It’s D bro bro
Plus u can look up the rocks one by one and just put creates crystals?
Answer:
ITS D
Explanation:
DID THE USATESTPREP
How many atoms are in 0.433 moles of Cu?
Answer:
2.61 × 10²³ atoms of Cu.
Explanation:
Given data:
Number of moles of Cu = 0.433 mol
Number of atoms = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole = 6.022 × 10²³ atoms of Cu
0.433 mol × 6.022 × 10²³ atoms of Cu / 1mol
2.61 × 10²³ atoms of Cu
Which symbol represents enthalpy?
ΟΗ
Ο ΔΗ
Ο ΔΤ
Ο q
Help ASAP :(
Answer:
The second symbol represents elthapy in chemical reactions.
Help asap pls! Circulating air caused when warm air rises and cool air sinks. Convection currents occur throughout the world.
1.barrage 2.collection area 3.convection current
3. Convection Current
But just a tip Next time try to emphasize the question a little more ! Hope this helps :)
which is an example of a colloid? a mixture that settles out, a mixture that scatters light, a mixture that is separated by filtration, or a salt and water mixture?
These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)
A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct
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Note Complete Question
which is an example of a colloid?
a mixture that settles out,
b mixture that scatters light,
c mixture that is separated by filtration,
d salt and water mixture?
How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is
40.7 k/mol.)
2.09 x 1020
O 2.31% 10110
O 1.18 x 102 103
O 1.11% 1021)
Which equation shows an increase in entropy?
Hint: Look at the states of matter, g s l, of the chemicals in each equation. A C2H4(g) + H2(g) + C2H6(g) в Caco3(9) + Cao(s) - CO2(g) c Fe(s) + S (s) -+ FeS (s)
The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A
In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).
When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.
Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.
In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.
The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A
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PLS HELP Quick!!!!!!!!!
Answer:
Bailee is incorrect. The mass of objects stay the same but the weight will change.
Explanation:
Mass is how much space something takes up, so that wouldn't change on the moon. The weight however would change because the gravitational pull on the earth is different from that on the moon.
I hope this helps!
Bailee explained that when traveling to the moon. The statement of Bailee is incorrect. The mass of the objects stays the same, but the weight will change. The correct option is B.
What is gravity?Gravity is a force that pulls all objects towards itself. It is present on the earth and in the galaxy. Gravity is the cause of all planets, and the sun and the moon stay in their own places.
The weight of items on the moon is equal to their weight on Earth, according to Bailee, thus he needs only bring a small amount of luggage. The mass is the quantity of matter. The mass never changes, only the weight changes of an object when they are on different planets.
Thus, the correct option is B. The mass of the objects stays the same, but the weight will change.
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How is matter divided?
plese help
Using the rules that you learned during the session, what is the answer to the following question?
55.78 * 23.7
Answers
A) 1,322
B) 1,320
explain:
2K + MgCh2 -> 2KCI + Mg
Which of the following statements best describes the reaction?
O This reaction is a double replacement reaction because K replaced Mg and a redox reaction because the ion charges of the elements changed from a 0 charge on K to +1 charge, and a +2 charge on Mg to a 0 charge.
• This reaction is a double replacement reaction because K replaced Mg and not a redox reaction because the ion charges of the elements remained the same.
This reaction is a single replacement reaction because K replaced Mg and a redox reaction because the ion charges of the elements changed from a 0 charge on K to +1 charge, and a +2 charge on Mg to a 0 charge.
O This reaction is a single replacement reaction because K replaced Mg and not a redox reaction
because the ion charges of the elements remained the same.
Answer:
The third option
Explanation:
This reaction is a single replacement reaction because K replaced Mg and a redox reaction because the ion charges of the elements changed from a 0 charge on K to +1 charge, and a +2 charge on Mg to a 0 charge.
