10^n = 10^3 times the square root of (10^31 / 0.001.)
What is n?

The value of x in the parallel line is as follows:

1. x = 50

2. x = 55

3. 102 - 2v

When parallel lines are cut by a transversal line, angle relationships are formed such as alternate interior angles, alternate exterior angles, corresponding angles, vertically opposite angles, linear angles etc.

Therefore, let's use the angle relationship to find the value of x as follows:

1.

m∠1 = m∠8(alternate interior angles)

2x + 25 = x + 75

2x - x = 75 - 25

x = 50

2.

m∠2 = m∠6(corresponding angles)

3x - 10 = 2x + 45

3x - 2x = 45 + 10

x = 55

3.

m∠3 + m∠8 = 180(same side interior angles)

4v - 31 + 2x + 7 = 180

2x = 180 + 31 - 7 - 4v

2x = 204 - 4v

x = 102 - 2v

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Answer:

\(\frac{1}{4}\)

Step-by-step explanation:

Using the rule of exponents / radicals

\(a^{\frac{m}{n} }\) = \((\sqrt[n]{a})^m\)

\(a^{-m}\) = \(\frac{1}{a^{m} }\) , then

\(-8^{-\frac{2}{3} }\)

= \(\frac{1}{-8^{\frac{2}{3} } }\)

= \(\frac{1}{(\sqrt[3]{-8})^2 }\)

= \(\frac{1}{-2)^{2} }\)

= \(\frac{1}{4}\)

Answer:

t > 82

Step-by-step explanation:

First write what we know.

Earned $72

$4 per ticket, t

Cost is $400

So let's write our equation:

The cost is $400 so we put that on the left side,

$400 =

Now on the right side, we know they earned $72, so +$72 and each ticket (t) is $4 so $4t would represent the amount earned after they sell a certain number of tickets.

So we write:

$400 = $4t + $72 Now solve for t to find the number of tickets they need to sell.

400 = 4t + 72   Subtract 72 from each side.

400 - 72 = 4t + 72 - 72  

328 = 4t     Divide each side by 4.

328/4 = 4t/4

328/4 = t

82 = t

If the committee wants money left over they need to sell more than 82 tickets!

Our inequality is:

t > 82

a) X'Y' + X'Y + XY simplifies to X' + Y.

b) A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the functions:

a) Complement is W' + X' + YZ.

b) Complement is (A' + B + C)(A'B' + C' + A'B).

a) To prove X'Y' + X'Y + XY = X' + Y, we can use Boolean algebra identities:

X'Y' + X'Y + XY

= Y'(X' + X) + XY(Distributive Law)

= Y' + XY(X + X' = 1)

= X' + Y(Commutative Law)

Therefore, X'Y' + X'Y + XY simplifies to X' + Y.

b) To prove A'BC' + ABC' + BC'D = BC', we can simplify the expression using Boolean algebra:

A'BC' + ABC' + BC'D

= BC'(A' + A) + BC'D   (Distributive Law)

= BC' + BC'D(A + A' = 1)

= BC'(BC' + BC'D = BC' + BC'(1) = BC')

Hence, A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the given functions:

a) The complement of WX(Y'Z + YZ') + W'X'(Y' + Z)(Y + Z') is W' + X' + YZ.

b) The complement of (A + B' + C')(A'B' + C)(A + B'C') is (A' + B + C)(A'B' + C' + A'B).

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We need to determine if the vectors u and v are linearly independent. If they are linearly independent, then they form a basis for W. If not, we can find a linearly independent set of vectors that spans W by applying the Gram-Schmidt process.

1. This process orthogonalizes the vectors, creating a new set of vectors that are linearly independent and span the same subspace.

2. Once we have the basis for W, we can find the orthogonal complement of W in R⁴. The orthogonal complement consists of all vectors in R⁴ that are orthogonal to every vector in W. This can be achieved by finding a basis for the null space of the matrix formed by the orthogonalized vectors of W.

3. By following these steps, we can find a basis for W and the orthogonal complement of W in R⁴. The basis of W will consist of linearly independent vectors spanning the subspace, while the basis of the orthogonal complement will consist of vectors orthogonal to W.

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The input value x in the function j(x) = 3-x as j(x) equals -5 is 8.

A function is simply a relationship that maps one input to one output.

Given the function in the question;

To determine the value x or input value, equate the function to -5 and solve for x.

j( x ) = 3 - x

j( x ) = -5

-5 = 3 - x

Add 5 to both sides

-5 + 5 = 3 + 5 - x

0 = 8 - x

Add x to both sides

0 + x = 8 - x + x

x = 8 - x + x

x = 8

Therefore, the value of x is 8.

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Therefore, the best estimate for the area under the curve is 192.

