A 10.-kilogram rubber block is pulled horizontally at constant velocity across a sheet of ice. Calculate the magnitude of the force of friction acting on the block.

Examples of fixed joints include the joints between the bones in the skull and the joint where the radius and ulna bones meet in the lower arm

Answer:

Your skull

Explanation:

your skull has fixed joints

Answer:

Three machines that humans have created are the lever, the wheel, and the axle, and also a pulley. even though there's actually more. A lever is A rigid bar that is free to move around a fixed point, such as a screwdriver. The wheel and axle, everyone should know what that is and what it does, it lifts heavy objects, moves people quickly, and moves parts of a complex machine. Pulleys are used to lift things, pulleys can be used singly or with many pulleys working together in order to transport people or things. They can also be used to provide power from one shaft to another. ... Construction pulleys are used in order to lift and place heavy materials.

Answer:

B my brother say that it was

Answer:

1) 6.53 × 10^5

2) 1.2943 × 10^5

3) 2.263 × 10^3

4) 1.48 × 10^-2

5) 9.04 × 10^-2

The answer is C. Hope this helps!

Answer:

The energy associated with an object's motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy.

Explanation:

is the energy stored in moving objects. As the object moves faster, more energy is stored.

called MOVEMENT energy

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

\(x=4t^3+3t^2-5t+2\)

Where,

x is in meters and t is in sec

We know that,

Velocity,

\(v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5\)

(a) i. t = 2 s

\(v=12(2)^2+6(2)-5=55\ m/s\)

At t = 4 s

\(v=12(4)^2+6(4)-5=211\ m/s\)

(b) Acceleration,

\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6\)

Pu t = 3 s in the above equation

So,

\(a=24(3)+6\\\\a=78\ m/s^2\)

Hence, this is the required solution.

Explanation:

electricity is the flow of electrical power or charge

Explanation:

the flow of current is called electricity

We know the Sun is primarily made from hydrogen and helium on the basis of its spectrum. The option d is correct answer.

The spectrum of the sun is obtained by observing the light it emits. When sunlight passes through a prism or spectrometer, it is separated into a continuous spectrum by black absorption lines. These lines correspond to specific wavelengths of light absorbed by the elements in the solar wind.

By comparing these absorption lines with well-known ones of different elements, the researchers found that the main absorption lines in the solar spectrum are similar to those produced by hydrogen and helium. This indicates that these two elements are the main components of the solar wind.

Other evidence, such as the Sun's mass, brightness, age, and color, cannot provide direct information about its composition. While these conditions are important for understanding the properties and behavior of the sun, they do not specifically indicate the abundance of hydrogen and helium in its composition.

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The work required to bring a seventh particle of charge q from very far away and place it at the center of the circle is \(W =  \frac{6k(q^2)}{r}\).

1. Since there are six particles equally spaced around the circle, the distance between the center of the circle and each particle is r.
2. The work required to bring a particle of charge q close to another particle of charge q is given by Coulomb's Law:

\(W =  \frac{k(q1 * q2)}{d}\),

where k is the electrostatic constant, q1 and q2 are the charges of the particles, and d is the distance between them.
3. In this case,

q1 = q2 = q and d = r.

So the work required to bring the seventh particle close to one of the six particles is \(W =  \frac{6k(q^2)}{r}\).
4. Since there are six particles, the total work required to bring the seventh particle to the center of the circle is the sum of the work done to bring it close to each of the six particles. Therefore, the total work is \(W =  \frac{6k(q^2)}{r}\).
The work required to bring a seventh particle of charge q from very far away and place it at the center of the circle with six equally spaced particles of charge q is \(W =  \frac{6k(q^2)}{r}\).

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The Zinc is a widely used metal due to its favorable properties such as being lightweight, durable, and resistant to corrosion. However, even with its corrosion potential is not the only factor that determines the corrosion resistance of zinc.