A gas mixture containing N2 and O2 was kept inside a 2.00 L container at a temperature of 23.0°C and a total pressure of 1.00 ATM the partial pressure of oxygen was 0.722 ATM how many grams of nitrogen are present in the gas mixture
Answer:
0.641 g of Nitrogen are present in the mixture.
Explanation:
We use the Ideal Gases Law, to solve this question.
For the mixture:
P mixture . V mixture = mol mixture . R . T
We convert the T° to K → 23°C + 273 = 296 K
R = Ideal gases constant → 0.082 L.atm/mol.K
1 atm . 2L = mol mixture . 0.082 L.atm/mol.K . 296K
2 atm.L / ( 0.082 mol /L.atm) . 296 = 0.0824 moles
We know that sum of partial pressure = 1
Partial pressure N₂ + Partial pressure O₂ = 1
1 - 0.722 atm = Partial pressure N₂ → 0.278 atm
We apply the mole fraction concept:
Partial pressure N₂ / Total pressure = Moles N₂ / Total moles
Moles N₂ = (Partial pressure N₂ / Total pressure) . Total moles
Moles N₂ = (0.278 atm / 1 atm) . 0.0824 mol → 0.0229 moles
We convert the moles to mass → 0.0229 mol . 28 g/mol = 0.641 g
641 mg
3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)
We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.
What are the steps involved?Here's an overview of the catalytic cycle, including the necessary details:
i. Chemical structure of the catalyst:
Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]
ii. Molecular geometry of the catalyst:
The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.
iii. Type of reactions involved:
The catalytic cycle involves several reactions, including:
Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.iv. Starting material, reagent, and solvent:
The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).
v. Major and minor end-products:
The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.
vi. Intermediates:
The intermediates in the catalytic cycle include:
Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.
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The urinary system main functions are to _____ and ______.
A:removal of waste and regulate the blood
B:Transport and energy production
C:mechanical digestion and transport
The urinary system's main functions are to remove waste and regulate the blood. Therefore, option (A) is correct.
What is the urinary system?The urinary system contains of the kidneys, ureters,bladder, and urethra. The main function of the urinary system is to remove waste from the body, regulate blood pressure and blood volume, control levels of electrolytes and metabolites, and regulate blood pH.
The urinary system is the drainage system of the human body for the eventual removal of urine. The kidneys have extensive blood provided through the renal arteries which leave the kidneys through the renal vein. Each kidney contains functional units known as nephrons.
Following filtration of blood exit the kidney through the ureters, tubes composed of smooth muscle fibers that propel urine towards the urinary bladder, stored and subsequently expelled from the body by urination.
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A syringe filled with gas holds a volume of 35mL The pressure of the gas in the syringe is
105kPa and it is being held at a temperature of 22°C
If the syringe were warmed to 45°C but the volume were not changed what would be the new
pressure of the gas in the syringe?
if, instead the syringe were warmed to 45°C but the volume was allowed to increase while the
pressure remained constant predict the new volume of the syringe.
The new pressure of the gas in the syringe is 113 kPa
The new volume of the syringe will also increase if the syringe were warmed to 45°C and the pressure remains constant.
When we have a relation between the volume of a gas, the pressure, and the temperature participating together we can use the Combined Gas Law to solve the new pressure or volume.
What is Combined Gas Law?The combined gas law shows the relation between Boyle's Law, Charles Law, and Gay-Lussac's Law and can be expressed by using the formula:
\(\mathbf{\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}}\)
From the parameters given:
Initial volume = 35 mLInitial Pressure = 105 kPaInitial Temperature = 22°C = (273 + 22) K = 295 KFinal temperature = 45 °C = 318 KFinal volume = 35 mLFinal Pressure = unknown??\(\mathbf{\dfrac{105 \times 35 }{295 }= \dfrac{P_2 \times 35}{318}}\)
\(\mathbf{P_2= \dfrac{12.458 \times 318}{35}}\)
\(\mathbf{P_2= 113 \ kPa}\)
However, if the initial volume is increased let say to 50 mL and pressure is constant:
\(\mathbf{\dfrac{V_1}{T_1}= \dfrac{V_2}{T_2}}\)
\(\mathbf{\dfrac{ 50 }{295 }= \dfrac{ x}{318}}\)
\(\mathbf{x = \dfrac{ 318 \times 50 }{295 }}\)
x = 54 mL
Therefore, the new volume of the syringe will also increase if the syringe were warmed to 45°C and the pressure remains constant.
