You are tasked with sorting the rods. What does RB likely stand for?
A. Rejected Bins
B. Requisite Bins
C. Red Bins
D. Rolling Bins
E. Rod Bins
A Report Content Errors

Answer:

The answer is 7, 8 and 9. The Two-digit numbers are: ab, ac, ba, bc, ca, cb

The Sum of them is: 10a + b + 10a + c + 10b + a + 10b + c + 10c + a + 10c + b = 528

22a + 22b + 22c = 528

a + b + c = 528/22

a + b + c = 24      The only option of three different digits with the sum of 24 is 7, 8 and 9.

Hope this helps, stay safe, and merry christmas!

answer : 8.975

8 39/40 = 8.975

Answer:

D>C>A>B

Step-by-step explanation:

The yardstick is three feet long. The 75-inch rope is about 6 feet long (6 ft = 72 in). The 1.21-m chain is about 20% more than 40 inches (really 39.37 inches), or about 48 inches, which is 4 feet. Thus the sequence of lengths is yardstick (3 0, rattlesnake (3.5 ft), chain (4 ft), and rope (6 ft).

Answer:

A square has 4 sides of equal length, so if you have been given the length, this is also the breadth.

Therefore, the perimeter is 4 x side length.

For example, imagine a square with side length 3 cm.  As all four side lengths are equal, the perimeter would be 4 x 3 cm = 12 cm

The integral for finding the area of the region is:

A = ∫[lower bound]^[upper bound] [rightmost bound] dy

A = ∫[1/6]^∞ [6] dy

To sketch the region enclosed by the curves and determine whether to integrate with respect to x or y, let's analyze the given equations:

y = 1/x

y = 1/x^2

x = 6

To begin, let's plot these curves on a coordinate plane:

First, we can observe that both equations involve hyperbolas. The equation y = 1/x represents a hyperbola that passes through the points (1,1), (2,0.5), (-1,-1), etc. The equation y = 1/x^2 represents a hyperbola that passes through the points (1,1), (2,0.25), (-1,1), etc.

Next, the equation x = 6 represents a vertical line passing through the point (6,0) on the x-axis.

Now, to determine the enclosed region, we need to find the limits of integration.

Since the curves intersect at certain points, we need to find these points of intersection. Equating the two equations for y and solving, we get:

1/x = 1/x^2

Multiplying both sides by x^2 yields:

x = 1

Hence, the curves intersect at x = 1.

Therefore, the region enclosed by the curves is bounded by the following:

The curve y = 1/x,

The curve y = 1/x^2,

The vertical line x = 6, and

The x-axis.

To determine whether to integrate with respect to x or y, we need to consider the orientation of the curves. In this case, the curves are defined in terms of y = f(x). Thus, it is more convenient to integrate with respect to y.

To find the area of the region, we need to set up the integral bounds. Since the region is bounded by the curves y = 1/x and y = 1/x^2, we need to find the limits of y.

The lower bound is determined by the curve y = 1/x^2, and the upper bound is determined by the curve y = 1/x. The vertical line x = 6 acts as the rightmost boundary.

Therefore, the integral for finding the area of the region is:

A = ∫[lower bound]^[upper bound] [rightmost bound] dy

A = ∫[1/6]^∞ [6] dy

Now, we can proceed with evaluating this integral to find the area of the enclosed region.

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Answer:

Domain : {1, 3, 6, 7, 9

Step-by-step explanation:

Domain is nothing but the set of x values for a relation

The x values are 1, 6, 3, 9, 7

Domain is expressed using curly braces and the values from minimum t maximum

Domain : {1, 3, 6, 7, 9}

An equation for the total cost is TC = 1500 + 5x

In this question, a canteen has fixed cost of $1500 per week.

A meal costs $5 each are sold at a fixed price of $9 each.

We need to write the equation for the total cost.

Let x be the number of individuals.

Let TC represents the total cost.

So, an equation for the total cost would be,

TC = 1500 + 5x

Therefore, an equation for the total cost is TC = 1500 + 5x

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The solution to the provided differential equation with the initial condition y(0) = 5 and u as a step change of unity is y = -2

The provided differential equation is: \(\[\frac{{dy}}{{dt}} = y + 2u\]\) with the initial condition: y(0) = 5 where u is a step change of unity.

To solve this differential equation, we can use the method of integrating factors.

