a hypodermic syringe (see fig. p5.30) is used to apply a vaccine. if the plunger is moved forward at the steady rate of 20 mm/s and if vaccine leaks past the plunger at 0.1 of the volume flowrate out the needle opening, calculate the average velocity of the needle exit flow. the inside diameters of the syringe and the needle are 20 mm and 0.7 mm.

The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.

Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

Δ P = m Δ v          

Δ P = m(vf - vi)

Δ P = 1300 (0 - 11)

Δ P = -1.43 × 10⁴ kg.m/s

The impulse is equal to the change in momentum of the car

I = -1.43 × 10⁴ kg.m/s

Magnitude of the force experienced by Kara

I = F × t

where, I is impulse acting on the car

t is time

- 1.43 × 10⁴ = F × 0.14

F = -1.021 × 10⁵ N

Negative sign represents the direction of the force.

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Your question is incomplete, most probably the complete question is:

Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.

a. Determine the momentum change of Kara's car.

b. Determine the impulse experienced by Kara's car.

c. Determine the magnitude of the force experienced by Kara's car.

5.73 seconds pass before the centripetal acceleration equals the tangential acceleration in strength.

This enables you to calculate the change in velocity in metres per second squared (m/s²). The change in velocity (v) over the change in time (t) is known as acceleration (a). It can be determined using the formula a = v/t.

a = v²/r

where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the circular track (half the diameter).

a = (2.97 m/s²)

r = (195 m)/2 = 97.5 m

v² = ar = (2.97 m/s²)(97.5 m) = 289.58 m²/s²

v = √(289.58 m²/s²) = 17.01 m/s

at = dv/dt

where at is the tangential acceleration, and v is the speed of the car. Since the car is starting from rest, its initial speed is zero, so we can simplify the formula to:

at = v/t

where t is the elapsed time.

We want to find the time at which the magnitude of the tangential acceleration is equal to the magnitude of the centripetal acceleration, so:

at = ac

v/t = ac

t = v/ac = 17.01 m/s / 2.97 m/s² = 5.73 s

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Freezing point of Ethylene glycol  =  - 10.3°C

Boiling point of solution  = 102.8°C

Ethylene glycol excess can harm the kidneys, liver, lungs, brain, and other organs. Chemical imbalances in the body, such as metabolic acidosis, are brought on by the poisoning. The disruptions might be so severe as to result in death, organ failure, and deep shock.

According to reports of fatalities brought on by ethylene glycol intake, a single dose of 150–1,500 mL may be lethal. The fatal dosage of ethylene glycol in humans is thought to be between 1,400 and 1,600 mg/kg.

Colligative qualities are the subject here:

Depression at the freezing point ΔT = Kf . m

T = Freezing temperature of solution minus the freezing point of a pure solvent

T = Kb. m is the boiling point elevation.

T = Pure solvent boiling point minus the boiling point of the solution

Let's calculate m, which stands for the molality of the solute in kilograms of solvent.

Ethylene glycol is the solute. Mass Equals 25 g

0.416 moles are equal to 25 g/60 g/mol, or one mole.

Solvent: Water

25 g of solute are present within 100 g of solution, or 25%.

The volume of water is thus 75 g (100 -25). (Solvent + Solute Equals Solution)

The mass is converted into g to kg 75 g. 1kg /1000g Equals 0.075 kg

Molality (mol/kg) is equal to 0.416 m/0.075 kg, or 5.55 m.

The formulae' data is changed as follows:

Depression of the freezing point: 0 ° 5.55 m. Freezing point of solution: 1.86 °C/m.

1.86°C/m x 5.55m = - 10.3°C for the freezing point of a solution.

raising the boiling point 100°C = 0.51°C/m or 5.55 m is the boiling point of a solution.

Solution's boiling point is 0.51 °C per meter. 5.55 m + 100°C = 102.8°C

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Answer:

A and E

Explanation:

An easy (calculation free) way to think about it is balance. The question states that the system is un-moving and therefore balanced in the picture. To keep it balanced, we want to add equal weights at equal distances on opposite sides of the pivot point. A and E are both 2 holes away from the pivot point.