We can estimate the area under the curve using the trapezoidal rule with a step size of Δx = 2:

Area ≈ Δx/2 [f(0) + 2f(2) + 2f(4) + f(6)]

Substituting the given function:

Area ≈ 2/2 [f(0) + 2f(2) + 2f(4) + f(6)]

≈ f(0) + 2f(2) + 2f(4) + f(6)

≈ 2(0)^2 + 3(0) - 1 + 2(2)^2 + 3(2) - 1 + 2(4)^2 + 3(4) - 1 + 2(6)^2 + 3(6) - 1

≈ 192

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Answer: <less than >greater than ≥ greater than or equal to ≤ less than or equal to

Step-by-step explanation:

Answer:

\( \boxed{f = -6} \)

Step-by-step explanation:

\( = > - 7f - 9 = 9 - 4f \\ \\ = > - 7f + 4f - 9 = 9 \\ \\ = > - 3f = 9 + 9 \\ \\ = > - 3f = 18 \\ \\ = > 3f = - 18 \\ \\ = > f = - \frac{18}{3} \\ \\ = > f = - 6\)

(a) tangent line to the graph of f(x) = x^3 at the point (4,2).

(b) equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12).

(a) To find the equation of the tangent line to the graph of f(x) = x^3 at the point (4,2), we need to find the slope of the tangent line at that point. We can do this by taking the derivative of f(x) with respect to x and evaluating it at x = 4. The derivative of f(x) = x^3 is f'(x) = 3x^2. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Once we have the slope, we can use the point-slope form of a linear equation to write the equation of the tangent line.

(b) Similarly, to find the equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12), we differentiate f(x) to find the derivative f'(x). The derivative of f(x) = x^2 - x is f'(x) = 2x - 1. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Using the point-slope form, we can write the equation of the tangent line.

In both cases, the equations of the tangent lines will be in the form y = mx + b, where m is the slope and b is the y-intercept.

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Answer:

$7.50

Step-by-step explanation:

formula for simple interest:

I = prt

I = ($125)(0.03)(2)

I = $7.50

Answer:

You time 125 by 1.03 twice subtract 125 from that awnser to get the amount of money from interest 7.6125 is the awnser

Step-by-step explanation:

Answer:

3/10 cups

Step-by-step explanation:

so what i did was add 4 plus 4 plus 4 and that will make a little left over but that gives you 3/10 hopes this helps

Answer:

Step-by-step explanation:

Answer: $924

Step-by-step explanation:

From the question, we are told that if Raul has a sale of $280 he'll earn $40 as commission. This shows that he earns 40/280 = 1/7 as commission.

If Raul would like for his commission to be $132, he'll have to make a sale of:

Let the sale be represented by a

= 1/7 × a = $132

a = $132 × 7

a = $924

He'll have to make a sale of $924

The population mean pulse is approximately 70.44 beats per minute. The mean pulse of sample 1 is approximately 65 beats per minute.

The mean pulse of sample​ 2, is approximately 73.67 beats per minute.

a. mean = ∑x/n

= 634 / 9

= 70.44

b. The mean of sample 1

= 64 + 65 + 66 / 3

= 195 / 3

= 65

c. the mean of sample 2

= 81 + 67 + 73 / 3

= 221 / 3

= 73.67

In summary,  The population mean pulse is approximately 70.44 beats per minute. The mean pulse of sample 1 is approximately 65 beats per minute. The mean pulse of sample​ 2, is approximately 73.67 beats per minute.

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Complete question

Student

Pulse

Perpectual Bempah

64

Megan Brooks

81

Jeff Honeycutt

67

Clarice Jefferson

68

Crystal Kurtenbach

80

Janette Lantka

70

Kevin McCarthy

73

Tammy Ohm

65

Kathy Wojdya

66

(a) Determine the population mean pulse is approximately ____?__beats per minute.

​(Type an integer or decimal rounded to the nearest tenth as​ needed.)

​(b) Determine the sample mean pulse of the following two simple random samples of size 3.

Sample​ 1: {Perpectual, Tammy Kathy}

Sample​ 2: {Jeff, Megan, Kevin}

The mean pulse of sample 1 is approximately ___?___ beats per minute.

​(Round to the nearest tenth as​ needed.)

The mean pulse of sample​ 2, is approximately ____?__ beats per minute.

​(Round to the nearest tenth as​ needed.)

Answer:

it is answer of this question

please mark as brainlist

Answer:

\(M=\frac{280}{140} =2\)

\(C=2+5=7\)

(2 Movies and 7 Commercials)

Step-by-step explanation:

Let's represent every time Carson's songs are played in a commercial as C and in movies as M.

Set up the following equations:

\(20C+120M=380\)  (1)

\(C=M+5\)   (2)

Substitute equation 2 for equation 1:

\(20(M+5)+120M=380\)

Distribute:

\(20M+100+120M=380\)

Simplify:

\(140M=280\)

Divide both sides by 140:

\(M=\frac{280}{140} =2\)

Substitute 2 as M back into either original equation, I will use (2):

\(C=2+5=7\)

Answer:

Step-by-step explanation:

Please post the question dear!

