Why does water that is frozen in an ice cube tray stay in the shape of a cube when it is
taken out of the tray?

A. The water particles can only slip past one another.
B. The water particles become locked in place.
C. The water particles stop moving completely.
D. The water particles grow bigger to fill the space.

Answers

Answer 1
The Answer is B : The water particles become locked in place.
Answer 2

Water freezes to form ice cubes. In this solid structure, particles are strongly bonded each other thus, the water particles become locked in place.

What is freezing point?

Freezing point is the temperature at which the substance converts from liquid state to solid state. In solid state, all particles are strongly bonded together.

In water, particles in liquid state are free to flow and they are not locked at all. In gaseous state no definite shape or volume are there and particles are away from each other and they diffuse easily.

In solid state particles are not at all free to flow and thus they are locked in place. That's why water molecules are locked in place in a cube until they melt completely.

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Related Questions

HELP HELP!!!!!!!!!!!!!!!!

HELP HELP!!!!!!!!!!!!!!!!

Answers

Magnetic force is used in: A door catch or a latch on kitchen cabinet

and A directional compass.

Electric force is used in: Two shocks stacks together coming out of a clothes dryers and An air filter that traps dust and ion particle.

What is magnetic force?

Electromagnetic force is a result of charge motion, which also produces magnetic force. We know that a moving charge creates a magnetic field around itself. In this situation, the magnetic force can be thought of as a force that results from magnetic fields interacting.

A door catch or a latch on kitchen cabinet and a  directional compass are example of use of magnetic field.

Two shocks stacks together coming out of a clothes dryers and an air filter that traps dust and ion particle are example of use of etectric force.

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its all in the sc
please help

its all in the scplease help

Answers

The displacement of 20 miles is the straight-line distance in the Southwest direction from the starting point whereas the distance of 70 m is the total distance along the path of travel.

What are displacement and distance?

Distance is the actual distance that a body travels. Additionally known as path length. As an illustration, the path length for an object going from point O to point A will be distance OA = 30 m. It is a scalar quantity, the distance.

Displacement is the change in an object's position in relation to a reference frame. It is a vector quantity with both magnitude and direction.

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its all in the scplease help

why doesn't the moon fall toward earth like apples do?

Answers

The moon doesn't fall toward the Earth like apples do because it is in a state of constant freefall, known as orbit. This is due to the balance between the force of gravity pulling the moon towards the Earth and the moon's own inertia.

The moon doesn't fall toward the Earth like apples do because it is in a state of constant freefall, known as orbit. The moon orbits around the Earth due to the force of gravity. Gravity is the force of attraction between two objects with mass. In this case, the Earth's gravity pulls the moon towards it, but the moon also has its own motion called inertia. Inertia is the tendency of an object to resist changes in its motion.

When the moon was formed, it was already moving forward with a certain velocity. As it falls towards the Earth due to gravity, it also moves forward, resulting in a curved path known as an orbit. This balance between the gravitational force and the moon's inertia keeps it in a stable orbit around the Earth.

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638 nm light passes through a single
slit. The third (m = 3) diffraction
minimum occurs at an angle of 5.48º.
What is the width of the slit?

Answers

which class question is this

Answer:

2.00

Explanation:

Move the sinθ to the right.

A marble is attached to a compressed horizontal spring and is then released. Which equation correctly shows the conservation of mechanical energy for this system? (1 point)

a. mgh=kx^2
b. mgh=(1/2)kx^2
c. (1/2)mv^2=kx^2
d. (1/2)mv^2=(1/2)kx^2​

Answers

Answer: the answer is 1/2mv^2 = 1/2 kx^

Explanation:

part a. A nerf dart is launched out of a pvc pipe, and while it is accelerating it goes from rest to a velocity of 30.00 m/s. The acceleration of the dart is 330 m/s^2. How long is the dart being accelerated?part b. How far does the dart travel being accelerated?

