When you are standing on a scale in a fast elevator that is taking you to the top of a tall building and the elevator slows down as it reaches the top, the apparent weight would decrease as the elevator decelerates.
The weight that you sense is the force with which your body presses on the scale, and this is equal to the gravitational force acting on your body. The gravitational force is constant, but the normal force that the scale exerts on you is not. The scale exerts a normal force on you that equals your weight when the elevator is stationary. When the elevator accelerates, the normal force increases and becomes greater than your weight. When the elevator decelerates, the normal force decreases and becomes less than your weight.
As a result, your apparent weight decreases as the elevator decelerates. An apparent weight is the perceived weight of an object due to the forces acting on it, such as gravity, buoyant force, or air resistance. In this case, the change in apparent weight is due to the change in the normal force acting on the body.
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Una cuerda de longitud 9,8 metros se somete a una tensión de 500N. Si su masa es de 93 kilogramos. La densidad lineal es:
The linear density of the string is 9.49 kg/m.
What is the Linear density?Linear density is commonly used in physics and engineering to analyze the properties and behavior of strings, wires, and cables.
Linear density (ρ) is defined as the mass per unit length of a string or wire. To find the linear density, we can divide the mass of the string by its length. Given that the string has a length (L) of 9.8 meters and a mass (m) of 93 kilograms, we can use the formula:
ρ = m / L
Plugging in the values, we have:
ρ = 93 kg / 9.8 m
Calculating this, we find:
ρ ≈ 9.49 kg/m
the linear density of the string is approximately 9.49 kg/m.
Therefore, that for every meter of the string, there is an average mass of 9.49 kg.
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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
The brakes of a car are applied, causing it to slow down at a rate of 11 ft/s. The car stops at 300 ft 300 ft Determine how fast the car was traveling immediately before the brakes were applied. The speed of the car immediately before the brakes were applied was _____ ft/s.
The speed of the car immediately before the brakes were applied was 81.24 ft/s.
The given data is given below:
Initial speed = ?
Final speed = 0
Acceleration = -11ft/s²
Time = ?
Distance = 300ft
Using the equation of motion, we have:
final velocity² = initial velocity² + 2 × acceleration × distance
Putting the given values in this formula, we get:
0² = v₀² + 2 × (-11ft/s²) × 300ftv₀²
= 6,600ft²/s²v₀
= √6,600ft²/s²v₀
= 81.24ft/s
Therefore, the speed of the car immediately before the brakes were applied was 81.24 ft/s.
When a car's brakes are applied, it begins to slow down. As a result, it is required to find the initial speed of the car. This issue can be solved using an equation of motion.
Initial velocity, final velocity, acceleration, distance, and time are all variables in the equation of motion. We have the final speed, acceleration, and distance in this problem, and we must determine the initial speed.
We'll substitute the given values into the formula and solve for initial velocity. We can write the equation of motion as follows:
final velocity² = initial velocity² + 2 × acceleration × distance
To calculate the initial velocity of the car, we'll use this formula. We can plug in the final speed as 0, since the car came to a complete stop, and we know that the acceleration was 11ft/s² in the opposite direction of the car's motion because the brakes were applied, and the distance was 300 ft. We obtain the value of initial velocity from this formula.
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What’s wrong with this picture ? ..(a group of musicians having a concert on the moon in space
Answer:
Nobody can hear them play.
Explanation:
There is no sound in space.
What’s wrong with this picture is in space it is not possible to hear any sound.
Why is space completely silent?When these waves reach your ears, they are the particles that vibrate in your eardrum for you to hear. So if space is a big vacuum, there are no particles to create sound waves. Therefore, sound cannot propagate if we are floating through the cosmos.
In this way, the irony of the image is given by the musical concert between astronauts that nobody can hear them playing.
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Jupiter takes 9.9259 hours to rotate on its axis and has a tangential speed of 12,293 m/s. What is the radius of Jupiter? 7,781.6 km 19,420 km 48,893 km 69,912 km
The radius of Jupiter is 11.37 × 10^6 km (approx).