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A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C. Use the chart to complete the multiple steps required to arrive at the final answer. Type in your answers below using 3 digits.
q1 = ___ kJ
q2 = ___ kJ
q3 = ___ kJ
qtot = ___ kJ
The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
Quantity heat required to convert the ice to liquid
The total quantity of heat required is calculated as follows;
q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)
q(tot) = mcΔθ₁ + mΔHf + mcΔθ₂
q(tot) = (100)(4.2)(0 - -45) + (334)(100) + (100)(4.2)(75 - 0)
q(tot) = 18,900 J + 33,400 J + 31,500 J
q(tot) = 18.900 kJ + 33.400 kJ + 31.500 kJ
q(tot) = 83,800 J = 83.8 kJ
Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
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Answer:
q1 9.42
q2 226
q3 31.4
qtot 267
Explanation:
hope this help
Classify the substances as atomic elements, molecular elements, molecular compounds, or ionic compounds.
Answer:
compounds ok I think I can't anderstand good
Which of the following best support the function of electrical signals in the nervous system?
Each nerve cell is connected to the brain by electrical signals.
Nerve cells communicate with the brain by sending out electrical signals
Electrical signals keep nerve cells alive.
Electrical signals are used to get rid of waste produced in the nervous system.
Answer:
Each nerve cell is connected to the brain by electrical signals
Explanation:
Answer:
they said it above me
Explanation:
PLEASE PLEASE PLEASE HELP ME AS SOON AS POSSIBLE!!!!!!!!!!!!!!!!!!!!!!!
1) The mechanical advantage of the pulley is the number of pulleys in the system.
2) It is a system of pulleys with ropes between them.
3) The mechanical advantage is equal to the number of rope sections that support the load, minus one.
How do you determine the mechanical advantage of a block and tackle pulley?The mechanical advantage of a block and tackle pulley system is determined by counting the number of sections of rope that support the load. The mechanical advantage is equal to the number of rope sections that support the load, minus one.
It's important to note that the mechanical advantage of a block and tackle pulley system is based on the assumption that the pulleys are frictionless. In reality, friction within the system will decrease the mechanical advantage. Additionally, the mechanical advantage can be further increased by adding more pulleys to the system.
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1b. Suppose that you were titrating a 100 mL acid solution with the 0.1 M NaOH solution that you made. You performed the titration multiple times and obtained the data below. Complete the data table below. Show work on a separate piece of paper/ the back of this paper.
Step 1: Write and balance the chemical equation (only need to do this once for each titration)
Step 2: Use the molarity and mL of base used to find the moles of base it took to neutralize the acid
Step 3: Calculate moles of acid neutralized
Step 4: Calculate molarity of acid
Step 5: Calculate pH
1c. Calculate the most likely pH of the acid solution by finding the average of all the pH's you found in each of your multiple titrations. We find the average to minimize human errors made while titrating.
The moles of NaOH used is 0.0008 moles
The molarity of the acid is 0.008 M
What is the molarity of the acid?The molarity of the acid is found as follows:
Moles of NaOH used = concentration of NaOH × volume of NaOH used
the average volume of NaOH used = 8.0 mL
moles of NaOH = 0.1 M × 8.0 mL
moles of NaOH = 0.0008 moles
Molarity of acid:
Assuming the acid is monobasic, the mole ratio of acid to base is 1 : 1
The volume of acid used is 100 mL
The molarity of acid = moles of acid / volume of acid in liters
The molarity of acid = 0.0008 moles / 0.1 L
The molarity of acid = 0.008 M
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Select True or False: The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol. Bloom's Level: Understand
True, the entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
The third law of thermodynamics states that, the entropy of a system approaches a constant value as the temperature of the system approaches absolute zero.