Answers

Part A. We are given that a dart travels from rest to a velocity of 30 m/s with an acceleration of 330 m/s^2 to determine the time we will use the following equation of motion:

\(v_f=v_0+at\)

Where:

\(\begin{gathered} v_f,v_0=\text{ final and initial velocities} \\ a=\text{ acceleration } \\ t=\text{ time} \end{gathered}\)

Since the dart is launched from rest this means that the initial velocity is zero, therefore:

\(v_f=at\)

Now, we divide both sides by "a":

\(\frac{v_f}{a}=t\)

Now, we plug in the values:

\(\frac{30\frac{m}{s}}{330\frac{m}{s^2}}=t\)

Solving the operation:

\(0.09s=t\)

Part B. Now, we are asked to determine the distance. To do that we will use the following equation of motion:

\(2ad=v_f^2-v_0^2\)

Now, we divide both sides by "2a":

\(d=\frac{v_f^2-v_0{}^2}{2a}\)

Now, we plug in the values:

\(d=\frac{(30\frac{m}{s})^2}{2(330\frac{m}{s^2})}\)

Solving the operations we get:

\(d=1.36m\)

Therefore, the distance is 1.36 meters.

a heart defibrillator is used to enable the heart to start beating if it has stopped. this is done by passing a large current of 12.0 a a through the body at 25.0 v v for a very short time, usually about 3.00 ms m s . you may want to review (page) . for related problemsolving tips and strategies, you may want to view a video tutor solution of power in a short circuit. part a what power does the defibrillator deliver to the body?

Answers

The power that the defibrillator delivers to the body is 300 Watts. The formula for power is given by:

P=IV

Where,

P is power

I is current

V is potential difference.

Substituting the given values, we get:

P=12.0 A × 25.0 VP = 300 W

Therefore, the power that the defibrillator delivers to the body is 300 Watts.

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What are the properties of different types of electromagnetic waves?

Answers

Answer:

1. All electromagnetic waves travelS at 3×10⁸m/s in vacuum

2.They are transverse in nature.

3.they can travel through vacuum.( doesn't require any materials for their transmission.

4.They under go phenomena of diffraction,reflection, refraction, interference and polarization.

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PLEASE PICK BRAINLIEST

A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.​

Answers

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

a 2.0 kg ball is dropped from a height of 20 m onto a soft surface and rebounds to a height of 5.0 m . what is the magnitude of the impulse exerted on the ball by the floor?

Answers

Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.

What is the impulse of the floor on the ball?

Using the equation of motion to determine the velocity at the end of the fall

v^2 = u^2 + 2gh

Where v is velocity at the end of fall

u is initial velocity = 0

g is acceleration due to gravity = 9.81 m/s^2

h is height = 20

Taking downward velocity as negative and up as positive

v^2 = 0 + 2 (9.81)(20)

v^2 = 392.4

v = - 19.8 m/s

The velocity, v after bouncing is calculated also:

u = 0

g = 9.81 m/s^2

h = 5.0 m

v^2 = 0 + 2(9.81)(5)

v^2 = 98.1

v = 9.904 m/s

Impulse = change in momentum Impulse = m(v- u)

Impulse = 2.0 × (9.9 -(-19.8)

Impulse = 59.4 Ns

Therefore, the impulse of the floor on the ball is 59.4 Ns.

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The position of an air-track cart that is oscillating on a spring is given by the equation x = (12.4 cm) cos[(6.35 s-1)t]. At what value of t after t = 0.00 s is the cart first located at x = 8.47 cm?

Answers

To find the value of t when the cart is first located at x = 8.47 cm, we need to set the given equation equal to 8.47 cm and solve for t. Therefore, we have:

8.47 cm = (12.4 cm) cos[(6.35 s^-1)t]

Dividing both sides by 12.4 cm, we get:

cos[(6.35 s^-1)t] = 0.6835

Taking the inverse cosine (cos^-1) of both sides, we get:

(6.35 s^-1)t = 46.13°

Multiplying both sides by (1 rad/57.3°) to convert degrees to radians, we get:

(6.35 s^-1)t = 0.805 rad

Finally, solving for t, we get:

t = (0.805 rad)/(6.35 s^-1) = 0.127 s

Therefore, the cart is first located at x = 8.47 cm at a time of t = 0.127 s after t = 0.00 s.
The position of an air-track cart oscillating on a spring is given by the equation x = (12.4 cm) cos[(6.35 s-1)t]. To find the value of t when the cart is first located at x = 8.47 cm, we can set the equation equal to 8.47 cm:

8.47 cm = (12.4 cm) cos[(6.35 s-1)t]

Now, we need to solve for t:

(8.47 cm) / (12.4 cm) = cos[(6.35 s-1)t]
0.6831 = cos[(6.35 s-1)t]

Next, take the inverse cosine (arccos) of both sides:

t = arccos(0.6831) / (6.35 s-1)

Calculating the value of t, we get:

t ≈ 0.3069 s

So, the cart is first located at x = 8.47 cm after approximately t = 0.3069 seconds.

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a dedicated sports car enthusiast polishes the inside and outside surfaces of a hubcap that is a section of a sphere. when he looks into one side of the hubcap, he sees an image of his face 30.0 cm in back of the hubcap. he then turns the hubcap over and sees another image of his face 10.0 cm in back of the hubcap. (a) how far is his face from the hubcap? (b) what is the radius of curvature of the hubcap?

Answers

(a) The distance from her face to the hubcap is 20 cm. and (b) The radius of curvature of the hubcap is 10 cm.

What is curvature?

Curvature is a measure of how much a curve deviates from a straight line. It is measured by the amount of change in the direction, or angle, of the curve in a given distance. Curvature is an important concept in mathematics, physics, and engineering. In mathematics, curvature is used to describe the properties of curves and surfaces, and to find their tangent lines.

A. This is calculated by subtracting the distance of her face from the hubcap in the second scenario (10 cm) from the distance of her face from the hubcap in the first scenario (30 cm):
Distance = 30 cm - 10 cm = 20 cm
B. his is calculated by dividing the distance of her face from the hubcap in the first scenario (30 cm) by twice the difference in the distance of her face from the hubcap in the first and second scenarios (20 cm):
Radius of Curvature = 30 cm / (2 × 20 cm) = 10 cm

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A 1295 kg car is driving down the road at a constant speed of 24.4 m/s. The engine
exerts a 1450 N force northward, what is the sum of all southward forces exerted on the
car?

Trolls will be reported.

Answers

The mass of the car is 1295 Kg. The downward force thus, acting to south is the force due to its weight, that is equal to 12691 N but it is cancelled in magnitude by 1450 northwards and net force will be 11240 southwards.

What is force?

Force is an external agent acts on a body to change its state or to deform it. There are different kinds of forces such as gravitational force, magnetic force, frictional force etc.

Two forces acting from the same direction results in a net force that is the sum of the magnitudes of the two forces. When these forces are acting from opposite directions, they will cancel each other in magnitude.

The normal force acting on the car by its weight 1295 kg is:

N = mg = 1295 kg × 9.8 m/s² = 12691 N

There acts a northward force of 1450 N which reduce the magnitude of the south ward force and the net force will be 12691 - 1450 = 11240 N

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An object needs a force of 152 Newtrons to move 8 meters. How much work is required?

Answers

Answer:

960J

Explanation:

Given parameters:

Force  = 120N

Distance = 8m

Unknown:

Work required  = ?

Solution:

The work done by a body is the force applied to move a body in a specific direction.

 Work done  = Force x distance

Insert the parameters and solve;

  Work done  = 120  x  8  = 960J

An electron (rest mass 9.11x10^(-31) kg, charge is 1.60x10^(-19) C) is moving opposite to an electric field of magnitude E = 5x10^5 N/C. All other forces are negligible in comparison to the electric field force. What is the magnitude of the force on electron F = qE
a. 8x10-24N
b. 8x10-19N
c. 8x10-14N
d. 8x10-15N

Answers

The force exerted on the electron has the magnitude of  \(8\times10^{-14} N\). The force on an electric charge q in an electric field E is given by the formula F = qE.