The actual (physics) explanation for this is using torques. The system is balanced in the picture since the center of mass of the bar is at D and the weight is at B. They are equal distances and weights from the pivot point, and cause torques of equal magnitude in opposite directions from each other, so the net torque is 0. We want to apply the same logic when adding 2 more masses. Torque = r F sinα, where r is the distance from the pivot point and F is the weight (force of gravity). Since F is down in both cases, they will cause torques in the opposite directions. To get a net torque of 0 (balanced), we want the torques to have equal magnitude in opposite directions, so as long as r (the distance from the pivot point) is equal for each mass, the system will remain balanced.

a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

The resultant of the vectors is equivalent to 28.1 meters at an angle of 27.5° with " - x axis ".

Given is that you walk 25m straight west and then 13m straight north.

The resultant of the vectors is equivalent to -

D² = D(x)² + D(y)²

D² = (25 x 25) + (13 x 13)

D² = 794

D = 28.1 meters

tan {Ф} =  D(y) / D(x)

tan {Ф} = 13/25

{Ф} = tan ⁻¹(13/25)

{Ф} = 27.5°

Therefore, the resultant of the vectors is equivalent to 28.1 meters at an angle of 27.5° with " - x axis ".

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The difference between ∆x & ∆y is found say in its position.  ∆x refers to the change in the position of the horizontal direction while ∆y refers to the change in the vertical direction.

The similarity between ∆x & ∆y is that both of them has to express same nature of phenomena.

What is position?

Position is described as a place where someone or something is located or has been put.

x and y has been used in all sciences to denote known and unknown variables.  ∆x & ∆y deals with the changes in those variables either known or unknown.

X is usually in the horizontal position while Y is in the vertical position.

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Answer:

Explanation:

1. Place a cup of hot tea on a flat surface.

2. Place a thermometer in the tea and record the temperature.

3. Place a fan in front of the cup of tea and turn it on.

4. Place the thermometer in the tea again and record the temperature.

5. Compare the two temperatures and observe the difference.

6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.

Answer:

d. the force is reduced by one quarter to 3.6 n

Explanation:

Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.

Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:

1200 m / 8 m per hPa = 150 hPa

Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.

Answer:

THEY WILL REPEL

Explanation:

THEY'LL MOVE IN OPPOSITE DIRECTIONS

The relationship between the temperature of an object and the frequency of electromagnetic waves generated by the object is described by the concept of blackbody radiation.

A blackbody is an idealized object that perfectly absorbs all electromagnetic radiation that falls on it and emits radiation in a continuous spectrum over a range of frequencies.

According to Planck's law, the spectral distribution of blackbody radiation depends on the temperature of the object. As the temperature of the object increases, the peak of the spectral distribution shifts towards higher frequencies.

This relationship is known as Wien's displacement law, which states that the wavelength at which the spectral radiance of a blackbody is maximum is inversely proportional to the temperature of the object.

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We have that the sources of error in density of liquid experiment is

From the Question we are told to find

Sources of error in density of liquid experiment

It is important to note that  common reasons for  error in density of liquid experiment

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Answer:

A dekagram is thousand (1000) times larger than a centigram.

Explanation:

→ [1 dekagram = 1,000 centigrams]

→ 1 dekagram = 10 grams

→ 10 grams = 100 decigrams

→ 100 decigrams = 1,000 centigrams

Answer:

68.9233231661

Explanation:

Just put it into your calculator, shift sin should do it but it will come up like this: \(sin^{-1}\) which is the same as arcsin

Answer:

Instrmentation engineering

Explanation:

Hope this helps!

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

Answer:

25.0 cm3

Explanation:

The volume is 25.0 cm3 .

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

The magnitude S of the star's displacement from the origin in its final position is approximately 1.9117 AU.

Astronomical Units (AU) are a unit of distance commonly used in astronomy to measure distances within our solar system. One AU is defined as the average distance between the Earth and the Sun, which is approximately 93 million miles or 149.6 million kilometers.

