Answer:
Due to the limited supply of oxygen, carbon (ii) oxide, a poisonous gas, is produced instead of carbon(iv) from the burning charcoal stove and this may result in death when inhaled.
Explanation:
When charcoal is burnt in a plentiful supply of oxygen, the combustion products is carbon (iv) oxide (carbon dioxide) which is not very toxic to the human body. The equation of the reaction is given below:
C + O₂ ----> CO₂
However, in a limited supply of oxygen gas, the combustion product is carbon (ii) oxide. The equation of the reaction is given below:
2C + O₂ ----> 2CO
Carbon (ii) oxide is a colorless and odorless gas which unlike carbon (iv) oxide is very toxic to human and results in fatality when inhaled in even small doses for a few minutes. Its mechanism of action of toxicity is that it competes with oxygen for transport in the body by hemoglobin. It combines irreversibly with hemoglobin to form carboxyhemoglobin, thereby depriving tissues and cells the oxygen they need. This results in death of the cells and tissues as well as of the whole organism. Thus, it is not advisable to light a charcoal stove in limited supply of oxygen.
if the maximum temperature for a particular day is 20°c and the minimum temperature is 10°c, the daily mean would be:
The daily mean, given the data from the question is 15 °C
Data obtained from the questionMaximum temperature = 20 °CMinimum temperature = 10 °CMean = ?How to determine the daily meanMean = Sumation of data / Number of data
Mean = (20 + 10) / 2
Mean = 30 / 2
Mean = 15 °C
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What do you think is happening to the soda and air in the can?
The soda and air will bubble, increasing the chances of an explosion.
Carbonation in soda is made up of carbon dioxide or CO2 bubbles. Carbonated beverages are injected with this colorless and odorless gas under high pressure during manufacture until the liquid is supersaturated with gas. Individuals determined, at the discretion of the Federal Aviation Surgeon, to have a static or non-progressive disqualifying condition.
In soda ash, the dispersed phase is a gas and the dispersion medium is a liquid. Soda ash is an example of a gas that dissolves in a liquid. Shaking the can introduces many small air bubbles into the liquid, so the dissolved gas is more likely to combine with existing air bubbles and evaporate rather than form new air bubbles. By avoiding the difficult step of shaking and frothing the soda, the gas can escape faster creating more fizz.
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A metal M forms oxides containing 11.1% and 20.0% of oxygen. show that these figures agree with the law of multiple proportions
Answer:
The law of multiple proportions states that when two elements combine to form more than one compound, the mass ratios of the elements in the compounds can be expressed as small whole numbers.
Let's assume that the metal M combines with oxygen to form two different oxides, which are represented by the formulas MOx and MOy, where x and y are the number of oxygen atoms in each oxide.
According to the problem, the two oxides contain 11.1% and 20.0% of oxygen, respectively. We can convert these percentages to mass ratios as follows:
Mass ratio of oxygen in MOx = 11.1 g / 100 g of oxide
Mass ratio of oxygen in MOy = 20.0 g / 100 g of oxide
We can simplify these ratios by dividing each by their lowest common factor, which is 1.1:
Mass ratio of oxygen in MOx = 10 g / 91 g of oxide
Mass ratio of oxygen in MOy = 20 g / 100 g of oxide = 20 g / 91 g of oxide
These ratios can be expressed as small whole numbers by multiplying them by a factor that makes the denominator equal to a whole number. We can multiply the ratio for MOx by 10 to get:
Mass ratio of oxygen in MOx = 100 g / 910 g of oxide
We can multiply the ratio for MOy by 5 to get:
Mass ratio of oxygen in MOy = 100 g / 910 g of oxide
Now we can see that the mass ratios of oxygen in the two oxides are in a small whole number ratio of 1:1, which is consistent with the law of multiple proportions. This means that the metal M forms two different oxides in a ratio of small whole numbers, and that the composition of the oxides is determined by the ratio of the masses of the elements involved.
Explanation:
A gas is contained in a cylinder with a volume of 4.3 L at a temperature of 30.3oC and a pressure of 766.9 torr. The gas is then compressed to a volume of 0.38 L, and the temperature is raised to 839.0oC. What is the new pressure of the gas? Express your answer in atmospheres (atm)
The ideal gas law can be used to determine the gas's new pressure. According to the ideal gas law, pressure times volume equals the amount of a gas in moles times the global gas constant times the temperature.
Pressure = (number of moles of gas times the universal gas constant times the temperature) divided by volume is the new equation we may use to calculate pressure.
