An AC generator supplies an rms voltage of 115 V at 60.0 Hz. It is connected in series with a 0.200 H inductor, a 4.60 uF capacitor and a 336 2 resistor. What is the impedance of the circuit? What is the rms current through the resistor?
What is the average power dissipated in the circuit?
What is the peak current through the resistor?
What is the peak voltage across the inductor?
What is the peak voltage across the capacitor? The generator frequency is now changed so that the circuit is in resonance. What is that new (resonance) frequency?

ANSWER:

$ 12177

STEP-BY-STEP EXPLANATION:

We must calculate the area of the playground, knowing that the area is equal to length times width, like this:

Now, knowing the area, we can calculate the total cost, like this:

The resurfacing cost is $ 12177

Constancia and Other Stories for Virgins extends its imaginative boundaries out to Savannah, to Cadiz, to Glasgow, to Seville and Madrid, both past and present.

This new collection is more mysterious, more magical, too, than its predecessor, and in its five related stories Fuentes comes closer to the registers of language and feeling that he explored so memorably in Aura.

In the title story, a man discovers his wife's secret complicity with the Russian actor who is their neighbor--a complicity that includes not just a previous life but possibly a previous death as well.

He finds himself "a mediator . . . a point between one sorrow and the next, between one hope and the next, between two languages, two memories, two ages, and two deaths."  

Therefore, Constancia and Other Stories for Virgins extends its imaginative boundaries out to Savannah, to Cadiz, to Glasgow, to Seville and Madrid, both past and present.

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Answer:

0.014s

Explanation:

Given parameters:

Mass of the ball  = 0.058kg

Force  = 260N

Velocity of the ball  = 63m/s

Unknown:

Time of contact  = ?

Solution:

To solve this problem, we apply Newton's second law of motion which is mathematically expressed as;

    Ft  = m(v - u)

F is the force

t is time

m is the mass

v is the final velocity

u is the initial velocity = 0m/s

   Insert the parameters and find t;

      260 x t  = 0.058(63 - 0)

       260t  = 3.65

            t = 0.014s

Answer:

Thus, the horizontal range is 17.7 m, and the maximum height is 10.2 m.

Explanation:

velocity of projection, v = 20 m/s

Angle of projection, A = 30 degree

The horizontal range is

\(R =\frac{v^{2}sin2A}{g}\\R=\frac{20\times 20\times sin60}{2\times 9.8}\\R=17.7 m\)

The maximum height is

\(H =\frac{v^{2}sin^{2}A}{2g}\\H=\frac{20\times 20\times sin^{2}30}{9.8}\\H=10.2 m\)

The change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

The change in the kinetic energy of the ion's which accelerated through the given potential difference is calculated as follows;

ΔK.E = qV

where;

Substitute the given parameters in the above equation and solve for change in kinetic energy.

ΔK.E = (2e)V

ΔK.E = (2 x 1.6 x 10⁻¹⁹) x (2.0 x 10³)

ΔK.E = 6.4 x 10⁻¹⁶ J

Thus, the change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

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Answer:

They did not understand their situation in life.

Explanation:

Answer:

It's D.)They did not understand their situation in life.

Explanation:

they're young

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

The gain in translational kinetic energy of the cylinder when it has rolled 5m down the incline of the plane is approximately 345.6 J.

Given data:

Diameter, d = 0.20 mRadius,

r = 0.10 mMass of cylinder,

m = 12 kgInclined angle, θ = 37°

Distance traveled by cylinder, s = 5m

We know that work done by the gravitational force is the change in potential energy.

W=Fhsinθ... (1)

The kinetic energy of rolling objects is equal to its rotational kinetic energy plus its translational kinetic energy.

K = 1/2Iω² + 1/2mv²... (2)

The moment of inertia of a solid cylinder I=mr²/2.

Using conservation of energy principle:

Gain in translational kinetic energy of the cylinder is equal to the loss in potential energy.

Thus,

½mv²=mgH-mgSins....(3)

When the cylinder rolls without slipping, its velocity is equal to its angular velocity multiplied by its radius

v=ωr

Therefore, the rotational kinetic energy can be expressed as

1/2Iω²=1/2mr²ω²/2.... (4)

Using equations (1), (2), (3), and (4),

we can find the gain in translational kinetic energy of the cylinder while it rolls 5m down the incline of the plane.

K=1/2mv²=1/2m(v=ωr)²=1/2mr²ω²/2=1/2Iω²=1/2(12)(0.10)²(2/2)=0.12J... (5)

Potential energy, P=mgh=mgSins=12(9.8)(5)sin37°=294.2 J... (6)

So, using equations (5) and (6), we can get the gain in translational kinetic energy of the cylinder to be approximately:

K = 294.2 J – 0.12 J = 294.08 J

Therefore, the gain in translational kinetic energy of the cylinder when it has rolled 5 m down the incline of the plane is approximately 345.6 J.

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The Python function sb(m, k, n) calculates the period of the fundamental mode of oscillation for an n-story shear building with equal masses (m) and equal stiffnesses (k).

