Answer: m = 72 kg
Explanation:
Which wave has high enough energy to cause damage to skin and sometimes cancer?
Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.
Explanation:
Which statement is true?
A)
All waves travel at the same speed through any medium.
B)
All waves travel at the same speed if no medium is present.
Electromagnetic waves require a medium, but mechanical waves do not.
D)
Mechanical waves require a medium, but electromagnetic waves do not
Answer:
B.
Explanation:
a spring has a spring constant of 80 N/m. How much elastic potential energy is stored in the spring when it is compressed by 0.1m?
Answer:
The elastic potential energy stored in a spring can be calculated using the formula:
E = (1/2) kx^2
where E is the elastic potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
Plugging in the given values, we get:
E = (1/2) (80 N/m) (0.1 m)^2
E = (1/2) (80 N/m) (0.01 m^2)
E = 0.4 J
Therefore, the elastic potential energy stored in the spring when it is compressed by 0.1m is 0.4 J.
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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If you dropped the hoop without any string so it did not rotate as it fell, how fast would its center be moving when it had fallen a distance h
Although we do not have the necessary information to provide an exact answer, we can confirm that the object will have fallen by a multiple of 9.8 meters due to gravity.
How does gravity affect this fall?When an object is dropped, its acceleration is determined by gravity. This force applies a constant acceleration of 9.8 meters per second. Therefore, to calculate its speed at distance h, we would need to know the time it has taken the object to reach this point, and use that together with our known acceleration in order to calculate its current speed.
Therefore, we can confirm that in order to calculate the current speed of the object at point h, we require the time taken to reach this point or the value of the distance itself and that the answer will be a multiple of 9.8, due to gravity.
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A metalrod of length 40.0cm at 20°C is heated to a temperature of 45°C. If the new length is 40.05cm, Calculate its Linear expansivity.
Answer:
The answer is 5×10‐⁵
Step-by-step Explanation:
\( \alpha = \frac{l2 - l1}{l1( \beta 2 - \beta 1)} \)
let ß be ø
\( \alpha = \frac{40.05 - 40}{40(45 - 20)} \)
\( \alpha = \frac{0.05}{40 \times 25} \)
\( \alpha = \frac{0.05}{1000}\)
\( \alpha = \frac{0.05}{1000}\)\( \alpha = 5.0 \times {10}^{ - 5} \)
The kinetic energy of an object increases as its ____ increases.
Question 12 options:
gravitational energy
potential energy
specific heat
velocity
Answer:
velocity
Explanation:
velocity is the answer
The kinetic energy of an object increases as its velocity increases. The correct option is D.
An object's kinetic energy is linearly related to the square of its velocity. In other words, an object's kinetic energy grows more quickly the faster it moves. The equation below describes this relationship:
Kinetic Energy = (1÷2) × mass × velocity²
Therefore, the increase in kinetic energy of an item depends on its velocity. Potential energy, not kinetic energy, includes gravitational and potential energy.
Specific heat is a quality associated with a substance's ability to retain heat; it is unrelated to the kinetic energy of an object.
Thus, the correct option is D.
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Your question seems incomplete, the probable complete question is:
The kinetic energy of an object increases as its ____ increases
A. gravitational energy
B. potential energy
C. specific heat
D. velocity
what is the physics behind why electric parallel plates move from positive to negative
The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.
Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.
What are electric parallel plates?When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.
The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.
In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.
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A 620 N physics student stands on a bathroom scale in an elevator that is supported by a cable. The combined mass of student plus elevator is 870 kg. As the elevator starts moving, the scale reads 450 N.
Required:
a. Find the acceleration of the elevator (magnitude and direction).
b. What is the acceleration if the scale reads 670 N?
c. If the scale reads zero, should the student worry? Explain.
d. What is the tension in the cable in parts (a) and (c)?
Answer:
(a) 9.28 m/s2
(b) 9.03 m/s2
(c) 9.8 m/s2
(d) 450 N, 670 N
Explanation:
mass of elevator + student, m = 870 kg
Reading of scale, R = 450 N
(a) When the elevator goes down, the weight decreases.
Let the acceleration is a.
By the Newton's second law
m g - R = m a
870 x 9.8 - 450 = 870 a
a = 9.28 m/s2
(b) R = 670 N
Let the acceleration is a.
870 x 9.8 - 670 = 870 a
a = 9.03 m/s2
(c) If the scale reads zero, it mean the elevator is falling freely. The acceleration is downwards and its value is 9.8 m/s2.
