an object initially at rest falls from a height h until it reaches the ground. two of the following energy bar charts represent the kinetic energy k and gravitational potential energy ug of the object-earth system at two positions. the first position is when the object is initially released, and the second position is when the object is halfway between its release point and the ground. which two charts could represent the mechanical energy of the object-earth system? select two answers.

Answer:

mirrors set parallel to each other at 45 degree angle.

real

The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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Average speed =

(total distance)

divided by

(total time).

That's 28.57 miles per hour.

The average speed of Big Bird is 0.384 miles/minute.

The average speed of a body is the ratio of the total distance travelled and the time taken to travel that distance.

The total distance travelled = 50 miles

total time taken = 130 minutes

Average speed = 50 miles/130 minutes = 0.384 miles/minute.

Therefore, the average speed of Big Bird is 0.384 miles/minute.

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Answer:

44.6 N

Explanation:

Draw a free body diagram of the block.  There are four forces on the block:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

and applied force F pulling right 30° above horizontal.

Sum of forces in the y direction:

∑F = ma

N + F sin 30° − mg = 0

N = mg − F sin 30°

Sum of forces in the x direction:

∑F = ma

F cos 30° − Nμ = 0

F cos 30° = Nμ

N = F cos 30° / μ

Substitute:

mg − F sin 30° = F cos 30° / μ

mg = F sin 30° + (F cos 30° / μ)

Plug in values:

mg = 20 N sin 30° + (20 N cos 30° / 0.5)

mg = 44.6 N

Answer:

24.64N

Explanation:

The force inclined at 30° exerted on the block has two components the horizontal and vertical components .

The vertical component force is ;

FsinA; where A is angle of inclination.

20sin30° = 10N

The horizontal component is ;

20cos30° = 17.32N

Now the normal reaction is a vertical upward force acting opposite to the weight.

Note also that for the body to slide it has to overcome a limiting Frictional force and this force must be 17.32N since it's this horizontal component that makes the body slide.

We can then go on to compute the normal reaction from the coefficient of friction formula given as;

Limiting Frictional Force/ Normal reaction

By change of subject formula;

Normal reaction = Limiting frictional force /coefficient of friction

By substituting the equivalent values of limiting Frictional force and coefficient of friction, we have:

17.32N/0.5 = 34.64N

Now since the object didn't fall downwards it means the sum of upward force is the same as the sum of down ward force.

The downward forces are the weight of the object and the vertical component of the applied force when the normal reaction is the upward force.

Expressed mathematically, we have:

34.64= 10 + weight of object

Hence weight of object = 34.64-10= 24.64N

Answer:

they are both types of changes that can occur in various forms of matter.

Explanation:

hope that helps

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12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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Answer:

The elastic potential energy stored in a spring can be calculated using the formula:

E = (1/2) kx^2

where E is the elastic potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

Plugging in the given values, we get:

E = (1/2) (80 N/m) (0.1 m)^2

E = (1/2) (80 N/m) (0.01 m^2)

E = 0.4 J

Therefore, the elastic potential energy stored in the spring when it is compressed by 0.1m is 0.4 J.

Answer:

Its liquid because when you pour water into different cups of different sizes its still the same shape

Answer:

Explanation:.

Answer:

a. i. conducting wire

ii high-pass and low-pass filters

iii. Cobra-4 Xpert-link

iii. voltage source

b. Power generated is 3.6 W.

Explanation:

Ohm's law state that the current passing through a metallic conductor, e.g wire is directly proportional to the potential difference across its ends, provided temperature is constant.

i.e      V = IR

i. conducting wire

ii high-pass and low-pass filters

iii. Cobra-4 Xpert-link

iii. voltage source

b. Given that; V = 12 V and R = 40 Ohm's.

P = IV

From Ohm's law, I = \(\frac{V}{R}\)

So that;

P = \(\frac{V^{2} }{R}\)

   = \(\frac{12^{2} }{40}\)

  = \(\frac{144}{40}\)

 = 3.6 W

The power is 3.6 W.