The options provided; the correct answer is A) -1.10V. This means that zinc will have a tendency to corrode in an environment with a potential difference of more than -1.10V. The more negative the potential, the greater the potential for corrosion. It is important to note that the corrosion potential is not the only factor that determines the corrosion resistance of zinc. Other factors such as the presence of impurities or the content loaded onto the zinc can also affect its resistance to corrosion. Zinc coatings, for example, are often used to provide additional protection against corrosion. In summary, the corrosion potential of zinc nominal is -1.10V, which means that it has a potential for corrosion in an environment with a potential difference greater than -1.10V. However, the resistance to corrosion of zinc can also be affected by other factors such as the content loaded onto it.

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The ranking  in order from largest to smallest of the magnitudes of the horizontal forces f1 , f2 , and f3 acting on the arrows is F1=F2=F3>0 because there is no change in the horizontal motion of the arrows.

All three arrows in the scenario have been shot and it is assumed that air resistance can be neglected. With the motion of the arrows in horizontal direction, there is no likely change in the horizontal motion of the three arrows. This makes the three forces equivalent to one another and each force is equal to zero (i.e. F1=F2=F3=0).

Here's the complete question:

Rank in order, from largest to smallest, the magnitudes of the horizontal forces F1, F2, and F3 acting on the arrows. Some may be equal. State your reasoning. Rank in order, from largest to smallest, the magnitudes of the horizontal forces , , and acting on the arrows. Some may be equal. State your reasoning.

a. F3>F1=F2 because the mass of the first arrow is equal to the mass of the second arrow which is less than the mass of the third arrow.

b. F1=F2=F3=0 because there is no change in the horizontal motion of the arrows.

c. F1>F2=F3 because the velocity of the second arrow is equal to the velocity of the third arrow which is less than the velocity of the first arrow.

d. F1=F2=F3>0 because there is no change in the horizontal motion of the arrows.

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With the use of K.E formula, the correct answers are:

a.) At point B, velocity = 2m/s

b.) At point C, velocity = 4m/s

C.) At point D, velocity = 3.5 m/s

POTENTION ENERGY

At maximum energy, total energy will be equal to maximum kinetic energy.

Given that a 2.5 kg mass starts from rest at point A and moves along the x-axis subject to the potential energy shown in the given figure.

Let us assume the that their maximum potential energies are given.

Total energy = maximum P.E = Maximum K.E

According to the graph, the P.E at point B,C, and D are:

Since Maximum P.E = Maximum K.E = 1/2m\(v^{2}\)

At point B

5 = 1/2 x 2.5 x \(v^{2}\)

\(v^{2}\) = 10/2.5

\(v^{2}\) = 4

v = \(\sqrt{4}\)

v = 2 m/s

At point C

20 = 1/2 x 2.5 x \(v^{2}\)

\(v^{2}\) = 40/2.5

\(v^{2}\) = 16

v = \(\sqrt{16}\)

v = 4 m/s

At point D

15 = 1/2 x 2.5 x \(v^{2}\)

\(v^{2}\) = 30/2.5

\(v^{2}\) = 12

v = \(\sqrt{12}\)

v = 3.5 m/s

b.) The turning point should be any point where velocity is negative. Since there is no point where velocity is negative, let us consider the points where potential energy is increasing.

The turning points of the mass will be at point B and D

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Answer:

Correct Answer: Option B

Explanation:

Explanation

P1/T1 = P2/T2

80/(273+47) = P1/(273+27) = 75Nm-2

Answer: 75.0 Nm^-2

Explanation:

P1/T1 = P2/T2 80/(273+47) = P1/(273+27) = 75Nm-2

The owner of the stack of notebooks is Sofia, but we do not have enough information to identify the owner of the modello.

To identify the owner of each object, we need to look for any personal information or belongings associated with the object. In the case of the stack of notebooks, we can assume that they belong to Sofia since her name is mentioned in the question. Therefore, the owner of the stack of notebooks is Sofia.

For the modello, we would need more information to determine the owner. Is there any identifying information on the modello itself or nearby? Without more context, we cannot identify the owner of the modello.

In summary, the owner of the stack of notebooks is Sofia, but we do not have enough information to identify the owner of the modello.

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Answer:

дангггггггггггггггггггггггггггггггггггггггггггггг

Answer: D.

