Write the balanced molecular and net ionic equation for the reaction that occurs when the contents of the two beakers are added together. (Use the lowest possible whole number coefficients. Include states-of-matter under SATP conditions in your answer.) (a) Cu2+ so Nat os? © (i) molecular equation chemPad Help X.X° = Greek (ii) net ionic equation chemPad X.X°C

White vinegar typically consists of 93%–96% water and 4–7% acetic acid. It can be used to cooking, bake, cleaning, and get rid of weeds. It can also help you lose weight and lower your blood sugar and cholesterol. Consumption is safe in moderation, but excessive consumption or when combined with certain medications could be harmful.

Apple cider vinegar is widely used in cooking and as a salad dressing because it contains acetic acid and nutrients like vitamins C and B vitamins. But at the same time, it's been utilized customarily as medication. It helps in losing weight.

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It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).

KH2PO4 is actually potassium dihydrogen phosphate, not potassium phosphate monobasic. Potassium phosphate monobasic, or monopotassium phosphate, is correctly represented by the chemical formula KH2PO4. It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).

On the other hand, potassium dihydrogen phosphate, or K2HPO4, is a different compound. It is formed from the potassium cation (K+) and the hydrogen phosphate anion (HPO4^2-). This compound is considered dibasic because it contains two replaceable hydrogen ions (H+).

Therefore, KH2PO4 is correctly identified as potassium phosphate monobasic, while K2HPO4 is potassium dihydrogen phosphate.

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Comparing the rate law based on the mechanism with the observed rate law, Yes the proposed mechanism is consistent with the observed rate law for the overall reaction.

Is the proposed mechanism consistent with the observed rate law for the given reaction?

The overall reaction can be written as:

2NO₂ -> 2NO + O₂ (overall reaction)

The mechanism proposed has two elementary steps:

Step 1: NO₂ + NO₂ → N₂O₄ (fast)

Step 2: N₂O₄ → 2NO + O₂ (slow)

The total reaction rate law is expressed as follows:

Rate = k[NO₂]²

where k is the slow step's rate constant.

To determine if the mechanism is consistent with the observed rate law, we need to calculate the rate law based on the mechanism and compare it with the observed rate law.

Step 1 is fast and in equilibrium. We can assume that the concentration of N2₂O₄ is constant and write an expression for the equilibrium concentration:

Kc = [N₂O₄]/([NO₂]²)

where Kc is the equilibrium constant.

Using the equilibrium expression and the law of mass action, we can write the rate law for step 2 as:

Rate = k'[N₂O₄]

where k' = k/Kc.

Substituting the equilibrium expression for [N2O4] in terms of [NO2] into the rate law for step 2, we get:

Rate = k'[N₂O₄] = k'[Kc][NO₂]²

Simplifying the expression, we get:

Rate = k[NO₂]²

Comparing the rate law based on the mechanism with the observed rate law, we see that they are the same. Therefore, the mechanism is consistent with the observed rate law.

In conclusion, the proposed mechanism is consistent with the observed rate law for the overall reaction.

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The number of moles of lead iodide formed is 0.000275 moles

The equation of the reaction is as follows:

MI₂ (aq) + Pb(NO₃)₂ (aq) ----> M(NO₃)₂ (aq) + PbI₂ (s)

The number of moles of MI₂ that reacted is 0.000275 moles

The group 2 metal is Calcium whose molar mass is 40.0 g

a. From the given values:

Mass of lead iodide precipitated = 0.1270 g

molar mass of lead iodide = 461 g/mol

number of moles = mass / molar mass

number of moles of lead iodide formed = 0.1270 g / 461 g /mol

number of moles of lead iodide formed = 0.000275 moles

b. The equation of the reaction shows the reactants as well as the products formed after reaction.

The general molecular equation is given as :

MI₂ (aq) + Pb(NO₃)₂ (aq) ----> M(NO₃)₂ (aq) + PbI₂ (s)

The net ionic equation is given as:

Pb²⁺ (aq) + 2 I⁻ (aq) ---> PbI₂ (s)

c. 1 mole of MI₂ reacts with 1 mole of Pb(NO₃)₂ to produce 1 mole of M(NO₃)₂ and 1 mole PbI₂

Since 0.000275 moles of PbI₂ was formed, it would require 0.000275 moles MI₂ to be formed.

