A parallel-plate capacitor is formed from two 9.1 cm-diameter electrodes spaced 1.3 mm apart. The electric field strength inside the capacitor is 5.0×106N/C.
What is the charge (in nC) on each electrode?

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The force of gravity changes as the mass of one object doubles. As the mass of one object is doubled then the force between the objects also gets doubled.

Force is an influence which can change the motion of an object through the application of an external force. A force can cause an object with the mass to change its velocity, that is the object undergo acceleration.

Force is directly proportional to the mass of the object and the acceleration of the object. If we double the mass of one of the objects, then we double the strength of the force. If we double the masses of both the objects, then we quadruple the strength of force.

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Answer:

3

Explanation:

The closer an orbit is to the nucleus the fewer energy

Answer:

velocity

Explanation:

Answer:

Velocity

Velocity tells you the speed and the direction it's going. Speed only tells you the speed, with no direction.

Explanation:

The bus's displacement from Houston to Texas with average velocity = -16.170 km/h

Evaluation :

average velocity = ( initial velocity -- final velocity )

                                    ( v-u )

displacement = \(\frac{v-u}{t}\)

displacement =  \(\frac{0 - 76 }{4.7}\)

                            = - 16.170 km/h

Average velocity is determined  as the change in position or displacement (∆x) divided by the time period  (∆t) in which the displacement results . The average velocity could be positive or negative based upon the sign of the displacement. The SI unit of average velocity is defined as  meters per second (m/s or ms-1).

The displacement is commonly the difference in the position of the two marks and is independent of the path covered  when traveling between the two of the  marks. The distance covered , however, is the total length of the path chosen  between the two marks. Displacement defined  as a vector quantity that mean  to "how far out of  the place an object is"; it's the object  overall changes  in  the position.

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Answer:

Explanation:

convert the mass from g to kg

1 g = 0,001 kg

m1 =559,5 g = 5,595 kg

m2 = 569,3 g = 5,569 kg

Newtons second Law

F = m *a = m * g

g = 10 m/s^2

a_y = g ((m_2 - m_1) / (m_2+m_1))

a_y = 10 m/s^2 * ((5,569kg -5,595kg) / (5,569kg + 5,595kg))

a_y = 10 m/s^2 [(-0,026kg) / 11,164kg]

a_y = 10 m/s^2 (-0,0023)kg

a_y = - 0,023 kg m / s^2

(a)

In order to find the series total resistance, we need to add all resistances:

If three resistances are 40 ohms and three are 80 ohms, we have:

(b)

Now, since the resistances are in parallel, we need to use the expression below:

So we have:

The x component of the force is -8.03 N.

The y component of the force is -11.47 N.

The parallel components of the force is resolved into x and y components as follows;

The x component of the force is calculated as follows;

Fx = F cosθ

where;

Fx = 14 N x cos (235)

Fx = -8.03 N

The y component of the force is calculated as follows;

Fy = F sinθ

where;

Fy = 14 N x sin (235)

Fy = -11.47 N

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The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.

Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.

From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.

Thus, the ideal solution is option C.

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The magnitude of the GPE depends on the position of the object.

Some parts of the question appears to be missing but I will try to answer generally.

As an object falls, its gravitational potential energy (GPE) decreases.

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. The GPE of an object is directly proportional to its mass, the acceleration due to gravity, and its height above a reference level. The formula for gravitational potential energy is:

GPE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference level.

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The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer:

5.2 AU

Explanation:

Answer:

5.2

Explanation:

just took the quiz i hope you pass.

Explanation:

Let

T

be the tension of the cable and m

g

be the force of gravity. If the upward direction is positive, then Newton’s second law is T−mg=ma, where a is the acceleration. Thus, the tension is T=m(g+a). We use constant acceleration kinematics (Table 2-1) to find the acceleration (where v=0 is the final velocity, v

0

=−12m/s is the initial velocity, and y=−42m is the coordinate at the stopping point). Consequently, v

2

=v

0

2

+2ay leads to

a=−

2y

v

0

2

=−

2(−42m)

−12m/s

=1.71m/s

2

We now return to calculate the tension:

T=m(g+a)

=(1600kg)(9.8m/s

2

+171m/s

2

)

=1.8×10

4

N

Explanation:

To determine the velocity and pressure head at position B in a horizontally converging pipe, we can use the principle of conservation of mass and Bernoulli's equation.

