sheesh sheesh
Explanation:
An 85-kg lumberjack stands at one end of a 340-kg floating log, as shown in the following figure (Figure 1). Both the log and the lumberjack are at rest initially.
A. The lumberjack then trots toward the shore with a speed of 2.7 m/s relative to the shore. What is the speed of the log relative to the shore? Ignore friction between the log and the water
B. If the mass of the log were greater, would its speed relative to the shore be greater than, less than, or the same as the speed found in part A?
i. Greater than speed A
ii. Less than Speed A
iii. The same as speed A
3. Check your answer to part B by calculating the speed relative to the shore for a 410- kg log.
Explanation:
A)
Using Law of conservation of momentum
m1v1 = m2v2
85 kg * 2.7 m/s = 340 kg * v2
v2= .68 m/s
B)
Less
C) 85 * 2.7 = 410 * v2
v2 = .56 m/s
The log's speed is 0.67 m/s relative to the shore. If the log's mass increases, its speed will decrease. In the case of a 410kg log, its speed will be 0.56 m/s.
Explanation:This is a problem related to conservation of momentum. Initially, both the lumberjack and the log are at rest, therefore, the total momentum is zero. When the lumberjack moves, he imparts momentum to the log in the opposite direction. To find this speed, we use the equation of conservation of momentum, which is m1v1 = -m2v2. The lumberjack has a mass of 85kg, and the log has a mass of 340kg, with the lumberjack moving at 2.7 m/s. Therefore, we find that the speed of the log (v2) is 0.67 m/s.
For part B, if the mass of the log is greater, its speed relative to the shore will be less than the speed found in part A. A larger mass requires more force to move at the same speed.
For part 3, if we replace the mass of the log with 410kg and solve for the speed, v2 = (85kg * 2.7m/s) / -410kg, we find that the speed is approximately 0.56 m/s, which verifies the conclusion in part B that a larger mass log moves at a slower speed.
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Which part of a star extends millions of kilometers into space? A. chromosphere B. corona C. photosphere D. radiative zone
The correct answer is
B. corona.
The corona is the outermost layer of a star's atmosphere and extends millions of kilometers into space.
It is composed of extremely hot plasma and is most easily observed during a total solar eclipse when it appears as a faint, pearly-white glow surrounding the darkened disk of the Moon. The other options mentioned are also parts of a star, but they do not extend to the same distances as the corona.
Hot plasma is a state of matter in which particles, such as electrons and ions, are so energized that they become completely or partially ionized. Plasma is often referred to as the fourth state of matter, in addition to solid, liquid, and gas. It is characterized by its ability to conduct electricity and respond to magnetic fields.
When a substance is heated to high temperatures, the thermal energy causes the atoms or molecules to move rapidly, eventually leading to the breaking of chemical bonds. In the case of plasma, the extreme heat causes the atoms to lose electrons, resulting in a mixture of positively charged ions and negatively charged electrons. This ionization process gives rise to a highly conductive medium with unique properties.
Plasmas can be found naturally occurring in phenomena such as lightning, the Sun's corona, and certain types of flames. They can also be created in laboratory settings using various methods, including heating a gas to high temperatures, subjecting it to strong electromagnetic fields.
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Which characteristics of an area could best identify the type of biome it is
Answer: average annual rainfall, average annual temperatures, types of plants and animals native to the area
Explanation: the best way you can identify a biome is by telling which animal or species are native to the certain area
Theoretically, what would be the mass of an object accelerated
to 100% the speed of light?
I know most of the answers will say infinity, but still this needs deeper look about its physical meaning and does it consider a practical logic?
Infinity usually used for something we could not measure, however the reality may be different!
The denominator of the equation would become 0 and the mass would become infinite if the mass's velocity ever surpassed the speed of light.
Speed of light and mass:The amount of energy needed to accelerate an infinite mass would be infinite as well. The fact that light travels at the speed of c indicates that it has no rest mass.
When a mass particle approaches the speed of light, its energy grows and becomes infinite at that speed, which is why it can never be accelerated to that speed.
Experiments have confirmed this, and it has been demonstrated that nothing goes faster than the speed of light.
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1. The International unit of volume closest in size to a liter is:
a. gallon.
b. Ounce
c. Liter
d. cup.
The customary system of measurement is used, in which a gallon is the closest unit of volume to a liter. Option (A) is correct.
The International unit of volume closest in size to a liter is: Liter. The definition of liter, which is the International System unit of volume is "a volume of 1000 cubic centimeters." Since the International System unit of volume is "a volume of 1000 cubic centimeters," the International unit of volume closest in size to a liter is the liter.
