Answer
Higher Temperatures
If the skater starts at a height of 2m on one side of the ramp and starts to move how high with he get on the the other side.
We are given that a skater starts at a height of 2 meters. If we do a balance of energy and assume that there is no friction or any other nonconservative forces we get:
\(\text{mgh}_0=mgh_f\)Where:
\(\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ h_0,h_f=\text{ initial and final height} \end{gathered}\)We can cancel out the mass and the acceleration of gravity:
\(h_0=h_f\)Substituting the initial height we get:
\(2m=h_f\)Therefore, on the other side, he will get to 2 meters in height.
What happens to pressure when the area of the surface increases ? *
Pressure will decrease whenever the surface area increases, and when the weight of the object is reduced.
\( \color{green} {\huge \circ \degree \degree} \boxed{\normalsize{ \mathrm{ \underline{ \color{red}pressure \: \: will \: \: decrease}}} } \: \: \huge \color{green}\degree \degree \circ\)
Explanation :We know that,
\(\large \boxed{ \mathrm{pressure = \frac{mass}{area \: \: of \: \: surface}} }\)
Now, we can observe that the area of surface is inversely proportional to the pressure, Therefore pressure will change opposite to the change in surface area in contact.
So, if we increase the surface area then there would be decrease in magnitude of pressure.
\( \large { \mathfrak{hope \: \:i t \: \: helps \: \: you..... }}\)
A circuit has an operating voltage of 220 volts. The circuit resistance is 55 ohms which limits the current to 4 amperes. You wish to add enough resistance to limit the current to 2 amperes. How much total resistance would you need in this circuit
Total, 110 ohms resistance you would need to the circuit in order to limit the current to 2 amperes.
To limit the current in the circuit to 2 amperes, we can use Ohm's Law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R);
I = V / R
Given;
Operating voltage (V) = 220 volts
Circuit resistance (R) = 55 ohms
Desired current (I_desired) = 2 amperes
We wil rearrange Ohm's Law to solve for the resistance required to achieve the desired current;
R_required = V / I_desired
Substituting the given values, we have;
R_required = 220 V / 2 A
Calculating the division, we find;
R_required = 110 ohms
Therefore, you would need to add an additional resistance of 110 ohms to the circuit in order to limit the current to 2 amperes.
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A spring is laid sideways on an air hockey table. It has a spring constant of 26.0 N/m. If a 2.45 kg air-hockey puck traveling at 1.50 m/s bounces into the spring, how much will the spring
compress before the puck is brought to rest?
(Hint: you will need to calculate how much WORK is done to slow the puck. Consult your notes and remember that work is a change in kinetic energy: KE)
__cm?
Answer: 46.0455 cm
Explanation:
The kinetic energy of the puck is 2.75625 Joules.
This energy is used to compress the spring and bring the puck to rest. The work done on the puck by the spring is equal to the change in kinetic energy of the puck, which is the kinetic energy it initially had.
The work done on the puck by the spring can also be expressed as the potential energy stored in the spring at the point of maximum compression, which is given by the formula \(\( \frac{1}{2} k x^2 \)\), where \(\( k \)\) is the spring constant and \(\( x \)\) is the distance the spring is compressed.
Setting these two expressions for the work done equal to each other gives:
\(\( \frac{1}{2} k x^2 = 2.75625 J \)\)
We can solve this equation for \( x \), the distance the spring is compressed.
The spring will compress approximately 0.460455 meters, or 46.0455 cm, before the puck is brought to rest.
An average male weighs approximately 84 kg. If the man is standing on one leg, what normal force is being produced by the ground upwards on the leg.
Assuming that the man is standing still on a flat, horizontal surface and neglecting air resistance, the normal force produced by the ground upwards on the leg would be equal in magnitude to the weight of the man, which is given as approximately 84 kg.
Therefore, the normal force being produced by the ground upwards on the leg would be approximately 84 kg multiplied by the acceleration due to gravity (9.81 m/s^2), which gives a value of approximately 823.44 N (Newtons).
So the normal force being produced by the ground upwards on the leg is approximately 823.44 N.
Between mercury, venus, earth and mars which has the smallest orbit
Answer:
Mercury has the shortest orbit
Explanation:
Its right
Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minute for the next 350 meters, and 3 minutes for the rest.
