Electrons are the particle pr4esent inside the atom that does not affect the stability of the atom,
What is radioactivity?The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.
An overabundance of neutrons or protons can make the nucleus of an atom unstable.
A radioactivity atom will try to become stable by extruding other particles, such as protons or neutrons, or by releasing energy in various ways.
Thus, Electrons are the particle present inside the atom that does not affect the stability of the atom,
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Why does an energy transfer not always result in phase change?
Answer:
Explanation:
The energy transfer are not changing in kinetic energy. They are changes in bonding energy between the molecules.
Describe the motion of an object experiencing blueshift
A source travelling in the direction of the observer causes Doppler blueshift.
When an object is moving towards us, the light from the object is known as blueshift.
The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.
During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.
This causes the color to shift from the red to the blue end of the spectrum in visible light.
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580 nm light shines on a double slit with d = 0.000125 m. What is the angle of the first bright interference maximum (m=1)?
PLS ANSWER
The angle of the first bright interference maximum (m=1) can be calculated using the equation: θ = sin-1(mλ/d).
What is equation ?An equation is a mathematical expression that uses symbols to describe a relationship between two or more variables. Equations are typically used to express relationships between physical quantities, such as forces and masses, or distances and times. They are also used to describe chemical reactions and other phenomena. Equations can be used to solve for unknown values, or to describe patterns or trends in data. Equations are typically written using algebraic notation, which includes variables, constants, and operators.
Substituting the given values, we get,θ = sin-1(1(580 × 10-9m)/(0.000125m)),θ = 0.00463 radians or 0.2637° .
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The books on the bottom shelf experience more gravity than the books on top, because they are closer to the ground.
A True
B False
Answer:
B. FALSE
Explanation:
Gravity is a force that acts on all objects with mass, pulling them towards the center of the Earth. The force of gravity is the same for all objects, regardless of their mass or the location on the Earth's surface. Therefore, the books on the bottom shelf experience the same amount of gravity as the books on the top shelf.
The answer would be (B) False.
A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
A 2 kg object and a 1 kg object are dropped from the same height.
Given that the inertia
masses of these objects are not the same, what hypothesis explains
why the two objects
fall with the same acceleration?
Select one:
O a. The force of gravity is the same for the 1 kg object as for the 2 kg object
O b. The force of friction is the same for the 1 kg object as for the 2 kg object.
O c. The force of gravity on the 1 kg object is twice as great as on the 2 kg object.
Od. The force of friction on the 2 kg object is twice as great as on the 1 kg object.
The first choice (A) will be accurate.
Objects weighing 1 kg and 2 kg are dropped from the same height.
Because the force of gravity is the same for both the 1 kg and the 2 kg objects, the two objects fall with the same acceleration.
What is gravity?Gravity pulls you toward the ground because all objects with mass, such as our Earth, actually bend and curve the fabric of the universe, known as spacetime. Gravity is the curvature of the earth. Gravity, also known as gravitation, is a force that exists between all physical objects in the universe. The force of gravity tends to attract any two objects or particles with nonzero mass toward each other. Gravity affects objects of all sizes, from subatomic particles to galaxy clusters. Gravity is the force that pulls objects toward the center of a planet or other entity. Gravity keeps all of the planets in orbit around the sun.To learn more about gravity, refer
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HELP!
Which process of heat transfer makes milk boil?
Answer:
milk is raised to a certain level for sometimes and immediately cooled to the lower degree
Platinum has a mass of 107.25 g and a volume of 5 cm3. What is the density of platinum?
Answer:
D=2145g/100cm cubed
Explanation:
D=M/V
D=107.25g/5cm cubed
D=2145g/100cm cubed
True or False
Microscopic organisms grow on the rocks near a volcano if the rocks are cooled to 120 degrees Celsius or less.
Explanation:
it's true
Kiss me if I'm wrong. But dinosaurs still exist right?
Answer:
True
Definetely true
A meteor falls from the sky to the Earth. The meteor already had an initial velocity downward when it
was spotted. If it hit the Earth at 335 m/s after being seen for 30 seconds, then what was the initial
velocity of the meteor?
a=9.8
A radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm. (a) Find the angular speed of the blade in rad/min. Incorrect: Your answer is incorrect. webMathematica generated answer key rad/min (b) Find the linear speed of the sawteeth in ft/s. Incorrect: Your answer is incorrect. webMathematica generated answer key ft/
Answer:
The angular speed of the blade is of 166.67 rad/min
If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then the angular speed of the blade would be 104.72 rad/seconds.
What is speed?
The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = total distance /Total time
As given in the problem If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then we have to find the angular speed of the blade,
the angular speed of the blade (ω) = 2πN/60
=2×π×1000/60
= 104.72 rad/seconds
Thus, the angular speed of the radial saw would be 104.72 rad/seconds
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HI PLEASE HELP ON QUESTION ASAP I ALREADY KNOW ANSWER =75 IF ANSWER IS CORRECT, ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST!