The correct answer to the given question is option D.
Jupiter is a giant planet in our solar system and takes 9.9259 hours to rotate on its axis. The tangential speed of Jupiter is given to be 12,293 m/s. We are required to find out the radius of Jupiter.
Given Data:
Rotation period of Jupiter, T = 9.9259 hours
Tangential speed of Jupiter, v = 12,293 m/s
Formula Used:
Radius of Jupiter, r = v × T / (2π)
Calculation:
We can find the radius of Jupiter using the above formula.
Substituting the given values in the formula, we get:
r = 12,293 × 9.9259 × 60 × 60 / (2π)r = 71,492,602.68 / (2π)r = 11,371,641.26 km ≈ 11.37 × 10^6 km.
Therefore, the radius of Jupiter is 11.37 × 10^6 km (approx).
Hence, the correct option is 69,912 km.
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Vanessa is riding a drop ride at a theme park. If Vanessa free falls from rest for 2.60 seconds, how far does she fall? Remember that gravity accelerates her 9.80m/s^
We can use kinematic equations to solve this problem. The distance she fall during the time of 2.60s is 33.123 m.
Here vanessa is under free fall. She is dropped from a certain height and falls for 2.60 s. We can use kinematic equation for distance to solve this.
Δx = v₀t + at²/2
Δx is the distance , in this case the distance she is dropped.
v₀ is the initial velocity
t is the time
a is acceleration, here it is acceleration due to gravity.
v₀ = 0, a=g= 9.8m² , t = 2.60s
Applying the values in equation
Δx = 0×2.60 + 9.8×(2.60)²/2
= 33.124 m
So the distance she fell during 2.60 s is 33.123s
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How is ice more reflective than water??
Answer:
Because it has more texture and is solid. Its like glass
Explanation:
Answer:
Why is ice more reflective (has higher albedo) than liquid water? They're both the same substance (water). Is something quantum mechanical involved?
Explanation:
In fact ice is slightly less reflective than water. The reflectivity is related to the refractive index (in a rather complicated way) and the refractive index of ice is 1.31 while the refractive index of water is 1.33. The slightly lower refractive index of ice will cause a slightly lower reflectivity. In both cases the reflectivity is about 0.05 i.e. at an air/water or air/ice surface about 5% of the light is reflected.
laser light with photon energy 4.7 ev is incident on potassium, which has work function 2.3 ev. what is the maximum kinetic energy of the emitted electrons?
The maximum kinetic energy of the emitted electrons can be calculated using the following formula:
Max Kinetic Energy = Photon Energy - Work Function Plugging in the given values, we get:
Max Kinetic Energy = 4.7 eV - 2.3 eV = 2.4 eV Therefore, the maximum kinetic energy of the emitted electrons is 2.4 eV.
Step 1: Recall the photoelectric effect equation
The equation for the photoelectric effect is given by:
KEmax = E_photon - W
where KEmax is the maximum kinetic energy of the emitted electrons, E_photon is the energy of the incident photon, and W is the work function of the material.
Step 2: Plug in the given values
Now, plug in the given values into the equation:
KEmax = 4.7 eV (photon energy) - 2.3 eV (work function of potassium)
Step 3: Calculate the maximum kinetic energy
Perform the subtraction to find the maximum kinetic energy of the emitted electrons:
KEmax = 2.4 eV
So, the maximum kinetic energy of the emitted electrons is 2.4 eV.
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Which of the following is an example of acceleration?
A boat sits on a boat trailer.
A boat sits on a boat trailer.
A car moves in a straight line at 60 km/hr.
A car moves in a straight line at 60 km/hr.
A plane moves in air at a steady speed of 850 km/hr.
A plane moves in air at a steady speed of 850 km/hr.
A bus moves on a straight road and then makes a right turn.
A bus moves on a straight road and then makes a right turn.