Since there are an equal amount of moles of gas in this situation, we can use the following formula to determine the new gas pressure: Pressure is equal to (4.3 L times 839.0oC) divided by (766.9 torr times 0.38 L). We obtain a new pressure of 118.6 atm by simplifying.
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all of the following are options for onsite treatment of a homeowner's wastewater except: a) Aeration b) Bacterial digestion c) Chlorination
All of the following are options for onsite treatment of a homeowner's wastewater except aeration. Option A.
On-site treatment of a homeowner's wastewater is a crucial process that is needed to ensure the proper disposal of household waste.
Wastewater treatment is divided into three categories: primary, secondary, and tertiary. The options for onsite treatment of a homeowner's wastewater include Aeration, Bacterial digestion, and Chlorination except for the following choice: a) Aeration.
1. Aeration: It is a process in which air is blown into the wastewater to speed up the breakdown of organic waste by bacteria. It can be useful in treating wastewater in the absence of oxygen but is not one of the options for onsite treatment of a homeowner's wastewater.
2. Bacterial digestion: In this process, bacteria digest organic matter in wastewater. The bacteria require a specific environment to function optimally, and this can be done using septic tanks and other related technologies.
3. Chlorination: It is the process of adding chlorine to wastewater to kill bacteria, viruses, and other microorganisms that may cause illness. This process is often used as a secondary or tertiary treatment process.
Hence, the right answer is option A. Aeration.
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How many carbon atoms are there for every 2 oxygen atoms in CO2? A. 1 B. 2 C. 3 D. 4
Answer:
I think it's 1, but if that's wrong I'm really sorry
Which group of coefficients balances the following chemical equation? 2KCIO3 → _KCI + _O2 a 1, 3 b 2,2 C 2,3 d 2.1 e 1, 1
Answer:
2KClO3 = 2KCl + 3O2
I hope it's helps you
If we blended all the gasoline sold in WI for transportation with 15.0% ethanol (by volume), what is the acreage needed to supply that much corn ethanol (in acres)
To determine the acreage needed to supply the amount of corn ethanol required to blend 15.0% ethanol into all gasoline sold in Wisconsin for transportation, we need to consider the amount of gasoline consumed in the state and the yield of ethanol per acre of corn.
According to the U.S. Energy Information Administration, Wisconsin consumed approximately 2.4 billion gallons of gasoline in 2019. To blend 15.0% ethanol into all of that gasoline, we would need to add 360 million gallons of ethanol.
On average, one bushel of corn yields around 2.8 gallons of ethanol. Therefore, to produce 360 million gallons of ethanol, we would need approximately 129 million bushels of corn.
The yield of corn per acre varies depending on various factors such as weather, soil type, and management practices. On average, however, one acre of corn can produce between 150 and 200 bushels of corn.
Using the conservative estimate of 150 bushels per acre, we can calculate that approximately 860,000 acres of corn would be needed to produce enough ethanol to blend 15.0% ethanol into all gasoline sold in Wisconsin for transportation.
In summary, blending all gasoline sold in Wisconsin for transportation with 15.0% ethanol would require around 860,000 acres of corn to produce the necessary amount of ethanol.
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Which has the larger radius, F or F− ?
A. They have the same radius.
B. F
C. F−
D. It is impossible to tell.
Answer is B- F has a smaller radius than F− because an additional electron causes greater repulsion in F− is the correct choice and the nuclear charge the radius of the anion increases.
Explanation: I hoped that helped!
The one that have larger radius is F-. The correct option is C.
What is atomic radius?A chemical element's atomic radius is a measurement of the size of its atom, usually the mean or typical distance from the nucleus's center to the outermost isolated electron.
Because a boundary is not a well-defined physical entity, various non-equivalent definitions of atomic radius exist.
As the number of energy levels decreases down a group, the distance between the nucleus and the outermost orbital increases.
As a result, the atomic radius expands. The ionic radius is the distance between the nucleus and the ion's electron cloud's outer edge.
Because they have fewer shells, F and F- are both smaller than the rest. F- now has one more electron than F, causing the radius to increase.
Thus, the correct option is C.
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Need help ASAP!! Full paragraph! Will give Brainliest!!
How did knowing the number of valence electrons in one of the alien elements help to identify it? Explain how the table was used to accomplish this task.
Answer:
All elements in the same group of the periodic table have the same number of valence electrons. This made it possible to compare the valence of the alien elements to the valence of elements from our periodic table, and match the alien elements to the correct group. For example, our group 14 elements all have 4 valence electrons, so the alien element with 4 valence electrons had to be part of group 14 also.