Cindy’s average speed for the entire run is
meters per minute. One kilometer is the same as 1,000 meters.
Answer:
200 m / min
Explanation:
Total distance = 2000 m
Total time = 2+4+1+3 = 10 minutes
Average speed = 2000 m / 10 min = 200 m/min
How do mountains affect the climate of a region?
Consider the system shown in the figure. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the 8.00-kg block and the tabletop is m_k=.25 . The blocks are released from rest.Use energy methods to calculate the speed of the 6.00-kg block after it has descended 1.50 m. How do i calculate work on the 8kg block.
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m. In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
Energy Method Block SpeedTo calculate the speed of the 6.00-kg block after it has descended 1.50 m, you can use the conservation of mechanical energy. The initial mechanical energy of the system is the potential energy of the 6.00-kg block (mgh) and the potential energy of the 8.00-kg block (mgh). As the blocks move, some of this energy is converted into kinetic energy, and some is lost to friction. The equation for the conservation of mechanical energy is:
E_initial = E_final + W_friction
Where E_initial is the initial mechanical energy of the system, E_final is the final mechanical energy of the system, and W_friction is the work done by friction.
The final mechanical energy of the system is the kinetic energy of the 6.00-kg block (1/2 mv²) and the potential energy of the 8.00-kg block (mgh).
To calculate the work done by friction, you can use the equation:
W_friction = force x distance x cos(theta)
Where force is the force of friction, distance is the distance over which the force of friction acts, and theta is the angle between the force of friction and the displacement. The force of friction is the coefficient of kinetic friction times the normal force.
In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
W_friction = m_kF_nd
Where m_k = 0.25 is the coefficient of kinetic friction, F_n = 8*9.8 N is the normal force, and d = 1.5m is the distance that the 8kg block moves.
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m.
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how high on a hill must an engineless resistance free car start for its speed at the bottom to be 50m/sec
The car must start at a height of approximately 127.55 meters on the hill in order to achieve a speed of 50 m/s at the bottom, assuming it is engineless and resistance-free.
To determine the height on a hill at which an engineless, resistance-free car must start in order to achieve a speed of 50 m/s at the bottom, we can use the principle of conservation of mechanical energy.
According to this principle, the sum of the potential energy and the kinetic energy of an object remains constant in the absence of external forces.
At the top of the hill:
The car has only potential energy (PE) due to its height above the bottom.
At the bottom of the hill:
The car has both potential energy and kinetic energy (KE).
Since the car is engineless and resistance-free, we can neglect any energy losses due to friction or air resistance.
The total mechanical energy (E) at the top of the hill is equal to the total mechanical energy at the bottom of the hill:
Etop = Ebottom
The potential energy (PE) at the top of the hill is given by the formula:
PE = m * g * h
Where m is the mass of the car, g is the acceleration due to gravity, and h is the height of the hill.
The kinetic energy (KE) at the bottom of the hill is given by the formula: KE = (1/2) * m * \(v^{2}\),
Where v is the speed of the car at the bottom.
Therefore, we have:
PEtop = KEbottom
m * g * h = (1/2) * m * \(v^{2}\)
We can cancel out the mass (m) from both sides of the equation:
g * h = (1/2) * \(v^{2}\)
Now, we can solve for the height (h):
h = (1/2) * \(v^{2}\) / g
Substituting the given values:
v = 50 m/s (speed at the bottom)
g = 9.8 m/\(s^{2}\) (acceleration due to gravity)
h = (1/2) * \((50 m/s)^2\) / (9.8 m/\(s^{2}\))
h = 127.55 m
Therefore, the car must start at a height of approximately 127.55 meters on the hill in order to achieve a speed of 50 m/s at the bottom, assuming it is engineless and resistance-free.
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You wish to date a hip bone fragment you found at a cave site.
You find a ratio of 1 14C atoms for every 31 14N atoms. How many
half- lives have elapsed?
To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.
The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.
In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.
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I really dont know physics
Answer:
3
Explanation:
I had this question before
14N = 3.5 kg × 4 m/sec²
What process would I need to get answer 14N?
The process that would be needed to get 14N as answer is exertion of force.
What is force?Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body.