Answer:
i would say a bus because it has to speed up after the turn
Answer:
The bus
Explanation:
when the bus turns it has a change in direction and since velocity is a vector based on speed and direction the velocity is considered changed and since acceleration is a change in velocity the bus is an example of acceleration
I need help. Pls explain fully thanks
When placed at a certain point, a
0.110 C charge feels an electric
force of 19.8 N. What is the
magnitude of the electric field at
that point?
Answer: 180
Explanation: Acellus
This equation gives the magnitude of the electric field generated by a point charge Q. The distance r in the denominator is the separation between the point of interest and the point charge Q. Or the center of a spherical charge.
What magnitude of the electric field at that point?It is simple to determine the size of the electric field by calculating the force per charge on the test charge. From this definition, the common metric units for electric field strength are derived. Electric field units would be force units divided by charge units, as the definition of an electric field is a force per charge.
F = |qvBsin()| calculates the magnetic force's magnitude. The following factors are involved in determining the force's direction. A plane is first defined by the magnetic field vector, B, and the velocity vector, v. In or out of this plane, the magnetic force is perpendicular to it.
Therefore, The electric force F, or Coulomb force, exerted per unit positive electric charge q at that place can be used to determine an electric field's strength, or E = F/q.
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04
Touch-screen phones are made of many different materials.
Figure 3 shows the main materials in a touch-screen phone.
Figure 3
other
15%
iron
20%
plastic
45%
copper
7%
glass
Calculate the percentage by mass of glass in a touch-screen phone. *
1 point
Answer:
Please attach the picture
describe one example of light being refracted in the living room
Answer:
television
Explanation:
a television refracts light (the light bounces off of the screen
Answer:
Suppose you have a glass slab as a paper weight, if you keep it on the paper, dont you see something strange? The paper becomes elevated in the glase slab. Everyone sees a waterbottle or glass everyday, while seeing through it, does everything seem normal? Nope. That's refraction.
Explanation:
You must have seen a prism, right? It makes light split into the visible electromagnetic spectrum.
How is speed calculated? multiply velocity by displacement divide velocity by displacement multiply distance by time divide distance by time
Answer:
\(\huge\boxed{Divide\ distance \ by \ time}\)
Explanation:
Speed = Distance / Time
So, to find distance, we actually divide distance by rime.
Answer:
\(\large \boxed{\mathrm{divide \ distance \ by \ time}}\)
Explanation:
Using the formula to calculate speed:
\(\displaystyle \sf speed =\frac{distance}{time}\)
We divide the distance by the time taken to get the average speed.
What is the ozone * 10 points layer and why it is important? What are the effects of depletion of ozone layer? ( 500 words approx.)
The ozone layer is a region of the Earth's stratosphere that contains a high concentration of ozone (O3) molecules.
It plays a crucial role in protecting life on Earth by absorbing the majority of the Sun's harmful ultraviolet (UV) radiation. The depletion of the ozone layer, primarily caused by human activities, leads to an increase in UV radiation reaching the Earth's surface. This has significant adverse effects on human health, ecosystems, and the environment.
The ozone layer is located in the Earth's stratosphere, approximately 10 to 50 kilometers above the surface. It is formed by the interaction of UV radiation from the Sun with oxygen molecules (O2). The UV radiation breaks apart the oxygen molecules, and the resulting oxygen atoms (O) combine with other oxygen molecules to form ozone (O3).
The ozone layer is essential because it acts as a shield, absorbing the majority of the Sun's UV-B and UV-C radiation, preventing it from reaching the Earth's surface. UV radiation is harmful to living organisms, as it can cause DNA damage, skin cancer, cataracts, and weakened immune systems. The ozone layer's ability to filter out these harmful rays helps protect human health and supports the functioning of ecosystems.
However, human activities have significantly contributed to the depletion of the ozone layer, primarily through the release of certain chemicals known as ozone-depleting substances (ODS), such as chlorofluorocarbons (CFCs) and halons. These substances were commonly used in aerosols, refrigeration, air conditioning, and fire suppression systems. Once released into the atmosphere, ODS molecules can reach the stratosphere and undergo reactions that break down ozone molecules.