Answer:
All elements in the same group of the periodic table have the same number of valence electrons. This made it possible to compare the valence of the alien elements to the valence of elements from our periodic table, and match the alien elements to the correct group. For example, our group 14 elements all have 4 valence electrons, so the alien element with 4 valence electrons had to be part of group 14 also.
What two of the following organisms are secondary consumers in this food web?
Secondary consumers are organisms that primarily feed on herbivores or other primary consumers.
They occupy the next trophic level above the primary consumers in a food web. They obtain energy by consuming the primary consumers and play an important role in regulating the population of herbivores.
Examples of commonly observed secondary consumers include:
Carnivorous mammals: Animals such as wolves, lions, and tigers that feed on herbivores like deer, zebras, or gazelles.
Birds of prey: Species like eagles, hawks, and owls that consume small mammals, reptiles, or other birds.
Carnivorous fish: Fish like pike, barracuda, or bass that prey on smaller fish or aquatic invertebrates.
Predatory insects: Insects such as spiders, mantises, or dragonflies that feed on other insects, including herbivorous insects.
In a specific food web, the identification of secondary consumers would depend on the specific organisms present and their feeding interactions. It would be necessary to analyze the trophic relationships among the organisms in the food web to determine the secondary consumers accurately.
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If the concentration of fluoride anion and aluminum cation was increased to 5 m, by how much would the measured ecell change?.
If the concentration of fluoride anion and aluminum cation was increased to 5M, then there would be decrease in Ecell by 0.055 volts
The standard reduction potential of Fluoride anion and aluminum cation are -
2Al -----> 2Al3+ + 6e- \(E^o\)cell = +1.66
6e- + 3F2 -----> 6F- \(E^o\)cell = +2.87
The complete reaction is -
2Al + 3F2 ------> 2Al3+ + 6F- \(E^o\) = +4.53
Using Nernst Equation :-
E = \(E^o\) – 0.0592/n*log[Al3+]^2[F-]^6
n = 6 (n = number of transferred electrons)
E = +4.53 - 0.0592/6*log(5)^2(5)^6
E = +4.53 - 0.00987*log(25)(1.56 x 10^4)
E = +4.53 – 0.00987*log(3.9 x 10^5)
E = + 4.53 -0.00987(5.59)
E = + 4.53 - 0.055
E = +4.47
The change in Ecell = 5 - 4.47 = 0.055V
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If a sample contained 2.33x10^23 atoms of tellurium, (element 52) how many grams would this be
Given the number of atoms or molecules, we need to use Avogadro's number, but first, let's review this concept: The number 6.02×10^(23 ) is called Avogadro's number, the number of representative particles in a mole or atom.
Remember that the symbol of tellurium is Te. Now, doing the conversion to moles we're going to obtain:
\(2.33\cdot10^{23}atoms\text{ Te}\cdot\frac{1\text{ mole}}{6.02\cdot10^{23}\text{atoms}}=0.387\text{ moles Te.}\)With this number, we can obtain the grams of tellurium using the molar mass that you can find in the periodic table which is 127.6 g/mol. The conversion from moles to grams will be:
\(0.387\text{ moles Te}\cdot\frac{127.6\text{ g Te}}{1\text{ mol Te}}=49.38\text{ g Te.}\)So, 2.33 x 10^(23) atoms of Te are 49.38 of tellurium.
(BRAINLIEST QUEATION)
Amelia wants to check whether blood is acidic or basic not only that she wants to find its approximate PH. Which of these indicators will she use?
Methyl orange
Litmus paper
pH meter
Thymolphthalein
Answer:
litmus paper
Explanation:
have a great day ahead
Answer:
methyl orange
Explanation:
hope it helps
Hybridization of the orbital will affect the chemical shift of a proton. The closer the orbital is to the nucleus, the more deshielded the proton is. Why then, does the hydrogen-bonded to an sp hybridized orbital of a terminal alkyne, appear at a lower delta value than a hydrogen-bonded to an sp2 hybridized carbon of an alkene
The hydrogen-bonded to an sp hybridized orbital of a terminal alkyne appears at a lower delta value (more shielded) than a hydrogen-bonded to an sp2 hybridized carbon of an alkene due to differences in the electron density distribution.
In an sp hybridized orbital, the electron density is concentrated closer to the nucleus due to the increased s-character of the hybrid orbital. This increased electron density near the nucleus results in stronger electron shielding, which reduces the effective magnetic field experienced by the hydrogen nucleus (proton). As a result, the hydrogen appears at a lower chemical shift (higher delta value) on the NMR spectrum.