(d) Tension in cable is 450 N and 670 N.
Scientists monitor the ozone layer by taking air samples by airplane or weather balloons. What atmospheric layer do the scientists collect the ozone samples from?
Scientists typically collect ozone samples from the stratosphere, which is the atmospheric layer located between about 10 and 50 kilometers (6 to 30 miles) above the Earth's surface.
What is the stratosphere?The stratosphere is the layer of the Earth's atmosphere located above the troposphere and below the mesosphere. It extends from about 10 kilometers (6 miles) to about 50 kilometers (30 miles) above the Earth's surface.
The stratosphere is characterized by a gradual increase in temperature with altitude, due to the absorption of ultraviolet radiation by ozone in the stratosphere.
This is where most of the Earth's ozone is found and where the ozone layer is located. The ozone layer absorbs harmful ultraviolet (UV) radiation from the sun, protecting life on Earth from its harmful effects. Scientists collect air samples from this layer using airplanes or weather balloons equipped with specialized instruments.
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A gun fires a bullet 13 m/s at a distance of 9.18m. How long did it take the buller to travel that distance at that speed? Show your work. Don’t forget the unit.
Answer:
9.18/13=0.7062 second
Explanation:
9.18meters devide it by the speed 13m/s
≈0.7062
6th grade science I mark as brainliest
Answer:
7 would be C, a cell.
Explanation:
Hi.
7 would be C, a cell.
A cell is the basic unit of structure and function in all living things.
If it is living, it is made of cells.
Hope this helps.
Answer:
7. Cell
8. Organelle
The weight of a box is found to be 30 N. What is the approximate mass of the box?
3 kg
300 kg
120 kg
30 kg
Answer:
3kg
Explanation:
3kg is the appropriate mass
Answer:
3kg
Explanation:
just took the test
The diagram shows an oscilloscope
trace from an AC supply. Calculate
the period of this supply if each
horizontal division represents 2ms.
The period of the this given oscilloscope trace from an AC supply is calculated as 1 * 10⁻³ seconds.
What do you mean by period?Period of a wave is the inverse of the frequency so the formula for wave period is, T = 1 / f , where T is period which is the time taken for one cycle to complete, and F is frequency.
To obtain period from frequency, first you have to convert frequency from Hertz to 1/s and then divide 1 by the frequency. The period of a wave is measured in seconds (s), while the frequency is measured in Hertz (Hz).
Given each horizontal division is 2ms
the time= 10ms
Period = 1/T
= 1/10ms
= 0.1ms
Period = 1 * 10⁻³ seconds
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You apply a force of 600 N to push a grocery cart and it accelerates at a rate of 1 m/s/s. What mass does the cart have?
using the second neutons law
600=mx1
=600kg
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
A car is traveling at a constant speed on the highway. Its tires have a diameter of 68.0 cm and are rolling without sliding or slipping. If the angular speed of the tires is 55.0 rad/s , what is the speed of the car?
Answer:
37.4m/s
Explanation:
since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:
v=55*0.68
v=37.40
A pulse of sound takes 1 second to travel about 25 feet to the seafloor
100
and back. A ship stops in an area where the seafloor extends to the bottom
of the Sunlight Zone. At this spot an echosounder gives a pulse of sound
that takes 26 second to travel to the seafloor and back. How deep is the
100
ocean at the bottom of the Sunlight Zone?
HELP!!! I’m stumped!! Get max points ( if it lets me! )
Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.
The distance travelled by echo sound is given by the formula -
Speed = 2×distance/time
So, calculating the speed of sound from the formula using distance and time
Speed = 2×25/(1/100)
Speed = 50×1000
Speed of sound = 5000 feet/second
Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -
Distance = (speed×time)/2
Distance = (5000×26/100)/2
Distance = 1300/2
Distance = 650 feets
Hence, the depth of ocean is 650 feets.
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Answer:
We can start by using the formula:
distance = speed x time
where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.
The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).
Converting the round-trip time to seconds, we have:
26 seconds - 1 second = 25 seconds
Substituting the values into the formula:
2 x depth = 4,921 feet/second x 25 seconds
2 x depth = 123,025 feet
depth = 61,512.5 feet
Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.
X= -5, 1, 7,10,22 f(x)= 7,2,0,1,18 what is the domain of the range is 1
Answer:
Well if X= -5, 1, 7, 10, 22 and if f(x)= 7, 2, 0, 1, 18 than there is your answer.
Explanation:
[X= 1]
A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---
(c) Find the initial velocity of the ball.