The depletion of the ozone layer has several detrimental effects. Increased UV radiation reaching the Earth's surface can lead to an increase in skin cancer cases, cataracts, and other health issues in humans. UV radiation also harms phytoplankton, which are vital for marine ecosystems and the global carbon cycle. Additionally, UV radiation can negatively impact terrestrial and aquatic ecosystems, causing DNA damage, reduced plant growth, disruption of food chains, and harm to coral reefs and other sensitive marine organisms.
Recognizing the importance of protecting the ozone layer, the international community developed the Montreal Protocol in 1987, which aims to phase out the production and use of ODS. Through global efforts to reduce ODS emissions, there has been a gradual recovery of the ozone layer in recent years.
In short , the ozone layer acts as a natural shield, protecting life on Earth from harmful UV radiation. The depletion of the ozone layer due to human activities has severe consequences for human health, ecosystems, and the environment. It is crucial to continue efforts to reduce ozone-depleting substances and preserve the integrity of the ozone layer for the well-being of present and future generations.
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A cargo plane is flying horizontally at an
altitude of 14.7 km with a constant speed of
994 km/hr when a large crate slides out of
the rear of the plane. A conceptual sketch is
shown.
994 km/hr
14.7 km
x
How long does it take the crate to hit
the ground? The acceleration of gravity is
9.81 m/s
2
.
1. 54.7443
2. 47.3562
3. 51.0841
4. 49.4619
5. 48.8397
6. 52.2676
7. 45.3776
8. 53.9944
9. 53.425
10. 50.0764
Answer in units of s
Answer:
1. 54.74433 s
Explanation:
h = Height of plane = 14.7 km
\(u_x\) = Velocity of crate in x direction = 994 km/h = \(276.11\ \text{m/s}\)
a = g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
\(h=u_yt+\dfrac{1}{2}at^2\\\Rightarrow t=\sqrt{\dfrac{2h}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 14700}{9.81}}\\\Rightarrow t=54.74433\ \text{s}\)
Time the crate takes to hit the ground is 54.74433 s
PLEASE HELP
which of the following graphs show the direct relationship between mass and force?
Answer:
Option 2!
Explanation:
According to F = ma, force increases as mass increases. (Assuming acceleration is constant.)
The ball is round on a string at 35° with respect to the vertical. if the length of the string is 12cm. how fast must be the ball is spinning?
Given that T=ma and a= v^2/r, we can solve for the velocity, v = √(Tr/m)
how to solve this problem?To solve this problem, we need to use the concept of centripetal force, which is the force that keeps an object moving in a circular path. The centripetal force is given by the equation:
F = m * a
where F is the centripetal force, m is the mass of the object and a is the centripetal acceleration.
The centripetal acceleration is given by the equation:
a = v^2 / r
where v is the velocity of the object and r is the radius of the circular path.
The radius of the circular path in this case is the length of the string (12cm). The angle of 35° is not needed for solving the problem.
Now we can substitute the value of a into the equation for the centripetal force:
F = m * (v^2 / r)
We know the force is the tension of the string, T, and the mass of the object, m. So we can write
T = m * (v^2 / r)
Given that T=ma and a= v^2/r, we can solve for the velocity, v = √(Tr/m)
Without knowing the mass of the object and the tension of the string we can't find the velocity of the spinning ball.
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A car starts at a position of 4km and moves a final position of 5 km. What is the total distance traveled by the car?
A. 1 km
B.-9 k m
C. 9 km
D. -1 km
Answer:
its c. 9km
Explanation:
Because it you add the 4km+5km that gives you a total of 9km
1) An airplane (m=1500 kg) is traveling at 225 m/s when it strikes a weather balloon (m 34.1 kg at rest. After the collision, the balloon is caught on the fuselage and is traveling with the airplane. What is the velocity of the plane + balloon after the collision (10 points)? The collision takes place over a time interval of 4.44x10 s. What is the average force that the balloon exerts on the airplane (5 points)?
the average force exerted by the balloon on the airplane is F = 0 / (4.44 × 10⁻³) = 0 N.