Number of moles of MI₂ that reacted = 0.000275 moles

d. Mass of 0.000275 moles of MI₂ = 0.0810 g

mass of 1 mole of MI₂ = 0.0810 / 0.000275 =294.5 g

In 294.5 g of MI₂, mass composition of Iodide = 127 * 2 = 254 g

Therefore mass of the metal = mass of compound - mass of iodine in the compound

mass of metal, M = 294.5 - 254 = 40.5 g

The group 2 metal is Calcium whose molar mass is 40.0 g

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The electron configurations that are not valid among the options are 1s²2s²2p 3s 3p 4s²4d¹04p5 and 1s²2s²2p 3s³3d5. Options 1 and 2.

The electron configuration of atoms using the various orbital levels follows the order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.

Also, according to Afbau principle, orbitals with low energy levels are filled with electrons before orbitals with higher energy levels.

Using the above,  1s²2s²2p 3s 3p 4s²4d¹04p5 is incorrect for some reasons:

1s²2s²2p 3s³3d5 is incorrect because:

The remaining electron configurations are correct with correctly placed electrons in the various orbitals.

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When 3-methylcyclopentanone is reacted with Tollens' reagent, it undergoes oxidation to form a carboxylate anion.

Here's the structural formula for the major organic anion formed:

\(O^- O=C(CH_3)CH_2CH_2CH_2^-\)

| |

\(H_3C---C---CH_2CH_2CH_2CH_3 + Ag(NH_3)^{2+} + OH^-\) → \(Ag(s) + H_2O + O=C(CH_3)CH_2CH_2CH_2^-\)

A Tollens' test, also known as a silver-mirror test, is a chemical test used to determine whether a carbonyl compound is present in a given sample. When a carbonyl compound is combined with a silver ammonia complex, it reduces the silver cation to metallic silver, forming a silver mirror on the surface of the container.

If no reaction occurs, the organic starting material, 3-methylcyclopentanone, would simply be:

O

|| \(CH_3\)

\(C---C---CH_2CH_2CH_2CH_3\)

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The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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Answer:

9.98%

Explanation:

To find the percent of NaCl in the mixture, we need to divide the mass of NaCl by the total mass of the mixture, and then multiply by 100 to express it as a percentage.

Step 1: Find the total mass of the mixture

total mass = mass of NaCl + mass of water

total mass = 23.5 g + 212 g

total mass = 235.5 g

Step 2: Calculate the percent of NaCl

% NaCl = (mass of NaCl / total mass) x 100

% NaCl = (23.5 g / 235.5 g) x 100

% NaCl = 0.0997876857 x 100

% NaCl = 9.978768677%

% NaCl = 9.98%

Therefore, the percent of NaCl in the mixture is 9.98%.

Answer:

the final state of the hydrogen atom = 3

Explanation:

From the given information;

Let first calculate the amount of energy by the ground state atom during the atoms absorbs  photon light  by using the formula:

\(E_{absorbs} = \dfrac{hc}{\lambda}\)

where;

h = planck's constant = \(6.626*10^{-34 }\ \ Js\)

c = speed of light = \(3.0*10^8 \ \ m/s\)

λ = wavelength = 92.57 nm = 92.57 × 10⁻⁹ m

\(E_{absorbs} = \dfrac{6.626*10^{-34 }\ \ Js * 3.0*10^8 \ \ m/s}{92.57*10^{-9} \ \ m}\)

\(E_{absorbs} = 2.15 *10^{-18} \ J\)

The energy emitted by the hydrogen atom is calculated by using the same formula from above ; but here , the wavelength λ = 954.3 nm = 954.3 × 10⁻⁹ m

\(E_{absorbs} = \dfrac{6.626*10^{-34 }\ \ Js * 3.0*10^8 \ \ m/s}{954.3*10^{-9} \ \ m}\)

\(E_{absorbs} = 2.08 *10^{-19} \ J\)

The change in the energy absorbed is:

\(\Delta E= 2.15 *10^{-18} \ J - 2.08 *10^{-19} \ J\)

\(\Delta E= 1.94 *10^{-18} \ J\)

The final state of the atom can be determined by using the relation:

\(\Delta E = R_H [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}]\)

where;

\(R_H\) = Rydberg constant = 2.18 × 10⁻¹⁸ J

\(\dfrac{\Delta E}{R_H} = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ \dfrac{1.94*10^{-18} \ J}{2.18*10^{-18} \ J } = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ 0.889 = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ 1 - 0.889 = \dfrac{1}{n^2_f} \\ \\ \\ 0.111= \dfrac{1}{n^2_f} \\ \\ \\ {n^2_f} = \dfrac{1}{0.111} \\ \\ \\ {n^2_f} = 9 \\ \\ \\ {n_f} = \sqrt{9} \\ \\ \\ \mathbf{n_f = 3}\)

Thus; the final state of the hydrogen atom = 3

\(E_a_b_s_o_r_b_e_d = (6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (92.57 *10^-^9 m)\)We can use the fact that the energy of the photon is given by the equation: to determine the final position of the hydrogen atom.