The entropy of any perfectly ordered, crystalline substance at absolute zero temperature is zero. That is, the entropy of a pure, perfect crystalline substance at 0 K is 0 J/K.
Thus, we can conclude that the given statement is true. The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
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How many grams of H2O will be formed when 32.0 g H2 is mixed with 84.0 g of O2 and allowed to react to form water
Answer:
94.58 g of \(H_2O\)
Explanation:
For this question we have to start with the reaction:
\(H_2~+~O_2~->~H_2O\)
Now, we can balance the reaction:
\(2H_2~+~O_2~->~2H_2O\)
We have the amount of \(H_2\) and the amount of \(O_2\) . Therefore we have to find the limiting reactive, for this, we have to follow a few steps.
1) Find the moles of each reactive, using the molar mass of each compound (\(H_2~=~2~g/mol~~O_2=~32~g/mol\) ).
2) Divide by the coefficient of each compound in the balanced reaction ("2" for \(H_2\) and "1" for \(O_2\)).
Find the moles of each reactive
\(32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}=15.87~mol~H_2\)
\(84.0~g~of~O_2\frac{1~mol~of~O_2}{32~g~of~O_2}=2.62~mol~of~O_2\)
Divide by the coefficient
\(\frac{15.87~mol~H_2}{2}=7.94\)
\(\frac{2.62~mol~of~O_2}{1}=2.62\)
The smallest values are for \(H_2\), so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:
\(32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}\frac{2~mol~H_2O}{2~mol~H_2}\frac{18~g~H_2O}{1~mol~H_2O}=94.58~g~H_2O\)
We have to remember that the molar ratio between \(H_2O\) and \(H_2\) is 2:2 and the molar mass of \(H_2O\) is 18 g/mol.
Find the volume of methane measured at 298 K
and 1.64 atm
required to convert 0.510 L
of water at 298 K
to water vapor at 373 K
.
Answer:
0.938 L.
Explanation:
The ideal gas law states that the product of pressure and volume is equal to the product of moles, the ideal gas constant and the temperature.
Since the pressure and temperature are constant and we know the volume of water vapor is 0.510 L, we can use that information to find the moles of water vapor.
n = PV/RT
The ideal gas constant R = 8.314 Latm/molK
n = 0.510 L * 1.64 atm / (8.314 Latm/molK * 373 K) = 0.001085 mol
Now we know the moles of water vapor at 373 K and 1.64 atm.
The reaction that takes place is:
CH4(g) + 2H2O(l) --> CO2(g) + 4H2(g)
This is a balanced equation, with the number of moles of each substance on both sides of the equation being equal.
So, the number of moles of methane required to convert 0.510 L of water to water vapor is 0.001085 mol/2 = 0.0005425 mol
Now we can use the ideal gas law to find the volume of methane measured at 298 K and 1.64 atm required to convert 0.510 L of water to water vapor at 373 K
V = nRT/P
V = 0.0005425 mol * 8.314 Latm/molK * 298 K / 1.64 atm = 0.938 L
Therefore, the volume of methane measured at 298 K and 1.64 atm required to convert 0.510 L of water to water vapor at 373 K is 0.938 L.