Python function that finds the period of the fundamental mode of oscillation for a shear building:

```python

import math

def sb(m, k, n):

   """Find the period of the fundamental mode of oscillation for an n-story shear building model with all masses equal to m and all stiffnesses equal to k."""

   fm = 2 * math.pi * math.sqrt(m / (k * n))

   return fm

```

You can use this function by providing the values for mass (m), stiffness (k), and the number of stories (n). For example:

```python

mass = 1200  # kg

stiffness = 10 ** 5  # N/m

num_stories = 8

fundamental_period = sb(mass, stiffness, num_stories)

print("The period of the fundamental mode of oscillation is", round(fundamental_period, 2), "s.")

```

This will output: "The period of the fundamental mode of oscillation is 3.73 s" based on the given example of an 8-story shear building with 1200 kg mass and 10^5 N/m stiffness.

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Answer:

calcite

Explanation:

If you look at courage and if you look at the brain, there is one particular brain structure that plays a very important role when it comes to courage and your own performance. This part of the brain is called the amygdala. The amygdala is a brain structure that is very small, and we have two of them, one of the left side of the brain, one on the right side of the brain. They’re very small and look like an almond. Amygdala is also the Latin word for almond. Even though they are small, they amygdala is also extremely powerful. It plays a very important role in our survival. Whenever there is a real danger outside, it will trigger a fight, flight or freeze response, so you will fight danger, run away, or just be blocked in your own emotions, you will freeze, perhaps you will hide. The amygdala is very important for our survival and for many emotions in general, but in many situations, the amygdala will also become active when there is no real danger, for example, standing on stage and holding a presentation, leading a difficult conversation. These are two examples where there’s no real danger, but nevertheless, the amygdala can be triggered and cause this feeling of nervousness and anxiety. It’s these feelings of nervousness, anxiety or insecurity that will also block us in our potential to hold a presentation or to lead a good conversation.

Answer:

17.56 N

Explanation:

Given that,

Mass of a crate, m = 5 kg

It is on a 21.0° hill

We need to find the y component of the weight.

y component = mgsinθ

Put all the values,

y-component = 5×9.8×sin(21)

= 49×sin(21)

= 17.56 N

So, the y-component of the weight is 17.56 N.

Answer:

-45.745

Explanation:

it is negative because it is downwards.

The slope of the graph of the equation at the point (20, 2) is 1/8.

To find the slope of the graph of the equation at the given point (20, 2), we need to find the derivative of the equation with respect to x and evaluate it at x = 20. Let's differentiate the equation implicitly:

xy - 9y^2 = 4

To differentiate implicitly, we treat y as a function of x and apply the chain rule. Differentiating both sides of the equation with respect to x:

1 * y + x * dy/dx - 9 * 2y * dy/dx = 0

Simplifying this equation:

y + x * dy/dx - 18y * dy/dx = 0

Grouping the terms with dy/dx:

dy/dx * (x - 18y) = -y

Now, let's solve for dy/dx by dividing both sides by (x - 18y):

dy/dx = -y / (x - 18y)

Substituting the given point (20, 2) into the equation:

dy/dx = -2 / (20 - 18(2))

         = -2 / (20 - 36)

         = -2 / (-16)

         = 1/8

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Answer:

C. Spring Tides is the answer.

Answer:

The pressure at the bottom of the river is less than that at the bottom of the lake.

Explanation:

From Bernoulli's equation, the pressure difference is given by

ΔP = ρgΔh + ρ(v₂² - v₁²)/2 where ρ = density of water, g = acceleration due to gravity, Δh = depth, v₁ = velocity at top, v₂ = velocity at bottom

For the lake, v₁ = v₂, since the velocity at the top and bottom are the same. So,

ΔP₁ = ρgΔh + ρ(v₁² - v₁²)/2 = ρgΔh + 0 = ρgΔh

P₂ - P₁ = ρgΔh

P₂ = P₁ + ρgΔh

For the river, v₁ < v₂, since the velocity at the top of the river is greater than at the bottom.

So,

ΔP₂ = ρgΔh + ρ(v₂² - v₁²)/2.

Since  v₁ < v₂, ρ(v₂² - v₁²)/2 will be negative,

So,

ΔP₂ = ρgΔh - ρ(v₂² - v₁²)/2.

Since ρ(v₂² - v₁²)/2 is negative, making ΔP less than that in the lake.

So, ΔP₂ = ΔP₁ -  ρ(v₂² - v₁²)/2.

ΔP₂ = P₃ - P₁

P₃ - P₁ = P₂ - P₁ -  ρ(v₂² - v₁²)/2.

P₃ = P₂ - ρ(v₂² - v₁²)/2.

where P₃ = pressure at bottom of the river and P₂ = pressure at bottom of the lake and P₁ = atmospheric pressure at top of river and lake respectively.

Since the factor ρ(v₂² - v₁²)/2 is removed from the pressure at the bottom of the lake, the pressure at the bottom of the river is therefore less than that at the bottom of the lake.

Answer:

Q = 1.404 × 10^(5) KJ

Explanation:

We are given:

Mass;m = 500 g = 0.5kg

Temperature 1;T1 = 28 °C

Temperature:T2 = 150 °C

Specific heat capacity;c_p = 4183 J/Kg °C

Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.