According to the principle of conservation of mass, the mass flow rate remains constant throughout the pipe. Therefore, we can write:

A₁V₁ = A₂V₂

where A₁ and A₂ are the cross-sectional areas at positions A and B, respectively, and V₁ and V₂ are the velocities at positions A and B, respectively.

Given:

A₁ = (π/4)(d₁)² = (π/4)(200 cm)² = 31416 cm²

A₂ = (π/4)(d₂)² = (π/4)(150 cm)² = 17671 cm²

V₁ = 2 m/s

We can calculate V₂ using the equation:

V₂ = (A₁V₁) / A₂

Substituting the values:

V₂ = (31416 cm² * 2 m/s) / 17671 cm² ≈ 3.54 m/s

Therefore, the velocity at position B is approximately 3.54 m/s.

Next, to determine the pressure head at position B, we can use Bernoulli's equation:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂² + ρgh₂

Assuming the datum is at position B, where the pressure head (h₂) is zero, the equation simplifies to:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂²

Given:

g = 10 m/s² (acceleration due to gravity)

Z = 0 m (datum)

ρ = density of the liquid (not given)

Since the density (ρ) of the liquid is not provided, we cannot determine the absolute pressure at position B or calculate the pressure head. The information given is insufficient to determine the pressure head at position B.

In summary:

- The velocity at position B is approximately 3.54 m/s.

- The pressure head at position B cannot be determined with the given information.

Answer:

momentum=31.5

Explanation:

given,

mass(m)=2.1kg

velocity(v)=15m/s

momentum(p)=?

now,

p=mv

p=15×2.1

p=31.5 kgm/s

As the box compresses the spring, the spring performs

-1/2 (85 N/m) (0.065 m)² ≈ -0.18 J

of work on the box. By the work energy theorem, the total work performed on the box (which is done only by the spring since there's no friction) is equal to the change in the box's kinetic energy. At full compression, the box has zero instantaneous speed, so

W = ∆K   ==>   -0.18 J = 0 - 1/2 (2.5 kg) v ²

where v is the box's speed when it first comes into contact with the spring. Solve for v :

v ² ≈ 0.14 m²/s²   ==>   v ≈ 0.38 m/s

Answer:

7.7 km 26°

Explanation:

The total x component is:

x = 2.5 cos(35°) + 5.2 cos(22°) = 6.87

The total y component is:

y = 2.5 sin(35°) + 5.2 sin(22°) = 3.38

The magnitude is:

d = √(x² + y²)

d = 7.7 km

The direction is:

θ = atan(y/x)

θ = 26°

Answer: It should be the 3rd option down!

Explanation:

Answer: C

Explanation:

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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Answer:

Below

Explanation:

1) Gravity force =~  m1 m2 / r^2     now   half the radius

                         = m1 m2 / ( 1/2r)^2 = 1/4  m1m2/r^2     so the force will be 1/4

                                            625 * 1/4 = 156.25 N

2)  mass does not change..it is a measure of the amount of mass an object has  .... it will still be 95 kg

The EMF induced in a single wire loop with an area of 0.0940 m² is in a uniform magnetic field which has an initial value of 3.80 T, is perpendicular to the plane of the loop, and decreases at a constant rate of 0.190 T = 0.34 V. And the current induced in the loop = 0.57 A.

Induced electromotive force or induced emf is the potential difference at the ends of the coil which will produce an induced electric current.

An induced electric current appears as long as there is a change in magnetic flux.

The equation is:

ε = d∅/dt

We have,

The area of the loop = 0.0940m²

The change in magnetic field with time = (3.80 T - 0.190 T) = 3.61 T

So, the EMF induced:

ε = d∅/dt

=  {(0.0940m²) (3.61)} / 1

= 0.34 V

And the current induced in the loop =

I = ε/R

= 0.34 V / 0.600 Ω

= 0.57 A

The question is incomplete, it should be:

A single loop of wire with an area of 0.0900m2 is in a uniform magnetic field that has an initial value of 3.8 T, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 T/s.