In everyday life, liters are frequently utilized to calculate the volume of liquid or dry matter. The liter is used in science and technology for calculations and information storage. A container that holds 1 liter of water is the same as a 1 liter container that holds oil or flour.A liter is abbreviated as "L" or "l" in scientific notation.
It's also abbreviated as "ℓ" (which looks like a script lowercase letter "L") on the Internet, but this is not widely used. In most countries, the metric system of measurement is used for quantity, weight, and volume. In the United States, Liberia, and Myanmar, however, the customary system of measurement is used, in which a gallon is the closest unit of volume to a liter.
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Which is an example of a way that
machines make work easier?
A. They spread a small force over a small
distance.
B. They spread a small force over a larger
distance.
C. They make the force exert all at once.
D. They increase the time it takes to do a task.
Answer:
C Thy make the force exert all at once
A system experiences a change in internal energy of 36 kJ in a process that involves a transfer of 14 kJ of heat into the surroundings. Simultaneously, which of the following is true?
Q= 14 u=36
U=Q-W
14-36=22
22 kJ of work is done on the system. is what i think but its saying its wrong.
The correct calculation for the work done on the system is 22 kJ.
To determine the work done on the system, we can use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat transferred into the system (Q) minus the work done by the system (W). Mathematically, it can be expressed as ΔU = Q - W.
In this case, the given values are Q = 14 kJ (heat transferred into the surroundings) and ΔU = 36 kJ (change in internal energy of the system). We need to find the work done on the system, which is represented by W.
Rearranging the equation to solve for W, we have W = Q - ΔU. Substituting the given values, we get W = 14 kJ - 36 kJ = -22 kJ.
Therefore, the correct answer is that 22 kJ of work is done on the system. The negative sign indicates that work is done on the system, rather than by the system.
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A system experiences a change in internal energy of -36 kJ in a process that involves a transfer of 14 kJ of heat into the surroundings. Simultaneously, which of the following is true?
22 kJ of work is done by the system.
22 kJ of work is done on the system.
50 kJ of work is done by the system.
50 kJ of work is done on the system.
If Bulb B burns
out, what happens?
A Bulb A and C will stay lit.
Answer: C
Explanation:
Since bulb B is burnt out, the wires can't transfer to bulb A, so that's why bulb A will burn out.
If I get it wrong, sorry. Im still learning.
Select the correct answer. Which statement correctly describes protons? A. They have no charge and are present in the nucleus of an atom. B. They have a negative charge and travel around the nucleus of an atom. C. They have a positive charge and travel around the nucleus of an atom. D. They have a positive charge and are present in the nucleus of an atom along with the neutrons.
The statement "They have a positive charge and are present in the nucleus of an atom along with the neutrons" correctly describes protons.
What are protons?Protons are small particles that make up the nucleus of an atom. They carry a positive charge and have a mass of approximately 1 atomic mass unit. The number of protons within an atom's nucleus defines its atomic number and thus its identity as an element.
For instance, carbon atoms have 6 protons, and oxygen atoms have 8 protons. Protons are vital building blocks of all atoms and play a significant role in the chemical behavior and reactions of elements.
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A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.40 m,3.10 m) with a velocity of −5.40
i
^
m/s and an acceleration of +13.7
j
^
m/s
2
. What are the (a) x and (b) y coordinates of the center of the circular path? (a) Number Unit (b) Number Unit
The particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.40 m, 3.10 m) with a velocity of −5.40i m/s and an acceleration of +13.7j m/s2. We are to find the (a) x and (b) y coordinates of the center of the circular path.Solution:
The force causing the circular motion of a particle is the centripetal force, which always acts perpendicular to the instantaneous velocity of the particlFrom the given information, we have:|a| = 13.7 m/s2v = 5.4 m/sThe magnitude of the velocity vector is given as 5.4 m/s. The speed of a particle moving in a circular path is equal to the magnitude of its velocity,
so the speed of the particle is 5.4 m/s.Therefore, the radius of the circular path is:r = v2/|a|= 5.4²/13.7= 2.13 mThus, the particle moves in a circle of radius 2.13 m.To find the center of the circle, we use the fact that it is equidistant from all points on the circle.
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A displacement factor with a magnitude of 20 m could have perpendicular component with magnitude of what
The perpendicular component of a displacement factor with a magnitude of 20 m is 20 m as well. When an object moves from its initial position to a final position, the displacement is the straight-line distance between the two positions and the direction of the displacement is from the initial position to the final position.
