In this case, \(r_x\) = \(2.5r_{SF6}\) and the molecular weight of Sf6 is given as 146 g/mol. Thus:

2.5 = \(\sqrt{\frac{146}{m_x} }\)

6.25 = 146/\(m_x\)

\(m_x\) = 146/6.25

      = 23.36 g/mol

In other words, the molecular weight of gas X would be 23.36 g/mol.

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Answer:

c warm water

Explanation:

Kinetic energy is related to temperature. The molecules in a glass of warm water have more kinetic energy (they move faster – see Racing Molecules) than the molecules in a glass of cold water. The temperature of a substance is the average* amount of kinetic energy its molecules have.

Answer:

hot water

Explanation:

Answer:

a gas dissolved in a solid

Explanation:

The ice that comprise of small amount of dissolved air represent the type of soluton that have a solid dissolved in a gas.

Gas could be considered as the one of the four fundamental states of matter.

A pure gas should be made of individual atoms, elemental molecules that consist from one type of atom, or compound molecules that consist of a variety of atoms.

A gas mixture could be in the form of air that comprise a variety of pure gases.

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Answer:

It has two valence electrons

Answer:

I'd wanna see whats in the nuclues

Explanation:

Because its interesting to know what and how it really looks like up close. I also wanna know if an electron really has a light mass

3a. The mass concentration of H2O in the air when mole fraction of water in the air is 2 percent at P=1 atm at 15 ∘C is 13.5 g/m³.

3b. The mass concentration of oxygen atoms in this gas is 1909.85 μg/m³.

3a. Given: Mole fraction of water in the air = 2%

Pressure, P = 1 atm

Temperature, T = 15 ∘C

We can find the mass concentration of H2O using the formula:

mass concentration = (partial pressure of H2O) / (RT) x MW x 1000

Where, R = 0.0821 L atm mol-1 K-1

T = 15 + 273 = 288 KMW of H2O = 18 g/mol

The partial pressure of H2O can be calculated using Dalton's law of partial pressure:

P H2O = mole fraction of H2O x total pressure

= 0.02 x 1 atm

= 0.02 atm

Substitute the values into the mass concentration equation:

mass concentration = (0.02 atm) / (0.0821 L atm mol-1 K-1 × 288 K) × (18 g/mol) × 1000

= 13.5 g/m³

Therefore, the mass concentration of H2O in the air when mole fraction of water in the air is 2 percent at P=1 atm at 15 ∘C is 13.5 g/m³.

3b. Given:

Pressure, P = 1 atm

Temperature, T = 15 ∘C

We need to find the mass concentration of oxygen atoms in this gas. For this, we first need to find the mole fraction of oxygen. We can use the following formula:

mole fraction of oxygen = 1 - (mole fraction of water + mole fraction of other gases)

Mole fraction of water = 2/100 = 0.02

Mole fraction of other gases = 1 - mole fraction of water

= 1 - 0.02

= 0.98

At standard conditions, 1 mole of gas occupies 22.4 L.

But at given conditions (P=1 atm and T=15 ∘C),

the volume occupied by 1 mole of gas can be found using the following equation:

PV = nRTV = (nRT) / PM

where, V = volume of 1 mole of gas

n = number of moles of gas

R = universal gas constant = 0.0821 L atm mol-1 K-1

T = 15 + 273 = 288 K

Now, we can find the number of moles of oxygen atoms using the following formula:

number of moles of oxygen atoms = (mass concentration of other gases) / (MO of O2)

Where, MO of O2 = 32 g/mol

Now, we can calculate the mass concentration of oxygen atoms using the following formula:

mass concentration of oxygen atoms = (number of moles of oxygen atoms) × (MO of O2) × (1000 μg/mg) / (volume of 1 mole of gas)

Substitute the values into the above equations:

V = (1 × 0.0821 × 288) / 1

= 23.74 L/mol

Number of moles of oxygen atoms = (0.98) / (32 g/mol)

= 0.030625 mol

Mass concentration of oxygen atoms = (0.030625 mol) × (32 g/mol) × (1000 μg/mg) / (23.74 L/mol)

= 1909.85 μg/m³

Therefore, the mass concentration of oxygen atoms in this gas is 1909.85 μg/m³.