Force is an influence that causes the motion of an object with mass to change its velocity, i.e. to accelerate. It can be calculated by multiplying the mass of the object by its acceleration.
Force can be a push or a pull, always with magnitude and direction, making it a vector quantity.
According to this question, the following expression was given: 14N = 3.5 kg × 4 m/sec². In this expression,
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If the bases in Major League Baseball are 90 feet apart, approximately how far would a throw from home plate to second base be?
The bases in Major League Baseball are 90 feet apart. A throw from home plate to second base would be approximately 127.2792206 feet.
How far is a throw from home plate to second base in Major League Baseball?The bases in Major League Baseball are 90 feet apart. A throw from home plate to second base would be approximately 127.2792206 feet.
This can be found using the Pythagorean theorem: a² + b² = c², where c is the hypotenuse (the distance from home plate to second base), and a and b are the two legs (the distance from home plate to the pitcher's mound and the distance from the pitcher's mound to second base).
Therefore, the ] answer to the question is that a throw from home plate to second base in Major League Baseball would be approximately 127.2792206 feet.
this distance is equivalent to 38.86 meters or 42.49 yards. Furthermore, knowing the distance is crucial in making strategic decisions in the game of baseball such as whether to make a throw from home plate to second base or not depending on the likelihood of the runner getting there.
In conclusion, a throw from home plate to second base in Major League Baseball would be approximately 127.2792206 feet or 38.86 meters or 42.49 yards.
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4. Create two more paths on the Gizmo like the one you created in question #2 above. List the energy conversions that happen along each path. Record your work in the tables below. Energy Path Energy conversion
Energy Path Energy conversion
Sun- Nuclear energy is converted to light and thermal energy.Sun- Air Radiant energy is converted to thermal energy.Air- Kinetic energy is converted to mechanical energy.Wind Turbines- Toaster Mechanical energy is converted to electrical energy.Toaster- Electrical energy is converted to thermal energy.Finally, the energy conversion begins with the Sun's nuclear energy, which is converted into radiant and thermal energy to heat the air. Wind turbines then convert the mechanical energy of the moving air into electrical energy, which is then transferred through the toaster. The bread is finally heated by converting electrical energy into thermal energy.
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Your question is incomplete, most probably the complete question is:
Create path: Create an energy path in the Gizmo, starting at the Sun. For each step of the path, describe the energy conversion that takes place. The first one is done for you. Discuss your answers with your classmates and teacher.
Energy Path Energy conversion
Sun Nuclear energy is converted to light and thermal energy.
Air Sunlight warms up the surface which warms up the air
Wind Wind turns the blades which creates electricity
Turbines Electricity flows through the toast
Toaster
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sis i love the eren season 1-2-3-4 but the eren season 5?....... i just :')
Answer:
Explanation:
Aaron yogurt supremacy
The force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires. If a force of 0.750 N exists between wires that are 1.75 cm apart, what is the force between them if they are separated by 2.50 cm?
the force between the two wires if they are separated by 2.50 cm is 0.525 N.
Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.
Let the initial force be F₁ and the initial distance be d₁.
Therefore, we can write the relationship between force and distance as;
F₁d₁ = F₂d₂
Where
;F₁ = 0.750 N (initial force)
d₁ = 1.75 cm (initial distance)
F₂ = ? (force at new distance)
d₂ = 2.50 cm (new distance)
Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂
Now substitute the values we know;
F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N
Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.
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Which equation is the slope-intercept form of this equation? y+8=4(x−3) 4x−y=−20 y+8=4x−12 y=4x−20 x=14y+5
Answer:
y=4x−20
Explanation:
The given equation is :
y+8=4(x−3)
Using distributive property at RHS.
y+8=4x−12
Taking variables to the one side and constant terms to another side.
y-4x = -12-8
y-4x=-20
or
y = 4x-20
Hence, the correct option is (c).
True or False: The further you get from the Sun, the solar
constant (S) gets larger.
The solar constant (S) does not get larger as you get further from the Sun. It actually gets smaller due to the decrease in solar radiation received per unit area with increasing distance from the Sun.
False. The further you get from the Sun, the solar constant (S) actually gets smaller, not larger.