A perpendicular component is created when the displacement vector is resolved into two components. When a displacement vector is divided into two perpendicular components, the magnitude of each component is found using the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
This theorem is represented mathematically as: a² + b² = c².Where c is the length of the hypotenuse, and a and b are the lengths of the other two sides of the triangle. In this case, the hypotenuse represents the displacement vector, and the two other sides represent the components of the displacement vector that are perpendicular to each other. Therefore, the perpendicular component of a displacement factor with a magnitude of 20 m is 20 m as well.
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A comet that was seen in April 574 by Chinese astronomers on a day known by them as the Woo Woo day spotted again in May 1994. Assume the time between observation is the period of the Woo Woo day comet and its eccentricity is 0.9932. What are (a) the semimajor axis of the comet's orbit and (b) its greatest distance from the Sun in terms of the mean orbit radius R pof Pluto?
The semimajor axis of the comet's orbit is approximately 3.53 x 10^13 meters.the greatest distance from the Sun of the Woo Woo day comet, expressed in terms of the mean orbit radius R_p of Pluto, is approximately 12.2.
(a) The semimajor axis of the comet's orbit can be calculated using the formula:T^2 = (4π^2 a^3)/(G(M + m))
where T is the period of the comet's orbit, a is the semimajor axis, G is the gravitational constant, M is the mass of the Sun, and m is the mass of the comet (which we assume to be negligible compared to the mass of the Sun). Rearranging the formula, we get:
a = (T^2 G(M + m))/(4π^2)
Substituting the given values, we get:
a = [(1420 years x 365.25 days/year x 24 hours/day x 3600 s/hour)^2 x 6.6743 x 10^-11 N m^2/kg^2 x (1.9891 x 10^30 kg)]/(4π^2) ≈ 3.53 x 10^13 m
Therefore, the semimajor axis of the comet's orbit is approximately 3.53 x 10^13 meters.
(b) The greatest distance from the Sun (aphelion distance) can be calculated using the formula:
r_a = a(1 + e)
where r_a is the aphelion distance and e is the eccentricity of the orbit. Substituting the given values, we get:
r_a = a(1 + e) ≈ 3.53 x 10^13 m x (1 + 0.9932) = 7.19 x 10^13 m
To express the result in terms of the mean orbit radius R_p of Pluto, we can divide the result by the mean distance of Pluto from the Sun:
r_a/R_p = (7.19 x 10^13 m)/(5.91 x 10^12 m) ≈ 12.2
Therefore, the greatest distance from the Sun of the Woo Woo day comet, expressed in terms of the mean orbit radius R_p of Pluto, is approximately 12.2.
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Water is considered to be
Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day
Explanation:
A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 6.0-V battery.
c) Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.
d) Calculate the charge on each capacitor assuming the two capacitors are in parallel.
The potential to difference across each capacitor assuming the two capacitors are in parallel are;
p.d(0.50-μF) = 4.42Vp.d(1.4-μF) = 1.58VThe charge on each capacitor assuming the two capacitors are in parallel are:
Q(0.5-μF) = 0.58CQ(1.4-μF) = 1.64CCapacitors in series and parallel connectionsC) The potential difference, p.d for the capacitors connected in series are inversely proportional to the capacitance and are as follows;
p.d(0.50-μF) = (1.4)/(1.9) × 6 = 4.42Vp.d(1.4-μF) = (0.5)/(1.9) × 6 = 1.58VD) When the connection is parallel, the charge on each capacitor is shared as follows;
First, Total charge, Q = C(total) × V.
where, C(total) = (0.5×1.4)/(1.9) = 0.37-μF.
Q = 0.37 × 6Q = 2.22C
Hence, the charge is shared as follows;
Q(0.5-μF) = (0.5/1.9) × 2.22 = 0.58CQ(1.4-μF) = (1.4/1.9) × 2.22 = 1.64CRead more on capacitors in series and parallel;
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Alika finds a certain kind of butterfly near her house. She reads that ultraviolet light is absorbed by the butterfly’s wings, red light is transmitted through the butterfly’s wings, and green light is reflected off the butterfly’s wings. Alika’s friend Claire tells her that if you shine light on the butterfly, its wings will glow.
Can light cause the butterfly’s wings to glow? Why or why not? Does it matter what type of light Alika shines on the butterfly?
Answer:
No the butterflies wings won't glow.
Explanation:
Butterflies have wings that have different color of attractiveness. Butterflies are however attracted to light but can't absorb the light.
Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is fixed. To keep the spring stretched or compressed an amount x, a force along the x-axis with x-component Fx=kx−bx2+cx3 must be applied to the free end. Here k=100N/m, b=700N/m2, and c=12000N/m3. Note that x>0 when the spring is stretched and x<0 when it is compressed.
Answer:
The work done will be 0.115 J.
Explanation:
Given that,
\(k=100\ N/m\)
\(b=700\ N/m^2\)
\(c=12000\ N/m^3\)
A force along the x-axis with x-component,
\(F(x)=kx-bx^2+cx^3\)
Suppose, How much work must be done to stretch this spring by 0.050 m from its unstretched length?
We need to calculate the work done
Using formula of work done
\(W(x)=\int{F(x)dx}\)
Put the value into the formula
\(W(x)=\int{(kx-bx^2+cx^3)dx}\)
\(W(x)=\dfrac{kx^2}{2}-\dfrac{bx^3}{3}+\dfrac{cx^4}{4}\)
Put the value of k,b,c and x
\(W(0.050)=\dfrac{100\times(0.050)^2}{2}-\dfrac{700\times(0.050)^3}{3}+\dfrac{12000\times(0.050)^4}{4}\)
\(W(0.050)=0.115\ J\)
Hence, The work done will be 0.115 J.
The value of spring displacement is greater than zero. Therefore, spring is stretched.
Force in spring :
It is given as, \(F=kx\)
Where k is constant and x is amount of displacement.
The force function is given that,
\(F(x)=kx-bx^{2}+cx^{3}\)
Here given that, \(k=100N/m, b=700N/m^{2} , c=12000N/m^{3} .\)
Substitute all values in above equation,
\(F(x)=100x-700x^{2} +12000x^{3}\)
To check, the spring is stretched or it is compressed.
Substitute f(x) = 0
We get x is greater than zero.
Thus, The value of spring displacement is greater than zero. Therefore, spring is stretched.
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What is the name of the shuttle with 134 successful launches
International space station is the mission of NASA. It has launched 134 successful space missions.
What is International Space Station ?International space station is a huge place in the space but in the close orbit with all possible facilities for astronauts , scientists and others
What is NASA ?The National Aeronautics and Space Administration (NASA) is an acronym for the National Aeronautics as well as Space Administration. NASA was established as a division of the United States government on October 1, 1958. NASA is just in charge of all research and technology related to aviation and space in the United States.
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5. He slept for eight hours. This sentence has
1. an intransitive verb
2. a transitive verb
3. an object
(it's english)
Answer:
an object (it's English
13. A lever does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's
resulting speed just after leaving the lever is -
.5 m/s
10 m/s
1 m/s
5 m/s
CLEAR ALL
Answer:
The resulting speed of the ball is;
10 m/s
Explanation:
The given parameters are;
The amount of work done by the lever = 5.0 J
The mass of the ball on which the work is done, m = 0.10 kg
By the principle of conservation of energy, we have;
The work done by the lever = The kinetic energy. K.E., gained by the ball
The kinetic energy, K.E., is given by K.E. = 1/2·m·v²
Where, for the ball, we have;
m = The mass of the ball
v = The resulting speed of the ball
Therefore, by substituting the known values, we have;
The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²
∴ 5.0 J = 1/2 × 0.10 kg × v²
v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²
v = √(100 m²/s²) = 10 m/s
The resulting speed of the ball, v = 10 m/s.
The rod of the fixed hydraulic cylinder is moving to the left with a constant speed va = 18 mm/s. Determine the acceleration ab of slider b when sa = 370 mm. The length of the cord is 1515 mm, and the effects of the radius of the small pulley at a may be neglected. The acceleration ab is positive if up
the acceleration at factor B is
24.357m/s2
.the rate of the rod is
VA=15mm/s.
the space of slider is
sA=380mm
The period of the twine is
=1505Mm
The expression of the restrained is given as,
2AB+AC=1505mm
with the aid of differentiating above expression.
2A˙B+A˙C=0
In ΔAPC it's miles proven as,
AC2=AP2+PC2
Differentiate above equation.
2(AC)(A˙C)=2(AP)(A˙P)+0(AC)(A˙C)
=(AP)(VA)
In ΔAPB
it's far proven as,
AB2=AP2+PB2
Differentiate above equation.
2(AB)(A˙B)=2(AP)(A˙P)+2(PB)(P˙B)(AB)(−A˙C)=2(AP)(VA)+2(PB)(−VB)
From the above expressions.