Here, the charge on the electron is \(q = 1.60\times 10^{-19} C\), and the electric field is \(E = 5\times10^5 N/C\).

the electron's Magnitude of force is given by :\(F = (1.60\times10^{-19} C)(5\times10^5 N/C) = 8\times10^{-14} N\)

This force is directed opposite to the direction of the electric field because the electron has a negative charge. Since all other forces acting on the electron are negligible in comparison to the electric field force, we can assume that the electron moves with a constant acceleration given by F = ma. The acceleration of the electron can be determined by using the formula a = F/m.

Substituting the values, we get

\(a = \frac{8\times10^{-14} N)}{(9.11\times10^{-31} kg)} = 8.78\times10^{16} m/s^2.\)

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Why does a solar nebula flatten into a disk instead of a sphere, even though the gravity of a nebula pulls in all directions?
A This flattening occurs because the initial shape of the nebula is already somewhat flat.
B This flattening is a natural consequence of collisions between particles in a spinning cloud.
C. This flattening occurs because of gravitational influences of nearby stars.
D. This flattening occurs because the temperature of the solar nebula decreased as it collapsed.

Answers

Solar nebula flattening is a natural consequence of collisions between particles in a spinning cloud. therefore, option B is correct.

When a solar nebula collapses under its own gravity, it begins to spin due to the conservation of angular momentum. As the cloud spins, particles within it collide and interact. These collisions cause the cloud to flatten into a disk shape rather than remaining spherical.

Angular momentum plays a crucial role in this process. The initial slight asymmetry or irregularity in the nebula's shape leads to variations in the speeds and directions of the particles' motions. As particles collide and transfer momentum, their motion tends to align along the rotational axis of the cloud, promoting the formation of a flattened disk structure.

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Charge A is +2.0 x 106 coulomb and charge B is +1.0 x 10-6 coulomb. Ifthe force that A exerts on B is 1.0 × 10-2 newton, the force that B exerts on A is A) 5.0 x 10'1 newton B) 1.0 x 10 newton c) 3.0 x 102 newton D) 2.0×10-2 newton 10)

Answers

The force that B exerts on A is 1.0 × 10^-2 newton, which is option D.

To calculate the force that B exerts on A, we can use Coulomb's law which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is: F = kq1q2/d^2, where F is the force, k is Coulomb's constant (9 × 10^9 N·m^2/C^2), q1 and q2 are the charges, and d is the distance between the charges.

Given that charge A is +2.0 x 10^6 coulomb, charge B is +1.0 x 10^-6 coulomb, and the force that A exerts on B is 1.0 × 10^-2 newton, we can rearrange the formula to solve for the force that B exerts on A:

F = kq1q2/d^2
1.0 × 10^-2 = (9 × 10^9)(2.0 × 10^6)(1.0 × 10^-6)/d^2

Simplifying this equation, we get:

d^2 = (9 × 10^9)(2.0 × 10^6)(1.0 × 10^-6)/(1.0 × 10^-2)
d^2 = 1.8 × 10^5
d = 424.3 meters (rounded to three decimal places)

Now that we know the distance between the charges, we can use Coulomb's law again to calculate the force that B exerts on A:

F = kq1q2/d^2
F = (9 × 10^9)(1.0 × 10^-6)(2.0 × 10^6)/(424.3)^2
F = 1.0 × 10^-2 newton

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What is the magnitude BBB of the magnetic field at the location of the charge due to the current-carrying wire

Answers

The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

What is magnetic field?

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

magnetic field due to the current-carrying wire

The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is calculated as follows;

B = μI/2πr

where;

I is the current in the wirer is the location of the magnetic fieldμ is permeability of free space

Thus, the magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

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When setting up the light source on the optical bench, it should be positioned at the 0cm mark on the bench.

Answers

By positioning the light source at the 0cm mark on the optical bench, you can accurately measure distances between various optical components and conduct your experiment with precision. This setup is essential for obtaining reliable results and maintaining consistency in your optical experiments.

When setting up the light source on the optical bench, it is important to position it at the 0cm mark on the bench. This placement ensures that the starting point for measuring the distance of various optical components, such as lenses or mirrors, is consistent and accurate.

To set up the light source on the optical bench, follow these steps:

1. Locate the 0cm mark on the optical bench, which is usually found on one end of the bench. This mark serves as the reference point for all distance measurements in the experiment.

