Write at least four more addition or multiplication equations for 2 in which all
the fractions have a denominator of 8.

Answer:

803.84yd²

Step-by-step explanation:

Surface Area of A Sphere: \(A=4\pi r^2\)

We are given the radius of 8 yards.

Using 3.14 for pi:

\(A=4*3.14*8^2\\\\A=4*3.14*64\\\\A=12.56*64\\\\\boxed{A=803.84}\)

The correct answer should be 803.84yd².

Brainilest Appreciated.

Answer:

803.84 yd^2

Step-by-step explanation:

4*3.14*8^2

12.56*64

803.84

brainliest pls

hope i helped

           -ZYLYNN

The distance, relative to mile marker 45, to the nearest mile when passing mile marker 112 on a straight highway is 67 miles.

When you pass mile marker 112 on a perfectly straight highway between marker 45 and marker 112, the distance covered is 112 - 45 = 67 miles. This means that you have traveled a total of 67 miles from mile marker 45 to mile marker 112.

To determine the distance relative to mile marker 45, we consider the distance remaining from mile marker 112.

Since you have passed mile marker 112, the remaining distance to cover until you reach the nearest mile relative to marker 45 is the difference between 112 and the nearest mile greater than 112.

Let's assume the nearest mile greater than 112 is 113.

Therefore, the remaining distance is 113 - 112 = 1 mile.

In conclusion, when passing mile marker 112 on the straight highway, the distance relative to mile marker 45 to the nearest mile is 67 miles.

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Answer: p = 4

Step-by-step explanation:

For app one, you start with 140 points, and you lose 10 each time you check your phone.

Then, if you check your phone x times, you will have:

140 - x*10 points in total.

For app two, you start with 80 points, and you lose p points each time you check your phone.

Then, if you check your phone x times, you will have:

80 - x*p points left

We know that when x = 10, you have the same number of points in both apps, then we have the equation:

140 - (10)*10 = 80 - (10)*p

We can solve this for p

140 - 10*10 = 80 - 10*p

140 - 100 = 80 - 10*p

40 = 80 - 10*p

10*p = 80 - 40

10*p = 40

p = 40/10 = 4

The volume of the right prism is equal to 1617 cubic meters.

In this problem we find the case of a right prism, whose volume is defined by the following formula:

V = A · h

V = 0.5 · b · l · h

Where:

If we know that b = 14 m, l = 10.5 m and h = 11 m, then the volume of the right prism is:

V = 0.5 · (14 m) · (10.5 m) · (11 m)

V = 1617 m³

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The number of ways to place 40 identical balls in 4 distinct boxes, with each box getting at least 2 balls and no box getting 18 or more balls, is 6,125.

1. Start by placing 2 balls in each of the 4 boxes, leaving 32 balls to distribute.

2. Since no box can have 18 or more balls, the maximum number of balls in a box is 17. Adjust the problem to consider distributing 32 balls without restrictions.

3. Use the stars and bars method to find the number of ways to distribute the 32 balls. There are 32 stars (balls) and 3 bars (dividing the boxes), resulting in 34! / (32! * 3!) combinations.

4. Now, subtract the number of ways where any box has 18 or more balls. For this, we need to consider cases where at least one box gets an additional 18 balls.

5. Calculate the combinations for each case (3 cases) and subtract them from the total combinations.

6. The result is 6,125 different ways to place the balls according to the given conditions.

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a) It may be possible to add additional constraints to the Reddy Mikks problem to obtain the solution (1,3), but it depends on the specific constraints and the nature of the problem. Further justification is required.

b) To compute the shadow prices in the Jobco problem, we need to replace the right-hand side (rhs) with random numbers and analyze the impact on the objective function.

a) The Reddy Mikks problem involves finding the optimal combination of ingredients to produce a desired mixture. If the given solution (1,3) is not feasible with the current constraints, additional constraints could be added to restrict the feasible region and potentially achieve the desired solution. However, without specific information about the constraints and the problem's requirements, it is difficult to determine the feasibility of achieving the solution (1,3). Further analysis and justification are needed based on the specific constraints and problem context.

b) In linear programming, shadow prices represent the rate of change in the objective function value with respect to changes in the right-hand side (rhs) of the constraints. To compute the shadow prices, the rhs values are replaced with random numbers, and the resulting changes in the objective function are observed. By calculating the differences in the objective function values before and after the rhs replacement, we can determine the shadow prices associated with each constraint.