The starting displacement can be used to determine the amplitude A is 0.5 ft.

The formula for the frequency f is f = 0.277 Hz.The frequency is inversed by the interval T ≈ 3.606 s.Let's start by finding the spring constant k. The weight of the ball is W = 64 lb = 64/32 = 2 slugs, and the spring is stretched 4 ft by this weight, so k = W/x = 2/(4/12) = 6 lb/ft.The equation of motion for the ball is mx'' + kx = 0, where m is the mass of the ball.

The mass can be found from its weight: m = W/g = 64/32 = 2 slugs. The displacement x(t) can be expressed as x(t) = A*cos(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the initial phase angle. Substituting this into the equation of motion, we get:-mω²Acos(ωt + φ) + kAcos(ωt + φ) = 0

Dividing both sides by A*cos(ωt + φ) (which is non-zero),

we get:-mω² + k = 0ω² = k/m = 3 rad/s²ω = √(3) rad/s.

The amplitude A can be found from the initial displacement: A = x(0) = 6/12 = 0.5 ft.The frequency f is given by f = ω/(2π) = √(3)/(2π) ≈ 0.277 Hz.The period T is the inverse of the frequency: T = 1/f ≈ 3.606 s.

The ball passes its equilibrium position twice per period, so its speed at this point is zero. The maximum speed occurs at the amplitude, where the kinetic energy is maximum and the potential energy is zero. At this point, all the energy is kinetic, so:1/2mv² = 1/2kA²v = √(k/m)*A = √(3)*0.5 ≈ 0.866 ft/s.

Therefore, the position of the ball at time t is:x(t) = 0.5*cos(√(3)*t)where x is measured in feet and t is measured in seconds.

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According to the Aristotle,

The object with more weight falls with more acceleration than the object with small weight.

According to the Galileo,

All the objects will fall at the constant rate.

Galileo proved the Aristotle wrong by showing that all the objects fall at the same rate. Thus, discovered the law of inertia.

As the acceleration of all the particles falling is constant.

Hence, the fourth option is the correct answer.

Answer:

The answer is "6:45 and 7:15".

Explanation:

In the given attache file two clocks are added, that's explanation defined as follows:

In the left image, it may assume, that the clock only at the right-hand side of a scene is move-in its previous position, which is shown to the left, as it was at 6:45 on the left but in the right image it will display the time that is 7:15.

The ions are;

S^2- Gained 2 electrons

Li^+ - Lost one electron

Al^3+ - Lost 3 electrons

Cl^- gained one electron

Sr^2+ Lost two electrons

P^3- gained 3 electrons

As an atom or molecule acquires or loses one or more electrons, ions are created. Protons and neutrons make up the positively charged nucleus of an atom, which is encircled by negatively charged electrons. An atom typically has a neutral charge because the amount of electrons and protons in it equals one.

The balance between the negatively charged electrons and positively charged protons is upset when an atom receives or loses an electron, creating an ion with a positive or negative charge.

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Answer:

  72.5 A

Explanation:

There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.

  V = πr²h  . . . . .  volume of a cylinder

  V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s

Then the charge flow rate is ...

  (13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s

The magnitude of the current is about 72.5 amperes.

______

Additional comment

The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.

Angle of incidence=angle of refraction

\(\\ \sf\longmapsto sin\:i=sin\:r\)

\(\\ \sf\longmapsto sin\:r=30°\)

Answer:

Frequency = 25 / 10 = 2.5 Hz

Explanation:

If the wave oscillates up and down 25 times in 10 seconds, then the frequency can be calculated as follows:

Frequency = Number of oscillations / Time

In this case, the number of oscillations is 25, and the time is 10 seconds. Therefore, the frequency is:

Frequency = 25 / 10 = 2.5 Hz

So the frequency of the wave is 2.5 Hertz, which means it completes 2.5 cycles or oscillations in one second.

The maximum height reached by the baseball is 31.89 m and the time taken to reach there is 1.3 seconds

Linear motions are straight line motions. It can be horizontal motion, or vertical motion which is motion under gravity.