The solar constant is a measure of the amount of solar radiation received per unit area at a distance of one astronomical unit (AU) from the Sun. It represents the average power per unit area received from the Sun at Earth's orbit. Since the solar constant is defined at a fixed distance from the Sun, it does not change as one moves away from it.
According to the inverse square law, the intensity of radiation decreases with increasing distance from the source. This means that as you move further from the Sun, the same amount of solar energy is spread over a larger area, resulting in a decrease in the solar radiation received per unit area.
Therefore, the solar constant is highest at a distance of one AU from the Sun, which is approximately the average distance between the Earth and the Sun. As you move closer to the Sun, the intensity of solar radiation increases, but as you move farther away, it decreases.
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What would be the weight of a 59.1-kg astronaut on a planet twice as massive as Earth and having twice Earth's radius
Answer:
29.55 kg
Explanation:
force gravity = G m1 m2 / (r^2) now change the mass 1 and the r
= G 2m1 m2 / ( 2r)^2
= 2/4 G m1 m2 / (r^2)
the weight will be 2/4 or 1/2 the original
what do you understand by domestic wiring or what are household electric circuits ??
please answer quick !!!
Explanation:
Domestic wiring is house wiring were phase/live wire,neutral wire,earth wire is used that functions in giving the electricity to our home except in case of neutral wire
name and describe the process that fuels the sun
Answer:
The Sun derives all its energy from a fusion cycle. In that process, tiny hydrogen molecules combine into a continuous proton-proton chain to create larger helium nuclei. The above figure illustrates the fusion of hydrogen into helium.
Explanation:
Hope this helps.
Answer:
nuclear fusion
Explanation:
In this process, small hydrogen molecules fuse together to form bigger helium nuclei in a continuous proton-proton chain.
A car travels at a constant speed around a circular track whose radius is 3.1 km. The car goes once around the track in 380 s. What is the magnitude of the centripetal acceleration of the car
To find the magnitude of the centripetal acceleration of the car, we use the formula for centripetal acceleration as: ac = v²/r
We know that the car travels at a constant speed around a circular track whose radius is 3.1 km. The car goes once around the track in 380 s. The formula for centripetal acceleration as:ac = v²/rWhere,ac is the centripetal accelerationv is the velocity of the objectr is the radius of the circular track. Given that the radius of the circular track is 3.1 km and the car goes once around the track in 380 s. To find the velocity of the car we use the formula:v = 2πr/tWhere,t is the time taken to go once around the track, Therefore,v = 2 × 3.14 × 3.1/380v = 0.51 km/sPutting the values of v and r in the formula of centripetal acceleration, we get:ac = (0.51 km/s)²/(3.1 km)ac = 0.083 km/s²Therefore, the magnitude of the centripetal acceleration of the car is 0.083 km/s².
The given problem can be solved by using the formula for centripetal acceleration, which is given as:ac = v²/rWhere,ac is the centripetal accelerationv is the velocity of the objectr is the radius of the circular trackIt is given that the car travels at a constant speed around a circular track whose radius is 3.1 km. The car goes once around the track in 380 s. We need to find the magnitude of the centripetal acceleration of the car.To find the velocity of the car, we use the formula:v = 2πr/tWhere,t is the time taken to go once around the trackThe radius of the circular track is 3.1 km and the car goes once around the track in 380 s. Therefore,v = 2 × 3.14 × 3.1/380v = 0.51 km/sPutting the values of v and r in the formula of centripetal acceleration, we get:ac = (0.51 km/s)²/(3.1 km)ac = 0.083 km/s²Therefore, the magnitude of the centripetal acceleration of the car is 0.083 km/s².
In conclusion, the magnitude of the centripetal acceleration of the car is 0.083 km/s², given that the car travels at a constant speed around a circular track whose radius is 3.1 km, and the car goes once around the track in 380 s.
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A 0. 5 kg drone traveling 15 m/s crashes into a tree. What is the momentum of the drone before and after the crash?.
The momentum of the drone before and after the crash is 7.5 Kg.m/s and zero respectively.
What is momentum?In Newtonian mechanics, momentum can be described as the product of the mass and velocity of an object. Momentum is a vector parameter, possessing a magnitude and a direction. If m is an object's mass and v is its velocity then the object's momentum will be given by : p = mv
In the International System of Units of measurement of momentum is the kilogram meter per second (kg⋅m/s) or newton-second.