Explanation: I took the test

The magnitude of the force exerted on particle B by particle A is 23.374 N.

The magnitude of the force exerted on particle B by particle A can be calculated using Coulomb's Law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is:

F = k * (q1 * q2) / r^2

Where F is the force, k is the Coulomb's constant (8.99 × 10^9 N * m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

Plugging in the given values, we get:

F = (8.99 × 10^9 N * m^2/C^2) * (6.50 × 10^-6 C) * (4.00 × 10^-6 C) / (0.10 m)^2

F = (8.99 × 10^9 N * m^2/C^2) * (26.00 × 10^-12 C^2) / (0.01 m^2)

F = (233.74 × 10^-3 N * m^2/C^2) / (0.01 m^2)

F = 23.374 N * m^2/C^2 * 100 C^2/m^2

F = 2337.4 N/C^2 * 10^-2 C^2

F = 23.374 N

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Answer:

146.4 s

Explanation:

Distance / rate = time

205 m / 1.4 m/s =  146.4 s

Answer:

Explanation:

To determine the velocity of cart B after the elastic collision with cart A, we can use the principle of conservation of momentum. In an elastic collision, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity.

Given:

Mass of cart A (m_A) = 40 kg

Initial velocity of cart A (v_Ai) = 12 m/s

Final velocity of cart A (v_Af) = -1.9 m/s (since it moves to the left)

Mass of cart B (m_B) = 55 kg

Initial velocity of cart B (v_Bi) = 0 m/s (since it is initially stationary)

Final velocity of cart B (v_Bf) = ?

Using the principle of conservation of momentum, we can write:

Total momentum before collision = Total momentum after collision

(m_A * v_Ai) + (m_B * v_Bi) = (m_A * v_Af) + (m_B * v_Bf)

(40 kg * 12 m/s) + (55 kg * 0 m/s) = (40 kg * -1.9 m/s) + (55 kg * v_Bf)

480 kgm/s = -76 kgm/s + (55 kg * v_Bf)

To isolate v_Bf, we can rearrange the equation:

(55 kg * v_Bf) = 480 kgm/s - (-76 kgm/s)

(55 kg * v_Bf) = 480 kgm/s + 76 kgm/s

(55 kg * v_Bf) = 556 kg*m/s

Now, we can solve for v_Bf by dividing both sides of the equation by 55 kg:

v_Bf = (556 kg*m/s) / 55 kg

v_Bf ≈ 10.11 m/s

Therefore, the velocity of cart B after the elastic collision is approximately 10.11 m/s.

Electrical conductivity of Earth's atmosphere with 5.00 10-13 A/m2 current density and 164 V/m electric field = 3.24 x 10-16 S/m.

The electrical conductivity of the Earth's atmosphere in the given region can be calculated by using Ohm's law, which states that the current density is equal to the electric field divided by the electrical conductivity. So, we have a current density of 5.00 10-13 A/m2 and an electric field of 164 V/m.

Rearranging the equation, we get electrical conductivity = electric field / current density.

Plugging in the values, we get electrical conductivity = 164 / 5.00 10-13 = 3.24 x 10-16 S/m.

This tells us how well the atmosphere conducts electricity in this region, which can be useful in understanding atmospheric phenomena like lightning.

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The permittivity of free space is a fundamental physical constant that describes the ability of a vacuum or free space to permit the passage of electric fields.

The permittivity of free space, often denoted as ε₀ (pronounced "epsilon naught"), is a fundamental physical constant that describes the ability of a vacuum or free space to permit the passage of electric fields. In other words, it is the measure of the resistance that free space offers to the formation of an electric field.

It is a fundamental constant of nature and is one of the defining values of the International System of Units (SI). Its value is approximately 8.85 x 10⁻¹² farads per meter (F/m).

The permittivity of free space plays a crucial role in the study of electromagnetism, and it is used in various equations and formulas that describe the behavior of electric fields, such as Coulomb's law, Gauss's law, and the capacitance of a capacitor. It also helps to determine the speed of electromagnetic waves in free space, which is the speed of light.