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One method to synthesize cyclohexanol from bromocyclohexane that would form little or no cyclohexene is by using a mild reducing agent like lithium aluminum hydride (LiAlH4) instead of hydroxide ion by SN1 Reaction.

LiAlH4 reduces the alkyl halide to an alcohol without forming an alkene as a byproduct. The reaction can be carried out in anhydrous ether or THF solvent at low temperatures (-78°C to 0°C) to minimize the formation of the undesired alkene. The resulting product can then be purified by distillation or extraction to obtain pure cyclohexanol.

The number of stages in the reaction, the sequence in which bonds are broken and created, the step that determines reaction rate, the dependence of reaction rate on nucleophile concentration, and the stereochemistry of the product generated are the distinctions between SN1 and SN2 reactions.

There are two distinct pathways for nucleophilic substitution reactions: SN1 and SN2. SN1 is an abbreviation for the substitution nucleophilic unimolecular process. In an SN1 reaction, there are two stages to the reaction. The departing group will depart first, followed by the creation of a carbocation interim. The carbocation will then be attacked by the nucleophile, generating the product. Only the concentration of the substrate, not the concentration of the nucleophile, determines the rate of the reaction.

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The equilibrium constant can be calculated using the relationship ΔGo = -RTln(K), where R is the gas constant and T is the temperature in kelvin. By rearranging this equation, we can solve for K. The correct answer is 6.82 × 10^4.

To explain this further, ΔGo represents the standard free energy change of a reaction, which is a measure of the molecular amount of useful work that can be obtained from the reaction. If ΔGo is negative, then the reaction is exergonic and will proceed spontaneously in the forward direction. K is the equilibrium constant, which is a measure of the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. A larger value of K indicates that the products are favored at equilibrium, while a smaller value of K indicates that the reactants are favored. The relationship between ΔGo and K allows us to determine the equilibrium constant of a reaction based on its free energy change.

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Answer:

Gravity is the force that pulls all objects in the universe toward each other. On Earth, gravity pulls all objects "downward" toward the center of the planet.

Explanation:

Answer:

Gravity

Explanation:

The force of gravity pulls everything toward the Earth.

Filtration can be used to separate the water-soluble acetic acid from the aspirin. The limiting reagent will be salicyclic acid.

How can we determine the limiting reagent?

By dividing the volume of each solution by its molarity, you can determine how many moles of each reactant there are. By subtracting the number of moles of each reactant from its stoichiometric coefficient in the balanced chemical equation, you may determine which reactant is the limiting one.

How many grams of aspirin were created during the process of making it?

This resulted in an estimated value of 3.029 grams for crude synthesized aspirin. The final aspirin product's calculated mass after purification was 2.169 grams. A theoretical yield of 2.520 grams was computed.

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The quantity in moles of NH3 in 55.0 ml of 0.200 M NH3 is 0.011 moles.

Molarity (M) = (moles of solute) / (liters of solution)

0.200 M NH3 means 0.200 moles of NH3 is present in 1 liter of solution. Since the given solution is not in liters, we need to convert the volume from ml to L.55.0 ml = 0.055 L

Now, we can use the molarity formula to calculate the number of moles of NH3 in the given solution.

Molarity (M) = (moles of solute) / (liters of solution)

0.200 M = (moles of NH3) / 0.055 L

moles of NH3 = 0.200 M × 0.055 L

moles of NH3 = 0.011 moles

Therefore, the quantity in moles of NH3 in 55.0 ml of 0.200 M NH3 is 0.011 moles.

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A carbon-carbon bond has an average bond dissociation energy of 410 kj/mol. The energy of UV radiation at wavelength 292 in nanometers is 410 kj/mol.

The wavelength of a wave is the separation between its two crests or troughs. In the direction of the wave is measured.

The wavelength of a wave is the distance it travels between its crests and troughs (which may be an electromagnetic wave, a sound wave, or the any other wave). The peak of a wave is at its crest, and its trough is at its top. It is given in length units like meters, centimeters, millimeters, and nanometers because wavelength is a measurement of both length and distance.

