how many grams of strontium chloride will be needed to make 250 ml of a 0.100 srcl2 aqueous csolution? the formula mass of srcl2 is 158.52 g/mol

Ep = mgh. energy associated with gravity. Ep = mgh. The labor required to lift an object is equal to the gravitational potential energy it contains.

Potential energy is simply stored energy that has the capacity to perform work as a result of the location or state of the object in question. Potential energy is described as the energy held within a system of physically interfering entities in more physics-focused terminology.

Because of where you choose to establish your zero point—the location at which your potential energy is zero—potential energy may also be negative. A book on a table has more potential energy than the floor, which is the potential energy zero.

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The null hypothesis (H0) states that the average time it takes smokers to quit smoking is greater than or equal to 16 years, while the alternative hypothesis (Ha) suggests that the average time is less than 16 years.

In the given scenario, the null and alternative hypotheses are as follows:

a) H0: 16 (The average time it takes smokers to quit smoking is greater than or equal to 16 years)

b) Ha: 16 (The average time it takes smokers to quit smoking is less than 16 years)

c) This is a left-tailed test because the alternative hypothesis (Ha) suggests a decrease in the average time to quit smoking.

d) To find the p-value, we need to conduct a statistical test. The test statistic (t-value) can be calculated using the sample mean, population standard deviation, sample size, and the hypothesized population mean (16 years). Using the t-distribution and degrees of freedom (n-1 = 24), the p-value can be determined.

e) Based on the p-value obtained from the test, we compare it to the significance level (α = 0.05). If the p-value is less than α, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.

f) In the conclusion, we state whether there is sufficient evidence to reject the claim. If the p-value is less than the significance level (α = 0.01), we can conclude that there is sufficient evidence to reject the claim. However, if the p-value is greater than α, we fail to reject the claim.

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The structure of the one of the products which is formed when the ether is treated with the HBr is (CH₃)₂CHBr.

When the ether (CH₃)₂CH-O-CH₂CH₃ is reacted with the hydrobromic acid tht is HBr, then the ether will undergoes the acid-catalyzed cleavage and from which they form the two different products.

The chemical reaction is as :

(CH₃)₂CH-O-CH₂CH₃  +  HBr --->   (CH₃)₂CHBr  +  (CH₃CH₂OH)

The One of the major products that is formed is the (CH₃)₂CHBr, that is the tertiary alkyl bromide. The second product that is formed is the ethanol (CH₃CH₂OH), and this is the byproduct of the reaction.

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This question is incomplete, the complete question is :

draw the structure of one of the products formed when the following ether is treated with hbr.

(CH₃)₂CH-O-CH₂CH₃

The number of atoms in 16.25 g of Al is calculated here. One mole or 26.98 g of Al contains 6.022 × 10²³ atoms. Thus, the atoms in 16.25 g or 0.60 mol of Al contains 3.62 × 10²³ atoms.

Any substance containing 6.022 × 10²³ atoms is called one mole of that substance. This number is called Avogadro number. Therefore, one mole of every substances contains Avogadro number of atoms. The mass of one mole of an atom is called its atomic mass.

Al is 13th element in periodic table. Its atomic mass is 26.98 g/mol. Thus, the  number of moles of 16.25 g of Al is calculated as follows:

no.of moles = given mass/atomic mass

                    = 16.25/26.98 =0.60 moles.

1 mole of Al contains 6.022 × 10²³ atoms. Thus, 0.60 moles contains 6.022 × 10²³ × 0.60 =  3.62 × 10²³ atoms.

Therefore, to calculate the number of atoms in a given number of moles of an element multiply the number of moles with Avogadro's number.

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Answer:

Even though the two substances possess many similarities, they have some unique properties. In turn, since they have the same properties, if they were the same substance, it would make matters worse, if the same chemical was in two different places, there would not be a difference between them since they are the same, just as it is with are two different chemicals would have differing properties since they are two properties would vary from one another since they are 2 totally different things!