Let the velocity of the airplane be V0 and the velocity of the balloon after the collision be v
After the collision, the momentum of the airplane + balloon system should be conserved before and after the collision, since there are no external forces acting on the system.
That is,m1v1 + m2v2 = (m1 + m2)V [1]
where m1 = 1500 kg (mass of airplane), v1 = 225 m/s (velocity of airplane), m2 = 34.1 kg (mass of balloon), v2 = 0 (initial velocity of balloon) and V is the velocity of the airplane + balloon system after collision.
On solving the above equation, we get V = (m1v1 + m2v2) / (m1 + m2) = 225(1500) / 1534.1 = 220.6 m/s
Therefore, the velocity of the airplane + balloon after the collision is 220.6 m/s.
The average force exerted by the balloon on the airplane is given by F = ΔP / Δt
where ΔP is the change in momentum and Δt is the time interval of the collision. Here, ΔP = m2v2 (since the momentum of the airplane remains unchanged), which is 0.
The time interval is given as 4.44 × 10⁻³ s. Therefore, the average force exerted by the balloon on the airplane is F = 0 / (4.44 × 10⁻³) = 0 N.
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Which of the following is the chemical formula for an element?
Answer:
A chemical symbol is a one- or two-letter designation of an element. Compounds are combinations of two or more elements. A chemical formula is an expression that shows the elements in a compound and the relative proportions of those elements. Many elements have symbols that derive from the Latin name for the element.
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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If you used a pulley of the type shown in the figure below to support a car engine of mass 135 kg, what would be the tension in the rope? The pulley system's mess is 6.65 kg MA-4 Subm Anawer Tries 0/1
The tension in the rope is 150 N.
The tension in the rope would be 150 N.
What are the given values?
Given,Mass of the engine = 135 kg
Mass of the pulley system = 6.65 kg
Acceleration due to gravity = 9.8 m/s²
Formula to calculate tension,T = m(g + a)
Where,T is the tension in the rope,m is the mass of the engine, and
a is the acceleration of the system.Here, the pulley system is at rest.
So, acceleration of the system is zero. Hence,a = 0
Substituting the given values in the above formula,T = 135 kg × (9.8 m/s² + 0)T = 1323 N
Now, the pulley system multiplies the tension by a factor of two.
Tension in the rope,T = 1323/2 N = 661.5 N= 662 N
Therefore, the tension in the rope is 150 N.
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if the coefficient of static friction is 0.360, and the same ladder makes a 60 degrees angle with respect to the horizontal, how far along the length of the ladder can a 70kg painter climb before the ladder begins to slip?
The painter can climb 5.88 meters before the ladder begins to slip. to find the maximum distance the painter can climb before the ladder begins to slip, we need to use the formula for static friction:
F_friction = coefficient of static friction x F_normal. In this case, the normal force is equal to the weight of the painter, which is F_normal = m x g = 70 kg x 9.81 m/s^2 = 686.7 N.
The maximum force of static friction is F_friction = coefficient of static friction x F_normal = 0.360 x 686.7 N = 247.8 N.
Now, we can use trigonometry to find the distance along the ladder where the maximum force of static friction is reached. The component of the weight of the painter parallel to the ladder is F_parallel = F_normal x sin(theta) = 686.7 N x sin(60 degrees) = 595.5 N.
The maximum distance the painter can climb before the ladder begins to slip is d = F_parallel / F_friction = 595.5 N / 247.8 N = 2.405. However, this is only the distance along the ladder that the painter has climbed. To find the total distance, we need to multiply by the length of the ladder: 2.405 x 2.44 m = 5.88 m. Therefore, the painter can climb 5.88 meters before the ladder begins to slip.
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by how many millimeters does the icicle shrink if a bitterly cold wind drops the temperature to -26 ∘c∘c ?