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Answer:

Frictional force will be 150N

An inquisitive physics student and mountain climber climbs a 41.9 m cliff that overhangs a calm pool of water. It takes 2.996 seconds for the stone to hit the water.

We set \(y_i = 0\) at the top of the cliff, and find the time interval required for the first stone to reach the water using the particle under the constant acceleration model:

\(y_f = y_i + v_{yi}t+ \frac{1}{2} a_yt^2\)

OR

\(y_f -y_i - v_{yi}t- \frac{1}{2} a_yt^2 = 0\)

OR

\(- \frac{1}{2} a_yt^2 - v_{yi}t+y_f-y_i=0\)

If we take the direction downward to be negative,

\(y_f = -41.9 m, v_{yi} = -2 m/s, a_y = 9.8 m/s^2\)

Substituting these values into the equation, we find

4.9t² + 2t - 50 = 0

The quadratic formula is now what we use. Since the stone is thrown into the pool, time must be positive, and the physical situation can only be described by the positive root:

\(t = \frac{-2 \pm\sqrt{2^2 - 4(4.9)(-41.9)} }{2(4.9)}\)

⇒ t = 2.996 sec

Therefore, it takes 2.996 seconds for the stone to hit the water.

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Answer:

Resistance to the flow of electricity in wires and resistance to the flow of water in pipes are similar in several ways:

Both are affected by the size of the conductor: In both cases, the resistance to flow is affected by the size of the conductor. A larger diameter wire or pipe will offer less resistance to the flow of electricity or water than a smaller diameter one.

Both are affected by the length of the conductor: The resistance to flow also increases with the length of the conductor. A longer wire or pipe will offer more resistance to the flow of electricity or water than a shorter one.

Both are affected by the material of the conductor: Different materials have different resistances to flow. In electrical wires, metals are commonly used as they have low resistance. In pipes, materials such as copper, plastic, or steel may be used depending on the specific application.

Both can be reduced by minimizing obstructions: Resistance to flow can be reduced in both cases by minimizing obstructions in the path of the flow. In pipes, for example, the use of smooth inner walls and proper pipe bends can help reduce resistance. In electrical wires, minimizing the number of connections and using high-quality connections can help reduce resistance.

Overall, resistance to flow is a fundamental concept that applies to the flow of electricity and water, and the factors affecting resistance are similar in both cases.

The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Given data :

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

A) initially through fingers

I = V / r

 = 6 V / 400,000

 = 1.5 * 10⁻⁵ amp

B) when the resistance between them drops

I = V / R

 = 6 V / 200000

 = 3 * 10⁻⁵ amp

Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp

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The angle that the bird makes with the positive x-axis can be found using trigonometry. We can use the given components of velocity to calculate the angle. The y-component is 0.10m/s and the magnitude of the velocity is 0.20m/s.

To find the angle, we can use the formula for the tangent of an angle: tan(θ) = opposite/adjacent. In this case, the opposite side is the y-component (0.10m/s) and the adjacent side is the magnitude of the velocity (0.20m/s). Using the formula, we have tan(θ) = 0.10/0.20. Solving for θ, we get θ = tan^(-1)(0.10/0.20). To find the value of θ, we can use a calculator or a table of trigonometric functions. The value of tan^(-1)(0.10/0.20) is approximately 26.57 degrees. Therefore, the bird makes an angle of approximately 26.57 degrees with the positive x-axis.

The y-component is 0.10m/s and the magnitude of the velocity is 0.20m/s. To find the angle, we can use the formula for the tangent of an angle: tan(θ) = opposite/adjacent. In this case, the opposite side is the y-component (0.10m/s) and the adjacent side is the magnitude of the velocity (0.20m/s). Using the formula, we have tan(θ) = 0.10/0.20. Solving for θ, we get θ = tan^(-1)(0.10/0.20). To find the value of θ, we can use a calculator or a table of trigonometric functions. The value of tan^(-1)(0.10/0.20) is approximately 26.57 degrees. Therefore, the bird makes an angle of approximately 26.57 degrees with the positive x-axis.

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Answer:

c 0.10

Explanation:

V=IR

12.0V=I x 120.12ohms

I=0.099

I= 0.10