BUT how do i work it out in an exam so exam marker knows what your doing
2)the mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. What is the number that was removed?
The mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. The number that was removed is 75.
To solve this problem, we can use the concept of the mean (average) and apply it to the given information. Let's go through the steps to determine the number that was removed.
Step 1: Find the sum of the 6 numbers.
Since the mean of the 6 numbers is 25, we can multiply the mean by the total number of values to find the sum. In this case, 25 * 6 = 150.
Step 2: Find the sum of the remaining numbers.
To find the sum of the remaining numbers, we need to subtract the number that was removed from the original sum. Let's denote the number that was removed as "x". Therefore, the sum of the remaining numbers is 150 - x.
Step 3: Determine the number of remaining numbers.
Since one number was removed, the total number of remaining numbers is 6 - 1 = 5.
Step 4: Calculate the average of the remaining numbers.
We are given that the average of the remaining numbers is 15. To find the sum of the remaining numbers, we can multiply the average by the number of remaining numbers. Therefore, 15 * 5 = 75.
Step 5: Set up the equation and solve for the removed number.
Now we can set up the equation using the information from Steps 2 and 4. We have the equation: 150 - x = 75.
Step 6: Solve the equation.
To find the value of x, we can solve the equation. Subtracting 75 from both sides gives us 150 - 75 = x, which simplifies to x = 75.
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817 cm3 at 80.8 kPa to 101.3 kPa
The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.
To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure (80.8 kPa)
V1 = Initial volume (817 cm³)
P2 = Final pressure (101.3 kPa)
V2 = Final volume (to be calculated)
Let's plug in the values into the equation and solve for V2:
80.8 kPa * 817 cm³ = 101.3 kPa * V2
V2 = (80.8 kPa * 817 cm³) / 101.3 kPa
V2 ≈ 651.25 cm³
Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.
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You see a train that is moving toward you and sounding its
whistle at a constant frequency. Compared to the sound
produced by the whistle, the wavelength of the sound
observed by you is
Answer:
Shorter
Explanation:
i got the same question lol
When a train approaches the observer, the observer hears the sound with high frequency and the wavelenght observed by the observer is shorter.
What is doppler effect?Doppler effect is defined as the phenomenon observed when the a wave from the source is moving towards or moving away from the observer. It gives the relation between the frequency change with respect to the observer.
When a light or sound wave from the source is moving towards the observer, it get compressed. When a light or sound wave is moving away from the observer, it gets stretched.
When the sound wave move towards the observer, the frequency received by the observer is greater. This is called the blue shift. When the sound waves move away from the observer, the frequency received by the observer is lesser. This is called red shift.
Frequency is inversely proportional to the wavelength. In red shift, frequency is lesser and wavelegth is higher. In blue shift, the wavelength is shorter due to higher frequency.
Hence, the train approach the observer, have high frequency and shorter wavelength.
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You launch a model rocket from ground level. It moves directly upward with a constant acceleration of 71.0 m/s2 for 1.45 seconds, at which point it runs out of fuel. Assuming air resistance on the rocket is negligible, what is the maximum altitude (above the ground) achieved by the rocket?
m
Answer:
74.0 meters
Explanation:
We can use the kinematic equation for displacement with constant acceleration to solve this problem:
Δy = v0t + 1/2at^2
where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.
Plugging in the given values, we get:
Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2
Δy = 74.0 m
Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.
What does the phrase “constant velocity” indicate?
a. zero distance
b. zero acceleration
c. constant acceleration
d. deceleration
When tracking inbound on the localizer, which of the following is the proper procedure regarding drift corrections?
A- Drift corrections should be accurately established before reaching the outer marker and completion of the approach should be accomplished with heading corrections no greater than 2 degrees
B- Drift corrections should be made in 5 degree increments after passing the outer marker
C- Drift corrections should be made in 10 degree increments after passing the outer marker
Option a, The proper procedure regarding drift corrections when tracking inbound on the localizer is Drift corrections should be accurately established before reaching the outer marker, and completion of the approach should be accomplished with heading corrections no greater than 2 degrees.
This means that any necessary drift corrections should be made as soon as possible after the aircraft is established on the localizer, and any subsequent heading corrections should be no greater than 2 degrees to maintain the proper course towards the runway.
This procedure helps to ensure that the aircraft remains on course and approaches the runway safely and accurately. Options B and C are not correct, as they do not follow the standard procedure for making drift corrections during an approach.
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The melting ice of a glacier represents what type of change
a. transitional
b. physical
c. chemical
d. transformative
Answer:
PHYSICAL CHANGE
Explanation:
PLEASE DON'T JUST IGNORE IT
I HOPE I WILL GET A GOOD RESPONSE
Consider a uniform electric field E of magnitude E = 7.2 N/C. The line segment connecting points A and B in the field is perpendicular to the direction of the field, while the line segment connecting points C and B is parallel to the field. The line segments have equal lengths of d = 0.38 m.
Find the potential difference, in volts, between point A and point B.