VB=12PB(2AP×VA+ABAPAC×VA)
The expression for the AC is given as,
AC=√AP2+PC2
substitute values within the above expression.
AC=√3802+2002AC=429.42mm
The expression for the AB is given as,
2AB+AC=1505
replacement values within the above expression.
2AB+429.forty two=1505
AB=537.8mm
The expression for the PB is given as,
PB=√AB2−AP2
alternative values in the above expression.
PB=√537.82−3802PB=380.55mm
The expression for the speed at B is given as,
VB=12PB(2AP×VA+ABAPAC×VA)
substitute values within the above expression.
VB=12×380.fifty five(2(380)×(15)+(537.8)380429.forty two×15)VB=24.357m/s
For a unit time period, acceleration of B is given as,
αB=VBtαB=24.3571αB
=24.357m/s2
for this reason, the acceleration at factor B is
24.357m/s2.
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eddy current is induced from the metallic surface which generates a magnetic field that is in opposite orientation of the original magnetic field
The phenomenon you are describing is known as the generation of eddy currents. When a metallic surface is exposed to a changing magnetic field, such as when a magnet is moved near it, eddy currents are induced in the metal. These currents circulate within the metal and generate their own magnetic field.
The direction of the eddy currents' magnetic field is such that it opposes the original magnetic field. This is due to Lenz's law, which states that the induced current will always flow in a direction that creates a magnetic field that opposes the change in the original magnetic field.
To understand this concept better, consider an example: Imagine a metal plate placed in the vicinity of a magnet. When the magnet is moved towards the plate, the magnetic field lines passing through the plate change. As a result, eddy currents are induced in the plate, flowing in circular paths. These currents, in turn, generate a magnetic field that opposes the change in the original magnetic field. This opposition slows down the motion of the magnet, demonstrating the action of the eddy currents.
In summary, eddy currents are induced from a metallic surface when it is exposed to a changing magnetic field. These currents generate a magnetic field that opposes the original magnetic field, according to Lenz's law. Understanding this phenomenon helps explain the behavior of eddy currents in various applications.
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FILL IN THE BLANK. protostars are observable by radio telescopes but hard to detect in visible light because they have ___ and are ___.
protostars are observable by radio telescopes but hard to detect in visible light because they have low surface and are surrounded by dust.
What makes a protostar glow?Although a protostar resembles a star, fusion has not yet begun in its core. The heating of the protostar as it shrinks is the only source of brightness. It is challenging to see protostars in the visible spectrum because they are typically surrounded by dust that absorbs the light that they release.
When a star's core runs out of hydrogen and is left with just helium, the fusion process's outward push starts to weaken, and the star can no longer maintain equilibrium. When internal pressure is no longer able to withstand the force of gravity, the star starts to collapse.
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Which of the following is a true statement?
The oceans replenish groundwater.
The oceans provide water for rivers and streams.
Lakes are only found in the Northern Hemisphere.
Coral reefs and sandbars create lagoons.
Answer:
LAST ONE
Explanation:
Answer:
Coral reefs and sandbars create lagoons.
Explanation:
"The combination of coral growth and water creates a lagoon. It may take as long as 300,000 years for an atoll formation to occur. Coastal lagoons form along gently sloping coasts. They are generally shallower than atoll lagoons and tend to be separated from the ocean by an island, reef, or sand bank." I got my information from google :)
Hope this helps :))))
The image shows positivle and negative charged particles bouncing around. Which state of matter is most likely represented in the image?
Answer:
Gas Solid Liquid Plasma
Explanation:
Answer:
plasma
Explanation:
plasma has charged particles and ions and electrons floating around
A body of mass 5kg is connected by a light inelastic string which is passed over a fixed frictionless pulley to a moveable frictionless pulley of mass 1kg over which is wrapped another light inelastic string which connects masses 3kg and 2kg. Find 1) the acceleration of the masses.
2) the tensions in the strings in terms of g, the acceleration dey to gravity
(a) The acceleration of the masses is determined as 1.1 m/s² in the direction of the 5 kg mass.
(b) The tension in the string in terms of gravity is T = g.
What is the acceleration of the masses?(a) The acceleration of the masses is calculated by applying Newton's second law of motion.
F(net) = ma
where;
m is the massesa is the acceleration of the masses(5 kg x 9.8 m/s² ) - (1 kg + 3 kg )9.8 m/s² = ma
9.8 N = (5kg + 1 kg + 3 kg )a
9.8 = 9a
a = 9.8 / 9
a = 1.1 m/s² in the direction of the 5 kg mass.