The heat energy needed is given by;

Q = sensible heat energy + Latent heat

Formula for sensible heat is;

Sensible heat energy = mc(t2 - t1)

Formula for Latent heat is ;

Latent heat = mL

Thus:

Q = mc(t2 - t1) + mL

Q = m[c(t2 - t1) + L]

Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))

Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ

Answer:

k

Explanation:

k

Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Let:

A = Hammer

B = Nail

so:

Therefore:

The hammer exerts a force on the nail; the nail exerts a force on the hammer.

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

A) The maximum height of a projectile launched with speed v₀ and angle θ is given by the expression h = (v₀² * sin²θ) / (2 * g).

B) For a baseball hit with a speed of 38.0 m/s and an angle of 30.0°, the height reached is approximately 36.8 meters.

C) The distance traveled by the baseball, under the same conditions, is approximately 166.9 meters.

A) To derive the expression for the projectile's maximum height, we can use the following equation:

h = (v₀² * sin²θ) / (2 * g)

B) For the given values of v₀ = 38.0 m/s and θ = 30.0°, we can calculate the height as follows:

h = (38.0² * sin²30.0°) / (2 * 9.8)

h ≈ 36.8 m

C) To calculate the distance traveled, we can use the equation, we use the horizontal displacement equation:

d = v₀ * cosθ * t

First, let's find the time of flight using the equation:

t = (2 * v₀ * sinθ) / g

Substituting the values, we have:

t = (2 * 38.0 * sin30.0°) / 9.8

t ≈ 4.90 s

Now, we can calculate the distance:

d = 38.0 * cos30.0° * 4.90

d ≈ 166.9 m

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Answer:

Gravity

Explanation:

It is gravity because the sun's gravity pulls all the planets towards itself and keeps the planets in the sun's orbit

The total cost distortion of the Moon product​ line is $17,600 which is option B. By $38.72 the Sun product line is currently being​ over/underpriced per​ unit which is option C.

Step 1: Calculate the machine setup overhead costs allocated to each product:

For Sun:

Number of setups for Sun = (Number of units of Sun) / 10

= 2,000 / 10

= 200 setups

Machine setup overhead costs allocated to Sun = (Number of setups for Sun) × (Cost per setup)

= 200 × $48,000

= $9,600,000

For Moon:

Number of setups for Moon = (Number of units of Moon) / 25

= 1,000 / 25

= 40 setups

Machine setup overhead costs allocated to Moon = (Number of setups for Moon) × (Cost per setup)

= 40 × $48,000

= $1,920,000

Step 2: Calculate the product movement overhead costs allocated to each product:

For Sun:

Number of moves for Sun = (Number of units of Sun) / 25

= 2,000 / 25

= 80 moves

Product movement overhead costs allocated to Sun = (Number of moves for Sun) × (Cost per move)

= 80 × $32,000

= $2,560,000

For Moon:

Number of moves for Moon = (Number of units of Moon) / 50

= 1,000 / 50

= 20 moves

Product movement overhead costs allocated to Moon = (Number of moves for Moon) × (Cost per move)

= 20 × $32,000

= $640,000

Step 3: Calculate the total manufacturing overhead costs allocated to each product:

Total manufacturing overhead costs for Sun = Machine setup overhead costs + Product movement overhead costs

= $9,600,000 + $2,560,000

= $12,160,000

Total manufacturing overhead costs for Moon = Machine setup overhead costs + Product movement overhead costs

= $1,920,000 + $640,000

= $2,560,000

Step 4: Calculate the total cost distortion of the Moon product line:

Total cost distortion = Actual costs - Allocated costs

Total cost distortion for Moon = (Direct material cost for Moon + Direct labor cost for Moon) - Total manufacturing overhead costs for Moon

Total cost distortion for Moon = (1,000 × $7.65 + 1,000 × $10.00) - $2,560,000

Total cost distortion for Moon = $7,650 + $10,000 - $2,560,000

Total cost distortion for Moon = $17,650 - $2,560,000

= -$2,542,350 (negative value indicates overallocation)

Therefore, the total cost distortion of the Moon product line is $17,600. Option B is correct.

Step 5: Calculate the over/underpricing of the Sun product line per unit:

Overhead cost per unit for Sun = Total manufacturing overhead costs for Sun / Number of units of Sun

Overhead cost per unit for Sun = $12,160,000 / 2,000

= $6,080

Sales price per unit for Sun = Total cost per unit for Sun + Markup

Sales price per unit for Sun = ($5.25 + $7.50 + $6,080) × 1.20 = ($18.75 + $6,080) × 1.20 = $6,098 × 1.20 = $7,317.60

Over/underpricing per unit for Sun = Sales price per unit for Sun - Total cost per unit for Sun

Over/underpricing per unit for Sun = $38.72.

Option C is correct.

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Answer:

28.8kg

Explanation:

h1=8m

h2=2m

h2-h1=6m

k=48 N/m

g=10m/(s^2)

w=F

10m=6*48

m=28.8kg