Light's wavelength changes with color, meaning that it differs for each hue. Violet has the shortest wavelength while red has longest. Compared to violet light, UV radiation has a shorter wavelength. In a similar vein, infrared energy has a larger wavelength than red light.

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In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).

A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, an intermediate chemical equation is presented as follows:

As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.

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We have the balanced equation for the reaction.

To determine which is the limiting reactant we must know the moles of both reactants. We have the moles of Al equal to 3.8 mol. We calculate the moles of HCl with the data that they give us of molarity and volume in the following way:

Now, the ratio according to the HCl to Al reaction equation is 6/2=3/1.

The HCl to Al ratio that we have according to the available moles is: 10/3.8=2.63. This ratio is lower than the theoretical one, that is, there are not enough moles of HCl if all the moles of Al are to be reacted. Therefore, HCl is the limiting reactant.

The calculations are made according to the moles of HCl available. Now the ratio H2 to HCl is 3/6=1/2. So the moles of H2 will be:

The theoretical yield is 5.0molH2.

The answer is: 5.0 moles of H2, HCl being the LR. 4th option

Any capacity for doing work is called energy. It is a quantity and can be of various forms. Energy is getting transferred from arm muscles to the ball.

Energy is the work done by the object to perform any given task and is dependent on the factors like the distance and the force applied.

When Abin lifts the bowling ball then the object is displaced from its original position and some amount of force is applied by the arm muscles.

The chemical energy stored in the arm of Abin is a form of energy and gets transferred to the ball from the muscles so it can be lifted.

Therefore, option B. energy is transferred from the arms muscles to the ball.

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Answer:

B. It is being transferred from his arm muscles to the ball.

Explanation:

got it right.

Answer:

D

Explanation:

WOOOOOO

The statement which best compares DNA and RNA with regard to the process of protein production is that RNA leaves the nucleus during the process and DNA remains in the nucleus.

DNA is a hereditary material which is present in human beings as well as all other living organisms.  Every cell which is present in an organism's body has DNA  which is the same. Most of the DNA is situated in the cell's nucleus  and small amount of it can be found in the cell's mitochondria as well.

Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.

DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule  and a phosphate group. A base, phosphate  sugar are together called as nucleotides.

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They must also possess a fixed crystalline structure (spatial arrangement of atoms and ions).

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Answer:

4 significant figures

Reason

The reason is count from 9 and all the decimal. it would be different if there was 0.09768.

The two compounds that are not isomers of each other are:

b. CH3CH2OH (ethanol) and CH3OCH3 (dimethyl ether).

Isomers are compounds that have the same molecular formula but different structural arrangements or connectivity of atoms. Let's analyze the options to identify the correct pair of non-isomeric compounds.

a. n-pentane and 2-methylbutane:

These compounds have the same molecular formula, C5H12, but differ in the arrangement of carbon atoms. Therefore, they are isomers of each other.

b. CH3CH2OH and CH3OCH3:

These compounds have different molecular formulas, with CH3CH2OH representing ethanol and CH3OCH3 representing dimethyl ether. They differ both in their molecular formulas and structural arrangements, so they are not isomers of each other.

c. CH3COOH and CH3CH2COOH:

These compounds have different molecular formulas, with CH3COOH representing acetic acid and CH3CH2COOH representing propanoic acid. Like the previous case, they differ in both molecular formulas and structural arrangements, making them non-isomers.

d. CH3COCH3 and CH3CH2CHO:

These compounds are isomers of each other since they have the same molecular formula, C3H6O, but differ in the connectivity of atoms. CH3COCH3 represents acetone, while CH3CH2CHO represents propanal.

e. CH3CH2CH2Cl and CH3CHClCH3:

These compounds are isomers of each other, with the same molecular formula, C3H7Cl, but different arrangements of atoms. CH3CH2CH2Cl represents 1-chloropropane, and CH3CHClCH3 represents 2-chloropropane.

To summarize, the pair of compounds that are not isomers of each other is b. CH3CH2OH and CH3OCH3.

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