Explanation:

Considering the definition of ideal gas law,  a pressure of 1.5 atm is required to achieve a CO₂ concentration of 0.0620 mol L⁻¹ at 20°C.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P×V = n×R×T

So the pressure is calculated as:

\(P=\frac{n}{V}xRxT\)

In this case, you know:

Replacing:

P=0.0620 \(\frac{mol}{L}\)× 0.082 \(\frac{atmL}{molK}\)× 293 K

Solving:

P= 1.489612 atm≅ 1.5 atm

Finally, a pressure of 1.5 atm is required to achieve a CO₂ concentration of 0.0620 mol L⁻¹ at 20°C.

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Answer:

5,596.8

Explanation:

159×2.2= 349.8×16= 5,596.8

Answer:

117 grams H₂O

Explanation:

To find the amount, you need to (1) convert from moles HNO₃ to moles H₂O (via mole-to-mole ratio from equation) and then (2) convert from moles H₂O to grams (via molar mass from periodic table). The final answer should have 3 sig figs according the the given value (19.5).

S + 6 HNO₃ --> H₂SO₄ + 6 NO₂ + 2 H₂O

Molar Mass (H₂O): 15.999 g/mol + 2(1.008 g/mol)
Molar Mass (H₂O): 18.015 g/mol

19.5 moles HNO₃         2 moles H₂O          18.015 grams
--------------------------  x  ----------------------  x  ----------------------  = 117 grams H₂O
                                    6 moles HNO₃           1 mole H₂O

Answer:

When a strong base reacts with a strong acid, a neutral salt is formed. When a strong base reacts with a weak acid, a basic salt is formed. When a strong acid reacts with a weak base, an acidic salt is formed.

Explanation:

Answer:

The method involves students exhaling air using a plastic straw into the over-titrated acid-base mixture, which turned pink-colored with phenolphthalein indicator.

At pKa1, the proportion of hooc-gly- nh /–ooc-gly- nh is 1:1, and the concentration of each form is equal.

The proportion of the HOOC-Gly-NH₂ and OOC-Gly-NH₂ molecules at pKa1 can be determined using the Henderson-Hasselbalch equation, which is used to calculate the pH of a buffer solution. In this context, pKa1 refers to the first ionization constant for the carboxylic acid group (COOH) in glycine, an amino acid.

The Henderson-Hasselbalch equation is given as follows:

pH = pKa + log10([A-]/[HA])

In this case, the terms [A-] and [HA] refer to the concentrations of the ionized (OOC-Gly-NH₂) and non-ionized (HOOC-Gly-NH₂) forms of glycine, respectively. The pKa1 value for glycine is approximately 2.34.

To find the proportion of HOOC-Gly-NH₂ and OOC-Gly-NH₂ at pKa1, you would set pH equal to the pKa1 value (2.34) and rearrange the equation to solve for the ratio [A-]/[HA]:

2.34 = 2.34 + log10([A-]/[HA])
0 = log10([A-]/[HA])

Taking the antilog (base 10) of both sides:

10^0 = [A-]/[HA]
1 = [A-]/[HA]

This result indicates that at pKa1 (2.34), the proportion of ionized (OOC-Gly-NH₂) to non-ionized (HOOC-Gly-NH₂) glycine molecules is 1:1. In other words, there are equal amounts of both forms present in the solution.

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The stronger intermolecular hydrogen bonding in HF leads to higher intermolecular forces and a higher boiling point compared to HCl.

The difference in the normal boiling points of hydrogen fluoride (HF) and hydrogen chloride (HCl) can be attributed to the differences in their intermolecular forces.

Hydrogen fluoride (HF) has a much higher normal boiling point compared to hydrogen chloride (HCl) due to the presence of stronger intermolecular hydrogen bonding.

In HF, the hydrogen atom is covalently bonded to fluorine, which is a highly electronegative atom.

This leads to a significant polarity in the HF molecule, with the hydrogen atom carrying a partial positive charge (δ+) and the fluorine atom carrying a partial negative charge (δ-).