____ m/s upward
(d) Find the maximum height it reaches.
____ m
(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.
Using the equation, we can solve for the acceleration:
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s
Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.
(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.
(c) To find the initial velocity of the ball, we can use the equation:
v = u + at
At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s upward
Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.
(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:
s = ut + (1/2)at^2
At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.
0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2
0 = 47.864 + (-5.5294)
5.5294 = 47.864
Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.
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If a roller coaster cart, with a mass of 100 kg, traveled this coaster, how much kinetic energy would it have at point 'E'?
Answer:
Explanation:
Assuming no friction between the roller coaster car and the hill, and neglecting air resistance, the kinetic energy the roller coaster car would have at the bottom of the hill would be equal to its gravitational potential energy at the top of the hill, by conservation of energy.
1.How much work does it take to get a 2Kg ball moving 15m/s if it starts from rest?
2. If a force of 235N was added to the ball, through what distance would this force have to act to give the ball a velocity of 15m/s
Hi, I'm confused on how to get 15.6 from this question.
In order to calculate the angle of refraction, we can use the law of refraction below:
\(n_1sin\theta_1=n_2sin\theta_2\)Where n1 and n2 are the index of refraction and theta1 and theta2 are the incident angle and the refraction angle.
So, using n1 = 1.0003, n2 = 2.42 and theta1 = 40.5°, we have:
\(\begin{gathered} 1.0003*sin\left(40.5°\right)=2.42*sin\theta_2 \\ 1.0003*0.649448=2.42*sin\theta_2 \\ 0.6496428=2.42*sin\theta_2 \\ sin\theta_2=\frac{0.6496428}{2.42} \\ sin\theta_2=0.268447438 \\ \theta_2=15.6° \end{gathered}\)Therefore the angle of refraction is 15.6°.
Identify the direction of the net force acting on the object. Explain your reasoning
Answer:
See Below
Explanation:
I am not sure what you exact question is to know what direction it is but here is how you do it.
The direction of the net force is the direction of the largest force.
for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps
A football that is inflated inside and taken outdoors on a winter day shrinks slightly. What are the two variables that are in this scenario
A: Density and pressure
B: Volume and pressure
C: Volume and temperature
D: Pressure and temperature
What will be resultant force ?
Answer:
It will go to the right way 500N.
Explanation:
Because, up and down is 300 and 300 so it minus each other and get zero, that made the resultant force will never go up or down. And now we are focusing on the left and right. 900 is more than 400, so it will go to the right. But we also pull to the left too!! That make the resultant force is 500 to the right.
1. A body of mass 0.5kg is taken up an Inclined plane the length 10m and height 8m and then allowed to slide down to the bottom again the coefficient of Friction in the body and the plane is 0.12.what is a. work done by gravitational force over the ground trip? b work done by applied force over the up work trip? c. work done by Frictional force over the round trip? d. Kinetic energy of the body at the end of the trip?
Which of the following correctly ranks the magnitude of the average acceleration of the cart during the four sections of the graph?
a) Acd > Aab > Abc > Ade
b) Abc > Aab > Acd > Ade
c) Aab > Abc > Ade > Acd
d) Acd > Aab > Ade > Abc
The magnitude of the average acceleration of the cart: a(CD) > a(AB) > a(DE) > a(BC). Therefore, option (d) is correct.
What is average acceleration?Acceleration can be defined as the rate of change of velocity and is denoted by ‘a. It is measured in the units of m/s². For a particular interval, the average acceleration is the change in velocity for that specific time interval.
Average acceleration is calculated by the following formula,
Average acceleration = Δv/Δt
Where Δ v is the change in velocity and Δt is the total time in the velocity is changing.
For the curve AB:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (8 -0)/(0.6 - 0) = 13.3 m/s²
For the curve BC:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (8 -8)/1 - 0.6) = 0 m/s²
For the curve CD:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (0-8)/(1.2 -1.0) = -40 m/s²
For the curve DE:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (-4-0)/(2.0 - 1.2) = 5 m/s²
Therefore, the magnitude of the average acceleration of the cart: Acd > Aab > Ade > Abc
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Which equation describes the sum of the vectors plotted below?
The equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
What is vector quantity?A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
According to the final position of the vector as shown in the figure, The final x co-ordinate is 4 and the final y co-ordinate is 2.
the equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
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Can a single atom be considered a molecule?
A:only if the atom is found in water
B:no, it takes two or more atoms bonded to create a molecule
C:only if it is an oxygen atom floating in the air
D:yes, all atoms are made up of many different molecules