Cattails A Scientist noticed that cattails grew only in swampy parts of his backyard. He decided to try to find out why. He went to the library and found out the following facts: Cattails are not found in deserts, Cattails are usually found in many swamps, Cattails sometimes grow in rivers and streams. The scientist thought for awhile, then said, " I think I have figured out the answer. Cattails need a lot of water to grow." He then went into his yard and dug up 100 cattails. He divided them into four groups. Each group contained 25 cattails. All of the groups were grown in the same type of soil, they all received the same amount of light, and they were all kept at the same temperature. There was only one difference between the groups. Group 1 received 4 mL of water a day. Group 2 received 3 mL of water a day. Group 3 received 2 mL of water a day. Group 4 received 1 mL of water each day. Every day he went out and measured the plants. After 30 days he observed that the plants in group 1 had grown an average of 8 cm. The plants in group 2 had grown an average of 4 cm. The plants in group 3 had grown an average of 2 cm. The plants in group 4 had grown an average of only 1 cm. He then decided that the amount of water that a cattail receives affects its growth. Plants that receive more water, grow more. The scientist then repeated his experiment using another 100 cattails
The dependent variable in this case is the length of the cattails while the independent variable is the volume of water received.
What is an experiment?An experiment is a carefully controlled study which establishes a cause and effect relationship between variables. There must be a dependent variable and an independent variable.
The dependent variable in this case is the length of the cattails while the dependent variable is the volume of water received. The control group is the group that did not receive any water.
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how do one get this solution
-log10 (2* 10^-2)
The result of the computation when you follow the steps is 1.699.
A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"
What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.
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Q is a solution of HCl containing 0.12 mol.dm^-3. P is a solution of Na2CO3 of unknown concentration. Solution Q was titrated against 25.0cm^3 portions of solution P and an average titre of 26.25cm^3 was obtained. Calculate the concentration of solution P in mol.dm^-3. Na2CO3 +2HCl = 2NaCl +CO2 + H2O.
HELLP I NEEED HELP NOWW NO GUESSING FRFR
What will happen when a piece of magnesium metal is dropped into a beaker
containing a 1 M solution of copper(II) chloride?
Mg2+ + 2e → Mg(s) ° =- 2.37 V
Cu2+ + 2e → Cu(s) £° = + 0.34 V
A deep blue color in Benedict's test indicates the presence of an aldehyde with an adjacent alcohol.
It is true to say that a deep blue color in Benedict's test indicates the presence of an aldehyde with an adjacent alcohol.
Benedict's test is a dark blue soluble arrangement used to test for the presence of the aldehyde utilitarian gathering, - CHO. One liter of Benedict's test can be ready from 100 g of anhydrous sodium carbonate, 173 g of sodium citrate and 17.3 g of copper (II) sulfate pentahydrate. Roughly 1 ml of test is put into a spotless test tube.
Benedict's test is a compound test that can be utilized to check for the presence of diminishing sugars in a given analyte. Hence, basic starches containing a free ketone or aldehyde utilitarian gathering can be related to this test. The test depends on Benedict's reagent (otherwise called Benedict's answer), which is a complicated combination of sodium citrate, sodium carbonate, and the pentahydrate of copper(II) sulfate.
When presented to diminishing sugars, the responses gone through by Benedict's reagent bring about the development of a block red encourage, which shows a positive Benedict's test.
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(Complete question) is:
A deep blue color in Benedict's test indicates the presence of an aldehyde with an adjacent alcohol. Select true or false.
738.90 m has ____ significant figures
Answer: 4
Explanation: because the zero doesn't count
a) What mass in grams of H20 is needed to react completely with 40.0 g of
Na2O2?
M(H2O) =18.02g/mol
M(NA2O2)= 78g/mol
Ecuation:
2Na2O2 (s)+2h2O(I)—> 4NaOH(aq) + O2 (g)
Answer:
\(m_{H_2O}=9.24gH_2O\)
Explanation:
Hello there!
In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:
\(m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2} *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O\)
Best regards!
How many percent by mass of mercury are there in a sample of tap water with a mass of 750 g containing 2.2g of Hg?
Answer:
Divide the mass of the water lost by the mass of hydrate and multiply by 100. The theoretical (actual) percent hydration (percent water) can be calculated from the formula of the hydrate by dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and multiplying by 100.