An icicle shrinks in size when the temperature drops because the water molecules within the icicle lose energy and move closer together, causing the icicle to contract. To determine the amount by which the icicle shrinks at a temperature of -26°C, we need to consider the thermal expansion coefficient of ice.
The thermal expansion coefficient of ice is approximately 51 x 10^(-6) per degree Celsius. This means that for every degree Celsius decrease in temperature, ice contracts by 51 x 10^(-6) of its original size.
If we assume that the icicle is made entirely of ice and has an initial length of L millimeters, the contraction in millimeters can be calculated using the following formula:
Contraction = L * (T2 - T1) * α
Where:
L is the initial length of the icicle,
T1 is the initial temperature (assumed to be 0°C),
T2 is the final temperature (-26°C),
α is the thermal expansion coefficient of ice.
Plugging in the values, we have:
Contraction = L * (-26) * 51 x 10^(-6)
Simplifying the equation, we get:
Contraction = -1.326 L
Therefore, the icicle would shrink by approximately 1.326 times its original length at a temperature of -26°C.
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The resistance to change the state of motion depends on the ___ of an object.
A. Size
B. temperature
C. volume
D. mass
NH3 → N2 + H2 Balance and classify it
Answer:
2NH3 --> N2 + 3H2 decomposition
Given the following acceleration function of an object moving along a line, find the position function with the given initial velocity and position. a(t)=−38;v(0)=24,s(0)=0
The position function of an object moving along a line can be determined by integrating the given acceleration function. With the given initial velocity of 24 and initial position of 0, the position function is s(t) = \(-19t^{2}\) + 24t.
To find the position function (s(t)) of the object, we integrate the given acceleration function (a(t)) with respect to time (t). Since the acceleration is a constant value of -38, the integral simplifies to:
v(t) = ∫a(t) dt = -38t + C,
where C is the constant of integration.
Given the initial velocity v(0) = 24, we substitute this value into the equation:
24 = -38(0) + C,
C = 24.
Now, we have the velocity function:
v(t) = -38t + 24.
To find the position function, we integrate the velocity function:
s(t) = ∫v(t) dt = ∫(-38t + 24) dt = \(-19t^{2}\) + 24t + D,
where D is the constant of integration.
Given the initial position s(0) = 0, we substitute this value into the equation:
0 = \(-19(0)^{2}\) + 24(0) + D,
D = 0.
Therefore, the position function is:
s(t) = \(-19t^{2}\) + 24t.
This equation represents the position of the object as a function of time, given the initial velocity of 24 and initial position of 0.
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HELPPP PLEASE I GIVE BRAINLIST
handles on kitchen stove pots are usually made of wood mainly because of ?
A ) Conduction
B ) Convection
C ) Radiation
D ) Condensation
Answer:
(B) Conduction
Explanation:
Answer:
a ) conduction
Explanation:
it's a because if u think about it a conductor keeps the heat from getting to a certain part of the metal
numeria
problems
lifted
Joy
1
لوووو
G. Solue the
following
A load
800 Nis
effort
If
the load is
laced at
a distance
Lo cun from
achat will be the
effort distance ?
Solher load ( l = 8oon
Effort
(e) = 200N
the fularum,
Answer:
\( \boxed{40 \: cm}\)Explanation:
Load ( L ) = 800 N
Effort ( E ) = 200 N
Load distance ( LD ) = 10 cm
Effort distance ( ED ) = ?
now, Let's find the effort distance:
\( \mathsf{L \times LD = E \times ED}\)
Plug the values
\( \mathsf{800 \times 10 = 200 \times ED}\)
Multiply the numbers
\( \mathsf{8000 = 200 \: ED}\)
Swipe the sides of the equation
\( \mathsf{200 \: ED = 8000}\)
Divide both sides of the equation by 200
\( \mathsf{ \frac{200 \: ED }{200} = \frac{8000}{200} }\)
Calculate
\( \mathsf{ED \: = \: 40 \: cm}\)
Hope I helped!
Best regards!