Which refers to an object’s resistance to any change in its motion? force acceleration gravity inertia

The time it would take it to reach Earth if the Sun remained at its current position is 978,349.5 years.

The time of motion of the giant molecular cloud is the time take for the giant molecular cloud to reach the earth.

Mathematically, the time taken for the giant molecular cloud to reach the earth is given as;

time = distance / speed

where;

time of motion = (6.48 x 10¹⁴ km) / (21 km/s)

time of motion = 3.086 x 10¹³ seconds = 978,349.5 years.

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The battery's emf has to be -108.75 volts for a 2a current to pass through a 5.00 v battery.

Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero. The conservation of energy, or to put it another way, is the characteristic of Kirchhoff's law which states that the algebraic sum of each voltage in the loop must equal zero.

Do a series/parallel reduction first. Apply Kirchhoff's laws now to get the answer.

ΔV adefa ​ =0 or − (20Ω) × (2A) × 5V − (20Ω) × I2 ​

= 0 or I2 ​

= −2.25A

I1 ​+ I2 ​= 2A or I1 ​= 2A − ( −2.25A ) = 4.25A

ΔV adefa ​= 0 or (15Ω) × (4.25A) + ϵ − (20Ω) (−2.25A) = 0

ϵ = −108.75V; Reversing polarity is necessary.

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Answer:

short teeth, short hair, camoflauge, and speed

Explanation:

Answer:

speed and awareness

Explanation:

Answer:

Explanation:

Voltage = 12 (the two batteries are in series and the voltage adds).

Resistance = 3 ohms

I = V / R

I = 12/3

I = 4 amperes.

None of the answers are the right ones. If there is a fifth one that reads 4 amperes then it is the correct answer.

The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The force,by the charge q₁ on the q₃;

\(\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}} = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N\)

The force,by the charge q₂ on the q₃;

\(\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}} = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09 \ N\)

The net force is the sum of the two forces;

\(\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N\)

Hence, the net force on q₃ will be 17.51 N.

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I think its -88 on acellus

A 90.0 kg skler glides down a slope with an incline of 17.0°. Uniform frictional force is needed for the skier to move at a constant velocity.

Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, like the traction required to walk without slipping, may be advantageous, they also pose a significant amount of resistance to motion. Automobile engines need around 20% of their output to overcome frictional forces in moving components.

The adhesion forces between the contact zones of the surfaces, which are always microscopically uneven, appear to be the primary cause of friction between metals. Shearing these "welded" joints and the action of the tougher surface's imperfections scrubbing against the softer surface cause friction. Friction is resistance tot he velocity.

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Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

Answer:

a increases

Explanation:

as distance between two objects increases the gravitational force decreases so when distance decreases the gravitational force increases

Answer:

single-mode fibers

Explanation:

Single mode fibers are used to produce polarization maintaining fibers which make them expensive. Also the alternative to them are multimode fibers which are complex but accurate. So, single-mode fibers are not generally utilized in optical fiber communication.

Answer: The frequency of a pendulum is \(0.2 s^{-1}\).

Explanation:

Time period is defined as the time required to produce complete wave.

As we know that the frequency and time are inversely proportional to each other.

That means,

\(\nu =\frac{1}{T}\)

Where,

\(\nu\) is frequency of pendulum

T is time period

Given:

Time period = 5 seconds

Now putting all the given values in the above formula, we get the frequency of the pendulum.

\(\nu =\frac{1}{T}\\\\\nu =\frac{1}{5s}\\\\\nu =0.2s^{-1}\)

Therefore, the frequency of a pendulum is \(0.2 s^{-1}\).

Explanation:

Elastic string constant (k)

= Slope of the graph F/x

= 15.0N/10.0m = 1.50N/m

Hence,

EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.

Answer:

6.8

Explanation:

Answer:

As the charge increases, the force decreases in strength

Explanation:

Experiments with electric charges have shown that if two objects each have electric charge, then they exert an electric force on each other. The magnitude of the force is linearly proportional to the net charge on each object and inversely proportional to the square of the distance between them...

Answer: The correct answer is: As the charge increases, the force increases in strength

Explanation:

Its kind of the obvious answer and other people don't know how to answer correctly. This was years ago but if anyone needs the answer today then here it is....

Answer:      780080

Explanation: BY FORMULA OF K.E

                           K.E=  1/2 MV^2

                                 =  1/2 (1990)(28)^2

                                 =   780080 JOULE

Answer:

T = 99.51 hour

Explanation:

Mass of Uranus, \(M=8.68\times 10^{25}\ kg\)

The moon Umbriel orbits Uranus at a distance of \(2.66\times 10^8\ m\)

We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.

\(T^2\propto r^3\\\\T^2=\dfrac{4\pi^2r^3}{GM}\\\\T^2=\dfrac{4\pi^2\times (2.66\times 10^8)^3}{6.67\times 10^{-11}\times 8.68\times 10^{25}}\\\\T=358244.51\ s\)

As 1 hour = 3600 s

358244.51 s = 99.51 hour

Hence, Umbriel's orbital period is 99.51 hour.

Answer:

Explanation:

its 99.51 im not just saying that because of the person on top of me but i have all my notes from physics and from chemistry and from biology from when i was on acellus! but the top of me is right :)

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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The final speed of the second puck is 5 m/s.

Speed can be defined as the rate of change of distance with respect to time.

To calculate the final speed of the second puck, we use the formula below.