On the other hand, in an sp2 hybridized carbon of an alkene, the electron density is distributed over a larger region due to the presence of a double bond. This distribution of electron density results in weaker electron shielding compared to the sp hybridized orbital. Consequently, the hydrogen bonded to an sp2 hybridized carbon appears at a higher chemical shift (lower delta value) on the NMR spectrum.
In summary, the hybridization of the orbital affects the electron density distribution, which in turn affects the chemical shift of a proton. The closer the orbital is to the nucleus, the more shielded the proton is, leading to a lower chemical shift.
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why do you think neutrons are necessary in the nucleus of an atom?
Answer:
They help stablize the strucure of an atom.
Explanation:
Take into consider isotopes where there are more or less than the ideal amount of neurtrons. These isotopes are radioactive and unstable to the point hey are used as atomic bombs. So with the proper amount of nuetrons it helps the atom maintain structure and not degrade
Answer: they have an important role to keep the atom stable
Explanation:
since protons are positively charged, there is an incredibly strong repulsive force between all the protons in a nucleus
differentiate between edible and non edible mushroom
Edible mushrooms: Consuming edible mushrooms is safe and provides health advantages like fiber, vitamins, and minerals.
Examples: Button mushrooms.Non-Edible mushrooms: Mushrooms that cannot be eaten could be harmful or have unappealing flavors and textures that could be harmful if consumed.
Examples: Death Cap.
AgCl is found to have 78.1% ionic character, and its gas phase dipole moment is 11.5 D. What is the distance between the Ag and Cl atoms in gaseous AgCl?
please explain how as well
Answer:
The ionic character of a compound can be used to determine the bond polarity, and the gas phase dipole moment can be used to calculate the bond length. The equation for the bond length (r) in terms of the bond polarity (p) and the bond dipole moment (μ) is given by:
r = (μ) / (4πpε_0p)
Where ε_0 is the vacuum permittivity and p is the bond polarity.
For AgCl, the bond polarity can be calculated from the ionic character:
p = 78.1%
So, substituting the values into the equation, we get:
r = (11.5 D) / (4π * 0.781 * 8.854 x 10^-12 C^2/Nm^2) = 2.8 x 10^-10 m
So the distance between the Ag and Cl atoms in gaseous AgCl is approximately 2.8 x 10^-10 meters.
Explanation:
What did the Fish and Wildlife Service (FWS) do to bring back black-footed ferrets from extinction?
The FWS moved mating pairs from the Wyoming population to over 8 western states and Mexico to begin new colonies.
The captive breeding program was implemented too late to save the black-footed ferret.
The FWS monitored a Wyoming population and captured enough individuals to start new populations.
The FWS use a captive breeding program to start populations in 8 states.
Answer:
The FWS use a captive breeding program to start populations in 8 states
Explanation:
I just took a quiz and got this answer right.
Answer:
The FWS use a captive breeding program to start populations in 8 states
Explanation:
what combination of ester and bromo-grignard reagent could you use to prepare the following tertiary alcohol? (select) draw structure ... bromo-grignard reagent
Esters are transformed into tertiary alcohols using a Grignard reagent reaction. A ketone is produced when one mole of Grignard reagent is added to the carbon-oxygen double bond, creating an unstable intermediate.
What takes place when esters and Grignard reagent interact?A potent nucleophile is the Grignard reagent. When it interacts with an ester, it goes through a nucleophilic addition process that results in ketone, which, when added to another substance, becomes tertiary alcohol.
Following acid hydrolysis and a reaction with the Grignard reagent, ketone and ester produce tertiary alcohol.
Tertiary alcohols esterify at a significantly slower pace than primary or secondary alcohols. Thus, tertiary alcohols as well as primary and secondary alcohols may be separated from mixtures by direct esterification with boric acid.
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carlos is preparing to take a comprehensive final exam in his chemistry course. this exam is an example of a(n)
In this example, the exam, Carlos concerns, and his behavior may be seen as an example of eustress.
What is stress?Stress is a normal physiological and psychological reaction that people have in response to their surroundings. Eustress refers to positive, motivating stress that improves functioning, whereas distress refers to negative, overwhelming stress that impairs functioning.
Eustress refers to positive stress, which can be psychological, physical, or biochemical/radiological. Endocrinologist Hans Selye coined the term, which combines the Greek prefix eu-, which means "good," and stress, which literally means "good stress." Eustress refers to beneficial stress, which can be psychological, physical, or biochemical/radiological in nature.