To find the magnitude S of the star's displacement from the origin in its final position, we can use the distance formula:

distance = square root of ((x2 - x1)² + (y2 - y1)²)

where (x1, y1) are the initial coordinates of the star and (x2, y2) are the final coordinates of the star.

In this case, the initial coordinates of the star are (0, 0) and the final coordinates of the star are (S, S). We don't know the value of S yet, but we can use the fact that the initial velocity of the center of mass of the system is zero to find it.

The center of mass of the system can be found using the formula:

(m₁x₁ + m₂x₂ + m₃x₃) / (m₁ + m₂ + m₃)=x cm

(m₁y₁ + m₂y₂ + m₃y₃) / (m₁ + m₂ + m₃)=ycm

where m₁, m₂, and m₃ are the masses of the star and the two planets, and (x₁, y₁), (x₂, y₂), and (x₃, y₃) are their initial coordinates.

Using the values from the table, we can calculate the center of mass of the system:

x_cm = (2.0197×10³⁰ * 0 + 2.5623×10²⁸ * 0.1119 + 6.2841×10²⁶ * 0.3751 + 8.6951×10²⁷ * 0) / (2.0197×10³⁰ + 2.5623×10²⁸ + 6.2841×10²⁶ + 8.6951×10²⁷) ≈ 0.0038 AU

y_cm = (2.0197×10³⁰ * 0 + 2.5623×10²⁸  * 0 + 6.2841×10²⁶ * 1.2975 + 8.6951×10²⁷ * 1.4245) / (2.0197×10³⁰ + 2.5623×10²⁸ + 6.2841×10²⁶ + 8.6951×10²⁷) ≈ 1.3019 AU

Since the initial velocity of the center of mass is zero, the final velocity must also be zero. This means that the final position of the center of mass must be the same as the initial position.

Setting (x_cm, y_cm) in the final position to (0, 0), we can solve for S:

S = √(x₂² + y₂²) = √((0 - 1.9117)² + (0 - 0)²) ≈ 1.9117 AU

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(a) The acceleration of the 1,400-kg boat is 0.30 m/s².

(b) The boat move 60 m in 20.0 s

(c) The velocity at the end of that time will be 6 m /s

It is given that mass of the boat = 1400 kg , forward push on the boat by the propeller = 1,725 N and resistive force of water = 1300 N

(a) Let the acceleration of the boat be "a" .

The net force on the boat will be

F(net) = F(push) - F(R)

         = 1725 - 1300

         = 425 N

Using Newton's second law of motion , we get

F(net) = ma

       a = F(net) / m

          = 425 / 1400

          =  0.30 m/s²

(b) Let the distance moved by the boat be "d" .

It is given that it starts from rest which means that u = 0

Now using the kinematic equation  s = ut + 1/2at² .   ...(1)

Putting a = 0.30  , t = 20 and u = 0  in equation (1) , we get

     s = 0 (20) + 1/2 (0.30)(20)²

        = 0 + 1/2 (0.30 × 400)

        =  120 /2

        = 60 m

(c) Let the final velocity of the boat be "v" .

Using the kinematic equation v = u + at     ..(2)

Putting a = 0.30  , t = 20 and u = 0  in equation (2) , we get

   v = 0 + (0.30)(20)

      = 6 m /s

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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The distance is 34m , magnitude of the displacement is 6m and direction of displacement is towards west.

As per question, a dog walks 14 meters to the east and then 20 meters back to the west.

The distance moved for this motion is given below,

Distance = 14 + 20 m = 34m

The magnitude of the displacement and its direction are given below:

Displacement = 14 - 20 m = - 6m

negative sign indicates that the direction of displacement is towards west.

Magnitude of the displacement = 6m

Thus, the distance is 34m ,direction of displacement is towards west and  magnitude of the displacement is 6m.

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So, the complete sentence is If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

When the mass of the sun is larger, Earth moves around the sun at a faster pace and When the mass of the sun is smaller, Earth moves around the sun at a slower pace.

When Earth is closer to the sun, its orbit becomes faster and When Earth is farther from the sun, its orbit becomes slower.