Formula:

Where:

Make v' the subject of the equation

Assuming,

From the question,

Given:

Substitute these values into equation 2

Hence, The final speed of the second puck is 5 m/s.

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Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is  6.5 * 10¹⁵  cells.

The number of cells in a human is calculated as follows:

The mass of an average cell is ten times the mass of a bacterium.

The mass of a bacterium = 1 * 10⁻¹⁵ kg

mass of an average cell = 10 *  1 * 10⁻¹⁵ kg =  1 * 10⁻¹⁴ kg

Number of cells = mass of person/mass of cell

Number of cells = 65 kg/1 * 10⁻¹⁴ kg

Number of cells = 6.5 * 10¹⁵  cells.

In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.

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Note that the complete question is given below:

Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.

Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation:

Answer:

t = 6 s

Explanation:

Given that,

A chair is thrown upward from a balcony that's 96 ft in the air, d = 96 ft

The initial velocity of chair, u = 16 ft/s

We need to find how many seconds does the chair take to reach its highest height. Let the time is t.

\(t=\dfrac{d}{v}\\\\t=\dfrac{96\ ft}{16\ ft/s}\\\\=6\ s\)

Hence, the chair take 6 seconds to reach its maximum height.

The speed of the wave that is propagated is 10 meters per second.

A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature

The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.

The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).

The speed of the wave (v) is given by the formula:

v = f * λ

Substituting the values we have, we get:

v = 2 Hz * 5 m = 10 m/s

Therefore, the speed of the wave is 10 meters per second.

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Answer: hello  below is the missing part of your question

A mass m = 10 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5029 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.49. The mass leaves the spring at a speed v = 3.4 m/s.

answer

x = 0.0962 m

Explanation:

First step :

Determine the length of the rough patch/spot

F = Uₓ (mg)

and  w = F.d = Uₓ (mg)  * d

hence;

d( length of rough patch) = w / Uₓ (mg) = 46.55 / (0.49 * 10 * 9.8) = 0.9694 m

next :

work done on unstretched spring length

Given that block travels halfway i.e. d = 0.9694 / 2 = 0.4847 m

w' = Uₓ (mg)  * d

    = 0.49 * 10 * 9.81 * 0.4847 = 23.27 J

also given that the Elastic energy of spring = work done ( w')

1/2 * kx^2 = 23.27 J

x = \(\sqrt{\frac{2*23.27}{5029} }\)  = 0.0962 m

Answer: Glucose

Explanation:

A battery of 9 volts is connected to a resistor of 1000 ohms, then the value of current flowing through it will be 0.009 A.

Any flow of electrical charge carriers, such as ions, holes, or subatomic charged particles, is referred to as electrical current.

When electrons serve as the charge transfer in a wire, the amount of charge moving through any point of wire in a given amount of time is measured as electric current. Electric charges' motion is intermittently reversed in the alternating current, but not in direct current.

In many situations, the direction of movement in electric circuits is assumed to be the direction of positive charge flow, which is the way opposite of the real particle drift. When properly specified, the current is known as conventional current.

From the question,

V = ir

i = v/r

i = 9/1000

i = 0.009 A

Therefore, the value of the current flowing through it is  0.009 A.

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Answer:

50km/hrs

Explanation:

speed= distance/time.

121 m far up the hill does he go.

Vo = 31.3 m/s

Angle \(\theta\) = \(20^o\)

Yo = 31.3*sin20

     = 28.57 m/s.

\(Y^2 = Yo^2 + 2g*h = 0.\)

\(28.57^2 - 19.6h = 0 \\19.6h = 816.4\\ h = 41.6 m.\)

\(d*sin20 = 41.6\\ d = 121 m. -- > up \ hill.\)

Friction is a force that opposes the relative motion of solid surfaces, fluid layers and material elements that slide against each other.

There are four types of friction and they are classified as follows:

Applications of friction

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The rock takes more time in second 5m of its journey than it does in the first 5 when thrown straight upward.

The downward motion that merely acts as a result of gravity is referred to as free fall. In the absence of air, all things in free fall accelerate the same regardless of mass since its acceleration is equal to a acceleration caused by gravity.

The height of fall h = 20 meters.

If we suppose that a rock takes t1 seconds to move the first 5 meters, we may compute the rock's initial speed as follows:

u = √2gh

u = √2*9.81*20

u = 19.80 m/s

The 3rd kinematic motion equation yields the following results:

v² = u² - 2g(hf - hi)

v = √(19.80² - 2*9.81*5)

v = 17.14 m/s

Using the first motion equation we can determine how long it will take the rock to move the first 5m, and we get:

t1 = (u - v) / g

t1 = (19.80 - 17.14)/9.81

t1 = 0.27 s

Similar to this, if a rock takes t2 to move 5 meters, then

v'² = u² - 2g(hf - hi)

v' = √(19.80² - 2*9.81*(20 - 5))

v' = 9.88 m /s

Using the first equation for motion, we can determine how long it will take the rock to move the last 5 m, and we get:

t2 = (v' - u')/g

t2 = (9.88 - 0)/9.81

t2 = 1.00 s

Thus, t2 >  t1

As a result, the rock takes more time in the second 5m of its journey than it does in the first 5.

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Answer:

2.5 s

Explanation:

F = ma

F = m(v - u/t)

2880 = 1140(6.4/t)

t = 7296/2880

t = 2.53

t ≅ 2.5 s