Since Carlos has a comprehensive final exam in three weeks that he is concerned about and this made him to go ahead and start studying, this is eustress.
Exhilarating rides, competition, and a good scary movie are all examples of Eustress.
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Complete question
Carlos has a comprehensive final exam in three weeks that he is concerned about. His concerns prompt him to go ahead and start studying and in doing so, he feels less worried as the exam approaches. In this example, the exam, Carlos concerns, and his behavior may be seen as an example of ?
which cations are found in higher concentration in the icf?
The cations found in higher concentration in the intracellular fluid (ICF) are potassium ions (K+) and magnesium ions (Mg2+).
The cations that are found in higher concentration in the intracellular fluid (ICF) are potassium (K+) and magnesium (Mg2+). This is because these cations are actively transported into the cell to maintain the electrochemical balance and are involved in many cellular processes such as protein synthesis, enzyme activity, and energy metabolism.
On the other hand, sodium (Na+) and calcium (Ca2+) are found in higher concentration in the extracellular fluid (ECF) and play important roles in maintaining fluid balance, nerve and muscle function, and blood pressure regulation.
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Crystallization or solidification of crystal follows two different mechanism; one is nuclei formation and the second is crystal growth. The nuclei formation is few atoms comes together to form a cluster; these atoms may or may not continue to be with the same cluster. However in order to retain the group and continue to crystal growth, what are the parameters that governs and how does those parameters influence the kinetic and potential energy of atoms while solidification?
Temperature, cooling rate, supersaturation, composition, and presence of impurities, collectively influence the formation of nuclei and subsequent crystal growth during solidification.
They determine the stability of nuclei, the rate of crystal growth, and the quality of the resulting crystal structure
When it comes to the solidification or crystallization process, the formation of nuclei and subsequent crystal growth are indeed two distinct mechanisms.
To understand how the parameters influence the kinetic and potential energy of atoms during solidification, we need to consider the factors that govern these processes.
Temperature:
Temperature plays a crucial role in solidification.
As the temperature decreases, the thermal energy of atoms decreases as well, leading to a decrease in their kinetic energy.
This reduction in kinetic energy promotes the formation of stable nuclei by allowing atoms to come closer together and form stable bonds.
Cooling Rate:
The rate at which the temperature decreases, or the cooling rate, affects the solidification process.
A slower cooling rate allows more time for atoms to diffuse and come together to form larger nuclei.
This slower cooling rate promotes the formation of well-defined crystal structures with fewer defects.
Supersaturation:
Supersaturation refers to a state where the concentration of solute atoms exceeds the equilibrium concentration.
In the context of solidification, supersaturation promotes nucleation by providing an excess of atoms available to form nuclei.
It increases the driving force for nucleation and subsequent crystal growth.
Composition:
The composition of the material being solidified influences the solidification process.
Different atomic compositions can result in varying interatomic forces and bonding energies.
These factors affect the stability of nuclei and the subsequent crystal growth.
For example, a material with a high atomic diffusion rate may exhibit faster crystal growth.
Presence of Impurities:
Impurities or foreign particles can have a significant influence on solidification.
They can act as nucleation sites, promoting the formation of nuclei and affecting crystal growth.
Impurities can also lead to the formation of different crystal structures or defects within the crystal lattice.
Regarding the kinetic and potential energy of atoms, the solidification process involves a decrease in both forms of energy:
Kinetic Energy:
As the temperature decreases, atoms lose thermal energy, resulting in a decrease in their kinetic energy.
This decrease in kinetic energy allows atoms to come closer together and form stable bonds.
Potential Energy:
During solidification, atoms rearrange themselves into a more ordered and stable arrangement, reducing their potential energy.
As atoms bond together to form a crystal lattice, their potential energy decreases due to the more favorable arrangement of atoms in the solid state compared to the liquid state.
Overall, the parameters mentioned above, such as temperature, cooling rate, supersaturation, composition, and presence of impurities, collectively influence the formation of nuclei and subsequent crystal growth during solidification.
They determine the stability of nuclei, the rate of crystal growth, and the quality of the resulting crystal structure.
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A 55.0 g piece of iron at 505 ° C is put into 735 grams of water at 15.0 ° C. What is the final temperature of the water and the iron?