Answer:

how can I help u plz can u say

The solution to the system of equations in this problem is given as follows:

x = 1.16, y = 3.71.

The system of equations for this problem is defined as follows:

Multiplying the first equation by 2, we have that:

x + 4y = 16

x = 16 - 4y.

Replacing into the second equation, the solution for y is obtained as follows:

3(16 - 4y) - 0.67y = 1

48 - 12y - 0.67y = 1

12.67y = 47

y = 47/12.67

y = 3.71.

Then the solution for x is of:

x = 16 - 4(3.71)

x = 1.16.

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To simply ratios, we need to get the common factor of the ratio, and divide the ratio by this common factor.

For a) 33 : 121

33 = 3 x 11

121 = 11 x 11

So the common factor of this ratio is 11

Dividing the ratio by 11 :

The answer is 3 : 11

For b) 30 : 72

30 = 2 x 3 x 5

72 = 2 x 2 x 2 x 3 x 3

So the common factor of this ratio is 2 x 3 = 6

Dividing the ratio by 6 :

The answer is 5 : 12

The given procedure does not result in a binomial distribution because it does not satisfy the criteria of having only two possible outcomes and independent trials.

No, this procedure does not result in a binomial distribution. In order for a distribution to be binomial, it must meet four criteria: (1) there must be a fixed number of trials; (2) the trials must be independent; (3) there must be only two possible outcomes (i.e., success or failure); and (4) the probability of success must remain the same in all trials.

In the given procedure, there are more than two possible outcomes (i.e., the different TV shows that the college students can choose) and the trials are not independent. Therefore, the procedure does not satisfy two of the four criteria necessary for a binomial distribution.

A binomial distribution can be described by the formula:

\(P(x) = nCx * p^x * (1 - p)^(n - x)\)

where n is the number of trials, x is the number of successes, and p is the probability of success. Since the given procedure does not meet the criteria for a binomial distribution, this formula does not apply.

The given procedure does not result in a binomial distribution because it does not satisfy the criteria of having only two possible outcomes and independent trials.

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Answer:

D on edge

Step-by-step explanation:

I got several quiz checks

Answer:

D) x2 + 81 = x2 + 20x + 100

Step-by-step explanation:

The power of substitutes is one of the five forces in Porter's Five Forces framework and it is a measure of how easy it is for customers to switch to alternative products or services. The higher the power of substitutes, the more competitive the industry and the lower the profitability.

The power of substitutes is based on the premise that when there are readily available alternatives to a product or service, customers can easily switch to those alternatives if they offer better value or meet their needs more effectively. This poses a threat to the industry as it reduces customer loyalty and puts pressure on pricing and differentiation strategies.

The availability and quality of substitutes influence the degree to which customers are likely to switch. If substitutes are abundant and offer comparable or superior features, the power of substitutes is strong, increasing the competitive intensity within the industry. On the other hand, if substitutes are limited or inferior, the power of substitutes is weak, providing more stability and protection to the industry.

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The question aims to perform the following steps using MATLAB m-file: Create a matrix a by giving the numbers in decrements of 1.5.

Create a matrix b by concatenating a five times. Show the first five elements of the third row of matrix b. Show all the elements of the last row of matrix b.

Find the maximum value of all the elements of matrix b. Find the minimum value of all the elements of matrix b.Compute the sum of all the elements of matrix b. Find the total number of elements of matrix b. Compute the average value of all the elements of matrix b. Find the square root of each element of matrix b. Find the square of each element of matrix b.

The complete MATLAB m-file is given below. Please find the comments in the code to get a better understanding of the code.% Creating matrix a a=[10:-1.5:1] % Creating matrix b by concatenating a five times b=repmat(a,5,1) % Showing the first five elements of the third row of matrix b b(3,1:5) % Showing all the elements of the last row of matrix b b(end,:) % Finding the maximum value of all the elements of matrix b max_b=max(b(:)) % Finding the minimum value of all the elements of matrix b min_b=min(b(:)) % Computing the sum of all the elements of matrix b sum_b=sum(b(:)) % Finding the total number of elements of matrix b numel_b=numel(b) % Computing the average value of all the elements of matrix b avg_b=sum_b/numel_b % Finding the square root of each element of matrix b sqrt_b=sqrt(b) % Finding the square of each element of matrix b square_b=b.^2

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Sin(300°) = -√3 / 2 .

Answer:

five plus 7 times two

Step-by-step explanation:

The total weight of the cards inside the box is approximately 217.6 oz.

Each deck of cards weighs 3.4 oz, and there are 64 decks of cards in the box. Therefore, the total weight of the cards inside the box is 3.4 oz/deck x 64 decks = 217.6 oz. As the answer needs to be rounded to the nearest ounce, we round 217.6 to the nearest ounce, which gives us 218 oz.

However, the question asks for the weight of the cards, which is only accurate to one decimal place. Therefore, we round 217.6 to one decimal place, which gives us 217.6 oz. Hence, the total weight of the cards inside the box is approximately 217.6 oz.

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