Given, the mass of the drone, m= 0.5 Kg
The velocity of the drone before the crash, u = 15 m/s
The momentum of drone before the crash, p = mu = 0.5 × 15 = 7.5 Kg.m/s
The velocity of the drone after the crash with the tree, v = 0 m/s
The momentum of the drone after the crash = 0
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How would you finish the explanation to sherman? why do colliding objects of unequal mass experience different effects?.
In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.
Collision between two objects naturally fall under Newton's third law of motion. When two objects collide, forces of equal magnitude and opposite direction are applied to each object. Such pressures frequently result in one thing gaining momentum and gaining speed while the other object slows down (lose momentum).
Newton's third law states that the forces acting on the two objects are of equal and opposite strength. The objects' accelerations may not be equal in magnitude even though the forces acting on them are opposite in direction and of equal magnitude. According to Newton's second law of motion, an object's acceleration depends on both its mass and force. Therefore, if the objects colliding have different masses, their velocities will differ as a result.
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A disk rotates with constant angular acceleration of 5. 45~\text{rad/s}^25. 45 rad/s 2. starting from rest, it turns through 220 rad. how much time elapses while it turns through the 220 radians?
The time elapsed is 8.98 sec when it turns through the 220 radians.
given:
initial angular velocity (ω°) = 0 rad/secangular acceleration (α) =5.45 \(rad/sec^{2}\)total angular displacement (Ф) = 220 radusing second equation of motion for rotation
we get ,
\(220=0.t + \frac{1}{2}.5.45.t^{2}\)
t^2 =80.98
t=8.98sec
therefore time elapsed is 8.98sec .
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6. When the net force that acts on a hockey puck is 12 N, the puck accelerates at a rate of 48 m/s2. Determine the mass of the puck.A) 0.25 kgB) 1.0 kgC) 5.0 kgD) 2.5 kgE) 2.0 kg
The equation F=ma, where F is the net force, m is the mass, and an is the acceleration, can be used. . Rearranging the formula to solve for mass, we get m=F/a. Substituting the given values, we get m=12 N/48 m/s^2 = 0.25 kg. Therefore, the answer is A) 0.25 kg.
To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force (F) is 12 N, and the acceleration (a) is 48 m/s². You are asked to determine the mass (m) of the hockey puck.
Using the equation F = ma, you can rearrange it to find the mass: m = F/a
Plug in the given values: m = 12 N / 48 m/s²
Calculate the mass: m = 0.25 kg
The mass of the hockey puck is 0.25 kg, which corresponds to option A.
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Newton's _______ law of motion states that "For every action there is an equal and opposite reaction." A. second B. fourth C. first D. third
Answer:
first
Explanation:
Newton's Newton's first law of motion states that for every action and there's an equal and opposite reaction
Answer:
D. Third
Explanation:
expert answer 1 month ago a) determine the distance of the spectrum. write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the first order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the first order. determine the angular separation of both closely spaced yellow lines of sodium of the first order. -- b) write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the second order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the second order. determine the angular separation of both closely spaced yellow lines of sodium of the second order. -- c) write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the third order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the third order. determine the angular separation of both closely spaced yellow lines of sodium of the third order. like 0 the
Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.
What is angle?Angle is the measure of a turn or displacement between two intersecting lines. Angles are typically measured in degrees, with 360 degrees in a full circle. acute angles are smaller than 90 degrees, while obtuse angles are larger than 90 degrees. Straight angles are exactly 180 degrees, while reflex angles are greater than 180 degrees.
The equation for the diffraction grating for the sodium is:
nλ = d sinθ
Where n is the order of the spectrum, λ is the wavelength of the light, d is the distance of the spectrum, and θ is the angle of the light.
For the first order, the initial angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
For the first order, the final angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
The angular separation of the two closely spaced yellow lines of sodium is:
Δθ = θ 1 - θ 2
Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.
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PLEASE HELP ME I FONT HAVE THAT MUCH TIME LEFT!!! THE ALL CAPS ARE TO CATCH YOUR ATTENTION SO NOW THAT I’VE GOT IT, PLEASE HELP ME!!!