Answer:
It would be 95.3
Explanation:
The car has a rechargeable battery to drive it’s motor. The rechargeable battery provided a potential difference of 330 volts and can store up to 64 mega Jules it takes 8 hours for the battery to receive a full charge assume that the charging process is 100% efficient calculate the total charge the flows while the battery is being charged
The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.
To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.
The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):
E = V * Q
Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):
Q = E / V
Substituting the given values, we have:
Q = 64 MJ / 330 V
To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:
Q = (64 * 10^6 J) / 330 V
Calculating the division:
Q ≈ 193,939.39 Coulombs
Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.
This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.
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A student filled a graduated cylinder with water and read the meniscus at 36.1 mL. The student then
dropped a metal cylinder into the graduated cylinder and the water level rose to 43.7 mL. If the metal
cylinder had a density of 2.70 g/
mL, determine the mass of the solid object. Show work.
Answer:
The mass of solid object is 20.52 g.
Explanation:
Given data:
Volume of water = 36.1mL
Volume of water with metal cylinder = 43.7 mL
density of metal cylinder = 2.70 g/mL
Mass of solid object = ?
Solution:
First of all we will calculate the volume of solid object.
Volume of solid object = Volume of water with metal cylinder - Volume of water
Volume of solid object = 43.7 mL - 36.1mL
Volume of solid object =7.6 mL
Density:
density = mass/ volume
2.70 g/mL = mass / 7.6 mL
mass = 2.70 g/mL × 7.6 mL
mass = 20.52 g
The mass of solid object is 20.52 g.
Which of the following Lewis structures would be an incomplete octet? A) NF3 B) SO2 C) BCI3 D) CF4 E) SO3^2-
C) BCI3 is the Lewis structure would be an incomplete octet.
The octet refers to the eight electrons in the outermost shell of each atom. The boron trichloride forms an incomplete octet and hence it does not obeys octet rule.
The central atom boron forms three covalent compounds from the three outermost electrons in the atom. The reason for covalent bond is non-metal characteristic of each atom. The electron sharing occurs with chlorine. However, each chlorine has complete octet. Boron trichloride is an inorganic compound used in organic synthesis.
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Jason shot a bb straight up in the air with a velocity of 105 m/s.what will the velocity of the bb when it is at a height of 203 m?
Answer:
The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.
brainlest?
Answer: v = 83.96 m/s
Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.
Using the equation for the vertical displacement of an object in free fall:
Δy = (v₀² - v²) / (2g)
Δy = vertical displacement (203m)
v₀ = initial velocity (105 m/s)
v = final velocity (not known yet)
g = accerlation due to gravity (9.8 m/s^2)
Lets rearrange the equation to solve for the final velocity:
v = v = √(v₀² - 2gΔy)
Substituting the given values:
v = √(105² - 2 * 9.8 * 203)
v ≈ √(11025 - 3979.6)
v ≈ √(7054.4)
v ≈ 83.96 m/s
Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.
What do you know about how krypton (Kr) behaves in real life just by looking at where it is on the periodic table? List at least 3 physical or chemical properties.
Answer:
.
Explanation:
a rare gas of Group 18 (noble gases) of the periodic table, which forms relatively few chemical compounds. About three times heavier than air, krypton is colourless, odourless, tasteless, and monatomic. Although traces are present in meteorites and minerals, krypton is more plentiful in Earth’s atmosphere, which contains 1.14 parts per million by volume of krypton.
If a yellow paint is to have 0.511% pbcro4 by mass, how many grams of chromite are needed per kilogram of paint?
Yellow paint has 0.511 % PbCrO4 by mass
Mass of PbCrO4 in 1 kg of paint = (0.511 / 100) * 1 kg = 0.00511 kg = 5.11 g
Moles of PbCrO4 = 5.11 g/ 323.19 g/mol
= 0.0158 moles
Moles of K2CrO4 also = 0.0158 moles
Moles of FeCr2O4 = 0.0158 moles K2CrO4 * (4 mole FeCr2O4 / 8 moles K2CrO4)
= 0.0079 moles
Mass of FeCr2O4 (chromite) = 0.0079 moles * 223.83 g/mol
= 1.77 g
Paints are divided into two types: oil-based paints and water-based paints. Oil paints are usually used as a primer, undercoat, and topcoat. In the past, we relied heavily on oil-based paints for surface durability and longevity, but today water-based paints are on par. It is used for prolongation and acts as a barrier against environmental influences. Paint consists of pigments, solvents, resins, and various additives. Pigments give the paint its color. Solvents make application easier. The resin helps dry. Additives range from fillers to antifungals. There are hundreds of different natural and synthetic pigments.
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