This approach helps evaluate the sensitivity of the objective function to changes in the rhs values and provides insight into the importance of each constraint in the optimization problem.

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Statistics computed for larger random samples tend to be less variable compared to statistics computed for smaller random samples.

This statement is based on the concept of the Central Limit Theorem (CLT) in statistics. According to the CLT, as the sample size increases, the distribution of the sample mean approaches a normal distribution regardless of the shape of the population distribution. This means that the variability of the sample mean decreases as the sample size increases.

The variability of a statistic is commonly measured by its standard deviation or variance. When working with larger random samples, the individual observations have less impact on the overall variability of the statistic. As more data points are included in the sample, the effects of outliers or extreme values tend to diminish, resulting in a more stable and less variable estimate.

In practical terms, this implies that estimates or conclusions based on larger random samples are generally considered more reliable and accurate. Researchers and statisticians often strive to obtain larger sample sizes to reduce the variability of their results and increase the precision of their statistical inferences.

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Company A has a higher risk percentage (55%) compared to Company B (3%).

To compute the Coefficient of Variation (CV) for each company, we need to use the formula:

CV = (Standard Deviation / Mean) * 100

Let's calculate the CV for each company:

For Company A:

Risk Percentage = 55%

Return = 14%

For Company B:

Risk Percentage = 3%

Return = 14%

Since we don't have the standard deviation values for each company, we cannot calculate the exact CV. However, we can still compare the riskiness of the two companies based on the provided information.

The Coefficient of Variation measures the risk relative to the return. A higher CV indicates higher risk relative to the return, while a lower CV indicates lower risk relative to the return.

In this case, Company A has a higher risk percentage (55%) compared to Company B (3%), which suggests that Company A is riskier. However, without the standard deviation values, we cannot make a definitive conclusion about the riskiness based solely on the provided information. The CV would provide a more accurate measure for comparison if we had the standard deviation values for both companies.

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Answer:

A. minimum value = 1; maximum value = 6

Step-by-step explanation:

Correct on Edge 2021

\((x - a)(x - b)\)

Step-By-Step Explanations:

1) Factor out the common term in the first two terms, then in the last two terms.

\(x(x - a) - b(x - a)\)

2) Factor out the common term x - a.

\((x - a)(x - b)\)

Therefor, the answer is ( x - a ) ( x - b ).

a. In practical terms, this slope means that for every additional American dollar (D) the tourist exchanges, she will receive approximately 0.4857 British pounds (P) in return.

b. The tourist would receive approximately 63.01 British pounds.

c. The tourist would receive approximately 5.98 American dollars.

a. To calculate the rate of change or slope of P with respect to D, we need to use the information given. We know that the tourist exchanged 70 American dollars for 34 British pounds. Since we can assume no service charge, this exchange rate represents the slope of the linear function.

The slope (rate of change) of P with respect to D can be calculated as:

slope = (change in P) / (change in D) = (34 - 0) / (70 - 0) = 34 / 70 ≈ 0.4857

In practical terms, this slope means that for every additional American dollar (D) the tourist exchanges, she will receive approximately 0.4857 British pounds (P) in return. It represents the conversion rate between the two currencies.

b. Using the exchange rate obtained in part a, we can calculate how many pounds the tourist would receive for 130 American dollars. The calculation is as follows:

Amount in pounds = exchange rate * number of American dollars

Amount in pounds = 0.4857 * 130 = 63.01

Therefore, the tourist would receive approximately 63.01 British pounds.

c. The tourist had £12.32 in British currency and wants to exchange it back to American dollars. To determine the amount in American dollars, we need to use the exchange rate obtained in part a. The calculation is as follows:

Amount in American dollars = exchange rate * amount in pounds

Amount in American dollars = 0.4857 * 12.32 ≈ 5.98

Therefore, the tourist would receive approximately 5.98 American dollars.

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Answer:

$48

Step-by-step explanation:

The friends have the bus from 5:00 PM to 3:00 AM, so:

3 + 18 − 5 = 15 − 5 = 10 hours.

The cost of renting the bus will be:

$300 + $18 × 10 = $300 + $180 = $480.