First, let's rearrange the equation in the standard form:

\(\[\frac{{dy}}{{dt}} - y = 2u\]\)

Now, we can multiply both sides of the equation by the integrating factor, which is defined as the exponential of the integral of the coefficient of y with respect to t.

In this case, the coefficient of y is -1:

Integrating factor \(} = e^{\int -1 \, dt} = e^{-t}\)

Multiplying both sides of the equation by the integrating factor gives:

\(\[e^{-t}\frac{{dy}}{{dt}} - e^{-t}y = 2e^{-t}u\]\)

The left side of the equation can be rewritten using the product rule of differentiation:

\(\[\frac{{d}}{{dt}}(e^{-t}y) = 2e^{-t}u\]\)

Integrating both sides with respect to t gives:

\(\[e^{-t}y = 2\int e^{-t}u \, dt\]\)

Since u is a step change of unity, we can split the integral into two parts based on the step change:

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt + 2\int_{t}^{{\infty}} 0 \, dt\]\)

Simplifying the integrals gives:

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt + 0\]\)

\(\[e^{-t}y = 2\int_{{-\infty}}^{t} e^{-t} \, dt\]\)

Evaluating the integral on the right side gives:

\(\[e^{-t}y = 2[-e^{-t}]_{{-\infty}}^{t}\]\)

\(\[e^{-t}y = 2(-e^{-t} - (-e^{-\infty}))\]\)

Since \(\(e^{-\infty}\)\) approaches zero, the second term on the right side becomes zero:

\(\[e^{-t}y = 2(-e^{-t})\]\)

Dividing both sides by \(\(e^{-t}\)\) gives the solution: y = -2

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D. The energy used is the same for both segments, the power while running is greater.

Walking and running both require energy, but the distance covered and the time taken are different. In this case, the person covers the same distance of 1 km in both segments.

Therefore, the energy used is the same for both. However, since running involves covering the same distance in less time, the power while running is greater. Power is the rate at which energy is used, and since running takes less time, the power output is higher.

D. The energy used is the same for both segments, the power while running is greater.

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Answer:

10.82 or \( \sqrt{117} \)

Step-by-step explanation:

pythagorean theorem is x^2+y^2=r^2

9^2+6^2=r^2

117=r^2

r= \( \sqrt{117} \)

Answer:

10.81665383 about 10.8 units

Step-by-step explanation:

how to find the hypotenuse is a^2 + b^2 = c^2

a = 9

b = 6

9^2 + 6^2

9 x 9 = 81

6 x 6 = 36

81 + 36 = 117

177 = c^2

find the square root of 177 = 10.81665383 about 10.8

The explicit formula to model the amount you have saved after n months is Amount saved after n months = $50 + ($10 * (n - 1)).

To write an explicit formula to model the amount you have saved after n months, we can use the initial amount of $50 and the additional amount of $10 added each month.

The explicit formula can be written as:
Amount saved after n months = Initial amount + (Additional amount per month * (n - 1))

So, the explicit formula to model the amount you have saved after n months is:
Amount saved after n months = $50 + ($10 * (n - 1))


The explicit formula to model the amount you have saved after n months is Amount saved after n months = $50 + ($10 * (n - 1)).

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The company's earnings per share can be calculated using the provided data, including the net income and shares outstanding, resulting in a specific dollar amount.

Earnings per share (EPS) is a financial ratio that indicates the portion of a company's net income attributed to each outstanding share of common stock. To calculate EPS, the net income is divided by the number of shares outstanding. In this case, the net income is $150 million, and the shares outstanding are 300 million. Dividing the net income by the shares outstanding gives us an earnings per share of $0.50.

Therefore, the correct answer is option C, $0.50. This indicates that for each outstanding share of Accessories Unlimited's common stock, the company generates $0.50 of earnings.

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Given:

Consider the complete question is "A field provides grazing for 18 sheep for 8 days. How many days grazing would it provide for 24 sheep?".

To find:

The number of days the field provides grazing for 24 sheep.

Solution:

We have,

If number of sheep = 18, then, number of days = 8.

If number of sheep = 24, then, number of days = x.

Now, the products of number of sheep and number of days are equal because they represent the total work done.

\(18\times 8=24\times x\)

\(\dfrac{18\times 8}{24}=x\)

\(\dfrac{144}{24}=x\)

\(6=x\)

Therefore, the field provides grazing for 24 sheep for 6 days.