2. Place the light source, such as a lamp or laser, directly over the 0cm mark. Ensure that the center of the light source aligns with the mark for accurate positioning.

3. Secure the light source to the bench using the appropriate mounting hardware, such as clamps or brackets. This will prevent the light source from moving during the experiment and maintain accurate distance measurements.

4. Turn on the light source and ensure that it is functioning properly. Adjust the brightness or intensity if necessary to provide the appropriate amount of light for the experiment.

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What is the function of Soda Line​

Answers

Soda-Lime is a mixture of chemicals, used in granular form in closed breathing environments, such as general anesthesia, submarines, rebreathers, recompression chambers, respiratory therapy departments and xenon delivery systems, to remove carbon dioxide from breathing gases to prevent CO2 retention and carbon dioxide

Can I have brainliest please?

We know the Sun is primarily made from hydrogen and helium on the basis of its
-mass.
-luminosity.
-age.
-spectrum.
-color.

Answers

We know the Sun is primarily made from hydrogen and helium on the basis of its spectrum. The option d is correct answer.

The spectrum of the sun is obtained by observing the light it emits. When sunlight passes through a prism or spectrometer, it is separated into a continuous spectrum by black absorption lines. These lines correspond to specific wavelengths of light absorbed by the elements in the solar wind.

By comparing these absorption lines with well-known ones of different elements, the researchers found that the main absorption lines in the solar spectrum are similar to those produced by hydrogen and helium. This indicates that these two elements are the main components of the solar wind.

Other evidence, such as the Sun's mass, brightness, age, and color, cannot provide direct information about its composition. While these conditions are important for understanding the properties and behavior of the sun, they do not specifically indicate the abundance of hydrogen and helium in its composition.

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Objects A and B have equal amounts volumes and are both traveling at 25 miles per hour. Object A is much denser than Object B. Which object has a greater amount of force and why

Answers

Answer:

Object A

Explanation:

Mass of an object= Volume × denstiy

Object having higher density will have greater mass

Next,

According to second law of Newton

Force= mass× acceleration

Force= mass× change is velocity/ time

For an equal amount of time, if change in velocity is equal then object with higher mass will have higher force. Hence, greater density, greater is mass and larger is the force.

A small ball P moves with speed v towards another identical ball Q along a line joining the centres of the two balls. Ball Q is at rest. Kinetic energy is conserved in the collision.

Answers

In this scenario, when ball P collides with ball Q, the kinetic energy is conserved. This means that the total kinetic energy of the two balls before the collision is equal to the total kinetic energy after the collision.

Initially, the kinetic energy of ball P is given by:

Kp = (1/2)mv^2

where m is the mass of each ball and v is the speed of ball P.

Since ball Q is at rest, its initial kinetic energy is zero.

Therefore, the total kinetic energy before the collision is:

Kinitial = Kp + Kq = (1/2)mv^2

After the collision, the two balls will move away from each other. Let's assume that ball P moves to the right with speed v1 and ball Q moves to the left with speed v2.

The conservation of kinetic energy tells us that:

Kfinal = (1/2)mv1^2 + (1/2)mv2^2 = (1/2)mv^2

However, the momentum is also conserved in this collision. The momentum before the collision is:

pinitial = mv

After the collision, the momentum of the two balls is:

pfinal = mv1 - mv2

Since momentum is conserved, we have:

pinitial = pfinal

or

mv = mv1 - mv2

Solving for v1 and v2, we get:

v1 = ((m - M)/m)v

v2 = ((2m)/m)v - v1 = (M/m)v

where M is the mass of ball Q.

Therefore, after the collision, the kinetic energy of the two balls is:

Kfinal = (1/2)m((m - M)/m)^2v^2 + (1/2)M((2m)/m)^2v^2

Simplifying this expression, we get:

Kfinal = (1/2)mv^2

Thus, the total kinetic energy of the two balls after the collision is the same as before the collision, which means that kinetic energy is conserved in this collision.

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6. A person starts at rest and accelerates at a uniform rate of at 3.2 m/s2 for 3.0 seconds. What distance
does this person cover in that time?