The thirty-six students will contribute $12 each for a total of:

$12 × 36 = $432.

So Mr. Jones will pay:

$480 − $432 = $48.

Hope this helped :)

Answer:

± \(\frac{1}{7}\)

Step-by-step explanation:

Using the rules of exponents

\(a^{-m}\) = \(\frac{1}{a^{m} }\) , \(a^{\frac{1}{2} }\) = \(\sqrt{a}\) , then

\(49^{-\frac{1}{2} }\) = \(\frac{1}{49^{\frac{1}{2} } }\) = \(\frac{1}{\sqrt{49} }\) = ± \(\frac{1}{7}\)

The value of the given condition is 1/7 or 0.142.

Simply put, to simplify is to make something simpler. Simplifying an equation, fraction, or issue in mathematics entails taking something complex and making it simpler. The issue is made simpler by calculations and problem-solving strategies. We can simplify fractions by removing all common elements from the numerator and denominator and putting the fraction in its simplest/lowest form.

Given value  \((49^{\frac{-1}{2} } )\)

factors of  49 = 7 x 7

49 = 7²

substitute value of 49

\(7^{2}( ^{\frac{-1}{2} } )\)

using  property (mⁿ)ᵃ = mᵃⁿ

\(7^{2}( ^{\frac{-1}{2} } )\) = \(7^{-1}\)

and \(7^{-1}\) = 1/7 = 0.142

Hence the measure of value is 1/7 or 0.142

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Answer: 1000 ms

Step-by-step explanation: mere guess

One second is made up of 1000 milliseconds.

Multiplication is a way of calculating the product of two or more integers in mathematics. It is one of the most fundamental mathematical operations that we utilize every day. In mathematics, multiplying implies adding equal groups. The number of items in the group grows as we multiply. A multiplication issue includes the two elements and the product. In the multiplication issue, 6 9 = 54, the numbers 6 and 9 are factors, and 54 is the result. In elementary algebra, multiplication is the act of computing the outcome when a number is multiplied by itself many times. The product of and is the outcome of a multiplication, and each of the integers and is known as a factor of the product.

Here,

1 second = 1000 milliseconds

There are 1000 milliseconds in one second.

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No two values of x in the computation we just did are equal, there are 4 different values of x for which the sequence contains the value 2001.

An ordered list of numbers is all that a sequence is. Number series are collections of numbers that adhere to a pattern or guideline. An arithmetic sequence is one where the rule is to add or take away a number each time.

To estimate a few terms of the sequence in order to obtain a feel how it looks like.

In our case, the definition is that \($\forall$\) (for all) \($n > 1: a_n=a_{n-1} a_{n+1}-1$\).

This can be rewritten as \($a_{n+1}=\frac{a_n+1}{a_{n-1}}$\).

We have \($a_1=x$\) and \($a_2=2000$\), and we estimate:

\($& a_3=\frac{a_2+1}{a_1}=\frac{2001}{x} \\\)

\($& a_4=\frac{a_3+1}{a_2}=\frac{\frac{2001}{x}+1}{2000}=\frac{2001+x}{2000 x} \\\)

\($& a_5=\frac{a_4+1}{a_3}=\frac{\frac{2001+x}{2000 x}+1}{\frac{2001}{x}}=\frac{\frac{2001+2001 x}{2000 x}}{\frac{2001}{x}}=\frac{1+x}{2000} \\\)

\($& a_6=\frac{a_5+1}{a_4}=\frac{\frac{1+x}{2000}+1}{\frac{2001+x}{2000 x}}=\frac{\frac{2001+x}{2000}}{\frac{2001+x}{2000 x}}=x \\\)

\($& a_7=\frac{a_6+1}{a_5}=\frac{x+1}{\frac{1+x}{2000}}=2000\)

At this point we see that the sequence will become periodic: we contain \($a_6=a_1, a_7=a_2$\), and each subsequent term exists uniquely determined by the previous two.

Hence 2001 appears, it contains to be one of \($a_1$\) to \($a_5$\).

As \($a_2=2000$\), we only have four possibilities left.

Clearly \($a_1=2001$\) for x = 2001, and \($a_3=2001$\) for x = 1.