(b) The tension in the string in terms of gravity is calculated as follows;
T = ( 5kg)g - (1 kg + 3 kg ) g
T = 5g - 4g
T = g
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label the parts of the milky way as shown here by identifying the galactic plane, an area far from the plane, and the area that is close but not on the galactic plane.
There are 6 parts of galaxy that are visible to us.
The Milky Way Galaxy’s structure is fairly typical of a large spiral system. (Spiral galaxies and other types of galaxies are described in the article galaxy.) This structure can be viewed as consisting of six separate parts: (1) a nucleus, (2) a central bulge, (3) a disk (both a thin and a thick disk), (4) spiral arms, (5) a spherical component, and (6) a massive halo. Some of these components blend into each other. As viewed from Earth, the visible region of the Milky Way's galactic plane occupies an area of the sky that includes 30 constellations. The Galactic Center lies in the direction of Sagittarius, where the Milky Way is brightest. The galactic plane (or galactic equator) is an imaginary plane that slices the Galaxy in half (top and bottom). In the galactic coordinate system, the equator is at galactic latitude b = 0. Galactic coordinate system.
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assume the acrylic d shaped lens is immersed in water. what is the critical angle of the d shaped lens while it is in water
To determine the D- shaped angles of both the incident and refraction light, we'll have used a laser, a piece of substance (glass, acrylics, or filled with a liquid of our choice), and a "rays table."
We shall strong sunlight in the direction of the D-shaped object's flat face. The angle between the light ray's normal as well as the surface normal where the light will strike the surface is i. Afterwards when, it will be refracted and departure from of the surface at an angle of r. Snell's Law stipulates that the ratio of both the refractive index determines the level of light deformation. This configuration will be used to determine the material's index of refraction for the D-shaped device (glass, acrylic or some liquid). To correctly test the refractive index, nevertheless, the apparatus must be positioned with great care.
The critical angle for the crowning glass-water interface is 61.0 degrees. The combination of materials on each side of the barrier determines the real value of both the critical angle. Let's take a look at two distinct media, channel I (incident medium) and intermediate r.
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A hunter in a valley is trying to shoot a deer on a hill. The distance of the deer along his line of sight is 10 181 meters and the height of the hill is 90 meters. His gun has a muzzle velocity of 100 m/s. Minimum how many
meters above the deer should he aim his rifle in order to hit it? [g= 10m/s Shot on realme
Answer: the hunter should aim his rifle 3,422 meters above the deer to hit it.
Explanation: We can solve this problem using projectile motion equations. Let's first identify the known variables:
Distance to the deer along the line of sight (horizontal distance): d = 10,181 m
Height of the hill: h = 90 m
Muzzle velocity of the gun: v0 = 100 m/s
Acceleration due to gravity: g = 10 m/s^2
We want to find the vertical distance (height) between the hunter's location and the deer, which we can call y. We can use the following equation for the vertical motion of a projectile:
y = v0tsin(theta) - (1/2)gt^2
where t is the time it takes for the bullet to reach the deer, and theta is the angle between the line of sight and the horizontal (the angle at which the rifle is aimed).
To find t, we can use the fact that the time of flight of a projectile is given by:
T = 2v0sin(theta)/g
We can solve for sine(theta) using the fact that the horizontal distance is related to the time of flight by:
d = v0*cos(theta)*T
Combining these equations, we get:
sin(theta) = d/(2Tv0)
cos(theta) = sqrt(1 - sin^2(theta))
t = T/2
Substituting these values back into the equation for y, we get:
y = (d*t/tan(theta)) - (1/2)gt^2
Now we just need to plug in the numbers and solve for y:
sin(theta) = 90/10,181
theta = arcsin(sin(theta)) = 0.523 degrees
cos(theta) = cos(0.523) = 0.999
T = 2100sin(theta)/g = 3.189 seconds
t = T/2 = 1.595 seconds
y = (10,181*t/tan(theta)) - (1/2)gt^2 = 3,422 meters
Therefore, the hunter should aim his rifle 3,422 meters above the deer to hit it. Note that this assumes no air resistance and that the rifle is perfectly aimed. In reality, the bullet would be affected by air resistance and the trajectory would depend on the accuracy of the rifle and the shooter's skill.
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Answer:
"Velocity always perpendicular to position vector" means that the distance from the particle of interest to the origin never changes. The question is whether such motion always traces out a circle. Counterexample: consider a plane pendulum with its pivot at the origin.
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