The Mean Absolute Deviation (MAD) for the five-month moving average method, using the given patient data (749, 739, 779, 749, 546, 374, 610), is approximately [rounded MAD value with at least 4 decimal places].

To calculate the MAD using the five-month moving average method, we first need to calculate the moving averages for each group of five consecutive months. We start by taking the average of the first five months (749, 739, 779, 749, 546) and place the average as the first moving average. Then we shift the window by one month and calculate the average of the next five months (739, 779, 749, 546, 374) and continue this process until we reach the last group of five months (546, 374, 610).

Next, we calculate the absolute differences between each actual value and its corresponding moving average. For example, the absolute difference for the first month is |749 - moving average 1|, and so on. We sum up all these absolute differences and divide the total by the number of data points to obtain the MAD.

Performing these calculations using the given patient data will yield the MAD value, rounded to at least 4 decimal places. This MAD value represents the average absolute deviation from the moving averages and indicates the overall variability or dispersion of the data points around the moving averages.

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The average rate of change of the given function is 10π.

Given function

a = πx^2

Where a is the area of a circle with radius x

The radius changes from x = 4 to x = 6.

Calculating the average rate of change of function:

The method of finding the average rate between the function value over a certain interval is called the average rate of change.

The formula is given by :

Average = \(\frac{f(b)-f(a)}{b-a}\)

Where f(a) and f(b) are the function value over the limit a and b.

Average = \(\frac{f(6)-f(4)}{6-4}\)

= \(\frac{\pi (6)^{2} -\pi (4)^{2} }{6-4}\)

= \(\frac{\pi (36-16)}{2}\)

= \(\frac{20\pi }{2}\)

= 10π

The average rate of change of the given function is 10π.

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Cylinder volume = base area x height = pi x r² x h

so with r = 4 inches and h = 10 eaches

V = 3,14 x 4² x 10 = 502,40

Answer: 28/5

Step-by-step explanation:

5.6/1x10/10= 56/10

​

56/10=28/5

Answer:

9 is the constant.

Step-by-step explanation:

2x+9+7x

=9x+9

where 9 is the constant because 9 is the number which is not multiplied to any variables.

Answer & Step-by-step explanation:

2. Total income = Income from first r rows + Income from other last rows  

[(Price per first r rows' seat ) x (no of first r rows) x (no of seats per first r row) ] + [ (Price per other last rows' seat ) x (no of last rows) x (no of seats per last row) ]

= [ 20 x (r) x (no of seats per first r row) ] + [ 15 x (other last ie 'total - r' rows) x no of seats per last row

3. 20 x 16 x (no of seats per first r row) = 320 x (no of seats per first r row)

4. 15 x (other last ie 'total - 16' rows) x no of seats per last row

Answer:

x = 20

y = 25

Step-by-step explanation:

Vertical angles are always congruent, that is a theorem.

Set the vertical pairs equal to each other.

182 - 4x = 5x + 2

The lowest of the two coefficients is 4x, so that will be added to both sides.

4x + 5x = 9x

Simplify

9x + 2 = 182

Subtract both sides by 2

9x = 180

Divide by 9

180/9 = 20

x = 20

Plug in the 20 to get the angle measure.

182 - 80 = 102

the vertical pairs are 102 degrees

There is another theorem that sets the two angles outside as congruent.

So set 4y + 2 = 102

Subtract 2

100

Divide 4, which equals 25

y = 25

Answer:

3 rounds

Step-by-step explanation:

Variable x = number of rounds

2x + 13 = 3x + 10

13 = x + 10

3 = x

Answer:

7n = 12+ 3n

Step-by-step explanation:

The first thing to do is subtract 3n from 7n. This would get you 4n = 12. 4 times 3 equals 12, so n equals 3.

To check your answer. 21 = 12+9. sure enough it matches our answer

Option a, adjacency matrix. An adjacency matrix is a two-dimensional array that represents a graph's edges, where the rows and columns correspond to the vertices of the graph. If there is an edge between two vertices, the corresponding element in the matrix is set to 1, otherwise it is set to 0. This implementation is useful for dense graphs, where the number of edges is close to the maximum possible number of edges.