The equation \($a_4=2001$\)

solves to \($x=\frac{2001}{2000 \cdot 2001-1}$\), and the equation \($a_5=2001$\) to \($x=2000 \cdot 2001-1$\)

There are four alternative values of x for which the sequence contains the value 2001 since no two values of x are equal in the computation we just performed.

Therefore, the correct answer is option (D) 4.

The complete question is:
Consider sequences of positive real numbers of the form x, 2000, y, ........  in which every term after the first is 1 less than the product of its two immediate neighbors. For how many different values of x does the term 2001 appear somewhere in the sequence?

(A) 1

(B) 2

(C) 3

(D) 4

(E) more than 4

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The flux of the vector-field F = 1i + 1j + 3k across the surface S is 2. We find out the flux of the vector-field using Green's Theorem.

Flux form of Green's Theorem for the given vector-field

φ = ∫ F.n ds

= ∫∫ F. divG.dA

Here G is equivalent to the part of the plane = 2x + 1y + z = 2.

and given F = 1i + 1j + 2k

div G = div(2x + 1y + z = 2) = 2i + 4j + k

Flux = ∫(1i + 1j + 3k) (2x + 1y + z) dA

φ = ∫ (2 + 4 + 2 ) dA

= 8∫dA

A = 1/2 XY (on the given x-y plane)

2x+4y =2

at x = 0, y = 1/2

y = 0, x = 1

1/2 (1*1/2) = 1/4

Therefore flux = 8*1/4 = 2

φ = 2.

Green's theorem has numerous applications. One method is to solve two-dimensional flow integrals, which state that the sum of fluid outflows from a volume equals the total outflow summed around an enclosing area.

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The equation that represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4) is y = 5x - 11.

We are given that

Slope of parallel lines is the same, so slope of the line parallel to the given line will be m = 5

We have the slope and a point, using the point-slope form we can write the equation of the line:

\(\rightarrow\text{y} - 4 =5 \ (\text{x} - 3)\)

\(\rightarrow\text{y} = 5\text{x} - 15 + 4\)

\(\rightarrow\bold{y = 5x - 11}\)

Hence, the equation that represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4) is y = 5x - 11.

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Your question is incomplete. The complete question is-

Which of the following equations represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4)?

A. y = 5x - 7

B. y = 5x + 19

C. y = -1/5x -4

D. y = 5x - 11

Answer:

25 dollars are saved

Step-by-step explanation:

you need to subtract 45 and 20

Answer: 25 $ is saved

Step-by-step explanation:

Answer:

Given expression:

\(\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}\)

Separate the variables:

\(\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}\)

Reduce the first fraction:

\(\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}\)

\(\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:\)

\(\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}\)

\(\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}\)

\(\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}\)

\(\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}\)

Therefore:

\(\implies \dfrac{7a^6b^3}{4c^5}\)

Answer:

-26

Step-by-step explanation:

well add the negative numbers first so you get

-17-18=(-35)

then you add 9 so its (-35)+9=26

Answer:

Step-by-step explanation:

-17 + 9 +(-18) = -8 -18 = -26 final answer

The correct graph to display this data is

The bar graph with the title favorite sport and the x-axis labeled sport and the y-axis labeled the number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.

The bar graph is used to display categorical data and the number of observations in each category. In this case, the categories are the different sports and the number of observations is the number of students who selected each sport as their favorite.

Here we have

A random sample of 100 middle schoolers was asked about their favorite sport. The following data was collected from the students.

Sports              Basketball    Baseball    Soccer    Tennis

No of Students       17                  12             27            44

A histogram is used to display continuous data and is not appropriate for this categorical data.

Additionally, the order of the bars in the first histogram is incorrect, which can lead to confusion when interpreting the data.

The correct graph to display this data is

The bar graph with the title favorite sport and the x-axis labeled sport and the y-axis labeled the number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.

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The average of the sample ranges for the weight of packages of Skittles is 0.11. So, the correct answer is (e) 0.11.

To find the average of the sample ranges for the weight of packages of Skittles, we first calculate the range for each sample. The range is the difference between the maximum and minimum values in each sample.