Answers

Answer:

14.4m

Explanation:

u = 0 i.e it started from rest

acceleration (a) = 3.2m/s2

time taken (t) = 3.0s

Using the second equation of motion:

s = ut + 1/2at2

s = 0(3.0) + 1/2(3.2)(3.0)2

s = 1.6(9.0)

s = 14.4m

hence the distance covered within that time is 14.4m.

An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Determine the net force acting on the object:

Answers

Explanation:

Draw a free body diagram.  There are two forces: weight force pulling down and air resistance pushing up.

Sum the forces in the y direction:

∑F = 50 N − (30 kg) (10 m/s²)

∑F = -250 N

In the simulation, both elastic and inelastic collisions take the same amount of time. In which type of collision is the acceleration less? Why?

Answers

Answer:

its ealstic.

Explanation:

Because the change in velocity is less in an inelastic collision, the acceleration is also less in an inelastic collision.

what is mach number?​

Answers

     Mach number is "the ratio of the speed of a body to the speed of sound in the surrounding medium" (Oxford Languages). Put simply, it's a ratio comparing the local flow velocity to the speed of sound in the medium.

     It is represented with the following formula. M is the mach number, u is the local flow velocity, and c is the speed of the sound in the medium.

                  \(\boxed{\displaystyle M=\frac{u}{c} }\)

amy bought 3 body lotions and 7 body spray for 80 jessica bought 6 body lotion and 3 body spray for 63.75 how much does one body spray cost

Answers

Answer:

Each body spray cost $ 21.25

Explanation:

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Whenever electrons of an atom unite with electrons of another atom, a chemical change occurs.

What is the cause?
What kind of change occurs?
Water expands when it freezes. Expanded ice floats on lakes and ponds.

What causes the water to expand?
What is the effect on the expanded ice?
Some metals will expand when heated. Expanded metals may bend.

What causes the metal to expand?
What are the effects of the expanded metal?
Gases expand when heated. An expanded gas occupies more space.

What causes the gas to expand?
What are the effects of the expanded gases?
Answer the above questions and give an example of a cause and effect relationship. See if you can think up a cause and effect relationship using acids, bases, and neutralization.

Answers

Answer:

C. would be the correct option

Explanation:

Burning gasoline is a chemical change because when gasoline is ignited, water and carbon dioxide are produced. Water freezing to form ice would be a physical change since its state of matter has changed, but not the water itself. Sugar dissolving in water is also a physical change because all it's really doing is just forming bubbles and changing the color. Choice D. would also be a physical change since the piece of metal is still a piece of metal, it just expanded when the temperature increased.

Match the phrase with word please help!

Phrases:

1.) The amount of work done when jerry carries a box from his house to the moving truck . He exerts a force of 35 N while carrying the box 4 meters

2.) The power resulting from 420 Nm of work being completed in 3 seconds

3.) The amount of work done when Fido carries his toy from the backyard to his crate. He exerts a force of 1.2 N over a distance of 15 m

4.) The power resulting from 120 Nm of work being completed in 20 seconds


A.) 140 joules

B.) 140 Newton-meters

C.) 6 joules

D.) 6 Newton-meters

Answers

Answer:

1-B, 2-A, 3-D, 4-C

Explanation:

1. The force exerted is, F = 35 N

  Distance the box is moved, d = 4 m

  So the amount of work done is, W = F x d

                                                            = 35 x 4

                                                            = 140 Newton-meters

2. Work done, W  = 420 Nm

   Time, T = 3 seconds

   Therefore, the power required is,

   \($P=\frac{W}{T}$\)

   \($P=\frac{420}{3}$\)

       = 140 joules

3. The force exerted is, F = 1.2 N

  Distance the box is moved, d = 5 m

  So the amount of work done is, W = F x d

                                                            = 1.2 x 5

                                                            = 6 Newton-meters

4. Work done, W  = 120 Nm

   Time, T = 20 seconds

   Therefore, the power required is,

   \($P=\frac{W}{T}$\)

   \($P=\frac{120}{20}$\)

       = 6 joules

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