Given that a baseball is hit almost straight up into the air with a speed of 25m/s estimate how high it goes.

At the maximum height, final velocity V = 0

Using third equation of motion, that is, V² = U² - 2gH, we can estimate how high it goes.

0 = 25² - 2 × 9.8 × H

625 = 19.6H

H = 625/19.6

H = 31.89 m

To know how long it is in the air, the factors that make this estimate will be

Speed = s / t

25 = 31.89 / t

t = 31.89 / 25

t = 1.2756

t = 1.3 s

Therefore, the maximum height reached by the baseball is 31.89 m and the time taken to reach there is 1.3 seconds

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Answer:

The technician must heat the frame to a temperature of T₂ = 0.0072°C

Explanation:

Change in one-dimension of an object upon heating is given by the following equation:

ΔL = α L ΔT

For the radius this equation can be re-written as follows:

ΔR = α R ΔT

where,

ΔR = Change in Radius =  2.16 cm - 2.14 cm = 0.02 cm

α = Thermal Expansion Coefficient = 1.3 x 10⁻⁴ /°C

R = Original Radius = 2.14 cm

ΔT = Change in Temperature = T₂ - 20°C

Therefore,

0.02 cm = (1.3 x 10⁻⁴ /°C)(2.14 cm)(T₂ - 20°C)

T₂ - 20°C = (0.02 cm)/(1.3 x 10⁻⁴ /°C)(2.14 cm)

T₂ = 0.0072°C + 20°C

T₂ = 20.0072°C

Answer:

They are the same.

Both have potential energy of M g H   and that is the energy that will be converted to kinetic energy for each twin,

65.78meters does the sled travel on the level surface before coming to a rest.

Final speed = 7 m/s

Coefficient of kinetic friction = 0.042

Weight of girl and sled together = 764 Newton

Acceleration of gravity = 9.8 m/s².

To find how far (distance) the sled travel on the level  ground before coming to a rest:

Mathematically, the force of kinetic friction is given by the formula;

\($F_k=u m g$\).........(1)

Where;

F_k represents the force of kinetic friction.

μ represents the coefficient of friction.

m represents the mass.

g is the acceleration due to gravity.

The decelerating force exerted on the sled is given by the formula:

\($F=-m a$\)  ........(2)

First of all, we would determine the deceleration of the sled before coming to a rest.

Equating the two equations, we have:

\($u m g=-m a$\)

\($a=-u g$\)

Substituting the given parameters into the formula, we have;

a =-  0.042*9.8

a= -\($0^2=7^2+2(-0.0.4116) S$\)0.4116m/s²

Now, we can determine how far (distance) the sled traveled by using the third equation of motion;

\($V^2=U^2+2 a S$\)

\($0^2=7^2+2(-0.3724) S$\)

= 49- 0.7448 s

s=65.78meters.

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Answer:

No because it could run out of gas quicker or get into a reck.

Explanation:

Answer:

Explanation:

The enclosure will behave as black body . For black body , the formula for radiant energy is given by Stefan's law as follows

E = σ A T⁴ where σ = 5.67 x 10⁻⁸ W m⁻² T⁻⁴

Area A = .01 m²

E = 48 W

48 = .01 x 5.67 x 10⁻⁸ T⁴

T⁴ =  846.56 x 10⁸

T= 539 K

Following are the calculation to the temperature of the interior enclosure wall:

Given:

\(\to A_s=50\ m^2\\\\\to A_0=0.01\ m^2\\\\\to q_{rad}=48\ w\\\\\to \sigma = 5.67 \times 10^{-8}\ \frac{W}{m^{-2} T^{-4}} \\\\\)

To find:

\(T_s=?\)

Solution:

Using the value to calculate the surface is black radiates power:

\(\to q_{rad}=A_0 E_0 T_s\\\\\to q_{rad}=A_0 \sigma T_{s}^4\\\\\to 48=0.01 \times 5.67 \times 10^{-8} \times T_{s}^4\\\\\)

\(\to T_{s}^4 =\frac{48}{0.01 \times 5.67 \times 10^{-8}} \\\\\)

        \(=\frac{48\times 100}{ 5.67 \times 10^{-8}} \\\\=\frac{48\times 100\times 10^{8} }{ 5.67 } \\\\=\frac{48\times 10^{10} }{ 5.67 } \\\\=8.46\times 10^{10} \\\\\)

\(\to \bold{T_s=\pm 539.31 \ K}\)

Therefore the final answer is "\(\bold{\pm 539.31 \ K}\)".