Sample 1: Range\(= 3.62 - 3.58 = 0.04\)

Sample 2: Range\(= 3.65 - 3.49 = 0.16\)

Sample 3: Range \(= 3.65 - 3.45 = 0.20\)

Sample 4: Range \(= 3.64 - 3.54 = 0.10\)

Sample 5: Range\(= 3.62 - 3.49 = 0.13\)

Next, we calculate the average of these sample ranges:

A\(verage = (0.04 + 0.16 + 0.20 + 0.10 + 0.13) / 5 = 0.11\)

Therefore, the average of the sample ranges for the weight of packages of Skittles is \(0.11\). So, the correct answer is (e) \(0.11.\)

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Answer:

$33.81

Step-by-step explanation:

Strawberries = $2.49 Per Pound (Bought 3)

Blueberries = $3.19 Per Pound (Bought 2)

Pineapples = $4.99 Per Pound (Bought 4)

So we have to multiply each price with the number of fruits bought.

So, For Example, Strawberries: $2.49 × 3 = $7.47

After you did all three individually, add them all up.

Strawberries : $7.47

Blueberries : $6.38

Pineapple : $19.96

Total = $33.81

Answer:

18 units

Step-by-step explanation:

PQ= 7 units

QR = 6 units

RS = 5 units

its really not that hard..

As per the problem statement, there is a linear relation,  between de whole earnings of Jada,  and her working time.

Solution:

y = 240 + 6×t

A Linear relation  is of the form:

y = ax + b

If we call total earnings´Jada "y",  and "t" the whole quantity of worked hours per week,  we get:

a fixed amount working 40 hours      12×40 = 480 $

and the quantity over 40 hours as   ( t - 40 ) × 6.

Then  y = fixed quantity + overtime

y = 480 + ( t - 40 ) × 6       reordering this expression

y = 480 + 6×t - 240

y = 240 + 6×t

Just for checking,  if this equation satisfies, the conditions of the problem

if t = 40 h    that means she did´nt do any overtime,

she earns    y = 240 + 6×(40)   ⇒  y = 480 $

if t = 50 h  meaning 10 hours of overtime, she earns:

y = 240 + (50)×6   ⇒  y = 540 $

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Answer:

8/15

Step-by-step explanation:

8/15

hope this helped!!

There are 1820 different groups of applicants for 4 management trainee positions, 126 different groups of trainees consisting entirely of women, and a 0.0692 probability that the trainee class will consist entirely of women.

The number of different groups of applicants that can be selected for the four management trainee positions can be calculated using the combination formula:

nCr = n! / (r! * (n-r)!)

where n is the total number of applicants (16 in this case) and r is the number of positions to be filled (4 in this case).

So the number of different groups of applicants that can be selected is:

16C4 = 1820

Therefore, there are 1820 different groups of applicants that can be selected for the four management trainee positions.

The number of different groups of trainees that would consist entirely of women can be calculated using the combination formula again, but this time we are selecting all 4 positions from the 9 female applicants:

9C4 = 126

Therefore, there are 126 different groups of trainees that would consist entirely of women.

Assuming that all groups of four are equally likely to be selected, the probability that the trainee class will consist entirely of women can be calculated by dividing the number of different groups of trainees that consist entirely of women (126) by the total number of different groups of applicants (1820):

Probability = 126 / 1820 = 0.0692

So the probability that the trainee class will consist entirely of women is 0.0692 (rounded to four decimal places).

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Answer:

50 dollars

Step-by-step explanation:

Answer:

Step-by-step explanation:

s/r=3/5

s/30=3/5

s=30(3)/5

s=90/5

s=$18

We can see that the first component of the vector equation is always zero, so the parabola lies in the xz-plane.

Moreover, the second component is a quadratic function of t, which gives us a vertical parabola when plotted in the yz-plane. The third component is a linear function of t, so the curve extends infinitely in both directions. Therefore, we have a vertical parabola in the xz-plane.

This statement is referring to a specific vector-valued function, which we can write as:

f(t) = (0, t^2, ct)

where c is a constant.

The second component of this vector function is t^2, which is a quadratic function of t. When we plot this function in the yz-plane (i.e., we plot y = t^2 and z = 0), we get a vertical parabola that opens upward. This is because as t increases, the value of t^2 increases more and more quickly, causing the curve to curve upward.

The third component of the vector function is ct, which is a linear function of t. When we plot this function in the xz-plane (i.e., we plot x = 0 and z = ct), we get a straight line that extends infinitely in both directions. This is because as t increases or decreases, the value of ct increases or decreases proportionally, causing the line to extend infinitely in both directions.

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