Enter an expression for the potential difference between point C and point B in terms of E and d.
Calculate the potential difference, in volts, between point C and point B.
a. Va-Vb= 0 volts
The two are perpendicular and therefore would have a difference of zero
b. Vc-Vb= -Ed
We already know V=Ed and in this case d is negative
c. -2.736 volts
(-7.2)*(.38)= -2.736
Plug in what was given for E and d into the equation for b
The problem is about the relation between electric field and potential difference. They both are related according to:
Vb -Va = - ∫ E× dl
The solution is:
a) V(B) - V(A) = 0
c) V(C) - V(B) = 2.74 (V)
a) The segment AB is perpendicular to the lines of the electric field, then the point product is zero and V(B) - V(A) = 0
b) The segment CB is parallel to the lines of the electric field, and it is uniform, the:
V(C) - V(B) = - ∫₀⁰°³⁸ E × dl = E× d |₀⁰°³⁸ = - (7.2)×(0.38) = - 2.74 (V)
So the expression for the potential difference between point C and point B in terms of E and d is:
V(C) - V(B) = - ( E×d)
And finally V(C) - V(B) = 2.74 (V)
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A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.
In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.
The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.
A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.
Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.
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Would a 2021 Ford Mustang GT be light weight or heavy weight?
Answer:
Heavy weight
Explanation:
It's a muscle car, its weight its 3,825 lb, and it's classified as heavy for a car.
Answer:
Heavy Weight
Explanation:
A 2021 Mutsang GT could wrigh from 3,532 to 3,868 lbs. This would be considered a Heavy meadium to Heavy muscle car.
No where close to the boat of mopar the challenger almost weighting up to 4,500lbs
What is the result of two displacement vectors having opposite directions? Question 6 options: The resultant is the sum of the two displacements, having the same direction as the smaller vector. The resultant is the sum of the two displacements, having the same direction as the larger vector. The resultant is the difference of the two displacements, having the same direction as the smaller vector. The resultant is the difference of the two displacements, having the same direction as the larger vector.
The resultant of two displacement vectors having opposite directions is the difference of the two displacements, having the same direction as the smaller vector.
When two displacement vectors have opposite directions, it means they are pointing in opposite ways. In other words, one vector is in the opposite direction of the other. To find the resultant of these vectors, we need to subtract one vector from the other.
If we consider two displacement vectors, let's say vector A and vector B, and they have opposite directions, we can represent them as A and -B.
To find the resultant, we subtract vector B from vector A: A - (-B) or A + B.
The resultant will have the same direction as the smaller vector. This is because when we subtract a larger vector from a smaller vector, the resultant will have the direction of the smaller vector.
Therefore, the correct option is: "The resultant is the difference of the two displacements, having the same direction as the smaller vector."
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A rocket is launched straight up, What is the acceleration at the top of the arc?
ANSWER:
9.8 m/s^2
STEP-BY-STEP EXPLANATION:
If an object is thrown vertically upward, its acceleration will always be the acceleration of gravity. This includes the highest point where its velocity is zero. This is due to the fact that at all times it is subjected to the attractive force of gravity.
That is, the acceleration is 9.8 m/s^2
Answer: A= F/m – g
#7777
The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.
Less than
15
1515 minutes
15
1515-
29
2929 minutes
30
3030-
44
4444 minutes
45
4545-
59
5959 minutes
60
6060 or more minutes Total
Private vehicle
636
636636
908
908908
590
590590
257
257257
256
256256
2647
26472647
Public Transportation
9
99
54
5454
96
9696
62
6262
108
108108
329
329329
Other
115
115115
70
7070
23
2323
7
77
7
77
222
222222
Total
760
760760
1032
10321032
709
709709
326
326326
371
371371
3198
31983198
Given that the commuter used public transportation, find the probability that the commuter had a commute of
60
6060 or more minutes.
P
(
60
+
minutes
∣
public transportation
)
=
P(60+ minutes ∣ public transportation)=
Answer:
36
Explanation:
Step review
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
A rollercoaster accelerates from 10 m/s to 100 m/s2 for 25 seconds. What is the acceleration?
Answer:
A roller coasters accelerates from an initial velocity of of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. What's the acceleration? Q. Acceleration only takes place when things speed up. Q. A drag racer accelerated from 0 m/s to 200 m/s in 5 s.
Explanation:
A 0.50-kg mass attached to the end of a string swings in a vertical circle (radius = 2.0 m). When the mass is at the lowest point on the circle, the speed of the mass is 12 m/s. What is the magnitude of the force of the string on the mass at this position?
Answer:
F= 36 N
Explanation:
F= mv^2/r
F= .5*12^2/2
F= ( .5 * 144 )/2
F= 72 / 2
F= 36
A roller-coaster car with a mass of 900 kg starts at rest from a point 22 m above the ground. At point B, it is 8 m above the ground. [Express your answers in kilojoules (kJ).]
What is the potential energy at point B?
Answer: 317.52
Explanation:
I'm just him, so I just know