The presence of these polarized bonds in HF allows for strong hydrogen bonding interactions between neighboring HF molecules.

The hydrogen atom in one HF molecule can form a hydrogen bond with the lone pair of electrons on the fluorine atom of another HF molecule.

These hydrogen bonds are stronger than the intermolecular forces present in HCl.

In hydrogen chloride (HCl), the electronegativity difference between hydrogen and chlorine is not as significant as in HF.

Therefore, the dipole-dipole interactions in HCl are weaker compared to the hydrogen bonding interactions in HF.

As a result, HCl has a lower boiling point compared to HF.

Overall, the stronger intermolecular hydrogen bonding in HF leads to higher intermolecular forces and a higher boiling point compared to HCl.

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The description of the molecular polarity and the intermolecular forces present in ammonium lauryl sulfate should be explained below.

The common name of it should be likely ammonium lauryl sulfate (ALS)  and its molecular formula should be  (CH3(CH2)10CH2OSO3NH4).

Also, one intermolecular formula that should be presented in the molecule should be considered as the electrostatic forces of attraction that lies between the non-polar chain and the polar ending group.

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the space occupied by quantity of matter

Answer:

1.47 × 10^(23) molecules

Explanation:

Answer:

1,250 °C

Explanation:

To find the new temperature, you need to use a variation of the Combined Gas Law. The equation looks like this:

P₁V₁ / T₁ = P₂V₂ / T₂

In this formula, "P₁", "V₁" and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. You can find the new temperature by plugging the given values into the equation and simplifying.

P₁ = 3.00 atm                      P₂ = 1.00 atm

V₁ = 10.0 L                           V₂ = 125 L

T₁ = 300 °C                          T₂ = ? °C

P₁V₁ / T₁ = P₂V₂ / T₂                                               <----- Combined Law equation

(3.00 atm)(10.0 L) / (300 °C) = (1.00 atm)(125 L) / T₂         <----- Insert values

0.1 = (1.00 atm)(125 L) / T₂                                    <----- Simplify left side

0.1 = 125 / T₂                                                         <----- Multiply 1.00 and 125

0.1 x T₂ = 125                                                        <----- Multiply both sides by T₂

T₂ = 1,250                                                             <----- Divide both sides by 0.1

E°ox of the anode half-cell is 1.051 V.

To determine the E°ox of the anode half-cell, we need to use the following equation: E°cell = E°cathode - E°anode. We are given E°cell (1.587 V) and E°red of the cathode half-cell (0.536 V). We can rearrange the equation to solve for E°ox of the anode half-cell: E°anode = E°cathode - E°cell.

Plugging the values into the equation, we get: E°anode = 0.536 V - 1.587 V = -1.051 V. However, since E°ox is the oxidation potential and we are given the reduction potential, we need to reverse the sign to obtain the oxidation potential. Thus, E°ox of the anode half-cell is 1.051 V.

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(a) 54.5 dm³ CH₄ contains approximately 2.28 moles.

(b) 250.0 cm³ CO contains approximately 0.0121 moles.

(c) 1.0 m³ O₂ contains approximately 43.56 moles.

To determine the number of moles present in each of the given substances at STP (Standard Temperature and Pressure), we need to use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

At STP, the conditions are defined as a temperature of 273.15 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (atm). The gas constant (R) is equal to 0.0821 L·atm/(mol·K).

(a) 54.5 dm³ CH₄:

To convert dm³ to liters, we multiply by 1 (since 1 dm³ = 1 liter). Therefore, the volume is 54.5 liters.

Using the ideal gas law, we have:

PV = nRT

(1 atm) (54.5 L) = n (0.0821 L·atm/(mol·K)) (273.15 K)

n = (1 atm * 54.5 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n ≈ 2.28 moles

(b) 250.0 cm³ CO:

To convert cm³ to liters, we divide by 1000. Therefore, the volume is 0.250 liters.