When Earth is closer to the sun, there will be a hotter climate. A little movement that takes one closer to the sun could lead to a huge impact, as the sun is very hot.

So, it can be concluded that If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

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Answer:

his type of shock is called inelastic

Explanation:

This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.

We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.

Looking for the moments

initial. Before the crash

           p₀ = m₁ v₁₀

final. After the crash

           p_f = (m₁ + m₂) v

the conservation of the moment is written

           p₀ = p_f

           m₁ v₁₀ = (m₁ + m₂) v

This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.

Given:

The reading of the scale in air, W_a=30 N

The reading of the scale in water, W_w=20 N

To find:

Which of the given statements is true?

Explanation:

The buoyant force is an upward force acting on the object submerged in a fluid. The buoyant force is equal to the weight of the fluid displaced due to the submerged object.

This upward force acting on the object causes it to weigh less.

Thus the weight of the object is slightly more than 30 N.

Final answer:

Thus the correct answer is option C.

The magnitude is 756.72 N and the coordinate direction angles of the resultant of the two forces acting at point A are alpha(\(149^{0}\)), beta(\(0^{0}\)), and gamma(\(59^{0}\)).

The resultant force is the overall force acting on an object, which is the vector sum of all the individual forces acting on the object. It is the net force that determines the motion of an object. In other words, it is the force that would have the same effect on the object's motion as all the individual forces combined. The direction of the resultant force is the direction of the net force and the magnitude is the sum of the magnitudes of the individual forces.

Given,

A = (5, 0, 0) m

B  = (0, 2, 3) m

C = (0, -2, 3) m

AB = B - A  = -5i + 2j + 3k

\(AB_{cap}\) = \(\frac{-5i+2j+3k}{\sqrt{5^{2}+2^{2}+3^{2} } } =\frac{-5i+2j+3k}{6.16}\)  

AC = C - A = -5i - 2j + 3k

\(AC_{cap} =\frac{-5i+2j+3k}{6.16}\)

Fb = 400 (-5i + 2j + 3k ) / 6.16\(F_{b} =\frac{400(-5i+2j+3k)}{6.16} =-324.44i+129.78j+194.67k \\F_{c}=\frac{400(-5i+2j+3k)}{6.16}= -324.44i-129.78j+194.67k\)

\(F_{net} =F_{b} +F_{c}\)= - 648.88i + 389.33k N

Magnitude = |\(F_{net}\)|  = \(\sqrt{648.88^{2}+389.33^{2} } =756.72N\) .......Ans

Coordination angles,

alpha = \(cos^{-1} \frac{F_{net} x}{|F_{net}| } =149^{0}\)

beta = \(cos^{-1}\frac{F_{net}y }{|F_{net} |} =0^{0}\)  

gamma = \(cos^{-1}=\frac{F_{net}z }{|F_{net} |} =59^{0}\)

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The complete question is given below:

Answer:

hydrogen and helium

Explanation:

i got it 100 percent. Hope this Helps!

The car will travel only distance of 25.92 m.In order to overtake it needs to travel 40m. So don't attempt to pass the truck.

Vehicle speed is 25 m/s.

40m is the distance the automobile must go to pass the truck.Distance between the car approaching from the opposite direction and the passing location is 400-40, or 360 meters.

Time allowed for a car to pass a truck of 20 meters in length is equal to the distance between the automobile coming from the other direction and the relative speed of the two cars.

Time equals 360/50, or 7.2 seconds.

Let's assume that the truck is going at the same rate as the car.

The expression "distance traveled by car in comparison to truck"

S is the distance traveled, u is the initial velocity, an is the acceleration, and t is the amount of time spent, where S = ut +\(\frac{1}{2}at^{2}\)

Here, u = 0, t = 7.2 s, and a = 1 m/\(s^{2}\)

hence, the distance driven in 7.2 seconds

So,     S = 0+ 25.92 = 25.92 m

So car will travel only travel 25.92 m

In order to overtake it needs to travel 40m. So don't attempt to pass the truck.

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