E = hc / λ

Where:

E is the energy of the photon,

h is Planck's constant \((6.626 * 10^-^3^4 J.s)\),

c is the speed of light in a vacuum \((3.00 * 10^8 m/s)\), and

λ is the wavelength of the photon.

Let's first determine the energy of the absorbed photon:

\(E_a_b_s_o_r_b_e_d = hc /\)λ\(_a_b_s_o_r_b_e_d\)

\(E_a_b_s_o_r_b_e_d = (6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (92.57 *10^-^9 m)\)

The energy of the photon released will then be determined by:

\(E_e_m_i_t_t_e_d = hc\) / λ\(_e_m_i_t_t_e_d\)

E\(_e_m_i_t_t_e_d\) = \((6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (945.3 *10^-^9 m)\)

The energy difference between the absorbed and released photons must now be determined:

ΔE = \(E_e_m_i_t_t_e_d - E_a_b_s_o_r_b_e_d\)

The energy levels of hydrogen are given by the equation:

ΔE = -13.6 eV *\((1 / n^2_f_i_n_a_l - 1 / n^2_i_n_i_t_i_a_l)\)

Where

\(n_f_i_n_a_l\) and \(n_i_n_i_t_i_a_l\) are the principal quantum numbers of the final and initial states, respectively, and -13.6 eV is the ionization energy of hydrogen.

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Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

Answer:

1. Both

2. Phosphorylation

3. Both

4. Phosphorylation

5. Oxidative.

6. Both

Explanation:

Phosphorylation only occurs in chloroplast and it involves larger electrical component. Both Phosphorylation and oxidative occurs in mitochondria and it involves proton gradient. They occur in plants to produce ATP. Oxidative involves in smaller electrical component.

Photophosphorylation is a process that captures the solar energy from the sun to transform it into chemical energy. It occurs in the chloroplast of a plant cell.

Photophosphorylation is a process of converting solar energy from the sun to ATP needed by plants and other organisms for cellular function and activity. This process takes place in the chloroplast of the plant cell and requires electrical components.

Oxidative Phosphorylation is the process of producing ATP with the help of oxygen and enzymes hence, occurs in aerobic cells. It does not need a larger electrical component.

Both phosphorylation and oxidative phosphorylation occurs in the mitochondria of plants cells and involves a proton gradient for the formation of ATP.

Therefore, oxidative phosphorylation option 5. involves a smaller electrical component, phosphorylation option 2. occurs in the chloroplast, and option 4. needs a larger electrical component.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

A

Explanation:

A option is correct .

you cannot create energy neither you can destroy it but you can only convert into other form

Answer:

whats CH3COOH please tell me so I can answer!

Answer:

\(N^{4+}O_2+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+H_2O\)

Explanation:

Hello,

In this case, for the given reaction, we first start by the writing of the oxidation states of all the involved elements:

\(Bi^{3+}(OH)^-+N^{4+}O^{2-}_2\rightarrow Bi^0+(N^{5+}O^{2-}_3)^-\)

In such a way, we are noticing nitrogen is undergoing an increase in its oxidation state, therefore it is being the oxidized species, for which the oxidation half reaction, should be (considering basic conditions):

\(N^{4+}O_2+H_2O+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+2H^++2OH^-\\\\N^{4+}O_2+H_2O+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+2H_2O\\\\N^{4+}O_2+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+H_2O\)

Best regards.

Answer:

\(5.412*10^{23}\)

Explanation:

We can find the moles of lithium by doing 0.0624 divided by the molar mass of lithium (which is 6.941). Then, we can multiply that number by 6.02*10^23 which is the avogadro number. Then, we get our answer.

Answer:

water

Explanation:

Answer:

Collision theory states that the rate of a chemical reaction is proportional to the number of collisions between reactant molecules. The more often reactant molecules collide, the more often they react with one another, and the faster the reaction rate.

(a) the molecular formula of the compound is C₆H₁₂.

(b)  the molecular formula of the compound is NH₂Cl.

(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.

The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6

Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:

CH₂ × 6 = C₆H₁₂

Thus, the molecular formula of the compound is C₆H₁₂.

(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.

The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1

Therefore, the molecular formula is the same as the empirical formula: NH₂Cl

Hence, the molecular formula of the compound is NH₂Cl.