Using the ideal gas law:

PV = nRT

(1 atm) (0.250 L) = n (0.0821 L·atm/(mol·K)) (273.15 K)

n = (1 atm * 0.250 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n ≈ 0.0121 moles

(c) 1.0 m³ O₂:

To convert m³ to liters, we multiply by 1000. Therefore, the volume is 1000 liters.

Using the ideal gas law:

PV = nRT

(1 atm) (1000 L) = n (0.0821 L·atm/(mol·K)) (273.15 K)

n = (1 atm * 1000 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n ≈ 43.56 moles

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Answer: C

Here is how I used Process of Elimination:

An hypothesis is your guess before you conduct the experiment.

An inquiry is when you ask for information.

A law is a statement based on repeated experiments.

The answer had to be conclusion.

Hope it helps!

Answer:

It would be a physical change, because the atoms are rerranging to form new molecules!

Explanation:

The fact of expanding of water as much as 9% of its volume as it freezes is the basis of frost wedging.

Water starts to contract as expected after it is cooled to a temperature of roughly 4 degrees Celsius. Once it hits the freezing point, it continues to grow gradually until it freezes and expands by around 9%.

When water fills a fissure, it freezes, expands (8–11% more volume than liquid water), and this process results in frost wedging. An enormous amount of pressure (up to 30,000 pounds per square inch) is applied to the rock by the growing ice, which causes the crack to widen.

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Answer: The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

Explanation:

We are given:

Average number of drops of sodium bicarbonate = 142

The chemical equation for the reaction of sodium bicarbonate and acetic acid in vinegar follows:

\(NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2CO_3\)

From the stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.

Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

To determine the vapor pressure of the substance at 29°C, we can use the Clausius-Clapeyron equation, which relates the vapor pressure (P) of a substance at a given temperature (T) to its normal boiling point (T_boiling), and the enthalpy of vaporization (ΔH_vap):

ln(P/P_boiling) = -ΔH_vap/R * (1/T - 1/T_boiling)

Where P_boiling is the vapor pressure at the boiling point, and R is the ideal gas constant (8.314 J/(mol·K)).

First, we need to convert the given temperatures to Kelvin:

T = 29°C + 273.15 = 302.15 K

T_boiling = 76°C + 273.15 = 349.15 K

Substituting the values into the equation:

ln(P/P_boiling) = -38.7 kJ/mol / (8.314 J/(mol·K)) * (1/302.15 K - 1/349.15 K)

Simplifying the equation further, we can solve for ln(P/P_boiling):

ln(P/P_boiling) = -4.6616 * (0.003312 - 0.002862)

ln(P/P_boiling) = -4.6616 * 0.00045

ln(P/P_boiling) = -0.002097

To find P/P_boiling, we take the exponential of both sides:

P/P_boiling = e^(-0.002097)

Finally, we can solve for P (vapor pressure) by multiplying P_boiling to both sides of the equation:

P = P_boiling * e^(-0.002097)

Explanation:

The Clausius-Clapeyron equation is a useful tool for calculating the vapor pressure of a substance at a temperature different from its boiling point. It is based on the relationship between temperature, vapor pressure, and enthalpy of vaporization. By using the equation, we can determine the vapor pressure at a given temperature using known values.

In this case, we are given the normal boiling point of the substance (76°C) and its enthalpy of vaporization (38.7 kJ/mol). The boiling point represents the temperature at which the vapor pressure is equal to the atmospheric pressure. By plugging the values into the Clausius-Clapeyron equation and solving for the vapor pressure (P), we can obtain the desired result.

It is important to note that the equation assumes ideal gas behavior and relies on the assumption that the enthalpy of vaporization remains constant over the temperature range. Additionally, the ideal gas constant (R) is used to convert the units of enthalpy from kJ/mol to J/(mol·K).

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Answer:What is happening to voltage-gated channels at this point in the action potential? Na+ channels are inactivating, and K+ channels are opening. Na+ channels are inactivating, and K+ channels are closing.