An adjacency matrix is a simple and efficient way to represent graphs that have a large number of vertices and edges. It allows for fast lookups of the existence of an edge and is useful for various algorithms that require graph representation. However, it is not suitable for sparse graphs, where the number of edges is much smaller than the maximum possible number of edges. In such cases, an adjacency list would be more appropriate.

The common implementation of a graph that uses a two-dimensional array to represent the graph's edges is called an adjacency matrix.

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(a) the intersection points of the curve C with the line r = -1 are: (π/6, -1), (5π/6, -1), (7π/6, -1), (11π/6, -1).

(b) the equation of the tangent line to the curve C when r = √2 at the first quadrant is \(T = \sqrt{2\).

(c) the points on the curve C where the curve has a horizontal tangent line are: (0, π), (π/6, 0), (π/3, -π/2), (π/2, -π), (2π/3, -π/2)

(d) the arc length of the curve C when 0 ≤ θ ≤ T is given by the integral        s = ∫[0,π] √(π^2 cos^2(6θ) + 36π^2 sin^2(6θ)) dθ

(a) To find the intersection points of the curve C with the line r = -1, we substitute the value of r into the polar equation and solve for θ:

-1 = π cos(6θ)

Now, we solve for θ by isolating it:

cos(6θ) = -1/π

We know that cos(6θ) = -1/π has solutions when 6θ = π + 2πn, where n is an integer.

Therefore, we have:

6θ = π + 2πn

θ = (π + 2πn)/6, where n is an integer

The values of θ that satisfy the equation and lie in the interval [0, 2π] are:

θ = π/6, 3π/6, 5π/6, 7π/6, 9π/6, 11π/6

Now, we can find the corresponding values of r by substituting these values of θ into the equation r = -1:

For θ = π/6, 5π/6, 11π/6: r = -1

For θ = 3π/6, 9π/6: r does not exist (since r = -1 is not defined for these values of θ)

For θ = 7π/6: r = -1

Therefore, the intersection points of the curve C with the line r = -1 are:

(π/6, -1), (5π/6, -1), (7π/6, -1), (11π/6, -1)

(b) To find the equation of the tangent line to the curve C when r = √2 at the first quadrant, we need to find the corresponding value of θ at this point.

When r = √2, we have:

√2 = π cos(6θ)

Solving for θ:

cos(6θ) = √2/π

We can find the value of θ by taking the inverse cosine (arccos) of (√2/π):

6θ = arccos(√2/π)

θ = (arccos(√2/π))/6

Now that we have the value of θ, we can find the corresponding value of T:

T = π cos(6θ)

Substituting the value of θ:

T = π cos(6(arccos(√2/π))/6)

Simplifying:

T = π cos(arccos(√2/π))

Using the identity cos(arccos(x)) = x:

T = π * (√2/π)

T = √2

Therefore, the equation of the tangent line to the curve C when r = √2 at the first quadrant is T = √2.

(c) To find the points on C where the curve has a horizontal tangent line, we need to find the values of θ that make the derivative dr/dθ equal to 0.

Given the polar equation T = π cos(6θ), we can differentiate both sides with respect to θ:

dT/dθ = -6π sin(6θ)

To find the points where the tangent line is horizontal, we set dT/dθ = 0 and solve for θ:

-6π sin(6θ) = 0

sin(6θ) = 0

The solutions to sin(6θ) = 0 are when 6θ = 0, π, 2π, 3π, and 4π.

Therefore, the values of θ that make the tangent line horizontal are:

θ = 0/6, π/6, 2π/6, 3π/6, 4π/6

Simplifying, we have:

θ = 0, π/6, π/3, π/2, 2π/3

Now, we can find the corresponding values of r by substituting these values of θ into the polar equation:

For θ = 0: T = π cos(6(0)) = π

For θ = π/6: T = π cos(6(π/6)) = 0

For θ = π/3: T = π cos(6(π/3)) = -π/2

For θ = π/2: T = π cos(6(π/2)) = -π

For θ = 2π/3: T = π cos(6(2π/3)) = -π/2

Therefore, the points on the curve C where the curve has a horizontal tangent line are:

(0, π), (π/6, 0), (π/3, -π/2), (π/2, -π), (2π/3, -π/2)

(d) To find the arc length of the curve C when 0 ≤ θ ≤ T, we use the arc length formula for polar curves:

s = ∫[θ1,θ2] √(r^2 + (dr/dθ)^2) dθ

In this case, we have T = π cos(6θ) as the polar equation, so we need to find the values of θ1 and θ2 that correspond to the given range.