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Answer:

Explanation:

1. x-axis: Temperature (in degrees Celsius)

2. y-axis: Heat (in Joules)

3. Title: Heating Curve for Water

4. All 3 phases of matter: solid (ice), liquid (water), gas (steam)

5. Show where KE is increasing: The line segment from A to B represents the increase in kinetic energy as the water is heated from solid to liquid state, and the line segment from C to D represents the increase in kinetic energy as the water is heated from liquid to gas state.

6. Show where PE is increasing: The line segment from A to B represents the increase in potential energy as the ice is melting into water, and the line segment from C to D represents the increase in potential energy as the liquid water is vaporizing into steam.

7. Identify the phase changes: The segment from A to B represents the melting of ice (solid to liquid), and the segment from C to D represents the vaporization of water (liquid to gas). The flat portions between B and C represent the heating of water in liquid state and the absorption of heat without any change in temperature (latent heat of fusion and latent heat of vaporization).

Answer:

x = 3472 [m]

Explanation:

To solve this problem we must use the following expression of kinematics:

\(v_{f}^{2}= v_{i}^{2}+(2*a*x)\\\)

where:

Vi = initial velocity = 0

Vf = final velocity = 300 [km/h]

a = acceleration = 1 [m/s^2]

x = takeoff distance [m]

Note: The initial velocity is equal to zero as avion starts its movement from rest.

Now we have to convert units of kilometers per hour to meters per second, the final velocity.

\(300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ]\)

(83.33)^2 = 0 + (2*1*x)

2*x = 6943.88

x = 3472 [m]

Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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Answer:

Melting and frezzing are physical changes

The temperature of a substance is determined by the average kinetic energy of its particles, so Substance X and Substance Y have higher temperatures because their particles have more kinetic energy. The number of particles does not affect temperature. The correct options are (A) and (C).

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Answer:

Describe how one-dimensional vector quantities are added or subtracted.

The statement that must be true is:  (Area of 1) + (Area of 2) = (Area of 3). This statement accurately reflects the relationship between the areas of the squares in the given diagram.

The correct answer is option B.

To determine which statement about the squares must be true, let's analyze the given diagram and the properties of squares.

In the diagram, square 1 is constructed on one side of the right triangle, square 2 is constructed on another side of the right triangle, and square 3 is constructed on the hypotenuse of the right triangle.

Statement A: (Perimeter of 1) + (Perimeter of 2) = (Area of 3)

This statement relates to the perimeters of squares 1 and 2 being equal to the area of square 3. However, this is not necessarily true. The perimeters of squares 1 and 2 are related to the lengths of their sides, while the area of square 3 is related to the length of its side. The perimeters and areas are different measures, so this statement is not necessarily true.

Statement B: (Area of 1) + (Area of 2) = (Area of 3)

This statement compares the areas of squares 1 and 2 to the area of square 3. Since squares have all sides equal in length, the areas of squares 1 and 2 are equal to the area of square 3. Therefore, this statement must be true

Statement C: (Perimeter of 1) + (Perimeter of 2) = (Perimeter of 3)

This statement relates to the perimeters of squares 1 and 2 being equal to the perimeter of square 3. However, since the squares have different side lengths, their perimeters are different. Therefore, this statement is not necessarily true.

Statement D: (Area of 1) + (Area of 2) = (Perimeter of 3)

This statement compares the areas of squares 1 and 2 to the perimeter of square 3. As mentioned earlier, the areas of squares 1 and 2 are equal to the area of square 3, which means they are not necessarily equal to the perimeter of square 3. Hence, this statement is not necessarily true.

Therefore, the correct statement is option B.

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