The mass of water needed to absorb 456 J is 1.44 g

We'll begin by calculating the change in the temperature of the water.

Initial temperature of water (T₁) = 22.7 °C

Final temperature (T₂) = 98.3 °C

ΔT = T₂ – T₁

ΔT = 98.3 – 22.7

Heat absorbed (Q) = 456 J

Change in temperature (ΔT) = 75.6 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

456 = M × 4.184 × 75.6

456 = M × 316.3104

Divide both side by 316.3104

M = 456 / 316.3104

Therefore, the mass of the water is 1.44 g

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1.00 pint of milk is equal to 473.18 milliliters, based on the conversion factor of 1 pint = 473.18 milliliters.

To convert pints to milliliters, we can use the conversion factor of 1 pint = 473.18 milliliters.

Since we have 1.00 pints of milk, we can multiply it by the conversion factor to find the volume in milliliters:

1.00 pint * 473.18 milliliters/pint = 473.18 milliliters.

Therefore, 1.00 pint of milk is equivalent to 473.18 milliliters. It's important to note that this conversion factor is based on the standard definition of a pint, which is equal to 473.18 milliliters. In some countries, the pint may have a different value, so it's essential to use the appropriate conversion factor based on the specific context or region.

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To determine the concentration of the iron(III) hydroxide solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between sulfuric acid (H₂SO₄) and iron(III) hydroxide (Fe(OH)₃).

The balanced chemical equation for the reaction is as follows:

H₂SO₄ + Fe(OH)₃ → Fe₂(SO₄)₃ + 3H₂O

From the balanced equation, we can see that the stoichiometric ratio between H₂SO₄ and Fe(OH)₃ is 1:1. This means that for every 1 mole of H₂SO₄, we need 1 mole of Fe(OH)₃ to react completely.

Given the volume and concentration of H₂SO₄, we can calculate the number of moles of H₂SO₄ using the formula:

moles of H₂SO₄ = volume (in liters) × concentration

Converting the volume of H₂SO₄ to liters:

25.5 mL = 25.5 / 1000 = 0.0255 L

Calculating the moles of H₂SO₄:

moles of H₂SO₄ = 0.0255 L × 0.25 M = 0.006375 moles

Since the stoichiometric ratio between H₂SO₄ and Fe(OH)₃ is 1:1, we know that 0.006375 moles of H₂SO₄ will react with an equal number of moles of Fe(OH)₃.

Now, let's calculate the concentration of Fe(OH)₃ using the volume of Fe(OH)₃ given in the problem.

Converting the volume of Fe(OH)₃ to liters:

57.9 mL = 57.9 / 1000 = 0.0579 L

Since the number of moles of Fe(OH)₃ is the same as that of H₂SO₄ (0.006375 moles), we can calculate the concentration of Fe(OH)₃ using the formula:

concentration = moles/volume (in liters)

Concentration of Fe(OH)₃ = 0.006375 moles / 0.0579 L ≈ 0.11 M

Therefore, the concentration of the iron(III) hydroxide solution is approximately 0.11 M.

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The overall reaction equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution can be obtained by combining the individual steps of the mechanism. The first step is a rapid equilibrium between hydrogen ions and hydrogen peroxide, which can be represented as: H + H2O2 = 1207-OH. The second step is a slow reaction between hydroxide ions and bromide ions to form hypobromous acid and water: H2O*-OH + Br" → HOBr + H2O. The third step is a fast reaction between hypobromous acid, hydrogen ions, and bromide ions to form bromine and water: HOBr + H+ + Br- → Br2 + H2O.

By combining these three steps, we can write the overall reaction equation as:

2H+ + 2Br- + H2O2 → Br2 + 2H2O

This equation shows that two hydrogen ions, two bromide ions, and one hydrogen peroxide molecule react to form one molecule of bromine and two molecules of water. Therefore, the correct answer is:

2H+ + 2Br + H2O2 → Br2 + 2H2O

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