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The temperature of the gas is 0.49 K.

An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.

Volume is a degree of occupied three-dimensional space. it's far more frequently quantified numerically the usage of SI-derived gadgets or by way of diverse imperial gadgets. The definition of length is interrelated with the extent.

An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect at the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable

Using the ideal gas equation:-

Given;

P₁ = 387 torr = 0.509211 atm

V₁ =  2 L

mole n = 0.25 mol

T = ?

R = 8.314

PV = nRT

T = PV /nR

   = 0.509211 × 2 / 0.25 × 8.314

   = 0.49 K

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Answer:

1.2 L

Explanation:

Step 1: Write the balanced equation

Mg + 2 HCl ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 2.3 g of Mg

The molar mass of Mg is 24.31 g/mol.

2.3 g × 1 mol/24.31 g = 0.095 mol

Step 3: Calculate the moles of H₂ produced

0.095 mol Mg × 1 mol H₂/1 mol Mg = 0.095 mol H₂

Step 4: Calculate the volume occupied by the hydrogen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 0.095 mol × (0.0821 atm.L/mol.K) × 298 K/2 atm = 1.2 L

The concentration of Oxalic Acid is 0.2625 M.

A kinetic experiment is conducted to determine the rate law of a reaction. The concentration of Oxalic Acid can be calculated using the given amount of the reactants and the volume of the test tube. A balanced chemical equation can be used to find the stoichiometric ratio of the reactants in the given reaction.The balanced chemical equation for the reaction is:5 H2C2O4 + 2 KMnO4 + 3 H2SO4 → 10 CO2 + 2 MnSO4 + 8 H2OThe stoichiometric ratio between Oxalic Acid and Potassium Permanganate is 5:2. The Oxalic Acid is the limiting reactant, and Potassium Permanganate is in excess.The amount of Oxalic Acid in the solution can be calculated using the formula:molarity = moles of solute / volume of solution in L.The moles of Oxalic Acid can be calculated using the formula:moles of H2C2O4 = Molarity of H2C2O4 x Volume of H2C2O4 in L= 0.525 M x 0.006 L= 0.00315 moles.

The volume of the solution after the addition of the reactants is:6.00 mL of 0.525 M Oxalic Acid + 4.00 mL of distilled water + 2.00 mL of 0.200 M KMnO4= 12.00 mLThe concentration of Oxalic Acid in the solution can be calculated using the formula:Molarity of H2C2O4 = moles of H2C2O4 / volume of solution in L= 0.00315 moles / 0.012 L= 0.2625 M.

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Answer: To solve this problem, you can use the first-order rate equation, which is given by:

[reactant] = [reactant]0 * e^(-k*t)

where [reactant] is the concentration of the reactant at time t, [reactant]0 is the initial concentration of the reactant, k is the rate constant, and t is the time.

Plugging in the given values, we get:

[reactant] = 1.304 M * e^(-4.10 x 10^-3 M s^-1 * 90.45 s)

= 1.304 M * e^(-0.0366)

= 1.304 M * 0.933

= 1.21 M

To express the answer with 3 significant figures, you can round the answer to 1.21 M. Therefore, the concentration of the reactant after 90.45 seconds is 0.933 ± 1%.

Answer:

Bohr's model of hydrogen atom

I hope this answer is correct

Answer:

Bohr's

Explanation:

An increased temperature generally causes a reaction to occur faster rather than slower. Therefore option C is correct.

The increased temperature leads to a higher average kinetic energy of the molecules, which results in more frequent and energetic collisions between the reactant particles.

This increased collision frequency and energy facilitate the breaking of chemical bonds and the formation of new bonds, leading to an accelerated reaction rate.

When the temperature is raised, the kinetic energy of the molecules increases. This means that the individual molecules move faster and possess a greater amount of energy. As a result, the molecules collide more frequently and with higher energy, enhancing the likelihood of successful collisions that lead to a reaction.

In summary, an increased temperature leads to a faster reaction rate by increasing the average kinetic energy of the particles, causing more frequent and energetic collisions.

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Answer:

1. Energy intensity (primary energy consumption divided by GDP) for the world and various countries. The lower the value, the less energy is used to generate economic output, so lower means more efficient in a sense.

2.Lower Your Thermostat. Adopt the habit of lowering the temperature on your thermostat while away from home.

Start a Compost Pile.

Install Low-Flow Showerheads.

Seal All Windows.

Limit Space Heater Use.

Turn Off Unnecessary Water.

Replace Incandescent Bulbs.

Unplug Unused Chargers.