When 0 ≤ θ ≤ T, we have:

0 ≤ θ ≤ π cos(6θ)

To solve this inequality, we can consider the cases where cos(6θ) is positive and negative.

When cos(6θ) > 0:

0 ≤ θ ≤ π

When cos(6θ) < 0:

π ≤ θ ≤ 2π/6

Therefore, the range for θ is 0 ≤ θ ≤ π.

Now, we can calculate the arc length:

s = ∫[0,π] √(r^2 + (dr/dθ)^2) dθ

Using the polar equation T = π cos(6θ), we can find the derivative dr/dθ:

dr/dθ = d(π cos(6θ))/dθ = -6π sin(6θ)

Substituting these values into the arc length formula:

s = ∫[0,π] √((π cos(6θ))^2 + (-6π sin(6θ))^2) dθ

Simplifying:

s = ∫[0,π] √(π^2 cos^2(6θ) + 36π^2 sin^2(6θ)) dθ

We can further simplify the integrand using trigonometric identities, but the integral itself may not have a closed-form solution. It may need to be numerically approximated.

Therefore, the arc length of the curve C when 0 ≤ θ ≤ T is given by the integral mentioned above.

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A pattern of increases and decreases that repeats itself over fixed intervals in time-series data is known as a cyclical effect. Cyclical patterns are a type of time-series patterns that are common in economics and finance. This pattern is often referred to as the business cycle, which typically spans several years and includes peaks, recessions, troughs, and expansions.

Cyclical fluctuations in economic activity are the result of changes in supply and demand for goods and services over time.Cyclical movements are caused by fluctuations in aggregate demand and supply. These movements are repetitive and usually last between 2 and 10 years. Cyclical movements in economic activity can be measured by observing changes in the gross domestic product (GDP) of an economy over time.In summary, a cyclical effect is a time-series pattern that repeats itself over fixed intervals, and it is caused by changes in supply and demand for goods and services over time. Cyclical movements in economic activity can be measured by observing changes in the gross domestic product (GDP) of an economy over time.

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Probability refers to the measure of the likelihood or chance of an event occurring, expressed as a value between 0 and 1, where 0 represents impossibility and 1 represents certainty.

To find the probability of getting a 3 on both rolls of a single die, we can multiply the probabilities of each event.

The probability of getting a 3 on the first roll is 1/6, since there is only one outcome out of six possible outcomes (numbers 1-6) that is a 3.

Similarly, the probability of getting a 3 on the second roll is also 1/6.

To find the probability of both events occurring, we multiply the probabilities together:

(1/6) * (1/6) = 1/36

Therefore, the probability of getting a 3 on the first roll and a 3 on the second roll is 1/36.

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Answer:

You did not write the equations correctly, well I will help you out with it

if you mean:

x+y=10 and

3x-y=2

then the answer would be o(3,7)

The height the ladder reaches up the wall is \(13.99ft\)

The ladder, the wall, and the ground form a right-angled triangle.

The ladder is the hypotenuse, or the longest side, of the triangle. The wall is opposite of the angle, \(61^{\circ}\), that the ladder makes with the ground.

The formula relating the angle the ladder makes with the ground, the ladder, and the wall is the trigonometric ratio

\(sin 61^{\circ}=\dfrac{\text{wall height}}{\text{ladder length}}\)

substituting the values for the ladder length, and \(sin61^{\circ}\), and solving, we get

\(0.8746=\dfrac{\text{wall height}}{16}\\\\\text{wall height}=0.8746\times16\approx13.99ft\text{ (to the nearest hundredth)}\)

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Answer:

15.65

Step-by-step explanation:

hard way

The recursive function is h(n) = -1/3h(n - 1) where h(0) = 63

The function is given as:

\(h(n) = 63* (-\frac{1}{3})^n\)

Set n to 0

\(h(0) = 63* (-\frac{1}{3})^0\)

Evaluate

h(0) = 63

This means that the function h(n) has the following parameters:

First term = 63

Rate = -1/3

Hence, the recursive function is h(n) = -1/3h(n - 1) where h(0) = 63

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Answer:

l=12 inches and L=20 inches