(a) What emf is induced in this loop?

(b) If the loop has a resistance of 0.600O, find the current induced in the loop.

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Answer:

4.41N or 4.5N (check explanation)

Explanation:

450g = 0.45kg

F = ma

Using 10m/s² = 10(0.45) = 4.5N

Using 9.8m/s² = 9.8(0.45) = 4.41N

With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.

By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.

According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.

The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

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Answer:

Produces 60-cycle AC electricity; it is usually an off-the-shelf induction generator. High-speed shaft: Drives the generator. Low-speed shaft: Turns the low-speed shaft at about 30-60 rpm. Nacelle: Sits atop the tower and contains the gear box, low- and high-speed shafts, generator, controller, and brake.

Explanation:

Answer:

C. amplitude = 0.10 m, wavelength = 0.60 m

Explanation:

The diagram shows an oscillating progressive wave, with its amplitude and wavelength.

Amplitude of a wave is the maximum distance covered either upward or downward.

So that,

amplitude of the wave, A = \(\frac{0.2}{2}\)

                                          = 0.1

Amplitude of the wave = 0.1 m

Wavelength in this case is the distance from crest to crest, or trough to trough of the wave.

So that,

wavelength = \(\frac{1.5}{2.5}\)

                   = 0.6

wavelength of the wave = 0.6 m

Therefore, the amplitude of the wave is 0.10 m, while the wavelength is 0.60 m.

According to the information, the rms speed of the gas will remain unchanged.

The rms (root-mean-square) speed of a gas is directly proportional to the square root of its temperature. In this scenario, the temperature is constant, which means that the rms speed of the gas will also remain constant.

The change in volume does not have a direct effect on the rms speed of the gas, as long as the temperature remains unchanged. Therefore, the rms speed of the gas in the vessel will not change.

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(a) The speed of the skydiver when the parachute opens is 98.42 ft/s.

(b) The distance fallen before the parachute opens is 1,640.43 ft.

(c) The limiting velocity vL after the parachute opens is 220 ft/s.

(d) The skydiver is in the air for an additional 158.18 s after the parachute opens.

(e) The velocity versus time graph will show a linear increase in velocity during free fall, followed by a curve that starts with a steep negative slope when the parachute opens and gradually approaches the limiting velocity vL.

During free fall, the force of air resistance is given by:

F = -11v (when the parachute is closed)

F = -180v (when the parachute is open)

where v is the velocity in ft/s.

When the parachute is closed, the equation becomes:

90(dv/dt) = -90g - 11v

When the parachute opens, the equation becomes:

90(dv/dt) = -90g - 180v

To find the speed of the skydiver when the parachute opens, we need to find the velocity at t = 10 s, when the parachute is opened.

v = (980 - 110e^(-11/90t))/9

v(10) = (980 - 110e^(-11/9))/9 = 98.42 ft/s

To find the distance fallen before the parachute opens, we need to integrate the velocity from t = 0 to t = 10 s,

y = ∫(0 to 10) v dt

y = ∫(0 to 10) (32.2t) dt

y = 1/2 (32.2) (10)^2

y = 1,640.43 ft

The limiting velocity vL,

mg = 180vL

vL = mg/180 = (90 x 9.8)/180 = 4.9 m/s

vL = 16.08 ft/s

The velocity is,

v = (1960/9 - 180/11)e^(-11/90t)

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Answer:

D is the answer  I think (0 w 0 )

Explanation:

The  glaciers move gradually. Hence, option (C) is correct.

A glacier is a long-lasting mass of heavy ice that is perpetually moving. When the ablation of snow is greater than the accumulation over a long period of time, frequently centuries, a glacier forms.

As it slowly flows and deforms under forces brought on by its weight, it gains distinctive features like crevasses and seracs. Cirques, moraines, and fjords are the result of the erosion of rock and debris from its substrate as it travels.

The considerably thinner sea ice and lake ice that form on the surface of bodies of water are not the same as glaciers, which form only on land and may flow into water bodies.

The huge ice sheets, commonly referred to as "continental glaciers," in the polar areas of the planet contain 99 percent of the planet's glacial ice.

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